Find the differential coefficient of
[tex]e^{2x}(1+Lnx)[/tex]​

Answers

Answer 1

Answer:

[tex] \rm \displaystyle y' = 2 {e}^{2x} + \frac{1}{x} {e}^{2x} + 2 \ln(x) {e}^{2x} [/tex]

Step-by-step explanation:

we would like to figure out the differential coefficient of [tex]e^{2x}(1+\ln(x))[/tex]

remember that,

the differential coefficient of a function y is what is now called its derivative y', therefore let,

[tex] \displaystyle y = {e}^{2x} \cdot (1 + \ln(x) )[/tex]

to do so distribute:

[tex] \displaystyle y = {e}^{2x} + \ln(x) \cdot {e}^{2x} [/tex]

take derivative in both sides which yields:

[tex] \displaystyle y' = \frac{d}{dx} ( {e}^{2x} + \ln(x) \cdot {e}^{2x} )[/tex]

by sum derivation rule we acquire:

[tex] \rm \displaystyle y' = \frac{d}{dx} {e}^{2x} + \frac{d}{dx} \ln(x) \cdot {e}^{2x} [/tex]

Part-A: differentiating $e^{2x}$

[tex] \displaystyle \frac{d}{dx} {e}^{2x} [/tex]

the rule of composite function derivation is given by:

[tex] \rm\displaystyle \frac{d}{dx} f(g(x)) = \frac{d}{dg} f(g(x)) \times \frac{d}{dx} g(x)[/tex]

so let g(x) [2x] be u and transform it:

[tex] \displaystyle \frac{d}{du} {e}^{u} \cdot \frac{d}{dx} 2x[/tex]

differentiate:

[tex] \displaystyle {e}^{u} \cdot 2[/tex]

substitute back:

[tex] \displaystyle \boxed{2{e}^{2x} }[/tex]

Part-B: differentiating ln(x)e^2x

Product rule of differentiating is given by:

[tex] \displaystyle \frac{d}{dx} f(x) \cdot g(x) = f'(x)g(x) + f(x)g'(x)[/tex]

let

[tex]f(x) \implies \ln(x) [/tex][tex]g(x) \implies {e}^{2x} [/tex]

substitute

[tex] \rm\displaystyle \frac{d}{dx} \ln(x) \cdot {e}^{2x} = \frac{d}{dx}( \ln(x) ) {e}^{2x} + \ln(x) \frac{d}{dx} {e}^{2x} [/tex]

differentiate:

[tex] \rm\displaystyle \frac{d}{dx} \ln(x) \cdot {e}^{2x} = \boxed{\frac{1}{x} {e}^{2x} + 2\ln(x) {e}^{2x} }[/tex]

Final part:

substitute what we got:

[tex] \rm \displaystyle y' = \boxed{2 {e}^{2x} + \frac{1}{x} {e}^{2x} + 2 \ln(x) {e}^{2x} }[/tex]

and we're done!

Answer 2

Answer:

Product Rule for Differentiation

[tex]\textsf{If }y=uv[/tex]

[tex]\dfrac{dy}{dx}=u\dfrac{dv}{dx}+v\dfrac{du}{dx}[/tex]

Given equation:

[tex]y=e^{2x}(1+\ln x)[/tex]

Define the variables:

[tex]\textsf{Let }u=e^{2x} \implies \dfrac{du}{dx}=2e^{2x}[/tex]

[tex]\textsf{Let }v=1+\ln x \implies \dfrac{dv}{dx}=\dfrac{1}{x}[/tex]

Therefore:

[tex]\begin{aligned}\dfrac{dy}{dx} & =u\dfrac{dv}{dx}+v\dfrac{du}{dx}\\\\\implies \dfrac{dy}{dx} & =e^{2x} \cdot \dfrac{1}{x}+(1+\ln x) \cdot 2e^{2x}\\\\& = \dfrac{e^{2x}}{x}+2e^{2x}(1+\ln x)\\\\ & = \dfrac{e^{2x}}{x}+2e^{2x}+2e^{2x} \ln x\\\\& = e^{2x}\left(\dfrac{1}{x}+2+2 \ln x \right)\end{aligned}[/tex]


Related Questions

A lab technician needs 35 ml of 15% base solution for a certain experiment,
but she has only 10% solution and 20% solution. How many milliliters of
the 10% and the 20% solutions should she mix to get what she needs?

