How much power does it take to lift a box with a weight of 50N to put it on a shelf that is 10m high in
10 sec?

Let consider the whole system to be at equilibrium where the net force is zero. The forces [tex]F_A[/tex] and [tex]F_B[/tex] are acting in the upward direction while the weight (w) of the crate is acting in the downward direction.

The force at equilibrium in the y-direction is computed as:

[tex]\sum F_y = ma_y[/tex]

[tex]F_A +F_B= mg[/tex]

[tex]\mathbf{F_A = mg -F_B}[/tex]  ---- (1)

Recall that the weight w = mg

where;

w = 200 × 9.8

w = 1960 N

The torque about the bottom end is also zero. i.e.

[tex]\sum \tau=0[/tex]

∴

[tex]F_B L_Z - wL_w = 0[/tex] --- (2)

[tex]F_B L_Z= wL_w[/tex]

[tex]F_B = \omega (\dfrac{L_w}{L_z})[/tex]

[tex]F_B =1960\times (\dfrac{0.375\times cos 45^0}{1.25\times cos 45^0})[/tex]

[tex]F_B =1960\times (0.3)[/tex]

[tex]\mathsf{F_B = 588 \ N}[/tex]

Replacing the value for the force of B into equation (1); we have:

[tex]F_A = mg - F_B[/tex]

[tex]F_A = 1960 - 588[/tex]

[tex]\mathsf{F_A = 1372 N}[/tex]

Thus, we can conclude that the magnitude of these forces i.e force B and force A are 588 N and 1372 N respectively.

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Answer:Testing

Explanation:Once a scientist has made a hypothesis, what would they typically do TESTING nextn

Once a scientist has made a hypothesis, they would typically do testing, therefore the correct answer is option B

Scientific claims are statements made in science based on an experiment.

These Scientific claims are backed by the experimental data and their true results obtained from scientific investigation and experimentation.

When a scientist performs a fair test is one in which all other circumstances are maintained while just one variable is changed at a time.

Scientists frequently discover that their hypotheses and predictions were not supported by the results of their experiments. In these situations, they will communicate the findings of their experiment before revising their original hypotheses and predictions in light of the new knowledge they have gained.

The right response is option B because once a scientist has made a theory, they usually do testing.

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Answer:

Humans naturally have what's known as binaural hearing, which is the ability to hear in two ears.

Explanation:

speeds = distance/time

=100/16

=6.25m/s

second speed is;

400/44 =9.09

av. speed = total speed /n

= (6.25+9.09)/2

=7.67 m/s

Answer:

1.7 BTU

Explanation:

q = mCΔT

q = (25 g) (0.9 J/g/°C) (100°C − 20°C)

q = 1800 J

q = 1800 J × (1 BTU / 1055 J)

q = 1.7 BTU

Answer:

Upthrust = 20 N

Explanation:

The question says that "A body weighs 100N in air and 80N when submerged in water. Calculate the upthrust acting on the body ?"

Upthrust is defined as the force when a body is submerged in liquid, then liquid applies a force on it.

ATQ,

Weight of body in air is 100 N

Weight of body in water is 80 N

Upthrust is equal to the weight of body in air minus weight of body in water.

Upthrust = 100 N - 80 N

Upthrust = 20 N

So, 20 N of upthrust is acting on the body.

Answer:

pull

Explanation:

because when you push there is one component of force that adds to tge weight of body and hence there is more friction. Whwn you pull the vertical component of force is against the weight of body and hence friction is low.

Answer:

I guess i would say the microscope

Explanation:

Because of the microscope, we can see the cells.

Answer:

27.34 (no unit)

Explanation:

26.975*82.33%+29.018*17.67%

=27.34

Answer:

For vegetarians beans

Explanation:

Because it's plant protein and very proteinious

Answer:

Abiogenesis in evolutionary science, not sure about creation science

Explanation:

Answer:

In this case reflection occurs.

Explanation:

This happens when they bounce on objects that they can not pass through.

Hope it helps

okay.

Answer:

For two resistors R1 = 12Ω and R2 = 18Ω are connected in series. The equivalent resistance R12 of the circuit can take any of the values

Answer:

C. sound energy

Explanation:

hope this helps

Answer:

66.7 cm

Explanation:

The focal length is half the radius of curvature, or f = 40 cm.

The image is real, so i = +100 cm.

The distance to the object is therefore:

1/o + 1/f = 1/i

1/o + 1/40 = 1/100

o = -66.7 cm

The object is 66.7 cm left of the mirror.

Answer:

8 atm

Explanation:

Ideal gas law:

PV = nRT

where P is pressure, V is volume, n is moles, R is universal gas constant, and T is absolute temperature.

If n is constant:

PV / T = PV / T

(4 atm) (60 L) / (27 + 273) K = P (40 L) / (127 + 273) K

0.8 atm = 0.1 P

P = 8 atm

Answer:

[tex]\boxed{0}[/tex]

Explanation:

Momentum is the measure of mass in motion.

[tex]\sf momentum = mass \times velocity[/tex]

An object at rest has a velocity of 0.

