Given the graph of the function, f(x) , what is the value of f (-2)?

Answer:

24,150km

Step-by-step explanation:

The plane travels 3450km in 1 hr, since we need the distance traveled in 7 hrs we need to multiply 3450 by 7.

distance in 7hrs: 3450*7 = 24,150km

Answer:180 °

Step-by-step explanation:

Answer:

90 degrees

Step-by-step explanation:

The only numbers that are possible to be divided into 180 are these: 30, 45, 60, 90, & 180.

Now to figure out if this figure is symmetrical. It is. Why? Because you can put at least one line through each triangle. 8 in total but 180 cannot be divided by 8. So you could maybe split it in half. 180/4= 45

45x2= 90

Easy: Since there are now, two halves, since it is split up, it could be possible that the answer could be 90. Because 180/2 halves= 90.

The answer is 90

[tex]\textbf{Heya !}[/tex]

use the slope-formula:-

[tex]\sf{\cfrac{y2-y1}{x2-x1}}[/tex]

put-in the values

[tex]\sf{\cfrac{-2-1}{1-(-3)}}[/tex]

[tex]\sf{\cfrac{-3}{1+3}}[/tex]

[tex]\sf{\cfrac{-3}{4}[/tex]

[tex]\sf{-\cfrac{3}{4}}[/tex]

`hope it's helpful to u ~

The probability that at least one of them is a kindergartner; 0.643.

Calculating or estimating how likely something is to occur is what probability is all about. The likelihood of an event occurring can be expressed using words like "certain," "impossible," or "probable."

Probabilities are always expressed in mathematics as fractions, decimals, or percentages with values ranging from 0 to 1.

Calculation for the probability of the one of them is a kindergarden;

The total number of children is 8.

The total number of kindergarden are 3.

The total number of first graders are 5.

Let 'P' be the probability that at least one of them is kindergarden.

P(at least one kindergartner) = 1 - P(no kindergartner) = 1 - P(all first-graders)

The probability that all are first-graders = (5/8)×(4/7)

                                                                  = 5/14

Therefore, P(at least one kindergartner) = 1 - (5/14)

                                                                   = 9/14

                                                                   = 0.643

Therefore, if two children are ill then, the probability that at least one of them is a kindergartner is 0.643.

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The correct question is-

A carpool contains three kindergartners and five first-graders. if two children are ill, find the probability that at least one of them is a kindergartner.

Answer: 225

Step-by-step explanation:

What is a square number?

A square number is a product of a number times itself

So, the 12th square number would be 12 * 12, or 12²

The 9th square number would be 9 * 9, or 9²

The equation would be 12² + 9²

So:

12² + 9²

= 144 + 81

= 225

So, the answer is 225

The probability of rolling an odd number is 9/19.

According to the statement

Total number of possible outcomes = 38

Odd numbered of outcomes = 18

Now we find the probability

Probability = possible outcomes / total outcomes

Probability = 18/38

Probability = 9/19

So, The probability of rolling an odd number is 9/19.

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The area of the pool that needs to be covered is 960.42 square feet.

According to the question:

Let us find the perimeter of our given pentagon by multiplying each side length by 5.

[tex]Perimeter of community pool $=5 \times 23.62\\Perimeter of community pool $=118.1$[/tex]

Now let us find apothem of our pentagon by using Pythagoras theorem.  

[tex]a^{2}=20.10^{2}-11.81^{2}\\$a^{2}=404.01-139.4761\\$a^{2}=264.5339\\$a=\sqrt{264.5339}\\$a=16.2645$[/tex]

Upon substituting our given values in above formula we will get,

[tex]Area of community pool =\frac{1}{2} \times 16.2645 \times 118.1\\Area of community pool $=8.13224907 \times 118.1\\Area of community pool $=960.418615627971 \approx 960.42$[/tex]

Therefore, the area of the pool that needs to be covered is 960.42 square feet.

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Answer: B). 960 ft2

Step-by-step explanation:

If the value of a is 7, b is 14 in the rhombus then the perimeter of the rhombus is equal to 31.3 units.

