I need help fast hurry

I Need Help Fast Hurry

Answers

Answer 1

Sound waves are mechanical waves. They need a medium for propagation. In air the sound waves will travel smoothly and we can get it. Whereas  in vacuum, no medium is there and the sound waves cannot propagate.No sound can be produced there.

What is mechanical waves?

Mechanical waves are waves propagating through a medium such as air, water etc. There are two types of mechanical waves namely transverse wave and longitudinal waves.

In transverse waves, the vibration of particles is in a direction perpendicular to the wave whereas, in longitudinal waves,  both are in one direction. Sound wave is a longitudinal wave.

Unlike electromagnetic waves mechanical waves cannot be travelled in vacuum. Hence if we try to produce sound in space or vacuum,no effect will be there but in air and water sound waves can be propagated.

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Related Questions

A football player runs due east for 30 yards then cuts up the field due north for a
distance of 35 yards before running into the end zone.
What is the total displacement of the football player?

Answers

You may find out an object's total displacement—or how far it is from its point of origin—by using the football player's total displacement, d=46.10yd,definite integral of velocity function of an item.

Is the overall displacement equivalent to the distance?

It's common for people to believe that distance & displacement are really just different labels for the same thing. Displacement and distance are different ideas, though. The overall distance traveled by an object during its voyage will be more than the displacement between those two points if it changes direction.

How is displacement volume calculated?

In terms of its density and volume, the displaced fluid's mass can be stated as m = V. W = mg, where g is the acceleration due to gravity, is the weight of the fluid that has been displaced. As a result, W = Vg can be used to indicate the weight of the displaced fluid.

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A ball rolls down a hill with a constant acceleration of 2 m/. The ball starts at rest and
travels for 4.0 s before it stops
2.-What was the ball's velocity just before it stopped?
a) 2.0 m/s.
b) 8.0 m/s
c)12 m/s
d) 16 m/s

Answers

According to the given statement The ball's velocity just before it stopped was  8.0 m/s.

The correct option is B.

What is acceleration?

The rate at which velocity and speed change over time is referred to as acceleration. When anything moves faster or slower, it is said to be accelerating or decelerating in a straight line. Even if the speed remains constant, moving in a circle quickens because the direction is always changing.

Is acceleration a speed?

A increase in an object's orientation or speed is referred to as acceleration. Acceleration is the term for the pace at which speed changes. Don't forget that velocity is made up of two components: direction and speed.

Briefing:

The definition of acceleration comes first

a = v[tex]_f[/tex] - v[tex]_o[/tex] /t

2 = v[tex]_f[/tex]- 0/4

v[tex]_f[/tex]= 8 m/s

After 4 seconds, the ball will be moving at a speed of 8 m/s.

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A truck has a speed of 14 m/s. How far will the truck go in 3 minutes? O a 18,650 meters 42 meters 4.7 meters 1640 meters 2520 meters​

Answers

Answer:2,520

Explanation: The truck goes 14 meters per second

Since it is traveling for 3 minutes which is 180 seconds, all you need to do is times the 180 seconds with the 14 meters. :)

Cory is studying the relationship between the temperature (T) of water, and the volume (v) of a certain gas that can dissolve in the water. He comes up with the following equation that describes the relationship: v = 0.036T+0.21. What is the qualitative relationship that describes this quantitative relationship?

Answers

The relationship that would be able to describe this is that the gas does not dissolve into the water at a temperature below -5.83 units.

What is a quantitative relationship?

This is the term that is used to refer to the data types that includes Numbers such as weight, cost, and measurements

What is qualitative data?

The descriptive and conceptual information gathered through surveys, interviews, or observation is referred to as qualitative data.

With a slope of 0.036, the volume v varies linearly with temperature T.

Volume v grows by 0.036 units for every unit increase in temperature as a result.

The volume of the gas dissolved in water is 0.21 units when the water's temperature is zero.

The smallest volume that is feasible is 0 because the volume cannot be negative. At a certain temperature, this occurs. This is the temperature at that time. Let's refer to it as Tc.

we have

Tc = -0.21 / 0.036

= -5.83

This means that the gas does not dissolve into the water below a temperature of -5.83 units.

