Answers
Answer:
Following are the answer to this question:
Explanation:
Galileo claims that perhaps the air resistance is due to an object falling slower. The object gradually falls under its control of free-fall gravity.
A free-falling object is also an object, which is affected by gravity only. The object operated only by the gravitational force is considered to get into a condition of free fall and the Items, that fall free may not feel air resistance.
please find the attachment.
Related Questions
Re-arrange the equation
x = vit + 1/2at2 v2f = vi2 + 2ax vf = vi + at x = 1/2(vi + vf)delta t
1. A car in front of the school goes from rest to 27 ms in 3.0 seconds. What is its acceleration (assuming it is constant)?
2. A rocket starts from rest and accelerates at a uniform rate of 190 m/s^2 for 2.4 seconds. What is its final velocity?
3. A car has a velocity of 15 m/s. It then accelerates at a uniform rate of 3.5 m/s^2 for the next 5.0 seconds. What distance does the car cover during this time?
4. What distance is required for a train to stop if its initial velocity is 23 m/s and its deceleration is 0.25 m/s^2? (Assume the train decelerates at a constant rate.
5. What distance will a car cover while uniformly accelerating from 12 m/s to 26 m/s in 14 seconds?
6. A person starts at rest and accelerates at a uniform rate of at 3.2 m/s^2 for 3.0 seconds. What distance does this person cover in that time?
7. What must be the acceleration of a train in order for it to stop from 12 m/s in a distance of 541 m? (Assume the train accelerates uniformly.)
Answers
Answer:
Explanation:
1) Acceleration is the change in velocity of a body with respect to time.
Acceleration a = vf - vi/t
vf is the final velocity
vi is the initial velocity.
t is the time taken
Since the body accelerates from rest, vi = 0m/s
a = 27-0/3
a = 27/3
a = 9m/s²
2) Given
u = 0m/s (accelerates from rest)
a = 190m/s²
t = 2.4seconds
v = ?
Using v = u+at
v = 0+190(2.4)
v = 190×2.4
v = 456m/s
The final velocity of the car is 456m/s
3) Given
u = 15m/s
a = 3.5m/s
t = 5seconds
Using the relationship
S = ut+1/2at²
S is the distance covered by the car.
S = 15(5)+1/2(3.5)×5²
S = 75+25×3.5/2
S = 75+43.75
S = 118.75m
4) Given
initial velocity u = 23m/s
Deceleration a = -0.25m/s²(negative acceleration)
Final velocity v = 0m/s
Using the relationship
V² = u²+2as
0² = 23²+2(-0.25)s
-23² = -0.5S
23² = 0.5S
S = 529/0.5
S = 1058m
The distance required for the train to stop is 1058m.
5) Given
initial velocity u = 12m/s
Final velocity v = 26m/s
time = 14sec
Acceleration a = v-u/t
a = 26-12/14
a= 14/14
a = 1m/s²
For Distance covered
v² = u²+2as
26² = 12²+2(1)S
676 = 144 +2S
2S = 676-144
2S = 532
S = 532/2
S = 266m
Distance that the car will cover is 266m
6) Given
Initial velocity u = 0m/s (person starts from rest)
acceleration a = 3.2m/s²
time t = 3.0s
To get the distance;
S = ut + 1/2at²
S = 0(3)+1/2(3.2)×3²
S = 0+1.6×9
S= 9×1.6
S = 14.4m
The distance that the person covered in 3.0s is 14.4m
7) initial velocity of train u = 12m/s
Distance covered S = 541m
Final velocity = 0m/s (on stopping)
acceleration a= ?
