Gaseous nitrogen dioxide dissolved in warm liquid water to form hno3 and gaseous nitrogen monoxide enter a balanced equation for this reaction

Explanation:

125)118

126)6

127)9

128)Au

There are 118 elements discovered yet and they are included in the periodic table.There are 6 hydrogens in ethanol. Number of total atoms in it is 9. The symbol of gold is Au.

Periodic table is a classification of elements discovered in nature. There are groups and periods for these elements where groups are vertical columns of elements with similar physical and chemical properties.

There are 118 elements in the periodic table. Thus option C is correct.

Ethanol is a simple alcohol formed by 2 carbons and 5 hydrogens with an OH group. Thus there are total 6  (option C) hydrogens and a total of 9 atoms (option C).  Ethanol is widely used in making of alcoholic products.

The chemical symbol of gold is Au. Chemical symbols are elements are derived from their latin names. The latin name of gold is Aurom. Thus it has the symbol Au. Therefore, option B is correct.

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Despite the fact that viruses and ambient bacteria found indoors could both be mesophiles, at 37 degrees Celsius, the temperature of the human body, pathogens would develop more quickly than environmental strains.

A virus would be an infectious submicroscopic creature that only reproduces inside of live cells.

Although bacteria may survive at higher and lower temperatures than humans, they thrive in an environment which really is warm, wet, protein-rich, and pH neutral as well as slightly acidic.

Therefore, Despite the fact that viruses and ambient bacteria found indoors could both be mesophiles, at 37 degrees Celsius, the temperature of the human body, pathogens would develop more quickly than environmental strains.

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Answer:

2.2 x 10⁻³⁴ J

      or

2.2 x 10⁻¹⁸ J

Explanation:

You can calculate the energy using the photon energy equation:

E = hc / λ

In this equation,

-----> E = energy (J)

-----> h = Planck's Constant (6.626 x 10⁻³⁴ J*s)

-----> c = speed of light (3.0 x 10⁸ m/s)

-----> λ = wavelength (m)

You can plug the given wavelength, along with the other constants, into the equation and simplify to find the energy.

E = hc / λ

E = (6.626 x 10⁻³⁴ J*s)(3.0 x 10⁸ m/s) / (9 x 10⁸ m)

E = 2.2 x 10⁻³⁴ J

I suspect that you may have forgotten the negative sign in front of the 8 (9 x 10⁻⁸). This would change your answer to 2.2 x 10⁻¹⁸ J.

The % V/V concentration of a 180-mL disinfectant solution containing 85 mL of isopropyl alcohol is 47 % V/V.

It refers to the milliliters of solute for every 100 milliliters of solution.

We have 180 mL of a disinfectant solution that contains 85 mL of isopropyl alcohol (solute).

The % V/V concentration of this solution is:

% V/V = (mL solute/mL solution) × 100% =

% V/V = (85 mL/180 mL) × 100% = 47% V/V

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Answer:

only one atom of that element

Explanation:

Example:

   H2 O    has two hydrogenatoms and ONE Oxygen atom

The presence of no subscript for an element in a chemical formula means that there is a single atom of that element in the compound.

In a chemical formula, subscripts are used to indicate the number of atoms of each element present in a compound. When an element has no subscript, it means that there is only one atom of that element in the compound.

For example, in the chemical formula H₂O, the subscript 2 indicates that there are two hydrogen atoms present. On the other hand, the absence of a subscript for oxygen means that there is only one oxygen atom in the compound.

Thus, when there is no subscript for an element in a chemical formula, it signifies that there is a single atom of that element in the compound.

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A covalent bond is the exact number of bonded pairs of electrons in a compound

One electron is added by each atom to a pair of shared electrons in a single bond. While double bonds share only one pair of electrons, triple bonds share three pairs. Bonds with multiple covalent bonds exchange several electron pairs

Covalent bonding happens when atoms share electron pairs. Atoms join together through covalent bonds to form a full electron shell, which boosts stability. By sharing their outermost (valence) electrons, atoms can fill out their outer electron shell and become stable. Nonmetals will swiftly create covalent bonds with other nonmetals in order to achieve stability.