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A type of toy catapult consists of a movable plunger which has a spring attached as shown above. The handle was pulled down to fully compress the spring and on release the metal ball of mass 0.1 kg (weight 1 N) was projected 0.75 m vertically. ai What type of energy is stored in a compressed spring? [1 ii What happens to this stored energy when the handle of the plunger is released?
A i. what happens to this stored energy when the handle of plunger is released?

Answers

iam for su

r it is A

Explanation:

ertically. ai What type of energy is stored in a compressed spring? [1 ii What happens to this stored energy when the handle of the plunger is released?

A i. what

alex is pushing a heavy box.The force he exerts is represented by the white arrow. In order to make his task easier in which direction should an additional force be applied?

Answers

Answer:

The other arrow/force should be in the same direction that Alex is pushing the heavy box.

Explanation:

If Alex is pushing the heavy box to the right, then another person helping him that is also pushing the heavy box to the right would lessen the amount that he has to push.

Pls solve the first question for me

Answers

Answer:

which question

Explanation:

please explain better

Part F
Imagine you were a sportscaster at the Olympics. You'd created a mathematical model similar to the one you just did. Imagine that you had a
computer program that could do an instantaneous analysis of video motion using that model. How could you use it in your sportscast?

Answers

A program that could do an instantaneous analysis of video motion will be useful it in a sportscast to analyze events as they occur.

Why will a program be needed?

A motion video is defined as the display of video images at a rate (such as thirty frames per second) that causes objects to appear to move smoothly and continuously.

Sports inherently involve fast and accurate motion, which can be difficult for competitors to master but also for coaches and trainers to analyze and audiences to follow. Because of the nature of most sports, monitoring with sensors or other devices attached to players or equipment is generally not possible. This opens up a plethora of opportunities for the use of computer vision techniques to assist competitors, coaches, and the audience

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A child can throw a baseball at 20 mph. Some professional ball players can throw a baseball at 100 mph, which is five times as fast. How much more energy does the pro ball player give to the faster ball?

Answers

The ball is 25 times more energetic when it is thrown by the professional then when it is thrown by the child.

What is the ratio of the energy?

Basically we ought to be reminded that the kinetic energy of the object is the energy that is possessed by the object by virtue of the fact that the object is in motion.

We have to recall that the kinetic energy is given by;

KE = 1/2 mv^2

m = mass of the object

v = velocity of the object

Since the mass of the object is held the same let us take note of the speed with which the ball is thrown by the student and the professional respectively

Speed of the student =  20 mph or 8.9 m/s

Speed of the professional = 100 mph or 44.7 m/s

Energy of the ball by the student = 0.5 * m * (8.9)^2

Energy of the ball by the professional = 0.5 * m * (44.7)^2

We now have;

0.5 * m * (44.7)^2/0.5 * m * (8.9)^2

25 times

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A car accelerated uniformly from rest and attained a velocity of 8m/s. it then travels with the uniform velocity of for the next 22 seconds and later brought to rest in 5 seconds
(a )draw the velocity time graph
(b.) calculate the total distance covered (c.) calculate the distance covered after 25 seconds.​

Answers

Answer:

See below

Explanation:

See diagram below

8 seconds to 60 m/s     then    60 m/s for 22 seconds then   to 0 m/s in 5 seconds

A light ray travelling from diamond into air has an angle of refraction of 56. A piece of glass is then placed right next to the diamond. Explain how the angle of refraction will change now that the light is moving from diamond into glass instead of air

Answers

The angle of refraction of a light ray travelling from diamond into air has an angle of refraction of 56 will decrease now that the light is moving from diamond into glass instead of air.

When a light ray travels from rarer medium to a denser medium, the refracted ray tends to move towards the normal. So angle of refraction < angle of incidence. When a light ray travels from denser medium to a rarer medium, the refracted ray tends to move away from the normal. So angle of refraction > angle of incidence.

