Find the length of FT¯¯¯¯¯¯¯ A. 77.71 B. 72.47 C. 56.84 D. 49.42

Answer:

x = -5 or x = i sqrt(3) or x = -i sqrt(3)

Step-by-step explanation:

Solve for x:

x^3 + 5 x^2 + 3 x + 15 = 0

The left hand side factors into a product with two terms:

(x + 5) (x^2 + 3) = 0

Split into two equations:

x + 5 = 0 or x^2 + 3 = 0

Subtract 5 from both sides:

x = -5 or x^2 + 3 = 0

x = (0 ± sqrt(0^2 - 4×3))/2 = ( ± sqrt(-12))/2:

x = -5 or x = sqrt(-12)/2 or x = (-sqrt(-12))/2

sqrt(-12) = sqrt(-1) sqrt(12) = i sqrt(12):

x = -5 or x = (i sqrt(12))/2 or x = (-i sqrt(12))/2

sqrt(12) = sqrt(4×3) = sqrt(2^2×3) = 2sqrt(3):

x = -5 or x = (i×2 sqrt(3))/2 or x = (-i×2 sqrt(3))/2

(2 i sqrt(3))/2 = i sqrt(3):

x = -5 or x = i sqrt(3) or x = (-2 i sqrt(3))/2

(2 (-i sqrt(3)))/2 = -i sqrt(3):

Answer: x = -5 or x = i sqrt(3) or x = -i sqrt(3)

Answer:

C. x = −5, 1.7i, −1.7i

Step-by-step explanation:

Quick answer:

C. x = −5, 1.7i, −1.7i

explanation:

C. is the only answer option that does NOT have 0 as a root, which is impossible, because there is a constant term, which means that all roots are non-zero. In other words, we cannot extract x as a factor.

Complete answer:

All odd degree polynomials have at least one real root.

By the real roots theorem, we know that

if there is a real root, it must be of the form [tex]\pm[/tex]p/q where q is any of the factors of the leading coefficient (1 in this case) and p is any factor of the constant term d (15 in this case).

Values of [tex]\pm[/tex]p/q are

On trial and error, using the factor theorem, we see that

f(-5) = 0, therefore -5 is a real root.  By long division, we have a quotient of x^2+3 = 0, which gives readily the remaining (complex) roots of +/- sqrt(5) i

The answer is {-5, +/- sqrt(5) i}, or again,

C. x = −5, 1.7i, −1.7i

Answer:

0.0319

Step-by-step explanation:

To approximate this probability, we shall be using the Bernoulli approximation of the Binomial distribution.

Let p = probability of selecting a reference book = 65% = 0.65

Let q = probability of selecting other books= 1-p = 1-0.65 = 0.35

Now, we want to find the probability that all of these 8 books to be re-shelved are reference book.

We set up the probability as follows;

P(X = 8) = 8C8 •p^8•q^0

P(X = 8) = 1 * (0.65)^8 * (0.35)^0

P(X = 8) = 0.031864481289 which is 0.0319 to 4 decimal places

Answer:

csctheta= [tex]\frac{\sqrt{13} }{3}[/tex]

Step-by-step explanation:

answer is provided on top

The value of the [tex]\rm cosec \theta = \frac{\sqrt{13} }{3}[/tex]. Cosec is found as the ratio of the hypotenuse and the perpendicular.

The field of mathematics is concerned with the relationships between triangles' sides and angles, as well as the related functions of any angle

The given data in the problem is;

[tex]\rm cot \theta = \frac{2}{3}[/tex]

The [tex]cot \theta[/tex] is found as;

[tex]\rm cot \theta = \frac{B}{P} \\\\ \rm cot \theta = \frac{2}{3} \\\\ B=2 \\\\ P=3 \\\\[/tex]

From the phythogorous theorem;

[tex]\rm H=\sqrt{P^2+B^2} \\\\ \rm H=\sqrt{2^2+3^2} \\\\ H=\sqrt{13} \\\\[/tex]

The value of the cosec is found as;

[tex]\rm cosec \theta = \frac{H}{P} \\\ \rm cosec \theta = \frac{\sqrt{13} }{3}[/tex]

Hence the value of the [tex]\rm cosec \theta = \frac{\sqrt{13} }{3}[/tex].

