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Answer:

x= -8 , y = 5

x= 25/4 , y = 1/4

Step-by-step explanation:

substitute first eqn into the second eqn:

(7 - 3y)^2 -y^2 = 39

49 - 42y + 9y^2 - y^2 = 39

8y^2 - 42y +10 =0

4y^2 - 21y + 5 = 0

(4y-1) (y-5) = 0

y= 1/4 , 5

when y=1/4

x = 7- 3/4

=25/4

when y= 5

x = 7- 15

= -8

The required solution of the given simultaneous equations are x = -8, 25/4 and y = 5, 1/4.

Simultaneous linear equations are two- or three-variable linear equations that can be solved together to arrive at a common solution.

Here,
x = 7 – 3y - - - - -(1)
x² - y² = 39 - - - - (2)

Put x from equation 1 in equation 2

(7 - 3y)² -y² = 39

49 - 42y + 9y² - y² = 39

8y² - 42y +10 =0

4y² - 21y + 5 = 0

(4y-1) (y-5) = 0

y= 1/4 , 5

Substitute this values in the equation 1,
x = -8 and 25/4

Learn more about simultaneous equations here:

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[tex]4 {x}^{2} - 25 {y}^{2} \\ (2 x) {}^{2} - {(5y)}^{2} \\ (2x + 5y)(2x - 5y)[/tex]

Answer:

[tex] = 1)(2x - 5y {)} \times (2x + 5y)[/tex]

Step-by-step explanation:

[tex]1) {4x}^{2} - 25 {y}^{2} [/tex]

[tex] = {2}^{2} {x}^{2} - 25 {y}^{2} [/tex]

[tex] = {2}^{2} {x}^{2} - {5}^{2} {y}^{2} [/tex]

[tex] = (2 {x)}^{2} - {5}^{2} {y}^{2} [/tex]

[tex] = ( {2x)}^{2} - (5 {y)}^{2} [/tex]

[tex] = (2x - 5y) \times (2x + 5y)[/tex]

[tex]2)4x^{2} - 35 {y}^{2} [/tex]

[tex] = {2}^{2} {x}^{2} - 5y \times 7 {y} [/tex]

[tex] =(2x {)}^{2} - (5y \times 7y)[/tex]

Answer:

The value representing one standard deviation  to the right of the mean is 55.

Step-by-step explanation:

The provided data set is:

S = {56, 54, 45, 52, and 48}

Compute the mean and standard deviation as follows:

[tex]\mu=\frac{1}{n}\sum X=\frac{1}{5}\times [56+54+45+52+48]=51\\\\\sigma=\sqrt{\frac{1}{n}\sum (X-\mu)^{2}}=\sqrt{\frac{1}{5}\cdot {(56-51)^{2}+...+(48-51)^{2}}}=\sqrt{\frac{1}{5}\times 80}=4[/tex]

Compute the value representing one standard deviation  to the right of the mean as follows:

[tex]X=\mu+1\cdot \sigma[/tex]

    [tex]=51+(1\times 4)\\=51+4\\=55[/tex]

Thus, the value representing one standard deviation  to the right of the mean is 55.

Answer:

x2 # of farmers

y2 # of hours

x1# unknown workers

x2# amount wanted

x1 y1 = x2 y2

x1 (8) = 12(20)

x1 = 12(20)/8

x1 = 30

30 Farmers needed to complete the same work in 8 hours.

Answer:

0.012

Step-by-step explanation:

Have a good day.

Answer:

.01

Step-by-step explanation:

Change the percent to decimal form

.04% = .0004

.0004 *30

.012

Round to the nearest hundredth

.01

Total Cost Of Shoe=2500

Totall discount Cost=2000

= 2500-2000

=500

Answer:

The answer is $12,000. 12 months × $1,000 per month = $12,000 minimum annual base rent; $435,000 gross sales × 2% = $8,700. The tenant paid $12,000 because the minimum base rent was more than the percentage of gross sales.

