The sample variance for distribution of the means is 9
The average of the squared differences from the Mean is called Variance. Variance is a measure of dispersion, meaning it is a measure of how far a set of numbers is spread out from their average value.
The Standard Deviation is a measure of how spread out numbers are.
Its symbol is σ (the Greek letter sigma)
Its formula is the square root of the Variance
Given: Standard Deviation = 3
Sample size = 36
∴ By formula we get
3 = √(Variance)
∴ 9 = Variance
Thus the sample variance for distribution of the means is 9
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Please HELP!!!!
will give brainliest!!
Answer:
Original equation:
y = a sin(b(θ -c)) + d
a = vertical dilation (stretch) of the amplitude
b = horizontal compression (shrink) of the period
c = horizontal shift (left/right)
d = vertical shift (up/down)
Your function is:
y = 3 sin(3θ + π) - 2
First, put it into the general from by factoring out the three in the argument of the sine:
y = 3 sin(3(θ + π/3)) - 2
a = vertical (amplitude) dilation = 3
b = horizontal (period) compression = 2π/period = 3
c = horizontal shift = π/3 to the left
d = vertical shift = -2
Find the area of the figure
Answer:
36 in.
Step-by-step explanation:
find the area of the rectangle and triangle first
area of rectangle = length x height
aR = (6 + 6) x 5
aR = 12 x 5
aR = 60
area of triangle = base x height x 1/2
aT = (6 + 6) x 4 x 1/2
aT = 12 x 4 x 1/2
aT = 24
now, to find the area of the shaded area subtract the triangle from the rectangle
area = rectangle - triangle
a = 60 - 24
a = 36
What is the best example of elasticity demand in the context university of rwanda
Answer:
Step-by-step explanation:
Elasticity Demand
The flexibility of interest is a significant minor departure from the idea of interest. Request can be delegated as versatile, inelastic, or unitary.Flexible interest is one in which the adjustment of the amount requested because of an adjustment of cost is huge. An inelastic interest is one in which the adjustment of the amount requested because of an adjustment of cost is little.The equation for processing versatility of interest is:(Q1 - Q2)/(Q1 + Q2)
(P1 - P2)/(P1 + P2)
In the event that the recipe makes an outright worth more prominent than 1, the interest is flexible. At the end of the day, the amount changes quicker than the cost. On the off chance that the worth is under 1, the request is inelastic. All in all, the amount changes more slowly than the cost. In the event that the number is equivalent to 1, the flexibility of interest is unitary. All in all, the amount changes at a similar rate as the cost.An illustration of items with a flexible interest is purchaser durables. These are things that are bought inconsistently, similar to a clothes washer or an auto, and can be deferred assuming the cost rises. For instance, vehicle refunds have been extremely fruitful in expanding car deals by diminishing costs.#SPJ10
The vertex of a parabola is (0,0)and the focus is (1/8, 0) . What is the equation of the parabola?
The equation of a parabola whose vertex is (0, 0) and focus is (1 / 8, 0) is equal to x = 2 · y².
How to derive the equation of the parabola from the locations of the vertex and focus
Herein we have the case of a parabola whose axis of symmetry is parallel to the x-axis. The standard form of the equation of this parabola is shown below:
(x - h) = [1 / (4 · p)] · (y - k)² (1)
Where:
(h, k) - Coordinates of the vertex.p - Distance from the vertex to the focus.The distance from the vertex to the focus is 1 / 8. If we know that the location of the vertex is (0, 0), then the standard form of the equation of the parabola is:
x = 2 · y² (1)
The equation of a parabola whose vertex is (0, 0) and focus is (1 / 8, 0) is equal to x = 2 · y².
