Answer:
[tex]|R_n (x)| \leq \dfrac{|x - \dfrac{\pi}{2}|^{n+1}}{(n+1)!}[/tex]
Step-by-step explanation:
From the given question; the objective is to show that :
[tex]\lim_{n \to \infty} R_n (x) = 0[/tex] for all x in the interval of convergence f(x)=cos x, a= π/2
Assuming for the convergence f the taylor's series , f happens to be the derivative on an open interval I with a . Then the Taylor series for the convergence of f , for all x in I , if and only if [tex]\lim_{n \to \infty} R_n (x) = 0[/tex]
where;
[tex]\mathtt{R_n (x) = \dfrac{f^{(n+1)} (c)}{n+1!}(x-a)^{n+1}}[/tex]
is a remainder at x and c happens to be between x and a.
Given that:
a= π/2
Then; the above equation can be written as:
[tex]\mathtt{R_n (x) = \dfrac{f^{(n+1)} (c)}{n+1!}(x-\dfrac{\pi}{2})^{n+1}}[/tex]
so c now happens to be the points between π/2 and x
If we recall; we know that:
[tex]f^{(n+1)}(c) = \pm \ sin \ c \ or \ cos \ c[/tex] (as a result of the value of n)
However, it is true that for all cases that [tex]|f ^{(n+1)} \ (c) | \leq 1[/tex]
Hence, the remainder terms is :
[tex]|R_n (x)| = | \dfrac{f^{(n+1)}(c)}{(n+1!)}(x-\dfrac{\pi}{2})^{n+1}| \leq \dfrac{|x - \dfrac{\pi}{2}|^{n+1}}{(n+1)!}[/tex]
If [tex]\lim_{n \to \infty} R_n (x) = 0[/tex] for all x and x is fixed, Then
[tex]|R_n (x)| \leq \dfrac{|x - \dfrac{\pi}{2}|^{n+1}}{(n+1)!}[/tex]
4. Katy has 6 times as many nickels as
Shaun. Shaun has 18 nickels. How many
nickels, n, does Katy have?
n is 6
18.
n=
Answer:
[tex]\huge\boxed{n = 108\ nickels}[/tex]
Step-by-step explanation:
Let the nickels with Katy be n
So, the condition is
n = 6 (Shaun nickels)
While Nickels of Shaun = 18 , So
n = 6 (18)
n = 108 nickels
The graph of F(x), shown below in pink, has the same shape as the graph of
G(x) = x3, shown in gray. Which of the following is the equation for F(x)?
Greetings from Brasil...
In this problem we have 2 translations: 4 units horizontal to the left and 3 units vertical to the bottom.
The translations are established as follows:
→ Horizontal
F(X + k) ⇒ k units to the left
F(X - k) ⇒ k units to the right
→ Vertical
F(X) + k ⇒ k units up
F(X) - k ⇒ k units down
In our problem, the function shifted 4 units horizontal to the left and 3 units vertical to the bottom.
F(X) = X³
4 units horizontal to the left: F(X + 4)
3 units vertical to the bottom: F(X + 4) - 3
So,
F(X) = X³
F(X + 4) - 3 = (X + 4)³ - 3The transformed function is f ( x ) = ( x + 4 )³ - 3 and the graph is plotted
What happens when a function is transformed?Every modification may be a part of a function's transformation.
Typically, they can be stretched (by multiplying outputs or inputs) or moved horizontally (by converting inputs) or vertically (by altering output).
If the horizontal axis is the input axis and the vertical is for outputs, if the initial function is y = f(x), then:
Vertical shift, often known as phase shift:
Y=f(x+c) with a left shift of c units (same output, but c units earlier)
Y=f(x-c) with a right shift of c units (same output, but c units late)
Vertical movement:
Y = f(x) + d units higher, up
Y = f(x) - d units lower, d
Stretching:
Stretching vertically by a factor of k: y = k f (x)
Stretching horizontally by a factor of k: y = f(x/k)
Given data ,
Let the function be represented as g ( x )
Now , the value of g ( x ) = x³
And , the transformed function has coordinates as A ( -4 , -3 )
So , when function is shifted 4 units to the left , we get
g' ( x ) = ( x + 4 )³
And , when the function is shifted vertically by 3 units down , we get
f ( x ) = ( x + 4 )³ - 3
Hence , the transformed function is f ( x ) = ( x + 4 )³ - 3
To learn more about transformation of functions click :
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Could anyone help me with this question please? Thank you.
