[tex]\begin{gathered} 9 - 4\sqrt{5} \\ \\ = 4 + 5 - 4\sqrt{5} \\ \\ = (- 2)^2 + (\sqrt{5})^2 + (2 \times - 2 \times \sqrt{5}) \\ \\ = (- 2 + \sqrt{5})^2 \\ \\ = (\sqrt{5} - 2)^2 \\ \\ \\ \therefore \sqrt{9 - 4\sqrt{5}} = \sqrt{5} - 2 \end{gathered}[/tex]
Hope this may be helpful.
Melissa bought 42 pine seedlings and 30 juniper seedlings
to plant in rows on her tree farm. She wants each row to
have the same number of seedlings. She wants only one
type of seedling in each row. What is the greatest number of
seedlings she can plant in each row? How many rows of each
type
of tree will there be?
Answer:
See below
Step-by-step explanation:
GCF (greatest common factor ) of 42 and 30 is 6
each row will have 6 seedlings
there will be ( 42+30) / 6 = 12 rows
7 pine rows 5 juniper rows
La nota de Karina en su curso de nivelación matemática es 7 veces la cantidad de factores primos que tiene el siguiente polinomio:
P (a; b; c) =a(a +b-c) +b(a+ b-c) +c(a +b- c)
Hallar la nota que obtuvo.
Karina obtuvo una nota final de 84 de 100 puntos en su curso de nivelación matemática.
¿Qué nota obtuvo Karina obtuvo en su curso de nivelación matemática?
Antes de comenzar la resolución de este problema, asumimos que la base de calificación del curso de nivelación matemática es 100 y que la nota mínima para pasar es 70. Por otra parte, sabemos que la nota obtenida por Karina es divisible por 7 y que es el producto de aquel número primo y un polinomio formado por una relación de tres números primos, la cual es simplificada a continuación:
p (a, b, c) = a · (a + b - c) + b· (a + b - c) + c · (a + b - c)
p (a, b, c) = a² + a · b - a · c + a · b + b² - b · c + a · c - b · c - c²
p (a, b, c) = a² + 2 · a · b + b² - c²
p (a, b, c) = (a + b)² - c²
p (a, b, c) = (a + b + c) · (a + b - c)
Si asumimos que Karina obtuvo 84, entonces se tiene que 84 = 7 × 12 y 12 = 2 × 6. Tanto el dos como el seis son múltiplos de dos, entonces asumimos a = b = c y encontramos que:
n (2, 2, 2) = 7 · (2 + 2 + 2) · (2 + 2 - 2)
n (2, 2, 2) = 7 · 6 · 2
n (2, 2, 2) = 84
En síntesis, Karina obtuvo una nota final de 84 de 100 puntos en su curso de nivelación matemática.
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In the geometric pattern below, n represents the number of blocks in the bottom row of each figure.
n = 1
n=2
Write a function that models the total number of blocks in terms of n.
OA f(1) = 2; f(n) = f(n-1) + 2n; for n ≥ 2
OB. f(1) = 1; f(n) = f(n-1) + 2n; for n ≥ 2
Oc f(1) = 1; f(n) = f(n-1) + n; for n ≥ 2
OD. f(1) = 2; f(n) = f(n-1) + 4n; for n ≥ 2
n=3
Complete the function for this graph.
-5
ertificati...
5
-5
y = |x|+ [?]
Hint: y = |x-h| + v
Answer:
-5
Step-by-step explanation:
The y coordinate of the vertex is -5.
R = 15 when m = 6 s= 4 inversely when m=24 s =4
The value of r If r varies directly with the square of m and inversely with s is 240
Variation
Suppose r varies directly with the square of m and inversely with s.
If r varies directly with the square of m and inversely with s, then;
r = km²/s
Given that R = 15 when m = 6 s= 4
15 = k(6)²/4
60 = 36k
k = 60/36
k = 5/3
If the value of m = 24 and s = 4, hence;
r = 5/3*24²/4
r = 240
Hence the value of r If r varies directly with the square of m and inversely with s is 240
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The average heart rate of an adult human is 72 beats per minute. For an adult elephant, the average heart rate is 35 beats per minute.