Acceleration will be negative since the train is coming to a stop (decelerating)
Using the formula v² = u²+2as
0² = 12² - 2a(541)
-12² = -1082a
144 = 1082a
a = 1082/144
a = 7.51m/s²
Hence the acceleration of a train in order for it to stop from 12 m/s in a distance of 541 m is 7.51m/s²
Velocity head is the mechanical energy of a fluid per unit weight of the fluid measured relative to the bottom of the channel.
a. True
b. False
Answers
Answer:
b. False
Explanation:
The Bernoulli's equation is given by;
[tex]P + \rho gh + \frac{1}{2} \rho v^2 = constat[/tex]
Divide through by the density of the fluid and acceleration due to gravity (ρg), to obtain energy per unit weight of the fluid known as head;
[tex]\frac{P}{\rho g} + h + \frac{v^2}{2g} = constant[/tex]
where;
[tex]\frac{P}{\rho g}[/tex] is pressure head
h is datum head (mechanical energy due to height of the fluid)
[tex]\frac{v^2}{2g}[/tex] is velocity head (mechanical energy due to velocity of the fluid)
Thus, the mechanical energy of a fluid per unit weight of the fluid, measured relative to the bottom of the channel is datum head.
The correct option is "b. False"
In a thermal circulation what is happening at the surface of the warm column of air?
Answers
Answer:
Explanation: Thermals are created by the irregular heating of Earth's surface from solar radiation, and are an example of convection, specifically atmospheric convection.
At this point, air is converging on low pressure and rising air forms clouds.
A beam of gamma rays is incident on a block of lead. The intensity of gamma rays passing through a uniform medium varies with depth x, in a manner given by the expression I(x) = 1, e-ux Here, I, is the intensity of the radiation at the surface of the material (at x = 0) and u is called the linear absorption coefficient. A) Find an expression for the thickness of material that would absorb half of the gamma rays. B) Find an expression for the thickness of material that would reduce the radiation intensity to a fraction of the initial intensity.
Answers
Answer:
A. x = -㏑(1/2)/μ B. x = -㏑(I/I₀)/μ
Explanation:
A. Since the intensity I = I₀exp(-μx) where I₀ = intensity at x = 0.
When I = I₀/2,
I = I₀exp(-μx)
I₀/2 = I₀exp(-μx)
dividing through by I₀, we have
1/2 = exp(-μx)
taking natural logarithm of both sides, we have
㏑(1/2) = ㏑[exp(-μx)]
㏑(1/2) = -μx
dividing both sides by -μ
x = -㏑(1/2)/μ
where x is the thickness of the material that would absorb half of the gamma rays
B. Since the intensity I = I₀exp(-μx) at thickness x, where I₀ = intensity at x = 0
I = I₀exp(-μx)
dividing through by I₀
I/I₀ = exp(-μx)
taking natural logarithm of both sides, we have
㏑(I/I₀) = ㏑exp(-μx)
㏑(I/I₀) = -μx
dividing both sides by -μ
x = -㏑(I/I₀)/μ
where x is the thickness of the material that would reduce the radiation intensity to a fraction of the initial intensity.
Work: If the force on an object is in the negative direction, the work it does on the object must be
Answers
Answer:
The work must be negative or positive depending on direction of motion of the object
Explanation:
This is because
W= force x distance
And = F x S cosစ
And this is positive when
Theta is less than π/2 and negative when theta is less than or equal to π/2
If a force acts in a specific direction on a thing, the work it puts on it can be positive or negative, regardless of the direction the object moves.
Define force.A force is indeed an influence which can alter an angular velocity. An object can alter its velocity, or speed, as a result of a force. Naturally, force can be characterized as a push or just a pull.
If a force acts in a specific direction on a thing, the work it puts on it can be positive or negative, regardless of the direction the object moves.
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The force on an object is F⃗ =−17j⃗ . For the vector v⃗ =2i⃗ +3j⃗ , find: (a) The component of F⃗ parallel to v⃗
Answers
Answer:
(a) [tex]\vec F_{\parallel} = -\frac{102}{13}\,i-\frac{103}{13}\,j[/tex] , (b) [tex]\vec F_{\perp} = \frac{102}{13}\,i -\frac{68}{13}\,j[/tex], (c) [tex]W = -51[/tex]
Explanation:
The statement is incomplete:
The force on an object is [tex]\vec F = -17\,j[/tex]. For the vector [tex]\vec v = 2\,i +3\,j[/tex]. Find: (a) The component of [tex]\vec F[/tex] parallel to [tex]\vec v[/tex], (b) The component of [tex]\vec F[/tex] perpendicular to [tex]\vec v[/tex], and (c) The work [tex]W[/tex], done by force [tex]\vec F[/tex] through displacement [tex]\vec v[/tex].
