I need help please?

A. {penguin, seagull, crow}

B.{penguin, seagull, crow, bat, mosquito}

C.{seagull, crow}

D.{seagull, crow, bat, mosquito}

I Need Help Please?A. {penguin, Seagull, Crow}B.{penguin, Seagull, Crow, Bat, Mosquito}C.{seagull, Crow}D.{seagull,

Answers

Answer 1

The Outcome of event A and B is simply the intersection of both sets written as A ∩ B is; C: {seagull, crow}

How to write sets notation?

From the image, we are given the animals namely; Pig, Penguin, Seagull, Tiger, Crow, Bat, Mosquito.

Now, these animals are classified as either a bird or can fly.

Animals that are birds are; Penguin, Seagull, Crow

Animals that can fly are; Seagull, Crow, Bat, Mosquito.

Now, we are told that;

Event A is the animal is a bird. Thus, the set notation that represents this event A is written as;

A = {Penguin, Seagull, Crow}

Event B is that the animal can fly and again the set notation that represents event B is written as;

B = {Seagull, Crow, Bat, Mosquito}

Now, Outcome of event A and B is simply the intersection of both sets. Thus; A ∩ B = {seagull, crow}

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Related Questions

Yolanda paid for her movie ticket using 28 coins, all nickels and quarters. the ticket cost $4. which system of linear equations can be used to find the number of nickels, n, and the number of quarters, q, yolanda used? n q = 28 0.05n 0.25q = 4 n q = 4 5n 25q = 28 n q = 28 5n 25q = 4 n q = 4 0.05n 0.25q = 28

Answers

The system of linear equations can be used to find the number of nickels, n, and the number of quarters, q, yolanda used is n + q = 28

n + q = 280.05n + 0.25q = 4

Simultaneous equation

n + q = 28

0.05n + 0.25q = 4

n = 28 - q

substitute n = 28 - q

0.05n + 0.25q = 4

0.05(28 - q) + 0.25q = 4

1.4 - 0.05q + 0.25q = 4

- 0.05q + 0.25q = 4 - 1.4

0.20q = 2.6

q = 2.6 / 0.20

q = 13

Substitute into

n + q = 28

n + 13 = 28

n = 28 - 13

n = 15

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Quick algebra 1 assignment for 50 points!


Only answer if you know the answer, tysm!



1. Create 5 questions referencing “Relations and Functions” Below is an example of this.

——————————————————————

Example :


Is the set of ordered pairs below a function? Yes or no, explain your reasoning.


{(4,6),(10,-2),(13,7),(15,8),(10,11)}

——————————————————————

2. Answer each question and show a brief step by step process on how you got the answer to each of your questions.

Answers

As per definition

In. a function every domain has an unique range of it

f(x)=y

Here

f(4)=6f(10)=-2f(13)=7d(15)=8f(10)=11

f(10) has two corresponding values hence it's not a function

Question 2: If you were to take a cross-section parallel to the base for one of your items, what shape would
you see? Can a cross-section be a sphere? Explain in two to three sentences.

Answers

The cross-section would be the same shape as the base. A cross-section cannot be a sphere because a cross-section must be two-dimensional, but a sphere is three-dimensional.

HELP PLEASE!)

A square pyramid has surface that is covered in dark glass. The sides of the pyramid are 456 feet in length. The slant height of the pyramid is 185 feet.

Find the lateral surface area to determine the square feet of glass needed to cover the surface of the pyramid.

Answer choices
376,656 ft^2
42,180 ft^2
337,440 ft ^2
168,720 ft^2

Answers

it should be 376,656 ft^2 bc
1. square the bases (456 x 456 = 207936)
2. four triangles 4(1/2 x base x height) which would be 4(1/2 x 456 x 185) = 168720
then add up 168720 + 207936 = 376656
hope this helps :D

6.
Write
√18+10
√2
in the form a+b√√3 where a and b are integers.

Answers

Answer:

3+10 square root of 2

Step-by-step explanation:

[tex](3 + 10) \sqrt{2} [/tex]

