I legit forgot how to do this I need help with this

Answer: 1/2

Step-by-step explanation:

Scale factor = (image)/(preimage) = 6/12 = 1/2

Answer:

Triangles MNP and QRS

Step-by-step explanation:

This is due to each corresponding line follows the same ratio of 1.5:1

e.g.

NP=6

RS=4

6:4

1.5:1

You can verify this by dividing 6 by 4 (6/4) which is 1.5

Answer:

(–4, 5) and (–2, 1)

Step-by-step explanation:

Answer: A: (-4,-3) (-2,1)

Step-by-step explanation:

I got this correct on the test. Using the substitution method give brainliest

Answer:

3n+1

Step-by-step explanation:

Subtract one from all the values, you get multiples of 3 in the equation 3n=nth term

So when you add one back, your equation is 3n+1=nth term

Answer:

f(t)=250(1-0.12)^t

or

f(t)=250(0.88)^t

Step-by-step explanation:

Use the formula f(t)=P(1+b)^t

Plug in the information.

f(t)=250(1-0.12)^t

or

f(t)=250(0.88)^t

The only thing I did in the second equation is I subtract 0.12 from 1.

Hope this helps!

Answer:

Step-by-step explanation:

hello :

4lnx - 8 = 12

4lnx - 8 +8= 12+8

4lnx =20

lnx =5

coclusion : x =e^5

A. x = 148.4

Step-by-step explanation:

pythogoras theorem = Q²=P²+R²

P=P

Q= 57.6

R=33.8 =

(57.8)²=(P)²+(33.8)²

=3,340.84=(P)²+1142.44

=3340.84-1142.44=P²

=2,198.4=P²

[tex] = \sqrt{2198.4} = p \\ = 46.8 = p[/tex]

The surface area of the composite figure shown in the figure attached is 233.6 cm²

An equation is an expression that shows the relationship between two or more numbers and variables.

The surface area of the composite = (6 * 8) + 2(8 * 3.6) + 2(0.5)(6 + 2 + 6 + 2)(3) + (8)(2 + 6 + 2) = 233.6 cm²

The surface area of the composite figure shown in the figure attached is 233.6 cm²

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[tex] \boxed{ \sf{ \color{purple}\huge Answer :}}[/tex]

[tex] \: \: [/tex]

[tex] \large \tt \purple↪ \: \: \: \: \: 5x - 16 = x + 10 [/tex]

[tex] \: \: [/tex]

[tex]\large \tt \purple↪ \: \: \: \: \:5x - x = 10 + 16 [/tex]

[tex] \: [/tex]

[tex]\large \tt \purple↪ \: \: \: \: \: 4x = 26[/tex]

[tex] \: [/tex]

[tex]\large \tt \purple↪ \: \: \: \: \: x = \cancel\frac{26}{4} [/tex]

[tex] \: \: [/tex]

[tex] \underline{ \boxed{\large \tt \purple↪ \red{ \: \: \: \: x = \frac{13}{2} }}}{ \large✓}[/tex]

[tex] \: \: [/tex]

hope helps ~

The probability that a kid who goes to the doctor has a sore throat given that he has a fever is 0.30 or 30%. Computed using conditional probability.

The probability of any event A given that event B has already taken place is found using the formula P(A|B) = P(A ∩ B)/P(B). This is known as conditional probability, where P(A ∩ B) is the probability of events A and B, and P(B) is the probability of event B.

In the question, we are given that 70% of kids who visit a doctor have a fever and 21% of kids have a fever and sore throats.

We are asked to find the probability that a kid who goes to the doctor has a sore throat given that he has a fever.

We suppose the event of going to the doctor while having a fever to be B, and going to a doctor while having a sore throat to be A.

We are given that 70% of kids who visit a doctor have a fever, that is, the probability of event B, P(B) = 70% = 0.7.

We are given that 21% of kids who visit a doctor have a fever and sore throats, that is, the probability of event A and event B, P(A ∩ B) = 21% = 0.21.

We are asked to find the probability that a kid who goes to the doctor has a sore throat given that he has a fever, that is, we are asked to find the conditional probability of event A, when event B has already taken place, that is, P(A|B).

By formula, we know that:

P(A|B) = P(A ∩ B)/P(B) = 0.21/0.70 = 0.30.

Thus, the probability that a kid who goes to the doctor has a sore throat given that he has a fever is 0.30 or 30%.

