Answer:60g
Step-by-step explanation:
Hope this the answer
can someone pls help me on this
Answer:
The answer is X=3/4 or -1/2
Fair coin say you flip a coin 10 times. It comes up tails 8 times and heads twice. Is this a fair coin?
7 cm
D
What is the sum of the areas of circle C and circle D?
O7ft units²
O 14 units²
O 49 units²
O98 units²
The sum of areas of circle C and circle D exists 98 square units.
How to estimate the sum of the areas of circle C and circle D?Given: Radius of circle = 7 units
Area of circle [tex]=\pi r^2[/tex] ..............(1)
Where, r be the radius of circle
The radius of circle C, r = 7 units
(1) becomes
Area of circle, C [tex]= \pi 7^2[/tex] square units
[tex]= 49\pi[/tex] units²
Area of circle, D [tex]= \pi 7^2[/tex] square units
[tex]= 49\pi[/tex] units²
Sum of areas of circles C and D,
= Area of circle C + Area of circle D
= 49 + 49
= 98 units²
The sum of areas of circles C and D exist 98 units².
Therefore, the correct answer is option d) 98 units².
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Every time I use a piece of scrap paper, I crumple it up and try to shoot it inside the recycling bin across the room. I'm pretty good at it: If I shoot $5$ pieces of paper at the recycling bin, at least one of them will make it inside the recycling bin with probability $\frac{211}{243}$. If I shoot $6$ pieces of paper at the recycling bin, what's the probability at least two of them make it inside the recycling bin
Using the binomial distribution, it is found that there is a 0.0012 = 0.12% probability at least two of them make it inside the recycling bin.
What is the binomial distribution formula?The formula is:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
The parameters are:
x is the number of successes.n is the number of trials.p is the probability of a success on a single trial.With 5 shoots, the probability of making at least one is [tex]\frac{211}{243}[/tex], hence the probability of making none, P(X = 0), is [tex]\frac{232}{243}[/tex], hence:
[tex](1 - p)^5 = \frac{232}{243}[/tex]
[tex]\sqrt[5]{(1 - p)^5} = \sqrt[5]{\frac{232}{243}}[/tex]
1 - p = 0.9908
p = 0.0092
Then, with 6 shoots, the parameters are:
n = 6, p = 0.0092.
The probability that at least two of them make it inside the recycling bin is:
[tex]P(X \geq 2) = 1 - P(X < 2)[/tex]
In which:
[P(X < 2) = P(X = 0) + P(X = 1)
Then:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 0) = C_{6,0}.(0.0092)^{0}.(0.9908)^{6} = 0.9461[/tex]
[tex]P(X = 1) = C_{6,1}.(0.0092)^{1}.(0.9908)^{5} = 0.0527[/tex]
Then:
P(X < 2) = P(X = 0) + P(X = 1) = 0.9461 + 0.0527 = 0.9988
[tex]P(X \geq 2) = 1 - P(X < 2) = 1 - 0.9988 = 0.0012[/tex]
0.0012 = 0.12% probability at least two of them make it inside the recycling bin.
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Can someone help? ASAP
Question 4
[tex]\sin 30^{\circ}=\frac{y}{14\sqrt{3}}\\\\\frac{1}{2}=\frac{y}{14\sqrt{3}}\\\\\boxed{y=7\sqrt{3}}\\\\\\\\\cos 30^{\circ}=\frac{x}{14\sqrt{3}}\\\\\frac{\sqrt{3}}{2}=\frac{x}{14\sqrt{3}}\\\\\boxed{x=21}[/tex]
Question 5
[tex]\cos 45^{\circ}=\frac{x}{28}\\\\\frac{1}{\sqrt{2}}=\frac{x}{28}\\\\x=\frac{28}{\sqrt{2}}\\\\\boxed{x=14\sqrt{2}}\\\\\\\\\sin 45^{\circ}=\frac{y}{28}\\\\\frac{1}{\sqrt{2}}=\frac{y}{28}\\\\y=\frac{28}{\sqrt{2}}\\\\\boxed{y=14\sqrt{2}}[/tex]
Darlene says that 1/4 is greater than 1/3 because 4 is great than 3. is she correct?
No she is not correct 1/3 is great that 1/4
Answer:
No, she isn't correct because if the numerator are same but if denominators is different,then the fraction with smaller denominator is greater.
