How does mercury differ from other metals?(1 point)

It does not conduct electricity.
It is not lustrous.
It is not solid under normal conditions.
It does not chemically react with other elements.

Answers

Answer 1

Answer:

It is not solid under normal conditions

Answer 2

Mercury differs from other metals as It is not solid under normal conditions. It is the only metal that is liquid at room temperature, therefore the correct answer is option C

What is the matter?

Anything which has mass and occupies spaces is known as matter, mainly there are four states of matter solid liquid gases, and plasma.

These different states of matter have different characteristics according to which they vary their volume and shape.

Because it is not solid under normal circumstances, mercury is different from other metals. Because it is the only metal that is liquid at room temperature,

Thus the correct answer is option C

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Related Questions

The speed of light in space is 3.00 x 10^8 m/s. The time for light from the sun to reach earth is 8mins and 20 seconds. Therefore, the distance from the Sun to Earth is

Select one:
A. 2.40 x 10^9 m
B. 8.64 x 10^12 m
C. 1.50 x 10^11
D. 2.25 x 10^9

Answers

Answer:

C. 1.50×10¹¹ m

Explanation:

First, convert the time to seconds.

8 min × (60 s/min) + 20 s = 500 s

Distance = speed × time

d = (3×10⁸ m/s) (500 s)

d = 1.50×10¹¹ m

The distance from the Sun to the Earth is 1.50 × 10¹¹. Speed is the distance travelled by an object in a particular time period. Thus, the correct option is C.

What is the Speed of light?

The speed of light in vacuum is commonly denoted by c. It is a universal physical constant. The speed of light (c) is exactly equal to 3.00 x 10⁸m/s (meter per second).

The speed of an object is the rate of change of position with respect to time. It is also defined as the distance covered by an object with respect to time. It can be calculated by dividing the distance travelled by an object by the time taken. It is a scalar quantity as it has only magnitude and no direction.

Speed = Distance / time

Distance = Speed × Time

Distance = 3.00 × 10⁸ × 500

Distance = 1500 × 10⁸

Distance =  1.50 × 10¹¹

Therefore, the correct option is C.

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Calculate the intensity of current flowing through a computer that consumes 180W and operates at 120 V.

A.)0,66 A
B.)12600 A
C.)1,5 A
D.)60 A

Answers

Answer:

C) 1.5 A

Explanation:

P = IV

180 W = I (120 V)

I = 1.5 A

what happen to the weight of a body when it is falling freely under the action of gravity?

Answers

Answer:

Explanation:

where W-weight, m-mass of the object and g-acceleration produced due to the earth's gravity. ... This happens because the normal reaction force exerted on the object in the lift is equal to zero, and normal force equals to mg, which in turn equals the weight of the object.

is iron and copper brittle​

Answers

Answer:

no

Explanation:

they are metal and there property is strong and hard

A 63 kg kg person starts traveling from rest down a waterslide 6.0 mm above the ground. At the bottom of the waterslide, it then curves upwards by 1.0 mm above the ground such that the person is consequently launched into the air. Ignoring friction, how fast is the person moving upon leaving the waterslide

Answers

Answer:

change waterslide according to question. and you are good to go. check photo for solve

The person moving with speed upon leaving the waterslide is equal to 0.313 m/s while ignoring the friction.

What is the law of conservation of energy?

If there is a loss of energy in any part of the system, there must be the same amount of a gain of energy in some other part of the isolated system.

Kinetic energy + Potential energy = constant

Therefore, the initial kinetic and potential energy of the person must be equal to the final kinetic and potential energy.

mgh₁ + mv₁²/2 = mgh₂ + mv₂²/2

gh₁ + v₁²/2 = gh₂ + v₂²/2

2gh₁ + v₁² = 2gh₂ + v₂²

2g(h₁ - h₂) = v₂² -  v₁²

[tex]v_2=\sqrt{2g(h_2-h_1) + v^2_1}[/tex]                                               .................(1)

