HELP I NEED TO FIND THE COORDINATES OF THE POINTS

Answer:

x = 10

Step-by-step explanation:

2x/3 + 1 = 7x/15 + 3

(times everything in the equation by 3 to get rid of the first fraction)

2x + 3 = 21x/15 + 9

(times everything in the equation by 15 to get rid of the second fraction)

30x+ 45 = 21x + 135

(subtract 21x from 30x; subtract 45 from 135)

9x = 90

(divide 90 by 9)

x = 10

2x/3 + 1 = 7x/15 + 3

(find the LCM of 3 and 15 = 15)

(multiply everything in the equation by 15, then simplify)

10x + 15 = 7x + 45

(subtract 7x from 10x; subtract 15 from 45)

3x = 30

(divide 30 by 3)

x = 10

Answer:

Total amount in dollars= $64614.00

Step-by-step explanation:

Initial starting salary is $40000.

Rate of increase is 3%

Number of years is 16 years

The salary is compounded yearly.

Amount A after 16 years is given as

A= p (1+r/n)^ (nt)

A=40000(1+0.03/16)^(16*16)

A= 40000(1.001875)^(256)

A=40000(1.61534824)

A= 64613.92959

Total amount in dollars= $64614.00

Answer: the answer is $806275

Step-by-step explanation:

A p e x

Answer:

y = 1/3x - 7/3

Step-by-step explanation:

y2 - y1 / x2 - x1

-1 - (-3) / 4 - (-2)

2/6

= 1/3

y = 1/3x + b

-1 = 1/3(4) + b

-1 = 4/3 + b

-7/3 = b

OPTIONS:

A. The interquartile range of the trail mix data is greater than the range of the cracker data.

B. The value 70 is an outlier in the trail mix data.

C. The upper quartile of the trail mix data is equal to the maximum value of the cracker data.

D. The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers.

Answer:

D.

Step-by-step explanation:

With the given information about how the box plot looks like, let's examine each option to see if they are true or not.

Option A: "The interquartile range of the trail mix data is greater than the range of the cracker data."

The interquartile range of trail mix data = 105 - 90 = 15

Range of cracker data = 100 - 70 = 30

Option A is NOT TRUE.

Option B: "The value 70 is an outlier in the trail mix data."

This is NOT TRUE. There are not outliers as 70 is the minimum value if the ranges of the data set for the trail mix.

Option C: "The upper quartile of the trail mix data is equal to the maximum value of the cracker data."

Upper quartile of the trail mix data = 105

Max value of cracker data = 100

This statement is NOT TRUE.

Option D: "The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers."

The greater the range value, the greater the variation. Thus,

Range value of the trail mix data = 115 - 70 = 45

Range value of the cracker data = 100 - 70 = 30

This is statement is correct because trail mix data have a greater range value, hence, it has a greater variation in the number of calories.

Answer: D. The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers.

Answer:

u= 2 ; v = 1

Sen 60 = [tex]\frac{\sqrt{3}}{u}[/tex]  so u=2

Using the pythagoras theorem [tex]u^{2} =v^{2} +\sqrt{3}^{2}[/tex] so v =[tex]\sqrt{2^{2} - 3}[/tex] =1

Answer:

(3,1) is the midpoint

Step-by-step explanation:

To find the x coordinate of the midpoint, average the x coordinates of the endpoints

(7+-1)/2 = 6/2 =3

To find the y coordinate of the midpoint, average the y coordinates of the endpoints

(10+-8)/2 = 2/2 = 1

(3,1) is the midpoint

Answer:

(3, 1)

Step-by-step explanation:

We can use the formula [ (x1+x2)/2, (y1+y2/2) ] to solve for the midpoint.

7+(-1)/2, 10+(-8)/2

6/2, 2/2

3, 1

Best of Luck!

[tex]\\ \rm\longmapsto \sqrt{-18}[/tex]

[tex]\\ \rm\longmapsto \sqrt{18}i[/tex]

[tex]\\ \rm\longmapsto \sqrt{9\times 2}i[/tex]

[tex]\\ \rm\longmapsto \sqrt{3(3)(2)}i[/tex]

[tex]\\ \rm\longmapsto 3i\sqrt{2}[/tex]

Answer:

A. [tex]\displaystyle 3i\sqrt{2}[/tex]

Step-by-step explanation:

[tex]\displaystyle \sqrt{-18} → \sqrt{[2][-1][9]}\\ \\ 3i\sqrt{2}[/tex]

As you can see, you need a perfect square to wourk with, which in this case is 9. Now, [tex]\displaystyle \sqrt{-1}[/tex] comes out as an imaginary number [tex]\displaystyle [i],[/tex]so pull it out of the radical alongside 3, [tex]\displaystyle \sqrt{9}.[/tex]

I am joyous to assist you at any time.

