Answers
Answer:
y = 54/25
Step-by-step explanation:
y = p×q^(x-1)
when x = 1 then y = 10
so,
10 = p×q^(1-1)
or, 10 = p×1
or, p = 10
when x = 6 then y = 0.7776
0.7776=p×q^(6-1)
or, 0.7776=p×q^5
or, 0.7776=10×q⁵
[0.7776 = 7776/10000 = 486/625]
or, 486/625 = 10×q⁵
or, 486/6250=q⁵
or, [tex] \frac{ \sqrt[5]{486} }{ \sqrt[5]{6250} } = q[/tex]
or, [tex]q = \frac{3 \sqrt[5]{2} }{5 \sqrt[5]{2} } [/tex]
or, q = 3/5
so, when x = 4
y = p×q^(x-1)
y = 10×(3/5)^(4-1)
y = 10×(3/5)^3
y = 10×27/125
y = 54/25
Related Questions
Can anyone help me please??
Answers
Answer:
-20x / (x-12) = y
Step-by-step explanation:
3/x - 5/y = 1/4
Multiply each side by 4xy to clear the fractions
4xy ( 3/x - 5/y = 1/4)
Distribute
12y - 20x = xy
Subtract 12y from each side
-20x = xy -12y
Factor out y
-20x = y(x-12)
Divide each side by (x-12)
-20x / (x-12) = y
log, (x + y)=log, y, log, x .
Solve for question D only
Answers
Answer:
4.
Step-by-step explanation:
Change of base formula is
logb x = loga x / loga b
So logx 25 = log5 25 /log5 x
Now log5 25 = log5 5^2 = 2, so:
logx 25 = 2 / log5 x
So log5 x^2 * logx 25
= log5 x^2 * 2 /log5 x
= 2 log5 x * 2 / log5 x
= 4.
The sum of 8 times a number and 7 equals 9!
Answers
Answer:
0.25*8+7=9
Step-by-step explanation:
8x+7=9
2/8=x
0.25=x
A bag contains 4 white and 2 black balls of the same size and weight and two balls are selected at random without replacement,what are the possible outcomes ?
Answers
Answer:
Step-by-step explanation:
Total balls in bag = 4+2
= 6 balls
Total white balls = 4
Total black balls = 2
The possible outcomes are
Black and Black or White and White or White and Black or Black and White.
Probability of black and black = 2/6
= 1/3
Probability of white and white = 4/6
= 2/3
Probability of Black and white or White and black
= 1/3×2/3
= 2/9
please click thanks and mark brainliest if you like :)
possible outcomes will be white and black, white and white, black and white or black and black
Divide 500 in the ratio 4:5:1
Answers
Answer:
200 : 250 : 50
Step-by-step explanation:
Sum the parts of the ratio, 4 + 5 + 1 = 10 parts
Divide the amount by 10 to find the value of one part
500 ÷ 10 = 50 ← value of 1 part of ratio , then
4 parts = 4 × 50 = 200
5 parts = 5 × 50 = 250
500 = 200 : 250 : 50
Answer:
200, 250 and 50.
Step-by-step explanation:
First find the 'multiplier'.
4 + 5 + 1 = 10
500/10 = 50 = multiplier.
So the answer is
4*50 = 200
5 * 50 = 250
and 1 * 50 = 50.
Find the center, vertices, and foci of the ellipse with equation 4x2 + 9y2 = 36. Center: (0, 0); Vertices: (-3, 0), (3, 0); Foci: Ordered pair negative square root 5 comma 0 and ordered pair square root 5 comma 0 Center: (0, 0); Vertices: (-9, 0), (9, 0); Foci: Ordered pair negative square root 65 comma 0 and ordered pair square root 65 comma 0 Center: (0, 0); Vertices: (0, -3), (0, -3); Foci: Ordered pair 0 comma negative square root 5 and ordered pair 0 comma square root 5 Center: (0, 0); Vertices: (0, -9), (0, 9); Foci: Ordered pair 0 comma negative square root 65 and ordered pair 0 comma square root 65
Answers
Answer:
Option A.
Step-by-step explanation:
The given equation of ellipse is
[tex]4x^2+9y^2=36[/tex]
Divide both sides by 36.
[tex]\dfrac{4x^2}{36}+\dfrac{9y^2}{36}=1[/tex]
[tex]\dfrac{x^2}{9}+\dfrac{y^2}{4}=1[/tex]
[tex]\dfrac{x^2}{3^2}+\dfrac{y^2}{2^2}=1[/tex] ...(1)
The standard form of an ellipse is
[tex]\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2}=1[/tex] ...(2)
where, (h,k) is center, (h±a,k) are vertices and (h±c,k) are foci.
