Answer:
v = 6.20 10⁻¹² m / s, v = 1.96 10⁻² cm/year
Explanation:
This is a kinematics problem, specifically of uniform motion
v = d / t
let's reduce the magnitudes to the SI system
d = 8.8 km (1000 m / 1 km) = 8.8 10³ m
t = 45 10⁶ years (365 day / 1 year) (24 h / 1 day) (3600 s / 1h)
t = 1,419 10¹⁵ s
let's calculate the speed
v = 8.8 10³ / 1.1419 10¹⁵
v = 6.20 10⁻¹² m / s
This is the correct unit of the SI system, but it is more common to give the value in centimeters per year, so let's reduce the value
v = 8.8 105 / 45 106
v = 1.96 10⁻² cm/year
The pressure gauge on a tank registers the gauge pressure, which is the difference between the interior pressure and exterior pressure. When the tank is full of oxygen (O2), it contains 11.0 kg of the gas at a gauge pressure of 35.0 atm. Determine the mass of oxygen that has been withdrawn from the tank when the pressure reading is 19.4 atm. Assume the temperature of the tank remains constant.
Answer:
mass of oxygen that has been withdrawn from the tank = 4.77 kg
Explanation:
We are given;
Initial mass of oxygen gas;m1 = 11 kg
Initial gauge pressure;p'1 = 35 atm
Final gauge pressue;p'2 = 19.4 atm
Now, for thia question we cannot use gauge pressure but absolute pressures.
Thus, formula for absolute pressure = gauge pressure + external atmospheric pressure.
External atmospheric pressure = 1 atm.
Thus;
P1 = 35 + 1 = 36 atm
P2 = 19.4 + 1 = 20.4 atm
Now, formula for ideal gas equation is;
PV = nRT = (m/M)RT
Where;
m is mass of gas
M is molar mass of gas
R is gas constant
T is temperature
Thus, for state 1,we have;
P1 × V1 = (m1/M)RT1 - - - (eq 1)
For state 2,we have;
P2 × V2 = (m2/M)RT2 - - - - - (eq 2)
Divide equation 1 by equation 2 to give;
(P1 × V1)/(P2 × V2) = (m1 × T1)/(m2 × T2)
The gas remains confined in the tank, thus, V1 = V2
Also, the temperature is constant, thus T1 = T2.
Thus, V1 & V2 and also T1 & T2 will cancel out to give;
P1/P2 = m1/m2
Since we are looking for the mass of oxygen( Δm) that has been with withdrawn from the tank, we have to rewrite the equation to accommodate Δm. Now, Δm is simply m1 - m2
Thus,
From P1/P2 = m1/m2, we have;
P1/P2 = m1/(-(m1 - m2) + m1)
This gives;
P1/P2 = m1/(m1 - Δm)
Cross multiply to get;
(m1 - Δm)(P1/P2) = m1
Cross multiply to get;
m1 - Δm = (P2/P1)m1
Δm = m1 - (P2/P1)m1
Δm = m1(1 - (P2/P1))
Plugging in the relevant values to get;
Δm = 11(1 - (20.4/36))
Δm = 4.77 kg
A stone is thrown directly upward with an initial speed of 4 m/s from a height of 20 m. After what time interval does the stone strike the ground
Given :
( Let , take upward direction +ve and downward direction -ve )
Initial speed of stone , u = 4 m/s .
Height , h = 20 m .
To Find : Time taken to reach ground .
Solution :
We know , by equation of motion .
Displacement is given by :
[tex]h=h_o+ut+\dfrac{gt^2}{2}\\\\0=20+4t-2t^2\\\\t^2-2t-10=0[/tex] ( Here , g = acceleration due to gravity = [tex]-9.8\ m/s^2[/tex] .)
Solving above equation , we get :
t = 4.32 s .
Hence , this is the required solution .
We can model the human back as a pivoted rod?