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What is the volume of the space filled with tissue paper in the packaging box? 81.84 cubic centimeters 105.84 cubic centimeters 198.264 cubic centimeters 222.264 cubic centimeters
The volume of the space filled with tissue paper in the packaging box is 198.264 cubic centimeters
Let l,b,h be the dimensions of small gift box V1 = Volume = l*b*h
= 24cm^3
Dimension of Large box are 2.1l , 2.1b,2.1h
Volume of large box = 2.1 l*2.1b*2.1h
= (2.1)^3*lbh
= (2.1)^3*24
V2 =222.264
Volume filled with tissue paper is V2-V1
222.264 - 24
= 198.264cm^3
Hence The volume of the space filled with tissue paper in the packaging box is 198.264 cubic centimeters
The complete question is shown below
Zoe is packaging a gift to send in the mail. A smaller gift box is placed inside a similar yet larger packaging box. The empty space inside the packaging box is filled with tissue paper to keep the gift box from moving. The dimensions of the larger box are each 2.1 times longer than the corresponding dimensions of the smaller box. The volume of the smaller box is 24 cubic centimeters.What is the volume of the tissue paper in the packaging box?
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y=x+3
y=-x-1
i need to find the solution of equations
Answer:
[tex]\huge\boxed{\sf \{(-2,1)\}}[/tex]
Step-by-step explanation:
Given equations:
y = x + 3
y = -x - 1
By comparing the above equations, we get:
x + 3 = -x - 1
Add x to both sides
x + x + 3 = -1 2x + 3 = -1Subtract 3 to both sides
2x = -1 - 3
2x = -4
Divide 2 to both sides
x = -4/2
x = -2Substitute x = -2 in first equation.
y = x + 3
y = -2 + 3
y = 1So,
Solution Set = {(x,y)}={(-2,1)}[tex]\rule[225]{225}{2}[/tex]
Answer:
[tex]x = - 2 \\ y = 1[/tex]
Step-by-step explanation:
The above are Simultaneous equations.
What are Simultaneous equations?Simultaneous equations are two or more algebraic equations which share same variables like X,Y or X,Y and Z.
They are called simultaneous equations because they can be solved the same time.
From the question,
[tex]y = x + 3 - - - - - - (1) \\ y = - x - 1 - - - - - - (2) \\ Substitute \: equation \: (2)into \: (1) \\ - x - 1 = x + 3 \\ Collect \: liketerms \\ - x - x = 3 + 1 \\ - 2x = 4 \\ Divide \: bothsides \: by \: - 2 \\ \frac{ - 2x}{ - 2} = \frac{4}{ - 2} \\ x = - 2 \\ Substitute \: the \: value \: of \: x \: into \: equation \: (1) \\ y = x + 3 \\ y = - 2 + 3 \\ y = 1 \\ Therefore \: x = - 2 \: \: and \: y = 1[/tex]
please help !!!!!!!!!
Answer:
D. completing the square
Step-by-step explanation:
The process shown rearranges the standard-form quadratic equation to vertex form. It involves factoring out the leading coefficient and distributing the constant so that the variable terms can be written as a perfect square.
What is a perfect square trinomial?A perfect square trinomial is the square of a binomial. It has the form ...
(x +b)² = x² +2bx +b²
Given two variable terms, x² and 2bx, the perfect square trinomial can be formed by adding b², which is the square of half the x-term coefficient.
When b² is added to the sum (x² +2bx), the square is complete. The sum (x² +2bx +b²) can be written as the square (x +b)².
Completing the squareThis process of adding b² to the sum (x² +2bx) will change the polynomial unless a similar quantity is subtracted. That is why the 3rd line of the problem statement show 4 being added and subtracted inside parentheses:
y = 5(x² +4x +4 -4) -17
When we're applying this transformation, we do not want to change the equation. We simply want to rearrange it.
In the next step, the subtracted term is brought outside the parentheses. This lets us write the quantity in parentheses as a perfect square.
y = 5(x² +4x +4) +5(-4) -17
y = 5(x² +4x +4) -20 -17
This process of adding and subtracting a suitable quantity and rearranging the equation so the variable terms make a perfect square is called ...
"completing the square."
__
Additional comment
The equation in this form is said to be in "vertex form."
y = a(x -h)² +k
In this form, the constant 'a' is a vertical scale factor; the ordered pair (h, k) identifies the vertex of the quadratic on a graph.
Express each of the following subsets with bit strings (of length 10) where the ith bit (from left to right) is 1 if i is in the subset and zero otherwise.
Subsets with bit strings:
001110000010100100010111001110What are subsets?A set A is a subset of a set B if all of its items are also elements of B; B is, therefore, a superset of A. A and B can be equal; if they are unequal, then A is a legitimate subset of B. Inclusion refers to the relationship of one set being a subset of another.To find the subsets with bit strings:
We need to express a) b) and c) into bit strings.