Which of the following are identities? I. y=x II. 4=3x2+2 III. x=x−−√ A. II and III B. I and III C. all D. none
None of the expressions is an identity
How to determine the identities?The expressions are given as:
I. y=x
II. 4 = 3x^2 + 2
III. x=x
In algebra, there are three identities; and they are
(x+y)^2 = x^2 + y^2 + 2xy(x-y)^2 = x^2 + y^2 – 2xyx^2 – y^2 = (x+y) (x-y)None of the given expression take the above forms
Hence, none of the expressions is an identity
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Will’s meal of grilled chicken strips and carrots contained a total of 333 calories. The bag of grilled chicken strips contained x servings of 110 calories each. The bag of carrots contained y servings of 29 calories each. Which equation written in standard form represents the number of servings of chicken strips and carrots that Will may have eaten?
110y = –29x + 333
29x + 110y = 333
29y = –110x + 333
110x + 29y = 333
Answer:
correct answer is 110x + 29y = 333
Step-by-step explanation:
Rule 1: Multiply by 2 then add 1 starting from 1.
Rule 2: Divide by 2 then add 4 starting from 40.
I need to make an sequence for both of them and I need help
Rule 1:
1, 3, 7, 15, 31, 63, 127, 255, 511, 1023 etc
Rule 2:
40, 24, 16, 12, 10, 9, 8.5, 8.25, 8.125, 8.0625 etc
Hope this helps!
The first sequence is 1,3,7,15,31 and second sequence is 40,24,16,12,10.
Given that first rule is that multiply by 2 then add 1 starting from 1 and second rule is that divide by 2 then add 4 starting from 40.
We have to find the sequences for each rule.
We have to start from starting point and then apply the rule to find the sequence.
Sequence of rule 1:
Second term of sequence=2*1+1=3
Third term of the sequence=2*3+1=7
Fourth term of the sequence=2*7+1=15
Fifth term of the sequence=2*15+1=31.
Sequence will be 1,3,7,15,31.
Sequence of rule 2:
Second term of sequence=40/2+4=24
Third term of sequence=24/2+4=16
Fourth term of sequence=16/2+4=12
Fifth term of sequence=12/2+4=10
Sequence will be : 40,24,16,12,10.
Hence the first sequence is 1,3,7,15,31 and second sequence is 40,24,16,12,10.
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if three pies require 2 dozen apples, then four bird require ? dozen apples?
Wright in point-slope form, slope-intercept form and in standard form an equation that passes through (-1, 2) with slope 4
Point-slope form
[tex]y-2=4(x+1)[/tex]
Slope-intercept form
[tex]y-2=4x+4 \\ \\ y=4x+6[/tex]
Standard form
[tex]4x-y+6=0[/tex]
Answer:
[tex]\textsf{Point-slope form}: \quad \sf y-2=4(x+1)[/tex]
[tex]\textsf{Slope-intercept form}: \quad \sf y=4x+6[/tex]
[tex]\textsf{Standard form}: \quad \sf 4x-y=-6[/tex]
Step-by-step explanation:
Given information:
Slope = 4Point on line = (-1, 2)Point-slope form of linear equation:
[tex]\sf y-y_1=m(x-x_1)[/tex]
(where m is the slope and (x₁, y₁) is a point on the line)
Substitute the given slope and point into the formula:
[tex]\implies \sf y-2=4(x-(-1))[/tex]
[tex]\implies \sf y-2=4(x+1)[/tex]
Slope-intercept form of a linear equation:
[tex]\sf y=mx+b[/tex]
(where m is the slope and b is the y-intercept)
Substitute the given slope and point into the formula and solve for b:
[tex]\implies \sf 2=4(-1)+b[/tex]
[tex]\implies \sf b=6[/tex]
Therefore:
[tex]\sf y=4x+6[/tex]
Standard form of a linear equation:
[tex]\sf Ax+By=C[/tex]
(where A, B and C are constants and A must be positive)
Rearrange the found slope-intercept form of the equation into standard form:
[tex]\implies \sf y=4x+6[/tex]
[tex]\implies \sf 4x-y+6=0[/tex]
[tex]\implies \sf 4x-y=-6[/tex]
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System of Linear Programming:
z=-3x + 5y
x+y> -22
x-y-4
x - y ≤ 2
Minimum value of z:
The minimum value of z is -12.