Given that the value of a is 7,b is 14.

We are required to find the perimeter of the rhombus.

The values which are given to us are of the lengths of diagonals of rhombus.

Perimeter of the rhombus is equal to 4 times the side of the rhombus. So in order to find the perimeter of the rhombus we need the side of the rhombus not the diagonals.

When we draw the diagonals in the rhombus it forms four right angled triangle in which the Base is equal to 7/2 units and 7 is the perpendicular.

We have to use pythagoras theorem to find the hypotenuse which is the side of the rhombus.

Suppose base is BC , perpendicular is AB and hypotenuse is AC.

AC=[tex]\sqrt{7^{2} +7/2^{2} }[/tex]

=[tex]\sqrt{49+49/4}[/tex]

=[tex]\sqrt{245/4}[/tex]

=7.826

Perimeter of rhombus=4*side

=4*7.826

=31.304

After rounding off it will be 31.3 units.

Hence if the value of a is 7, b is 14 in the rhombus then the perimeter of the rhombus is equal to 31.3 units.

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The matched answers are:

1. semicircle

2. central angle

3. Radius

4. Secant

5. center

6. tangent

7. diameter

8. minor arc

9. chord

10. major arc

A circle is the locus of points equidistant from a given point called the center of the circle.

A circle can be described if its radius and the center of the circle is known.

Analysis:

1. RCH  is called a semicircle when a diameter divides a circle into two equal parts, a part is called the semicircle.

2. ∠RAH is the central angle, because it is the angle subtended at the Center of the circle.

3. CA is the radius of the circle, a line drawn from the center to any point on the circumference of the circle.

4. MR is a secant, a line that cuts the circle into two parts.

5. A is the center of the circle.

6. MT is the tangent, because line MT touches the circle at a point T.

7. CH is the diameter of the circle, a line that divides the circle into two semi circles.

8. CT is the minor arc, the curved line that is found in the smaller part of the divided circle.

9. HT is chord, it is a line that divides the circle into two unequal parts.

10. CRH is  major arc, the curved line of the bigger portion of the divided circle.

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The equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

A quadratic function is represented as:

y = a(x - h)^2 + k

Question #6

The vertex of the graph is

(h, k) = (-1, 2)

So, we have:

y = a(x + 1)^2 + 2

The graph pass through the f(0) = -2

So, we have:

-2 = a(0 + 1)^2 + 2

Evaluate the like terms

a = -4

Substitute a = -4 in y = a(x + 1)^2 + 2

y = -4(x + 1)^2 + 2

Question #7

The vertex of the graph is

(h, k) = (2, 1)

So, we have:

y = a(x - 2)^2 + 1

The graph pass through (1, 3)

So, we have:

3 = a(1 - 2)^2 + 1

Evaluate the like terms

a = 2

Substitute a = 2 in y = a(x - 2)^2 + 1

y = 2(x - 2)^2 + 1

Question #8

The vertex of the graph is

(h, k) = (1, -2)

So, we have:

y = a(x - 1)^2 - 2

The graph pass through (0, -3)

So, we have:

-3 = a(0 - 1)^2 - 2

Evaluate the like terms

a = -1

Substitute a = -1 in y = a(x - 1)^2 - 2

y = -(x - 1)^2 - 2

Hence, the equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

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The experimental probability that the subsequent booth competitor will receive a reward is 3/8.

The possibility of an event occurring is determined by probability.

The probability of the occurrence ranges from 0 to 1.

If the event doesn't happen, it = 0;

otherwise, it = 1.

For instance, the likelihood that it will storm on Sunday ranges from 0 to 1. If it storms, the event is given a value of 1. If it doesn't, the event is given a value of zero.

Depending on the outcome of a study that has been run several times, the experimental probability is calculated.

The number of winners in the games divided by the total number of competitors in those games determines the probability that the following competitor will earn a reward.

So, here the probability = 6/16 = 3/8 (by dividing both the numerator and the denominator by 2).

Therefore, the final solution is P= 3/8 .

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The margin of error is calculated using the formula, C. ME = z × s / √n.