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The equation which represent the interpretation of the scenario is 5 + 2x

Total laws mowed = Number of lawns Homer mowed + (Additional laws mowed each month × Number of months)

= 5 + (2 × x)

= 5 + 2x

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The correct expression is 1 Over 5 x Superscript minus 8 Baseline y Superscript minus 13 Baseline endFraction.

Given expression [tex](3x)^-6*y^-3/ 15x^2*y^10[/tex]

Lets simplify the equation:

[tex]= > (3x)^-6*y^-3/ 15x^2*y^10\\=1/5 x^-8*y^-13[/tex]

Expression:

An expression is a sentence with a minimum of two numbers or variables and at least one math operation. This math operation can be addition, subtraction, multiplication, or division. The structure of an expression is: Expression is (Number/Variable, Math Operator, Number/Variable)

Hence the correct expression is 1 Over 5 x Superscript minus 8 Baseline y Superscript minus 13 Baseline EndFraction.

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Answer:

a₅ = 80 , [tex]a_{n}[/tex] = 5[tex](2)^{n-1}[/tex]

Step-by-step explanation:

to find a term in the geometric sequence multiply the previous term by r

a₁ = 5

a₂ = a₁ × 2 = 5 × 2 = 10

a₃ = a₂ × 2 = 10 × 2 = 20

a₄ = a₃ × 2 = 20 × 2 = 40

a₅ = a₄ × 2 = 40 × 2 = 80

the nth term of a geometric sequence is

[tex]a_{n}[/tex] = a₁ [tex](r)^{n-1}[/tex]

here a₁ = 5 and r = 2 , then

[tex]a_{n}[/tex] = 5 [tex](2)^{n-1}[/tex]

The probability that no two consecutive heads will occur is 13/32.

It should be noted that probability simply means the likelihood of the occurence of an event based on chance.

In this case, the fair coin is tossed 5 times and we simony want it find the probability that no two consecutive heads will occur.

This will be:

Let n be the number of strings of h

Let t be the length n with two adjacent H's.

Therefore, the probability will be:

= (8+5)/2^5

= 13/32

In conclusion, the probability that no two consecutive heads will occur is 13/32.

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Answer:

502.5

Step-by-step explanation:

C = 24(12) + 5.50(39)

C = 288 + 214.5

C = $502.5

Answer: 18

Step-by-step explanation:

Opposite angles of a rhombus are congruent, so

[tex]5 \times 25=7x-1\\\\125=7x-1\\\\126=7x\\\\x=18[/tex]

Answer:

15.2

Step-by-step explanation:

The explanation is in the photo.. but basically this question is about similar triangles and you need to find the scale factor to find the height.

Hope it helps

the height of the tree is approximately 15.2 meters.

To find the height of the tree, we can set up a proportion between Andrew's height and the height of the tree based on their respective shadow lengths.

Let's denote the height of the tree as "h" meters.

The proportion between the height and shadow lengths can be written as:

h / 28.0 = 1.9 / 3.5

Now, we can solve for "h":

h = (1.9 / 3.5) * 28.0

h ≈ 15.2 meters

To the nearest tenth of a meter, the height of the tree is approximately 15.2 meters.

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The coefficient of (3y² + 9)5 is 15.

A polynomial is of the form a₀xⁿ + a₁xⁿ⁻¹ + a₂xⁿ⁻² + ... + aₙ₋₁x + aₙ.

Here, x is the variable, aₙ is the constant term, and a₀, a₁, a₂, ..., and aₙ₋₁, are the coefficients.

a₀ is the leading coefficient.

In the question, we are asked to identify the coefficient of (3y² + 9)5.

First, we expand the given expression:

(3y² + 9)5

= 15y² + 45.

Comparing this to the standard form of a polynomial, a₀xⁿ + a₁xⁿ⁻¹ + a₂xⁿ⁻² + ... + aₙ₋₁x + aₙ, we can say that y is the variable, 15 is the coefficient, and 45 is the constant term.

Thus, the coefficient of (3y² + 9)5 is 15.

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Using the surface area formula for rectangular and triangular prism, the surface area of the composite figure is: 444 m².

Total surface area = surface area of the top triangular prism + surface area of the bottom rectangular prism - area of the surface both share together.

Surface area of the top triangular prism = (S1 + S2+ S3)L + bh = (10 + 10 + 16)5 + (16)(6) = 276 m².