Firstly, a number of elements in the universal set represent the number of bits in the bit string.
Secondly, 1 = yes element is present in both universal sets as well as in subset.
0 = No, the element is not present in the subset but present in the universal set.
Hence, we have:
a) Subset {3,4,5} = 0011100000 (As there are 3 1's which means only 3,4,5 are present in both universal set and subset.
Similarly,
b) Subset {1, 3, 6, 10} = 1010010001
c) Subset {2, 3, 4, 7, 8, 9} = 0111001110
Therefore, Subsets with bit strings:
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Complete question:
Suppose that the universal set is U={1,2,3,4,5,6,7,8,9,10}. Express each of the following subsets with bit strings (of length 10) where the ith bit (from left to right) is 1 if i is in the subset and zero otherwise.
a) {3, 4, 5}
b) {1, 3, 6, 10}
c) {2, 3, 4, 7, 8, 9}.
Your family is going on vacation for two nights. You don't want to spend more than $135 on a hotel room for your vacation. Write an inequality to represent how much you can spend each night on your hotel room.
Answer:
x ≤ 135/2
Step-by-step explanation:
x is the cost per night. You have to pay for 2 nights, and you do not want to spend more than $135 total. Another way to say that, is you want to spend less than or equal to $135.
x = cost per night
2 = number of nights
2x = total cost
Total cost must be less than or equal to $135.
2x ≤ 135
Divide each side by 2.
x ≤ 135/2
Volume=
Help me please!! Asap thanks so much
The volume of the oblique cylinder is 6867.18 cubic units
How to determine the volume?The given parameters are:
Height = 27
Radius = 9
The volume is calculated as:
[tex]V = \pi r^2 h[/tex]
So, we have:
[tex]V = 3.14 * 9^2 * 27[/tex]
Evaluate
V = 6867.18
Hence, the volume of the oblique cylinder is 6867.18 cubic units
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can someone please help mee
Answer:
I think that this answer is 22
Determine if y varies directly with x. Give the constant of variation, when appropriate. (picture below)
A) Does y vary directly with x?
B) What is the constant of variation?
Based on the given variation, y does not vary directly with x and the constant of variation are 8, 3.2 and 1.25 respectively.
Variationy = k × x
where,
k = constant of proportionality
y = -40
x = -5
y = k × x
-40 = k × -5
-40 = -5k
k = -40/-5
k = 8
when,
y = 8 and x = 2.5
y = k × x
8 = k × 2.5
8 = 2.5k
k = 8/2.5
k = 3.2
when,
y = 5 and x = 4
y = k × x
5 = k × 4
5 = 4k
k = 5/4
k = 1.25
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The product of three different positive integers is 8 what is the sum of these integers
Answer:
(4)(2)(1)=
4+2+1=
explanation:
4.10.1 checkup, answer questions about the unit circle
Using the unit circle, the correct answer regarding the comparison of angles w and t is given by:
a. t > w.
What is the unit circle?For an angle [tex]\theta[/tex] the unit circle is a circle with radius 1 containing the following set of points: [tex](\cos{\theta}, \sin{\theta})[/tex].
From this, we get that the sine is represented by the vertical axis. As we advance into the second quadrant, as the angle increases, sine decreases. Hence, since sin w > sin t, we have that t > w and option a is correct.
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The sampling distribution used when making inferences about a single population variance is?
We use the chi-square distribution when making inferences about a single population variance.
Short Description of Chi-Square Distribution
The continuous probability distribution known as the chi-square distribution. The number of degrees of freedom (k) a chi-square distribution has determines its shape. This type of sampling distribution has a variance of 2k and a mean equal to its number of degrees of freedom (k). The range is of a chi-square distribution is from 0 to ∞.
Variance plays a key role in the analysis of risk and uncertainty. The sample variance, an unbiased estimator of population variance, is expressed by the following formula of core statistic for a sample size 'n' and Y' as the sample mean:
S² = ∑(Yₓ - Y') / (n-1)
The formula, (n-1)S² / σ² has the central chi-square distribution as χ²ₙ₋₁. Here (n-1) represents the degrees of freedom.