Given, the mass of the person, m = 63 Kg

The initial speed of the person as at rest, v₁ = 0

Consider that the speed of the person while leaving the waterslide is v₂

The initial height of the person above the ground, h₁ = 6.0 mm

The height of the person leaving the waterslide, h₂= 1.0 mm

Substitute, the value of m, v₁, h₁ and h₂ in equation (1):

[tex]v_2 = \sqrt{2(9.8m/s^2)(6mm-1mm) + (0)^2}[/tex]

[tex]v_2 =\sqrt{2(9.8)\times 5 \times 10^{-3}} \;m/s[/tex]

[tex]v_2 =\sqrt{0.098}\; m/s[/tex]

v₂ = 0.313 m/s

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Please help me , I also have to show work on paper

Answers

Answer:

Choose B

Explanation:

Hope Can I help you

Two objects, one of mass m and the other of mass 2m, are dropped from the top of a building. If there is no air resistance, when they hit the ground A) both will have the same kinetic energy. B) the heavier one will have twice the kinetic energy of the lighter one. C) the heavier one will have four times the kinetic energy of the lighter one. D) the heavier one will have half the kinetic energy of the lighter one. E) the heavier one will have one-fourth the kinetic energy of the lighter one.

Answers

Answer:

option b

Explanation:

the heavier one will have twice the kinetic energy of the lighter one

The heavier one will have twice the kinetic energy of the lighter one. Hence, option (B) is correct.

Given data:

The mass of object 1 is, m.

The mass of object 2 is, 2m.

Here, the concept of kinetic energy is used. The kinetic energy of an object is the energy possessed by the object by virtue of its motion. Motion means something related with the speed.

And the mathematical expression for the kinetic energy is given as,

[tex]KE =\dfrac{1}{2}mv^{2}[/tex]

Here,

m is the mass of body.

v is the speed of body.

Now considering the kinetic energy for the two given objects as,

[tex]KE=\dfrac{1}{2}mv^{2}\\\\KE'=\dfrac{1}{2}(2m)v^{2}[/tex]

Comparing both the values of kinetic energies, we find that,

KE' = 2KE

Thus, we can conclude that the heavier one will have twice the kinetic energy of the lighter one. Hence, option (B) is correct.

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Which is the second step of the fusion process?
O
H+1H - ?H+e+ + v + energy
O 6(3H) +21_e) - He +24H) + energy + 2u
{H+1H He + energy
O
He He He + 1H+1H + energy

Answers

Answer:

The correct option is;

[tex]_{1}^{2}\textrm{He} + _{1}^{1}\textrm{H} \rightarrow _{3}^{2}\textrm{He} + energy[/tex]

Explanation:

The second step of the fusion process is the reaction (combination) where a Deuterium combines with a hydrogen to produce one helium 3, 3He, nucleus and a energy photon as follows;

[tex]_{1}^{2}\textrm{He} + _{1}^{1}\textrm{H} \rightarrow _{3}^{2}\textrm{He} +\gamma \ (energy)[/tex]

After which the produced Helium-3 combines to form the Helium nucleus an emit 2 protons

Steps 1 and 2 are take place two times (producing 26 MeV energy) before the step three (the combination of the formed helium-3) takes occurs.

Answer:

C on edge

Explanation:

Just did it and got it right :)

Light travels at a speed of 2.998*108 m/s. Light takes approximately 3.25 minutes to travel from the Sun to reach a planet. Calculate the distance from the Sun to this planet in meters. Give your answer to 0 decimal places.

Answers

Answer:

585×10⁸ m

Explanation:

Distance = rate × time

d = (2.998×10⁸ m/s) (3.25 min) (60 s/min)

d = 585×10⁸ m

Do cheese and chips good?

Answers

They good good smack, nachos, cheesy chips, chips and quest, cheese and chips ( ˘ω˘ )
Please mark brainliest my good cheesy sire

Define measurement and write its importance.​

Answers

Answer:

Measurement is the way humans define certain amounts of matter, and is expressed in various types of units respective to the type of matter or object being defined.