Answer:
So the answer is yes, we can the back be shaped like a spinning rod
spinal column that is approximated by a long and narrow rod,
Explanation:
The bone system of the body is very well modeled in physics, the back has a spinal column that is approximated by a long and narrow rod, this rod is fixed in the lower part to the coccyx and has a weight in the upper part (head), this rod has longitudinal vertical movement and twisting movement around the lower part of the bar.
So the answer is yes, we can the back be shaped like a spinning rod
What is (Fnet3)x, the x-component of the net force exerted by these two charges on a third charge q3
This question is incomplete, the complete question is;
Coulomb's law for the magnitude of the force F between two particles with charges Q and Q' separated by a distance d is
|FI = |QQ'I / d²
where K = 1/4π∈0, and
∈0 = 8.854 × 10⁻¹² C²/(N.m²) is the permittivity of free space.
Consider two point charges located on the x-axis:
one charge, q₁ = -18.5 nC, is located at
x₁ = -1.715m; the charge q₂ = 30.5 nC, is at the origin ( x₂=0 )
What is (Fnet3)x, the x-component of the net force exerted by these two charges on a third charge q₃ = 51.0 nC placed between q₁ and q₂ at x₃ = -1.085 m ?
Answer: (Fnet3)x = -3.3287 × 10⁻⁵ N
Explanation:
Given that;
Q₁ = -18.5 nC Q₃ = 51 nC Q₂ = 30.5 nC
x₁ = - 1.715m x₃ = - 1.085m x₂ = 0
Now
x - component of Net force on charge Q₃ is
(Fnet3)x = -K|Q₁I|Q₃I / r₁3² - -K|Q₂I|Q₃I / r₂3²
(Fnet3)x = -(9×10⁹)(51×10⁻⁹) [ 18.5 / ((-1.085 + 1.715)²) + (30.5 / (-1.085)² ] × 10⁻⁹
(Fnet3)x = -3.3287 × 10⁻⁵ N
How could you record the number 4000 and report 2 significant figures?
Explanation:
Write in scientific notation.
4000 = 4.0×10³
Jennifer has taught her pet rat to run a maze. She thinks that the rat will
go faster if she puts its favorite treat at the end. She has the rat run the
maze ten times with the favorite treat and ten times with a regular food
pellet. She uses a stopwatch to measure how long it takes for the rat to get
to the reward.
O Replication
O Repetition
similarity of gravity and electromagnetic force
Answer:
Gravity is an attractive force as well as electromagnetic, but electromagnetic attracts and repels.
Explanation:
a ball of mass 100g moving at a velocity of 100m/s collides with another ball of mass 400g moving at 50m/s in same direction, if they stick together calculate the velocity and loss of energy
Answer:
Velocity of the two balls after collision: [tex]60\; \rm m \cdot s^{-1}[/tex].
[tex]100\; \rm J[/tex] of kinetic energy would be lost.
Explanation:
VelocityBecause the question asked about energy, convert all units to standard units to keep the calculation simple:
Mass of the first ball: [tex]100\; \rm g = 0.1\; \rm kg[/tex].Mass of the second ball: [tex]400\; \rm g = 0.4 \; \rm kg[/tex].The two balls stick to each other after the collision. In other words, this collision is a perfectly inelastic collision. Kinetic energy will not be conserved. The velocity of the two balls after the collision can only be found using the conservation of momentum.
Assume that the system of the two balls is isolated. Thus, the sum of the momentum of the two balls will stay the same before and after the collision.
The momentum of an object of mass [tex]m[/tex] and velocity [tex]v[/tex] is: [tex]p = m \cdot v[/tex].
