Help PLZZ
Find the slope of the line through each pair of points
1.(10,-9),(-4,-14)
2.(16,6),(-4,-14)
3.(9,-4),(5,-20)
4.(-13,20),(-18,20)

Answers

Answer 1
[tex]\huge \rm༆ Answer ༄[/tex]

To find slope we use the formula ~

[tex] \sf \dfrac{y2 - y1}{x2 - x1} [/tex]

[ Ratio of the difference of y - coordinates of the points and the difference of x - coordinates of the points ]

let's find the slope of line passing through the given points ~

1. (10 , -9) and (-4 , -14)

[tex] \sf \dfrac{ - 9 - ( - 14)}{10 - ( - 4)} [/tex]

[tex] \sf \dfrac{ - 9 + 14}{10 + 4} [/tex]

[tex] \sf \dfrac{5}{14} [/tex]2. (16 , 6) and (-4 , -14)

[tex] \sf \dfrac{6 - ( - 14)}{16 - ( - 4)}[/tex]

[tex] \sf \dfrac{6 + 14}{16 + 4} [/tex]

[tex] \sf \dfrac{20}{20}[/tex]

[tex] \sf1[/tex]3. (9 , -4) and (5 , -20)

[tex] \sf \dfrac{ - 4 - ( - 20)}{9 - 5}[/tex]

[tex] \sf \dfrac{ - 4 + 20}{4} [/tex]

[tex] \sf \dfrac{16}{4} [/tex]

[tex] \sf4[/tex]

4. (-13 , 20) and (-18 , 20)

[tex] \sf \dfrac{20 - 20}{ - 13 - ( - 18)} [/tex]

[tex] \sf\dfrac{0}{ - 13 + 18} [/tex]

[tex]0[/tex]

I hope it helps ~

___________________________________

[tex]꧁ \: \: \large \rm{kaul} \: ꧂[/tex]


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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answers

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Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

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Given data ,

Let the equation be A , 3.74 = 0.4n + 2.5

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Answers

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Step-by-step explanation:

Answer:

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Step-by-step explanation:

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hi have a good day.

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Answers

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Step-by-step explanation:

Just ask!

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~Happy Holidays!!~ o(* ̄▽ ̄*)ブ

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Answers

Answer: A cos (π/4)

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

  A.  {-1, 2, 7}

Step-by-step explanation:

For a set of ordered pairs, the domain is the set of first-numbers (x). The range is the set of second numbers (y, or g(x)).

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The attachment shows a table.

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_____

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find area of parallelogram multiple choice

refer to image.
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MUST. give thoughtful explanation

Answers

In ∆ABD

[tex]\\ \sf\longmapsto Area=\dfrac{1}{2}bh=\dfrac{1}{2}(7\times 4)[/tex]

In ∆BCD

[tex]\\ \sf\longmapsto Area=\dfrac{1}{2}(7\times 4)[/tex]

Now

IN PARALLELOGRAM ABCD

[tex]\\ \sf\longmapsto Area=\dfrac{1}{2}(7\times 4)+\dfrac{1}{2}(7\times 4)[/tex]

Option A

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