(a) The component of [tex]\vec F[/tex] parallel to [tex]\vec v[/tex] is determined by the following expression:
[tex]\vec F_{\parallel} = (\vec F \bullet \hat {v} )\cdot \hat{v}[/tex]
Where [tex]\hat{v}[/tex] is the unit vector of [tex]\vec v[/tex], which is determined by the following expression:
[tex]\hat{v} = \frac{\vec v}{\|\vec v \|}[/tex]
Where [tex]\|\vec v\|[/tex] is the norm of [tex]\vec v[/tex], whose value can be found by Pythagorean Theorem.
Then, if [tex]\vec F = -17\,j[/tex] and [tex]\vec v = 2\,i +3\,j[/tex], then:
[tex]\|\vec v\| =\sqrt{2^{2}+3^{3}}[/tex]
[tex]\|\vec v\|=\sqrt{13}[/tex]
[tex]\hat{v} = \frac{1}{\sqrt{13}} \cdot(2\,i + 3\,j)[/tex]
[tex]\hat{v} = \frac{2}{\sqrt{13}}\,i+ \frac{3}{\sqrt{13}}\,j[/tex]
[tex]\vec F \bullet \hat{v} = (0)\cdot \left(\frac{2}{\sqrt{13}} \right)+(-17)\cdot \left(\frac{3}{\sqrt{13}} \right)[/tex]
[tex]\vec F \bullet \hat{v} = -\frac{51}{\sqrt{13}}[/tex]
[tex]\vec F_{\parallel} = \left(-\frac{51}{\sqrt{13}} \right)\cdot \left(\frac{2}{\sqrt{13}}\,i+\frac{3}{\sqrt{13}}\,j \right)[/tex]
[tex]\vec F_{\parallel} = -\frac{102}{13}\,i-\frac{153}{13}\,j[/tex]
(b) Parallel and perpendicular components are orthogonal to each other and the perpendicular component can be found by using the following vectorial subtraction:
[tex]\vec F_{\perp} = \vec F - \vec F_{\parallel}[/tex]
Given that [tex]\vec F = -17\,j[/tex] and [tex]\vec F_{\parallel} = -\frac{102}{13}\,i-\frac{153}{13}\,j[/tex], the component of [tex]\vec F[/tex] perpendicular to [tex]\vec v[/tex] is:
[tex]\vec F_{\perp} = -17\,j -\left(-\frac{102}{13}\,i-\frac{153}{13}\,j \right)[/tex]
[tex]\vec F_{\perp} = \frac{102}{13}\,i + \left(\frac{153}{13}-17 \right)\,j[/tex]
[tex]\vec F_{\perp} = \frac{102}{13}\,i -\frac{68}{13}\,j[/tex]
(c) The work done by [tex]\vec F[/tex] through displacement [tex]\vec v[/tex] is:
[tex]W = \vec F \bullet \vec v[/tex]
[tex]W = (0)\cdot (2)+(-17)\cdot (3)[/tex]
[tex]W = -51[/tex]
Name at 2 areas of physics that make video games possible
Answers
Answer:
projectiles
electromagnetic
Answer:
Explanation:
física cuántica y Quantum Moves
1. An insect inside a bus flies from the back toward the front at 2 m/s. The bus is moving in a
straight line at 20 m/s. What is the total speed of the insect as seen by a person standing on the
side of the road?
Answers
Answer:
Total speed of the insect as seen by a person standing on the side of the road is 22 m/s
Explanation:
There i a composition of velocities, since the air inside the bus is moving at the same speed as the bus, and the insect flying relative to it.
So for an observer on the side of the road, the insect is flying at a speed of :
20 m/s + 2 m/s = 22 m/s
A
is a precise way to represent data, but it does not identify trends in the data.
