How many excess electrons must be distributed uniformly within the volume of an isolated plastic sphere 26.0 cm in diameter to produce an electric field of 1440 N/C just outside the surface of the sphere

Answers

Answer 1

a metaphor for generosity and joy and joy and joy and joy organised a large wedding guests had to choose their meal from beef chicken tikka and a kind young women in the streets of St

Answer 2

The number of excess electrons needed to be distributed uniformly in the sphere to produce the given electric field is 1.69*10^(10).

What is an electric field?

The electric force exerted on a unit charge is called the electric field.

For a sphere of uniform charge density, the magnitude of the electric field on its surface is given by,

E=k*q/r^2

where E is the magnitude of the electric field, k is the coulomb's constant which has a value of 9*10^9 N m^(2) C^(-2), and q is the total charge of the sphere, and r is the radius of the sphere.

The radius of the sphere is half of the diameter. Given the diameter of the sphere is 26.0 m, the radius of the sphere r=26.0/2 cm or r=13.0 cm.

It is given that E=1440 N/C, r=13.0 cm, and the value of k is 9*10^9 N m^(2) C^(-2). Substitute these values in the formula of the electric field and solve it to get the value of the total charge on the sphere.

Note: 1 cm = 0.01 m.

1440 (N/C)= (9*10^9 N m^(2) C^(-2))*q/( 13 cm)^2

1440 (N/C)= (9*10^9 N m^(2) C^(-2))*q/( 13*0.01 m)^2

1440 ( N/C)= (532.54*10^(9) N C^(-2))*q

q=1440/(532.54*10^(9)) C

q=2.704*10^(-9) C

Since the charge is quantized, the total charge inside the sphere is the integral multiple of an elementary charge. In the given case, the value of that elementary charge is 1.6*10^(-19) C. The total charge is then given by,

q=ne

where q is the total charge, n is the number of elementary charges and e is the value of the elementary charge.

The value of q is 2.704*10^(-9) C and the value of e is 1.6*10^(-19) C.

Substitute these values in the formula of total charge and solve it to get the number of elementary charges.

2.704*10^(-9) C =n*1.6*10^(-19) C

n=2.704*10^(-9)/ 1.6*10^(-19)

n=1.69*10^(10)

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Related Questions

A car increases its speed from 30 km/h to 60 km/h in 5 seconds. Its acceleration​

Answers

Answer:6km/sec

Explanation: Acceleration = Change in velocity / Time

Change in velocity = 60km/h minus 30km/hr

Time = 5seconds

A power supply is connected to a 59 Ohm resistor and a 53 Ohm resistor in series. The total current is found to be 0.15 A. What is the voltage drop across the 53 Ohm resistor? Round your answer to 2 decimal places.

Answer:

Answers

the answer is 47265.dug

Explanation:

im bot sure

What is the threshold frequency for sodium metal if a photon with frequency 6.66 × 1014 s−1 ejects an electron with 7.74 × 10−20 j kinetic energy?

Answers

The threshold frequency for sodium metal is

5.49 x 10^14 s-1

Given:

photon with frequency = 6.66 × 10^14 s−1

kinetic energy = 7.74 × 10−20 j

To Find:

threshold frequency

Solution: The threshold frequency is defined as the minimum frequency of incident radiation below which the photoelectric emission is not possible completely. irrespective of the intensity of incident radiation

We know, relation between threshold frequency, kinetic energy and frequency s given by :

K.E = hv - hvo

Here h is plank's constant and vo, is threshold frequency.

Putting all these value in above equation we get:

7.74 x 10^-20 = (6.66 × 10^14-vo) x 6.626 x 10^-34

vo = 5.49 x 10^14 s^-1

Hence, the threshold frequency for sodium metal is 5.49 x 10^14 s-1

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In addition to ozone, what four other greenhouse gases or groups of greenhouse gases are included in nearly all the climate models?

Answers

In addition to ozone, the four other greenhouse gases or groups of greenhouse gases are included in nearly all the climate models are Carbon dioxide, water vapor, and methane, nitrous oxide.