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Answer:

then what's the question???..

Answer:

1250 amps

Step-by-step explanation:

V = 5000 V

R = 4 ohms

Use ohms law: V = IR

5000 =I(4)

I = 1250 amps

Answer:

f(x) + f(4)

Step-by-step explanation:

TRUST ME DO THIS PROCESS

There will be a total of 4 test scores including the final exam. To get a 70, the 4 tests need to equal 4 x 70 = 280 points , to be 79, they have to equal 4 x 79 = 316 points.

The 3 already done = 61 + 62 + 86 = 209 points.

The final exam needs to be between :

280 -209 = 71

316 -209 = 107. The answer would be between 71 and 100%

Answer:

x =2

Step-by-step explanation:

(x+4) /3 = 2

Multiply each side by 3

(x+4) /3  *3= 2*3

x+4 = 6

Subtract 4

x+4-4 = 6-4

x =2

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▹ Answer

x = 2

▹ Step-by-Step Explanation

[tex]\frac{x + 4}{3} = 2\\\\3 * 2 = 6\\\\x + 4 = 6\\\\x = 2[/tex]

Hope this helps!

CloutAnswers ❁

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Answer:

[tex] \frac{2}{3} [/tex]

Step-by-step explanation:

Area of Octagon A = 4 m²

Side length of Octagon A = a

Area of Octagon B = 9 m²

Side length of Octagon B = b

The scale factor of their side lengths = [tex] \frac{a}{b} [/tex]

According to the area of similar polygons theorem, [tex] \frac{4}{9} = (\frac{a}{b})^2 [/tex]

Thus,

[tex] \sqrt{\frac{4}{9}} = \frac{a}{b} [/tex]

[tex] \frac{\sqrt{4}}{\sqrt{9}} = \frac{a}{b} [/tex]

[tex] \frac{2}{3} = \frac{a}{b} [/tex]

Scale factor of their sides = [tex] \frac{2}{3} [/tex]

Answer:

3:5

Step-by-step explanation:

square root of 9 is 3.

square root if 25 is 5.

therefore, 3:5.

Answer:

13 units

Step-by-step explanation:

(x₁,y₁) = (-5 , 3)   & (x₂ , y₂) = (7 ,8)

[tex]Distance = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}} \\[/tex]

              [tex]= \sqrt{(7-[-5])^{2}+(8-3)^{2}} \\\\= \sqrt{(7+5)^{2}+(8-3)^{2}} \\\\= \sqrt{(12)^{2}+(5)^{2}}\\\\=\sqrt{144+25}\\\\=\sqrt{169}\\\\= 13[/tex]

Answer:

d  = -4M + 28

Step-by-step explanation:

Answer:

33 web pages (at least)

Step-by-step explanation:

We can set up an inequality to represent this, where x represents the number of web pages made.

1.5x > 1.25x + 8

1.5x represents the number of hours it will take normally, and 1.25x + 8 represents the time with the new software. 1.5x (amount of hours using old software) needs to be larger than the time it takes with the new software.

Solve for x:

1.5x > 1.25x + 8

0.25x > 8

x > 32

So, the designer would have to make at least 33 pages.

The number of web pages would the designer have to make in order to save time using the new software will be 33 web pages (at least).

Inequality is the relationship between two expressions that are not equal, employing a sign such as ≠ “not equal to,” > “greater than,” or < “less than.”.

We can set up an inequality to represent this, where x represents the number of web pages made.

1.5x > 1.25x + 8

The time with the new software is represented by 1.25x + 8 and the normal time is represented by 1.5x. The number of hours spent using the old software must be 1.5 times greater than the time spent using the new product.

Solve for x:

1.5x > 1.25x + 8

0.25x > 8

x > 32

Therefore, the number of web pages would the designer have to make in order to save time using the new software will be 33 web pages (at least).