Answers

Answer:

17.5ml- of 10 percent solution, 17.5ml- of 20 percent solution

Step-by-step explanation:

35:100*15=5.25- ml of alkali in the base solution

Suppose we need x ml of 10 percents solution and 35-x - of 20 percents.

Then The quantity of alkali in the first one (10 percents) is x/100*10=0.1x

when in the second one we have (35-x)/100*20= 7-0.2x of alkali

0.1x+7-0.2x=5.25

7-0.1x= 5.25

0.1x=1.75

x=17.5- 0f 10 percents

35-17.5=17.5 - of 20 percents

If Q(x)=x2−6x−2, find Q(−4).

Answers

Answer:

Q(-4) = 38

Step-by-step explanation:

Q(x)=x² − 6x − 2

To find Q(−4) substitute the value of x which is - 4 into Q(x)

That's

Q(-4) = (-4)² - 6(-4) - 2

Q(-4) = 16 + 24 - 2

We have the final answer as

Q(-4) = 38

Hope this helps you

How many different sets of polar coordinates can be given for a point, within one rotation? I thought it was infinite, but the given options are 1, 2, 3, and 4.

Answers

Answer:

the answer is 4

Step-by-step explanation:

so 1 rotation is like a circle 1 unit circle requires 4 quadrant to be in this is the most simplified i can get

Answer:

Solution : 4

Step-by-step explanation:

The question asks us how many polar coordinates are possible for one rotation. For one rotation there will be 4 polar coordinates, one present in each quadrant such that,

( r, theta ), ( r, theta ), ( - r, theta ), ( - r, theta )

Respectively if theta was q say,

( r, q ), ( r, - q ), ( - r, q ), ( - r, -q )

Therefore there are 4 sets of polar coordinates for one rotation, in each of the 4 quadrants.

If you conducting a test for statistical study and you got outcome with the likelihood of 0.005. Please evaluate outcome.

Answers

Here is the complete question:

a. Statistically significant at 0.01

b. Not statistically significant

Answer:

The test is significant

Step-by-step explanation:

When a p value is smaller than or less than alpha we say it is statistically significant.

We are testing the p value or likelihood of 0005 against a significant level of 0.01

P value = 0.005 < 0.01

0.005 is less than 0.01 which shows the test to be significant.

The decision rule would be to reject the null hypothesis and say the result is statistically significant.

6. If the equations kx - y = 2 and 6x - 2y = 3 have a solution then state the value of k a) K = 3 b) k 3 c ) K 0 d) k = 0 7.

Answers

Answer:

k ≠ 3

Step-by-step explanation:

Given the system of equation;

kx - y = 2 ------------------- 1

6x - 2y = 3 -------------------- 2

Rewriting the equations in the format ax+by+c = 0

Equation 1 becomes kx - y - 2 = 0

Equation 2 becomes 6x - 2y - 3 = 0

where a₁ = k, b₁ = -1 and c₁ = -2  and a₂ = 6, b₂ = -2 and c₂ = -3

For the system of equation to have a unique solution the following must be true;

a₁/a₂ ≠ b₁/b₁

Substituting the coefficients into the condition, we will have;

k/6 ≠ -1/-2

k/6 ≠ 1/2

Cross multiplying we will have;

2k ≠ 6

k ≠ 6/2

k ≠ 3

This means that k can be any other real values except 3 for the system of equation to have a unique solution.