Carbon dioxide, absorbs energy at a variety of wavelengths, a range that overlaps with that of infrared energy. As CO2 soaks up this infrared energy, it vibrates and re-emits the infrared energy back in all directions. About half of that energy goes out into space, and about half of it returns to Earth as heat, contributing to the ‘greenhouse effect.’

As methane is emitted into the air, it reacts in several ways. It reacts and  after oxidization methane forms water vapor and carbon dioxide. So, not only does methane contribute to global warming directly but also, indirectly through the release of carbon dioxide.

Nitrous oxide enhances the greenhouse effect by capturing reradiated infrared radiation from the Earth’s surface and subsequently warming the troposphere . It is chemically inert in the troposphere and stays in the troposphere for about 120 years before moving into the stratosphere where it ultimately leads to destruction of stratospheric ozone.

Water vapor does absorb longwave radiation and radiates it back to the surface, thus contributing to warming.

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If the strength of a magnetic field at B is three units the strength of the magnetic field at A is ____?

Answers

If the strength of a magnetic field at B is three units the strength of the magnetic field at A, means that point B has three times more turns as compared to point A.

How strength of the magnetic field should be increased?

We can increase the strength of the magnetic field by increasing the number of turns which increases the strength of the current flow.

So we can conclude that point B has three times more turns as compared to point A.

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An engine has an input of heat energy of 10,750 J and does 2,420 J of work. Which of the following is the heat loss?
Group of answer choices

a. 13,200 J

b. 8,330 J

c. 4.44 J

c. 0.225 J

Answers

B. The heat loss by the heat engine is 8,330 J.

Heat loss by the heat engine

The heat loss by the heat engine is calculated as follows;

H = E - W

where;

H is heat lossE is input energyW is work done

H = 10,750 J - 2,420 J

H = 8,330 J

Thus, the heat loss by the heat engine is 8,330 J.

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Excessive use of fossil fuels causes an energy crisis

Answers

yes, it causes an energy crisis. Burning Fossil Fuels

When we burn oil, coal, and gas, we don't just meet our energy needs, we move the current global warming crisis as well.

Fossil fuels produce large amounts of carbon dioxide when burned. Carbon emissions trap heat in the air and lead to climate change.

What are the major causes of energy crisis?

Most energy crises have been caused by localized shortages, wars and market manipulation. Some have argued that government efforts like tax hikes, nationalization of energy companies, and rule of the energy sector, shift supply and demand of energy away from its economic stability.

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Two objects X and Y move directly towards each other. The objects have the same mass.
Object X has a velocity of 5.0 m/s to the right. Object Y has a velocity of 3.0 m/s to the left.
Object X and object Y collide and stick together.
What is their velocity after colliding?

Answers

X and Y are two things that travel in the same direction. The mass of the things is the same. 5.0 m/s is the velocity of object x as it moves to the right. The velocity of object y to the left is 3.0 m/s. Objects x and y collide and adhere to one another. Following their collision, they both move at a speed of 1.0 m/s to the right.

Their velocity after colliding is 1.0 m / s to the right.

What is the velocity during the collision?

In a collision, the velocity change is always computed by subtracting the initial value from the final value. If an object is moving in one direction before a collision and rebounds or somehow changes direction, then its velocity after the collision has the opposite direction as before.Inelastic collisions occur when only the momentum is conserved but not the system's kinetic energy. Perfectly inelastic collisions happen when objects stick together and have a common velocity after collision. To solve for the final velocity in perfectly inelastic collisions, use v' = (m1v1 + m2v2)/m1 + m2.The magnitude of the relative velocity is the same before and after the collision.

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At a point in space an electric force acts vertically upward on an electrion, the directon of the electric field at that point is:____

Answers

Answer:

F = Q E      force acting on charge Q due to field E

A positive electric field is directed from positive to negative.

An electron will be attracted to the positive terminal.

Thus if the electric force is upwards the direction of the field must be directed downwards, or

if F is positive and Q is negative E must also be negative or downwards.

(taking upwards as positive)

The technique called adaptive optics uses dynamic mirror motion to enhance the performance of the new generation of spaced-based telescopes. True False

Answers

The mentioned statement is true.

What is adaptive optics(AO)?