Answer:
C) 549 km²
Step-by-step explanation:
The area of the regular pentagon is given by ...
A = (1/2)Pa
where P represents the perimeter, and 'a' represents the apothem (6.2 km). Of course, the perimeter is 5 times the side length.
The lateral area is the product of the perimeter and the height:
LA = Ph
Using these formulas, and recognizing the total area includes two (2) pentagons, we have ...
total area = (LA) +2(A) = Ph +2(1/2)Pa = P(h +a)
= (45 km)(6 km +6.2 km) = 549 km^2
In the multiplication below, each of A, B and
C represents a different digit. What is ABC?
A B C
X
3
В В В
Answer:
ABC = 148, 3*148 = 444
Step-by-step explanation:
We know that 111 = 3* 37, so all numbers of the form BBB has the factor 37.
So we need a multiple of 37 such thant when multiplied, we get three digits the same as the middle digit.
Try 4*37 = 148, 148*3 = 444, bingo, we got the right combination.
So ABC is 148.
This solid shape is made from 5 cubes. Which of the diagrams show the plan of the solid? Please help!
Answer:
A Maybe
Step-by-step explanation:
Cogntive identification
Unable to answer mathematically or analytically
The Plan of the solid shape is shown by : (A)
What is the Meaning of solid shape?A solid shape can be defined as a shape that possesses three dimensions. that is to say they are three dimensional shapes.
A solid shape has both length, width and height. They are more tangible and look physical than two dimensional shape.
solid shapes can take up space in the universe because they are more tangible and realistic.
In conclusion, the Plan of the solid shape is shown by : (A)
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17. Complete the following equation using <, >, or =
7 __ 24/2
A. >
B. <
C. =
Leena is arranging 3 different books in a row on a shelf. Create a sample space for the arrangement of a detective story (D), a mystery story (M), and a comic book (C).
Source
StylesNormal
There are 6 DIFFERENT POSSIBLE arrangements as obtained using the factorial method and they are :
DMC, CMD, DCM, MDC, CDM, MCD
Given :
DETECTIVE STORY = D
MYSTERY STORY = M
COMIC BOOK = C
To use the factorial method, we find the factorial value of the number of books to be arranged
Number of different possible arrangements = (number of books)!
Number of books = 3
Hence, 3! = 3 * 2 * 1 = 6 ways
The sample space :
DMC
CMD
DCM
MDC
CDM
MCD
THEREFORE, there are 6 different samples on the SAMPLE SPACE.
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What is the nearest 100 of 1730
Answer:
1700
Step-by-step explanation:
pls thnx and mark me brainliest
what is the end point of a ray
Answer:
point A is the rays endpoint
Step-by-step explanation:
Answer:
The "endpoint" of a ray is the origin point of the ray, or the point at which the ray starts.
Step-by-step explanation:
A ray starts at a given point, the endpoint, and then goes in a certain direction forever ad infinitum. The origin point of a ray is called "the endpoint".
Cheers.
Avanety of two types of snack packs are delivered to a store. The box plots compare the number of calories in each
snack pack of crackers to the number of calories in each snack pack of trail mix.
Number of Calories in Each Snack Pack
Crackers
Trail Mix
65
70
75
80
85
90
95
100 105 110 115
Which statement is true about the box plots?
The interquartile range of the trail mix data is greater than the range of the cracker data.
The value 70 is an outlier in the trail mix data
The upper quartile of the trail mix data is equal to the maximum value of the cracker data
O The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs
of crackers
Answer:
The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs
of crackers
Step-by-step explanation:
IQR of trail mix data = 105 - 90 = 15
The range of cracker data = 100 - 70 = 30.
Therefore, the first option is NOT TRUE.
To check if option 2 is correct, calculate the lower limit to see if 70 is below the lower limit. If 70 is below the lower limit, then it is an outlier in the trail mix data.