Find the distance between the points (-4, -2) and (-8, 6)

Answers

Answer:

distance=√[(x2-x1)²+(y2-y1)²]

√[{6-(-2)}²+ (-8-(-4))²]

√(64+16)

√[100]

10

Points given

(-4,-2)(-8,-6)

Distance:-

[tex]\\ \sf \longmapsto \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

[tex]\\ \sf \longmapsto \sqrt{(-8+4)^2+(6+2)^2}[/tex]

[tex]\\ \sf \longmapsto \sqrt{(-4)^2+(8)^2}[/tex]

[tex]\\ \sf \longmapsto \sqrt{64+16}[/tex]

[tex]\\ \sf \longmapsto \sqrt{80}[/tex]

[tex]\\ \sf \longmapsto 8.4[/tex]

translate this into an expression: the quotient of a number, x, and 8, could you please explain it to me?​

Answers

Answer:

x/8

Step-by-step explanation:

First, we are given "the quotient of...". This means that we are dividing something/something else. If two numbers are given in the phrase "something and something else", the first number given will be the something, and the second number will be the something else.

The first number listed is x. Therefore, we have

x/something else.

Next, we are given "and 8", so we have x/8 as our expression

What is the correct answer please I’m stumped

Answers

Answer:

The choose C. 2

[tex]( \frac{4 ^{ \frac{5}{4} } \times 4^{ \frac{1}{4} } }{4 ^{ \frac{1}{2} } } )^{ \frac{1}{2} } = 2[/tex]

Answer:

2

Step-by-step explanation:

inside the parenthesis is equivalent to 4^(5/4 + 1/4 - 1/2) = 4¹ = 4

√4 = 2


A marathon started at 7:30am. The winner took 3hrs and 47
minutes to complete the race and the last person finished 55
minutes later. At what time did the marathon end?​

Answers

Answer:

12:12

Step-by-step explanation:

first add 3 hours to 7:30 which makes it 10:30

then add 47 min and it becomes 11:17

add 55 min to that and its 12:12

Help please, i really need the answer asap.

Answers

Answer: Bottom right corner

The larger metallic object is initially at rest, so the velocity is 0 when t = 0. The speed changes after t = 3 seconds.

Answer:

It would be the last one.

Step-by-step explanation:

It says the object is initially at rest, so you look for a table with 0 m/s and you find the last table had been at rest for 0 -2  seconds. The small rocky object initially had a speed of 90 m/s and then decreased to 36 m/s as its energy transferred to the metallic object. The metallic object's speed from time 4-6s with the small rocky object equals the small rocky initial speed.

Rocky Object initial speed = 90 m/s

Rocky Object new speed = 36 m/s

Large metallic object speed after collision = 64 m/s.

64 m/s + 36 m/s = 90 m/s

Large metallic object speed after collision + Rocky Object new speed

= Rocky Object initial speed

You can also test this for kinetic energy.

Assume that​ women's heights are normally distributed with a mean given by mu = 64.3 inches​, and a standard deviation given by sigma= 2.2 inches.
A) If a woman is randomly selected, find the probability that her height is less than 65 inches.
B) If 34 women are randomly selected, find the probability that they have a mean height less than 65 inches.

Answers

Answer:69

Step-by-step explanation:

Please answer asap this person made a mistake what is the error and correct solution to this problem

Answers

Answer:

6

Step-by-step explanation:

Hello, please consider the following.

[tex](4+x)^2=4^2+2\cdot 4\cdot x+x^2=16+\boxed{8}x+x^2\\\\\text{ ... and not ...}\\\\16+\boxed{4}x+x^2[/tex]

So the correct equation becomes.

[tex]x^2+64=16+8x+x^2\\\\8x=64-16=48\\\\\text{ we divide by 8 both sides of the equation.}\\\\x=\dfrac{45}{8}=6[/tex]

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

Answer:

Error : The expression ( 4 + x )² was expanded incorrectly.

Correct Solution : x = 6

Step-by-step explanation:

The planning of the solution is correct, by Pythagorean Theorem you can say that PQ² + QO² = PO², and hence through substitution x² + 8² = ( 4 + x )². Let's look into the calculations.

PQ² + QO² = PO²,

x² + 8² = ( 4 + x )²,

x² + 8² = 16 + 8x + x²,

64 = 16 + 8x,

48 = 8x,

x = 48 / 8 = 6, x = 6

As you can see, the only error in the calculations was expanding the expression ( 4 + x )². ( 4 + x )² = 4² + 2 [tex]*[/tex] 4 [tex]*[/tex] x + x² = 4² + 8x + x² = 16 + 8x + x², not 16 + 4x + x².

