Help!!! PLEASEEEEEEE

Answer:

kinetic energy = 1/2 X m(v)^2

= 1/2 X 88 X 12

= 528 j

Your question has been heard loud and clear.

Kinetic energy formula= 1/2mv^2

Mass = 88kg (convert to grams because velocity is in m/s)

Mass in grams = 88000g or 88*10^3 g

Velocity= 12m/s

Now kinetic energy = 1/2 * 88000*12*12= 6336 joules

Kinetic energy = 6336 Joules or 6.336 Kilo joules

Thank you.

Answer:

The answer is C variable. Just took the quiz.

Explanation:

Answer:

C. variable

Explanation:

Answer:

260 km

65 km/hr

Explanation:

The displacement of an object is the distance moved by that object in a particular direction.

velocity = displacement / time, therefore,

Displacement = velocity * time.

Total displacement for the 4 HR trip = displacement for 2.5 hr + displacement for 1.5 hr

total displacement = (80 * 2.5) + (40 * 1.5)

Total displacement = 200 + 60

Total displacement = 260 Km

average velocity for the total trip = total displacement / total time taken

average velocity = 260 km/ 4 hr

average velocity = 65 km/hr

Answer:

(30010001) 10^8 m/s

Explanation:

Answer: first and third.

Explanation:

An equation is dimensionally correct if the units are the same in both sides of the equation.

first, let's define the units used:

{m} = kg

{v} = m/s

{F} = kg*m/s^2

{x} = m

{t} = s

{a} = m/s^2

Now, let's analyze each option:

1) m*v/t = F

in the left side the units are:

{m}*{v}/{t} =  kg*(m/s)*(1/s) = kg*m/s^2

And as is written above, these are the units of F, so this is correct.

2) x*v^2 = F*(x^3/x^2)

This is more trivial, in the right side we can see an F, that has mass units (kg)  and in the left side we have x and v, and we know that none of these have mass units, so this expression is not correct.

3) xt= vt^2+at^3

the units in the right side are:

{x}*{t] = m*s

in the right side are:

{v}*{t}^2 + {a}*{t}^2 = (m/s)*s^2 + (m/s^2)*s^3 = m*s + m*s

So in both sides of the equation we have the same units, then this equation is dimensionally correct.

Answer:

It is increased

Explanation:

If the amplitude of a transverse wave in a string is increased, then also, the speed of that wave along the string also increases.

In transverse waves, the particles of the medium does move vertically, m either up or down and also moves at right angles to the direction of the wave. It should be noted also, that the wave amplitude of a transverse wave is defined as the difference in height between the crest(high) and the resting position(low).

The highest point particles of the medium reach is often tagged as the crest, while the lowest point is tagged as the resting position. The higher the height of the crests are, the greater the amplitude of the wave will be.

Answer:

it develop isometric strength and endurance in glutes calves quadriceps,hamstring and adductor muscle

Answer:

a

 [tex]f = 614.3 \ Hz[/tex]

b

 [tex]f_h = 1229 \ Hz[/tex]

Explanation:

From the question we are told that

  The speed of sound in the air is  [tex]v_s = 344 \ m/s[/tex]

   The length of the test tube is  [tex]l = 14.0\ cm = 0.14 \ m[/tex]

Since the test tube is closed at on end  the frequency is mathematically represented as

        [tex]f = \frac{v_s}{ 4 l }[/tex]

=>     [tex]f = \frac{344}{ 4 * 0.14 }[/tex]

=>     [tex]f = 614.3 \ Hz[/tex]

From the part B the column of the test tube is half filled with water so the frequency becomes

    [tex]f_h = \frac{v_s}{ 2 l }[/tex]

     [tex]f_h = \frac{344}{ 2 * 0.14}[/tex]

    [tex]f_h = 1229 \ Hz[/tex]

Answer:

The Veterans Health Administration (VHA) is the largest integrated health

care system in the United States, providing care at 1,255 health care

facilities, including 170 VA Medical Centers and 1,074 outpatient sites of care

of varying complexity ( VHA outpatient clinics) to over 9 million Veterans

enrolled in the VA .

Given :

Mass of tiger , m = 81 kg .

Velocity of tiger , v = 5.4 m/s .

To Find :

The momentum of tiger .

Solution :

We know , momentum of a body is given by the product of its mass and velocity .

[tex]P=m\times v[/tex]

Now , putting value of m and v in above equation , we get :

[tex]P=m\times v\\\\P=81\times 5.4 \ kg\ m/s\\\\P=437.4 \ kg\ m/s[/tex]

Therefore , the momentum of tiger is 437.4 kg m/s .

Hence , this is the required solution .