Thus, Lower Limit = [tex]Q_1 - 1.5(IQR)[/tex]
Q1 = 90,
IQR = 105 - 90 = 15
Lower Limit = [tex]90 - 1.5(15)[/tex]
Lower Limit = [tex]90 - 22.5 = 67.5[/tex]
70 is not less than the lower limit, therefore, 70 is not an outlier for the trail mix data. The second option is NOT TRUE.
The upper quartile of the trail mix data = 105.
The maximum value of the cracker data = 100.
Therefore, the third option is NOT TRUE.
Range can be used to determine how much variable there is in a data represented on a box plot. The greater the range value, the greater the variation.
Range of trail mix data = 115 - 70 = 45
Range of cracker data = 100 - 70 = 30.
The range value for the number of calories in trail mix is greater than that for cracker, therefore, the number of calories in the packs of trail mix have a greater variation than the number of calories in the packs
of crackers.
The fourth option is TRUE.
Answer: D. The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers.
if b<0 and |b| = 4b+15 what is the value of b
Answer:
|b|= 4b+15
-b=4b+15
-b-4b= 15
-5b= 15
b= 15/-5
b= -3
the ans -3
If [tex]a<0[/tex] the [tex]|a|=-a[/tex]
So
[tex]|b|=4b+15\\-b=4b+15\\5b=-15\\b=-3[/tex]
The square root of 3/100 is between what two numbers
9514 1404 393
Answer:
0.17 and 0.18
Step-by-step explanation:
Usually, a question like this asks for two integer values that bound the root. Here, those would be 0 and 1.
√(3/100) = (√3)/10 ≈ 0.17320508...
You can truncate this at any point to find a number lower than √.03, then add 1 to that value's least-significant digit to find a number higher than √.03.
For example, if we use 4 digits, the two numbers bounding the root could be ...
0.1732 and 0.1733
Factorise the following using the Difference of Two Squares or Perfect Squares rule: a) (2x-2)^2 - (x+4)^2 b) (3x+4) (3x-4)
Answer:
Step-by-step explanation:
Hello, please consider the following.
a)
[tex](2x-2)^2 - (x+4)^2 \\\\=(2x-2-(x+4))(2x-2+x+4)\\\\=(2x-2-x-4)(3x+2)\\\\=\boxed{(x-6)(3x+2)}[/tex]
b)
[tex](3x+4) (3x-4)\\\\=(3x)^2-4^2\\\\=\boxed{9x^2-16}[/tex]
Thank you.
A translation T maps point B(-2,4) onto point B (3,-1). What is the translation T?
HELP PLSS!!!!
A- (x+5, y-5)
B- (x+5, y+5)
C- (x-5, y+5)
D- (x-5, y-5)
Answer:
(x+5, y-5) is the correct answer
Step-by-step explanation:
first, take -2 and 3 on x value; when you jump from -2 to 3, your answer is positive 5
second, take 4 and -1 on y value; when you jump from 4 to -1, your answer is negative 5
hence your answer for this question is a- (x+5, y-5)
Use any estimation strategy to calculate ,51.12 times 87.906 pls help!
Answer:
the real answer is: 4493.75472
BUT for ESTIMATION STRATEGY it is: 4500
Step-by-step explanation:
An urn has 6 white balls and 4 orange balls if Sam chooses 5 balls at random from the urn what is the probability that he chooses 2 white balls and 3 orange balls
Answer:
probability of picking white is 6/10
and probability of picking orange is 4/10
Step-by-step explanation:
so probability of picking 2 white and 3 orange will be 9/25 + 64/100 = 8/125
2. An economist reports that 576 out of a sample of 1,200 middle-income American households participate in the stock market. A confidence interval of [0.468, 0.492] was calculated. What confidence level was used in this calculation
Answer:
Confidence level = 59.46%
Step-by-step explanation:
Given that:
An economist reports that 576 out of a sample of 1,200 middle-income American households participate in the stock market.
sample mean = 576
sample size = 1200
The sample proportion [tex]\hat p[/tex] = x/n
The sample proportion [tex]\hat p[/tex] = 576/1200 = 0.48
A confidence interval of [0.468, 0.492] was calculated. What confidence level was used in this calculation?