On comparing (1) and (2), we get
[tex]h=0,k=0,a=3,b=2[/tex]
Now,
Center [tex]=(h,k)=(0,0)[/tex]
Vertices [tex]=(h\pm a,k)=(0\pm 3,0)=(3,0),(-3,0)[/tex]
We know that
[tex]c=\sqrt{a^2-b^2}=\sqrt{3^2-2^2}=\sqrt{5}[/tex]
Foci [tex]=(h\pm c,k)=(0\pm \sqrt{5},0)=(\sqrt{5},0),(-\sqrt{5},0)[/tex]
Therefore, the correct option is A.
Jeff is playing a racing game. The game awards him an initial of virtual money. In addition, he gets of virtual money for each race he wins. In the end, he calculates average earnings of for each race he won. If represents the number of races he won, which equation can be used to find the number of wins? A. B. C. D.
Answers
How is multiplying 3 - 2i by ia represented on the complex plane?
Drag a term or measure into each box to correctly complete the statements
The complex number 3 - 2i lies in quadrant IV
of the complex plane. When any complex number is multiplied by the
imaginary unit, the complex number undergoes a
90°
rotation in a counterclockwise direction This means that
the complex product of 3 - 2i and 22 lies in
quadrant I
of the complex plane.
Answers
The equation is represented 3 units to the left of the complex plane and 2 units up.
What is complex equation?A complex equation is an equation that involves complex numbers when solving it. A complex number is a number that has both a real part and an imaginary part.
Well to see how this is represented, we first need to multiply it out so we can see how it looks when it is simplified!
[tex]=(3-2i)(i^2)\\\\\\i^2=-1\\\\\\=(3-2i)(-1)\\\\\\=(-3+2i)[/tex]
We know that on a complex plane, our imaginary numbers are represented on the vertical axis.
So the original expression, (3-2i) would have been 3 units to the right on a complex graph and 2 units downward!
The equation I input above should be pretty straightforward, but one thing I didn't mention was that i^2 should = -1 when dealing with complex numbers!
Therefore, the equation 3-2i * i^2 is equal to -3 + 2i, this is graphed 3 units to the left and to units upward!
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A number is multiplied by 8, and that product is added to 2. The sum is equal to the product of 2 and 25. Find the number.
Answers
Answer: the number = 6
Step-by-step explanation:
Let x be the number.
Set equation according to the information given
2 + 8x = 2 × 25
Simplify by multiplication
2 + 8x = 50
Subtract 2 on both sides
2 + 8x - 2 = 50 - 2
8x = 48
Divide 8 on both sides
8x / 8 = 48 / 8
[tex]\boxed {x=6}[/tex]
Hope this helps!! :)
Please let me know if you have any questions
Name the property of real numbers illustrated by the equation
Answers
Answer:
A. Commutative property
Step-by-step explanation:
The commutative property states that multiplication can be performed in any order. This means that a*b=b*a. Therefore, it does not matter whether [tex]\sqrt{2}[/tex] or 3 is first in the multiplication problem. So, the first answer is correct.
The radius of a sphere is measured as 7 centimeters, with a possible error of 0.025 centimeter.
Required:
a. Use differentials to approximate the possible propagated error, in cm3, in computing the volume of the sphere.
b. Use differentials to approximate the possible propagated error in computing the surface area of the sphere.
c. Approximate the percent errors in parts (a) and (b).
Answers
Answer:
a) dV(s) = 15,386 cm³
b) dS(s) = 4,396 cm²
c) dV(s)/V(s) = 1,07 % and dS(s)/ S(s) = 0,71 %
Step-by-step explanation:
a) The volume of the sphere is
V(s) = (4/3)*π*x³ where x is the radius
Taking derivatives on both sides of the equation we get:
dV(s)/ dr = 4*π*x² or
dV(s) = 4*π*x² *dr
the possible propagated error in cm³ in computing the volume of the sphere is:
dV(s) = 4*3,14*(7)²*(0,025)
dV(s) = 15,386 cm³
b) Surface area of the sphere is:
V(s) = (4/3)*π*x³
dV(s) /dx = S(s) = 4*π*x³
And
dS(s) /dx = 8*π*x
dS(s) = 8*π*x*dx
dS(s) = 8*3,14*7*(0,025)
dS(s) = 4,396 cm²
c) The approximates errors in a and b are:
V(s) = (4/3)*π*x³ then
V(s) = (4/3)*3,14*(7)³
V(s) = 1436,03 cm³
And the possible propagated error in volume is from a) is
dV(s) = 15,386 cm³
dV(s)/V(s) = [15,386 cm³/1436,03 cm³]* 100
dV(s)/V(s) = 1,07 %
And for case b)
dS(s) = 4,396 cm²
And the surface area of the sphere is:
S(s) = 4*π*x³ ⇒ S(s) = 4*3,14*(7)² ⇒ S(s) = 615,44 cm²
dS(s) = 4,396 cm²
dS(s)/ S(s) = [ 4,396 cm²/615,44 cm² ] * 100
dS(s)/ S(s) = 0,71
helppppppppppppppppp pllllzzzzz
a
b
c
Answers
Answer:
b rectángulo de la referencia de los números que están por debajo de la construcción de un triángulo obtusangulo
if a point is chosen inside the large circle what is the probability that it will also be inside the small circle?