Adaptive optics (AO) is a technique that enhances optical systems' performance by minimizing the impact of incoming wavefront aberrations and deforming a mirror to account for the distortion. It is employed in microscopy, optical manufacturing, and retinal imaging systems to lessen optical aberrations and in astronomical telescopes and infrared communication devices to eliminate the impacts of environmental turbulence. Using a technology that adjusts flaws, including a flexible reflector or a liquid crystal array, adaptive optics(AO) measures the abnormalities in a wavefront and adjusts them.

How can adaptive optics(AO) enhance a telescope's capabilities?

To counteract the impacts of disturbance, it quickly modifies the telescope mirror's shape.A moderately luminous target star that is adjacent to the target being studied is necessary for adaptive optics. With the use of the deformable mirror, the blurring brought on by the nearby atmosphere is measured using this reference star.

Therefore, it is concluded that the mentioned statement is true.

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A vehicle that weights 400 n on the surface of the earth is traveling in outer space at a speed of 400 m/s. It can be stopped by applying a constant force of 20 n for:_____.

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A vehicle that weights 400 n on the surface of the earth is traveling in outer space at a speed of 400 m/s. It can be stopped by applying a constant force of 20 n for 800 secs.

Newtons 3 law whilst one object exerts pressure on any other object, the second object exerts a force on the first item this is identical in significance, but opposite in course; for each movement, there is an identical, but opposite response; referred to as the law of action-reaction.

You can use the equal formulation d = rt because of this distance equals the price instance's time. To solve for speed or rate use the components for pace, s = d/t this means that pace equals distance divided by way of time. To clear up for time use the components for time, t = d/s this means that time equals distance divided by way of velocity.

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A 540 gram object is attached to a vertical spring, causing the spring’s length to change from 70 cm to 110 cm.

What is the spring constant k?

Group of answer choices

130 N/m

33 N/m

13 N/m

330 N/m

Answers

Answer:

Approximately [tex]13\; {\rm N \cdot m^{-1}}[/tex] (assuming that [tex]g = 9.81\; {\rm N \cdot kg^{-1}}[/tex].)

Explanation:

Let [tex]F_{\text{s}}[/tex] denote the force that this spring exerts on the object. Let [tex]x[/tex] denote the displacement of this spring from the equilibrium position.

By Hooke's Law, the spring constant [tex]k[/tex] of this spring would ensure that [tex]F_\text{s} = -k\, x[/tex].

Note that the mass of the object attached to this spring is [tex]m = 540\; {\rm g} = 0.540\; {\rm kg}[/tex]. Thus, the weight of this object would be [tex]m\, g = 0.540\; {\rm kg} \times 9.81\; {\rm N \cdot kg^{-1}} \approx 5.230\; {\rm N}[/tex].

Assuming that this object is not moving, the spring would need to exert an upward force of the same magnitude on the object. Thus, [tex]F_{\text{s}} = 5.230\; {\rm N}[/tex].

The spring in this question was stretched downward from its equilibrium by:

[tex]\begin{aligned} x &= (70\; {\rm cm} - 110\; {\rm cm}) \\ &= (-40)\; {\rm cm} \\ &= (-0.40) \; {\rm m}\end{aligned}[/tex].

(Note that [tex]x[/tex] is negative since this displacement points downwards.)

Rearrange Hooke's Law to find [tex]k[/tex] in terms of [tex]F_{\text{s}}[/tex] and [tex]x[/tex]:

[tex]\begin{aligned} k &= \frac{F_{\text{s}}}{-x} \\ &\approx \frac{5.230\; {\rm N}}{-(-0.40)\; {\rm m}} \\ &\approx 13\; {\rm N \cdot m^{-1}}\end{aligned}[/tex].

If we ignore lift and drag forces as the squid flies through the air, what is the maximum horizontal range that the squid can achieve before splashing down?

Answers

The speed is 42 m/s at which squid rejects the water.

The maximum horizontal range that squid can achieve is 1.25 m

What is a drag force?

Drag force is a force acting opposite to the relative motion of any object moving concerning a surrounding fluid. This exists between two fluid layers or between a fluid and a solid surface.