Momentum of the two balls before collision:
First ball: [tex]p = m \cdot v = 0.1\; \rm kg \times 100\; \rm m \cdot s^{-1} = 10\; \rm kg \cdot m \cdot s^{-1}[/tex].Second ball: [tex]p = m \cdot v = 0.4\; \rm kg \times 50\; \rm m \cdot s^{-1} = 20\; \rm kg \cdot m \cdot s^{-1}[/tex].Sum: [tex]10\; \rm kg \cdot m \cdot s^{-1} + 20 \; \rm kg \cdot m \cdot s^{-1} = 30 \; \rm kg \cdot m \cdot s^{-1}[/tex] given that the two balls are moving in the same direction.Based on the assumptions, the sum of the momentum of the two balls after collision should also be [tex]30\; \rm kg \cdot m \cdot s^{-1}[/tex]. The mass of the two balls, combined, is [tex]0.1\; \rm kg + 0.4\; \rm kg = 0.5\; \rm kg[/tex]. Let the velocity of the two balls after the collision [tex]v\; \rm m \cdot s^{-1}[/tex]. (There's only one velocity because the collision had sticked the two balls to each other.)
Momentum after the collision from [tex]p = m \cdot v[/tex]: [tex](0.5\, v)\; \rm kg \cdot m \cdot s^{-1[/tex].Momentum after the collision from the conservation of momentum: [tex]30\; \rm kg \cdot m \cdot s^{-1}[/tex].These two values are supposed to describe the same quantity: the sum of the momentum of the two balls after the collision. They should be equal to each other. That gives the equation about [tex]v[/tex]:
[tex]0.5\, v = 30[/tex].
[tex]v = 60[/tex].
In other words, the velocity of the two balls right after the collision should be [tex]60\; \rm m \cdot s^{-1}[/tex].
Kinetic EnergyThe kinetic energy of an object of mass [tex]m[/tex] and velocity [tex]v[/tex] is [tex]\displaystyle \frac{1}{2}\, m \cdot v^{2}[/tex].
Kinetic energy before the collision:
First ball: [tex]\displaystyle \frac{1}{2} \, m \cdot v^2 = \frac{1}{2}\times 0.1\; \rm kg \times \left(100\; \rm m \cdot s^{-1}\right)^{2} = 500\; \rm J[/tex].Second ball: [tex]\displaystyle \frac{1}{2} \, m \cdot v^2 = \frac{1}{2}\times 0.4\; \rm kg \times \left(50\; \rm m \cdot s^{-1}\right)^{2} = 500\; \rm J[/tex].Sum: [tex]500\; \rm J + 500\; \rm J = 1000\; \rm J[/tex].The two balls stick to each other after the collision. Therefore, consider them as a single object when calculating the sum of their kinetic energies.
Mass of the two balls, combined: [tex]0.5\; \rm kg[/tex].Velocity of the two balls right after the collision: [tex]60\; \rm m\cdot s^{-1}[/tex].Sum of the kinetic energies of the two balls right after the collision:
[tex]\displaystyle \frac{1}{2} \, m \cdot v^{2} = \frac{1}{2}\times 0.5\; \rm kg \times \left(60\; \rm m \cdot s^{-1}\right)^2 = 900\; \rm J[/tex].
Therefore, [tex]1000\; \rm J - 900\; \rm J = 100\; \rm J[/tex] of kinetic energy would be lost during this collision.
If the maximum acceleration that is tolerable for passengers in a subway train is 1.39 m/s2 and subway stations are located 780 m apart, what is the maximum speed a subway train can attain between stations
Answer:
The maximum speed a subway train can attain between stations is 32.93 m/s.
Explanation:
Given;
maximum tolerable acceleration = 1.39 m/s²
distance between subway train, d = 780 m
The distance available to accelerate between stations = ¹/₂ x 780 m = 390 m
Apply the following kinematic equation to determine the maximum speed;
v² = u² + 2ad
v² = 0 + 2ad
v² = 2(1.39)(390)
v² = 1084.2
v = √1084.2
v = 32.93 m/s
Therefore, the maximum speed a subway train can attain between stations is 32.93 m/s.
You throw a 20-N rock vertically into the air from ground level. You observe that when it is a height 14.8m above the ground, it is traveling at a speed of 25.0 m/s upward.
A) Use the work-energy theorem to find its speed just as it left the ground. What is it?
B) Use the work-energy theorem to find its maximum height. What is it?
