Answer:
Explanation:
according to balance chemical equation
3 A2 moles produced 2 moles of A3B
so 12 moles A2 will produced moles of A3B= 12*2/3=24/3= 8
therefore 12 moles of A2 produced 8 moles of A3B
A balanced chemical reaction is an equation that has the same number of stoichiometry coefficients on both sides. When 12 moles of A₂ react, then 8 moles of A₃B are produced.
What are excess reagents?Excess reagents are the reactants that are present in more quantity than the other reactant and are left in reaction after completion.
The balanced chemical equation:
3A₂ + B₂ → 2A₃B
From reaction: 3 moles of A₂ molecule are needed to produce 2 moles of A₃B. So, 12 moles of A₂ will produce:
(12 × 2) ÷ 3 = 8 moles
Therefore, 8 moles of A₃B will be produced from 12 moles of A₂.
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Classify each of the following as either a physical change or a chemical change.
(a) Dissolving sugar in water
(b) Crushing rock salt
(c) Burning sulfur
(d) Digesting a chili dog
Answer:
(a) Dissolving sugar in water ⇒ physical change
(b) Crushing rock salt ⇒ physical change
(c) Burning sulfur ⇒ chemical change
(d) Digesting a chili dog ⇒ chemical change
Explanation:
Physical changes are those in which the substance does not alter its composition. They only involve changes of states of matter and the chemical substance is stil the same after the change occurs. By other hand, chemical changes are those in which new subtances are formed. So, the subtance is not the same after the change.
(a) Dissolving sugar in water ⇒ physical change; because we obtain a solution of sugar in water (sugar is stil sugar).
(b) Crushing rock salt ⇒ physical change; because we obtain crushed salt, but the chemical composition of the salt is not altered.
(c) Burning sulfur ⇒ chemical change; because sulfur is oxidized (chemical reaction) and new compounds are formed, for example sulfur dioxide.
(d) Digesting a chili dog ⇒ chemical change; because the digestion process is produced by the action of hydrocloric acid, and new compounds are formed.
Which of the following are properties of acids? Check all that apply. • A. Corrosive • B. Reacts with certain metals • C. Tastes bitter □ D. Turns litmus paper blue
Explanation:
a) Corrosive and b) Reacts with certain metals
the observation has to be made up and i can’t think of anything or a hypothesis who can help!
Answer:the answer is hypothesis
Explanation: that’s the answer
Using the correct answer from Part B, calculate the volume of a rectangular prism with a length of 5.6 , a width of 2.1 , and a height of 6.6 Part B answer: 11.76cm^2
Answer:
The volume of the rectangular prism is 77.616 cm³
Explanation:
Here is the remaining part of the question:
Part B:
What value should you use as the area of the base when calculating the answer to Part C.
Part C:
Using the correct answer from Part B, calculate the volume of a rectangular prism with a length of 5.6 cm , a width of 2.1 cm , and a height of 6.6 cm Part B answer: 11.76 cm^2
Explanation:
The volume of a rectangular prism is given by:
V = l×w×h
Where V is the volume of the rectangular prism
l is the length of the rectangular prism
and w is the width of the rectangular prism
Recall that the Area (A) of the base of the rectangular prism can be calculated by using
A = l × w
Hence, the volume of the rectangular prism can also be calculated by substituting this into the equation to give
V = A × h
From the question, the correct answer from part B for the area of the base is 11.76 cm^2; and the height (h) is 6.6 cm
Hence, the volume of the rectangular prism is
V = A × h
V = 11.76 cm² × 6.6 cm
V = 77.616 cm³
You have 87.0mL of a 0.500M stock solution that must be diluted to 0.100M. What is the final volume g
Answer:
435 mL
Explanation:
Step 1: Given data
Initial volume (V₁): 87.0 mLInitial concentration (C₁): 0.500 MFinal volume (V₂): ?Final concentration (C₂): 0.100 MStep 2: Calculate the final volume of the solution
We want to prepare a diluted solution from a concentrated one. We can calculate the final volume of the solution using the dilution rule.
C₁ × V₁ = C₂ × V₂
V₂ = C₁ × V₁ / C₂
V₂ = 0.500 M × 87.0 mL / 0.100 M
V₂ = 435 mL
What is the engine piston displacement in liters of an engine whose displacement is listed as 490 in^3?