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Answer:

x=-3 x=-11

Step-by-step explanation:

−3|x + 7| = −12

|x + 7|=4

x+7=4 x+7=-4

x=-3    x=-11

Answer:

The work done by the force is 42.4 Joules

Step-by-step explanation:

The force F = 7 pounds

angle to the horizontal that the force acts ∅ = 30°

The object is moved a distance d = 7 feet

The coordinate  (0 comma 0 )to (7 comma 0 ), indicates that the movement started from the origin, and is along the x-axis.

The work done by this force = F cos ∅ x d

==> 7 cos 30° x 7

==> 7 x 0.866 x 7 = 42.4 Joules

Answer:

[tex]\huge\boxed{n\leq\dfrac{2-2c}{p}\ \text{for}\ p<0}\\\boxed{n\geq\dfrac{2-2c}{p}\ \text{for}\ p>0}[/tex]

Step-by-step explanation:

[tex]-np-4\leq2(c-3)\qquad\text{use the distributive property}\\\\-np-4\leq2c-6\qquad\text{add 4 to both sides}\\\\-np\leq2c-2\qquad\text{change the signs}\\\\np\geq2-2c\qquad\text{divide both sides by}\ p\neq0\\\\\text{If}\ p<0,\ \text{then flip the sign of inequality}\\\boxed{n\leq\dfrac{2-2c}{p}}\\\text{If}\ p>0 ,\ \text{then}\\\boxed{n\geq\dfrac{2-2c}{p}}[/tex]

Answer:

[tex](1,-1)[/tex] and [tex](3.5,1.5)[/tex]

Step-by-step explanation:

Given

[tex]y = 2x^2 - 8x+5[/tex]

[tex]y = x - 2[/tex]

Required

Determine the solution

Substitute x - 2 for y in [tex]y = 2x^2 - 8x+5[/tex]

[tex]x - 2 = 2x^2 - 8x+5[/tex]

Collect like terms

[tex]0 = 2x^2 - 8x - x + 5 + 2[/tex]

[tex]0 = 2x^2 - 9x + 7[/tex]

Expand the expression

[tex]0 = 2x^2 - 7x - 2x+ 7[/tex]

Factorize

[tex]0 = x(2x - 7) -1(2x - 7)[/tex]

[tex]0 = (x-1)(2x - 7)[/tex]

Split the expression

[tex]x - 1 = 0[/tex] or [tex]2x - 7 = 0[/tex]

Solve for x in both cases

[tex]x = 1[/tex] or [tex]2x = 7[/tex]

[tex]x = 1[/tex] or [tex]2x/2 = 7/2[/tex]

[tex]x = 1[/tex] or [tex]x = 3.5[/tex]

Recall that

[tex]y = x - 2[/tex]

When [tex]x = 1[/tex]

[tex]y = 1 -2[/tex]

[tex]y = -1[/tex]

When [tex]x = 3.5[/tex]

[tex]y = 3.5 - 2[/tex]

[tex]y = 1.5[/tex]

Hence, the solution is;

[tex](1,-1)[/tex] and [tex](3.5,1.5)[/tex]

[tex]\\ \sf\longmapsto 49\times 51[/tex]

[tex]\\ \sf\longmapsto (50-1)(50+1)[/tex]

[tex]\\ \sf\longmapsto (50)^2-(1)^2[/tex]

[tex]\\ \sf\longmapsto 2500-1[/tex]

[tex]\\ \sf\longmapsto 2499[/tex]

49 × 51

⇛(50 + 1) (50 - 1)

⇛(50)² - (1)²

⇛2500 - 1

⇛2499

Answer:

A. 20•5+9

B.109 flies

Answer:

Step-by-step explanation:

[tex]6 \div \frac{3}{8} = 6 \times \frac{8}{3} \\ [/tex]

[tex] = \frac{6 \times 8}{3} \\ \\ = \frac{48}{3} =1 6[/tex]

Answer:

3x^4+(x^3)y-8x^2y^2+9xy^3-13y^4

Step-by-step explanation:

3x^4+(nothing)=3x^4

x^3y+(nothing)=x^3y

-10x^2y^2=2x^2y^2=-8x^2y^2

9xy^3+(nothing)=0

-4y^4-9y^4=-13y^4

Add it all up and write the terms by descending order of exponent value, and u get my answer.