Answer:

437.4

Explanation: did the math

Answer:

light should be direct

glass should not be cracked

pins should be pointed carefully

Explanation:

Explanation:

The resistance of a wire is given by the formula as follows :

[tex]R=\rho \dfrac{l}{A}[/tex]

l is length of wire

A is area of cross section, [tex]A=\pi r^2[/tex]

Since, r=d/2, d = diameter

[tex]A=\pi \dfrac{d^2}{4}[/tex]

It is given in the problem that the resistance of two aluminum wires is same.

[tex]R_1=R_2\\\\\rho\dfrac{L_1}{\pi d_1^2/4}=\rho\dfrac{L_2}{\pi d_2^2/4}\\\\\dfrac{L_1}{L_2}=\dfrac{d_1^2}{d_2^2}[/tex]

We have, L₁=2L₂

So,

[tex]\dfrac{2L_2}{L_2}=\dfrac{d_1^2}{d_2^2}\\\\\dfrac{d_1^2}{d_2^2}=2\\\\\dfrac{d_1}{d_2}=\sqrt{2}[/tex]

So, the ratio of the diameter of the longer wire to the diameter of the shorter wire is [tex]\sqrt2:1[/tex]

Answer: the awnser to this question is 15

Explanation:

First you will divide the typing speed and the total number of words by the speed 2000 ÷ 50

Then divide bobs typing speed by 2000 equation 2000÷80 once you get the total both you will subtract the 2 totals together and get 15 as your awnser.

Hoped this helped!

Answer:

Explanation:

Using the equation of motion v = u + at to get the speed at which the object would be travelling.

v is the final speed (in m/s)

u is the initial velocity (in m/s)

a is the acceleration (in m/s²)

t is the time taken (in  secs)

Given parameters

u = 0m/s

t = 10s

a = g = 9.8m/s²

Substituting this values into the formula;

v = 0+9.8(10)

v = 0+ 98

v  = 98m/s

Hence the rock will be travelling at a speed of 98m/s.

Answer:

Explanation:

A, yes

b,

The force(per unit length) on wire 1 by 2 is to the left and

= μo*I1*I2/2πr

= 2*10^-7 * 1.2 * 4.2/0.20

= 5.04*10^-6N/m

From third law we have the force on wire2 by wire 1 is 5.04*10^-6N/m and to the right

So the magnitude of the force on each wire by wire 3 must be 4.2*10^-6N/m

Since the current in wire 2 is > wire 1 then wire 3 must be closer to wire 1 than 2

and wire 3 must be to the left of wire 1

Let x be the distance from wire 3 to wire 1 so x + 0.20 = distance from wire 3 to wire 2

Now μo*I1*I3/2πx = μo*I3*I2/2π(x + 0.20)

so solving for x we get

I1/x = I2/(x+0.20)

or x +0.20 = 4x

so x = 0.20/3 = 0.0667m

Now μo*I1*I3/2πx = 4.2*10^-6

so I3 = 4.2x10^-6 * 0.0667/(2.0x10^-7 * 1.2) = 1.167 A and its direction is down

Explanation:

We know that :

[tex]F = m\frac{(v - u)}{t} [/tex]

[tex]100 = 20 \frac{(v - 10)}{1} [/tex]

[tex]v(final \: velocity) = 15 \: m \: sec^{ - 1} [/tex]

Answer:

The acceleration of the proton is 2.823 x 10¹⁷ m/s²

The acceleration of the electron is 5.175 x 10²⁰ m/s²

Explanation:

Given;

distance between the electron and proton, r = 7 x 10⁻¹⁰ m

mass of proton, [tex]m_p[/tex] = 1.67 x 10⁻²⁷ kg

mass of electron, [tex]m_e[/tex] = 9.11 x 10⁻³¹ kg

The attractive force between the two charges is given by Coulomb's law;

[tex]F = \frac{k(q_p)(q_e)}{r^2}[/tex]

where;

k is Coulomb's constant = 9 x 10⁹ Nm²/c²

[tex]F = \frac{k(q_p)(q_e)}{r^2} \\\\F = \frac{(9*10^9)(1.602*10^{-19})(1.602*10^{-19})}{(7*10^{-10})^2} \\\\F = 4.714 *10^{-10} \ N[/tex]

Acceleration of proton is given by;

F = ma

[tex]F = m_pa_p\\\\a_p = \frac{F}{m_p}\\\\a_p = \frac{4.714*10^{-10}}{1.67*10^{-27}}\\\\a_p = 2.823 *10^{17} \ m/s^2[/tex]

Acceleration of the electron is given by;

[tex]F = m_ea_e\\\\a_e = \frac{F}{m_e}\\\\a_e = \frac{4.714*10^{-10}}{9.11*10^{-31}}\\\\a_e = 5.175 *10^{20} \ m/s^2[/tex]