30 points!!!!!!!
There are 6 red marbles, 9 blue marbles, and 10 green marbles in a bag.

Several trials are performed with the results shown in the table. What is the experimental probability of randomly drawing a red marble?

Red Blue Green
16 30 34
32%
25%
20%
16%

Answers

Answer:

C. 20%

Step-by-step explanation:

Outcomes with red = 16Total trials = 16 + 30 + 34 = 80P(red) = 16/80 = 1/5 = 20%

Correct choice is C

Answer:

20%

Step-by-step explanation:

80 x 20% = 16 red marbles

Dia is 10 years old. How many years have to add with twice of her age to get 24? ​

Answers

Answer:

4

Step-by-step explanation:

twice her age:

10*2 = 20

24-20 = 4

Answer:

4 i believe that's the answer

A football team starts on the 10 yard line moving toward the 50 yard line so they can score on the other side of the field. In three plays they gain 14 yards, lose 12 yards, and gain 4 more yards. What yard line do they start their fourth play?

Answers

Answer:

16 yard line

Step-by-step explanation:

The football team is starting on the 10 yard line. In the first play, they move up to the 24 yard line. Then in the second play, they go back to the 12 yard line since they lost 12 yards. Then in the third play, they gain 4 yards so you add 4 to 12. They end up at the 16 yard line after the third play. This means that they're going to start their fourth play at the 16 yard line.

Answer:

16 yards.

Step-by-step explanation:

They start at 10 yards. They are moving towards the 50 yard line, so gaining yards will add to the 10 yards instead of subtract from the 10 yards.

In the first play, they gain 14 yards. 10 + 14 = 24 yards.

In the second play, they lose 12 yards. 24 - 12 = 12 yards.

In the third play, they gain 4 yards. 12 + 4 = 16 yards, which is where they start their fourth play.

Hope this helps!

On a coordinate plane, 2 lines are shown. Line A B has points (negative 4, negative 2) and (4, 4). Line C D has points (0, negative 3) and (4, 0). Which statement best explains the relationship between lines AB and CD? They are parallel because their slopes are equal. They are parallel because their slopes are negative reciprocals. They are not parallel because their slopes are not equal. They are not parallel because their slopes are negative reciprocals.

Answers

Answer:

A. they are parallel because their slopes are equal.

Step-by-step explanation:

edge 2020

Answer:

its A in egde

Step-by-step explanation:

Find an equation in slope-intercept form of the line that has slope –9 and passes through point A(-9,-1)

Answers

Answer:

y = -9x - 82

Step-by-step explanation:

Line with slope m=-9 passing through A(x1, y1) =A(-9,-1)

y-y1 = m(x-x1)

Substitute values

y-(-1) = -9(x-(-9)

y+1 = -9x -81

y = -9x - 82

The lines shown below are parallel. If the green line has a slope of -2, what is the slope of the red line?



A.
2

B.
-2

C.


D.
-

Answers

Answer:

the slope of the read line is also -2

Step-by-step explanation:

The probability distribution of number of televisions per household in a small town is given below.

x 0 1 2 3
​P(x) ​ 0.05 0.15 0.25 0.55


a. Find the probability of randomly selecting a household that has one or two televisions.
b. Find probability of randomly selecting a household that has one or two televisions

Answers

Answer: 0.20

Step-by-step explanation:

The given probability distribution of number of televisions per household in a small town:

x          0       1     2      3

​P(x) ​ 0.05 0.15 0.25 0.55

To find : The probability of randomly selecting a household that has one or two televisions ( in both parts a. and b.).

The computations for this would be :

P( 1 or 2) = P(1)+P(2)

= 0.05+0.15

= 0.20

Hence, the required probability= 0.20

Answer:

Step-by-step explanation:

If Evan does a job in 168 hours and with the help of Emma they can do it together in 56 hours, how long would it take Emma to do it alone?

Answers

Means Evan completes the 1/168 of the job each hour, and together they complete 1/56 each hour. 1/56 = 3/168, so Evan completes 1/168 of the job each hour and Emma completes the other 2/168 (so together they add up to be 3/168). So Emma completes 2/168 = 1/84 of the job per hour if she does it alone. So 84 hour is how long it takes.

g natasha is in a class of 30 students that selects 4 leaders. How many ways are there to select the 4 leaders so that natasha is one of the leaders

Answers

Answer:

3,654 different ways.