The formula for finding the margin of error is given as: ME = z × s / √n, where we have the following:

ME = margin of error

z = z-score

s = population standard deviation

n = sample size

The margin of error is used to determine amount of error in a random sampling.

Thus, the formula is: C. ME = z × s / √n.

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Answer:

Answer C: m = 26, f = 22

there is a typo in answer D.

Step-by-step explanation:

There are 48 vehicles, so m + f = 48.

They have 140 wheels, so 2m+4f = 140.

You can rewrite the first as m = 48-f and then plug it into the second:

2(48-f) + 4f = 140 =>

96 - 2f + 4f = 140 =>

2f = 140 - 96 =>

2f = 44

f = 22

m = 48 - 22 = 26

Answer:

D

Step-by-step explanation:

Let m = motorcycles and c = cars

m + c = 48                 2m + 4c = 140

m + c  = 48  Multiple this equation through by -2

-2m -2c = -96  Add this to the second equation above

2m +4c = 140

        2c = 44  Divide both sides by 2

          c  = 22.  There are 22 cars.  Plug this back into the top equation to find the number of motorcycles.

m + c = 48

m + 22 = 48 Subtract 22 from both sides

m = 26

Generally, the equation of a circle is organized like this: [tex](x-h)^2+(y-k)^2=r^2[/tex], where (h,k) is the centre and r is the radius.

We're given the endpoints of the diameter: [tex](-6,-3)[/tex] and [tex](-6,-8)[/tex].

First, we can find the centre of the circle by finding the midpoint of these two endpoints.

[tex]midpoint=(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2})[/tex]

Plug in the points:

[tex]midpoint=(\dfrac{-6+-6}{2},\dfrac{-3+-8}{2})\\\\midpoint=(-6,\dfrac{-11}{2})[/tex]

Therefore, the centre of the circle is [tex](-6,\dfrac{-11}{2})[/tex]. Plug this into the general equation:

[tex](x-h)^2+(y-k)^2=r^2\\\\(x-(-6))^2+(y-(-\dfrac{11}{2}))^2=r^2\\\\(x+6)^2+(y+\dfrac{11}{2})^2=r^2[/tex]

To find the radius of the circle, we can calculate the distance between the centre and one of the given endpoints:

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2[/tex]

Plug in the centre and one of the endpoints:

[tex]d=\sqrt{(-6-x_1)^2+(\dfrac{-11}{2}-y_1)^2}\\d=\sqrt{(-6-(-6))^2+(\dfrac{-11}{2}-(-3))^2}\\d=\sqrt{(-6+6)^2+(\dfrac{-11}{2}+3)^2}\\\\d=\sqrt{(0)^2+(-5.5+3)^2}\\\\d=\sqrt{(0)^2+(-2.5)^2}\\\\d=\sqrt{(0)^2+(-\dfrac{5}{2})^2}\\\\d=\sqrt{0+\dfrac{25}{4}}\\d=\sqrt{\dfrac{25}{4}}\\\\d=\dfrac{5}{2}[/tex]

Therefore, the radius of the circle is [tex]\dfrac{5}{2}[/tex]. Plug this into the general equation:

[tex](x+6)^2+(y+\dfrac{11}{2})^2=r^2\\\\(x+6)^2+(y+\dfrac{11}{2})^2=(\dfrac{5}{2})^2\\\\(x+6)^2+(y+\dfrac{11}{2})^2=\dfrac{25}{4}[/tex]

[tex](x+6)^2+(y+\dfrac{11}{2})^2=\dfrac{25}{4}[/tex]

The values of x that will give the quadratic equation no real number solutions are -5 and 9

Real roots of a quadratic equation are values of x, whose numbers can be represented on a number line.

Analysis:

We have -[tex]x^{2}[/tex] +3x +c = 0

[tex]b^{2}[/tex] - 4ac  is called the discriminant of a quadratic equation.

if [tex]b^{2}[/tex] - 4ac  < 0, then the quadratic equation has no real root.

where a = -1, b = 3 c = c

[tex](3)^{2}[/tex] -4(-1)c < 0

9 + 4c < 0

4c < -9

c < -9/2

Which means values lower than -9/2 would give the solution no real root.