Step-by-step explanation:

Answer:

Step-by-step explanation:

AO = CO = radius

AO = CO  ⇒  AB = BC  and  m∠AOB = m∠BOC = ¹/₂m∠AOC

From BDOE:

m∠EOB + m∠OBC + m∠CDE + m∠DEO = 360°

(65° + 75°) + 90° + x + 90° = 360°

140° + 180° + x = 360°

x = 40°

Answer:

See step by step explantation

Step-by-step explanation:

Step 1. given

Step 2. Subtraction property of equality

Step 3. Simplification

Step 4. Subtraction property of equality

Step 5. Simplification

Step 6. Multiplication property of equality

Step 7. Simplification

Answer:

2,041 square centimeters

Step-by-step explanation:

surface area = (2 × π × r × h) + ((π × r) × (r+ (√(c² + r²))))+(π × r²)

where,

cylinder  base radius (r) = 10  cm

height of cylinder (h) = 16 cm

total height = 28 cm

cone height (c) = total height - height of cylinder = 28 - 16 = 12cm

π = 3.14

surface area = (2 × 3.14 × 10 × 16) + ((3.14 × 10) × (10+ (√(12² + 10²))))+(3.14 × 10²)

surface area = 1004.8 + (31.4 * 25.6) + 314

surface area = 2122.64 cm²

therefore the approximate surface area given is 2,041 square centimeters

Answer:

[tex]\boxed{y=-2x+25}[/tex]

Step-by-step explanation:

First, subtract 4x from both sides of the equation to put into slope-intercept form (y = mx + b). Then, divide by 2 to isolate the y.

4x + 2y = 50

2y = -4x + 50

y = -2x + 25

Answer:

[tex]y=-2x+25[/tex]

Step-by-step explanation:

To find the slope-intercept form of the equation, we just need to isolate the y-variable.

So we have the equation:

[tex]4x+2y=50[/tex]

First, subtract 4x from both sides. The 4xs on the left cancel:

[tex](4x+2y)-4x=50-4x\\2y=-4x+50[/tex]

Now, divide both sides by 2. The 2s on the left cancel:

[tex]\frac{2y}{2}=\frac{-4x+50}{2} \\y=\frac{-4x+50}{2}[/tex]

Simplify the right side. Expand the fraction:

[tex]y=\frac{-4x}{2}+\frac{50}{2} \\[/tex]

Cancel out the terms:

[tex]y=-2x+25[/tex]

Therefore, the slope-intercept form is:

[tex]y=-2x+25[/tex]

Answer:

C

Step-by-step explanation:

The 28 is independent of the number of hours. Both B and D are incorrect.

You don't subtract the 28 from the total. That's part of the total. A is wrong.

The answer is C

Answer: Density = 0.23 tons per cubic meter.

Step-by-step explanation:

Formula : [tex]Density=\dfrac{Mass(in \ ton)}{Volume (in\ m^3)}[/tex]

1 ton = 32000 ounces

⇒ 1 ounce = 0.00003125 ton

⇒  7 ounces = 7(0.00003125)=  0.00021875 ton

1 gallon = 0.00378541 cubic meter

2.5 gallons = 0.009475 cubic meter

Density= [tex]\dfrac{0.00021875}{0.009475}\text{ tons per cubic meter}[/tex]

[tex]\dfrac{21875}{94750}\text{ tons per cubic meter}\approx0.23\text{ tons per cubic meter}[/tex]

Hence, Density = 0.23 tons per cubic meter.

Answer:

0.02 tons per cubic meter

Step-by-step explanation:

Answer:

2^3×3^2=6^5​  equation is wrong because

2×2×2×3×3=72

6^5=6×6×6×6×6=36×36×6=7776

the two numbers are not equal

Mate, I think your question is wrong ! ;(

[tex]Corrected \\ Question...\\[/tex] (2^3)^2*(3^2)^3=6^5

Answer:

x^2 -root 15 +o = 0

Step-by-step explanation:

x^2 - (x+y) + xy

x^2 -root 15 +o = 0

Answer:

A.  [tex]Claire = 20250[/tex]

B.   [tex]Richard = 9350[/tex]

C.    Height = 3.2 feet

D. Charges = $760

Step-by-step explanation:

Given

[tex]Claire = 50x^2 + 250[/tex]

[tex]Richard = 40x^2 + 350[/tex]

Solving (a): Claire's 20ft charges

In this case, x = 20

Substitute 20 for x in [tex]Claire = 50x^2 + 250[/tex]

[tex]Claire = 50(20)^2 + 250[/tex]

[tex]Claire = 50(400) + 250[/tex]

[tex]Claire = 20000 + 250[/tex]

[tex]Claire = 20250[/tex]

Solving (b): Richard's 15ft charges

In this case, x = 15

Substitute 20 for x in [tex]Richard = 40x^2 + 350[/tex]

[tex]Richard = 40(15)^2 + 350[/tex]

[tex]Richard = 40(225) + 350[/tex]

[tex]Richard = 9000 + 350[/tex]

[tex]Richard = 9350[/tex]

Solving (c): Height which they both charge the same;

This implies that

[tex]50x^2 + 250 = 40x^2 + 350[/tex]

Solving for x [Collect Like Terms\

[tex]50x^2 - 40x^2 = 350 - 250[/tex]

[tex]10x^2 = 100[/tex]

Divide both sides by 10

[tex]x^2 = 10[/tex]

Take square roots of both sides

[tex]x = \sqrt{10}[/tex]

[tex]x = 3.2ft[/tex]  (Approximated)

Hence; Height = 3.2 feet

Solving (d): How much they charge when the charge the same amount.