[tex]p=mv[/tex]

[tex]p = 25 \times 0[/tex]

[tex]p=0[/tex]

The momentum of an object at rest is always 0.

Answer:

(II). The fractions in simplest form

[tex]\dfrac{31}{35}[/tex], [tex]\dfrac{91}{165}[/tex] and [tex]\dfrac{13}{5}[/tex]

(III). The fractions in ascending order

[tex]\dfrac{91}{165}<\dfrac{31}{35}<\dfrac{13}{5}[/tex]

Explanation:

Given that,

(I). Represent the fractions in pictorial form

(II). Write the fractions in simplest form.

(III). Arrange them in ascending order.

Suppose, The fractions in pictorial form

(a). [tex]\dfrac{3}{5}+\dfrac{2}{7}[/tex]

(b). [tex]\dfrac{9}{11}-\dfrac{4}{15}[/tex]

(c). [tex]\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}[/tex]

We need to write in simplest form

Using given fraction

(a). [tex]\dfrac{3}{5}+\dfrac{2}{7}=\dfrac{3\times7}{5\times7}+\dfrac{2\times5}{7\times5}[/tex]

[tex]\dfrac{3}{5}+\dfrac{2}{7}=\dfrac{21}{35}+\dfrac{10}{35}[/tex]

[tex]\dfrac{3}{5}+\dfrac{2}{7}=\dfrac{21+10}{35}[/tex]

[tex]\dfrac{3}{5}+\dfrac{2}{7}=\dfrac{31}{35}[/tex]

(b). [tex]\dfrac{9}{11}-\dfrac{4}{15}=\dfrac{9\times15}{11\times15}-\dfrac{4\times11}{15\times11}[/tex]

[tex]\dfrac{9}{11}-\dfrac{4}{15}=\dfrac{135-44}{165}[/tex]

[tex]\dfrac{9}{11}-\dfrac{4}{15}=\dfrac{91}{165}[/tex]

(c). [tex]\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}=\dfrac{7}{10}+\dfrac{2\times2}{5\times2}+\dfrac{3\times5}{5\times2}[/tex]

[tex]\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}=\dfrac{7}{10}+\dfrac{4+15}{10}[/tex]

[tex]\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}=\dfrac{7+4+15}{10}[/tex]

[tex]\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}=\dfrac{26}{10}[/tex]

[tex]\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}=\dfrac{13}{5}[/tex]

We need to arrange them in ascending order

Using simplest form

The simplest fraction in ascending order

[tex]\dfrac{91}{165}<\dfrac{31}{35}<\dfrac{13}{5}[/tex]

Hence, This is required solution.

Answer:

[tex]{ \bf{mechanical \: adv = \frac{load}{effort} }}[/tex]

To calculate the density of a substance, its mass and volume has to be determined. So that:

i. For the milk in the carton, its mass and volume should be known.

ii. For the two objects given in the question, their individual masses and volumes have to be determined.

Density of a substance (ρ) is the rate of the mass (m) of the substance to its volume (V). It is measure in kg/[tex]m^{3}[/tex].

i.e ρ = [tex]\frac{m}{V}[/tex]

The density of a substance can be determined once the mass and its volume have been accurately measured.

1. How to measure the density of the contents of a milk carton.

a. Determine the mass of the milk carton with its content.

b. Determine the mass of the milk carton when empty.

c. Subtract the mass of the milk carton when empty from the mass of the carton with its content. This will give the mass of the milk in the carton.

d. Using a beaker, measure the volume of the milk.

e. Divide the mass of the milk by its volume to determine its density.

2. How to measure the densities of two objects of equal mass.

a. Fill an Eureka's can or a beaker with sprout with water to its brim.

b. Slowly drop the mass into the beaker with water so as to collect the volume of the liquid displaced into another beaker.

c. The volume of the liquid displaced is the volume of the mass.

d. Divide the mass of the object by its volume to determine its density.

NB: These procedures are observed to determine the densities of the two object individually.

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Answer and Explanation:

Data provided in the question

Force = 50N

Length = 5mm

diameter = 2.0m = [tex]2\times 10^{-3}[/tex]

Extended by = 0.25mm = [tex]0.25\times 10^{-3}[/tex]

Based on the above information, the calculation is as follows

a. The Stress of the wire is

[tex]= \frac{force\ applied}{area\ of \ circle}[/tex]

here area of circle = perpendicular to the are i.e cross-sectional  i.e

= [tex]\frac{\pi d^{2}}{4}[/tex]

= [tex]\frac{\pi(2\times 10^{-3})^2}{4}[/tex]

Now place these above values to the above formula

[tex]= \frac{4\times 50}{\pi\times 4 \times 10^{-6}} \\\\ = \frac{50}{\pi}[/tex]

= 15.92 MPa

As 1Pa = 1 by N m^2

So,

MPa = 10^6 N m^2

b. Now the strain of the wire is

[tex]= \frac{Change\ in\ length}{initial\ length} \\\\ = \frac{0.25\times 10^{-3}}{5}[/tex]

= [tex]5 \times 10^{-5}[/tex]

Answer:

6s , 60mls

Explanation:

hope this helps love

Answer:

0m/s

Explanation:

When the object strikes the ground, it then becomes in uniform motion and when an object is in uniform motion, the velocity is 0

Answer:

The formula for speed is speed=distance

time

Explanation:

to work out what the units are for speed,you need to know the units for distance and time.In this example,distance is in metres(m) and time is in seconds (s) , so the units for speed is metre per second (m/s).

