g(x)=7x-2/5x+1
Find g^-1(x), where g^-1 is the inverse of g.
Also state the domain and range of g^-1 in interval notation.

Answer:

God bless you

i don't have nice handwriting

Answer:

6 + x^2

Step-by-step explanation:

Plug in the values for A and B.

(-x + 2x - x + 1) + (x^2 + 5)

Remove the parenthesis. Combine like terms.

-2x + 2x = 0

1 + x^2 + 5

Combine like terms again.

6 + x^2

●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●

               Hi my lil bunny!

   ❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

[tex]( \frac{p^{2} }{2} + \frac{2}{2_{q} }) ( p^{2} - \frac{2}{2_{q}})[/tex]

[tex]= \frac{\frac{1}{2}p^{4}q^{4} + p^{2} q^{2} - 4 }{q^{4}}[/tex]

 ❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

 ●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●

        Have a great day/night!

                   ❀*May*❀

Answer:

ree

Step-by-step explanation:

Answer:

x = 145, y = 35

Brainliest, please!

Step-by-step explanation:

y = 35 degrees because it and the original 35 degree angle are alternate interior angles. Alternate interior angles are congruent, or the same.

x is supplementary to y. x + y = 180. x + 35 = 180. x = 180 - 35. x = 145

Answer:

VW=4

Step-by-step explanation:

UW=VW+UV

5x-5=(x)+(3x-1)

5x-5=4x-1

5x-4x=-1+5

x=4

VW=x= 4

I hope I helped you^_^

Answer:

The median of the data set that you've provided, is 13,350.

Explanation:

13350 is the middle number from the set after writing the set in ascending order. you have 5 numbers on the left of 13350 and 5 on the right, 13350 is the middle one thus it's the median.

After Arranging it in Ascending order

The total number of items is 11

The middle one is 13,350

Therefore the range is 13,350

Must click thanks and mark brainliest

Answer:

(I) 17.25 miles

(ii) 1hr56mins20seconds

(III) 4hrs47mins38seconds

Step-by-step explanation:

(I) read from the lowest distance given

(ii) read from the longest time given

(III) added all times together to get total cycling time

Step-by-step explanation:

here,

shortest distance is 17.25 miles

the longest time is 1:56:20 hrs:mins:secs

total time is 4:47:38

[tex](x+3)(x+1)(x-2)=\\(x^2+x+3x+3)(x-2)=\\(x^2+4x+3)(x-2)=\\x^3-2x^2+4x^2-8x+3x-6=\\x^3+2x^2-5x-6[/tex]

Answer:

Step-by-step explanation:

Adding both equations

4x+5y+5y-4x=19+38

10y = 57

y= 5.7

Subtracting equation i from ii

5y-4x-4x-5y=38-19

-8x=9

x= -0.9

Step-by-step explanation:

To calculate the compound interest we use the formula

Where

A is the amount

P is the principal

C is the compound interest

To find the amount we use the formula

where P is the principal

r is the rate

n is the period

From the question

P = 4000 rupees

rate = 8%

n = 2 years

Substitute the values into the above formula

That's

A = 4665.6

Since the amount is found we can now find the compound interest

C = 4665.60 - 4000

C = 665.6

Hope this helps you

Answer:

C is the answer

Step-by-step explanation:

Answer:

none of them is correct. Option c would have been correct if it was +8x² instead of -8x².

Answer:

[tex]10 {x}^{2} + ( - 18)[/tex]

Step-by-step explanation:

Inserting fx into gx we get

[tex]5(2 {x}^{2} - 5) + 7[/tex]

Which then becomes

[tex]10 {x}^{2} - 25 + 7[/tex]

And finally the answer is

[tex]10 {x}^{2} - 18[/tex]

Answer:

4 and 34/63

Step-by-step explanation:

we know that he has to walk 8 and 2 thirds of an kilometer to school. so far he has ran 1 10/11 of a kilo.

To solve this you would have to divide 8 2/3 by 1 10/11.

you would have to make them into improper fractions so 26/3 divided by 21/11

your answer will be 4 34/63

Alan covers he distance by walking is   6+25/33 km.

distance is a scaler quantity which means it only have magnitude and no direction if any person or any thing moves from place A to B then it will show the distance between A and B

Given that Alan's school a distance is 8+2/3 km which is 26/3 km,

and he ran one and ten elevenths kilometers

means 1+10/11 = 21/11 km

and walks rest

let distance covered by walking be x

total distance for Alan school = distance covered by running + distance covered by walking

26/3 = 21/11 +x

x = 26/3 - 21/11

x = 223/33 = 6+25/33

Hence rest walking distance for Alan is 6+25/33

Learn more about Distance

https://brainly.com/question/15317318

#SPJ3

Answer:

This is an experiment because a treatment was applied to a group.

Step-by-step explanation:

There are two groups, The first group used the computer program while the second group did not therefore this is an experiment. An experiment involves changing an independent variable to see how it affects a dependent variable. The dependent variable in this case  determining the effect of a new computer program on learning while the independent variables was testing with the computer program and not testing with the program.