Answers
Answer:
1/4
Step-by-step explanation:
The probability will be equal to 1 - (probability that it will not be inside the small circle) = 1 - (pi*4-pi)/(pi*4)=1/4
Which equation represents a population of 210 animals that decreases at an annual rate of 14%
Answers
Answer:
The equation i.e. used to denote the population after x years is:
P(x) = 490(1 + 0.200 to the power of x
Step-by-step explanation:
This problem could be modeled with the help of a exponential function.
The exponential function is given by:
P(x) = ab to the power of x
where a is the initial value.
and b=1+r where r is the rate of increase or decrease.
Here the initial population of the animals are given by: 490
i.e. a=490
Also, the rate of increase is: 20%
i.e. r=20%
i.e. r=0.20
Hence, the population function i.e. the population of the animals after x years is:
P(x) = 490(1 + 0.200 to the power of x
So for this, we will be using exponential form, which is y = ab^x (a = initial value, b = growth/decay).
Since we start off with 210 animals, that is our a variable.
Next, since this is *decreasing* by 14%, you are to subtract 0.14 (14% in decimal form) from 1 to get 0.86. That will be your b variable.
Putting everything together, your equation is y = 210(0.86)^x
A couple has a total household income of $84,000. The husband earns $18,000 less than twice what the wife earns. How much does the wife earn? Select the correct answer below:
Answers
Answer:
$34000
Step-by-step explanation:
We can set up a systems of equations, assuming [tex]h[/tex] is the husbands income and [tex]w[/tex] is the wife's income.
h + w = 84000
h = 2w - 18000
We can substitute h into the equation as 2w - 18000:
(2w - 18000) + w = 84000
Combine like terms:
3w - 18000 = 84000
Add 18000 to both sides
3w = 102000
And divide both sides by 3
w = 34000
Now that we know how much the wife earns, we can also find out how much the husband earns by substituting into the equation.
h + 34000 = 84000
h = 50000
Hope this helped!
reflect the x axis A B C D
Answers
Answer:
see explanation
Step-by-step explanation:
Under a reflection in the x- axis
a point (x, y ) → (x, - y ) , then
A (- 1, - 17 ) → A' (- 1, 17 )
B (0, - 12 ) → B' (0, 12 )
C (- 5, - 11 ) → C' (- 5, 11 )
D (- 6, - 16 ) → D' (- 6, 16 )
slope=-3, passing through (-9, -9)
Answers
Hey there! I'm happy to help!
We want to find the equation of a line in y-intercept form, which is y=mx+b, where x and y are a point on the line, m is the slope, and b is the y-intercept.
We already know that our slope is -3.
y=-3x+b
We want to solve for b now. We can plug in our point (-9,-9) to solve for it.
-9=-3(-9)+b
-9=27+b
b=-36
So, our equation is y=-3x-36.
I hope that this helps! Have a wonderful day! :D
B(n)=2^n A binary code word of length n is a string of 0's and 1's with n digits. For example, 1001 is a binary code word of length 4. The number of binary code words, B(n), of length n, is shown above. If the length is increased from n to n+1, how many more binary code words will there be? The answer is 2^n, but I don't get how they got that answer. I would think 2^n+1 minus 2^n would be 2. Please help me! Thank you!
Answers
Answer:
More number of words that can be made: [tex]\bold{2^n}[/tex]
Please refer to below proof.
Step-by-step explanation:
Given that:
The number of binary code words that can be made:
[tex]B(n) =2^n[/tex]
where n is the length of binary numbers.
Binary numbers means 2 possibilities either 0 or 1.
