Answer: 14.41*10^2 m/s
Explanation:
let, V be the escape velocity of the moon.
M be the mass of the earth.
r be the distance between the moon and the earth.
G be the universal gravitational constant.
And G = 6.67428*10^-11 m^3kg^-1 s^-2
here, given in the question that
The earth has a mass of 5.98*10^24 kg.
so, M = 5.98*10^24 kg.
And the distance from the earth to the moon is 3.84*10^8 m.
so, r = 3.84*10^8 m.
now, we know,
V = √2GM/r
V = √(2 * 6.67428*10^-11* 5.98 * 10^24 )/ 3.84*10^8
V = √79.82*10^13/3.84*10^8
V = √20.78*10^5
V = 14.41*10^2 m/s
What are the rock forming minerals and its meaning.
Answer:
There are almost 5000 known mineral species, yet the vast majority of rocks are formed from combinations of a few common minerals, referred to as “rock-forming minerals”.
If the current leaving the cell in a parallel circuit is 0.3 A, what is the sum of the currents through all the branches in the parallel circuit?
The sum of the currents through all the branches in the parallel circuit is 0.3 A.
What is a parallel circuit?A parallel circuit is a type of circuit which comprises branches so that the current divides and only part of it flows through any branch.
The voltage, or potential difference, across each branch of a parallel circuit is the same, but the currents may vary.
The sum of the current flowing in any branch of a parallel circuit is determined by applying Ohms law as follows;
I = V/R₁ + V/R₂ + V/R₃
where;
V is the voltage across the circuitR₁ is the resistance of the first component of the circuitR₂ is the resistance of the second component of the circuitR₃ is the resistance of the third component of the circuitThus, If the current leaving the cell in a parallel circuit is 0.3 A, then it implies that the resultant current or total current in the parallel circuit is 0.3 A.
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If your actual mechanical advantage is 70 J, and the theoretical is 100 J, what is your percent efficiency?
Charlie flew from phoenix to Tucson, a distance of 120 miles. the trip there took one hour. he then returned back to Phoenix in 2 hours. what was his total distance for the entire trip?
0 miles
120 miles
240 miles
360 miles
Planets A and B have the same mass, but planet
is nait the
Which statement correctly explains the
weight you would experience on each
planet?
O A. You would weigh less on planet A because the distance between
you and the planet's center of gravity would be smaller.
•
B. You would weigh the same on both planets because the masses
of the planets are the same.
• C.
You would weigh more on planet A because the distance between
you and the planet's of center of gravity would be smaller.
both planets because your mass
D. You would weigh the same on
would be the same on both.
b
Statement is accurate C. You would weight more on planet A because the distance between you and the planet's of center of gravity would be smaller.
What is the proper statement's justification?You would weigh less on planet A due to a closer proximity to the planet's center of gravity, which is the statement that best represents your weight on each planet.
According to Newton's rule of universal gravitation, "the force of gravity between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distances between them,"
Given that weight is a function of both mass and gravity, objects on planets with stronger gravitational pull will have heavier masses.
The weight will be lighter since there is less space between the individual and the planet's center.
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An object with a mass of 33g and a volume of 39cm^3 is placed in a liquid with a density of 1.25 g/cm^3. Find the volume of the part of the object that is NOT submerged in the liquid. Give your answer in cm^3 and with 3 significant figures.
Answer:
V₂ = 12.6 cm³ - volume of the NOT immersed part:
Explanation:
Given:
m = 33 g
V = 39 cm³
ρ = 1.25 g/cm³
____________
V₂ - ?
Gravity:
F = m·g
Strength of Archimedes:
Fa = ρ·g·V₁
V1 - the volume of the submerged
The object is floating, so:
F = Fa
m·g = ρ·g·V₁
m = ρ·V₁
V₁ = m / ρ = 33 / 1.25 ≈ 26,4 cm³
V₂ - volume of the NOT immersed part:
V₂ = V - V₁ = 39 - 26.4 = 12.6 cm³
A feather is dropped onto the surface of the moon. How far will the feather have fallen if it reaches the surface in 9.00 seconds? Given: g on moon = -1.63 meters/second2
[tex]66.015 \mathrm{~m}[/tex] will the feather have fallen if it reaches the surface in 9.00 seconds.