4. You read an article in your local newspaper about a discussion between the owner of a popular business and a group
of community members. The business owner keeps a flag raised on an outdoor flagpole during nighttime hours, but
the community members are calling for the flag to be properly illuminated at night. The business owner says that the
flag cannot be illuminated because the only power source available for the spotlights is solar power, but there is too
much shade on the ground for solar-powered spotlights to charge sufficiently during the day.
You realize that you can offer a solution to the problem by suggesting that the solar-powered spotlights be mounted
on the roof of the building where it can be charged by sufficient sunlight. You decide to contact the business owner to
suggest angling the spotlight down to the raised flag from the roof instead of angling it up to the raised flag from the
ground. The business owner informs you that the flagpole is located 55 feet from the building. If the building is 45 feet
high and the flagpole is 25 feet high, at what angle should you tell the business owner to angle a spotlight mounted on
the roof? Please show all your work.

Answers

The business owner should be told to angle a spotlight mounted on the roof at the angle of =39°

Calculation of angle

The distance of the flagpole from the building = 55ft

The building has the height of = 45ft

The flagpole has the height of = 25ft

The angle can be calculated using the formula;

Tan θ = opposite/adjacent

Where opposite= 45ft

adjacent = 55ft

Tan θ = 45/55 = 0.82

θ = Tan–¹0.82

θ = 39°

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Can someone please help me with this similar area question? I have the answer but I’m not sure how to get to it. Will make brainliest!

Answers

Step-by-step explanation:

well there is a very simple point that you have mistaken tho:

484cm², 25cm²

Areas are defined in square cm but the radius is in cm

so:

[tex] \sqrt{ \frac{484 {cm}^{2} }{25 {cm}^{2} } } = \frac{7.92}{r} = = = > 4.4 = \frac{7.92cm}{x} = = > x = \frac{7.92cm}{4.4} = x = 1.8cm[/tex]

and there you go

can someone help me with this thanks ​

Answers

The length of the brace required is 4.3m

What is sine rule?

In a ΔABC a, b and c are the sides and A, B and C are angles then,

[tex]\frac{a}{SinA}=\frac{b}{sinB}=\frac{c}{sinC}[/tex]

We can find the length, l as shown below:

Let AB=3m, BC=2m and AC=l

Let ∠A=25°

So, in ΔABC

[tex]\frac{BC}{sinA}=\frac{AB}{sinC}=\frac{AC}{SinB}[/tex]

[tex]\frac{BC}{sinA}=\frac{AB}{sinC}[/tex]

[tex]\frac{2}{sin25}=\frac{3}{sinC}[/tex]

[tex]\angle{C}=sin^{-1}(\frac{3\times sin25}{2} )[/tex]

∠C=39.34°

∠A+∠B+∠C=180°

∠B=180°-25°-39.34°

∠B=115.66°

[tex]\frac{BC}{sinA}=\frac{AC}{SinB}[/tex]

[tex]\frac{2}{sin25}=\frac{l}{sin(115.66)}[/tex]

[tex]l=\frac{2\times sin(115.66)}{sin25}[/tex]

l=4.2659

Rounding to nearest tenth of meter.

l=4.3m

Hence, the length of the brace required is 4.3m

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If 1 skip equals 4 hops, and 1 jump equals 3 skips, what is the total number of hops in a hop, a skip and a jump

Answers

There are 17 hops in a hop, a skip, and a jump.

How to perform changes of units?

We have the relations:

1 skip = 4 hops.1 jump = 3 skips.

How many hops are in a hop, a skip and a jump?

So we have:

1 hop + 1 skip + 1 jump.

First, using the second relation we rewrite:

1 hop + 1 skip + 3 skips = 1 hop + 4 skips.

Now, using the first relation:

1 hop + 4 skips = 1 hop + 4*(4 hops) = 1 hop + 16 hops = 17 hops.

There are 17 hops in a hop, a skip, and a jump.

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Find the center and radius of the circle with the equation: (x-0^2 + (y+1)^2 = 4

a.
center: (-5, 1)
radius: 4
c.
center: (-5, 1)
radius: 2
b.
center: (5, -1)
radius: 4
d.
center: (5, -1)
radius: 2

Answers

The center and radius of the circle is (b) center: (-5, 1) radius: 2

How to determine the center and the radius?