Explanation:

Measurement is extremely important because it helps one another understand how much of something is needed to accomplish something. If no method existed to define the specific amount needed, we would simply mess delicate operations up and machines, even simple recipes, would fail.

why audiotape, credit cards and videotape not placed closed to a strong magnet

Answers

Answer:

There are many possible causes of magnetic defects in credit cards. But there are two direct causes: 1. Close to a strong magnet 2. Damage from scratches or wear Even if used properly it can cause magnetic defects. But if used incorrectly, it can cause an immediate relapse. If you have never used a credit card due to magnetic defects, check what will cause magnetic defects and for example credit cardMagnetic stripe cards, such as credit cards and cash cards, are more likely to cause magnetic field defects if brought near magnetically generating objects such as magnets. Although exposure to strong magnets does not necessarily lead to failure. However, it should be kept away from objects that may cause magnetic field defects.

Explanation:

Magnetic fields can erase or distort the data stored on these items. The correct option is A.

Magnetic media are used to store information in a magnetic format on audiotapes, credit cards, and videotapes. They may have their magnetic patterns and particle alignment disturbed if they are placed close to a powerful magnet.

The stored data may be lost or damaged as a result. For instance, credit cards' magnetic stripes may become illegible, audiotapes may lose their sound quality or possibly be completely erased, and videotapes may have distorted or scrambled imagery and audio.

To preserve the accuracy and utility of the data they contain, it is crucial to keep these things away from strong magnetic fields.

Thus, the correct option is A.

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Your question seems incomplete, the probable complete question is:

Why audiotape, credit cards and videotape not placed closed to a strong magnet

A. Magnetic fields can erase or distort the data stored on these items.

B. Magnetic fields can cause these items to become permanently demagnetized.

C. Magnetic fields can cause these items to generate excess heat and potentially catch fire.

D. Magnetic fields can cause these items to emit harmful radiation.

You have a cup with 50cm filled with water. How much pressure will the water act on the bottom of the cup? The density of water is 1000kg/m^3 and g = 10N/kg

Answers

Answer:

5000 N/m².

Explanation:

The following data were obtained from the question:

Density (d) = 1000 kg/m³

Acceleration due to gravity (g) = 10 N/kg

Height (h) = 50 cm = 50/100 = 0.5 m

Pressure (P) =.?

Pressure is related to density and height by the following equation:

P = dgh

Where

P is the pressure.

d is the density.

g is the acceleration due to gravity.

h is the height.

With the above formula, we can obtain the pressure at the bottom of the cup as follow:

P = dgh

P = 1000 x 10 x 0.5

P = 5000 N/m²

Therefore, the pressure at bottom of the cup is 5000 N/m².

HELP ME PLEASEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE A student uses a spring scale attached to a textbook to compare the static and kinetic friction between the textbook and the top of a lab table. If the scale measures 1,580 g while the student is pulling the sliding book along the table, which reading on the scale could have been possible at the moment the student overcame the static friction? 1,140 g 1,580 g 820 g 1,860 g

Answers

Answer:

1,860

Explanation:

Your help will really be great plz help me

Answers

5 N

Archimedes' Principle

25 N

A 2-kg cart, traveling on a horizontal air track with a speed of 3m/s, collides with a stationary 4-kg cart. The carts stick together. The impulse exerted by one cart on the other has a magnitude of

Answers

Answer:

The impulse exerted by one cart on the other has a magnitude of 4 N.s.

Explanation:

Given;

mass of the first cart, m₁ = 2 kg

initial speed of the first car, u₁ = 3 m/s

mass of the second cart, m₂ = 4 kg

initial speed of the second cart, u₂ = 0

Let the final speed of both carts = v, since they stick together after collision.

Apply the principle of conservation of momentum to determine v

m₁u₁ + m₂u₂ = v(m₁ + m₂)

2 x 3 + 0 = v(2 + 4)

6 = 6v

v = 1 m/s

Impulse is given by;

I = ft = mΔv = m(

The impulse exerted by the first cart on the second cart is given;

I = 2 (3 -1 )

I = 4 N.s

The impulse exerted by the second cart on the first cart is given;

I = 4(0-1)

I = - 4 N.s (equal in magnitude but opposite in direction to the impulse exerted by the first).