The confidence interval level can be determined by using the formula:
[tex]M.E =Z_{critical} \times \sqrt{\dfrac{\hat p (1- \hat p)}{n}}[/tex]
If the calculated confidence interval was [0.468, 0.492]
Then,
[tex]\hat p[/tex] - M.E = 0.468
0.48 -M.E = 0.468
0.48 - 0.468 = M.E
0.012 = M.E
M.E = 0.012
NOW;
[tex]0. 012 =Z_{critical} \times \sqrt{\dfrac{0.48 (1- 0.48)}{1200}}[/tex]
[tex]0. 012 =Z_{critical} \times \sqrt{\dfrac{0.48 (0.52)}{1200}}[/tex]
[tex]0. 012 =Z_{critical} \times \sqrt{\dfrac{0.2496}{1200}}[/tex]
[tex]0. 012 =Z_{critical} \times \sqrt{2.08\times10^{-4}}[/tex]
[tex]0. 012 =Z_{critical} \times 0.01442[/tex]
[tex]\dfrac{0. 012}{0.01442} =Z_{critical}[/tex]
[tex]Z_{critical} =0.8322[/tex]
From the standard normal tables,
the p - value at [tex]Z_{critical} =0.8322[/tex] = 0.7973
Since the test is two tailed
[tex]1 - \alpha/2= 0.7973[/tex]
[tex]\alpha/2= 1-0.7973[/tex]
[tex]\alpha/2= 0.2027[/tex]
[tex]\alpha= 0.2027 \times 2[/tex]
[tex]\alpha= 0.4054[/tex]
the level of significance = 0.4054
Confidence level = 1 - level of significance
Confidence level = 1 - 0.4054
Confidence level = 0.5946
Confidence level = 59.46%
HELP PLEASE PLEASE :(
Answer:
16
Step-by-step explanation:
It’s a ratio.
x/12=21/28
21x=12*28
21x=336
x=336/21
x=16
A hypothesis test is to be performed in order to test the proportion of people in a population that have some characteristic of interest. Select all of the pieces of information that are needed in order to calculate the test statistic for the hypothesis test:
No piece of information is supplied to choose from ; However, the requirements for the test statistic of the hypothesis in question is given below.
Answer:
Kindly check explanation
Step-by-step explanation:
The hypothesis in the question above which is to be tested is a one sample proportion test ;
The test statistic formula for a one sample proportion test is given as :
Test statistic = (Phat - P) / √[P(1 - P) / n] ;
Where;
Phat = sample proportion
P = population proportion
n = sample size
Sample proportion = x / n ;
Therefore, once the parameters (Sample proportion, population proportion and sample size are given) then obtaining the test statistic is possible.
HHHHHHHheeellllllppppp MEMEMEMEMMEMEMEMEMEEEEEEEE PLLLZZZZ
If f(x)=ax^2+bx+c and f(0)=-4 and f(1)=-2 and f(2)=6, what is the value of A and B and C?
Hello There!!
I'm not a 100% sure this right.
Step-by-step explanation:
f(x)=ax2+bx+c for which f(1)=0, f(-2)=6 and f(2)=-14
0 = a +b +c
6 =4a -2b +c
-14=4a+2b +c
subtract third equation from second to get
20 = -4b and so b=-5
first equation is now 5 = a+c
second is now -4=4a+c
subtract to get -9=3a and so a=-3
equation one now is 0=-3-5+c or c=8 Hope This Helps!!
What is the solution (x, y) to this system of linear equations? 2x – 3y = –6 x + 2y = 11
Answer:
x = 3, y = 4
Step-by-step explanation:
Solve for the first variable in one of the equations, then substitute the result into the other equation.
5 x 5 = 10 x 5= 20 x 5 = Answer these 3 problems and then tell how they are
related.
Step-by-step explanation:
First we need to find out what they all 3 equal, with multiplication.