Here,

mass of the water, m1 = 3.0 kg

mass of the squid, m2 = 36 kg

initial speed, v2 = 3.5 m/s

(a)

According to the conservation of momentum:

m1*v1 = m2*v2

3 * v1 = 36 * 3.5

v1 = 42 m/s

It is the speed at which the squid rejects the water.

(b)

The maximum range:

R(max) = (v2) ^2 / g

where,

g=9.8 m/s^2 and launch angle is 45°

R(max) = 3.5^2 / 9.8

R(max) =  1.25 m

Hence,

The speed is 42 m/s at which squid rejects the water.

The maximum horizontal range that squid can achieve is 1.25 m

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Your question is incomplete, but most probably the full question was:

We’ve seen that squid can escape from predators by ejecting water. Some squid do this at the surface of the ocean, thus launching themselves into the air—a particularly effective escape strategy. Suppose a 36 kg squid (not including water) at rest at the surface of the water brings in and quickly ejects 3.0 kg of water to achieve a takeoff speed of 3.5 m/s; these are typical numbers.

a. At what speed does the squid eject the water?

b. If we ignore lift and drag forces as the squid flies through the air, what is the maximum horizontal range that the squid can achieve before splashing down?

A wire coil inside a generator has 150 square loops and an area equal to 0.042 m2.
The coil rotates one-quarter turn in 1.7 ms. If a 0.86 T magnetic field surrounds the
coil, what is the maximum electromotive force induced in the coil

a. 3.2 V
b. 130 V
c. 1600 V
d. 3200 V

Answers

D. The maximum electromotive force induced in the coil is determined as 3,200 V.

Maximum electromotive force induced in the coil

emf(max) = NAB/t

where;

N is number of turnsB is magnetic fieldA is area of the coilt is time

Substitute the given parameters and solve for emf

emf(max) = (150 x 0.042 x 0.86) / (1.7 x 10⁻³)

emf(max) = 3,187.1 V

emf(max) ≈ 3,200 V

Thus, the maximum electromotive force induced in the coil is determined as 3,200 V.

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Which of newton's three laws is the hardest to describe or explain when viewing common occurrences?

Answers

Newton's second law is the hardest to describe as it is about momentum  (F = ma), and a lot of people don't know the concept of momentum.

Newton's first law of motion:- every object moves in a straight line unless acted upon by a force.

Newton's 2nd law of motion:-the acceleration of an object is directly proportional to the net force exerted and inversely proportional to the item's mass. Newton's 2nd law is a quantitative description of the changes that a force can produce on the motion of a body. It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.

Newton's 3rd law of motion:- For every action, there's an equal and opposite reaction.

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An ordinary flashlight battery has a potential difference of 1.2 V between its positive and negative terminals. How much work must you do to transport an electron from the positive terminal to negative terminal

Answers

The work done to transport an electron from the positive to the negative terminal is 1.92×10⁻¹⁹ J.

Given:

Potential difference, V = 1.2 V

Charge on an electron, e = 1.6 × 10⁻¹⁹ C

Calculation:

We know that the work done to transport an electron from the positive to the negative terminal is given as:

W.D = (Charge on electron)×(Potential difference)

       = e × V

       = (1.6 × 10⁻¹⁹ C)×(1.2 V)

       = 1.92 × 10⁻¹⁹ J

Therefore, the work done in bringing the charge from the positive terminal to the negative terminal is 1.92 × 10⁻¹⁹ J.

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(a) Circular metal wires in electrical circuits may have different cross-sectional areas (different diameters) and different lengths. For a given applied voltage, how would the joule heat vary with these parameters

Answers

For the different wires the values given are

For Wire A,  Area=[tex]A_{A}[/tex], Resistivity=[tex]ρ_{A}[/tex], Length= [tex]L_{A}[/tex], Heat=[tex]H_{A}[/tex], Voltage= V, Time= t, Wire B,  Area=[tex]A_{B}[/tex], Resistivity=[tex]ρ_{B}[/tex], Length= [tex]L_{B}[/tex], Heat=[tex]H_{B}[/tex]