O graph
O table
Ovariable
O diagram
Answers
Answer: table
Explanation:
Answer:Table
Explanation:
A table is a way to represent data , but does not identify trends in the data
How much energy is stored in the capacitor before the dielectric is inserted?Express your answer in joules.
Answers
Answer:
0.004394Joules
Explanation:
The question is incomplete. Find the complete question in the attachment below;
Energy stored in a capacitor = 1/2CV² where;
C is the capacitance of the capacitor
V is the potential difference across the plates
Given parameters
C = 13.0μF = 13 * 10⁻⁶F
V = 26.0V
Required
Energy stored in the capacitor
Substituting the values into the equation given;
E = 1/2 * 13 * 10⁻⁶ * 26²
E = 1/2 * 13 * 10⁻⁶ * 676
E = 1/2* 8788 * 10⁻⁶
E = 4394 * 10⁻⁶
Hence the Energy stored in the capacitor in Joules is 0.004394Joules
A 0.40 kg ball, attached to the end of a horizontal cord, is rotated in a circle of radius 1.5 m on a frictionless horizontal surface. If the cord will break when the tension in it exceeds 63 N, what is the maximum speed the ball can have?
Answers
Answer:
The maximum speed the ball can have is 15.37 m/s
Explanation:
Given;
mass of the ball, m = 0.4 kg
radius of the chord, r = 1.5 m
maximum tension on the chord, T = 63 N
The maximum tension on the chord is given by;
[tex]T_{max} = \frac{mv_{max}^2}{r} \\\\v_{max}^2 = \frac{T_{max} *r}{m}\\\\ v_{max} = \sqrt{\frac{T_{max} *r}{m}} \\\\ v_{max} =\sqrt{\frac{63 *1.5}{0.4}}\\\\v_{max} = 15.37 \ m/s[/tex]
Therefore, the maximum speed the ball can have is 15.37 m/s
A uniform seesaw is balanced at its center of mass, as seen below. The smaller boy on the right has a mass of 40.0 kg. What is the mass of his friend is (A) 40 kg (B) 20 kg (C) 80 kg (D) Cannot be determined
Answers
Answer:
C. 80kgExplanation:
The question lacks the appropriate diagram. Find the diagram attached below:
Let the mass of his friend be M.
Using the principle of moment which states that the sum of clockwise moment is equal to the sum of its anticlockwise moment to solve the problem,.
Since Moment = Force * perpendicular distance.
The smaller boy will move in the clockwise direction and his friend will move in the anti clockwise direction.
Clockwise moment = 40 * 4 = 160kgm
anticlockwise moment = M * 2 = 2Mkgm
Equating both moments to get the mass M of his friend
160 = 2M
Divide both sides by 2
2M/2 = 160/2
M = 80kg
Hence the mass of his friend that will keep the seesaw balanced horizontally is 80kg.
What is the wavelength of the waves you create in a swimming pool if you splash your hand at a rate of 2.00 Hz and the waves propagate at 0.800 m/s
Answers
Answer:
The wavelength of the waves created in the swimming pool is 0.4 m
Explanation:
Given;
frequency of the wave, f = 2 Hz
velocity of the wave, v = 0.8 m/s
The wavelength of the wave is given by;
λ = v / f
where;
λ is the wavelength
f is the frequency
v is the wavelength
λ = 0.8 / 2
λ = 0.4 m
Therefore, the wavelength of the waves created in the swimming pool is 0.4 m
Skater A skates toward Skater B and gently pushes Skater B away. If the skaters are in a closed system, which statement is correct about the total momentum of the system? A. Total momentum may increase or decrease depending on the duration of the collision. B. Total momentum remains the same. C. Total momentum increases. D. Total momentum decreases.
Answers
Answer:
option B is correct
Explanation:
according to law of conservation of momentum the total momentum in a closed system remains constant before and after collision
If the skaters are in a closed system the total momentum remains the same.
In a closed system the total momentum is always conserved.
By applying the principle of conservation of linear momentum, the total momentum before the push of skater A, will be equal to the total momentum after the push.