Answer:
490 in^3 = 8.03 L
Explanation:
Given:
The engine displacement = 490 in^3
= 490 in³
To determine the engine piston displacement in liters L;
(NOTE: Both in^3 (in³) and L are units of volume). Hence, to find the engine piston displacement in liters (L), we will convert in^3 to liters (L)
First, we will convert in³ to cm³
Since 1 in = 2.54 cm
∴ 1 in³ = 16.387 cm³
If 1 in³ = 16.387 cm³
Then 490 in³ = (490 in³ × 16.387 cm³) / 1 in³ = 8029.63 cm³
∴ 490 in³ = 8029.63 cm³
Now will convert cm³ to dm³
(NOTE: 1 L = 1 dm³)
1 cm = 1 × 10⁻² m = 1 × 10⁻¹ dm
∴ 1 cm³ = 1 × 10⁻⁶ m³ = 1 × 10⁻³ dm³
If 1 cm³ = 1 × 10⁻³ dm³
Then, 8029.63 cm³ = (8029.63 cm³ × 1 × 10⁻³ dm³) / 1 cm³ = 8.02963 dm³
≅ 8.03 dm³
∴ 8029.63 cm³ = 8.03 dm³
Hence, 490 in³ = 8029.63 cm³ = 8.03 dm³
Since 1L = 1 dm³
∴ 8.03 dm³ = 8.03 L
Hence, 490 in³ = 8.03 L
An engine piston displacement of 490 in³ is equivalent to 8.03 L.
The engine piston displacement is 490 in³ and we want to convert it to liters. Since both of them are units of volume, we will need one or more conversion factors.
What is a conversion factor?A conversion factor is an arithmetical multiplier for converting a quantity expressed in one set of units into an equivalent expressed in another.
Step 1: Convert 490 in³ to cm.We will use the conversion factor 1 in = 2.54 cm.
490 in³ × (2.54 cm/1 in)³ = 8.03 × 10³ cm³
Step 2: Convert 8.03 × 10³ cm³ to L.We will use the conversion factor 1 L = 1000 cm³.
8.03 × 10³ cm³ × (1 L/1000 cm³) = 8.03 L
An engine piston displacement of 490 in³ is equivalent to 8.03 L.
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A 0.100 M solution of an acid, HA, has a pH = 2.00. What is the value of the ionization constant, Ka for this acid?
Answer:
[tex]Ka=1.11x10^{-3}[/tex]
Explanation:
Hello,
In this case, since the ionization of the given HA acid is:
[tex]HA\rightleftharpoons H^++A^-[/tex]
The equilibrium expression is:
[tex]Ka=\frac{[H^+][A^-]}{[HA]}[/tex]
Whereas the concentration of hydrogen ions is compute from the pH=
[tex][H^+]=10^{-pH}=10^{-2.00}=0.01M[/tex]
Which also equals the concentration of [tex]A^-[/tex] and the in general the ionization extent, therefore, the acid ionization constant, Ka, turns out:
[tex]Ka=\frac{0.01*0.01}{0.1-0.01}\\ \\Ka=1.11x10^{-3}[/tex]
Regards.
Which chemical formula represents an organic molecule? A.CCl2F2 B.4H2O C.Al2O3 D.H2SO4
Answer:
The answer is Option A = CCl2F2
The chemical formula for an organic molecule is CCl2F2. The correct option is A.
What is an organic molecule?An organic molecule is a complicated compound that is chiefly comprised of carbon atoms bonded with other elements and another carbon atoms.
All lifeforms on Earth are comprised of organic molecules. A molecule is a cluster of atoms which are basically bonded together.
Molecules other than organic molecules is referred to as inorganic molecule. These are basically simple and are not usually encountered in living things.
Although all organic substances encompasses carbon, some substances containing carbon, such as diamonds, are taken as inorganic.
Organic compounds as well as inorganic compounds develops the basis of chemistry.
The chief distinction between organic and inorganic compounds is that organic compounds always contain carbon while most inorganic compounds do not encompass carbon.
Also, perhaps all organic compounds contain carbon-hydrogen or C-H bonds.
Thus, the correct option is A.
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A unimolecular elementary step involves only a single reactant that breaks apart.a) trueb) false
Answer:
True
Explanation:
The correct option is; True.