From, the options,  only -5 would give no real solution, since it is lower than -9/2.

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The expression which is equivalent to 4x²√5x⁴ × 3√5x^8 is; 60x^8.

The expression given in the task content is; 4x²√5x⁴ × 3√5x^8.

Hence, upon evaluation of the product; we have;

= 12x²√25x¹².

= 60x^8.

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Answer:

Vertical shift up 3

Horizontal shift to the right 2

Brainliest, please :)

Answer:

Step-by-step explanation:

f(x) is moved 2 units to the right followed by 3 units up,

The correct option is A. hot water moving through a pipe.

Electrical current passing through a metal wire is similar to hot water moving through a pipe.

Electrical charge carriers, often electrons or atoms deficient in electrons, travel as current. The capital letter I is a typical way to represent current. The ampere, denoted by the letter A, is the common unit.

The method of flowing of electrical current in metal wire is-

Comparison of flow of electricity with flow of water in pipe-

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The complete question is-

which of the following situations would be mist similar to an electrical current passing through a metal wire in a closed circuit?

A. hot water moving through a pipe

B. an automobile traveling through a tunnel

C. an airplane flying through clouds

D. a flying pan heating up on a hot plate

E. a bird building a nest

Answer: [tex]x^{16}y^{22}[/tex]

Step-by-step explanation:

[tex]\frac{(x^6 y^8)^3}{x^2 y^2}=\frac{x^{18}y^{24}}{x^2 y^2}=x^{16}y^{22}[/tex]

Answer:

Perimeter = 36

Area = 81

Step-by-step explanation:

Perimeter of a square is side length * 4.

9*4 = 36

Area of a square is L*L,

9*9 = 81

Using the normal distribution, the value that separates the highest 70% of the scores in a normal distribution from the lowest 30% is:

z = -0.52.

The z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The value that separates the highest 70% of the scores in a normal distribution from the lowest 30% is is the 30th percentile, which is Z with a p-value of -0.3, hence z = -0.52.

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The function will exist on all real numbers. Hence the domain of the exponential function given is all real numbers

The domain are independent values of an expression for which it exist. The standard exponential equation is expressed as y = ab^x

Given the exponential function as shown:

y = 5(3)^x

The function will exist on all real numbers. Hence the domain of the exponential function given is all real numbers

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Answer:

L (1, - 7 )

Step-by-step explanation:

give endpoints (x₁, y₁ ( and (x₂, y₂ )  then the midpoint is

( [tex]\frac{x_{1}+x_{2} }{2}[/tex] , [tex]\frac{y_{1}+y_{2} }{2}[/tex] )

here (x₁, y₁ ) = K (9, - 7 ) and (x₂, y₂ ) = L (x, y )

use the midpoint formula and equate to corresponding coordinates of M

[tex]\frac{9+x}{2}[/tex] = 5 ( multiply both sides by 2 to clear the fraction )

9 + x = 10 ( subtract 9 from both sides )

x = 1

and

[tex]\frac{-7+y}{2}[/tex] = - 7 ( multiply both sides by 2 )

- 7 + y = - 14 ( add 7 to both sides )

y = - 7

Then L  = (1, - 7 )

[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

As per the given information ~

The given triangles are similar, so their corresponding sides should be in same ratio :

[tex]\qquad \sf  \dashrightarrow \: \dfrac{2x}{4} = \cfrac{5}{x - 3} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \dfrac{x}{2} = \cfrac{5}{x - 3} [/tex]

[tex]\qquad \sf  \dashrightarrow \: x(x - 3) = 10[/tex]

[tex]\qquad \sf  \dashrightarrow \: {x}^{2} - 3x = 10 [/tex]

[tex]\qquad \sf  \dashrightarrow \: {x}^{2} - 3x - 10 = 0[/tex]

[tex]\qquad \sf  \dashrightarrow \: {x}^{2} - 5x + 2x - 10 = 0[/tex]