Glass is denser than air. So the angle of refraction will be higher for air than the angle of refraction of glass. So, when the medium is changed from air to glass, the angle of refraction will decrease.

Therefore, the angle of refraction of a light ray travelling from diamond into air has an angle of refraction of 56 will decrease now that the light is moving from diamond into glass instead of air.

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What is the approximate tangential speed of an object orbiting Earth with a radius of 1.8 × 108 m and a period of 2.2 × 104 s?

Answers

The approximate tangential speed of an object orbiting Earth with a radius of 1.8 × 108 m and a period of 2.2 × 104 s is  5.34 m/sec.

What is speed?

The speed of an object is the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.

Given in the question an object orbiting Earth with a radius of 1.8 × 108 m and a period of 2.2 × 104 s, tangential speed is ,

v = [tex]2\pi*r[/tex]/t

v = 2*3.14*1.8*108/2.2*104

v = 5.34 m/sec.

The approximate tangential speed of an object orbiting Earth with a radius of 1.8 × 108 m and a period of 2.2 × 104 s is  5.34 m/sec.

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URGENTTTT
Referring to the graph in the section header, what was his displacement between 100 and 300 seconds?


Referring to the graph in the section header, what was the runner's velocity during segment D?

Answers

The displacement of the runner according to the graph is obtained as 250 m.

What is the displacement?

The term displacement has to do with the distance that is covered in a specified direction. The difference between distance and displacement is that displacement is a vector while distance is a scalar quantity.

Thus we bring the direction into play when we are talking about the displacement of the object. Now we have a graph that shows the displacement of the runner in the vertical axis and then shows the time that is taken in the horizontal axis.

Given the graph as we have it, we can be bale to pick out the following from the graph;

1) Displacement of the runner at 100 s = 500 m

2) Displacement of the runner at 300 s = 750 m

Therefore;

Displacement of the runner between 100 and 300 seconds;

750 m - 500 m = 250 m

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In an arcade game a 0.097 kg disk is shot
across a frictionless horizontal surface by compressing it against a spring and releasing it.
If the spring has a spring constant of
166 N/m and is compressed from its equilibrium position by 5 cm, find the speed with
which the disk slides across the surface.

Answers

Answer:

Explanation:

Mass of disk = 0.14 kgSpring constant = 155 N/mLength = 4 cmWe need to calculate the speed Using energy conservationWhere, k = spring constantx = compressed lengthm = mass of the discPut the value into the formulaHence, The speed with which the disk slides across the surface is 1.33095 m/s.

a race car is traveling in a uniform circular motion around a race track what happends to the radial aceleration of the car if the velocity is dobled and the radio od the circel is half

Answers

A race car is traveling in a uniform circular motion around a race track, the radial acceleration of the car when the velocity is doubled and the radius of the circle is halved will increase by a factor of 8 (Option D)

What is radial acceleration?

To arrive at the above conclusion, we must recall that radial acceleration is defined by:

Ac = v²/r; where

Ac - is the magnitude of radial acceleration

v -  is the linear or tangential speed

r - is the radius of the circular path

A′c -  is the new magnitude of the radial acceleration.

Given that the linear velocity is duplicated and simultaneously the radius is split in two, then the new radial acceleration increases by a factor of 8, according to the following calculation:

A'c = (2v²)/(0.5r)

= 4v²/(0.5r)

= 8 · (v²/r)

= 8 · Ac

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Full Question:

A race car is traveling in a uniform circular motion around a race track what happens to the radial acceleration of the car if the velocity is doubled and the radius of the circle is halfed?