Given:
[tex]$$\begin{aligned}&t=9 \mathrm{~s} \\&a=1.63 \mathrm{~m} / \mathrm{s}^2\end{aligned}$$[/tex]
The distance traveled by the feather onto the surface of the moon can be computed using the following equation:
[tex]d=\frac{1}{2} a t^2=(0.5)\left(1.63 \mathrm{~m} / \mathrm{s}^2\right)(9 \mathrm{~s})^2=66.015 \mathrm{~m}$$[/tex]
Kinematics in classical mechanics explains the motion of a specific item in a system. We're looking at the motion of a feather on the moon's surface.
Kinematics is the study of mechanical points, bodies, and systems in their motion without regard for their related physical qualities or the forces acting on them. The discipline is known as geometry of motion, and it mathematically describes these motions using algebra.
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A 32.0 kg crate is initially moving with a velocity that has magnitude 3.58 m/s in a direction 37.0 ∘ west of north. How much work must be done on the crate to change its velocity to 5.10 m/s in a direction 63.0 ∘ south of east?
The amount of work done on the crate to change its velocity is 211.1 J.
What is the work done on the crate to change its velocity?
The work done on the crate to change its velocity is calculated by applying the principle of conservation of energy as shown below.
Applying work-energy theorem, the work done in changing the velocity of the crate is equal to the change in kinetic energy of the crate as shown below;
W = ΔK.E
W = ¹/₂m(v₂² - v₁²)
where;
m is mass of the cratev₁ is the initial velocity of the cratev₂ is the final velocity of the crateW = ¹/₂m(v₂² - v₁²)
W = ¹/₂(32)(5.1² - 3.58²)
W = 211.1 J
Thus, the amount of work done on the crate to change its velocity from 3.58 m/s at 37.0 ∘ west of north to 5.10 m/s in a direction 63.0 ∘ south of east, is based on the principle of conservation of energy.
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What happens to Fg if both masses double
A. Reduced by 1/2
B. increases by 2
C. Reduces by 1/4
D. Increases by 4
If both masses double, FG increases by 4.
What is Gravitational Force?
Gravity is a fundamental interaction that all objects with mass or energy experience due to its Latin root, gravitas, meaning "weight". Approximately 1038 times weaker than that of the strong interaction, 1036 times weaker than that of the electromagnetic force, and 10^29 times weaker than the weak interaction, gravity is by far the weakest of the four fundamental interactions. The level of subatomic particles is therefore unaffected by it significantly. The motion of planets, stars, galaxies, or even light is controlled by gravity, which is the most important interaction between objects just at macroscopic level.
What happens to Fg if both masses double?
The gravitational force increases by 4, when both the masses double.
F = Gm1m2/r2
If both masses double, then
m1 = 2m1 , m2 = 2m2
F = G(2m12m2)/r2 ⟹
F = 4F
Thus gravitational force becomes 4 times.
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A hiker walks due East for a distance of 6 km
from her base camp. On the 2nd day, she covered
8km, North. On the 3rd day she walks for 4 km
South and found a cave. Determine her resultant
displacement between the base camp and the
cave.
Resultant displacement between the base camp and the cave will be 7.211 km
Displacement is a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.
Her resultant displacement can be calculated using Pythagoras theorem
[tex]H^{2} = P^{2} + B^{2}[/tex]
= [tex]4^{2} + 6^{2}[/tex]
= 52
H = [tex]\sqrt{52}[/tex] = 7.211 km
Resultant displacement between the base camp and the cave will be 7.211 km
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What are the causes of different falls in the air?
A, Highlight drop drop
B, The Wind Blows
C, of object
D, Air resistance
D. air resistance
Hope it helps
A ball at the end of a string of length 2m rotates at a constant speed in a horizontal circle. It makes 7 rev/s.
What is the period of the ball’s motion? Answer in units of s.
The period of the ball's motion is 0.142 s and the frequency of the motion is 7 Hz.
What is the period of the ball's motion?The period of the ball's motion is calculated by applying the following kinematic equation as shown below.
v = 2πr/T
ωr = 2πr/T
ω = 2π/T
T = 2π/ω
where;
T is the period of the ball's motionω is the angular speed of the ballThe angular speed of the ball = 7 rev/s = 7 rev/s x 2π rad/rev = 14π rad/s
T = 2π/14π
T = 1/7 s = 0.142 s
The frequency of the ball's motion is the inverse of the period of the motion and can be calculated as follows;
f = 1/T
f = (1) / (1/7) = 7 Hz
Thus, the period of the ball's motion is determined from the angular speed of the ball while the frequency of the ball's motion is the reciprocal of the period of the motion.