So, [tex]H_{A}[/tex]/ [tex]H_{A}[/tex]=[tex]\frac{V^{2} *t}{\frac{ρ(1)*L_{A} }{A_{A} } }[/tex]/[tex]\frac{V^{2} *t}{\frac{ρ(2)*L_{B} }{A_{B} } }[/tex]

Therefore [tex]H_{A}[/tex]/ [tex]H_{A}[/tex]= [tex]\frac{A_{A}*ρ_{B} *L_{B}}{A_{B}ρ_{A} L_{A} }[/tex]

Heat

The type of energy that moves between two materials with varying temperatures is referred to by scientists as heat. Because the average translational kinetic energy per molecule in the two materials varies, an energy transfer takes place. Up until thermal equilibrium is attained, heat is transferred from the substance with the higher temperature to the material with the lower temperature. The joule, with 1 joule equalling 1 newton meter, is the SI unit of heat. Imagine the following situation to better comprehend what happens when this energy transfer takes place: Tiny rubber balls are bouncing all over two distinct containers that are full with them. The difference between the average ball speed in one container and the second container is substantial.

(a) Circular metal wires in electrical circuits may have different cross-sectional areas (different diameters) and different lengths. For a given applied voltage, how would the joule heat vary with these parameters

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Basic elements for every contract include
1) an offer,
2) acceptance,
3) ___________,
4) with legal capacity, for a legal purpose

Answers

The basic elements for every contract include

1) an offer,

2) acceptance,

3) Awareness

4) with legal capacity, for a legal purpose

What is a contract?

A contract is an agreement between two or more parties, to perform a specific job or duty. A contract is usually temporary or of fixed duration and usually governed by a written agreement.

The basic elements every contract should contain are as follows:

An offer, which encompasses the duties and responsibilities of each partyAcceptance; the offeree must decide whether to accept or reject the proposal/offer. Awareness; for a contract to be binding, the involved parties must first be aware that they are entering into an agreementLegal capacity; all contracts are subject to the laws of the jurisdiction in which they operate

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Are the acceleration and force vectors related? does the simulation show this relation?

Answers

The direction of the force vector and acceleration are identical (downwards) during the motion. The simulation also indicates the same relation.

Newton's 2nd regulation, F = ma is a vector equation. It says that the net force (a vector) acting on a mass m (a range of) causes an acceleration (a vector) of the object within the same path as the net force.

A simple mathematical relationship exists between the mass of an item (m), the net force at the item (f) and its acceleration (a). The acceleration of an object is without delay proportional to the net force and indirectly proportional to the item's mass (a = f/m).

For example, displacement, velocity, and acceleration are vector quantities, while speed (the magnitude of velocity), time, and mass are scalars. To qualify as a vector, a quantity having magnitude and direction must also obey certain rules of combination.

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The diagram below shows a pendulum at two different positions in its path. The pendulum started from rest in position 1.


Pendulum with two different positions. Position 1 is higher and to the left compared to position 2


Which best describes the energy change as the pendulum moves from position 1 to position 2?

Group of answer choices


a. The total energy is decreasing.


b. The kinetic energy is increasing.


c. The thermal energy is decreasing.


d. The potential energy is increasing.

Answers

From position 1 to position 2, the kinetic energy is increasing.

Kinetic of a pendulum in simple harmonic motion

The kinetic energy of a pendulum undergoing simple harmonic motion decreases as the displacement of the pendulum increases and increases as the displacement of the pendulum decreases.

From position 1 to position 2, the kinetic energy is increasing while the potential energy is decreasing.

Thus, from position 1 to position 2, the kinetic energy is increasing.

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Barry slides across an icy pond. The coefficient of kinetic friction between his
shoes and the ice is 0.15. If his mass is 83 kg, what is the force of friction
acting on him?
OA. 813 N
B. 1150 N
C. 122 N
D. 352 N

Answers

The force of friction acting on him is 122 N. The correct answer is option C

What is Friction ?

Friction is a force that opposes the motion of a static or a moving object.

Given that Barry slides across an icy pond. The coefficient of kinetic friction between his shoes and the ice is 0.15. If his mass is 83 kg

The given parameters are;

Mass m = 83 kgCoefficient of kinetic friction μ = 0.15Frictional force [tex]F_{r}[/tex] = ?