Here, suppose if we have 5 as the length of binary number.
And there are 2 possibilities for each digit.
So, total number of possibilities will be [tex]2\times 2\times 2\times 2\times 2 = 2^5[/tex]
If the length of binary number is 2.
The total words possible are [tex]2^2[/tex].
These numbers are:
{00, 01, 10, 11}
If the length of binary number is 3. (increasing the 'n' by 1)
The total words possible are [tex]2^3[/tex].
These words are:
{000, 001, 010, 100, 011, 101, 110, 111}
So, number of More binary words = 8 - 4 = 4 or [tex]2^2[/tex] or [tex]2^n[/tex].
So, the answer is [tex]2^n[/tex].
Let us try to prove in generic terms:
[tex]B(n) = 2^n[/tex]
Increasing the n by 1:
[tex]B(n+1) = 2^{n+1}[/tex]
Number of more words made by increasing n by 1:
[tex]B(n+1) -B(n)= 2^{n+1} -2^n\\\Rightarrow 2\times 2^{n} -2^n\\\Rightarrow 2^n(2-1)\\\Rightarrow \bold{2^n}[/tex]
Hence, proved that:
More number of words that can be made: [tex]\bold{2^n}[/tex]
A man earns RS.95 in a day how much does we earn in 18 days
Answers
Answer:
RS 17.10
Step-by-step explanation:
If they earn 0.95 a day, you can multiply that income by the number of days, which is 18.
RS 17.10
Identify the slope and y-intercept of the function y = –2x+1.
Answers
Answer:
Below
Step-by-step explanation:
The function is y= -2x +1
● the slope is -2
● the y-intercept is 1
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the
correct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag
the item to the trashcan. Click the trashcan to clear all your answers.
Perform the following computation with radicals. Simplify the answer.
V6 18
311
123 45
6
7
8
+
x
Answers
Question: Perform the following computation with radicals. Simplify the answer. √6 • √8
Answer:
[tex] 4\sqrt{3} [/tex]
Step-by-step explanation:
Given, √6 • √8, to perform the computation, we would simply evaluate the radicals and try as much as possible to leave the answer in the simplest form in radicals.
Thus,
[tex] \sqrt{6}*\sqrt{8} = \sqrt{6*8} [/tex]
[tex] = \sqrt{48} [/tex]
[tex] = \sqrt{16*3} = \sqrt{16}*\sqrt{3}[/tex]
[tex] = 4\sqrt{3} [/tex]
How many 4 digit palidromes are there?
Answers
Which expression is equal to (1+6i)−(7+3i) ?
Answers
Answer:
- 6+3iStep-by-step explanation:
[tex](1+6i)-(7+3i) ?\\Group\:the\:real\:part\:and\:the\:imaginary\\\:part\:of\:the\:complex\:number\\\left(a+bi\right)\pm \left(c+di\right)=\left(a\:\pm \:c\right)+\left(b\:\pm \:d\right)i\\=\left(1-7\right)+\left(6-3\right)i\\1-7=-6\\6-3=3\\=-6+3i[/tex]
In this diagram, bac~edf. if the area of bac= 6 in.², what is the area of edf? PLZ HELP PLZ PLZ PLZ PLZ
Answers
Answer:
Area of ΔEDF = 2.7 in²
Step-by-step explanation:
It's given in the question,
ΔBAC ~ ΔEDF
In these similar triangles,
Scale factor of the sides = [tex]\frac{\text{Measure of one side of triangle BAC}}{\text{Measure of one side of triangle EDF}}[/tex]
[tex]=\frac{\text{BC}}{\text{EF}}[/tex]
[tex]=\frac{3}{2}[/tex]
Area scale factor = (Scale factor of the sides)²
[tex]\frac{\text{Area of triangle BAC}}{\text{Area of triangle EDF}}=(\frac{3}{2})^2[/tex]
[tex]\frac{6}{\text{Area of triangle EDF}}=(\frac{9}{4})[/tex]
Area of ΔEDF = [tex]\frac{6\times 4}{9}[/tex]
= 2.67
≈ 2.7 in²
Therefore, area of the ΔEDF is 2.7 in²
1. Which word best describes how you feel when working on a math assessment? ( point)
bored
excited
anxious
confident
Answers
Answer:
math is really a difficult subject for me. sometimes i feel confident when i get my answers correct, but sometimes i feel bored when i dnt get my answer. Sometimes i feel anxious , sometimes i feel excited to solve the problems.