The circle equation is given as:

(x-5)^2 + (y+1)^2 = 4

The circle equation is represented as:

(x-a)^2 + (y-b)^2 = r^2

Where:

Center = (a,b)

Radius = 4

By comparison, we have:

(a, b) = (-5, 1)

r^2 = 4

This gives

(a, b) = (-5, 1)

r = 2

Hence, the center and radius of the circle is (b) center: (-5, 1) radius: 2

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Suppose that f'(4) = 3 , g'(4) = 7 , g(4) = 4 and g(x) not= to 4 for xnot= to 4 . then cmpute lim xgose to 4 f(g(x))/x-4-f(4)/x-4

Answers

It looks like the limit you want to compute is

[tex]\displaystyle \lim_{x\to4} \frac{f(g(x)) - f(4)}{x-4}[/tex]

Since [tex]g(4)=4[/tex], this limit corresponds exactly to the derivative of [tex](f\circ g)(x) = f(g(x))[/tex] at [tex]x=4[/tex]. Recall that

[tex]f'(a) = \displaystyle \lim_{x\to a} \frac{f(x) - f(a)}{x - a}[/tex]

By the chain rule,

[tex](f\circ g)'(4) = f'(g(4)) \times g'(4) = f'(4) \times g'(4) = 3\times7 = \boxed{21}[/tex]

Since [tex]g'(4)[/tex] exists, [tex]g[/tex] is differentiable at [tex]x=4[/tex] so it must be continuous.

Find the missing segment in the image below.

Answers

Using the proportionality theorem, the length of the missing segment is 25 units.

What is the Proportionality Theorem?

According to the proportionality theorem, the middle segment in the diagram given divides the two sides it intersects proportionally.

Therefore, we would have:

x = missing segment

36/21 = (35 + x)/35

Cross multiply

35(36) = 21(35 + x)

1,260 = 735 + 21x

1,260 - 735 = 21x

525 = 21x

525/21 = x

x = 25

The missing segment is: 25 units.

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Draw a graph of Lin’s distance as a function of time for this situation:



Lin walked a half-mile to school at a constant rate. Five minutes after arriving at school, Lin realized that she had left her permission slip at home. Lin began sprinting home, but when she was halfway there she got tired and walked the rest of the way.

Answers

The graph of Lin's distance as a function of time cannot be a straight line graph because of decrease in speed.

Given that Lin walks half a mile at a constant rate i.e. Lin velocity is constant.

If the speed is low then the time will be high. If speed is high then the time will be low because of the following rule:

Speed=Distance/ time.

For the first five minutes the graph will be upward sloping because he was sprinting and his speed was high so he will cover much more distance.

But after five minutes the graph will be downward sloping as the speed becomes low and he willcover less distance.

Hence the graph of Line's distance will not look like linear curve.

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A random sample of n = 4 scores is obtained from a normal population with m = 30 and s = 8. what is the probability that the sample mean will be smaller than m = 22?

Answers

the probability that the sample mean will be smaller than m = 22 is 0.02275.

For the given question,

A z-score measures exactly how many standard deviations a data point is above or below the mean. It allows us to calculate the probability of a score occurring within our normal distribution and enables us to compare two scores that are from different normal distributions.

Here sample size, n = 4

mean, μ = 30

standard deviation, σ = 8

The probability that the sample mean will be smaller than m = 22 is

z = [tex]\frac{m-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex]

⇒ z =[tex]\frac{22-30}{\frac{8}{\sqrt{4} } }[/tex]

⇒ z = [tex]\frac{22-30}{\frac{8}{2} }[/tex]

⇒ z = [tex]-\frac{8}{4}[/tex]

⇒ z = -2

Refer the Z table for p value,

Thus for P(z < -2) is 0.02275.

Hence we can conclude that the probability that the sample mean will be smaller than m = 22 is 0.02275.

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i need help with this question, thxs

Answers

The item which yield the greatest level of accuracy to the true weight of rock with the least error is bricks.

Rock

A rock refers to a solid substance formed from the fusion of organic minerals.

Types of rockSedimentary rock: They are firmed from sediments, that is, dead plant and animals, silt etc.

Metamorphic rock: They are firmed from previously existing rocks.

Igneous rock: They are formed from the pressure of molten magma.

Therefore, bricks is the item which yield the greatest level of accuracy to the true weight of rock with the least error.