Surface area of the bottom rectangular prism = 2(wl + hl + hw) = 2·(5·16+4·16+4·5) = 328 m²

Area of the surface both share together = 2(16)(5) = 160 m²

Total surface area = 276 + 328 - 160 = 444 m².

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Mathew's speed of 100 m/min, and the distance of 10 m. east to which he is blown by the wind gives the angle in degrees Mathew is blown off his path as approximately 2.86°.

The given parameters are;

Speed at which Mathew is flying = 100 m/min

Distance and direction in which the strong wind blows him = 10 m. east

Time it takes the wind to deflect Mathew by 10 m. = 2 minutes

Therefore;

Speed and direction of the wind = 10/2 m/min east

Speed and direction of the wind = 5 m/min east

Mathew's flight path can be represented using a vector diagram (please see attached drawing)

Distance Mathew travels in 2 minutes = 100 m/min × 2 minutes = 200 m.

Tangent of the angle by which Mathew is off his flight path, A, can be found as follows;

tan(A) = 10/200 = 1/20

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The probability that exactly one tank in the sample contains high-viscosity material is P(A) = 0,4607 or P(A) = 46,07 %

P(A) = Number of favorable events/ Total number of events FE/TE

If A and B are complementary events ( the sum of them is equal to 1) then:

P(A) = 1 - P(B)

The total number of events is:

C ( 24,4) = 24! / 4! ( 24 - 4 )!    ⇒  C ( 24,4) = 24! / 4! * 20!

C ( 24,4) = 24*23*22*21*20! / 4! * 20!  

C ( 24,4) = 24*23*22*21/4*3*2C ( 24,4) = 24*23*22*21/4*3*2    ⇒  C ( 24,4) =  10626

TE = 10626

Splitting the group of tanks in two 6 with h-v  and 24-6 (18) without h-v

we get that total number of favorable events is the product of:

FE = 6* C ( 18, 3)  = 6 * 18! / 3!*15!  =  18*17*16*15!/15!

FE =  4896

Then P(A) ( 1 tank in the sample contains h-v material is:

P(A) = 4896/10626

P(A) = 0,4607     or   P(A) = 46,07 %

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Answer:
slope: -1/3

Y-intercept: 0

Step-by-step explanation:

The line crosses the y-axis at 0, and the pibe decreases by 1 down and goes to the side by 3, using rise over tu it would be -1/3

I hope it helps! Have a great day!

Pan~

Answer:

Slope: -1/3

Y-intercept: 0

Step-by-step explanation:

I hope it helps! Have a great day!

bren~

The coordinate pair that represents the volume and cost of the extra-large size is (24, 8).

A coordinate plane is a plane that can be used to represent the position of a point. The plane consists of x-axes and y-axes. The position of a point is referenced from the origin.

The small size of a pizza is represented by the coordinate pair (8, 4) ⇒ (volume, cost)

Since the volume of the extra-large size will have three times the volume of the small size, hence:

Volume of extra-large size = 8 * 3 = 24

The cost of an extra large is twice as much as the small size, hence:

Cost of extra large = 4 * 2 = 8

A coordinate plane is a graphing and outline machine for factors and lines. A vertical (y) axis and a horizontal (x) axis make up the coordinate plane. There are four quadrants inside the coordinate plane. The point at which these strains join is known as the starting place (0, zero).

Coordinates are written as (x, y) meaning the point on the x-axis is written first, followed by the point on the y-axis. a few children can be taught to keep in mind this with the phrase 'along the hall, up the stairs, that means that they must observe the x-axis first after which the y.

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Answer:

<1 =73

Step-by-step explanation:

The sum of the angles of a triangle add to 180 degrees

72+ 35 + <1 = 180

Add like terms

107 + <1 = 180

Subtract 107 from each side

<1 = 180-107

<1 =73

F(x)= 2(x-2)^2 + 2 is the correct equation of F(x)

A quadratic function is a polynomial function of the second degree. The general form of a quadratic function is this: f (x) = ax^2 + bx + c, where a, b, and c are real numbers and a≠ 0.

Graphs of quadratic functions

The term "parabola" refers to the graph of a quadratic function. A parabola essentially resembles the letter "U," yet it can be inverted or exactly this shape depending on the situation. The leading coefficient determines whether the graph of a quadratic function opens up or down; if it is more than zero, the parabola opens up; if it is less than zero, the parabola opens down.

It is given that graph of F(x), shown below, resembles the graph of G(x) = x^2, but it has been changed somewhat.