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PLEASE HELP ASAP
I think it’s supposed to be an arithmetic series or sequence.
Kaydence is saving for an RRSP. She saved $100 the first year, $200 the second year, $300 the third year, and so on. If she put $100 away on January 1, 2014, $200 away on January 1, 2015, and continued to put money away on the first of each year, how much money would Kaydence have saved by the end of the day on January 1, 2050?
Answer:
$70,300
Step-by-step explanation:
The amount Kaydence saved is the value of an arithmetic series with first term 100 and common difference 100. The number of terms in the sum is 37. The formula for the sum can be used.
Sum of an arithmetic seriesThe formula for the sum of n terms of an arithmetic series is ...
Sn = (2a1 +d(n -1))(n/2) . . . . . . first term a1, common difference d
ApplicationThe number of terms being added is ...
2050 -2014 +1 = 37 . . . . . . years Kaydence made deposits
The formula with a1=100, d=100, and n=37 is ...
[tex]S_{37}=(2\cdot100+100(37-1))\dfrac{37}{2}=\dfrac{(200+3600)\cdot37}{2}\\\\S_{37}=70,\!300[/tex]
Kaydence would have saved $70,300 by the end of Jan 1, 2050.
PLEASE GUYS THIS IS THE HARDEST MATH PORBLEMS PLEASE ASAP PLEASE I NEED HELP PLEASE T_T
The simplified form of R(x) is [tex]R(x) =\frac{x^{2} -13x+42}{x^{2} -10x+25}[/tex]
Simplifying an expressionFrom the question, we are to simplify the expression
From the given information,
[tex]f(x) =\frac{x^{2}-11x+28 }{x^{2}-11x+30}[/tex]
and
[tex]g(x) =\frac{x^{2}-9x+20 }{x^{2}-12x+36}[/tex]
Also,
[tex]R(x) = f(x) \div g(x)[/tex]
∴ [tex]R(x) =\frac{x^{2}-11x+28 }{x^{2}-11x+30} \div \frac{x^{2}-9x+20 }{x^{2}-12x+36}[/tex]
[tex]R(x) =\frac{x^{2}-11x+28 }{x^{2}-11x+30} \times \frac{x^{2}-12x+36 }{x^{2}-9x+20}[/tex]
Factoring each of the quadratics
[tex]R(x) =\frac{x^{2}-7x-4x+28 }{x^{2}-6x-5x+30} \times \frac{x^{2}-6x-6x+36 }{x^{2}-4x-5x+20}[/tex]
[tex]R(x) =\frac{x(x-7)-4(x-7) }{x(x-6)-5(x-6)} \times \frac{x(x-6)-6(x-6) }{x(x-4)-5(x-4)}[/tex]
[tex]R(x) =\frac{(x-4)(x-7)}{(x-5)(x-6)} \times \frac{(x-6)(x-6)}{(x-5)(x-4)}[/tex]
Simplifying
[tex]R(x) =\frac{(x-7)}{(x-5)} \times \frac{(x-6)}{(x-5)}[/tex]
[tex]R(x) =\frac{(x-7)(x-6)}{(x-5)(x-5)}[/tex]
[tex]R(x) =\frac{x^{2} -6x-7x+42}{x^{2} -5x-5x+25}[/tex]
[tex]R(x) =\frac{x^{2} -13x+42}{x^{2} -10x+25}[/tex]
Hence, the simplified form of R(x) is [tex]R(x) =\frac{x^{2} -13x+42}{x^{2} -10x+25}[/tex]
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A 10-foot board is to be cut into 3 pieces. Two of the pieces will be the same length and one piece will be 2 feet longer
than the other two.
Which equation could be used to solve for the lengths?
x+x+x=10+2
x+x+ 2 x= 10
x+x+x+2=10
x+x+x-2=10
Answer:
the third : x + x + x + 2 = 10
Step-by-step explanation:
x = the length of the first 2 pieces.
the third piece will be x+2 ft long.
so, the total length of the original board is the sum of all 3 pieces and must be all in all 10 ft.
10 = x + x + (x + 2) = x + x + x + 2
so, it is the third answer option.
A group of friends wants to go to the amusement
park. They have no more than $420 to spend on
parking and admission. Parking is $8.75, and
tickets cost $25.75 per person, including tax.