A. It remains the same.

B. It increases by a factor of 2.

C. It increases by a factor of 4.

D. It increases by a factor of 8.

E. It decreases by a factor of 2.

Mars had an orbital period of 1.88 years. In two or more complete sentences,explain how to calculate the average distance from mars to the sun, then calculate it

Answers

The average distance from mars to the sun if Mars had an orbital period of 1.88 years is 2.27 * [tex]10^{8}[/tex] km

P² = a³

P = Orbital period

a = Average distance

P = 1.88 years

a³ = 1.88²

a³ = 3.53

a = 1.52 AU

a = 1.52 * 1.496 * [tex]10^{8}[/tex] km

a = 2.27 * [tex]10^{8}[/tex] km

The formula used to solve the given problem is derived from Kepler's third law of planetary motion. AU is the abbreviated from of Astronomical unit. 1 AU = 1.496 * [tex]10^{8}[/tex] km

Therefore, the average distance from mars to the sun is 2.27 * [tex]10^{8}[/tex] km

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In each of three trials of an investigation, a single force is applied to a mobile. Each time, the mobile acquires a different acceleration. The table shows the relationship between the acceleration and the acting force.
Which phrase best describes a graph that would represent the relationship shown in the table?
O a downward-sloping line drawn on a graph with acceleration shown on the y-axis and force shown on the x-axis
B) a downward-sloping line drawn on a graph with acceleration shown on the x-axis and force shown on the y-axis
C) an upward-sloping line drawn on a graph with acceleration shown on the x-axis and force shown on the y-axis
D) an upward-sloping line drawn on a graph with acceleration shown on the y-axis and force shown on the x-axis​

Answers

The best representation of the graph is an upward-sloping line drawn on a graph with acceleration shown on the y-axis and force shown on the x-axis​. Option D

What is the relationship between the force and the acceleration?

We know that there is a direct relationship between the force and the acceleration of the object. According to the Newton second law, when force is applied to an object. The object would acquire an acceleration. In order words, the force that acts on the body is able to increase  the speed of the object.

If we look at the table that was shown in the question that we have attached here, you would notice that as the force that acted on the object was increased, there was a commensurate increase in the acceleration of the object as seen.

This goes on to buttress that the relationship between the force and the accaleration is a direct relationship. This also tell us that we will have a graph that runs upwards and not downwards!

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Determine the distance Covered by a body is 5 Second, if it initial velocity is 30mls and acceleration 5. om/s​

Answers

The distance is 212.5m.

Please help me asap with all I’ll mark you brainly

Answers

The point that represents maximum potential energy is W.

The point that represents potential energy at 0 joules is Z.

The point that represents potential energy at 50 percent is Y.

The point that represents maximum kinetic energy is X.

Potential energy is the energy held through an object because of its function relative to other items, stresses inside itself, its electric-powered fee, or different elements. potential energy is energy this is saved – or conserved - in an object or substance. This saved energy is based totally on the position, arrangement, or state of the object or substance.

Potential energy refers to the stored energy within an object that exists because of the item's role, country, or arrangement. Potential energy is the strength this is stored in an item because of its function relative to some 0 roles. An item possesses gravitational capability strength if it is located at a top above (or beneath) the zero top.

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The design of a new road includes a straight stretch that is horizontal and flat but that suddenly dips down a steep hill at 18°. The transition should be rounded with what minimum radius so that cars traveling 95 km/h will not leave the road

Answers

Answer:

  74.7 m

Explanation:

You want the minimum radius of curvature of a vertical circular arc so that vehicles traveling 95 km/h making the transition from horizontal to an 18° down grade will not leave the road.

Acceleration

The acceleration due to gravity on the vehicle at the point it is traveling 18° down is ...

  g·cos(18°) ≈ (9.8 m/s²)·0.95106 ≈ 9.32 m/s²

Radius

The radius of an arc and the speed of travel are related to the normal acceleration by ...

  r = v²/a

where v is the speed along the arc, and 'a' is the normal acceleration required to make an object follow the circular curve.

The speed of 95 km/h can be translated to m/s by ...

  (95 km/h) · (1000 m/(1 km)) · (1 h)/(3600 s) = 95/3.6 m/s ≈ 26.389 m/s

Radius

Using the above relation to find the radius, we get ...

  r = (26.389 m/s)²/(9.32 m/s²) ≈ 74.72 m

The minimum radius of the vertical circular arc should be 74.7 meters to prevent vehicles from becoming airborne.

__

Additional comment

In actual roadway design, factors of sight distance and stopping distance come into play. Sight distance over this crest would be about 25 m. It would need to be more than 6 times that distance for the roadway to be safe at 95 km/h.