[tex]\qquad \sf  \dashrightarrow \: x(x - 5) + 2(x - 5) = 0[/tex]

[tex]\qquad \sf  \dashrightarrow \: (x + 2)(x - 5) = 0[/tex]

so, x = 5 or -2

but since side length can't be negative, we will take x = 5 neglecting the negative value (-2)

So, side lengths of unknown sides are :

[tex] \qquad \sf  \dashrightarrow \: {2x = 2 × 5 = 10 units} [/tex]

and

[tex]\qquad \sf  \dashrightarrow \: x - 3 = 5 - 3 = 2 \: \: units[/tex]

The quantity of deciliters of apple juice a medium bottle contain is 10 deciliters

4s + 3l = 64

3s + 2l + 2m = 64

6s + 4m = 64

If

m = 10

s = 4

l = 16

Check:

3s + 2l + 2m = 64

3(4) + 2(16) + 2(10)

= 12 + 32 + 20

= 64

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Answer:

C

Step-by-step explanation:

The temperature rises by 30 degrees, so lets say that it goes from 0 to 30.

The temperature is now 30. But then, it falls by 30 degrees. It is now 0 again. The quantities even out, or make 0.

Step-by-step explanation:

[tex] \frac{y2 - y1 }{x2 - x1} = \frac{3 - - 2}{5 - 0} = \frac{5}{5} = 1[/tex]

Determining the slopes of each side, we get the slope of [tex]\overline{AB}[/tex] is [tex]2[/tex], the slope of [tex]\overline{BC}[/tex] is -1/2, the slope of [tex]\overline{CD}[/tex] is 2, and the slope of [tex]\overline{AD}[/tex] is -1/2. Since the slopes of sides AB and CD and BC and AD are equal, it follows that [tex]\overline{AB} \parallel \overline{CD}[/tex] and [tex]\overline{BC} \parallel \overline{AD}[/tex]. Thus, ABCD is a parallelogram because it is a quadrilateral with two pairs of opposite congruent sides. However, we can also note that the slope of side AB is the negative reciprocal of that of sides BC, and thus [tex]\overline{AB} \perp \overline{BC}[/tex]. Using the fact that perpendicular lines form right angles, we can conclude that [tex]\angle ABC[/tex] is a right angle, and since ABCD is thus a parallelogram with a right angle, it must also be a rectangle.

Answer:

Answers will vary based on the method used, but the final slope-intercept form of the equation of A⁢B↔ will be the same.Let the equation of A⁢B↔ in slope-intercept form be y=m⁢x+d, where m is the slope and d is the y-intercept.The coordinates of points A and B are (1, 1) and (5, 3), respectively, so the slope of A⁢B↔ is m=yB−yAxB−xA=24=0.5.Substitute the value of m back in the equation:y = 0.5x + d.Substitute the coordinate of point A (1, 1) in the equation above, and solve for d: 1 = 0.5 + dd = 0.5.Therefore, the equation of A⁢B↔ is y = 0.5x + 0.5. To check whether C lies on A⁢B↔ substitute the x-coordinate of C into the right side of the equation: 0.5 (2.6) + 0.5 = 1.8.The result is equal to the y-coordinate of C. Thus, C satisfies the equation of A⁢B↔ which means that C lies on A⁢B↔.

Step-by-step explanation:

I did it

The range of values of y is -1.6 < y < 7

The complete question is added as an attachment

From the attached image, we have the following sides

4y + 15 and 5y + 8

Both sides must be greater than 0.

So, we have:

4y + 15 > 0 and 5y + 8 > 0

Rewrite as:

4y > -15 and 5y > - 8

Solve for y

y > -3.75 and y > -1.6

If y is less than -1.6, the side 5y + 8 would be negative.

So, we make use of the inequality y > -1.6 as one of the range

Also, 4y + 15 is greater than 5y + 8.

So, we have:

4y + 15 > 5y + 8

Evaluate the like terms

-y > -7

Divide by -1

y < 7

So, we have:

y > -1.6 and y < 7

Combine both inequalities

-1.6 < y < 7

Hence, the range of values of y is -1.6 < y < 7

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