Unimolecular elementary steps in a reaction requires only one reactants, they are usually decomposition reactions. They take the general form;
A --> B + C
What is the enthalpy change during the process in which 100.0 g of water at 50.0 C is cooled to ice at -30 oC
Answer:
33600 J
Explanation:
From the question,
ΔH = cm(t₂-t₁)..................... Equation 1
Where, ΔH = Enthalpy change of water, c = specific heat capacity of water, m = mass of water, t₂ = Final temperature of water, t₁ = Initial temperature of water
Given: c = 4200 J/kg.°C, m = 100 g = 0.1 kg, t₂ = 50°C, t₁ = -30°C
Substitute these values into equation 1
ΔH = 4200(0.1)(50+30)
ΔH = 420(80)
ΔH = 33600 J
Which is most closely associated with the Lewis dot diagrams for molecules that contain atoms of elements from the boron family, Group 13 (Group IIIA)
The question is incomplete, the complete question is;
Which is most closely associated with the Lewis dot diagrams for molecules that contain atoms of elements from the boron family, Group 13 (Group IIIA)?
a. elements shown as 3+ ions
b. expanded octets of electrons
c. incomplete octets of electrons
d. odd number of valence electrons
e. kernel electrons promoted to the valance shell
Answer:
incomplete octets of electrons
Explanation:
A Lewis dot structure is a representation of a molecule based on the number of valence electrons on its valence shell. These electrons are shown as dots hence Lewis structures are also called dot electron structures.
For elements of group 13, they mostly form dimeric compounds due to the fact that their compounds possess an incomplete octet of electrons. This is common to group 13 elements, hence the answer above.
What must happen to uranium before it can be used as a fuel source?
Answer:
Uranium must be purified before it is used as a fuel source
Explanation:
The purer the uranium sample, the more the concentration of uranium in the fuel is.
Whenever uranium is extracted from nature, it contains a lot of impurities. Only a few special nuclear reactors can utilize uranium in this raw state. most of the others have to get uranium to become about 3% pure before they begin using it.
To do this, uranium has to be passed through a series of chemical reactions all with the aim of extracting the other compounds that may be present in the fuel.
Using VSEPR model, how is the electron arrangement about the central atom (electron-pair geometry) for XeF4 ?
Answer:
See explanation
Explanation:
XeF4 has a square planar structure. There are six electron pairs on the valence shell of the central atom. This gives rise to an octahedral geometry based on valence shell electron pair repulsion theory.
There are two lone pairs of electrons present on the central atom, hence the four bond pairs are found to occupy the corners of a square thereby giving a square planar compound. The two lone pairs are found above and blow the plane of the square.
Which of the following molecules can form hydrogen bonds? Group of answer choices NH3 NaH HI BH3 CH4
Answer:
NH₃
Explanation:
The hydrogen bond is a specially strong type of dipole-dipole interaction. For a hydrogen bond to occur, a molecule must have a hydrogen atom and a very electronegative atom, such as nitrogen, oxygen or fluorine. The hydrogen atom has a positive charge density while the heteroatom has a negative charge density.
Which of the following molecules can form hydrogen bonds?
NH₃ YES
NaH NO
HI NO
BH₃ NO
CH₄ NO
A gas has a temperature of 273.15 K and a pressure of 101.325 kPa. What can be concluded about the gas? It has reached standard temperature and pressure. The pressure needs to be increased to reach the standard pressure. The temperature needs to be increased to reach the standard temperature. Both the temperature and pressure need to be lowered to reach STP.
Explanation:
A gas has a temperature of 273.15 K and a pressure of 101.325 kPa. It can be concluded that this gas has reached standard temperature and pressure.
Standard temperature is zero degree celcius which corresponds to 273.15 degree kelvin.
Standard pressure is 760 mmHg which corresponds to 101.325 kPa.
Answer:
a. it has reached standard temperature and pressure
Explanation:
edge 2021
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-5°F to kelvins nearest whole number
Answer: 252
Explanation:
# turn F to C
C=(F-32)5/9
C=(-5-32)5/9
C=-37 × (5/9)
C= -21
# turn C to K
K=C+273
K=(-21)+273
K=252
Answer:
253 Kelvins
Explanation:
We want to convert -5°F to Kelvins.
First, we must convert -5°F to Celsius. The formula is:
°C= (°F - 32) * 5/9
Plug -5 in for °F.
°C= (-5-32) * 5/9
Solve inside the parentheses first. Subtract 32 from -5.
°C= (-37) * 5/9
Multiply -37 and 5/9.
°C= -20.5555556
-5° F is equal to -20.5555556° C.
Next, convert Celsius to Kelvins. The formula is:
K= °C + 273.15
Plug -20.5555556 in for °C.
K= -20.5555556 + 273.15
Add -20.5555556 and 273.15.