Given that the system of linear programming
z=-3x+5y
x+y≥-22
x-y≥-4
x-y≤2
Firstly, we will convert the given constraints into equality as
x+y=-22
x-y=-4
x-y=2
Now, we will take the equation x+y=-22 and taking x as 0 as find y and taking y as 0 to find x, we get
If x=0 then y is
0+y=-22
y=-22
If y=0 then x=-22
So, the points lie on the line x+y=-22 is (0,-22) and (-22,0).
Further, we will take the equation x-y=-4 and taking x as 0 as find y and taking y as 0 to find x, we get
If x=0 then y=4
If y=0 then x=-4
So, the points lie on the line x-y=-4 is (0,4) and (-4,0).
Furthermore, we will take the equation x-y=2 and taking x as 0 as find y and taking y as 0 to find x, we get
If x=0 then y=-2
If y=0 then x=2
So, the points lie on the line x-y=2 is (0,-2) and (2,0).
now, we will find the feasible region of the given constraints as shown in figure.
We will find that each constraint will contain origin or not by substituting (0,0), we get
0+0≥-22 containing origin
0-0≥-4 containing origin
0-0≤2 containing origin
From the graph we can see that the minimum value of x is -13 and minimum value of y is -12.
z=-3x+5y
z=-3x+3y+2y
z=-3(x-y)+2y
minmum value of x-y from the given constraints is
-4≤x-y≤2
From here minimum value of x-y is -4
So, z=-3(-4)+2y
z=12+2y
For the minimum value of z the value of y should be minimum.
From the graph we can see the minimum value of y=-12
So, z=12+2(-12)
z=12-24
z=-12
Hence, the minimum value of z for the system of Linear Programming:
z=-3x + 5y, x+y≥-22, x-y≥-4, x - y ≤ 2 is -12.
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4 kilograms of almonds cost $34. how much does it cost for kilograms of almonds?
The cost of kilograms of almonds is $8.5 if 4 kilograms of almonds cost $34.
According to the questions,
4 kilograms of almonds cost $34. In order to find one kilograms of almonds only if we divide 34 by 4.
= [tex]\frac{34}{4}[/tex] = 8.5
Hence, the cost of kilograms of almonds is $8.5 if 4 kilograms of almonds cost $34.
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Do 7 ft, 9 ft, 11 ft form a right triangle
Answer:
no
Step-by-step explanation:
using the converse of Pythagoras' identity
if the square on the longest side is equal to the sum of the squares on the other 2 sides then the triangle is right.
longest side = 11 and 11² = 121
7² + 9² = 49 + 81 = 130
since 121 ≠ 130 then sides do not form a right triangle
if we multiply or divide both sides of a linear equation with a non zero number, then the solution of the linear equation
hi
"does not change " or "remain the same "
Need help on the Sin(4x) part of the question please!!
a. The equivalent expression for cos(4x) in terms of just x is 8cos⁴x - 8cos²x + 1
b. The equivalent expression for sin(4x) in terms of just x is 4sinxcos³x - 2sinxcosx
a. The equivalent trigonometric expression for cos(4x)To find the trigonometric expression for cos(4x)
cos(4x) = cos[2(2x)]
Now from trigonometric identities
cos2Ф = 2cos²Ф - 1
Let 2x = Ф.
So, cos(4x) = 2cos²2x - 1
Also, cos2x = 2cos²x - 1
So, substituting cos2x into cos4x, we have
cos(4x) = 2cos²2x - 1
cos(4x) = 2[2cos²x - 1]² - 1
cos(4x) = 2[4cos⁴x - 4cos²x + 1] - 1
cos(4x) = 8cos⁴x - 8cos²x + 2 - 1
cos(4x) = 8cos⁴x - 8cos²x + 1
So, the equivalent expression for cos(4x) in terms of just x is 8cos⁴x - 8cos²x + 1
b. The equivalent trigonometric expression for sin(4x)To find the expression for sin(4x)
sin(4x) = sin2(2x)
From trigonometric identities sin2Ф = 2sinФcosФ
Let 2x = Ф
So, sin(4x) = sin2(2x)
= 2sin2xcos2x
Since
sin2x = 2sinxcosx and cos2x = 2cos²x - 1Substituting these into the equation, we have
sin(4x) = 2sin2xcos2x
sin(4x) = (2sinxcosx)(2cos²x - 1)
sin(4x) = 4sinxcos³x - 2sinxcosx
So, the equivalent expression for sin(4x) in terms of just x is 4sinxcos³x - 2sinxcosx
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Bill and his classmates completed 14 activities in 4 hours. what is the unit rate at which they ocompleted the activities
Step-by-step explanation:
we first divide fourteen by four
14/4= 3.5
then we change 0.5 to hours by multiplying by 60
0.5 * 60 = 30
so in conclusion it would take 3hrs 30mins to finish each activity
The graph shows a system of inequalities.