Substitute 3.2 for x in any of the given equation

[tex]Claire = 50x^2 + 250[/tex]

[tex]Claire = 50(3.2)^2 + 250[/tex]

[tex]Claire = 50*10.24 + 250[/tex]

[tex]Claire = 512 + 250[/tex]

[tex]Claire = 762[/tex]

[tex]Richard = 40x^2 + 350[/tex]

[tex]Richard = 40(3.2)^2 + 350[/tex]

[tex]Richard = 40 * 10.24 + 350[/tex]

[tex]Richard = 409.6 + 350[/tex]

[tex]Richard = 759.6[/tex]

The reason for the difference is due to approximation

Hence, they both charge approximately 760

Expand the products on both sides:

[tex]a(y+c)=b(y-c) \implies ay+ac=by-bc[/tex]

Move all terms containing y to one side:

[tex]ay+ac=by-bc \implies ay-by=-ac-bc[/tex]

Factor out y :

[tex]ay-by=-ac-bc \implies y(a-b)=-ac-bc[/tex]

Solve for y :

[tex]y(a-b)=-ac-bc \implies y=\dfrac{-ac-bc}{a-b}=-\dfrac{c(a+b)}{a-b}=\dfrac{c(a+b)}{b-a}[/tex]

THIS IS YOUR ANSWER

HOPE IT HELPS YOU

Answer:

[tex](x+1)^2+(y+4)^2=9\\[/tex]

Step-by-step explanation:

The general format for the equation of a circle is the following:

[tex](x-h)^2+(y-k)^2=a^2\\[/tex]

Where [tex](h,k)[/tex] is the center of the circle and ([tex]a[/tex]) is the circle's radius. Please note, that the circle ([tex](x-h)^2+(y-k)^2=a^2\\[/tex]) has a center that is (h) units to the right of the origin, and (k) units above the origin.

The given circle has a center at [tex](-1,-4)[/tex], moreover, its radius is (3) units. Therefore, one must substitute these points into the equation of a circle and simplify to find its equation:

[tex](x-h)^2+(y-k)^2=a^2\\[/tex]

[tex](x-(-1))^2+(y-(-4))^2=(3)^2\\[/tex]

[tex](x+1)^2+(y+4)^2=9\\[/tex]

Answer:

Step-by-step explanation: Let's first determine the center of the circle

which is represented by the red dot and it has the coordinates (-1, -4).

The radius of the circle is a segment that joins the center of the

circle to a point on the circle and all radii of a circle are congruent.

The radius of the circle shown here is 3.

Now, the equation of a circle is (x - h)² + (y - k)² = r² where

(h, k) is the center of the circle and r is the radius.

Now we plug all our given information into the formula.

So we have [x - (-1)]² + [y - (-4)]² = (3)².

Notice that I changed the parentheses in the formula to brackets

so that we wouldn't be dealing with too many sets of parentheses.

Changing the brackets back to parentheses,

our equation is (x + 1)² + (y + 4)² = 9.

Answer:

G = 1, 9.

Step-by-step explanation:

There are two cases to this problem: G is either to the left or right of E. If G is to the left of E, then G = 5 - 4 = 1 and if G is to the right of E, then G = 5 + 4 = 9. Therefore, our answer is G = 1, 9.

Answer:

They either both have to be positive or negative.

Step-by-step explanation:

1 / 1 = 1

-1 / -1 = 1

This gets you positive, when both dividend and divisors are positive or negative.

-1 / 1 = -1

1 / -1 = -1

This gets you negative, when both dividend and divisors are different signs.