Answer:

a = sqrt(7)

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2 + b^2 = c^2

where a and b are the legs and c is the hypotenuse

a^2 +3^2 = 4^2

a^2 +9 = 16

a^2 = 16-9

a^2 = 7

Taking the square root

a = sqrt(7)

Answer:

y = 5x + 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = 5, thus

y = 5x + c ← is the partial equation

To find c substitute (2, 13) into the partial equation

13 = 10 + c ⇒ c = 13 - 10 = 3

y = 5x + 3 ← equation of line

Answer: triangleDEF - 3 units down

triangleGHI - 5 units left

triangleJKL - 4 units left and 5 units down

Step-by-step explanation:

Answer:

7.2

Step-by-step explanation:

Apply Law of Cosines, given that b is 13.5, c is 8.9, and Angle a is 29.

[tex] {a}^{2} = {b}^{2} + {c}^{2} - 2bc \cos(a) [/tex]

[tex] {a}^{2} = {13.5}^{2} + {8.9}^{2} - 2(13.5)(8.9) \times \cos(29) [/tex]

[tex] {a}^{2} = 182.25 + 79.21 - 240.3 \times 0.8746[/tex]

[tex] {a}^{2} = 182.25 + 79.21 - 210.1711[/tex]

[tex]a = 7.2[/tex]

Answer:

[tex]a\approx7.2[/tex]

Step-by-step explanation:

The given problem presents one with the following information:

To solve this problem, one can use the law of cosines. The law of cosines is a property that can apply to any triangle. This property comes in the form of a formula, which is as follows:

[tex]a^2=\sqrt{b^2+c^2-2bc(cos(A))}[/tex]

Where (a), (b), and (c) are sides of the triangle, and (<A) is the angle opposite the side (a).

Substitute the given information into the formula and solve for the unknown side (a):

[tex]a=\sqrt{b^2+c^2-2bc(cos(A))}[/tex]

[tex]a=\sqrt{(13.5)^2+(8.9)^2-2(13.5)(8.9)(cos(29))}[/tex]

Simplify,

[tex]a=\sqrt{(13.5)^2+(8.9)^2-2(13.5)(8.9)(cos(29))}[/tex]

[tex]a=\sqrt{182.25+79.21-240.3(cos(29))}[/tex]

[tex]a=\sqrt{261.46-240.3(cos(29))}[/tex]

[tex]a=\sqrt{261.46-210.1711}[/tex]

[tex]a=\sqrt{51.2889}[/tex]

[tex]a\approx7.2[/tex]

Answer:

-2q+5

Step-by-step explanation:

-6q +7 -2 +4q

Combine like terms

-6q+4q+7-2

-2q+5

Answer:

= solution,

= -6q + 7 - 2 +4q

= -6q + 4q +7 -2

= - 2q + 5

✌✌✌✌

Sum means add.

Start at -6 and add 9

-6 + 9 = 3

Answer: 3

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\text{What is the sum of -6 \& 9?}[/tex]

[tex]\huge\textsf{The word \underline{sum} means to \bf add/addition }[/tex]

[tex]\huge\text{The EQUATION: -6 + 9 = [blank]}[/tex]

[tex]\huge\bullet\huge\textsf{To find out your result you have to start}\\\huge\textsf{at -6 \& go UP 9 spaces to the right}\\\huge\textsf{since you are ADDING \& NOT}\\\huge\textsf{SUBTRACTING.}\\\\\huge\bullet\huge\textsf{If you are subtracting you would do the}\\\huge\textsf{opposite \& go down to the left}[/tex]

[tex]\huge\boxed{\star}\huge\text{ Without further ado, we have reached}\\\huge\text{our result to your question is \boxed{\bf 3}}[/tex]

[tex]\boxed{\boxed{\huge\text{Answer: \bf 3}}}\huge\checkmark[/tex]

[tex]\huge\textsf{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\huge\boxed{\frak{Amphitrite1040:)}}[/tex]

Answer:

[tex]\huge\boxed{\frac{7}{8}}[/tex]

Step-by-step explanation:

[tex](\frac{49 }{64})^{1/2}[/tex]

=> [tex](\frac{7^2}{8^2} )^{1/2}[/tex]

=> [tex]\frac{7^{2*1/2}}{8^{2*1/2}}[/tex]

=> [tex]\frac{7}{8}[/tex]

Answer:

Below

Step-by-step explanation:

You should now that:

● (m/n)^(1/2) = √(m/n)

So:

● (49/64)^(1/2) = √(m/n)

You shoukd now also that:

● √(m/n) = √m / √n

So:

● √(49/64) = √49/√64

Notice that 64 = 8^2 and 49 = 7^2

● √49 / √64 = √(7^2)/√(8^2) = 7/8

So the answer is 7/8

Answer:

7 8 9

Step-by-step explanation:

Answer:

Choice A

Step-by-step explanation:

Answer:

The height of the triangular base of the pyramid is s√3/2 units

Step-by-step explanation:

Here in this question, what we are concerned with is to calculate the height of the equilateral-triangle base of the oblique pyramid.