Which inequality can be used to determine x, the
maximum number of people who can go to the
amusement park?
Answer:
The maximum amount of people that can go to the amusement park is 15.
Step-by-step explanation:
First you create an equation to represent the question
8.75+25.75x≤420
You put the less than or equal to sign because 420 is the maximum amount of money.
Now you just solve the equation.
25.75x≤420-8.75
25.75x≤411.25
x≤411.25/25.75
x≤15.9708738
Then you have to round down because you cant have .9 of a person.
So x≤15
Then, Check your solution
8.75+(25.75 x 15)≤420
8.75+386.25≤420
395≤420
That is true. But to make sure that is the maximum add another 25.75
395+25.75≤420
420.75≤420
This is equation is false so, our answer is correct.
The maximum amount of people that can go to the amusement park is 15.
Solve algebraically:
[tex]\huge\text{Hey there!}[/tex]
[tex]\huge\textbf{Equation a.}[/tex]
[tex]\rm{2x^2 - 162 = 0}[/tex]
[tex]\huge\textbf{Solving for:}[/tex]
[tex]\rm{2x^2 - 162 = 0}[/tex]
[tex]\huge\textbf{Add \boxed{\bf 162} to both sides:}[/tex]
[tex]\rm{2x^2 - 162 + 162 = 0 + 162}[/tex]
[tex]\huge\textbf{Simplify it:}[/tex]
[tex]\rm{2x^2 = 0 + 162}[/tex]
[tex]\rm{2x^2 = 162}[/tex]
[tex]\huge\textbf{Divide \boxed{\bf 2} to both sides:}[/tex]
[tex]\rm{\dfrac{2x^2}{2} = \dfrac{162}{2}}[/tex]
[tex]\huge\textbf{Simplify it:}[/tex]
[tex]\rm{x^2 = \dfrac{182}{2}}[/tex]
[tex]\rm{x^2 = 81}[/tex]
[tex]\huge\textbf{Take the square root of \boxed{\bf 81}}[/tex]
[tex]\rm{x = \pm \sqrt{81}}[/tex]
[tex]\rm{x = 9\ or\ x = -9}[/tex]
[tex]\huge\textbf{Therefore, your answer should be:}[/tex]
[tex]\huge\boxed{\textsf{x = } \frak{9\ or } \ \textsf{x = }\frak{-9}}\huge\checkmark[/tex]
[tex]\huge\textbf{Equation b.}[/tex]
[tex]\rm{-\dfrac{1}{2}(x - 3)^2 = -2}[/tex]
[tex]\huge\textbf{Solving for:}[/tex]
[tex]\rm{-\dfrac{1}{2}(x - 3)^2 = -2}[/tex]
[tex]\huge\textbf{Simplify both sides of your equation:}[/tex]
[tex]\rm{-\dfrac{1}{2}x^2 + 3x - \dfrac{9}{2} = -2}[/tex]
[tex]\huge\textbf{Subtract \boxed{\bf -2} to both sides:}[/tex]
[tex]\rm{-\dfrac{1}{2}x^2 + 3x - \dfrac{9}{2} - (-2) = -2 - (-2)}[/tex]
[tex]\huge\textbf{Simplify it:}[/tex]
[tex]\rm{- \dfrac{1}{2}x^2 + 3x - \dfrac{5}{2} = 0}[/tex]
[tex]\huge\textbf{Now, we can convert the equation to:}[/tex]
[tex]\rm{-0.5x^2 + 3x - 2.5 = 0}[/tex]
[tex]\large\text{When we changed the equation entirely, we made it easier to solve}\uparrow[/tex]
[tex]\huge\textbf{Use the quadratic formula to solve.}[/tex]
[tex]\large\textsf{The quadratic formula:}[/tex]
[tex]\mathsf{x= \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}}[/tex]
[tex]\huge\textbf{Here are your labels:}[/tex]
[tex]\text{a = }\rm{-0.5}\\\\\text{b = }\rm{ 3}\\\\\rm{c = }\rm{\ -2.5}[/tex]
[tex]\huge\textbf{Your new equation:}[/tex]
[tex]\rm{x = \dfrac{-(3) \pm \sqrt{3^2 - 4(-0.5)(-2.5)}}{2(-0.5)}}[/tex]
[tex]\huge\textbf{Simplify it:}[/tex]
[tex]\rm{x = \dfrac{-3 \pm \sqrt{4}}{-1}}[/tex]
[tex]\rm{x = 1\ or \ x = 5}[/tex]
[tex]\huge\textbf{Therefore, your answer should be: }[/tex]
[tex]\huge\boxed{\textsf{x = }\frak{1}\ \textsf{or x = }\frak{5}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex][tex]a)\ x_1=-9,\ x_2=9\\\\b)\ x_1=1,\ x_2=5[/tex]
Step-by-step explanation:Given equations:
[tex]a)\ 2x^2 - 162 = 0\\\\b) -\dfrac{1}{2}(x-3)^2=-2[/tex]
A) 2x² - 162 = 0
Step 1: Divide both sides by 2.