The graph shows a dashed upward opening parabola with a vertex at 0 comma 0 that passes through negative 3 comma 9 and 3 comma 9, with shading inside the parabola. It also shows a graph of a downward opening parabola with a vertex at 4 comma 22 that passes through 0 comma 6 and 8 comma 6, with shading inside the parabola.
Which point is a solution to the system?
(–1, 6)
(0, 22)
(2, 9)
(8, 2)
The number of tickets sold on Friday were 66 children tickets and 97 adult tickets.
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
The equation of the parabola passing through (0, 0), (-3, 9) and (3, 9) is y = x²
The equation of the parabola with vertex at (4, 22) passing through (0, 6), (8, 6) and (3, 9) is y < -x² + 8x + 6
The solution to the system of equation is the darker region and it contains the point (-1, 6)
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Answer:
(2,9)
Step-by-step explanation:
Got it on FlVS
Determine whether the triangles can be proved similar. If they are similar, write a similarity statement. If they are not similar, explain why.
Answer:
They are similar. Triangle abc is similar to triangle edc.
Step-by-step explanation:
To prove that triangles are similar, you must show that the 3 angles in one triangle are equal to the 3 angles in the other triangle. We know that they both have a 50 degree angle. We can also see that they both have a right angle. That means that the 3rd angle must also equal 40 (180-90-50). So by AAA the two triangles are congruent.
Triangle ABC is similar to triangle EDC.
Answer:
triangle ABC is similar to triangle DCE
Step-by-step explanation:
Reason being that angles in triangle ABC Correspond to That of triangle DCE Eg triangle ABC=CDE
POINTS!!!! PLS HELP LOOK AT PIC
Answer:
first option
Step-by-step explanation:
two solutions means 2 cutting points
Speedy Swift is a package delivery service that serves the greater Atlanta, Georgia, metropolitan area. To maintain customer loyalty, one of Speedy Swift's performance objectives is on-time delivery. To monitor its performance, each delivery is measured on the following scale: early (package delivered before the promised time), on-time (package delivered within 15 minutes of the promised time), late (package delivered more than 15 minutes past the promised time), or lost (package never delivered). Speedy Swift's objective is to deliver 99% of all packages either early or on-time.
Speedy collected the following data for last month's performance:
On-time On-time Early Late On-time On-time On-time On-time Late On-time
Early On-time On-time Early On-time On-time On-time On-time On-time On-time
Early On-time Early On-time On-time On-time Early On-time On-time On-time
Early On-time On-time Early Early Early On-time Loss On-time Early
Late Late Late On-time On-time On-time On-time On-time On-time On-time
On-time Late Early On-time Early On-time Lost On-time On-time On-time
Early Early On-time On-time Late Early Early On-time On-time On-time
On-time On-time Early On-time Early On-time Early On-time Late On-time
On-time Early On-time On-time On-time Late On-time Lost On-time On-time
On-time On-time On-time On-time On-time Early Early On-time On-time On-time
(a) What scale is used to measure delivery performance? What kind of variable is delivery performance?
(b) Construct a frequency table for delivery performance for last month.
(c) Construct a relative frequency table for delivery performance last month.
(a) The scale used in the analysis is qualitative as the data is not assigned any numeric value.
The daily performance is an ordinal variable, as the values assigned are ranked according to an order of the delivery time.
(b) The frequency table of the given data is:
Variable Frequency
Early 23
On-time 65
Late 9
Lost 3
Total 100.
(c) The relative frequency table for the given data is:
Variable Frequency Relative frequency
Early 23 23/100 = 0.23 = 23%
On-time 65 65/100 = 0.65 = 65%
Late 9 9/100 = 0.09 = 9%
Lost 3 3/100 = 0.03 = 3%
(a) The scale used in the analysis is qualitative as the data is not assigned any numeric value.
The daily performance is an ordinal variable, as the values assigned are ranked according to an order of the delivery time.
(b) The frequency table is a table showing frequency of each variable for the number of times they appear in the data.