Answer:

0.0009765625

Step-by-step explanation:

This is what i got its probally incorrect

Answer: x= -1, z=2, y= -4

Step-by-step explanation:

System of equations:

-5x - 4y - 3z= 15  +

-10x + 4y + 6z= 6

-15x         + 3z = 21  ------>  3 (-5x + z) = 7.3

-5x + z = 7

now,

-10x + 4y + 6z= 6

2(-5x + z) + 4y + 4z = 6

14 + 4y + 4z = 6

7 + 2y + 2z = 3

2y + 2z= -4

y+z=-2

Now we were using the equation: 20x + 4y + 4z = -28

20x + 4(y+z) = 20x -8= - 28

20 x = -20

x= -1

With this we can find y and z

X=-1

-5x + z = 7

z= 2

y+z=-2

y=-4

Finally we have: x= -1, z=2, y= -4

I hope this can help you.

Thank you

Answer:

D) Prospective observational study

Step-by-step explanation:

A study which gathers data moving forward is called a prospective study.  Since the data is gathered on students without controlling the setting moving forward, it is a prospective observational design.

9514 1404 393

Answer:

  KM = 8

Step-by-step explanation:

The ratio of long side to short side is the same for all of the triangles in this geometry:

  KM/ML = JM/KM

  KM² = ML·JM = 4(20-4) = 64

  KM = √64 = 8

The length of KM is 8 units.

Answer:

this is the return on an investment that does not include the taxes the investor must pay on this return

Answer:

question is not proper

Step-by-step explanation:

question is

Answer:

The answer to your question will be the choice "D."

Answer:

1.3859

Step-by-step explanation:

The formula for Margin of Error is given as:

Margin of Error = Critical value × Standard Error

Critical value = z score

In the question, we are given a confidence interval of 95%.

Z score for a 95% confidence level is given as: 1.96

Hence, critical value = 1.96

Standard Error = σ / √n

Where n = number of samples = 98 chicken eggs

σ = Standard deviation = 7 milligrams

Standard Error = 7/√98

Standard Error = 0.7071067812

Hence, Margin of Error = Critical value × Standard Error

Margin of Error = 1.96 × 0.7071067812

Margin of Error = 1.3859292911

Therefore, the margin of error corresponding to a 95% confidence interval for the true mean cholesterol content, μ, of all such eggs is approximately 1.3859

Answer:

Cohen's d : 1.00

Step-by-step explanation:

We know that M₁ = 18, and M₂ = 14. Given that the pooled variance for the these two samples are 16, S²Pooled = 16, and therefore S - pooled = 4.

The formula to solve for the value of Cohen's d is as follows,

d = M₁ - M₂ / S - pooled,

d = 18 - 14 / 4 = 4 / 4 = 1

Therefore the value of Cohen's d = 1

Answer:

A. The interquartile range (IQR) for brand A, $10, is less than the IQR for brand B, $25.

Step-by-step explanation:

The most appropriate measure that can be used to compare the SPREAD of the data of the 2 brands plotted on a box plot, is the Interquartile range (IQR).

Interquartile range is the difference between Q3 and Q1.

Q3 is the value which lies at the end of the rectangular box, while the Q1 lies at the beginning of the box.

From the box plot given,

IQR for brand A = 80 - 70 = $10

IQR for brand B = 50 - 25 = $25

Therefore, the correct option is "A. The interquartile range (IQR) for brand A, $10, is less than the IQR for brand B, $25."

Answer:

NEGATIVE; DECREASED.

Step-by-step explanation:

A correlation coefficient of -0.76 indicates that there is a "fairly" strong negative relationship between the daily temperature and the number of people who visit the store.

This implies that, as the daily temperature increases, number of customers who come to the store decreases.

Therefore, the interpretation of the situation is:

"There is a NEGATIVE association between x and y. As the high temperature of the day increases across days, the number of customers who come to the store DECREASED.

Answer:

The correct answer is:

Stratified (c.)

Step-by-step explanation:

Stratified sampling technique is one in which the groups of data are divided into smaller groups or strata, based on shared common characteristics in these groups, and the samples randomly selected from each group in a proportional way. In this example, the sub-groups used is "times of the day" ie. morning, afternoon or evening. Other strata that can be used are; age, gender, continents etc. Stratification is done when the researcher wants to understand the relationships between the two or more groups. Stratified random sampling is also known as proportional random sampling or quota random sampling.

Answer:

Step-by-step explanation:

Given:

Total amount = $20,000

Assume

Government bonds = x

Municipal bonds = y

Computation:

1. Invest total money

x + y ≤ 20,000

2. invest no more than $5,000 into municipal bonds

y ≤ 5,000

3. at least twice as much into government bonds.

x ≥ 2y

Answer:

  (a) -2.3°/min

  (b) -2.9°/min

Step-by-step explanation:

The average rate of change is the ratio of the difference in R values to the difference in the corresponding t values.

(a) m = (157.6 -226.6)/(30 -0) = -69/30 = -2.3 . . . degrees per minute

__

(b) m = (61.6 -119.6)/(70 -50) = -58/20 = -2.9 . . . degrees per minute

Answer:

x = 2 is the solution to x + 1.5 = 3.5

Step-by-step explanation:

x + 1.5 = 3.5

   -1.5      -1.5

--------------------

x = 2

Answer:

(a) 1.341

(b) -2.539

(c) -2.160 and 2.160

Step-by-step explanation:

(a) We have to find the critical​ value(s) for a​ right-tailed test of a population mean at the alpha = 0.10 level of significance with 15 degrees of freedom. ​

Since the degrees of freedom are included here, so we will use t table here for a population mean test.