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Two wires are 16 m and 24 m long. The wires are to be cut into pieces of equal length. a) Find the maximum length (in m) of each piece. b) What is the total number of such pieces formed from the two wires?
Answer:
A. The maximum is 8cm. B. 5 pieces of wire.
Explanation:
To find each pieces' length we need to find what can divide both wires = 8cm
A. The maximum is 8cm.
The amount of pieces = 16m/8m = 2 pieces and 24m/8m = 3 pieces. 2 pieces + 3 pieces = 5 pieces of wire.
B. 5 pieces of wire.
4. Ebo throws the ball again at an initial velocity of 18 m/s but this time at an angle of 53° to the ground. a) Work out the velocity in component vector form. b) Why will the ball spend a longer time in the air than it did before. c) Calculate the range of the ball.
16.52 m/s is the velocity and vcosθ is the velocity in component vector form.
velocity in vector form= vcosθ
vector form= vcosθ
vector form=18cos53
v=16.52 m/s
"The rate at which an item changes its location" is described by a vector number called velocity. Imagine someone walking quickly, one step forward, one step back, and starting each step from the same location. Velocity is a vector quantity. Therefore, velocity is cognizant of direction. The direction must be taken into account when determining an object's velocity. A velocity of 55 miles per hour is not sufficient information. It is necessary to account for the direction in order to accurately describe the object's velocity. Simply put, the direction of the velocity vector represents the motion of the object.
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A 50.0-kilogram cheetah has a kinetic energy of 18000J How fast is the cheetah running ? ( Hint : Rearrange the equation to solve for v .)
I found that people say it’s 36 but there is no explanation for it
Answer:
Explanation:
here take kinetic energy =1/2×m×v²
m=50.0-kilogram (given)
kinetic energy=18000J (given)
now by taking the given values we get v²=(2×18000)/50
⇒v²=720
⇒v=26.8328m/s
done!
Which of the following is not one of the rules that must be followed regarding animal research? A. Animal research must have a clear scientific purpose. B. Animal research can acquire its animals illegally. C. Animal research must provide humane care and housing. D. Animal research must ensure the least amount of suffering possible. Please select the best answer from the choices provided A B C D
On research on animals they must given proper care and housing. And the purpose of the research must have a scientific reason. Thus option B is correct.
What is animal research?Animal research includes various scientific investigation on animals such as testing various doses of some drugs, effect of various chemicals, level of toxicity of some compounds etc.
According to the research ethics, no animals can be used to conduct any unscientific works. There must be a scientific purpose which is very important to conduct any animal research.
If any animals irrespective of its nature,it must be provided proper care, food and housing. No harmful things must be there which make them more suffering. Hence, option B is correct.
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A 60km is suspended from two cables which makes 30° and 45° angle with the vertical. Determine the tension in each string.
The tension in each string if a 60 kg is suspended from two cables which makes 30° and 45° angle with the vertical is 429.2 N to the left and 302.25 N to the right.
m = 60 kg
Resolving the tension force of 30° string into its horizontal and vertical components
Tx = T1 sin θ
Tx = T1 sin 30°
Tx = 0.5 T1
Ty = T1 cos θ
Ty = T1 cos 30°
Ty = 0.87 T1
Resolving the tension force of 45° string into its horizontal and vertical components
Tx = T2 sin θ
Tx = T2 sin 45°
Tx = 0.71 T2
Ty = T2 cos θ
Ty = T2 cos 45°
Ty = 0.71 T2
∑Fx = 0
- 0.5 T1 + 0.71 T2 = 0 → ( 1 )
∑Fy = 0
0.87 T1 + 0.71 T2 - m g = 0
0.87 T1 + 0.71 T2 - ( 60 * 9.8 ) = 0
0.87 T1 + 0.71 T2 - 588 = 0 → ( 2 )
( 2 ) - ( 1 ),
1.37 T1 - 588 = 0
T1 = 588 / 1.37
T1 = 429.2 N
Sub T1 in ( 1 ),
( - 0.5 * 429.2 ) + 0.71 T2 = 0
- 214.6 + 0.71 T2 = 0
T2 = 214.6 / 0.71
T2 = 302.25 N
Therefore, the tension in each string is 429.2 N to the left and 302.25 N to the right.