K= 252.594444
Round to the nearest whole number. The 5 in the tenth place tells us to round 252 to 253.
K ≈ 253
-5°F is equal to about 253 Kelvins.
in a science fiction movie, a woman proceeds through nine months of pregnancy in minutes. she takes in no nutrients during this time. she dies during labor, and an emergency c-section is performed to save the child. the child lives for only a matter of hours, rapidly aging, and dies a withered old man. a classmate claims that the movie is based on a government-documented but secret alien encounter.
Answer:
Sounds great
Explanation:
Probably fake but you never know do you
You start with 420 mg of isotope which has half life of 20 days. How many mg will be left after 40 days
Answer:
105 mg
Explanation:
The following data were obtained from the question:
Original amount (N₀) = 420 mg
Half life (t½) =20 days
Time (t) = 40 days
Amount remaining (N) =..?
Next, we shall determine the rate constant K, for the disintegration.
This can be obtained as follow:
Half life (t½) =20 days
Rate constant (K) =?
K = 0.693/ t½
K = 0.693/20
K = 0.03465 /day
Finally, we shall determine the amount remaining after 40 days as follow:
Original amount (N₀) = 420 mg
Rate constant (K) = 0.03465 /day
Time (t) = 40 days
Amount remaining (N) =..?
Log(N₀/N) = kt/2.3
Log (420/N) = (0.03465 x 40)/2.3
Log (420/N) = 1.386/2.3
Log (420/N) = 0.6026
420/N = antilog (0.6026)
420/N = 4
Cross multiply
420 = N x 4
Divide both side by 4
N = 420/4
N = 105 mg
Therefore, the amount remaining after 40 days is 105 mg.
Which of the following properties are intensive, and which are extensive? Malleability intensive or extensive Length intensive or extensive Hardness intensive or extensive Volume intensive or extensive
Answer:
Malleability is intensive
Length is extensive
Hardness is intensive
Volume is extensive
Explanation:
Extensive properties change when u change the size of an object and intensive properties don’t
Also I just took the quiz
A physical property refer to the properties of an object that can be measured and observed without changing (altering) the chemical composition of the object.
In Chemistry, there are two (2) main types of physical property and these include:
I. Extensive property: this is a property that changes when the size of an object changes. Some examples of an extensive property are:
Length.Volume.II. Intensive property: it is a property that remains the same regardless of the change in the size of an object, Some examples of an intensive property are:
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During which phase of mitosis do the chomosomes align at the middle part of the cell? (1 point) O telophase O anaphase O metaphase O prophase
Answer:
Metaphase - this is when the chromosomes align
During Metaphase of mitosis, the chomosomes align at the middle part of the cell. Henc ethe correct option is (C).
What is Mitosis cell division ?In cell biology, mitosis is a part of the cell cycle in which replicated chromosomes are separated into two new nuclei.
Cell division by mitosis gives rise to genetically identical cells in which the total number of chromosomes is maintained. Therefore, mitosis is also known as equational division.
During metaphase, the nucleus dissolves and the cell's chromosomes condense and move together, aligning in the center of the dividing cell.
At this stage, the chromosomes are distinguishable when viewed through a microscope.
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Olivia noticed that the pH of her garden soil decreased after it rained. Did her garden soil become more acidic or less acidic
Answer:
It is becoming more acidic.
Explanation:
The pH scale is a way to express the concentration of hydrogen ions. This scale goes from 0 to 14 and it is adimensional.
If the pH < 7, the solution is acid.If the pH = 7, the solution is neutral.If the pH > 7, the solution is basic.The lower the pH, the more acidic the solution. Since the pH of the garden soil of Olivia is decreasing, it is becoming more acidic.
What is the pH of a buffer made from 0.130 mol of HCNO (Ka = 3.5 × 10⁻⁴) and 0.410 mol of NaCNO in 2.0 L of solution?
Answer:
[tex]pH=3.95[/tex]
Explanation:
Hello,
In this case, by using the Henderson-Hasselbach equation we can compute the pH as follows:
[tex]pH=pKa+log(\frac{[base]}{[acid]} )[/tex]
Whereas the concentration of the acid (HCNO) and the base (NaCNO) are computed by considering the given volume:
[tex][base]=\frac{0.410mol}{2.0L}=0.205M[/tex]
[tex][acid]=\frac{0.130mol}{2.0L}=0.065M[/tex]
Therefore, the pH turns out:
[tex]pH=-log(3.5x10^{-4})+log(\frac{0.205M}{0.065M} )\\\\pH=3.95[/tex]
Regards.