Therefore, the impulse exerted by one cart on the other has a magnitude of 4 N.s.

Một bóng đèn có hiệu điện thế định mức là 110V. Đặt vào hai đầu bóng đèn các hiệu điện thế sau đây, hỏi trường hợp nào dây tóc của đèn sẽ đứt?

Answers

Answer:

fhaiisjrbekxkrkebxnsiiwj4bnds

A rifle bullet with mass 8.00 g and initial horizontal velocity 280 m/s strikes and embeds itself in a block with mass 0.992 kg that rests on a frictionless surface and is attached to one end of an ideal spring. The other end of the spring is attached to the wall. The impact compresses the spring a maximum distance of 15.0 cm. After the impact, the block moves in SHM. Calculate the period of this motion.

Answers

Answer:

0.4113772 s

Explanation:

Given the following :

Mass of bullet (m1) = 8g = 0.008kg

Initial horizontal Velocity (u1) = 280m/s

Mass of block (m2) = 0.992kg

Maxumum distance (x) = 15cm = 0.15m

Recall;

Period (T) = 2π√(m/k)

According to the law of conservation of momentum : (inelastic Collison)

m1 * u1 = (m1 + m2) * v

Where v is the final Velocity of the colliding bodies

0.008 * 280 = (0.008 + 0.992) * v

2.24 = 1 * v

v = 2.24m/s

K. E = P. E

K. E = 0.5mv^2

P.E = 0.5kx^2

0.5(0.992 + 0.008)*2.24^2 = 0.5*k*(0.15)^2

0.5*1*5.0176 = 0.5*k*0.0225

2.5088 = 0.01125k

k = 2.5088 / 0.01125

k = 223.00444 N/m

Therefore,

Period (T) = 2π√(m/k)

T = 2π√(0.992+0.008) / 233.0444

T = 2π√0.0042910

T = 2π * 0.0655059

T = 0.4113772 s

The period of the simple harmonic motion (SHM) is 0.42 s.

The given parameters;

mass of the bullet, m₁ = 8 g = 0.008 kginitial horizontal velocity of the bullet, u = 280 m/smass of the block, m₂ = 0.992 kginitial velocity of block, u₂ = 0extension of the spring, x = 15 cm = 0.15 m

The final velocity of the system after the impact is calculated as follows;

[tex]m_1 u_1 + m_2u_2 = v(m_1 + m_2)\\\\0.008(280) \ + \ 0.992(0) = v(0.008 \ + \ 0.992)\\\\2.24 = v(1) \\\\v = 2.24 \ m/s[/tex]

The spring constant is calculated as follows;

[tex]\frac{1}{2} kx^2 = \frac{1}{2} mv^2\\\\k = \frac{mv^2}{x^2} \\\\k = \frac{(0.008 + 0.992))\times 2.24^2}{(0.15)^2} \\\\k = 223 \ N/m[/tex]

The angular speed of the simple harmonic motion (SHM) is calculated as follows;

[tex]\omega = \sqrt{\frac{k}{m} } \\\\\omega = \sqrt{\frac{223}{(0.008 + 0.992)} }\\\\\omega = 14.933 \ rad/s[/tex]

The period of the oscillation is calculated as follows;

[tex]T = \frac{2\pi }{\omega} \\\\T = \frac{2\pi }{14.933} \\\\T = 0.42 \ s[/tex]

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Each corner of a right-angled triangle is occupied by identical point charges "A", "B", and "C" respectively. Draw a sketch of this arrangement. "A" exerts force F on "B". An equal force F is exerted by "C" on "B" (/_ ABC= 90 degrees). Determine an expression for the net force on "B".

Answers

Answer:

Fnet = F√2

Fnet = kq²/r² √2

Explanation:

A exerts a force F on B, and C exerts an equal force F on B perpendicular to that.  The net force can be found with Pythagorean theorem:

Fnet = √(F² + F²)

Fnet = F√2

The force between two charges particles is:

F = k q₁ q₂ / r²

where

k is Coulomb's constant, q₁ and q₂ are the charges, and r is the distance between the charges.