The equation is given as;
Initial momentum = final momentum
[tex]m_au_a + m_bu_b = m_av_a + m_bv_b[/tex]
where;
u and v represents the initial and final velocity of both skaters.Thus, we can conclude that if the skaters are in a closed system the total momentum remains the same.
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Juliette sets the initial velocity to +10 m/s and the acceleration to −2 m/s2, then clicks "start". How can Shakina describe the subsequent motion of the car?
Answers
Answer:
Shakina can sayThe car moves initially to the right with decreasing speed. Eventually, the car stopsand moves to the left with increasing speed.
Explanation:
Because initially the acceleration is negative during which the car is moving to the right and then it slows down and stops, and once it begins moving to the left, it begins to accelerate faster
Two cars, P and Q, travel in the same direction on a long, straight section of a highway. car P passes car Q, and is adjacent to car Q at time t (subscript 0).
a) Suppose that car P and car Q each move with constant speed. At time t (subscript 0), is the magnitude of the instantaneous velocity of car P greater than, less than, or equal to the magnitude of the instantaneous velocity of car Q? Explain.
b) Suppose instead that car P is moving with constant speed but car Q is speeding up. At time (subscript 0), is the magnitude of the instantaneous velocity of car P greater than, less than, or equal to the magnitude of the instantaneous velocity of car Q? Explain.
Answers
Answer:
the instantaneous velocity of P is greater that Q because P obviously passes Q at that instant in time t
2. P has greater velocity at that instant (to) because P will need to be at a greater velocity to pass Q
Compare and contrast the inner and outer planets. (Must be in complete sentences) (At least 5 sentences).
Answers
To contrast inner and outer planets we will start with the climate of the planets and then move on to there lighting. To start the planets closet to the sun, mercury, venus, earth and mars, are all hot compared to the further one, jupiter, saturn, uranus, neptune. This distance also makes the farthe away planets darker than the ones closer. Now to compare all the planets vary from either gass or solid, rocky or icy. All of them spin around the sun and all have objects spinning around them, moons.
determine the weight in newtons of a woman whose weight in pounds is 125. also, find her mass in slugs and in kilograms. DEtermine your own weight in newtons
Answers
Answer:
124 just subtract only one
Explanation:
Kendra drove 300 km in 2 hours. Henry drove the same 300 km in 3 hours. If
Kendra and Henry had the same average speed for their trips, what must be
true?
a. Kendra must have stopped for one hour during her trip
b. henry must have stopped for one hour during his trip
c. kendra must have had a lower velocity than henry
d. henry must have had a lower velocity then kendra
Answers
Answer:
b. henry must have stopped for one hour during his trip
When it comes to how ray lines are drawn, what makes the convex lens and concave mirror similar to each other?
Answers
Answer:
Convex lens and convex mirrors are similar that
1. They have the same image characteristics at various object positions
2. They possess a positive focal length
3. Both their ray lines converge to a particular focal point
Convex lens and concave mirror have certain similarities that are explained below.
The shape of concave mirror is spherical.
Convex lens is the combination of two concave mirrors.
When the ray lines are drawn at the convex lens, then the coverage of the rays leads parallel to its principal axis.
When the ray lines are drawn at the concave mirror, then the coverage of the rays leads parallel to its focal point.
The focal length of concave mirror and convex lens is positive.
Concave mirror and convex lens both project the real and inverted image of the object.
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https://brainly.com/question/14295029.
Find the average velocity for the time interval beginning when t = 4 with duration 1 seconds, 0.5 seconds, and 0.05 seconds.
Answers
This question is incomplete, the complete question is;
A student dropped a textbook from the top floor of his dorm and it fell according to the formula s(t) = -16t² + 8√t, where t is the time in seconds and s(t) is the distance in feet from the top of the building.
(a) Write a formula for the average velocity of the ball for t near 4.
(b) Find the average velocity for the time interval beginning when t = 4 with duration 1 seconds, 0.5 seconds, and 0.05 seconds
(c) What is your estimate for the instantaneous velocity of the ball at t = 4
Answer:
a)
Average velocity, (Vavg) of the ball for t near 4.