[tex]\\\implies \dfrac{2x^2 - 162}{2} = \dfrac{0}{2}\\\\\implies x^2-81=0\\\\\implies x^2=81[/tex]Step 2: Take the square root of both sides (using both the positive and negative roots).
[tex]\\\implies \sqrt{x^2}=\sqrt{81}\\\\\implies x=\pm\ 9[/tex]
Step 3: Separate into two cases.
[tex]\implies x_1 = -9,\ x_2 =-9[/tex]
----------------------------------------------------------------------------------------------------------------
B) -1/2(x - 3)² = -2
Step 1: Multiply both sides by -2.
[tex]\\\implies -2\left(-\dfrac{1}{2}(x-3)^2\right)=-2(-2)\\\\\implies (x-3)^2=4[/tex]
Step 2: Take the square root of both sides (using both the positive and negative roots).
[tex]\\\implies\sqrt{(x-3)^2}=\sqrt{4}\\\\\implies x-3=\pm\ 2[/tex]
Step 3: Separate into two cases and solve each one.[tex]1)\ x-3=-2\implies x=-2+3\implies \boxed{x=1}\\\\2)\ x-3=2\implies x=2+3\implies \boxed{x=5}[/tex]
each of 16 students in a class made a poetry book. each book contained 24 poems. how many poems are in 16 books
Escribe una ecuación de la recta que pasa por el punto (5, –8) con pendiente 5.
Considerando la expresión de una ecuación lineal, la ecuación de la recta que pasa por el punto (5, –8) con pendiente 5 es y= 5x - 33.
Ecuación linealUna ecuación lineal o línea se puede expresar en la forma y = mx + b
donde
x y son coordenadas de un punto.m es la pendiente.b es la ordenada al origen y representa la coordenada del punto donde la línea cruza el eje y.La ecuación lineal se puede expresar también mediante la ecuación punto-pendiente de la recta, que se plantea si se conoce la pendiente de la recta y cualquiera de sus puntos. Con ello queda determinada la recta, conociendo la pendiente “m” y un punto (x1, y1) dado:
y - y1= m(x -x1)
Ecuación de la recta en este casoEn este caso, la recta que pasa por el punto (5, –8) con pendiente 5.
Reemplazando en la ecuación punto-pendiente de la recta:
y - (-8)= 5(x -5)
Resolviendo:
y + 8= 5(x -5)
Aplicando propiedad distributiva:
y + 8= 5x - 5×5
y + 8= 5x - 25
Aislando la variable "y":
y= 5x - 25 - 8
y= 5x - 33
Finalmente, la ecuación de la recta que pasa por el punto (5, –8) con pendiente 5 es y= 5x - 33.
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Write an equation of a line in slope intercept form going through the points (1,6) and (3,0)
Answer:
y = -3x + 9
Step-by-step explanation:
The slope is
[tex] \frac{6 - 0}{1 - 3} = - 3[/tex]
Substituting into point-slope form, we get
y = -3(x-3)
y = -3x + 9
Which function in vertex form is equivalent to f(x) = x² + x +1?