Answer:
30.25 m/s
46.68 m
Explanation:
Work Energy theorem states that
W = ½mv2² - ½mv1²
W = ½m(v2² - v1²)
Net work done by the force = -mgd
Net work done = -m * 9.8 * 14.8
Net work done = -145m
Using the work energy theorem
-145m = ½m(v2² - v1²)
-145m = ½ * m(25² - v1²)
-290m = 625m - v1²m
v1² = 625 + 290
v1² = 915
v1 = √915 = 30.25 m/s
B
-mgd = ½m(v2² - v1²), where v2 = 0, so
-mgd = ½mv1²
Making d the subject of the formula, we have
d = -½mv1²/mg
d = v1²/2g
d = 915/ 2 * 9.8
d = 915 / 19.6
d = 46.68 m
Two forces 5N and 10N are acting at "O" and "P" respectively on a uniform rod of length 100 cm suspended at the position of center of gravity 50cm mark as shown in figure .
Answer:
Option C. 75 cm
Explanation:
To obtain the position of P, let us calculate the value of y as shown in the attached photo.
The value of y can be obtained as follow:
Anticlockwise moment = clockwise moment
Anticlockwise moment = 5 × 50
Anticlockwise moment = 250
Clockwise moment = y × 10
Anticlockwise moment = clockwise moment
250 = y × 10
Divide both side by 10
y = 250/10
y = 25 cm
Finally, we shall obtain the value of P as follow:
Since P lies after the pivot (i.e 50 cm), therefore,
P = 50 + y
y = 25
P = 50 + 25
P = 75 cm
Therefore, the position of P on the metre rod is 75 cm
12. A sprinter has an acceleration of 5m/s” during the first 2 seconds of the race. What
velocity does she reach after this time?
Answer:
v=10m/s
Explanation:
[tex]a=\frac{vf-vi}{t}\\ 5m/s^{2}=\frac{vf-0}{2}\\ vf=5*2\\vf=10 m/s[/tex]
What does CWT stand for?
hundredweight cwt is a standard unit of weight or mass used in certain commodities trading contracts.
Answer:
hundredweight
Explanation:
A 12-V DC automobile head lamp is to be used on a fishing boat with a 24-V power system. The head lamp is rated at 50 W. A resistor is to be connected in series with the lamp to permit it to operate on 24 V. What should be the resistance and power rating of the resistor?
Answer:
The resistance is [tex]R = 2.88 \ \Omega[/tex]
Explanation:
From the question we are told that
The voltage rating of the headlamp is [tex]V_1 = 12 \ V[/tex]
The voltage of the power system is [tex]p = 24 \ V[/tex]
The power rating of the headlamp is [tex]P = 50 W[/tex]
Generally the power which the resistor dissipates is mathematically represented as
[tex]P = V_L * I[/tex]
=> [tex]50 = 12 * I[/tex]
=> [tex]I = 4.1667 \ A[/tex]
Generally the resistance is
[tex]R = \frac{V_1 }{I}[/tex]
[tex]R = \frac{12 }{4.1667}[/tex]
[tex]R = 2.88 \ \Omega[/tex]
5. What kind of mirror would you use if you needed to start a fire using a mirror? Why? At what position would you place the kindling from the mirror?
Answer:
Concave mirror
The kindling should be positioned at the focus point of the mirror
Explanation:
A concave mirror should be used, because it forms a real image, and focuses the image of an incident ray coming from a distant source on a single point. These mirrors are called "converging mirrors" because they tend to collect light that falls on them, refocusing parallel incoming rays toward a focus, and are sometimes used to collect light from a large area and focus it into a small spot, as in concentrated solar power.
In a liquid with a density of 1400 kg/m3, longitudinal waves with a frequency of 390 Hz are found to have a wavelength of 7.60 m. Calculate the bulk modulus of the liquid. Express your answer in pascals.