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Answer:

0.409 L

Explanation:

Because you are dealing with volume and temperature, you need to use the Charles' Law equation:

V₁ / T₁ = V₂ / T₂

In this equation, "V₁" and "T₁" represent the initial volume and temperature. "V₂" and "T₂" represent the final volume and temperature.

V₁ = 5.18 L                            V₂ = ? L

T₁ = 76.0 °C                          T₂ = 6.0 °C

V₁ / T₁ = V₂ / T₂                                           <----- Charles' Law equation

5.18 L / 76.0 °C = V₂ / 6.0 °C                     <----- Insert values

0.06815789 = V₂ / 6.0 °C                          <----- Simplify left side

0.409 L = V₂                                              <----- Multiply both sides by 6.0

The surface area of the statute covered with the gold is 9,627.32 m².

Volume is a scalar quantity expressing the amount of three-dimensional space enclosed by a closed surface.

The volume of the statute covered with gold is calculated as follows;

Volume = mass/density

Volume = (279 kg) / (19,320 kg/m³)

Volume = 0.0144 m³

The surface area of a solid object is a measure of the total area that the surface of the object occupies.

V = S.A x h

where;

S.A = V/h

S.A = (0.0144) / (0.0015 x 10⁻³)

S.A = 9,627.32 m²

Thus, the surface area of the statute covered with the gold is 9,627.32 m².

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Answer:

D.) in the cloud-like areas around the nucleus

Explanation:

A.) is incorrect. Electrons exist in orbitals in the Bohr's Model.

B.) is incorrect. Electrons do not exist in the nucleus. They always exist outside of the nucleus, but their exact position has been debated.

C.) is incorrect. While the electron clouds in the quantum mechanical model can cover a relatively large amount of space, the distance from the nucleus is not great. Within this cloud, electrons can exist closer to the nucleus at a particular time.

D.) is correct. Electrons are said to exist somewhere within these clouds around the nucleus. The model uses the cloud references to display how you can never be sure where the electrons are located - they are always moving around.

electrical conductivity is the kind of defect or dislocation a carbon in a ti metal lattice represents.

The electrical conductivity of a metal is the result of the movement of charged particles. Atoms of metal elements are electrons in the outer shell of the atom and are characterized by the presence of valence electrons that can move freely around

Staircase dislocations and Lomer-Cottrell dislocations are examples of fixed dislocations. The two main types of movable dislocations are blade dislocations and spiral dislocations. The blade dislocations can be visualized as being caused by the termination of the atomic plane at the center of the crystal.

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Answer:

See below

Explanation:

It is melting the ice ( or other solid) at a constant temperature...the solid will absorb heat as it melts but remain at the same temp

In an aqueous solution containing Mn(II) and Mn (IV) salts, Mn (IV) cation is expected to be the more strongly hydrated.

A chemical event called hydration occurs when two substances interact with water. Since Mn (IV) has a stronger cation with a +4 charge than Mn (II), it will draw more oxygen ions from the Mn(II) in aqueous solution. Mn(IV) will consequently be more intensely hydrated.

Another reason for this is that Mn(IV) ions are often smaller than ions. Now, if we take a look at the element that significantly influences hydration, it is ion size. Therefore, the ion will be more hydrated if it is smaller.

So, In an aqueous solution containing Mn(II) and Mn (IV) salts, Mn (IV) cation is expected to be the more strongly hydrated.

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Considering the definition of radioisotope, a radioactive isotope is an isotope that contain an unstable combination of neutrons and protons, or excess energy in their nucleus.

An atomic species is defined by the number of protons in the nucleus (called the atomic number, Z) and the total number of protons plus neutrons (called the mass number, A).