If we say the charge of each particle is q, then:

F = kq²/r²

Substituting:

Fnet = kq²/r² √2

what is acceleration produced by a force of 12 newton exerted on an object of mass 3kg​

Answers

Answer:

a=F/m

a=12N/3kg  (here newton can be written as kgm/s^2 so kg will be cancelled)

a=4m/s^2

Explanation:


A baseball weights 1429 (0.142kg) were striked with force of 120N. Calculate its acceleration at
that time. Include the correct unit with your answer. Include one decimal place.

Answers

Answer:

a=845.07 m/s2

Explanation:

m=0.142kg

F=120N

a=?

F=m*a /:m

a=F/m

a=120N/0.142kg

a=845,07m/s2

Answer:

a = 845.07 m/s²

Explanation:

As we know ,

as per newton's 2nd law:-

F = ma

therefore

a = F/m

given:

a = ?

F = 120N

m = 0.142 kg

procedure:-

a = 120/0.142

therefore :

a = 845.07 m/s²

write down the reading shown on the instrument above in units of the instrument

Answers

Answer:

The reading of the vernier calliper is 3.93 mm

Explanation:

The given instrument is a micrometer screw gauge that has a main scale reading and a vernier scale reading

The the question, we have;

The individual divisions of the main scale = 0.5 mm

The reading on the main scale = 3.5 mm

The reading on the vernier scale = 43

The accuracy of the vernier caliper = 0.01

Reading on the vernier scale multiplied by the accuracy of the vernier caliper = 43 × 0.01 = 0.43 mm

The reading of the micrometer screw gauge = The reading on the main scale + Reading on the vernier scale multiplied by the accuracy of the vernier caliper

Therefore, the reading of the micrometer screw gauge = 3.5 + 0.43= 3.93 mm

The reading of the vernier calliper = 3.93 mm.

A series combination of 12 Ω and 3 Ω is connected in parallel with another series combination of 6 Ω and 3 Ω. If a potential difference of 4 V is applied across it find the i) current is drawn from the battery ii) current through 12 Ω resistor (iii)potential difference across 6 Ω resistor?

Answers

Answer:

a) 0.73A

b) 0.23A

c) 2.76V

Explanation:

We need to first resolve the two resistors in series. The resistors in series are

12 Ω and 3 Ω  AND 6 Ω and 3 Ω

For  12 Ω and 3 Ω in series, total effective resistance =  12 Ω + 3 Ω = 15 Ω

For  6 Ω and 3 Ω in series, total effective resistance =  6 Ω + 3 Ω = 9 Ω

Since the equivalent series resistors i.e 15Ω ND 9Ω are connected in parallel, the total effective resistance Rt will be expressed as;

1/Rt = 1/15+1/9

1/Rt = (3+5)/45

1/Rt = 8/45

Rt = 45/8 Ω

a) If a potential difference of 4 V is applied across it, the total current I in the circuit can be derives using the ohms law.

According to the law E = IRt

Given E = 4V, Rt = 45/8

I = E/Rt

I = 4/(45/8)

I = 4 * 8/45

I = 32/45

I = 0.73A

Hence, the current drawn from the battery is 0.73A

b) Before we can calculate the current in the 12Ω resistor, we need to calculate the current in the equivalent resistance of 15Ω(sum of 12Ω and 3Ω)

Current in the 15Ω resistor = Voltage across the 15Ω resistor/Resistance

Current in the 15Ω resistor = 4/15

Current in the 15Ω resistor = 0.27A

Since the same current flows in a series connected resistors, hence the correct in the 12ohms resistor is also 0.27A.

c) Before we can calculate the pd across the 6ohms resistor, we need to know the voltage across the effective resistance of 9ohms(6ohms+3ohms). The pd across the 9ohm resistance will be the same as the source voltage i.e 4Volts.

We will need to share this 4volts between the 6ohms and the 3ohms using ohms law.