5×5=25
10×5=50
20×5=100
In each of these problems, the answer is multiplying itself by 2 in order to get to the next answer. So this is how they are related
Calcule o valor de x nas equações literais: a) 5x – a = x+ 5a b) 4x + 3a = 3x+ 5 c) 2 ( 3x -a ) – 4 ( x- a ) = 3 ( x + a ) d) 2x/5 - (x-2a)/3 = a/2 Resolva as equações fracionárias: a) 3/x + 5/(x+2) = 0 , U = R - {0,-2} b) 7/(x-2) = 5/x , U = R - {0,2} c) 2/(x-3) - 4x/(x²-9) = 7/(x+3) , U = R - {-3,3}
Answer:
1) a) [tex]x = \frac{3}{2}\cdot a[/tex], b) [tex]x = 5-3\cdot a[/tex], c) [tex]x = -a[/tex], d) [tex]x = \frac{5}{2}\cdot a[/tex]
2) a) [tex]x = -\frac{3}{4}[/tex], b) [tex]x = -5[/tex], c) [tex]x = 3[/tex]
Step-by-step explanation:
1) a) [tex]5\cdot x - a = x + 5\cdot a[/tex]
[tex]5\cdot x - x = 5\cdot a + a[/tex]
[tex]4\cdot x = 6\cdot a[/tex]
[tex]x = \frac{3}{2}\cdot a[/tex]
b) [tex]4\cdot x + 3\cdot a = 3\cdot x + 5[/tex]
[tex]4\cdot x - 3\cdot x = 5 - 3\cdot a[/tex]
[tex]x = 5-3\cdot a[/tex]
c) [tex]2\cdot (3\cdot x - a) - 4\cdot (x-a) = 3\cdot (x+a)[/tex]
[tex]6\cdot x -2\cdot a -4\cdot x +4\cdot a = 3\cdot x +3\cdot a[/tex]
[tex]6\cdot x -4\cdot x -3\cdot x = 3\cdot a -4\cdot a +2\cdot a[/tex]
[tex]-x = a[/tex]
[tex]x = -a[/tex]
d) [tex]\frac{2\cdot x}{5} - \frac{x-2\cdot a}{3} = \frac{a}{2}[/tex]
[tex]\frac{6\cdot x-5\cdot (x-2\cdot a)}{15} = \frac{a}{2}[/tex]
[tex]\frac{6\cdot x - 5\cdot x+10\cdot a}{15} = \frac{a}{2}[/tex]
[tex]2\cdot (x+10\cdot a) = 15 \cdot a[/tex]
[tex]2\cdot x = 5\cdot a[/tex]
[tex]x = \frac{5}{2}\cdot a[/tex]
2) a) [tex]\frac{3}{x} + \frac{5}{x+2} = 0[/tex]
[tex]\frac{3\cdot (x+2)+5\cdot x}{x\cdot (x+2)} = 0[/tex]
[tex]3\cdot (x+2) + 5\cdot x = 0[/tex]
[tex]3\cdot x +6 +5\cdot x = 0[/tex]
[tex]8\cdot x = - 6[/tex]
[tex]x = -\frac{3}{4}[/tex]
b) [tex]\frac{7}{x-2} = \frac{5}{x}[/tex]
[tex]7\cdot x = 5\cdot (x-2)[/tex]
[tex]7\cdot x = 5\cdot x -10[/tex]
[tex]2\cdot x = -10[/tex]
[tex]x = -5[/tex]
c) [tex]\frac{2}{x-3}-\frac{4\cdot x}{x^{2}-9} = \frac{7}{x+3}[/tex]
[tex]\frac{2}{x-3} - \frac{4\cdot x}{(x+3)\cdot (x-3)} = \frac{7}{x+3}[/tex]
[tex]\frac{1}{x-3}\cdot \left(2-\frac{4\cdot x}{x+3} \right) = \frac{7}{x+3}[/tex]
[tex]\frac{x+3}{x-3}\cdot \left[\frac{2\cdot (x+3)-4\cdot x}{x+3} \right] = 7[/tex]
[tex]\frac{2\cdot (x+3)-4\cdot x}{x-3} = 7[/tex]
[tex]2\cdot (x+3) -4\cdot x = 7\cdot (x-3)[/tex]
[tex]2\cdot x + 6 - 4\cdot x = 7\cdot x -21[/tex]
[tex]2\cdot x - 4\cdot x -7\cdot x = -21-6[/tex]
[tex]-9\cdot x = -27[/tex]
[tex]x = 3[/tex]
Big sleds must hold 3 children and small sleds must hold 2 children. If 17 children want to go sledding at the same time, how many of each type of sled is needed?