Isotopes are those atoms of an element with the same atomic number but different atomic mass, that is, with the same number of protons and therefore identical chemical properties, but different numbers of neutrons and different physical properties.

Isotopes can be stable and unstable or radioisotopes.

So, a radioisotope is a chemical element whose nucleus is unstable, that is, in imbalance in the relationship between protons and neutrons. Due to this, this element releases the excess energy it contains in the form of ionizing radiation until this element reaches stability.

In summary, radioisotopes are the unstable form of an element that emits radiation to transform into a more stable form.

Finally, a radioactive isotope is an isotope that contain an unstable combination of neutrons and protons, or excess energy in their nucleus.

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strength in milligrams is 0.3mg

Mass of the solute in grams/Volume of the solution in litres equals the strength of the solution. The overall formula must be multiplied by 1000 if the volume is measured in millilitres (mL). The concentration of the solution, measured in grammes per litre, can be used to determine the solution's strength.

Molarity -  The moles of solute per litre of solution is measured as molarity. For instance, when table salt is dissolved in water, water serves as both the solution and the solute. Sodium chloride weights 58.44 grammes per mole. One molar solution, or 1M, is created by dissolving 58.44 grammes of sodium chloride in one litre of water.

Relation between Molarity and Strength?

The volume of solute in one litre of a solution determines its strength. As a result, a solution's strength is calculated by multiplying its molecular mass by its molarity.

1 grain = 64.8 milligrams.

1/200 grains = 64.8/200

                     = 0.3mg

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Based on the mole ratio, the mass of oxygen reacting is 45.8 g.

The incomplete combustion of propane with oxygen produces carbon (ii) oxide and water.

The mole ratio of propane to oxygen according to the equation of the reaction is 2 : 7.

Molar mass of propane = 44 g/mol

Molar mass of oxygen = 32 g/mol

moles in 18.0 g = 18/44 mole

Mass of oxygen reacting = 18/44 * 7/2 * 32 = 45.8

In conclusion, incomplete combustion of propane produces carbon (ii) oxide.

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The molecular formula of dye:

A major textile dye manufacturer developed a new yellow dye with a molecular formula [tex]C_{15}N_{3}H_{15}[/tex].

Given:

Percentage composition:

C = 75.95%

N = 17.72%

H = 6.33%

Molar mass = 240 g

To find: molecular formula of dye

Calculation:

Let's assume the mass of the compound is 100 gm.

So,  Mass of C = 75.95 gm

Mass of N = 17.72 gm

Mass of H = 6.33 gm

The number of moles = given mass/mass

Therefore, the number of moles of C = 75.95/12 = 6.33

The number of moles of N = 17.72/14 = 1.27

Number of moles of H =6.33/1 = 6.33

Simplest ratio:

C = 6.33/1.27 = 4.98 =5

N = 1.27/1.27 = 1

H = 6.33/1.27 = 4.98 =5

Therefore, the empirical formula is [tex]C_{5}NH_{5}[/tex]

The mass of empirical formula = 12 x 5 + 14 + 1 x 5 = 79 gm

Number of moles= molar mass/ empirical formula

n = 240/79 = 3.04 =3

Therefore, molecular formula = empirical formula x n

Hence, molecular formula = [tex]C_{15}N_{3}H_{15}[/tex]

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The term would be partial pressure.

The partial pressure of a gas refers to the amount of pressure contributed by the gas to the overall pressure of a non-reacting gas mixture.

For example, if a gas is formed from a mixture of two gases A and B. The pressure of the gas would be the sum of the pressure of A and that of B. The pressures that A and B contribute to the overall pressure of the gas are called the partial pressures of A and B respectively.

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Answer:

which one is isn't the one that is wrong

Explanation:

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The mechanical advantages of the machine are 3.

The amount that a force is boosted by employing a machine is known as the mechanical advantage. It is determined by dividing the applied force by the machine's force ( force exerted by the machine).