Vavg = [s(4) - s(0)] / (4 - 0)
Where s(4) = -16 × 4² + 8 × √4= - 240 m
s(0) = -16 × 0 + 8 * 0 = 0
b)
duration = 1 sec
Vavg = [s(5) - s(4)] / (5 - 4)
s(5) = -16 × 52 + 8 × √5 = - 382 m
s(4) = -16 × 42 + 8 √4 = - 240 m
Vavg = (-382 - (-240)) / (5 - 4)
Vavg = - 142.1 m/s
duration = 0.5 sec
Vavg = [s(4.5) - s(4)] / (4.5 - 4)
s(4.5) = -16 × 4.52 + 8 × √4.5 = - 307 m
s(4) = -16 × 42 + 8 × √4 = - 240 m
Vavg = (-307 - (-240)) / (4.5 - 4)
Vavg= - 134.1 m/s
duration = 0.05 sec
Vavg = [s(4.05) - s(4)] / (4.05 - 4)
s(4.05) = -16 × 4.052 + 8 × √4.05 = - 246 m
s(4) = -16 × 42 + 8 × √4 = - 240 m
Vavg = (-246 - (-240)) / (4.05 - 4)
Vavg= - 126.8 m/s
c)
Instantaneous velocity, v = ds/dt
= - 16 × 2 × t + 8 ×× (0.5 / √t )
= - 32 × t + 4/√t
ds/dt at t = 4 is,
v = - 32 × 4 + 4 / √4
= - 126 m/s
A 150 lb diver stands at the end of a rigid 8 ft long diving board. What is the magnitude of the torque the diver exerts on the diving board
Answers
Answer:
1200 lb-ft
Explanation:
Weight of diver W = 150 lb
length of board L = 8 ft
This board is pivoted at one end therefore, the perpendicular distance from the pivot = 8 ft
Torque = weight x perpendicular distance from pivot
T = WL
Torque = 150 x 8 = 1200 lb-ft
E
Which is the downward pull on an object due to gravity?
volume
mass
weight
matter
Answers
Answer:
Weight
Explanation:
Weight is the downward pull on an object due to gravity.
For example, the moon has less gravity than Earth so we would weigh less on the moon. Our Mass and volume always stay the same but our weight could change.
Answer:
weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight weight
Explanation:
Question No 1 Find the voltage drop across 24 ohm resistor and current flowing through 22 ohm resistor in the given circuit as shown in figure.
Answers
Answer:
8.25 V
Explanation:
We can ignore the 22Ω and 122Ω resistors at the bottom. Since there's a short across those bottom nodes, any current will go through the short, and none through those two resistors.
The 2Ω resistor and the 44Ω resistor are in parallel. The equivalent resistance is:
1 / (1 / (2Ω) + 1 / (44Ω)) = 1.913Ω
This resistance is in series with the 12Ω resistor. The equivalent resistance is:
1.913Ω + 12Ω = 13.913Ω
This resistance is in parallel with the 24Ω resistor. The equivalent resistance is:
1 / (1 / (13.913Ω) + 1 / (24Ω)) = 8.807Ω
Finally, this resistance is in series with the 4Ω resistor. The equivalent resistance of the circuit is:
8.807Ω + 4Ω = 12.807Ω
The current through the battery is:
12 V / 12.807Ω = 0.937 A
The voltage drop across the 4Ω resistor is:
(0.937 A) (4Ω) = 3.75 V
So the voltage between the bottom nodes and the top nodes is:
12 V − 3.75 V = 8.25 V
Multiple choice! To be dimensionally consistent, velocity [L/T], force [ML/T^2], mass [M], and length [L] must be related as follows. Multiple Choice A. velocity^2 = force × length/mass B. velocity^2 = force × length/mass^2 C.velocity = force × length^2/mass D. velocity = force × length/mass
Answers
Answer:
velocity^2=force*length/mass
Explanation:
velocity^2=force*length/mass is dimensionally consistent
as we know that
unit of force=Newton
unit of length=meter
unit of mass=kilogram so
velocity^2=newton*meter/kilogram
newton=kg*m/sec^2 therefore
v^2=kg*m*m/sec^2*kilogram
v^2=kg*m^2/sce^2*kg
v^2=m^2/sec^2
taking square root on both side
√ v²=√m²/sec²
v=m/s now the dimensions of V is
v=(L/T)
so option A is dimensionally consistent
It should be related like velocity^2=force*length/mass
Calculation of the relationship:
Since we know that
unit of force=Newton
unit of length=meter
And,
unit of mass=kilogram
Therefore,
velocity^2=newton*meter/kilogram
Now
newton=kg*m/sec^2
So,
v^2=kg*m*m/sec^2*kilogram
v^2=kg*m^2/sce^2*kg
v^2=m^2/sec^2
Now we take square root on both side
So,
√ v²=√m²/sec²
v=m/s
v=(L/T)
Therefore, option A is correct
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A drone is launched with a velocity of 63 m/s, 29 . Three minutes after the drone is launched it suddenly changed its course to 22 m/s, 233 to avoid high trees on its way. Then, it finally goes back at a rate of 98 m/s, 321. Calculate for the total resultant vector of the drone.