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One factor of the polynomial 3x3 + 20x2 - 21x + 88 is (x + 8). what is the other factor of the polynomial? (note: use long division.)
oa (3x2 - 4x+11)
b. (3x - 4x)
c. (3x2 +11)
d. (3x2 + 4x - 11)

Answers

The other factor of the polynomial is a. 3x2-4x+11

Given polynomial is 3x3 + 20x2 - 21x + 88 and the factor is (x+8)

We need to find another factor using long division method

So,

We will divide the polynomial by the factor to find the another factor

Therefore,

[tex]\sqrt[x+8]{3x^3+20x^2-21x+88}[/tex]

Now calculating

First multiplying [tex]3x^2[/tex] with (x+8) so , [tex]3x^2[/tex] will be in the quotient

We get [tex]3x^3+24x^2[/tex]

simplifying the calculation for [tex]3x^3+20x^2[/tex] and [tex]3x^3+24x^2[/tex]

We get the remainder is [tex]-4x^2-21x+88[/tex]

Second we will multiply -4x with (x+8) Where -4x will be in the quotient

We get [tex]-4x^2-32x[/tex] and then we will simplify the equation

We get 11x +88 as a remainder

The quotient we get is [tex]3x^2-4x[/tex]

Third we will multiply +11 with (x+8) Where +11 will be in the quotient

we get 11x+88

Simplifying the equation we get the remainder 0

So the quotient we get is  (3x2 - 4x+11)

Hence the another factor of the polynomial is  (3x2 - 4x+11)

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You buy 4 health bars and 3 health drinks for $10. your friend buys 6 health bars and 2 health drinks for $10.

Answers

Answer:

The bars cost 1 each and the drinks cost 2 each.

Step-by-step explanation:

Let b = bars and d = drinks

4b + 3d = 10           6b + 2d = 10

There are a few ways to solve this.  If I want to eliminate the b's from both equations.  I would multiple the first equation all the way through by -6 and the second equation all the way through by 4.

4b+ 3d = 10

-6(4b + 3d) =(10)-6   Multiple all the way through by -6

-24b -18d = -60  A positive multiplies by a negative is a negative

6b + 2d = 10  

4(6b + 2d) = (10)4  Multiple all the way through by 4

24b + 8d = 40

Take the two bold equations from above and add them together

-24b - 18d = -60

24 b + 8d = 40  

          -10d = -20  Divide both sides by -10

d = 20 A negative divided by a positive is a negative.

Plug in 2o for d in either of the top two equations and get b = 1.

Select the correct answer from each drop-down menu.
Given: line AB ||line DC and DF_~BF
Prove: DFC _~BFA

Answers

Angles are formed when two or more lines intersect. Angles are majorly measured in degrees.

The required proof is as shown below:

Whenever a transversal passes through two parallel lines, angles are formed which have some similar properties.

             STATEMENTS                                           REASONS

1. AB ║DC                                                          Given.

2. < FDC ≅ < FBA                                              Alternate angle theorem.

3. <AFB  ≅ < DFC                                              Vertical opposite angle rule.

4. DF ≅ BF                                                         Given

5. ΔDFC  ≅ Δ BFA                                            Angle-Angle-Side property

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how many 3cm cubes can be put in a box 3cm long 6cm wide 12cm high?

Answers

Answer:

8

Step-by-step explanation:

A cube is equal on all sides. Therefore the cubes must be 3cm x 3cm x 3cm. Therefore, each cube has an area of 27cm^3. The box that the cube has an area in is 3cm x 6cm x 12 cm which = 216cm^3. If you do [tex]216cm^3/27cm^3 = 8 cubes[/tex]

The number of cubes that fit on the 3 cm side times the number that fit on the 6 cm side times the number that fit in the 12 cm high side.

I don't understand any recursive sequences please help explain so

The graph of f(x) = |x| is reflected across the y-axis and translated to the left 5 units. Which statement about the domain and range of each function is correct?


A).Both the domain and range of the transformed function are the same as those of the parent function.

B).Neither the domain nor the range of the transformed function are the same as those of the parent function.

c).The range of the transformed function is the same as the parent function, but the domains of the functions are different.

D).The domain of the transformed function is the same as the parent function, but the ranges of the functions are different.