That is the mechanical advantage of any machine is equal to the ratio between the output force and the input force.

Mechanical advantages M.A. = Input force / Output force

We have,

Input force: 52 N

Output force: 156 N

Therefore,

Mechanical advantage = Input force / Output force.

52/156 = 3

Hence, the mechanical advantages of the machine are 3.

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a.

A substance's specific heat tells you how much heat is required to increase the temperature of 1 g of that substance by 1°C.

The equation that establishes a relationshop between heat and change in temperature is

q = m • c • ∆T, where

q - heat absorbed

c - the specific heat of the substance, in your case of water

ΔT - the change in temperature, defined as the difference between the final temperature and the initial temperature

so:

q = 1.00 g • 4.18 J/g×°C • (75.0 - 38.5)°C

q = 152,57 J

just apply this formula for all exercises

A. How many Joules of energy are required to raise 3.50kg of water from 38.5 to 75.0C ? (specific heat of water is 4.184J/g C)(1000g=1kg)

Answer:

q = 534,506 Joules

q = 534.506 KiloJoules

534.506 KiloJoules or 534,506 Joules energy required to raise 3.50kg of water from 38.5 to 75.0C

Sp. Heat is the heat required to increase the temperature of the 1 mass of a given substance by a  [tex]1^{0}[/tex] C temperature.

The formula of specific heat Cp = [tex]\frac{q}{m (∆T)}[/tex]

Where,

q = energy of substance (Joules / KiloJoules),

Cp = Specific heat capacity of the substance (J/Kg.C),

m = mass of the substance

∆T = Change in temp.

Explanation:

Given data from que: -

Mss of the water (m) = 3.50 Kg = 3.50 × 1000 gm = 3500 gm

specific heat capacity of water (Cp) = 4.184J/g C

Change in temp (∆T) = 75.0 - 38.5 = 36.5

now, put all above given data in formula

we get

Cp = [tex]\frac{q}{m (∆T)}[/tex]

q = Cp ×m×∆T

q = 4.184×3500×36.5

q = 534,506 Joules

q = 534.506 KJ

A diprotic acid is titrated with a strong base. The pH at the first half-equivalence point is 3.27. The pH at the second half-equivalence point is 8.53. The value of ka2 is 27.89.

pH is used to measure whether the substance is acidic, basic or neutral and the range is 0-14. If the pH is less than 7 then the solution is acidic in nature. if the pH is more than 7 then the solution is basic in solution. If the pH is equal to 7 then the solution is neutral in nature.

To find the polyprotic value

[tex]K_{a_2}[/tex] = pH of first half equivalence point × pH of second half equivalence point

[tex]K_{a_2}[/tex] = 3.27 × 8.53

      = 27.89

Thus from the above conclusion we can say that A diprotic acid is titrated with a strong base. The pH at the first half-equivalence point is 3.27. The pH at the second half-equivalence point is 8.53. The value of ka2 is 27.89.

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It is true that brittleness is a physical property that differs from one kind of material to another.

Physical qualities of a substance are those that can be seen without changing the substance's identity.

If a material splits under stress with low elastic deformation and little to no substantial plastic deformation, it is considered brittle.

Brittleness is a physical property as it alters the shape of the substance but not the identity of substance.

For example - the brittleness of chalk is different than the brittleness of glass. Thus we can say that the brittleness of chalk's material is different than the  brittleness of glass's material.

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The concentration of the sodium hydroxide will be 0.016 M

First, the concentration of the diluted nitric acid needs to be found.

m1 = 2.0 M,  v1 = 100 mL, v2 = 300.0 mL

m2 = 2 x 100/300 = 0.6667 M

The equation of the reaction goes thus: [tex]HNO_3 + NaOH = NaNO_3 + H_2O[/tex]

The mole ratio is 1:1.