Answer:

There will  be a huge problem of holding the wire strands together, and the power losses will also be amplified.

Explanation:

The force per unit length on two current carrying conductors, lying parallel to each other is proportional to the product of the current through the conductors, and inversely proportional to their distance apart. This force is attractive if the current flows through these conductors in the same direction, and is repulsive if it flows in the opposite direction.

For the strand of wire that make up a high voltage wire bundle, there will be a force of attraction pulling the wires closer to each other, and they will experience the maximum pulling force possible, since they lie next to each other. This force helps to hold these wires in a high tension wire strand together, limiting the area, and reducing "skin effect."

In the case that this wires in the wire strand acts in opposite of the known behavior, the wires will repel and push each other apart. This pushing apart will increase power loss due "skin effect" which is increased by an increase in exposed surface area of the wire strands. This will pose a big problem for high tension transmission.

Thiết bị không phải nguồn điện:

Đáp án D

Answer:

=33 .3×10^6Ω

=33.3M Ω

Explanation:

We were told to calculate the Resistance value,

Given the heart pacemaker fires as 72 times a minute, which is the time constant

Then we can convert the pacemaker fires of 72 times a minute to seconds for unit consistency.

1 minutes= 60secs

Then ,Time constant τ=60secs/72=0.8333 seconds

Time constant τ can be calculated using the formula below

τ= RC

Where R= resistance

C = capacitance

Then making RESISTANCE subject of formula we have

R=τ/C

But Capacitance=25.0-nF = 25×10^25F

Substitute the values we have

R=0.833/25×10^25

=33 .3×10^6 Ω

But can still be converted to M Ω= 33.3M Ω

Therefore, the resistance is 33 .3×10^6 Ω or 33.3M Ω

NOTE: 1M= 10^6

The value of the resistance will be "3.33×10⁷ Ω".

According to the question,

Capacitor, C = 25.0 nF

60 sec - 72 fires

now,

Time for 1 fire,

[tex]t = \frac{60}{72}[/tex]

 [tex]= \frac{5}{6} \ sec[/tex]

Now,

⇒            [tex]V = V_0 (1-e^{-\frac{t}{RC} })[/tex]

     [tex]0.632 V_0=V_0(1-e^{\frac{-\frac{5}{6} }{R.25 n C} })[/tex]

[tex]e^{-\frac{1}{R\times 30\times 10^{-9}} } = 1-0.632 = 0.368[/tex]

                  [tex]= 2.72[/tex]

By taking "log" both sides,

⇒ [tex]ln \ e^{\frac{1}{R\times 30\times 10^{-9}} } = ln \ 2.72[/tex]

hence,

The Resistance be:

⇒ [tex]R = \frac{10^9}{30}[/tex]

       [tex]= 3.33\times 10^7 \ \Omega[/tex]

Thus the above approach is right.

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We know

[tex]\boxed{\sf F_c=\dfrac{mv^2}{r}}[/tex]

[tex]\\ \sf\longmapsto F_c=\dfrac{20(10)^2}{4}[/tex]

[tex]\\ \sf\longmapsto F_c=\dfrac{20(100)}{4}[/tex]

[tex]\\ \sf\longmapsto F_c=\dfrac{2000}{4}[/tex]

[tex]\\ \sf\longmapsto F_c=500N[/tex]

The centripetal force on the truck can be determined from the mass, velocity and the radius of the circular path. The centripetal force acting on the truck is 500 N. Hence, option A is correct.

Centripetal force is a type force acting on an object traveling through a circular path. The centripetal force is the rotational analogue of the linear force.

The centripetal force acting on an object is related to the mass, velocity and radius of the circular path is given by:

Fc =  mv ²/r

Given that, mass of truck = 20 Kg

radius of circle = 4 m

velocity = 10 m/s

Then, centripetal force Fc = 20 kg ×  10² m/s / 4 m = 500 N

Therefore, the centripetal force on the truck is 500 N.

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Answer:

λ = 2.5m

Explanation:

Given the following :

Speed of sound (v) = 10m/s

If 5 oscillations pass through a point in 0.5seconds;

Time taken (period) for 1 oscillation is :

Number of oscillations / total time taken

5 / 0.5 = 0.25 seconds

Wavelength, period and Velocity are related by the formula:

v = λ / T

λ = v * T

λ = 10 * 0.25

λ = 2.5 m

Explanation:

To find the average of these numbers, we just have to add the three numbers together and divide by 3.

Explanation:

Because the temperature and the radiation are not correlated, they're not represented as functions of each other, they're represented as independent variables thus using graph 5 you cannot figure out how one affect another

Answer:

It doesn’t show how temperature and radiation relate to each other. It’s difficult to draw conclusions from data that’s separated this way.