An 18° down grade is about 3 times the usual maximum for roadway design, which will severely increase stopping distance. The vertical arc described here would leave the car with no normal force on the roadway at the end of the arc, so braking would be impossible. Passengers would be feeling weightless, too.

Roadway curves are generally parabolic (not circular), so they have a constant rate of change of slope with horizontal distance.

A student throws a baseball vertically upward and then catches it. What would that graph look like?

Answers

Answer:When the body is thrown upwards, it moves up until the ball's velocity becomes zero and the force exerted on it becomes zero. After that, the ball reaches the ground with acceleration due to gravity with zero speed. When the ball goes up, the height of the ball increases and it also moves up.Formula = v2=u2−2gh ( Body is moving vertically upwards)

The form of energy found in moving objects is ___??

Answers

Answer:

kinetic energy

Explanation:

It is kinetic energy because it is an energy in motion. In order words it is an energy which the body or object moves.

Two forces, F1=(1.65i−0.90j+1.15k) N F2=(−1.00i+1.20j) N are applied on a moving object of mass 0.20 kg. The displacement vector produced by the two forces is d=(10.0i+8.8j+5.1k)m. What is the work done by the two forces?

I need help with this question. please

Answers

Answer:

I don't Know espero que le entiendas

Lucy is cruising through space in her new spaceship. As she coasts along, a tiny spacebug drifts into her path and bounces off the window.

Consider several statements concerning this scenario. Evaluate each statement according to the law of momentum conservation and match it to the appropriate category.

Answers

TRUE: The total change in momentum for this interaction is zero.

FALSE: The change in the space bug's momentum is greater than the change in the spaceship's momentum.

UNDETERMINED: If the space bug had stuck to the spaceship instead of bouncing off, momentum would not have been conserved for this interaction.

aball is through horizontal From The top at buiding the ball lands I00m for building and It takes 4 Second For It to hit The ground Find: A, The Inital horizontal componet OF Velocity ​

Answers

A ball is through horizontal From The top at building the ball lands I00m for building and It takes 4 Second For It to hit The ground . The Initial horizontal component of Velocity ​will be 25 m/s

using kinematic equation

s = u t + 1/2 a [tex]t^{2}[/tex]

since , there is no acceleration in horizontal direction

s = u(x) t + 0

100 = u (x) * 4

u(x) = 100 / 4

      =  25 m/s

The Initial horizontal component of Velocity ​will be 25 m/s

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Honey is a technology company that provides online coupons to its subscribers. Honey's analytics staff has developed a classification method to predict whether a customer who has been sent a coupon will apply the coupon toward a purchase. For a sample of customers, the following table lists the classification model's estimated coupon usage probability for a customer. For this particular campaign, suppose that when a customer uses a coupon, Honey receives $1 in revenue from the product sponsor. To target the customer with the coupon offer, Honey incurs a cost of $0.05. Honey will offer a customer a coupon as long as the expected profit of doing so is positive. Using the equation
Expected Profit of Coupon Offer = P(coupon used) × Profit if coupon used + (1 - P(coupon used)) × Profit if coupon not used
determine which customers should be sent the coupon.

Customer Probability of Using Coupon
1 0.44
2 0.34
3 0.24
4 0.11
5 0.06

Determine the expected profit for each customer. Round your answers to the nearest cent. Enter negative value as negative number, if any.

Customer Expected Profit
1 $
2 $
3 $
4 $
5 $

The expected profit is positive for customers (Select your answer: 2 and 3, 4 and 5, 1, 2, and 33, 4, and 5, 1, 2, 3, and 4, 1, 2, 3, and 5, 2, 3, 4, and 5, 1, 2, 3, 4, and 5) so these customers (Select your answer: should be offered or should not be offered) the coupon.

Answers

The expected profit is positive for the customers 1, 2, 3, 4, 5.

What is expected profit?

This is the term that is used to refer to the gain that would be expected to be gotten based on the fact that a person has engaged in a business.