Answer:
The bulk modulus of the liquid is 1.229 x 10¹⁰ Pa
Explanation:
Given;
density of liquid, ρ = 1400 kg/m³
frequency of the wave, f = 390 Hz
wavelength, λ = 7.60 m
The speed of the sound is given by;
v = fλ
v = 390 x 7.6
v = 2964 m/s
The bulk modulus of the liquid is given by;
[tex]v = \sqrt{\frac{B}{\rho}}\\\\v^2 = \frac{B}{\rho}\\\\B = \rho v^2[/tex]
where;
B is bulk modulus
B = (1400)(2964)²
B = 1.229 x 10¹⁰ N/m²
B = 1.229 x 10¹⁰ Pa
Therefore, the bulk modulus of the liquid is 1.229 x 10¹⁰ Pa
Timmy drove 2/5 of a journey at an average speed of 20 mph.
He drove the remaining 60 miles at another speed. If the
average speed for the whole journey was 25 mph, what's the
amount of time for the whole journey?
Answer:
4hr
Explanation:
The total time Timmy spent in the whole journey is 4 hours.
The given parameters;
average speed of Timmy for [tex]\frac{2}{5}[/tex] of the journey = 20 mphthe remaining fraction of the journey = 60 milesaverage speed of the entire journey = 25 mphThe total distance of the journey is calculated as follows;
[tex]( 1 - \frac{2}{5} ) \times total = 60 \ miles\\\\\frac{3}{5} \times total = 60\\\\total = \frac{60 \times 5}{3} \\\\total = 100 \ miles[/tex]
The amount of time for the whole journey is calculated as follows;
[tex]average \ speed = \frac{total \ distance}{total \ time} \\\\total \ time = \frac{100 \ miles }{25 \ mph} \\\\total \ time = 4 \ hours[/tex]
Thus, the total time Timmy spent in the whole journey is 4 hours.
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A sinusoidal transverse wave travels along a long, stretched string. The amplitude of this wave is 0.0957 m, its frequency is 3.75 Hz, and its wavelength is 1.97 m. What is the shortest transverse distance between a maximum and a minimum of the wave?
Answer:
Shortest distance = 0.1914 m
Explanation:
Given that,
Amplitude of the wave is 0.0957 m
Frequency of the wave is 3.75 Hz
Wavelength of the wave is 1.97 m
We need to find the shortest transverse distance between a maximum and a minimum of the wave.
The distance between maximum point in positive axis and the baseline is equal to amplitude.
Shortest distance = 2 A
D = 2 × 0.0957
D = 0.1914 m
So, the shortest transverse distance between a maximum and a minimum of the wave is 0.1914 m.
You're driving on a straight road (in the x direction) at a constant speed of 28 m/s. In 10 seconds, you speed up to 37 m/s to pass a truck. (a) Assuming your car speeds up at a constant rate (constant force by the road on the tires), what is your average x component of velocity vavg,x during this maneuver
Answer:
The average [tex]x[/tex] component velocity [tex]V_{avg,x}[/tex] is 32.5 m/s
Explanation:
v = u +at bhjklj kj h
x = (u + v / 2 )t
Average velocity is given by
[tex]V_{avg} = \frac{Displacement}{Time} \\V_{avg} = \frac{x_{2} - x_{1} }{t_{2} - t_{1} }[/tex]
From the question,
Initial speed, u = 28 m/s
Final speed, v = 37 m/s
Time, t = 10 secs
From the formula
[tex]x = (\frac{u + v}{2})t\\[/tex]
where [tex]x[/tex] is the displacement
Put the given values into the equation to find the displacement [tex]x[/tex]
[tex]x = (\frac{28 + 37}{2}) 10\\ x = (\frac{65}{2})10\\ x = (\frac{32.5}{10})\\ x = 325 m[/tex]
Now, for the average [tex]x[/tex] component velocity [tex]V_{avg,x}[/tex]
[tex]V_{avg} = \frac{Displacement}{Time} \\V_{avg} = \frac{x_{2} - x_{1} }{t_{2} - t_{1} }[/tex]
[tex]V_{avg,x} = \frac{325 - 0}{10 - 0}\\V_{avg,x} = \frac{325}{10}\\ V_{avg,x} = 32.5 m/s[/tex]
Hence, the average [tex]x[/tex] component velocity [tex]V_{avg,x}[/tex] is 32.5 m/s
The average x component of velocity during the maneuver of the truck is 32.5 m/s.