The frequency table of the given data is:
Variable Frequency
Early 23
On-time 65
Late 9
Lost 3
Total 100.
(c) The relative frequency for a variable is the ratio of its frequency to the total frequency.
The relative frequency table for the given data is:
Variable Frequency Relative frequency
Early 23 23/100 = 0.23 = 23%
On-time 65 65/100 = 0.65 = 65%
Late 9 9/100 = 0.09 = 9%
Lost 3 3/100 = 0.03 = 3%
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Answer:
C.
Step-by-step explanation:
Which of the following is
key property of the quadratic parent function?
A. Its vertex is at the origin.
B. It is not a function.
C. It iS not a parabola.
D It is in quadrants III and IV.
Answer:
Step-by-step explanation:
i think it is c
Answer:
A
Step-by-step explanation:
So let's look at each and determine whether they're true or not.
A. It's vertex is at the origin:
This is true! The reason for this is because you can express a quadratic in vertex form as such: [tex]f(x)=a(x-h)+k[/tex] where (h, k) is the vertex. If you remember the parent function is simply: [tex]f(x)=x^2[/tex] which we can express as: [tex]f(x) = (x-0)+0[/tex] meaning the vertex is at (0, 0). This also intuitively makes sense, the x^2 will only output positive values for real numbers, so when x<0, f(x) is still going to be positive because it's squaring the negative, so that means when you go from -5 to -4, even though you increased x by 1, the f(x) decreases by 1, since it's squaring the value to get a positive value. The lowest value this can output is 0 because 0^2 = 0. This means you vertex is at the origin.
B. It is not a function:
So the quadratic parent function only outputs 1 value for each input, although it isn't a one-to-one function, meaning that each output isn't unique, but each input still only outputs 1 output, which makes this a function
C. It is not a parabola:
parabolas are expressed as quadratic equations, so this is false.
D. It is in quadrants ||| and IV:
This is not true since the parent function opens upwards and has a vertex at (0, 0) so it will only be in quadrant I and II. I'll provide a diagram showing this.
Confused on this so please help:
optimize the equation p = 2x + y using the constraints. what is the maximum?
choices:
a. 7
b. -1
c. 5
d. 13
The equation p=4+3y is maximised at (4,5) and the maximised value is 31.
Given equation p=4x+3y and constraints x>0,x<4, y<5.
We have to maximise the equation p=4x+3y with constraints x>0,x<4,y<5.
To find out the points we have to make graphs of the constraints first.
From the graph we have found that points are (0,0),(0,5),(4,0),(4,5).
The above points are common points of graphs of all constraints.
The value of equations are as under:
At (0,0) , p=4*0+3*0=0
At (0,5), p=4*0+3*5=15
At (4,0),p=4*4+3*0=16
At (4,5),p=4*4+3*5=16+15=31
Maximum value of p is 31 and that is for (4,5).
Hence the equation is maximised at (4,5) and the maximum value is 31.
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There are 26 prize tickets in a bowl, labeled A to Z. What is the probability that a prize ticket with a vowel will be chosen, not replaced, and then another prize ticket with a vowel will be chosen? Does this represent an independent or dependent event? Explain.
The probability that a prize ticket with a vowel will be chosen, not replaced, and then another prize ticket with a vowel will be chosen is 0.031 or 3.1%. So, this represents a dependent event.
What are independent and dependent events?Independent events are the events in which the outcome of one event does not affect the outcome of the other event.Dependent events are the events in which the outcome of one event affects the outcome of the other event.Calculation:It is given that there are 26 prize tickets in a bowl, labeled A to Z.
There are 5 vowels- A, E, I, O, U
So, the probability of choosing a ticket with a vowel will be - (5/26)
Another ticket with a vowel will be chosen without replacing the first ticket. Then, its probability is (4/25)
So, the required probability is,
(5/26) × (4/25) = 2/65 = 0.031
The event of choosing the first ticket with a vowel effect the event of choosing the second ticket with a vowel and vice-versa. So, this represents dependent events.
Therefore, the probability is 3.1 %.
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The local high school is hosting the last soccer game. They charged adults, x, 5 dollars to enter, and 3 dollars for students, y. It cost the school $300 to pay the referees for the game. The school wants to make a profit on the game, and 75 people attended. This is represented by the system:
5x + 3y > 300
x + y = 75
Which of the following points is a solution to the system?