The normal reaction N on the body = mg

N = 83 x 9.8

N = 813.4 N

The Frictional force formula is  [tex]F_{r}[/tex] = μN

[tex]F_{r}[/tex] = 0.15 x 813.4

[tex]F_{r}[/tex] = 122.01 N

Therefore, the force of friction acting on him is 122 N approximately.

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A train is traveling at 30.0 m/sm/s relative to the ground in still air. The frequency of the note emitted by the train whistle is 262 HzHz. The speed of sound in air should be taken as 344 m/sm/s .

Answers

frequency fapproach is heard by a passenger = 302.05 Hz

frequency frecede is heard by a passenger = 228.37433 Hz

Given :

speed of train to the ground = 30.0 m/s

frequency emitted by the train whistle = 262 Hz

speed of sound in air = 344 m/s

To Find :

(A) frequency fapproach (B) frequency frecede

Solution :

The frequency of approach is given by

f' = f v + v(relative)

v - v(air)

= 262x 344 + 18

344 - 30

f' = 302.05 Hz

The frequency of approach is 302.05 Hz

The frequency of recede is given by

f' = f v - v(relative)

v + v(air)

= 262 x 344 - 18

344 + 30

The frequency of recede is 228.37433 Hz

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A 5.0-kg object is suspended by a string from the ceiling of an elevator that is accelerating downward at a rate of 2.6 m/s 2. What is the tension in the string

Answers

The tension in the string is 36 N.

To find the answer, we need to know about pseudo acceleration.

What's pseudo acceleration?When an object is placed on a vehicle, it experiences a pseudo acceleration in the opposite direction of the motion of the vehicle. Magnitude of the pseudo acceleration is same as that of the acceleration of vehicle.What's the pseudo acceleration of a mass suspended in a lift that's moving downward with an acceleration of 2.6 m/s²?Here, the acceleration of the lift is 2.6m/s², so the mass suspended by a string inside it will feel a pseudo acceleration of 2.6m/s² upward.So the effective acceleration of the mass = acceleration due to gravity - pseudo acceleration = 9.8 - 2.6 = 7.2 m/s²What's the tension of the string suspending the mass?

Tension of the string= mass × effective acceleration

= 5 × 7.2 = 36 N

Thus, we can conclude that the tension in the string is 36 N.

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Technical skills: knowledge base of sport rearrange our coaching skills from best (at the top) to worst (at the bottom) by dragging each skill to where you think it belongs. this should help you identify your current strengths and limitations as a teacher/coach. after organizing each group of skills, describe steps you think you can take to enhance your strengths and being to address your limitations as a coach.

Answers

The steps which enhance strengths and address limitations as a coach include:

Identifying weakness.Setting goals.Consistency.

Who is a Coach?

This is referred to a professional who gives special training about a particular subject or topic.

It is best to identify weakness and work towards improvement through determination and consistency.

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An astronaut in training is seated at the end of a horizontal arm 8 meters long. How many revolutions per second must the arm make for the astronaut to experience a horizontal acceleration of 4.0g

Answers

Answer:

a = v^2 / R        where a is the centripetal acceleration and R the radius

v = 2 π R N / t        where (N / t) is the revolutions / sec giving distance / time

a = 4 g         horizontal acceleration

4 g = (2 π R N / t)^2 / R = 4 π^2 * R * (N / t)^2

(N / t)^2 = g / (π^2 * R)

N / t = 1 /  π * (g / R)^1/2 = .318 * (9.80 m / s^2 / 8 m)^1/2  = .352 / sec

A microwave is a(n) _____ that is directed from one microwave station tower to another

Answers

The high-frequency radio signal is the answer.

Radiofrequency (RF) radios are in the wavelength band of 100 to 10 meters and extend from 3 MHz to 30 MHz. Much of the HF bandwidth is allocated to mobile and fixed voice communications services that require transmission bandwidth of less than 12 kHz. International (Shortwave) Broadcast

Radio Frequency (HF) is an ITU term for the range of high-frequency electromagnetic waves (radio waves) from 3 to 30 MHz (MHz). It is also known as the decameter band or decameter wave because it has wavelengths in the range of 1 to 10 decameter (tens to hundreds of meters).