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In Graph C above, which line(s) shows an object that has a constant
velocity?
Answer:
it's D that has a constant velocity
The best graph to use if I want to compare the price of six different cars would be a
The best graph to use if I want to compare the price of six different cars would be a bar graph
A bar graph is a graphical representation of the given data . It uses bars that extend to different heights to depict value .
Bar graphs are used to compare different type of things between different groups or to see changes over a period of time. Hence , bar graph will fits the best if one want to compare the price of six different cars .
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A car increases its velocity from 0m/s to 14 m/s in 2 seconds
answer -
7 m/s^2
Explanation:
it goes 7m/s 14 / 2 = 7
Help on solving this single logarithm
log 8 + log 16 - log 2 = log64, In order to get another number, a number should be raised to a certain power, which is known as a logarithm.
The correct answer is A
Describe a logarithm.A number must be increased to a specific power, or logarithm, in order to obtain another number. For additional information on exponents, visit Figure 3.3 of this Math Review. As an example, the base 10 logarithm of the number ten raised to the power of two two is two, or log 100, which equals two.
What does a number's log mean?Exponentiation is a mathematical operation, and the logarithm, simply log, is its inverse. In other words, the log of a number is the value that a fixed base must be increased to in order to produce the value. Although technically any base can be used, the term "log" often suggests that base 10 is being used.
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A .50 kg mass attached to an ideal spring of spring constant 80N/c oscillate on horizontal frictionless surface , the mechenical energy is .12j , the greatest energy from y to x is
The greatest energy or the greatest extension from its equilibrium positions is equal to 0.12 J.
What is mechanical energy?Mechanical energy is the sum of potential energy and kinetic energy that is used to do work. Mechanical energy defines the energy of a system because of its motion or position.
The total mechanical energy is conserved as we know the energy can neither be created nor destroyed. The mechanical energy of a system can only be changed from one form to another whenever the forces used to do work are conservative in nature.
The energy is stored in the form of potential energy in a compressed string. If the elastic potential energy is changed into kinetic energy as it is used to accelerate the mass.
The total mechanical energy required to compress the spring is the maximum amount of elastic potential energy stored in the spring. The greatest energy of the spring will be at the maximum displacement. Therefore, the spring will have the greatest potential energy at equilibrium positions equal to 0.12 J.
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Which one of the following is true of centrifugal force?
Centrifugal force is a fictional force.
Centrifugal force is a real force.
Centrifugal force pulls in a circular motion.
Centrifugal force causes objects moving in a circular path to move in.
Answer:
a is answer
Explanation:
centrifugal force, a fictitious force, peculiar to a particle moving on a circular path, that has the same magnitude and dimensions as the force that keeps the particle on its circular path (the centripetal force) but points in the opposite direction.
please help
help having issues with the problem
Answer:
2 m/s²
Explanation:
You want the acceleration produced by a force on 14 kg if that same force produces an acceleration of 7 m/s² when acting on a mass of 4 kg.
Inverse proportionFor the same force, the acceleration is inversely proportional to the mass. In this problem, the mass increases from 4 kg to 14 kg, a factor of 14/4 = 7/2.
The acceleration will change by a factor that is the inverse of this: 2/7.
acceleration of 14 kg = (7 m/s²) × (2/7) = 2 m/s²
Two small plastic spheres having positive electrical charges are given. When they are 60.00cm apart, the repulsive force between them has the magnitude 0.250N.calculate the charge on each sphere
Answer:
3.16 × 10‐⁶
Explanation:
through coulomb's law
the force of attraction or repulsion of charges is given by the relation
F = k.q1.q2/r²
where your k = 9 × 10⁹
Answer:
Charge 3.16 mkC microcoulomb
Explanation:
Given:
q₁ = q₂ = q - Electrical charges
r = 60.00 sm = 0.60 m - Distance between charges
F = 0.250 N - Repulsive force between charges
___________________
q - ?
F = k·q₁·q₂ / r² = k·q·q / r² = k·q² / r²
Charge:
q = √ (F·r² / k )
q = r·√ (F / k )
q = 0.60· √ (0.250 / 9·10⁹) ≈ 3.16·10⁻⁶ C or:
q = 3.16 mkC (microcoulomb)
Nabil wants to work out the density of a pebble. He has a displacement can and a beaker. What other piece of equipment will he need?