According to the law, V = IR

For the 6ohms resistor, voltage across it will be;

V = (0.73-0.27)×6

V= 0.46×6

V = 2.76Volts.

Hence the voltage across the 6ohms resistor is 2.76V.

Need help with this!!!
15 points!!!!

Answers

Answer:

// EDU HACK REDDIT EDITON //

if (running == null) {

var running = null; console.log("Program Loading...");

var iframe = document.getElementById("stageFrame");

for (i = 0; i < 1; i++) {

 setInterval(function() {

  if (running == null) { running = true; console.log('Program Loaded! Enjoy!') }

  if (iframe.contentWindow.document.getElementsByClassName('FrameRight') != null) { iframe.contentWindow.document.getElementsByClassName('FrameRight')[0].onclick(); }

  if (iframe.contentWindow.document.getElementById("invis-o-div") != null) { iframe.contentWindow.document.getElementById("invis-o-div").remove(); }

 },1000);

}

} else {

console.log("Program already running!")

}

Explanation:

Identifying Maller
In your own words, describe how matter is identified.

Answers

Answer:

Matter can be identified through its properties. One clue to helps us identify matter is magnetism. Magnetism is the ability of a material to be attracted by a magnet. Only certain materials are attracted to magnets, like iron, nickel, and cobalt.

Explanation:

we can identify matter by:  physical properties  and

chemical properties

The image formed is 0.25 times the size of the object and 10 cm behind the pinhole. If the height of image on screen is 6 cm what is the distance of the object from the screen?

Answers

Answer:

40 cm

Explanation:

Magnification of a pinhole camera is given by;

M= height of image/ height of object

Since;

M= 0.25

Height of image = 6cm

Height of object = height of image / M

Height of object = 6/0.25 = 24 cm

Height of image/ height of object = distance of image from pinhole/ distance of object from pinhole

Since the distance of image from pinhole = 10cm

Let the distance of object from pinhole be x

6/24 = 10/x

6x = 240

x= 240/6

x = 40 cm

the unit of energy is a derived unit​

Answers

Explanation:

Hi, there!!

Energy is defined as the capacity or ability to do work. It's SI unit is Joule.

here,

Joule = (kg×m×m)/(s×s)

= kg×m^2/s^2.

Therefore, the derived unit is kg.m^2 by s^2.

Hope it helps...

A construction worker uses an electrical device to attract fallen nails and sharp objects
from a construction site. What is causing the attraction of the metal objects?
O An electrical wave oscillating perpendicular to the electrical device.
O An electrical charge radiating perpendicular to the wire
O Amagnetic wave radiating perpendicular to an electrical device
O A magnetic wave and electrical current moving in opposite directions

Answers

Answer:

is the last one, a magnetic wave and electrical current moving in opposite directions

Explanation:

opposite directions always attract in magnetic waves and fields

An object accelerates to a velocity of 230 m/s over a time of 2.5 s. The acceleration it experienced was 42 m/s2. What was its initial velocity?

Answers

Answer:

230 = x + 105

x= 125

Explanation:

v = v0 + at

If 5 complete oscillations of a sound wave pass through a point in 0.5 s and the speed of sound was recorded to be 10 m/s, then find the wavelength of the sound.

Answers

Answer:

Wavelength = 1 meters

Explanation:

Given that,

Number of oscillations is 5

It passes through a point in 0.5 s

The speed of sound was recorded to be 10 m/s.

We need to find the wavelength of the sound.

Firstly, we will find frequency of this wave. Total no of oscillations per unit time is called frequency. So,

[tex]f=\dfrac{5}{0.5}\\\\f=10\ Hz[/tex]

Now the speed of wave in terms of wavelength and frequency is given by :

[tex]v=f\lambda[/tex]

Here, [tex]\lambda[/tex] = wavelength

[tex]\lambda=\dfrac{v}{f}\\\\\lambda=\dfrac{10\ m/s}{10\ Hz}\\\\\lambda=1\ m[/tex]

So, the wavelength of the sound is 1 meters.

Other Questions
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