Given:

By using Coulomb's law, the attractive force will be:

→ [tex]F = \frac{k(q_p) (q_e)}{r^2}[/tex]

By substituting the values, we get

        [tex]= \frac{(9\times 10^9)(1.602\times 10^{-19}) (1.602\times 10^{-19})}{(7\times 10^{-10})^2}[/tex]

        [tex]= 4.714\times 10^{-10} \ N[/tex]

Now,

The acceleration of proton will be:

→ [tex]F = ma[/tex]

       [tex]= m_p a_p[/tex]

or,

→ [tex]a_p = \frac{F}{m_p}[/tex]

        [tex]= \frac{4.714\times 10^{-10}}{1.67\times 10^{-27}}[/tex]

        [tex]= 2.823\times 10^{17} \ m/s^2[/tex]  

and,

The acceleration of electron will be:

→ [tex]F = m_c a_c[/tex]

or,

→ [tex]a_e = \frac{F}{m_e}[/tex]

        [tex]= \frac{4.714\times 10^{-10}}{9.11\times 10^{-31}}[/tex]

        [tex]= 5.175\times 10^{20} \ m/s^2[/tex]

Thus the above answer is correct.

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Answer:

6.2m/s

Explanation:

v=u+at

v=7+(-0.8/2)(2)

v=7-0.8

v=6.2m/s

Answer:

x = -3t² + 12

Explanation:

x vs t² is a line.

x = at² + b

The y intercept is 12.

x = at² + 12

At t² = 4s², x = 0.

0 = a(4) + 12

a = -3

Therefore, the function is:

x = -3t² + 12

Answer:

Explanation:

It is the far point an myopic person . For it she uses concave lens . For her ,

object distance u = infinity

image v = - 9.5 cm

f = ?

form the lens formula

[tex]\frac{1}{f} = \frac{1}{v} - \frac{1}{u} \\[/tex]

[tex]\frac{1}{f} = \frac{1}{-9.5} - 0 \\[/tex]

f = - 9.5 cm  = - 9.5 / 100 m

P = 1 /f = - 100 / 9.5 =  - 10.52 D .

Answer:

D

There is both a positive correlation and causation

The relationship between how hard the gas pedal is pressed and the acceleration of the car is positive correlation and causation.

From the given statement the relationship between the cause (pedal) and the effect (velocity) can be described as direct relationship.

The harder the gas pedal in a car is pressed, the velocity increases. This shows that as the force applied to the gas pedal increases (the cause of the action), the greater the velocity of the car (the effect of the cause).

Thus, we can conclude that the relationship between how hard the gas pedal is pressed and the acceleration of the car is positive correlation and causation.

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Answer:

speed=d/t.

s=4/5=0.8m/s.

Answer:

6779.7m/s

Explanation:

Using

GMm/(Re +h)² = mv²/ (Re+h)

So making v subject we have

V= √GM/Re+h

So

V = √ 6.67*10^-11 x 5.97*10^24/(6371+2300)*10^3

V= 6779.7m/s

Note h = height of satellite

Re= radius of the earth

M = mass of the earth

Answer:

(c) Both A and B

Explanation:

Given;

wavelength of the incident light, λ = 3500 Å = 3500 x 10⁻¹⁰ m

The energy of the incident light is given by;

E = hf

where;

h is Planck's constant = 6.626 x 10⁻³⁴ J/s

f is frequency =  c / λ

[tex]E = \frac{hc}{\lambda} \\\\E = \frac{(6.626*10^{-34})(3*10^8)}{3500*10^{-10}}\\\\E = 5.68 *10^{-19} \ J\\\\E = 5.68 \ eV[/tex]

Work function is the minimum amount of energy required to liberate electrons from a metal surface.

The work function of metal A is 3.2 eV and

Th e work function of metal B is 1.9 eV

Both work functions are less than the incident energy of the light calculated as 5.68eV.

Thus, both metals will emit photoelectrons.

(c) Both A and B

Answer:

14.1mins

Explanation:

We know that

Time =Distance/Speed

So

= 1.7 au/ (3 E8 m /s )

= 1.7 x 1.496 x 10^11 m /(3 x 10^8 m /s

Converting Au to meters (1.7 x 1.496 x 10^11 m)

= 847.7 s

=14.1 mins

Answer:

Time = 847.73 s = 14.12 min

Explanation:

The distance traveled by an object travelling at a constant speed is given by the following formula:

Distance = (Speed)(Time)

Time = Distance/Speed

where,

Distance = 1.7 AU

converting it into meters:

Distance = (1.7 AU)(1.496 x 10¹¹ m/1 AU) = 2.543 x 10¹¹ m

Speed = 3 x 10⁸ m/s

Therefore, using these values in the equation we get:

Time = (2.543 x 10¹¹ m)/(3 x 10⁸ m/s)

Time = 847.73 s = 14.12 min

Answer:

In the absence of government, what would determine the way people act towards each other is the need to acquire means of survival such as food or shelter.