(20, 15)
(25, 70)
(30, 45)
(40, 35)
IVE HEARD (30, 45) AND (40, 35). PLEASE HELP.
The correct answer is (40, 35) because by plugging in, 40 +35 = 75 and
(40 x 5) + (35 x 3) > 300
How to solve Word Problem ?Word problem can be solved by interpreting the problem into its best fit equation. The equation may be linear, quadratic or simultaneous equations.
Given that
5x + 3y > 300
x + y = 75
Let us first assume that 5x + 3y = 300. That is,
5x + 3y = 300
x + y = 75
Eliminate y by multiplying equation 2 by 3
5x + 3y = 300
3x + 3y = 225
2x = 75
x = 75/2
x = 37.5
Substitute x in equation 2
37.5 + y = 75
y = 75 - 37.5
y = 37.5
The correct answer is (40, 35) because 40 +35 = 75 and
(40 x 5) + (35 x 3) > 300
Therefore, the solution to the system is (40, 35)
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What is the slope of the line through (-1,8)(−1,8)left parenthesis, minus, 1, comma, 8, right parenthesis and (3,-4)(3,−4)left parenthesis, 3, comma, minus, 4, right parenthesis? Choose 1 answer: Choose 1 answer: (Choice A) A \dfrac13 3 1 start fraction, 1, divided by, 3, end fraction (Choice B) B 333 (Choice C) C -\dfrac13− 3 1 minus, start fraction, 1, divided by, 3, end fraction (Choice D) D -3−3
The slope of the line through the points is -3
How to determine the slope?The points are given as:
(-1, 8) and (3, -4)
The slope is calculated as:
m = (y2 - y1)/(x2 - x1)
So, we have:
m = (-4 - 8)/(3 + 1)
Evaluate the expression
m = -3
Hence, the slope of the line through the points is -3
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The slope of the line that passes through (-1, 8) and (3, -4) is: -3.
How to Find the Slope of a Line?Slope of a line (m) = change in y / change in x.
Given the points, (-1, 8) and (3, -4):
Slope (m) = (-4 - 8)/(3 - (-1))
Slope (m) = (-12)/(4)
Slope (m) = -3
Thus, the slope that passes through the given points is: -3.
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These cones are similar. Find the surface area of the smaller cone. Round to the nearest tenth. 3cm 2 cm. Help!!!
Answer:
33.3
Step-by-step explanation:
The scale factor is 2/3.
The ratio of the surface areas is the square of the scale factor, so the surface area of the smaller cone is 75(2/3)², which is about 33.3 cm²
What must be true for lines a and b to be parallel lines? Select two options.
Lines a and b are crossed by transversals c and d. The angles formed by lines a, c, and d, clockwise from top left, are (3 x minus 1) degrees, 2, blank, blank, blank, 1. The angles formed by lines b and c are blank, (4 x minus 10) degrees, blank, blank. The angles formed by lines b and d are 58 degrees, blank, blank, blank.
mAngle1 = (4 x minus 10) degrees
mAngle2 = 58Degrees
x = 20
(3 x minus 1) degrees equals = (4 x minus 10) degrees
Angle1 = 58
The expression that must be true for a to be parallel to b are mAngle2 = 58Degrees and <1 = 4x - 10
Lines and anglesA line is the shortest distance between two points and the point where two lines meet is known as an angle
From the figure shown
m<2 = 58 degrees (alternate exterior angle)
Since the sum of angles on a straight line is 180 degrees, hence;
3x-1+<2 + 4x - 10= 180
3x-1 + 58 + 4x - 10 =180
7x + 47 = 180
7x = 180- 47
7x = 133
x = 19
Hence the expression that must be true for a to be parallel to b are mAngle2 = 58Degrees and <1 = 4x - 10
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Answer:
angle 2=58 degrees
angle 1=4x-10 degrees
Step-by-step explanation:
can someone please help me?
answer choices:
A. sin (0)
B. cos (0)
C. sin (3/2)
D. cos (3/2)
E. sin ()
F. cos ()
Answer:
B, cos(0)=1
Step-by-step explanation:
cos(0)=1
Coordinate A is at point (1,0)
19. Since April 1, 1986 was a Tuesday, March,
1986 had? Mondays.
og
(A) 3
(B) 4
(C) 5
(D) 6
Answer:
Since April 1, 1986 was a Tuesday, March,
1986 had? Mondays.
og
the answer A