Answer:

Step-by-step explanation:

Both dividend and divisor have same sign -  

(i) both have positive sign  or

(ii) both have negative sign

Eg:

(i) [tex]\frac{10}{2}=5[/tex]

(ii)[tex]\frac{-10}{-2}=5[/tex]

Answer:

loss

Step-by-step explanation:

Selling an item for less than was paid gives a loss

Selling an item for more than was paid gives a profit

Answer:

The price of the game is 33.75

Step-by-step explanation:

45% of 75

.45 * 75

33.75

The price of the game is 33.75

Answer:

hypotenuse = 13

shortest side = 5

third side = 12

Step-by-step explanation:

Given sides a, b, and c, with c representing the hypotenuse of a right triangle, we can say that

a²+b² = c² using the Pythagorean Theorem.

We are given that the hypotenuse (c) = 8 cm more than the shortest side. Representing the shortest side as a, we can say that c= 8 + a. Then, the third side, which we can represent as b, is 1cm shorter than the hypotenuse, so c-1 = b

c= 8+a

c-1 = b

a²+b² = c²

One thing we can do is to solve for everything in terms of c and solve the third equation from there

c= 8+a

subtract 8 from both sides

c-8 = a

a²+b² = c²

(c-8)²+b² =c²

b = c-1

(c-8)² + (c-1)² = c²

expand

c²-16c + 64 + c² - 2c + 1 = c²

2c² - 18c + 65 = c²

subtract c² from both sides to make this an equation that we can more easily solve

c² - 18c + 65 = 0

To factor, we can find two numbers that add to (-18) and multiply to 65. Two numbers that work at 13 and 5, so we have

c²-13c-5c + 65 = 0

c(c-13) -5(c-13) = 0

(c-5)(c-13) = 0

Therefore, the hypotenuse, or c, is 5 or 13. Because a=c-8, if c=5, a would be negative 3. This is not possible, so c cannot be 5. Therefore, c=13, a=c-8=5, and b=c-1= 12

Answer:

U just add a .3      

Step-by-step explanation:

so it would be 384.3 i think

Answer:

HOME CARE & WELLNESS BASIC PET CARE HOW LONG CAN YOU SAFELY LEAVE A CAT ALONE?

BASIC PET CARE

How Long Can You Safely Leave a Cat Alone?

How Long Can You Safely Leave a Cat Alone?

People who live with cats know that they're not nearly as aloof or independent as alleged. Although cats don't require daily walks like dogs, your presence matters to them… and not only because you have the ability to open a can, fill a water bowl and clean a litter box.

Still, there may be times when you must leave your adult cat for overnight or longer. (Kittens younger than four months should not be left alone for more than four hours. Older than that, they can handle another hour or so. When they reach six months, they can tolerate an eight-hour day without company.)

The length of time you can leave a grown-up cat alone depends on the cat, his diet and your environment. Cats who eat dry food that you can make readily available may be left on their own for 24-48 hours as long as fresh water is accessible as well. Beyond that time frame, water may get too dirty to drink and the litter box full.

To prepare for leaving your cat alone, take steps to make your absence as low‐stress on him as possible. This should include a conversation with your veterinarian.

Answer:

31

Step-by-step explanation:

multiple 5 into 7 that is equal to I week than find the answer that is equal to 35 and minas it by 4 that is equal to 31

Answer:

[tex](x-2)^{2} + (y+3)^{2} = 16[/tex]

Step-by-step explanation:

Answer:

[tex]\displaystyle x = \frac{\pi}{4} , \frac{5\pi}{4}[/tex]

Step-by-step explanation:

We want to find all solutions to the equation:

[tex]\displaystyle \sin 2x - 1 = 0[/tex]

In the interval [0, 2π).

First, add one to both sides:

[tex]\displaystyle \sin 2x = 1[/tex]

Recall that sin(u) equals one whenever u = π/2. This will occur for every rotation. Hence, we can say that u = π/2 + 2nπ where n is an integer.

And in this case, u = 2x. Thus:

[tex]\displaystyle 2x = \frac{\pi}{2} + 2n\pi\text{ where } n\in\mathbb{Z}[/tex]

Dividing both sides by two yields:

[tex]\displaystyle x = \frac{\pi}{4} + n\pi \text{ where } n\in \mathbb{Z}[/tex]

There are two values of x in the interval [0, 2π) given when n = 0 and n = 1:

[tex]\displaystyle x _ 1= \frac{\pi}{4} \text{ and } x_2 = \frac{\pi}{4} + (1)\pi = \frac{5\pi}{4}[/tex]

Any other solutions will be outside our interval.

Therefore, our solutions are:

[tex]\displaystyle x = \frac{\pi}{4} , \frac{5\pi}{4}[/tex]