We need to find the equation of F(x)

In the figure, parabola opens up, the leading coefficient is greater than zero ,So option (d) is correct

Hence the equation of F(x) is 2(x-2)^2 + 2

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The slope of y = 3x - 4 on the interval [2, 5] is 3 and the slope of y = 2x^2-4x - 2 on the interval [2, 5] is 10

The interval is given as:

x = 2 to x = 5

The slope is calculated as:

[tex]m = \frac{y_2 -y_1}{x_2-x_1}[/tex]

16. y = 3x - 4

Substitute 2 and 5 for x

y = 3*2 - 4 = 2

y = 3*5 - 4 = 11

So, we have:

[tex]m = \frac{11 - 2}{5 - 2}[/tex]

[tex]m = \frac{9}{3}[/tex]

Divide

m = 3

Hence, the slope of y = 3x - 4 on the interval [2, 5] is 3

17. y = 2x^2-4x - 2

Substitute 2 and 5 for x

y = 2 * 2^2 - 4 * 2 - 2 = -2

y = 2 * 5^2 - 4 * 5 - 2 = 28

So, we have:

[tex]m = \frac{28 + 2}{5 - 2}[/tex]

[tex]m = \frac{30}{3}[/tex]

Divide

m = 10

Hence, the slope of y = 2x^2-4x - 2 on the interval [2, 5] is 10

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The cities such that this path is [tex]C_{1}[/tex] → [tex]C_{2}[/tex] → [tex]C_{3}[/tex] . . . → [tex]C_{n}[/tex]. Now, if all roads are going towards [tex]c_{n}+1[/tex], then add  [tex]c_{n}+1[/tex] at the end of this path. Otherwise, let [tex]C_{i}[/tex] be the first city in this path such that there is a road from  [tex]C_{i}[/tex]-1 to  [tex]c_{n}+1[/tex] and from  [tex]c_{n}+1[/tex] to  [tex]C_{i}[/tex]. Place  [tex]c_{n}+1[/tex] between  [tex]C_{i}[/tex]−1 and  [tex]C_{i}[/tex] to get the desired path.

Mathematical Induction is a technique of proving a statement, theorem or formula which is thought to be true, for each and every natural number n. By generalizing this in form of a principle which we would use to prove any mathematical statement is 'Principle of Mathematical Induction'.

The question says that between any two cities X and Y, either there’s an

one-way road from X to Y or from Y to X, but not both. Then show that

there is a path from some city A which visits all the cities exactly once.

This problem is very similar to the Football league problem #7 in Homework 1. This problem can be modeled as a directed graph in which cities

are represented as vertices and there’s an edge from vertices X to Y if

there’s a road from cities X to Y. And then, our goal is to find a path

in this graph which visits every vertex in the graph.

The rest of the solution is very similar to the argument in Problem 7 of

homework 1. We use induction of number of cities, say n.

As a base case, if n = 2, there are only two cities X and Y and the path

is simply the edge between X and Y.

For induction hypothesis, assume that the statement is true for any set

of n cities. That is’ for any set of n cities, we can find a path which visits

all the cities exactly once.

Let’s prove the statement for n + 1 cities. Leave out n + 1 th city (say,

[tex]c_{n}+1[/tex]) and for the remaining n cities, by induction hypothesis, we can find a path which visits all these n cities exactly once. Let us label the cities such that this path is [tex]C_{1}[/tex] → [tex]C_{2}[/tex] → [tex]C_{3}[/tex] . . . → [tex]C_{n}[/tex]. Now, if all roads are going towards [tex]c_{n}+1[/tex], then add  [tex]c_{n}+1[/tex] at the end of this path. Otherwise, let [tex]C_{i}[/tex] be the first city in this path such that there is a road from  [tex]C_{i}[/tex]-1 to  [tex]c_{n}+1[/tex] and from  [tex]c_{n}+1[/tex] to  [tex]C_{i}[/tex]. Place  [tex]c_{n}+1[/tex] between  [tex]C_{i}[/tex]−1 and  [tex]C_{i}[/tex] to get the desired path.

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Answer:

Step-by-step explanation:

jello :

3x=2(mod4)

multiply by ; 5

5×3x=5×2(mod4)

15x=10(mod4)

but : 15= -1 (mod4)   and 10= 2 (mod4)

-x=2 (mod4)

now multiply by ; -1 you have :  x= -2 (mod4)

-2=2(mod4)

conclusion : x=2 (mod4)  means : x=4k+2   k in Z