Step-by-step explanation:

If there are 30 students in a class with natasha in the class and natasha is to select four leaders in the class of which she is already part of the selection, this means there are 3 more leaders needed to be selected among the remaining 29 students (natasha being an exception).

Using the combination formula since we are selecting and combination has to do with selection, If r object are to selected from n pool of objects, this can be done in nCr number of ways.

nCr = n!/(n-r)!r!

Sinca natasha is to select 3 more leaders from the remaining 29students, this can be done in 29C3 number of ways.

29C3 = 29!/(29-3)!3!

29C3 = 29!/(26!)!3!

29C3 = 29*28*27*26!/26!3*2

29C3 = 29*28*27/6

29C3 = 3,654 different ways.

This means that there are 3,654 different ways to select the 4 leaders so that natasha is one of the leaders

On a coordinate plane, a line has points (negative 2, negative 4) and (4, 2). Point P is at (0, 4). Which points lie on the line that passes through point P and is parallel to the given line? Select three options. (–4, 2) (–1, 3) (–2, 2) (4, 2) (–5, –1)

Answers

Answer:

the correct options are:

(–1, 3),  (–2, 2) and (–5, –1)

Step-by-step explanation:

Given that a line passes through two points

A(-2, -4) and B(4, 2)

Another point P(0, 4)

To find:

Which points lie on the line that passes through P and is parallel to line AB ?

Solution:

First of all, let us the find the equation of the line which is parallel to AB and passes through point P.

Parallel lines have the same slope.

Slope of a line is given as:

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

[tex]m=\dfrac{2-(-4)}{4-(-2)} = 1[/tex]

Now, using slope intercept form ([tex]y = mx+c[/tex]) of a line, we can write the equation of line parallel to AB:

[tex]y =(1)x+c \Rightarrow y = x+c[/tex]

Now, putting the point P(0,4) to find c:

[tex]4 = 0 +c \Rightarrow c = 4[/tex]

So, the equation is [tex]\bold{y=x+4}[/tex]

So, the coordinates given in the options which have value of y coordinate equal to 4 greater than x coordinate will be true.

So, the correct options are:

(–1, 3),  (–2, 2) and (–5, –1)

Answer:

b,c,e

Step-by-step explanation:

I got it right on edge

Given the following situation:
A cell phone company offers a data package by charging $20 a month plus $12 per gigabyte of data used. Write a linear equation
that relates the cost C, in dollars, to the amount of data used. Use it to determine the amount of data used if they charge you
$116.

Answers

9514 1404 393

Answer:

C = 20 +12g8 gigabytes

Step-by-step explanation:

At $12 per gigabyte, the data charge will be 12g where g is the number of gigabytes. Then the total charge is ...

  C = 12g +20

__

If C = 116, the value of g is found from ...

  116 = 12g +20

  96 = 12g . . . . . . . subtract 20

  8 = g . . . . . . . . . . divide by 12

The amount of data used is 8 gigabytes if the charge is $116.

Based on experience, the Ball Corporation’s aluminum can manufacturing facility in Ft. Atkinson, Wisconsin, knows that the metal thickness of incoming shipments has a mean of 0.2771 mm with a standard deviation of 0.000855 mm.


(a) A certain shipment has a diameter of 0.2742. Find the standardized z-score for this shipment. (Round your answer to 3 decimal places.)


z



(b) Is this an outlier?


Yes

No

Answers

Answer:

(a) The standardized z-score for this shipment is -3.392.

(b) Yes, this an outlier.

Step-by-step explanation:

We are given that the Ball Corporation’s aluminum can manufacturing facility in Ft. Atkinson, Wisconsin, knows that the metal thickness of incoming shipments has a mean of 0.2771 mm with a standard deviation of 0.000855 mm.

Let X = the metal thickness of incoming shipments.