Velocity:
The term velocity of any object is defined as the ratio of displacement covered by any object to the time taken by the object to displace.
Given data:
The magnitude of initial speed is, u = 28 m/s.
The magnitude of final speed is, v = 37 m/s.
The time interval is, t = 10 s.
The displacement covered by the truck is calculated as,
[tex]d = \dfrac{v+u}{2} \times t\\\\ d = \dfrac{37+28}{2} \times 10\\\\ d = 325 \;\rm m[/tex]
Now, the expression for the x-component of the average velocity is given as,
[tex]v_{x}=\dfrac{d}{t}[/tex]
Solving as,
[tex]v_{x}=\dfrac{325}{10}\\\\ v_{x}=32.5 \;\rm m/s[/tex]
Thus, we can conclude that the average x component of velocity during the maneuver of truck is 32.5 m/s.
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Describe a sound wave. Discuss what determines pitch and volume.
Answer:
The amplitude of a sound wave is a reflection of how much energy is carried, which contributes to the intensity of the sound. Intensity is measured in decibels and is perceived as sound volume. Thus, the volume is proportional to the amplitude of the sound wave. The frequency of a sound wave is perceived as pitch.
Explanation:
The amount of energy carried by a sound wave is reflected in its amplitude, which affects the sound's intensity. The perception of intensity as sound loudness is expressed in decibels. Hence, the relationship between the volume and the sound wave's amplitude is clear. Pitch is the perceived frequency of a sound wave.
What is wave ?Wave is is a disturbance in a medium that carries energy as well as momentum . wave is characterized by amplitude, wavelength and phase. Amplitude is the greatest distance that the particles are vibrating. especially a sound or radio wave, moves up and down. Amplitude is a measure of loudness of a sound wave. More amplitude means more loud is the sound wave.
Wavelength is the distance between two points on the wave which are in same phase.
Phase is the position of a wave at a point at time t on a waveform.
There are two types of the wave longitudinal wave and transverse wave.
Longitudinal wave : in which, vibration of the medium (particle) is parallel to propagation of the wave. Sound wave is a longitudinal wave.
Transverse wave : in which, vibration of the medium (particle) is perpendicular to propagation of the wave. Light wave is a Transverse wave.
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Which of the following statements are true according to the uncertainty principle? A. It is impossible to simultaneously determine both the energy and the momentum of a particle with arbitrary accuracy. B. It is impossible to determine a particle's energy with arbitrary accuracy in a finite amount of time. C. It is impossible to simultaneously determine both the position and the momentum of a particle with arbitrary accuracy. D. It is impossible to measure the position of a particle with arbitrary accuracy in a finite amount of time. E. It is impossible to simultaneously measure both the energy and position of a particle with arbitrary accuracy.
Answer and Explanation: Heisenberg's Uncertainty Principle states that if the position of the particle is known, its momentum is unknown and vice-versa.
So, it is impossible to determine both the position and the momentum of a particle with arbitrary accuracy.
The statement, " It is impossible to simultaneously determine both the position and the momentum of a particle with arbitrary accuracy" is correct. Hence, option (c) is correct.
The given problem is based on the Heisenberg's uncertainty principle. As per the Heisenberg's uncertainty principle, "It is not possible to obtain both the momentum and position of particles at same time, if one is obtained with full certainty then other comes uncertain". And the expression for the Heisenberg's principle is,
[tex]\Delta x \times \Delta p \geq \dfrac{h}{4\pi}[/tex]
Here,
[tex]\Delta x[/tex] is the uncertainty in position.