○ f(x) = (x + 1/ 1³² + 1 ²1/0
3
4
○ f(x) = (x + 1)² + 2/1/2
○ f(x) = (x + ²/2 1²³ + ²/
4
5
f(x) = (x + 1/2-1² + ²/1/2
4
Answer:
[tex]\left( x+\frac{1}{2} \right)^{2} + \frac{3}{4}[/tex]
Step-by-step explanation:
NOTE :
[tex]x^2+ax=\left( x+\frac{a}{2} \right)^{2} -\left( \frac{a}{2} \right)^{2}[/tex]
………………………………………
f(x) = x² + x +1
[tex]=x^{2}+2\times \frac{x}{2} +1[/tex]
[tex]=\left( x+\frac{1}{2} \right)^{2} -\left( \frac{1}{2} \right)^{2} +1[/tex]
[tex]=\left( x+\frac{1}{2} \right)^{2} - \frac{1}{4}+1[/tex]
[tex]=\left( x+\frac{1}{2} \right)^{2} + \frac{3}{4}[/tex]
please help me im in a rush
Answer:
a. 25 seniors are randomly selected; 14 plan to go to a 4 year college
b. 420 students
Step-by-step explanation:
a. the less they have in common, the better
b. 14/25 is only between 25 students. make the denominator the same (750) and multiply the same to the numerator
750/25 = 30
14/25 x 30 = 420/750
Give the center and radius of a circle with the equation: (x+1)²+(y-2)²=100
A-The center is (-1. 2) and the radius is 10
B-The center is (1, -2) and the radius is 50
C- The center is (1, -2) and the radius is 10
D- The center is (-1, 2) and the radius is 50
OPTION A is the correct answer
Solve the following:
-5² + 10²
(2 × (-5) × 3) + 3³
Give your answer in simplest form.
Casey is deciding which of two landscapers to hire. Each landscaper charges an hourly rate plus a fee for each job. Casey correctly wrote and solved a system of linear equations by substitution. In his work, he substituted an expression for one variable and solved for the other. This resulted in the equation 5
One landscaper's hourly rate is $15 lower than the other landscaper's. Casey is deciding which of two landscapers to hire. Each landscaper charges an hourly rate plus a fee for each job.
What is system of linear equations?
A set of two linear equations with two variables is a system of linear equations. Casey is deciding between hiring one of two landscapers. Each landscaper bills a fee for each job in addition to an hourly rate. A set of linear equations was appropriately written and solved by Casey using substitution. He solved for the other variable and substituted an expression for one in his work. The intersection of the lines that represent the linear equations is where a system of linear equations finds its solution. Each landscaper bills a fee for each job in addition to an hourly cost. Casey produced a system of linear equations that was correctly written and solved. The hourly rates for both landscapers are the same, however their rates for individual jobs vary.
Casey is deciding between hiring one of two landscapers. Each landscaper bills a fee for each job in addition to an hourly cost. By using substitution, Casey created and properly figured out a set of linear equations. He solved for the other variable and replaced an expression for one in his work, producing the equation 5 = 20.
equation 5=20
20-5 = 15
Therefore, One landscaper's hourly rate is $15 lower than the other landscaper's.
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Geometric Series
It has 6 terms, increases by a factor of 4, and has a sum of 1365. Find the value of the first term.
Since the geometric series has 6 terms, increases by a factor of 4, and has a sum of 1365, the value of the first term is 1.
What is the sum of a geometric series?The sum of a geometric series is given by
Sₙ = a(rⁿ - 1)/(r - 1) with r > 1 where
n = number of terms, a = first term and r = common ratioNow, since our Geometric Series has 6 terms, n = 6. Also, it increases by a factor of 4, so, r = 4 and has a sum of 1365, so Sₙ = 1356. So,we have that
n = 6, Sₙ = S₆ = 1365 andr = 4The value of the first termSince we require the first term, a , making a subject of the formula, we have
a = Sₙ(r - 1)/(rⁿ - 1)
Substituting the values of the variables into the equation, we have
a = Sₙ(r - 1)/(rⁿ - 1)
a = S₆(r - 1)/(r⁶ - 1)
a = 1365(4 - 1)/(4⁶ - 1)
a = 1365(3)/(4096 - 1)
a = 4095/4095
a = 1
So, the value of the first term is 1.
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I need help I’m really stuck on this and have absolutely no idea how to work this out your supposed to “solve for t”
Answer:
t = -35/8
Step-by-step explanation:
Divide both sides by 2/5.