Answers
Answer:
v = 127.66 m / s θ’= 337.59
Explanation:
For this exercise we must use the speed composition of the drone.
The first speed is 63 m / s in direction 29, three minutes later the speed reaches 22 m / s and direction 233, finally it returns to the launch point with 98 m / s in direction 321, in the attachment you can see a diagram of these speeds.
To find the resulting average velocity, the easiest thing is to decompose each velocity into the x and y coordinate system, then add each velocity
let's break down the speeds
cos 29 = v₁ₓ / v₁
sin 29 = [tex]v_{1y}[/tex] / v₁
v₁ₓ = v₁ cos 29
v_{1y} = v₁ sin 29
v₁ₓ = 63 cos 29 = 55.10 m / s
v_{1y} = 63 sin 29 = 30.54 m / s
speed 2
cos 22 = v₂ₓ / v₂
sin 22 = v_{2y} / v₂
v₂ₓ = v₂ cos 233
v_{2y} = v₂ sin 233
v₂ₓ = 22 cos 233 = -13.24 m / s
v_{2y} = 22 sin 233 = -17.57 m / s
speed 3
cos 321 = v₃ₓ / v₃
sin 321 = v_{3y} / v₃
v₃ₓ = v₃ cos 321
v_{1y} = vₐ sin 321
v₃ₓ = 98 cos 321 = 76.16 m / s
v_{3y} = 98 sin 321 = -61.67 m / s
We already have all the component of the speeds, the resulting speed is
vₓ = v₁ₓ + v₂ₓ + v₃ₓ
vₓ = 55.10 -13.24 +76.16
vₓ = 118.02 m / s
v_{y} = v_{1y} + v_{2y} + v_{3y}
v_{y} = 30.54 -17.54 - 61.67
v_{y} = -48.67 m / s
there are two ways to give the result
v = (118.02 i -48.67 j) m / s
or in the form of magnitud and angle.
We use the Pythagorean theorem for the module
v = √ (vₓ² + v_{y}²)
v = RA (118.02² + 48.67²)
v = 127.66 m / s
let's use trigonometry for the angle
tan θ = v_{y} / vₓ
θ = tan⁻¹ (v_{1} / vₓ)
θ = tan⁻¹ (-48.67 / 118.02)
θ = -22.41
if we want to measure the angles with respect to the positive side of the x axis
θ’= 360 - 22.41
θ’= 337.59
Tell uses of cancave mirror and convex mirror.
Answers
Answer:
Uses of concave mirror:
Shaving mirrors.
Head mirrors.
Ophthalmoscope.
Astronomical telescopes.
Headlights.
Solar furnaces.
Uses of convex mirror:
Convex mirrors always form images that are upright, virtual, and smaller than the actual object. They are commonly used as rear and side view mirrors in cars and as security mirrors in public buildings because they allow you to see a wider view than flat or concave mirrors.
please give me full points.