A. Whose heart beats more times in one hour
B. Whose heart makes 1,000,000 beats in less time
Answer:
A. the adult human
B. the adult human
Step-by-step explanation:
A. There are 60 minutes in an hour, and the human's heart beats 72 bpm (beats per minute). If you multiply 60 by 72, you get 4,320 bpm. If you multiply 60 by 35, you only get 2,100 bpm.
B. If you use the same logic that 72 is greater than 35, than you can assume that the human hear makes 1,000,000 beats in less time. However, if you want to do the math, then simply divide 1,000,000 by 72. Then, divide 1,000,000 by 35. Whichever has the smaller number is the one that can make more heart beats in a faster time.
Rationalize the denominator and simplify
√a+1-2/√a+1+2
5+a-4√(a+1)/(a-3) is the simplified form of the number. This can be obtained by multiplying numerator and denominator with conjugate of the denominator.
Simplify the number:Given the number,
√a+1-2/√a+1+2
Denominator = √a+1+2
Conjugate of the denominator = √a+1 - 2
Now, (√a+1-2)(√a+1 - 2 )/√(a+1+2)(√a+1 - 2 )
=(√a+1 - 2 )²/(√a+1)² - 4
=(a+1 -4√a+1+5)/(a+1-4)
=5+a-4√(a+1)/(a-3)
Hence 5+a-4√(a+1)/(a-3) is the simplified form of the number.
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The function g is related to one of the parent functions g(x) = x2 – 3 The parent function is: f(x)= x^2 Use function notation to write g in terms of f.
g(x) is a translation of f(x), we have:
g(x) = f(x) - 3
How to write g(x) in terms of f(x)?
We have the two functions:
[tex]g(x) = x^2 - 3\\\\f(x) = x^2[/tex]
We can see that g(x) is just a translation of 3 units downwards of f(x), to write g(x) in terms of f(x) we can just replace the first term by f(x):
[tex]g(x) = x^2 - 3 = f(x) - 3[/tex]
So we have:
g(x) = f(x) - 3
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What is the best approximation of the solution to the system to the nearest integer values?
Answer:
(-2, 6)
Step-by-step explanation:
3x - 4y = -32
3x + 5y = 24
-9y = -56
y = [tex]\frac{56}{9}[/tex] = 6
3x - 4*[tex]\frac{56}{9}[/tex] = -32
3x - [tex]\frac{224}{9}[/tex] = -32
3x = -32 + [tex]\frac{224}{9}[/tex]
3x = -[tex]\frac{288}{9}[/tex]+ [tex]\frac{224}{9}[/tex]
3x = -[tex]\frac{64}{9}[/tex]
x = -[tex]\frac{64}{27}[/tex] = -2
101.19 / 4 using long division
Ram bough some pen for Rs 90. If he paid Rs 1 less for each he would have 3 more pens. How many pens did he buy?
Based on the fact that Ram bought some pens and they cost Rs.90 but if he had paid Rs.1 less for each he would have 3 more pens, the number of pens he bought is 6 pens.
What number of pens did Ram buy?This can be represented as:
(x + 3) (y - 3) = 90
Where xy = 90
xy - 3x + 3y - 9 = xy
3y - 3x - 9 = 0
y - x - 3 = 0
x - y + 3 = 0
Solving further gives:
x - 90/ x + 3 = 0
x² + 3x - 90 = 0
Remembering that:
90 = 9 x 10
= 3 x 3 x 2 x 5
= 15 x -6
Going back to the formula:
x (x + 15) - 6 (x + 15)
(x + 15) (x - 6) = 0
x - 6 = 0
x = 6 pens
In conclusion, the number of pens bought was 6 pens.
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Evaluate functions from their graph g(−9)=
See the Correct Answer Attached!
Evaluating the function from the given graph, g(-9) = 1.
How to Evaluate a Function?To find the value of a function for a given x-value using a given graph, trace the x-value against the corresponding y-value on the y-axis.
To evaluate the function from the graph given, for g(-9), find the y-value that corresponds to the x-value of -9.
The graph shows that when x = -9, the corresponding y-value is 1.
Therefore, g(-9) = 1.
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help this is affecting my grade i need help pls i beg of you
Mal works at a photo gallery. He charges $50 for a large photo and $40 for a large frame. Sales tax is 5%. How much total tax will a customer pay on both?Answer the questions to show how to write and simplify expressions that represent the problem
1. One way to calculate the total tax is 0.05(50 + 40). Use the order of operations to evaluate this expression. Show your work. (2 points)
Answer:
$4.50
Step-by-step explanation:
Okay so, first add both.