In order to determine the density of the pebble, Nabil requires a balance to measure the mass of the pebble.
What is the density of a substance?The density of a substance is the measure of how tightly-packed the particles in the substance are.
Density is the ratio of the mass and volume of the substance.
Density = mass/volumeTo determine the density of a substance, the mass of the substance is measured with a balance and the volume of the substance if it is solid is measured using a displacement can and a beaker.
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A tennis ball with a mass of 0.2 kg is thrown upwards from the ground at a velocity of 30 m/s. What
is the height of the ball when it has a velocity of 20 m/s?
The height of the ball when it has a velocity of 20 m/s is 45m.
What is mass?
It is the most fundamental feature of matter and one of the fundamental quantities in Physics. Mass can be defined as the amount of matter in a body. Kilogram is the SI unit of mass (kg).
It should be noted that a body's mass does not alter with time. Only in severe instances where a massive amount of energy is provided or removed from the body. In a nuclear reaction, for example, a tiny bit of matter is turned into a massive amount of energy, reducing the mass of the substance.
Given Initial velocity of ball, u=30 m/s
Let the maximum height reached and time taken to reach that height be H and t respectively.
Assumption: g=9.8 m/s2
holds true (maximum height reached is small compared to the radius of earth)
30/g=30/9.8=3 seconds
as the time taken to reach max height.
h(3)=-4.9(3²)+30(3)
=90–45
=45m
The height of the ball when it has a velocity of 20 m/s is 45m.
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Brooke is learning about electronic devices that use electric current to encode information. She learns that when a person speaks into the microphone of a telephone, the sound wave generated by the person’s voice is changed into an electronic signal. This electronic signal is then transmitted to another telephone where it is converted back to a sound wave so the other person can hear the voice. The sound wave is encoded by varying the voltage of the electronic signal. Brooke learns that the voltage can be changed in two ways, resulting in two types of electronic signals: analog and digital. Figure 1 and Figure 2 represent these two types of signals.
Identify the type of signal represented by each figure. Explain your reasoning.
The signals in this problem are classified as follows:
Figure 1: Digital signal.Figure 2: Analog signal.What are analog and digital signals?Analog signals are signals that are continuous in both domain and range, meaning that it can assume decimal values, hence it's graph is represented by a continuous curve.
Digital signals are signals that are discrete in both domain and range, meaning that it assumes only integer values, hence it's graph is composed by pulses.
Hence the classification of the signals for each figure in this problem are given as follows:
Figure 1: Digital signal, as the graph is composed only by pulses.Figure 2: Analog signal, as the graph is represented by the continuous and oscillating curve.More can be learned about analog and digital signals at https://brainly.com/question/22858440
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Please help! I don't understand how to do this!
A babysitter pushing a stroller starts from rest and accelerates uniformly at a rate of 0.778 m/s^2. What is the velocity of the stroller after it has traveled 5.54 m?
A babysitter pushing a stroller starts from rest and accelerates uniformly at a rate of 0.778 m/s^2. The velocity of the stroller after it has traveled 5.54 m will be 2.94 m/s
acceleration = 0.778 [tex]m/s^{2}[/tex]
distance = 5.54 m
initial velocity = 0
velocity of the stroller after it has traveled 5.54 m = ?
2as = [tex]v^{2} - u^{2}[/tex]
2 * 0.778 * 5.54 = [tex]v^{2}[/tex] - 0
v = 2.94 m/s
The velocity of the stroller after it has traveled 5.54 m will be 2.94 m/s
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A turtle with a mass of 28.59 kg starts from rest and is pushed to the right on an ice rink upside down on its shell (he loves it I promise). He reaches the opposite end and ends up travelling at 5.18 m/s which takes 37.80 s. What would be the net force acting on the turtle?
The net force acting on the turtle would be 3.92N.
What is net force?
This is referred to as the total forces acting on an object.
Formula for calculating force on a body:
F= mv/t...........(i)
Formula for calculating net force:
Fnet= F₁ +F₂ +F₃ +F......FN ............(ii)
where,
F₁ +F₂ +F₃ +F......FN= force acting on the body.
From the Question:
Mass, M=28.59 kg
Velocity, V= 5.18 m/s
time, T =37.80 s.
Using equation (i)
F= mv/t
=28.59 kg*5.18 m/s
37.80 s.
=3.92N
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