There are 24 g of carbon in a substance with a mass of 30 g. What is the percent carbon by mass for this substance?
here are 24 g of carbon in a substance with a mass of 30 g. What is the percent carbon by mass for this substance?
Answer:
Explanation:
The composition of the vapor in mass percent.
According to Dalton's law,
where is the partial pressure of the gas j, is the mole fraction of the gas j in the gas mixture and is the total pressure.
To know the composition of the vapor we must first calculate the molar fractions of the components of the mixture in the vapor:
→
→
If we consider 1 mole of solution then we will have 0.56 mol of benzene and 0.44 mol of toluene in the vapor. In this way, the number of grams of each component in the vapor will be,
The percentage by mass of each component in the vapor will be,
% benzene = (g benzene / g total) x 100% = (43.7 g / (43.7 g + 40.6 g)) x 100% → % benzene = 51.8 %
% toluene = 100 % - % benzene → % toluene = 41.2%
So, the composition of the vapor in mass percent is 51.8 % benzene and 41.2% toluene.
Why is the composition of the vapor different from the composition of the solution?
The composition of the vapor will be different from that of the solution, since the more volatile compound will have a larger molar fraction in the vapor phase than in the liquid phase.
In a mixture with different volatile components the compound that volatilizes more easily is the one that will have greater capacity to escape from the solution in the form of vapor and, therefore, will be in a greater composition in the vapor above the solution.
We can measure this by means of vapor pressure, which is a measure of the volatility of a substance, that is, the capacity of the substance to pass from a liquid to a gaseous state. In the question, benzene is in greater proportion than toluene in the vapor mixture since it has a higher vapor pressure (94.2 torr) than toluene (28.4 torr).
6. Which statement is true about all metals?
A) They are attracted to a magnet.
B) They are weak and brittle.
C) They may be used to form alloys.
D) They react with water.
Answer:
A They are attracted to a magnet
Answer:
not sure but I think it's c
Zn + HCl → H2 +ZnCl2 type of reaction?
Answer:
The answer to your question is "Displacement " reaction. Here in the reach Zn +HCl ⇒ZnCl2 + H2 zinc replaces the hydrogen to make the zinc chloride and hydrogen gas is produced as the result and liberated.
reaction container holds 5.77g of P4 and 5.77g of O2. The following reaction occurs:
P4 + O2 → P4O6.
If enough oxygen is available then the P4O6 reacts further:
P4O6 + O2 → P4O10. (P=31, O =16)
a. What is the limiting reagent for the formation of P4O10? (1mk)
b. What mass of P4O10 is produced? (3mks)
c. What mass of excess reactant is left in the reaction container? (1reaction container holds 5.77g of P4 and 5.77g of O2. The following reaction occurs:
P4 + O2 → P4O6.
If enough oxygen is available then the P4O6 reacts further:
P4O6 + O2 → P4O10. (P=31, O =16)
a. What is the limiting reagent for the formation of P4O10? (1mk)
b. What mass of P4O10 is produced? (3mks)
c. What mass of excess reactant is left in the reaction container? (1
Answer:
a. O₂ is limiting reactant
b. 5.68g P₄O₁₀ are produced
c. 5.83g P₄O₆ are left in the reaction container
Explanation:
Based in the first reaction,
P₄ + 3O₂ → P₄O₆
1 mole of P₄ reacts with 3 moles of oxygen
Initial moles of P₄ and O₂ are:
Moles P₄ (Molar mass: 124g/mol):
5.77g P₄ * (1mol / 124g) = 0.0465 moles P₄
Moles O₂ (32g/mol):
5.77g O₂ * (1mol / 32g) = 0.180 moles O₂
For a complete reaction of 0.0465 moles P₄ are required:
0.0465 moles P₄ * (3 moles O₂ / 1 mol P₄) = 0.140 moles of O₂
That means will remain 0.040 moles of O₂ and there are produced 0.0465 moles of P₄O₆
For the second reaction:
P₄O₆ + 2O₂ → P₄O₁₀
2 moles of oxygen reacts per mole of P₄O₆
For a complete reaction of P₄O₆ are required:
0.0465 moles P₄O₆ * (2 moles O₂ / 1mol P₄O₆) = 0.093 moles of O₂. As there are just 0.040 moles of O₂,
a. O₂ is limiting reactantb. There are produced:
0.040 moles O₂ * (1 mole P₄O₁₀ / 2 moles O₂) = 0.020 moles P₄O₁₀
In mass (Molar mass: 284g/mol):
0.020 moles * (284g / mol) =
5.68g P₄O₁₀ are producedc. Also, 0.020 moles P₄O₆ are reacting and will remain:
0.0465 mol - 0.020 mol = 0.0265 moles P₄O₆
In mass (Molar mass: 220g/mol):
0.0265 moles P₄O₆ * (220g / mol) =
5.83g P₄O₆ is left in the reaction containerif jerome is swinging on a rope and transferring energy from gravitational potential energy to kinetic energy
Answer:
If Jerome is swinging on a rope and transferring energy from gravitational potential energy to kinetic energy,work is being done. Work is said to be done when it transforms energy from one form to another or from one place to another.