50+40 is 90, then multiply 90 by the tax percent which is
90x5%=4.5
If expression then,
x=money that they have to pay.
5%(50+40)=x (the original)
btw there's already a question like this :
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4. In the figure above ABCD is a parallelogram with
mLB = 60°, BC = XC = AZ = 4, XZ BC. What
is the perimeter of parallelogram ABCD?
Answer:
G. 24
Step-by-step explanation:
The perimeter of the figure is the sum of its side lengths. The given dimensions tell us all of the side lengths.
AnalysisTriangle BCX is given as an isosceles triangle with a base angle of 60° and side lengths of 4. Such a triangle is equilateral, so all side lengths will have a measure of 4.
The given information tells us all sides that appear parallel are parallel, so the figure consists of 4 equilateral triangles. Every short line segment has length 4.
PerimeterThe perimeter is the length of 6 short line segments, so is ...
P = 6×4 = 24
The perimeter of parallelogram ABCD is 24 units.
Find the area between the two functions
The area between the two functions is 0
How to determine the area?The functions are given as:
f₁(x)= 1
f₂(x) = |x - 2|
x ∈ [0, 4]
The area between the functions is
A = ∫[f₂(x) - f₁(x) ] dx
The above integral becomes
A = ∫|x - 2| - 1 dx (0 to 4)
When the above is integrated, we have:
A = [(|x - 2|(x - 2))/2 - x] (0 to 4)
Expand the above integral
A = [(|4 - 2|(4 - 2))/2 - 4] - [(|0 - 2|(0 - 2))/2 - 0]
This gives
A = [2 - 4] - [-2- 0]
Evaluate the expression
A = 0
Hence, the area between the two functions is 0
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that any pair of congruent triangles is similar True or false.
Answer:
yes it's true no problem sir
a map has a scale of 2in: 6mi. if a two twons on a map is 10 in apart then how far apart are the real twons
Answer: 30 miles
Work Shown:
2 in : 6 mi
5*2 in : 5*6 mi
10 in : 30 mi
Simplify the following fractions.
Answer =
[tex] \frac{9}{16 \\ \\ } [/tex]
Show me step by step
Answer:
Expressions with numerous operators must be simplified in "BODMAS" order only, from left to right. The brackets are solved first, followed by powers or roots,division, or multiplication (whatever comes first from the left side of the formula), and finally subtraction or addition. The BODMAS simplification of fractions is a solution for addressing fractions that include many operations such as addition (+), subtraction (-), multiplication (×),division(÷), and brackets ().[tex] \pink{\maltese{ \text{BODMAS \:Full \: Form \: }}}[/tex]
To make numerical equations easier to understand, operations must be performed according to the BODMAS rule, which involves division, multiplication, addition, and subtraction to be performed in the order brackets.For example,The expression (48-24)÷3×4 as per BODMAS rule.
(48-24)÷3×4
=24÷3×4
=8×4
=32
Now,
The given question is,
Simplify:
[tex] \displaystyle{ \frac{7}{8} \div 5 \frac{1}{3} \times \frac{24}{7} }[/tex]
[tex] \displaystyle{ = \frac{7}{8} \div \frac{16}{3} \times \frac{24}{7} }[/tex]
[tex] \displaystyle{ = \frac{ \cancel{7} \times 3 \times \cancel{24} \: {}^{3} }{ \cancel{8 } \times 16 \times \cancel{7}} }[/tex]
[tex] \displaystyle{ = \frac{3 \times 3}{16} }[/tex]
[tex] \displaystyle{} = \frac{9}{16} [/tex]
Thus,the final answer is 9/16.
Solution -:
[tex] \frac{7}{8} \div 5 \frac{1}{3} \times \frac{24}{7} [/tex]
Let's begin-
solve,,,
Now,,According to BODMAS rule fist we divide ,
[tex] \frac{7}{8} \times \frac{3}{16} \times \frac{24}{7} \\[/tex]
Now , we multiple
[tex] \frac{3 \times 3}{16} \\ \\ = \frac{9}{16} [/tex]
and this is our final answers
▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃
Division → Multiplication → Addition → Subtraction
B stand bracket O stand of D stand divisionM stand MultiplicationA stand for additionS stand for subtractionA pension fund manager is considering three mutual funds. The first is a stock fund, the second is a long-term government and corporate bond fund, and the third is a T-bill money market fund that yields a sure rate of 5.5%. The probability distributions of the risky funds are:
Suppose now that your portfolio must yield an expected return of 12% and be efficient, that is, on the best feasible CAL.