[tex]\Delta p[/tex] is the uncertainty in momentum.
h is the Planck's constant.
So, as per the above definition the statement, " It is impossible to simultaneously determine both the position and the momentum of a particle with arbitrary accuracy" is justified.
Thus, we can conclude that the statement, " It is impossible to simultaneously determine both the position and the momentum of a particle with arbitrary accuracy" is correct. Hence, option (c) is correct.
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what was the average speed in km/h of a car that travels 490.0 km in 4.2 h?
Answer:
116.67 km/h
Explanation:
avarge speed = total distance / total time
Answer: 490 / 4.2 = 116.67 km/h
In the drawing, what is the vector sum of forces A→+B→+C→ if each grid square is 7.00 N on a side? If the resultant is eastward, enter a positive value and if the resultant is westward, enter a negative value.
Answer:
resultant force = 14 N ( East direction)
Explanation:
A = √( (4*7)² + (4*7)² )
A = 39.6 N
B = 4 * 7
B = 28 N
C = 2 * 7
C = 14 N
∑ y forces = Ay - B = (4*7) - 28 = 0
∑ x forces = Ax - C = (4*7) - 14 = 14 N
so the resultant force = 14 N ( East direction)
Please give an example of a scenario with distance and displacement.
Answer:
distance means the length of any thing that have one starting point mad ending point
displacement means the short distance that move by an object due to help of any force
Answer:
there is examples and defination for distance and displacement
for an ideal gas, a plot of In P versus 1 / T (in Kelvin) yields a straight line with a slope equal to
You fly east in an airplane for 100 km. You then turn left 60 degrees and fly 200 km. In what direction are you from the starting point
Answer:
North east
Explanation:
r_1 = 100 i
r_2 = 200 (cos60i + sin60j) = 100i + 173.2j
By vector addition
r = r_1 + r_2 = 200i + 173.2j
Distance (Or magnitude) = sqrt(200^2 + 173.2^2) = 264 km
Direction from the starting point is north of east.
Which of the following does a microscope use to produce an image?
a) reflection
b) refraction
c) total internal reflection
d) two of A, B, and C
e) all of A, B, and C
Answer:
All of a,b, and c hope this helps
How much would it cost to cover the entire land area of the U.S. in dollar bills?
How much would it take to cover the entire land area of the U.S. in dollar bills?
The contiguous United States can be approximated as a rectangle that measures 1000 x 3000 miles, while Alaska has about 1/5 of the area of the contiguous U.S. Ignore Hawaii for this calculation. Also note that the dollar bill measures roughly 6.5cm x 15.5cm.
How much would it cost to cover the entire land area of the United States?
*Round your answer to one significant figure*
Answer:
$900 trillion
Explanation:
If Alaska is 20% of the contiguous US, then the approximate area of interest is ...
1200 miles × 3000 miles = 3.6×10^6 square miles.
The size of a dollar bill is about ...
(6.5 cm)·(15.5 cm) = 100.75 cm^2
One mile is 160,934.4 cm, so 1 square mile is about ...
1 mi^2 = (160,934.4 cm)^2 ≈ 2.59·10^10 cm^2
The number of dollars of interest is then ...
(3.6 · 10^6 mi^2)(2.59 · 10^10 cm^2)/(100.75 cm^2) ≈ 9.3·10^14
≈ 930 × 10^12 . . . dollars
It would cost about 900 trillion dollars to cover the land area of the US in $1 bills.
What is the variable that is manipulated by the experimenter during an experiment called
three equal charges are fixed at the three corners of a rectangle what is the force on the top left charge from the bottom left
Answer:
hello your question is incomplete attached below is the missing parts and the detailed solution of the problem
answer : [tex]\frac{1}{4\pi e_{0} } * \frac{q^2}{h^2} i_{y}[/tex] ( D )
Explanation:
The force on the top left charge from the bottom left can be determined applying the equations/expression as represented in the detailed solution
option D was chosen because it accurately represents the force on the top left charge( positive y axis ) from the bottom left