The z-score probability distribution for the normal distribution is given by;

                              Z  =  [tex]\frac{X-\mu}{\sigma}[/tex]  ~ N(0,1)

where, [tex]\mu[/tex] = mean thickness = 0.2771 mm

           [tex]\sigma[/tex] = standard deviation = 0.000855 mm

(a) Now, it is given that a certain shipment has a diameter of 0.2742 mm and we have to find the standardized z-score for this shipment.

So, z-score  =  [tex]\frac{X-\mu}{\sigma}[/tex]

                   =  [tex]\frac{0.2742-0.2771}{0.000855}[/tex]  = -3.392

Hence, the standardized z-score for this shipment is -3.392.

(b) Yes, we can consider this as an outlier because the standardized z-score is very large and this value is far from the population mean.

a swift can fly at 160km/h. what is the speed in m/s? show clearly how you worked out your answer.

Answers

Answer:

[tex]\huge\boxed{\sf Speed = 44.44 \ m/s}[/tex]

Step-by-step explanation:

Speed = 160 km / hr

To convert km/hr to m/s, we multiply it by [tex]\sf \frac{10}{36}[/tex]

Hence,

[tex]\displaystyle Speed = 160 \times \frac{10}{36} \ m/s\\\\Speed = \frac{1600}{36} \ m/s\\\\Speed = 44.44 \ m/s\\\\\rule[225]{225}{2}[/tex]

Hope this helped!

~AH1807Peace!

The solution system to 3y-2x=-9 and y=-2x+5

Answers

Answer:

[tex]\boxed{(3,-1)}[/tex]

Step-by-step explanation:

Hey there!

Well to find the solution the the given system,

3y - 2x = -9

y = -2x + 5

So to find x lets plug in -2x + 5 for y in 3y - 2x = -9.

3(-2x + 5) - 2x = -9

Distribute

-6x + 15 - 2x = -9

-8x + 15 = -9

-15 to both sides

-8x = -24

Divide -8 to both sides

x = 3

Now that we have x which is 3, we can plug in 3 for x in y = -2x + 5.

y = -2(3) + 5

y = -6 + 5

y = -1

So the solution is (3,-1).

Hope this helps :)

NEED HELP ASAP


Which point represents the center of the circle shown below?

Answers

Answer:

Point O represents the center of the circle

Step-by-step explanation:

HOPE IT HELPS. PLEASE MARK IT AS BRAINLIEST

Answer: Point O

Explanation:

Point O is in the middle of the circle

And other point are not in the middle

Estimate the line of best fit using two points on the line.
.
10
9
8
7
6
5
(6,8)
(9,6)
N
1 2 3 4 5 6
8 9 10
O A. y-2x+12
O B. y--{x+12
O C. y= O D. y=-3x+12

Answers

Answer:

B. y = -2/3x + 12

Step-by-step explanation:

Formula to find the slope when given two points on a line:

y2 - y1

x2 - x1

Substitute the two given points (6, 8) (9, 6):

6 - 8

9 - 6

Slope = -2/3x

We found the slope! And the answer choices already gave us one y-intercept, which is 12. The last thing we do is we form an equation with the information we solved and that was given to us.

y = slope (x) + y-intercept

y = -2/3x + 12

The answer choice that matches this equation is B.

In conclusion, the equation that best estimates the line of best fit shown above is answer choice B.

An equation of a line with given coordinates is y= -2/3 x+12. Therefore, option B is the correct answer.

What is the equation of a line?

The general equation of a straight line is y=mx+c, where m is the gradient, and y = c is the value where the line cuts the y-axis. This number c is called the intercept on the y-axis.

From the given graph, the coordinate points are (6, 8) and (9, 6).

We know that, the formula to find the slope of a line is slope = (y₂-y₁)/(x₂-x₁).

Here, slope = (6-8)/(9-6)

= -2/3

Substitute m=-2/3 and (x, y)=(6, 8) in y=mx+c, we get

8=-2/3 (6)+c

8=-4+c

c=12

So, equation of a line is y= -2/3 x+12

Therefore, option B is the correct answer.

To learn more about the equation of a line visit:

https://brainly.com/question/2564656.