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Pentagon ABCDE and pentagon A”B”C”D”E” are shown on the coordinate plane below. Which two transformations are applied to pentagon ABCDE to create A”B”C”D”E”?
Answers
Answer:
Translated according to the rule (x, y)⇒ (x+7, y+1) , reflected across the x-axis
Step-by-step explanation:
Transformation involves changing the orientation, or even size of a given figure or object to produce its image. The methods of transformation include; translation, rotation, reflection, and dilation.
Comparing the pentagon ABCDE and A”B”C”D”E”, the two transformations applied are reflection across the x-axis first, then translation.
HELP ASAP PLEASE I WILL MARK BRAINLEST
Show all work to identify the asymptotes and zero of the function f of x equals 6 x over quantity x squared minus 36.
Answers
Answer:
vertical asymptotes
x=6, x=-6
horizontal asymptotes
y=0
zeros (0,0)
Step-by-step explanation:
f(x) = 6x / ( x^2 - 36)
First factor
f(x) = 6x / ( x-6)(x+6)
Since nothing cancels
The vertical asymptotes are when the denominator goes to zero
x-6 = 0 x+6=0
x=6 x= -6
Since the numerator has a smaller power than the denominator (1 < 2), there is an asymptote at y = 0
To find the zeros, we find where the numerator = 0
6x=0
x=0
[tex]\\ \rm\Rrightarrow y=\dfrac{6x}{x^2-36}[/tex]
The h orizontal asymptote
As x has less degree than x²
y=0 is a asymptoteVertical asymptote
x²-36=0x²=36x=±6Find the missing probability. P(A)=7/20,P(A∪B)=191/400,P(A∩B)=49/400 ,P(B)=? A. 7/8 B. 1/4 C. 117/400 D. 19/40
Answers
Answer:
B
Step-by-step explanation:
P(AUB)=P(A)+P(B)-P(A∩B)
191/400=7/20+P(B)-49/400
P(B)=191/400+49/400-7/20=240/400-7/20=12/20-7/20=5/20=1/4
The value of P(B) is 1/4.
What is probability?The probability is defined as the possibility of an event is equal to the ratio of the number of favorable outcomes and the total number of outcomes.
For an experiment having q number of outcomes, the number of favorable outcomes can be denoted by p. The formula to calculate the probability of an event is as follows:
Probability(Event) = Favorable Outcomes/Total Outcomes = p/q
Given data as :
P(A) = 7/20,
P(A∪B) = 191/400,
P(A∩B) = 49/400 ,
P(AUB) = P(A) + P(B) - P(A∩B)
Substitute the values of P(A), P(A∪B) and P(A∩B) in formula,
191/400 = 7/20 + P(B) - 49/400
Rearrange the terms in the equation,
P(B) = 191/400 + 49/400 - 7/20
P(B) = 240/400 - 7/20
P(B) = 12/20 - 7/20
P(B) = 5/20
P(B) = 1/4
Hence, the value of P(B) is 1/4.
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find the domain of the graphed function.
Answers
Both < signs should be greater than OR EQUAL signs, I just couldn’t find that symbol, sorry.
Compute the flux H F of F(x,y) = hxy, x − yi across the boundary of the square given by −1 ≤ x ≤ 1, −1 ≤ y ≤ 1.
Answers
Answer:
4i.
Step-by-step explanation:
To find the flux through the square, we use the divergence theorem for the flux. So Flux of F(x,y) = ∫∫divF(x,y).dA
F(x,y) = hxy,x - yi
div(F(x,y)) = dF(x,y)/dx + dF(x,y)dy = dhxy/dx + d(x - yi)/dy = hy - i
So, ∫∫divF(x,y).dA = ∫∫(hy - i).dA
= ∫∫(hy - i).dxdy
= ∫∫hydxdy - ∫∫idxdy
Since we are integrating along the boundary of the square given by −1 ≤ x ≤ 1, −1 ≤ y ≤ 1, then
∫∫divF(x,y).dA = ∫₋₁¹∫₋₁¹hydxdy - ∫₋₁¹∫₋₁¹idxdy
= h∫₋₁¹{y²/2}¹₋₁dx - i∫₋₁¹[y]₋₁¹dx
= h∫₋₁¹{1²/2 - (-1)/2²}dx - i∫₋₁¹[1 - (-1)]dx
= h∫₋₁¹{1/2 - 1)/2}dx - i∫₋₁¹[1 + 1)]dx
= 0 - i∫₋₁¹2dx
= - 2i[x]₋₁¹
= 2i[1 - (-1)]
= 2i[1 + 1]
= 2i(2)
= 4i