Mole of 0.6667 M, 7.05 mL HNO3 = 0.6667 x 0.00705 = 0.0047 mol

Equivalent mole of NaOH = 0.0047 mol

Molarity of 0.0047 mol, 30.0 mL NaOH = 0.0047/0.3 = 0.016 M

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Answer:

The synthesis of zeolite-supported Mo carbide species was studied by testing different reduction/carburization conditions applied to a zeolite-supported Mo oxide catalyst, with the aim to find the optimized treatment conditions necessary to form stable supported Mo carbide catalysts ex situ for application in methane dehydroaromatization reaction. Four types of treatment were performed and studied using temperature-programmed reduction and carburization profiles: (1) heating the catalyst in a reducing gas, H2, up to reaction temperature and switching to CH4; (2) heating the catalyst in a reducing gas, H2, mixed with dilute CH4; (3) heating the catalyst in CH4 up to reaction temperature; and (4) heating the catalyst in an inert gas (commonly He) up to reaction temperature and then switching to CH4 or to H2 followed by CH4 or to H2/CH4 mixture. Each of these processes were stopped at intermediate points to analyze the phases that were present in order to identify the structural evolution of the supported Mo carbides that originate from the supported Mo oxides. Once the supported carbides were formed, they were quenched under the same gas mixture, and then they were each tested in methane dehydroaromatization via previous heating to reaction temperature in He flow. Despite all of them showing only presence of Mo2C species on HZSM-5, the catalytic properties were dramatically different. Catalysts treated in H2 or CH4/H2 showed remarkably higher stability. These catalysts exhibited a higher Mo dispersion and thus exposure on the active surface.

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Answer:

Carbon:  14

Oxygen: 16

Nitrogen: 15

Sulpher: 16

Answer:

1.8 x 10²⁴ atoms Ag

Explanation:

You can find the amount of silver (Ag) atoms by multiplying the moles by Avogadro's number. It is important to arrange the conversion in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 2 sig figs to match the sig figs of the given value.

Avogadro's Number:

6.022 x 10²³ atoms = 1 mole

3.0 moles Ag           6.022 x 10²³ atoms
----------------------  x  --------------------------------  = 1.8 x 10²⁴ atoms Ag
                                           1 mole

Answer:

.5 gm / ml

Explanation:

Density is defined as   mass/ volume

  so   density of this substance is   5 gm / 10 ml =  .5  gm/ ml

The amino acid and which atom which has most to do with myoglobin’s ability to bind o2 is histidine and haemoglobin respectively

Amino acids simply refers to those molecular substances which combine together to form proteins. However, they are the end products of protein digestion

So therefore, the amino acid and which atom which has most to do with myoglobin’s ability to bind o2 is histidine and haemoglobin respectively

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Red curve shows the course of the reaction in the presence of an enzyme. Line a represents the activation energy for that reaction.

Hence, Option (iv) is correct answer.

Activation energy is the minimum energy required an input of energy to initiate the reaction.

[tex]k = Ae^{\frac{-E_a}{RT}}[/tex]

where,

k = rate constant

A = pre-exponential factor

Eₐ = activation energy

R = universal gas constant

T = absolute temperature (in K)

Activation energy = Threshold energy - Energy of colliding molecule.

Thus from the above conclusion we can say that Red curve shows the course of the reaction in the presence of an enzyme. Line a represents the activation energy for that reaction.

Hence, Option (iv) is correct answer.

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Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: This graph illustrates the course of a chemical reaction with and without an enzyme. While the products and reactants are the same, the presence of an enzyme changes the amount of energy required for the reaction to begin.

Part A - Interpreting the graph

Which curve shows the course of the reaction in the presence of an enzyme--the black curve or the red curve? Which line represents the activation energy for that reaction--a, b, or c?

(i) a black curve; line a

(ii) black curve; line b

(iii) black curve; line c

(iv) red curve; line a

(v) red curve; line b

(vi) red curve; line c