This problem is about pension fund management. It is to be noted that the best Feasible Capital Allocation Line (CAL) is: 0.3162.
What is Capital Allocation Line (CAL)?
A graph's capital allocation line depicts all conceivable combinations of risky and risk-free assets, allowing investors to estimate future returns depending on risk.
What is the calculation for the above solution?
It is to be noted that the optimal risky portfolio's stock percentage is determined by:
Weight of Stock = ((Return on Stock - Risk Free Rate) * Variance of bond) - ((Return on Bond - Risk Free Rate) * Co-Variance of bond & Stock)/ ((Return on Stock - Risk Free Rate) * Variance of bond + (Return on Bond - Risk Free Rate) * Variance of Stock - ((Return on Bond - Risk Free Rate + Return on Stock - Risk Free Rate + ) * Co-Variance of bond & Stock)
→ The weight of stock
= ((15% - 5.5%) * 529) - ((9% - 5.5%) * 110.40)/ ((15% - 5.5%) * 529) + (9% - 5.5%) * 1,024 - ((15% - 5.5% + 9% - 5.5%) * 110.40)
= [(50.255) * (3.864) /(50.255) + (46.08) - (14.352)]
Weight of Stock = 0.646628
Weight of Bonds = 1 - 0.646628
Weight of Bonds= 0.353372
Expected return of portfolio = 0.646628 * 15% + 0.353372 * 9%
= 12.88%
Standard Deviation of Portfolio (SDP)= (0.6466282² * 1,024 + 0.3533722² * 529 + 2 * 0.646628* 0.353372* 110.40)⁰·⁵
SDP = (544.67)⁰·⁵
SDP = 23.34%
Hence,
Best feasible CAL = (12.88% - 5.5%)/ 23.34%
Best feasible CAL = 0.3162
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Full Question
See the attached spread sheet for additional information related to the questions.
pls need help
ersrsreerre
The computation shows that the salesman that has the highest total earnings for the three weeks period will be salesman A.
How to compute the value?It should be noted that from the information given, we are given the information about three salesmen and their sales.
The total earnings for salesman A will be:
= (1300 × 3) + 65 × (11 + 14 + 16)
= 3900 + 2730
= 6630
The total earnings for salesman B will be:
= 300 × 3 + 40 × (14 + 15 + 13)
= 900 + 1680
= 2580
The total earnings for salesman C will be:
= 900 × 3
= 2700
Therefore, the computation shows that the salesman that has the highest total earnings for the three weeks period will be salesman A.
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what is the range if the given function?
Answer:
Second option
Step-by-step explanation:
The range is the set of output values a function can take. As shown in the table, as x is substituted in, y is the corresponding value.
On a recent trip to the convenience store, you picked up 2 gallons of milk, 6 bottles of water, and 7 snack-size bags of chips. Your total bill (before tax) was $25.65. If a bottle of water costs twice as much as a bag of chips, and a gallon of milk costs $1.90 more than a bottle of water, how much does each item cost?
Answer:
The water costs $1.90, the chips are $.95 and the milk is $3.80.
Step-by-step explanation:
Let m = milk
Let w = water
Let c = chips
2m+6w+7c =25.65 w = 2c m = w + 1.90
For the first equation, substitute w for 2C and m for w + 1.90 to get:
2(w+1.90) +6(2c) + 7c = 25.65
2w+3.8+12c+7c=25.65
2w+19c = 21.85
Now substitute 2c for w:
2(2c)+19c =21.85
4c + 19c = 21.85
23c = 21.85
c = .95 Now that we know the cost of the chips we can use that to find the water and the milk for the original equations that we wrote at the top.
w = 2c
w=2(.95) = 1.90
m = w + 1.90 = 1.90+1.90 = 3.80
60 POINTS IF CORRECT AND BRAINLIEST ANSWER FOR COMPLETE ANSWER
1. The solution to the first percent puzzle is as follows:
75% 66²/₃ 11¹/₉
33¹/₃% 25% 22¹/₅% 3⁷/₁₀%
50% 37¹/₂% 33¹/₃% 5¹/₂%
50% 37¹/₂% 33¹/₃% 5¹/₂%
2. The solution to the second percent puzzle is as follows:
10% 90%
50% 5% 45%
50% 5% 45%
What is a percent puzzle?A percent puzzle is a puzzle that engages students to practice working with percentages.