From the question, we are told that the equilateral triangle has a length of a units.

Let’s have a recall on some of the properties of equilateral triangles;

a. All sides are of equal lengths. Meaning side s is the length of all the sides in this case.

b. All angles are equal, meaning they are 60 degree each.

c. Dropping a perpendicular line from the top vertex to the base length will split the equilateral triangle into two right-angled triangles of angles 60 and 30 each.

So to find the height of this triangular base, we can use any of the two right angled triangles.

Kindly recall that the properties of each would be angles 30, 60 and side length s

so to calculate the height h, we can use trigonometric identities

Mathematically, the trigonometric identity we can use is the sine( side length s represents the hypotenuse, while the height h represents the opposite facing the angle 60 degrees)

Thus; we have

Sine of an angle = length of the opposite/length of hypotenuse

sin 60 = h/s

h = s sin 60

In surd form,

sin 60 = √3/2

Thus;

h = s * √3/2 = s√3/2 units

Answer:

BBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBB

Step-by-step explanation:

Answer:

Step-by-step explanation:

Here is an example:

2/3 +4/5

Cross multiply

3 times 4 = 12

5 times 2 = 10

These 2 products will be added in the numerators

Now multiply denominators

3 times 5 = 15

Finally form them into a fraction

12+10/15

22/15

This method is not the original way to do it but its just how I do it quickly

Here is the original method:

2/3+4/5

Get common denominators

Multiply the first fraction (both numerator and denominator) by 5

2(5)/3(5) = 10/15

Now multiply the second fraction (both numerator and denominator) by 3

4(3)/5(3) = 12/15

Add those 2 fractions together and you should get 10/15+12/15 = 22/15

Step-by-step explanation:

⅛

In this fraction, 1 is called numerator and 8 is called denominator.

Let's say you want to add ⅛ and ⅞. Here, denominators are same, so you just add the numerator and denominator remains the same. So, it becomes (1+7)/8 = 8/8.

If the denominator is different you first make them same, by cross multipling.

Let's say you want to add ¼ and ⅔. Then you multiply the numerator and denominator of ¼ by 3 (because it is the denominator of the second fraction). So, ¼ becomes (1×3)/(4×3) = 3/12. The same goes for ⅔, you multiply the numerator and denominator by 4 (it is the denominator of the other fraction). So, ⅔ becomes (2×4)/(3×4) = 8/12. So, now you add 3/12 and 8/12 the same way you added ⅛ and ⅞ above. Add the numerator, denominator remains the same. So, answer is (3+8)/12 = 11/12.

Hope it helps!!

Answer:

15%

Step-by-step explanation:

profit=sp -cp

cp=sp-profit

=17250-2250

=15000

profit%= profit amount/cp *100%

=2250/15000×100

= 15

Answer:

Step-by-step explanation:

Given,

SP ( Selling price ) = Rs 17250

Profit ( P ) = Rs 2250

CP ( Cost price ) = Rs 17250 - Rs 2250 = Rs 15000

Now, let's find the profit / gain percentage :

Profit % = [tex] \sf{ \frac{profit}{cost \: price} \times 100\%}[/tex]

plug the values

⇒[tex] \sf{ \frac{2250}{15000} \times 100\%}[/tex]

Calculate

⇒[tex] \sf{15\%}[/tex]

-----------------------------------------------------------------

▪[tex] \underline{ \underline{ \sf{ \blue{What \: is \: the \: formula \: to \: find \: profit \: percent \: and \: loss \: percent?}}}}[/tex]

We know that , profit and loss are calculated on cost price ( CP ). So, profit percent and loss percent can be calculated by using the following formula :

[tex] \boxed{ \sf{Loss\% \: = \frac{cp - sp}{cp} \times 100\%}}[/tex]

[tex] \boxed{ \sf{ \bold{Profit\% \: = \: \frac{sp \: - \: cp}{cp} \times 100}}}[/tex]

Hope I helped!

Best regards!!

Answer:

705 meters

Step-by-step explanation:

[tex]cos~60=\frac{650^2+750^2-d^2}{2 \times 650 \times 750} \\2 \times 650 \times 750 \times \frac{1}{2}=50^2(13^2+15^2)-d^2 \\487500=2500(169+225)-d^2\\487500=2500(394)-d^2\\487500=985000-d^2\\487500-985000=-d^2\\d^2=497500\\d=\sqrt{497500}\\or~d\approx705.337 \approx 705~meters[/tex]

Answer:

7 0 5  M E T E R S !!!!!

Step-by-step explanation:

Answer:

Rs 2160

Step-by-step explanation:

1 dozen = 12 copies

2 dozen = 24 copies ( 2*12)

72÷12 = 6 dozen

72 copies = 6 dozen

1 dozen = Rs 720÷2

1 dozen Rs 360

6 dozen = 360*6

6 dozen = 72 copies = Rs 2160