Answer:
5 big sleds and 1 small sled
Another trader would like to carry out a hypothesis test about stocks that offer dividends. Why is this hypothesis test right-tailed? Select the correct answer below: This is a right-tailed test because a direction is not specified. This is a right-tailed test because a direction is specified. The population parameter is greater than the specified value. This is a right-tailed test because a direction is specified. The population parameter is less than the specified value. More information is needed.
Answer:
This is a right-tailed test because a direction is specified. The population parameter is greater than the specified value.
Step-by-step explanation:
The hypothesis testing technique is used to test an assumption regarding population parameter. Null hypothesis is a statement that is to be tested against the alternative hypothesis and then decision is taken whether to accept or reject the null hypothesis. A right tailed test is where the most of data is in the right side. This is one tailed test where the direction is specified.
The curve y=2x^3+ax^2+bx-30 has a stationary point when x=3. The curve passes through the point (4,2).
(A) Find the value of a and the value of b.
#secondderivative #stationarypoints
A stationary point at x = 3 means the derivative dy/dx = 0 at that point. Differentiating, we have
dy/dx = 6x ² + 2ax + b
and so when x = 3,
0 = 54 + 6a + b
or
6a + b = -54 … … … [eq1]
The curve passes through the point (4, 2), which is to say y = 2 when x = 4. So we also have
2 = 128 + 16a + 4b - 30
or
16a + 4b = -96
4a + b = -24 … … … [eq2]
Eliminate b by subtracting [eq2] from [eq1] and solve for a, then for b :
(6a + b) - (4a + b) = -54 - (-24)
2a = -30
a = -15 ===> b = 96
Let s1 = k and define sn+1 = √4sn − 1 for n ≥ 1. Determine for what values of k the sequence (sn) will be monotone increasing and for what values of k it will be monotone decreasing.
Answer:
The answer is "[tex]\bold{\frac{1}{4}<k\leq 2+\sqrt{3}}[/tex]"
Step-by-step explanation:
Given:
[tex]\ S_1 = k \\\\ S_{n+1} = \sqrt{4S_n -1}[/tex] [tex]_{where} \ \ n \geq 1[/tex]
In the above-given value, [tex]S_n[/tex] is required for the monotone decreasing so, [tex]S_2 :[/tex]
[tex]\to \sqrt{4k-1} \leq \ k=S_1\\\\[/tex]
square the above value:
[tex]\to k^2-4k+1 \leq 0\\\\\to k \leq 2+\sqrt{3} \ \ \ \ \ and \ \ 4k+1 >0\\\\[/tex]
[tex]\bold{\boxed{\frac{1}{4}<k\leq 2+\sqrt{3}}}[/tex]
use the product of powers property to simplify the numeric expression.
4 1/3 • 4 1/5 = _____
Answer:
The value of [tex]4^{\dfrac{1}{3}} {\cdot} 4^{\dfrac{1}{5}[/tex] is [tex]4^{\dfrac{8}{15}}[/tex] .
Step-by-step explanation:
We need to simplify the numeric expression using property. The expression is as follows :
[tex]4^{\dfrac{1}{3}} {\cdot} 4^{\dfrac{1}{5}[/tex]
The property to be used is : [tex]x^a{\cdot} x^b=x^{a+b}[/tex]
This property is valid if the base is same. Here, base is x.
In this given problem, x = 4, a = 1/3 and b = 1/5
So,
[tex]4^{\dfrac{1}{3}} {\cdot} 4^{\dfrac{1}{5}}=4^{\dfrac{1}{3}+\dfrac{1}{5}}\\\\=4^{\dfrac{5+3}{15}}\\\\=4^{\dfrac{8}{15}}[/tex]
So, the value of [tex]4^{\dfrac{1}{3}} {\cdot} 4^{\dfrac{1}{5}[/tex] is [tex]4^{\dfrac{8}{15}}[/tex] .
What is $121 divided into ratio of 7:4
Answer:
77:44
Step-by-step explanation:
Since 7:4 is equal to 11 and 121/11, each ratio can be multiplied by 11.