We have 1 - 0.05 = 0.95 profit if the coupon is used

-0.05 is the profit if the coupon is not used

for consumer 1

the probability = 0.44

expected profit = 0.44 x 0.95 - 0.05 x 0.56

= 0.418 - 0.028

= 0.39

for consumer 2

the probability = 0.34

expected profit = 0.34 x 0.95 - 0.05 x 0.66

= 0.323 - 0.033

= 0.29

For consumer 3

the probability = 0.24

expected profit = 0.24 x 0.95 - 0.05 x 0.76

= 0.228 - 0.038

= 0.19

For consumer 4

the probability = 0.11

expected profit = 0.11 x 0.95 - 0.05 x 0.89

= 0.1045 - 0.0445

= 0.06

For consumer 5

the probability = 0.06

expected profit = 0.06 x 0.95 - 0.05 x 0.94

= 0.057 - 0.047

= 0.01

The expected profits can be listed as:

0.390.290.190.060.01

The expected profits are positive for all of 1, 2, 3, 4, and 5, hence these customers can purchase the coupon.

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16) What is the acceleration of the ball on its way up?
a) 0m/s
b) 8m/s
c) -9.81m/s^2
d) +9.81m/s

Answers

The acceleration of the ball on it way up is -9.81m/s².

The correct option is C)

What is acceleration?

This is the rate of change of velocity with respect to time. The speed and direction of the accelerating object are also very important. It unit is meters per second square, m/s².

What is Gravity?

This is the force that pulls a body toward the center of the earth. This force causes objects to fall freely. This free-falling object has an acceleration of 9.8m/s downward the earth. This is called acceleration gravity.

What is velocity?

This refers to the speed at which an object moves in a given direction. It unit is meters per second, m/s.

Recall that the direction of motion is assumed to be the positive direction. Other parameters depend on the direction of motion. Hence for upward acceleration, the direction of motion is positive but the acceleration due to gravity is negative because the direction is downwards.

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A falling object with a mass of 2.55 kg encounters 4.0 N of air resistance. What is the acceleration of the object? (Choose up to be the positive direction, and remember the definition of weight).

Question 9 options:

a)

-21 N


b)

-241.0 m/s2


c)

-21.0 m/s2


d)

-8.2 m/s2


e)

8.2 m/s2

Answers

The acceleration of the falling obeject of mass 2.55 kg is  -8.2 m/s². And the right option is d) -8.2 m/s².

What is acceleration?

This can be defined as the rate of change of velocity.

To calculate the acceleration of the object, we use the formula below.

Formula:

a = (R-mg)/m............. Equation 1

Where:

a = Acceleration of the objectm = Mass of the objectR = Air resistanceg = Acceleration due to gravity.

Note: Taking forces acting upward to be positve and downward force to be negatove,

From the question,

Given:

R = 4 Nm = 2.55 kgg = 9.8 m/s²

Substitute these values into equation 2

a = [4-(2.55×9.8)]/2.55a = -20.99/2.55a = -8.2 m/s²

Hence, The acceleration of the object is -8.2 m/s².

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A plane is flying to Minnesota with a velocity of 373.52 km/h, N. The plane encounters a crosswind with a velocity of 64.90 km/h, W. What is the magnitude of the resultant velocity of the plane?

Answers

Answer:

  379.12 km/h N 9.86° W

Explanation:

You want to know the resultant velocity when a plane's velocity of 373.52 km/h N is modified by a crosswind at 64.90 km/h W.

Vector sum

In (N, E) coordinates, the sum of the velocities is ...

  (373.52, 0) +(0, -64.90) = (373.52, -64.90)

The magnitude of this vector is ...

  |v| = √(373.52² +64.90²) ≈ 379.12 . . . . km/h

The direction will be west of north by the angle ...

  θ = arctan(-64.90/373.52) ≈ -9.86° . . . . . . N = 0°, + = clockwise

The resultant velocity is 379.12 km/h N 9.86° W.

IF B is added to Ã, under what Condition does the resultant vector have magnitude equal to A + B ?​

Answers

Answer:

its b and a

Explanation:

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