Explanation:
i need to know the measurements of this to the appropriate amount of significant figures
Answer:
[See Below]
Explanation:
23 or 23.5 ml.
If the eyepiece of your scope has a power of 10, and the selected objective lens has a power of 20,what is the total
magnification?
20x
200x
O O
Ο Ο
0 30x
300x
Answer:
200x
Explanation:
The total magnification of a microscope depends on the power of the eyepiece and that of the objective lens. It is obtained by multiplying the two factors together.
The total magnification of a microscope can be mathematically expressed as:
Total Magnification = ocular/eyepiece magnification x objective magnification
In the illustration, eyepiece magnification = 10 and objective magnification = 20. Hence,
Total Magnification = 10 x 20 = 200x
The magnification power of the microscope has been 200X. Thus, option B is correct.
A microscope has been the instrument used for the analysis of the magnified image of micro-sized or small objects.
The microscope has been consisted of the objective lens and eyepiece that adjusts the level of magnification of the microscope.
The magnification of the microscope has been the product of the power of the eyepiece and objective lens.
Magnification power = Objective lens power [tex]\times[/tex] Eyepiece power
The given power of objective lens = 20
The power of the eyepiece = 10
Magnification power = 20 × 10
Magnification power = 200X.
The magnification power of the microscope has been 200X. Thus, option B is correct.
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Sodium only has one naturally occuring isotope, Na23 , with a relative atomic mass of 22.9898 u. A synthetic, radioactive isotope of sodium, Na22 , is used in positron emission tomography. Na22 has a relative atomic mass of 21.9944 u.
A 1.5909 g sample of sodium containing a mixture of Na23 and Na22 has an apparent "atomic mass" of 22.9785 u . Find the mass of Na22 contained in this sample
Answer:
0.000399316 g
Explanation:
We can start with the molar fraction for each isotope:
We can say that the abudandance of [tex]^2^3Na[/tex] is an unknow value "X" and the molar fraction of [tex]^2^2Na[/tex] is "Y". We have to keep in mind that the molar fractions can be added:
Y + X = 1
So, we can put the molar fraction of [tex]^2^2Na[/tex] in terms of [tex]^2^3Na[/tex], so:
Y=1-X
So, we will have the molar fraction of each isotope:
[tex]^2^2Na[/tex]: X-1
[tex]^2^3Na[/tex]: X
And the atomic mass:
[tex]^2^2Na[/tex]: 21.9944
[tex]^2^3Na[/tex]: 22.9898
If we multiply the molar mass by the each atomic mass of each isotope we will have:
[tex] 22.9898*(X)~+~21.9944*(X-1)~=~22.9785[/tex]
Now we can solve for "X" :
[tex]22.9898X~+~21.9944X~-21.9944~=~22.9785[/tex]
[tex]44.9842X-21.9944~=~22.9785[/tex]
[tex]44.9842X~=~22.9785~+~21.9944 [/tex]
[tex]44.9842X~=~44.9729 [/tex]
[tex]X~=~\frac{44.9729}{44.9842}[/tex]
[tex]X~=~0.999749 [/tex]
The molar fraction of [tex]^2^3Na[/tex] is 0.999749. Now we can calculate the molar fraction of [tex]^2^2Na[/tex], so:
[tex]Y~=~1-0.999749~=~0.000251 [/tex]
Now, if we multiply the molar fraction by the mass we can find the mass of [tex]^2^2Na[/tex], so:
[tex]mass~of~^2^2Na~=~1.5909~g*0.000251~=~0.000399316~ g[/tex]
The mass of [tex]^2^2Na[/tex] is 0.000399316 g
I hope it helps!