In the table there are two values given, one is the degrees of freedom and another is the value of P.

P is the level of significance at which the critical values are calculated.

So, here the degrees of freedom (n - 1) = 15 and the level of significance for a right-tailed test is 0.10, i.e. P = 10%

Now, looking in the t table with P = 10% and [tex]\nu[/tex] = 15, we get the critical value of 1.341.

(b) We have to find the critical​ value(s) for a​ left-tailed test of a population mean at the alpha = 0.01 based on a sample size of n = 20. ​

Since the degrees of freedom are included here, so we will use t table here for a population mean test.

In the table there are two values given, one is the degrees of freedom and another is the value of P.

P is the level of significance at which the critical values are calculated.

So, here the degrees of freedom (n - 1) = 20 - 1 = 19 and the level of significance for a left-tailed test is 0.01, i.e. P = 1%

Now, looking in the t table with P = 1% and [tex]\nu[/tex] = 19, we get the critical value of 2.539. But since it is a left-tailed test, so the critical value will be -2.539.

(c) We have to find the critical​ value(s) for a​ two-tailed test of a population mean at the alpha = 0.05 level of significance based on a sample size of n = 14. ​

Since the degrees of freedom are included here, so we will use t table here for a population mean test.

In the table there are two values given, one is the degrees of freedom and another is the value of P.

P is the level of significance at which the critical values are calculated.

So, here the degrees of freedom (n - 1) = 14 - 1 = 13 and the level of significance for a two-tailed test is [tex]\frac{0.05}{2}[/tex] is 0.025, i.e. P = 2.5%.

Now, looking in the t table with P = 2.5% and [tex]\nu[/tex] = 13, we get the critical value of -2.160 and 2.160 for a two-tailed test.

Answer:

0.5 km/min and 1km

Step-by-step explanation:

30 km in an hour

30 km in 60 mins, 30/60 km in one minute so she cycle 0.5km/min. They will cover 1 km in 2 minutes

Answer:

Step-by-step explanation:

Equation of a circle is given by

( x - h)² + ( y - k)² = r²

where r is the radius and

( h , k) is the center of the circle

From the question the radius R = 1/3

the center ( h ,k ) = (4/3 , -8/3)

Substituting the values into the above equation

We have

[tex](x - \frac{4}{3} )^{2} + {(y - - \frac{8}{3}) }^{2} = ({ \frac{1}{3} })^{2} [/tex]

We have the final answer as

[tex](x - \frac{4}{3} )^{2} + {(y + \frac{8}{3}) }^{2} = \frac{1}{9} [/tex]

Hope this helps you

Answer:

vertical angles

Step-by-step explanation:

Angle 1 and 3 are vertical angles.  The angles are made from the same lines and share a vertex.  They are opposite it each other

The probability that the average price is between $153 and $155 is 0.04.

Probability refers to a possibility that deals with the occurrence of random events.

The probability of all the events occurring need to be 1.

The average price of a math textbook =$158

The standard deviation =$26

The mean= 158

n =number of textbooks randomly chosen which is 40

n=10

Then

σ = 26

σₓ = σₓ/√n

= 26/√40

Therefore. σₓ² = 16.90

For the group of 48, find the probability that the average price is between $153 and $155.

The probability that the average price is between $153 and $155

= 0.04

Learn more about probability here;

https://brainly.com/question/11234923

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Answer:

Hello,

answer D 48°

Step-by-step explanation:

In the right triangle down, a+42°=90° ==> a=90°-42°=48°

please mark this answer as brainlist

Answer:

The temperature of the 5th day was 3°C

Step-by-step explanation:

Mean temperature of the first 4 days = 8°C

Note that:

Mean = Sum of temperatures ÷ number of days

∴ 8 = sum of temperature ÷ 4

[tex]= 8 = \frac{sum\ of\ temperatures}{4}[/tex]

[tex]= sum\ of\ temperatures\ = 8\ \times\ 4 = 32[/tex]

Therefore the sum of the first 4 days = 32

Let the temperature of the next day (the fifth day) be m

Hence,

sum of the temperatures of first 5 days = 32 + m - - - - (1)

Next, the sum of the first 5 days can be calculated from the given average of the first 5 days as follows:

Mean temperature of the first 5 days = 7

[tex]Mean = \frac{sum\ of\ temperatures}{number \ of\ days}\\\\7 = \frac{sum\ of\ temperatures}{5} \\sum\ of\ temperatures\ = \ 7\ \times\ 5\ = 35\\sum\ of\ temperature\ of\ the\ first\ 5\ days\ =\ 35 - - - - - (2)[/tex]

Now, you will notice that equation (1) = equation (2)

∴ 32 + m = 35

m = 35 - 32 = 3

therefore, the temperature of the 5th day was 3°C