#SPJ7

A study was conducted by a research center. It reported that most shoppers have a specific spending limit in place while shopping online. The reports indicate that men spend an average of $240 online before they decide to visit a store. If the spending limit is normally distributed and the standard deviation is $20.
A. Find the probability that a male spent less than $210 online before deciding to visit a store.
B. Find the probability that a male spent between $270 and $300 online before deciding to visit a store.
C. Ninety percent of the amounts spent online by a male before deciding to visit a store are less than what value?

Answers

Answer:

(A) The probability that a male spent less than $210 online before deciding to visit a store is 0.0668.

(B) The probability that a male spent between $270 and $300 online before deciding to visit a store is 0.0655.

(C) Ninety percent of the amounts spent online by a male before deciding to visit a store is less than $265.632.

Step-by-step explanation:

We are given that the reports indicate that men spend an average of $240 online before they decide to visit a store. If the spending limit is normally distributed and the standard deviation is $20.

Let X = the spending limit

The z-score probability distribution for the normal distribution is given by;

                           Z  =  [tex]\frac{X-\mu}{\sigma}[/tex]  ~ N(0,1)

where, [tex]\mu[/tex] = mean spending limit = $240

           [tex]\sigma[/tex] = standard deviation = $20

So, X ~ Normal([tex]\mu=\$240,\sigma^{2} =\$20^{2}[/tex])

(A) The probability that a male spent less than $210 online before deciding to visit a store is given by = P(X < $210)

     P(X < $210) = P( [tex]\frac{X-\mu}{\sigma}[/tex] < [tex]\frac{\$210-\$240}{\$20}[/tex] ) = P(Z < -1.50) = 1 - P(Z [tex]\leq[/tex] 1.50)

                                                            = 1 - 0.9332 = 0.0668

The above probability is calculated by looking at the value of x = 1.50 in the z table which has an area of 0.9332.

(B) The probability that a male spent between $270 and $300 online before deciding to visit a store is given by = P($270 < X < $300)

     P($270 < X < $300) = P(X < $300) - P(X [tex]\leq[/tex] $270)

     P(X < $300) = P( [tex]\frac{X-\mu}{\sigma}[/tex] < [tex]\frac{\$300-\$240}{\$20}[/tex] ) = P(Z < 3) = 0.9987

     P(X [tex]\leq[/tex] $270) = P( [tex]\frac{X-\mu}{\sigma}[/tex] [tex]\leq[/tex] [tex]\frac{\$270-\$240}{\$20}[/tex] ) = P(Z [tex]\leq[/tex] 1.50) = 0.9332

The above probability is calculated by looking at the value of x = 3 and x = 1.50 in the z table which has an area of 0.9987 and 0.9332 respectively.

Therefore, P($270 < X < $300) = 0.9987 - 0.9332 = 0.0655.

(C) Now, we have to find ninety percent of the amounts spent online by a male before deciding to visit a store is less than what value, that is;

         P(X < x) = 0.90     {where x is the required value}

         P( [tex]\frac{X-\mu}{\sigma}[/tex] < [tex]\frac{x-\$240}{\$20}[/tex] ) = 0.90

         P(Z < [tex]\frac{x-\$240}{\$20}[/tex] ) = 0.90

In the z table, the critical value of z that represents the bottom 90% of the area is given as 1.2816, i.e;

                     [tex]\frac{x-\$240}{\$20}=1.2816[/tex]

                     [tex]x-240=1.2816\times 20[/tex]

                     [tex]x=240 + 25.632[/tex]

                     x = 265.632

Hence, Ninety percent of the amounts spent online by a male before deciding to visit a store is less than $265.632.

through: (3, - 3); slope = 2/3

Answers

Answer:

y=2/3x - 5

Step-by-step explanation:

Since we have the slope and a point, we can make an equation in point intercept form (y=mc+b) by using the point slope form formula (y-y1)=m(x-x1), where (x1,y1) is the point you plug in.

(y-y1)=m(x-x1)

m=2/3

y1=-3

x1=3

y- -3=2/3(x-3)

y+3=2/3(x-3)

Distribute 2/3 with (x-3) by multiplying

y+3=2/3x - 2

Subtract 3 from both sides

y=2/3x - 5

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