How does the decrease in gravitational potential energy of a falling ball compare to its increase in kinetic energy? (Ignore air friction.)
Answers
Answer:
for every decrease in potential energy, a kinetic energy proportional to 2gΔh is gained.
Explanation:
Let us consider a ball falling from its maximum height
For a body falling from its maximum height to a point p
change in height = Δh
The potential energy decrease is then proportional to
ΔPE = mgΔh
where
ΔPE is the decrease in kinetic energy
m is the mass of the ball
g is acceleration due to gravity
Δh is the change in height
For a body falling from its maximum height, the increase change in velocity
Δv = u + 2gΔh (at maximum height u = 0)
where
u is the initial kinetic energy of the ball
Δv = 0 + 2gΔh
Δv = 2gΔh
The kinetic energy increases by
ΔKE = [tex]\frac{1}{2}[/tex]m(Δv)^2
but Δv = 2gΔh
therefore
ΔKE = [tex]\frac{1}{2}[/tex]m(2gΔh)^2 = 2m(gΔh)^2
comparing the increase in kinetic energy to the decrease in potential energy, we have
(2m(gΔh)^2)/(mgΔh) = 2gΔh
This means that for every decrease in potential energy, a kinetic energy proportional to 2gΔh is gained.
What is the magnitude of the electric force on the charge at the bottom left-hand vertex of the triangle due to the other two charges
Answers
Answer:
[tex]\frac{kq^{2} }{2a^2}[/tex]
Explanation:
The magnitude on the charge at the bottom-left corner due to the charge on the top vertex of the triangle will act along the +ve x-axis and the +ve y-axis.
From Coulomb's law the magnitude of the forces on the charge at the bottom-left corner, due to the charge on the top vertex of the triangle are [tex]\frac{kq^{2} }{a^2}[/tex]cos 60, and
The magnitude on the charge due to the charge at the bottom-right corner will only act in the -ve x-axis, since they repel each other (like charges repel). The magnitude is [tex]\frac{kq^{2} }{a^2}[/tex]
The angle made by the upper charge to the charge we're considering is 60° with the horizontal.
The total force on the charge along the x-axis is
[tex]F_{x}[/tex] = [tex]\frac{kq^{2} }{a^2}[/tex]cos 60 -
[tex]F_{x}[/tex] = [tex]\frac{kq^{2} }{2a^2}[/tex] - [tex]\frac{kq^{2} }{a^2}[/tex]
==> -[tex]\frac{kq^{2} }{2a^2}[/tex]
For the y-axis, we have
[tex]F_{y}[/tex] = [tex]\frac{kq^{2} }{a}[/tex]sin 60
[tex]F_{y}[/tex] = [tex]\frac{\sqrt{3}* kq^{2} }{2a^2}[/tex]
The resultant force is
[tex]|F| = \sqrt{F_{x}^{2}+ F_{y}^2 }[/tex]
The common factors between the two x-axis force, and the y-axis force is
[tex]\frac{kq^{2} }{2a^2}[/tex], we put this outside the square root (squaring this and square rooting will give us the initial value)
[tex]|F|[/tex] = [tex]\frac{kq^{2} }{2a^2}[/tex][tex]\sqrt{(\frac{1}{2})^2 + (\frac{\sqrt{3} }{2})^2 }[/tex]
[tex]|F|[/tex] = [tex]\frac{kq^{2} }{2a^2}[/tex][tex]\sqrt{\frac{1}{4} +\frac{3}{4} }[/tex]
==> [tex]\frac{kq^{2} }{2a^2}[/tex][tex]\sqrt{1}[/tex]
the magnitude of the electric force on the charge at the bottom left-hand vertex of the triangle due to the other two charges is
[tex]|F|[/tex] = [tex]\frac{kq^{2} }{2a^2}[/tex]
If two identical blocks are glued together and pulled with twice the original force, what will their acceleration be
Answers
Answer:
The acceleration will be a
Explanation:
Using F = ma
But we are given that F2= 2F1 and
m2= 2m1
So
a2= F2/m2= F1/m1
and
F1/m1=a