The percent puzzle involves a matrix format, in which students multiply the column percent by the row percent to find the percent they must put in the missing boxes to complete the puzzle.
The multiplication results for the missing boxes can be either stated in decimals, fractions, or a combination.
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PLEASE HELP!!
From the triangle below, if AD=2 and CD=8. Find the Length of side AB
Which of the following rational functions is graphed below?
Answer:
A
Step-by-step explanation:
If you were to substitute 2 or -3 into equation A, the denominator would be zero and you would have to divide by zero. Thus there are asymptotes for this function at -3 and 2, matching the graph
Triangles ABC and A''B''C'' are similar. Identify the type of reflection performed and the scale factor of dilation.
The type of reflection performed and the scale factor of dilation of the diagram are; Reflection over the x-axis and a scale factor dilation of 2.
How to Identify Transformation used on diagram?From the given diagram, we are told that triangle ABC is transformed into Triangle A"B"C".
Now, we are told that both triangles are similar and as such if they are similar then, it means each corresponding side has the same ratio. Thus, there was a dilation by a scale factor of 2.
Now, the reflection that took place after the dilation would be a reflection over the x-axis.
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In the town of Rockville, 3/5 of the students in middle school participate in organized sports after school. If 1/4 of them play basketball, what fraction of the students play basketball?
The fraction of students that play basketball is [tex]\mathbf{= \dfrac{1}{10}}[/tex].
What is the fraction of students that play basketball?The fraction of students that play basketball from the given information can be determined by assuming that the whole number of students in the middle school is whole i.e. (1)
Let us first determine the number of students that participate in sports, we have:
[tex]\mathbf{=1- \dfrac{3}{5}}[/tex]
[tex]\mathbf{= \dfrac{2}{5}}[/tex]
If 1/4 of these students play basketball, then we have:
[tex]\mathbf{= \dfrac{1}{4}\times (\dfrac{2}{5})}[/tex]
[tex]\mathbf{= \dfrac{1}{10}}[/tex] students play basketball.
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Someone please help with this question!
The value of angle 20 is as follows:
m∠20 = 50.9 degrees.
How to find angles when parallel lines are cut by a transversal?When parallel lines are cut by a transversal, angle relationships are formed. This include corresponding angles, alternate angles , vertical angles etc.
Therefore, line l and m are parallel lines cut by the two transversal.
Hence,
m∠6 ≅ m∠20 (alternate angles)
Therefore, alternate angles are congruent
m∠20 = 2x - 4
m∠19 + m∠20 = 180 (angles on a straight line)
5x - 8 + 2x - 4 = 180
7x - 12 = 180
7x = 180 + 12
7x = 192
x = 192 / 7
x = 27.4285714286
x = 27.43
Therefore,
m∠20 = 2(27.43) - 4
m∠20 = 50.8571428571
m∠20 = 50.9 degrees.
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Enter the letter of the graphed
function.
-
-
a.y = (x + 2)(x − 1)(x − 3)
b.y = (x + 2)(x - 1)(x - 3)²
-
c. y = (x + 2)(x − 3)(x - 1)²
d.y= (x - 1)(x − 3)(x + 2)²
e.y = (x - 1)(x - 3)(x + 2)³
The graphed function is: y = (x + 2)(x − 1)(x − 3).
Option (a) is correct.
From the graph given in the question, it can be seen that the graph has 3 critical points, namely, x= -2, x = 1 and x = 3.
From all the five options given, the first option, that is, y = (x + 2)(x − 1)(x − 3), has the critical points x= -2, x = 1 and x = 3.
The critical points for a function are obtained by substituting the function to be equal to zero.
So, (x + 2)(x − 1)(x − 3) = 0
That is, x= -2, x = 1 and x = 3.
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