Thus, since the government regulates the rights and obligations of citizens to guarantee equal access to essential services and goods for life, in the event of the disappearance of the state as a form of social organization, people would tend to act selfishly. to provide itself with those goods and services.

Society would then return to a state of nature, where man competes with his peers for access to resources. So the need for those resources would ultimately determine the way humans relate to each other.

Throughout the absence of regulation, the necessity to gain means of subsistence, which includes extra help, would decide how individuals interact with one another.

As a consequence, while the organization governs individuals' rights and duties purpose of providing equitable access to vital services and products for life, if the community as more than just a form of social organization disappears, individuals might likely behave selfishly to offer such commodities.

Thus the response above is right.

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Answer:

Explanation:

Velocity is a vector with speed and direction components. If the speed does not change, then the direction must. In order to change the direction of a velocity vector, there must be some acceleration, and it must be orthogonal to the direction of motion.

Circular motion is motion that has a constant acceleration perpendicular to the direction of travel.

__

Another kind of motion that meets the requirement is the motion of light. Light travels at a constant speed, regardless. If light changes direction (as in a gravitational field or when reflected), its direction will change, but its speed will not.

Answer:

Explanation:

Using the given values

Let

Px= 2.3 x 10^6, Py=0, Qx=1.5x10^6cos(70),

Qy= 1.5x10^6sin(70)

So let

Hx= Px+Qx=2.813 x 10^6, Hy=Py+Qy=1.401 x 10^6

Magnitude = √ ((2.813 x 10^6)^2+(1.401 x 10^6)^2)= 3.14 x 10^6

To find direction

tan စ = Hy/Hx = 1.401/2.813= 0.4980

စ = 26.5°

The magnitude and direction of the path of the spaceship if it had traveled to the space station through the nebula are 3.14 x 10⁶ m and 26.5°.

A nebula is a huge cloud consisting of dust and gas in space. Some nebula come from the gas and dust thrown out by the explosion of a dying star known as a supernova.

The captain orders the ship to travel in horizontal direction, Px= 2.3 x 10⁶ m, Py=0,

After turning 70° and it travels to reach the space station, Qx = 1.5x10⁶ x cos70° in horizontal direction.

and Qy= 1.5x10⁶sin70°

So, total horizontal distance moved is

Hx= Px+Qx = 2.813 x 10⁶

Total vertical distance moved is
Hy=Py+Qy  = 1.401 x10⁶

Magnitude of the path = sq rt [(2.813 x 10⁶)²+(1.401 x 10⁶)²]

Path = 3.14 x 10⁶ m

Direction of the path,

tan α = Hy/Hx

tan α = 1.401/2.813

tan α = 0.4980

α = 26.5°

Thus, the magnitude and direction of the path of spaceship is 3.14 x 10⁶ m and 26.5°.

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Answer:

Isolation of Variables.

Explanation:

I am just taking a guess but Experimental investigations allow you to isolate variables (making most variables constant, allowing only the independent variable to have an impact on the dependent variable). With other scientific investigations, if they don't isolate the variables it is very possible that an unknown third variable could be skewing the results (which will result in correlation but not causation).

Answer:

Experimental investigations are the best type of scientific investigation to demonstrate cause-and-effect relationships because they allow the investigator to actively manipulate variables and control conditions. The independent variable can be isolated and manipulated, producing a change (or no change) in the dependent variable. This change can be measured to gather evidence to support or refute the cause-and-effect relationship. Experimental investigations also use a control group (a group that does not receive the factor being tested) for comparison.

Explanation:

Automated-response....it's right

Answer:

The  value is   [tex]Q_{net} =  1.239 *10^{-6} \  C[/tex]

Explanation:

From the question we are told that

   The electric flux is [tex]\Phi =  1.4*10^{5} \  N\cdot m^2/C[/tex]

Generally the net charge is mathematically represented as

    [tex]Q_{net} =  \Phi *  \epsilon_o[/tex]

Here [tex]\epsilon_o[/tex] is the permetivity of free space with value  

       [tex]\epsilon_o =  8.85*10^{-12}  \  \  m^{-3} \cdot kg^{-1}\cdot  s^4 \cdot A^2[/tex]

So

   [tex]Q_{net} =  1.4*10^5 *  8.85*10^{-12}[/tex]

=>   [tex]Q_{net} =  1.239 *10^{-6} \  C[/tex]