Answer:

where is the whole question

Answer:

my straight time payment will be $116 for last week

Step-by-step explanation:

The local bowling alley pays

$7.25 per hour to manage the desk.

If worked 16 hours, my straight time payment will be

Rate= $7.25 per hour

Hour worked= 16 hours

my straight time payment = rate*hour worked

my straight time payment = 7.25*16

my straight time payment = 166.00

my straight time payment will be $116

Answer:

In this question, we shall be accepting the null hypothesis H0 since the critical value is greater than the test statistic value

Step-by-step explanation:

Here in this question, we want to make a conclusion about the null hypothesis H0.

To make or give the correct conclusion about the null hypothesis in this case, we shall need to compare the absolute value of the test statistic used against the value of the critical value.

Hence, we draw a conclusion if the test statistic is larger or smaller than the critical value.

From the value given in the question, we can see that the test statistic given as 1.68 is lesser in value compared to the critical value given as 1.96.

In this kind of case, the conclusion that we shall be drawing is that we will accept the null hypothesis H0 and reject the alternative hypothesis

Triangle DEF is scalene

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The triangle DEF will be a scalene triangle as all the sides of the triangle are unequal.

A scalene triangle is a type of triangle which have all the sides to be unequal and similarly, all the angles will also be unequal to each other.

Given that:-

it is given that all the sides of the triangle are x, x+3, and x−1 we can clearly see that for any value of x all the three sides will have different values. we can conclude from this that the triangle DEF is a scalene triangle.

Therefore triangle DEF will be a scalene triangle as all the sides of the triangle are unequal.

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One way to write this polar coordinate is to say (2.5, pi/2) meaning we move 2.5 units away from the origin toward the pi/2 direction

pi/2 radians = 90 degrees

An alternative is to write (-2.5, 3pi/2) which is where we aim at the 3pi/2 direction (270 degrees) and walk backward while still facing directly south, and we'll arrive at the same location.

Answer:

25 CAN be written as a fraction.

=> 250/10 = 25

Square root of 14 is 3.74165738677

It is NOT POSSIBLE TO WRITE THIS FULL NUMBER AS A FRACTION,  but if we simplify the decimal like: 3.74, THEN WE CAN WRITE THIS AS A FRACTION

=> 374/100

-1.25 CAN be written as a fraction.

=> -5/4 = -1.25

Square root of 16 CAN also be written as a fraction.

=> sqr root of 16 = 4.

4 can be written as a fraction.

=> 4 = 8/2

Pi = 3.14.........

It is NOT POSSIBLE TO WRITE THE FULL 'PI' AS A FRACTION, but if we simplify 'pi' to just 3.14, THEN WE CAN WRITE IT AS A FRACTION

=> 314/100

.6 CAN be written as a fraction.

=> 6/10 = .6

Answer:

[tex]\boxed{-20i^2 -13ij+21j^2}[/tex]

Step-by-step explanation:

[tex]\sf Plug \ in \ the \ values.[/tex]

[tex](5i+7j) \cdot (-4i+3j)[/tex]

[tex]\sf Expand \ brackets.[/tex]

[tex]5i(-4i+3j)+7j(-4i+3j)[/tex]

[tex]-20i^2 +15ij+-28ij +21j^2[/tex]

[tex]\sf Combine \ like \ terms.[/tex]

[tex]-20i^2 -13ij+21j^2[/tex]

Answer:

(a) Null Hypothesis, [tex]H_0[/tex] : [tex]\mu \geq[/tex] 30 points

    Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] < 30 points

(b) Type I error is that we conclude that test-takers who had completed the training showed a mean increase smaller than 30 points but in actual, the program raises SAT scores by an average of at least 30 points.