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Would it be more efficient to warm your bed on a cold night with a hot water bottle that contains 1 kg of water at 500 C or with a 1 Kg iron bar at 1000 C.

Answers

Warming the bed with water is far more efficient than warming the bed with an iron, the difference is the specific heat capacity of water and iron.

The specific heat capacity of a substance can be defined as the amount of the heat required to raise the temperature of the unit mass of a given substance by a given amount (usually one degree).

What is the Specific heat of Water?

q = m x C x AT

As the specific heat of water is 4.18 J/g°C and the specific heat of iron is 0.450 J/g°C. Since, the specific heat of water is greater than the specific heat of iron.

Therefore, we can conclude that water is more efficient to warm your bed on a cold night with a hot water bottle that contains 1 kg of water at 50 degrees C.

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Two celestial objects are in space: one with a mass of 8.22 x 109 kg and one with a mass of 1.38 x 108 kg. If they are separated by a distance of 1.43 km, what is the magnitude of the force of attraction (in newtons) between the objects

Answers

Answer: Two celestial objects are in space: one with a mass of 8.22 x 109 kg and one with a mass of 1.38 x 108 kg. If they are separated by a distance of 1.43 km, then, the magnitude of the force of attraction (in newtons) between the objects will be 52.9kN

Explanation: To find the answer we need to know more about the Newton's law of gravitation.

What is Newton's law of gravitation?Gravitation is the force of attraction between any two bodies.Every body in the universe attracts every other body with a force.This force is directly proportional to the product of their masses and inversely proportional to the square of the distance between these two masses.Mathematically we can expressed it as,

                        [tex]F=\frac{GMm}{r^2} \\where, G=6.67*10^-11Nm^2kg^-2[/tex]

How to solve the problem?Here, we have given with the data's,

                      [tex]M=8.22*10^9kg\\m=1.38*10^8 kg\\r=1.43*10^3m[/tex]

Thus, the force of attraction between these two bodies will be,

               [tex]F=6.67*10^-11*\frac{8.22*10^9*1.38*10^8}{1.43*10^3} =52.9kN[/tex]

Thus, if two celestial objects are in space: one with a mass of 8.22 x 109 kg and one with a mass of 1.38 x 108 kg and, If they are separated by a distance of 1.43 km, then, the magnitude of the force of attraction (in newtons) between the objects will be 52.9kN.

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When operating an aircraft at cabin pressure altitudes above 12,500 feet msl up to and including 14,000 feet msl, supplemental oxygen shall be used during?

Answers

Supplemental oxygen shall be used in that flight time in excess of 30 minutes at those altitudes.

Most plane cabins are pressurized to 8,000 feet above sea level, an altitude that lowers the amount of oxygen inside the blood by approximately 4 percentage points, researchers say.

The higher the altitude, the less oxygen there is in the air and the lower the overall air pressure is. If flights were not pressurized, passengers could be prone to various physiological illnesses. Because of this, federal policies require that all commercial flights over 8,000 feet be pressurized.

The flight crew must use supplemental oxygen for the entire duration of flight operations above a cabin pressure altitude of 14,000 feet MSL.

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A 16.9 kg monkey is swinging on a
5.32 m long vine. It starts at rest,
with the vine at a 43.0° angle.
How much PE does the monkey
have?
(Unit = J)

Answers

The potential energy of the monkey at the given position is 600.9 J.

What is potential energy?

Potential energy is the energy stored in a body that depends upon the relative position of various parts of the body.

It increases with increase in the height of the object above the ground level.

Potential energy of the monkey

The potential energy of the monkey is calculated as follows;

P.E = mgh

P.E = mg (L sin43)

where;

m is mass of the monkey, given as 16.9 kgg is acceleration due to gravity, given as 9.8 m/s²L is length of the vine given as 5.32 m

Substitute the given parameters and solve potential energy of the monkey

P.E = (16.9)(9.8)( 5.32 x sin 43)

P.E = 600.9 J

Thus, the potential energy of the monkey at the given position is 600.9 J.

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