Step-by-step explanation:

We are given that a test-preparation company advertises that its training program raises SAT scores by an average of at least 30 points.

A random sample of test-takers who had completed the training showed a mean increase smaller than 30 points.

Let [tex]\mu[/tex] = average SAT score.

(a) So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu \geq[/tex] 30 points

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] < 30 points

Here, the null hypothesis states that the training program raises SAT scores by an average of at least 30 points.

On the other hand, the alternate hypothesis states that test-takers who had completed the training showed a mean increase smaller than 30 points.

(b) Type I error states the probability of rejecting the null hypothesis given the fact that null hypothesis is true.

According to the question, the Type I error is that we conclude that test-takers who had completed the training showed a mean increase smaller than 30 points but in actual, the program raises SAT scores by an average of at least 30 points.

The consequence of a Type I error is that we conclude the test-takers have low SAT scores but in actual they have an SAT score of at least 30 points.

In this question, we have to identify the zeros of the polynomial, along with a point, and then we get that the formula for the polynomial is:

[tex]p(x) = -0.5(x^3 - x^2 + 6x)[/tex]

------------------------

Equation of a polynomial, according to it's zeros:

Given a polynomial f(x), this polynomial has roots such that it can be written as: , in which a is the leading coefficient.

------------------------

Identifying the zeros:

Given the graph, the zeros are the points where the graph crosses the x-axis. In this question, they are:

[tex]x_1 = -2, x_2 = 0, x_3 = 3[/tex]

Thus

[tex]p(x) = a(x - x_{1})(x - x_{2})(x-x_3)[/tex]

[tex]p(x) = a(x - (-2))(x - 0)(x-3)[/tex]

[tex]p(x) = ax(x+2)(x-3)[/tex]

[tex]p(x) = ax(x^2 - x + 6)[/tex]

[tex]p(x) = a(x^3 - x^2 + 6x)[/tex]

------------------------

Leading coefficient:

Passes through point (2,-8), that is, when [tex]x = 2, y = -8[/tex], which is used to find a. So

[tex]p(x) = a(x^3 - x^2 + 6x)[/tex]

[tex]-8 = a(2^3 - 2^2 + 6*2)[/tex]

[tex]16a = -8[/tex]

[tex]a = -\frac{8}{16} = -0.5[/tex]

------------------------

Considering the zeros and the leading coefficient, the formula is:

[tex]p(x) = -0.5(x^3 - x^2 + 6x)[/tex]

A similar problem is found at https://brainly.com/question/16078990

The formula that represents the polynomial in the figure is [tex]p(x) = x^{3}-x^{2}-6\cdot x[/tex].

Based on the Fundamental Theorem of Algebra, we understand that Polynomials with real Coefficient have at least one real Root and at most a number of Roots equal to its Grade. The Grade is the maximum exponent that Polynomial has and root is a point such that [tex]p(x) = 0[/tex]. By Algebra we understand that polynomial can be represented in this manner known as Factorized form:

[tex]p(x) = \Pi\limits_{i=0}^{n} (x-r_i)[/tex] (1)

Where:

[tex]n[/tex] - Grade of the polynomial.

[tex]i[/tex] - Index of the root binomial.

[tex]x[/tex] - Independent variable.

We notice that polynomials has three roots in [tex]x = -2[/tex], [tex]x = 0[/tex] and [tex]x = 3[/tex], having the following construction:

[tex]p(x) =(x+2)\cdot x \cdot (x-3)[/tex]

[tex]p(x) = (x^{2}+2\cdot x)\cdot (x-3)[/tex]

[tex]p(x) = x^{3}+2\cdot x^{2}-3\cdot x^{2}-6\cdot x[/tex]

[tex]p(x) = x^{3}-x^{2}-6\cdot x[/tex]

The formula that represents the polynomial in the figure is [tex]p(x) = x^{3}-x^{2}-6\cdot x[/tex].

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