Answers

The statement that is true about the domain and range of each function is; A) Both the domain and range of the transformed function are the same as those of the parent function.

How to interpret reflection of a function?

We are told that the graph of f(x) = |x| is reflected across the y-axis. Thus;

|-x| = x

Now, the function is translated to the left by 5 units and so the transformed function is; g(x) = |x + 5|

Thus, from the graph, we get;

Domain of both functions is the set of all real numbers.

Range of both functions is the set {y|y ≥ 0}

Thus, we conclude that Both the domain and range of the transformed function are the same as those of the parent function.

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Lunch costs $6.90. How much change will
Hector get from $20.00?

Answers

Answer: 22

Step-by-step explanation:

Very much appreciated!!!

Answers

Answer:

80

Step-by-step explanation:

The sum of the interior angles of a triangle is 180.  Subtract out the 2 angles that you know.

180 - 70 - 30 = 80

Find and compare the growth rates in the weekly number of specialty items produced at each factory.

Show your work.

Answers

0.129 is the change in the growth rate of company.

According to statement

we have to find and compare the growth rate of the company weekly.

we use the growth rate formula is

GROWTH RATE = present - past / present

Substitute the values in this formula

1st week = 220-190 / 220

1st week = 0.136

2nd week = 252-220 / 252

2nd week = 32 / 252

2nd week = 0.126

3rd week = 290-252 / 290

3rd week = 0.131

4th week = 337 - 290 / 337

4th week = 0.139

5th week = 380 - 337 / 380

5th week = 0.113

6th week = 440 - 380 / 440

6th week = 0.136

7th week = 505 - 440 / 505

7th week = 0.128

Now we find the average value of growth rate

Average = 0.136 + 0.126+0.131+0.139+0.113+0.136+0.128 /7

Average = 0.909/7

Average = 0.129

So, 0.129 is the change in the growth rate of company.

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Solve for x when [tex]x^{yz} =y^{2}[/tex]

Answers

The value of x in x^yz = y^2 is [tex]x = \sqrt[yz]{y^2}[/tex]

How to solve for x?

The equation is given as:

x^yz = y^2

Rewrite the equation properly as follows

[tex]x^{yz} = y^2[/tex]

Take the yz root of both sides

[tex]\sqrt[yz]{x^{yz}} = \sqrt[yz]{y^2}[/tex]

Apply the law of indices

[tex]x^{\frac{yz}{yz}} = \sqrt[yz]{y^2}[/tex]

Divide yz by yz

[tex]x = \sqrt[yz]{y^2}[/tex]

Hence, the value of x in x^yz = y^2 is [tex]x = \sqrt[yz]{y^2}[/tex]

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Answer:

e

Step-by-step explanation:

Using euler's identity we can see that e^ipi=-1 and considering that i=y and  i^2=-1 we can conclude that x=e

PLSS HELP ASAP
A bag of marbles contains 7 red, 8 orange, 9 purple, 7 white, and 5 yellow. Mark reaches into the bag and randomly picks out 3 marbles all at once.

How many different 3-marble groups are possible?

What is the probability that he will select 2 red and 1 yellow marbles?

Answers

based on the number of marbles in the bag, the number of marble groups possible is 7,140 groups.

the probability of selecting 2 red and 1 yellow is 1/68.

what number of 3-marble groups can be made?

first, find the number of marbles:

= 7 + 8 + 9 + 7 + 5

= 36

the number of marble groups are:

= 36 ! / (3 ! x 33 !)

= 7,140 groups

the probability of picking 2 red and 1 yellow is:

= (( (7! / (2! x 5!)) x ( ( 5! / (1! x 4!))) / 7,140

= 1 / 68

= 1.47%

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Solve for x: 12x^2 – 6 (a^2 + b^2)x + 3a^2b^2 = 0

Answers

Step-by-step explanation:

[tex]12 {x}^{2} - 6( {a}^{2} + {b}^{2} )x + 3 {a}^{2} {b}^{2} = 0[/tex]

Using quadratic formula, we get

[tex]x = 6( {a}^{2} + {b}^{2} )± \frac{ \sqrt{( - 6) {}^{2}( {a}^{2} + {b}^{2}) {}^{2} - 4(12)(3 {a}^{2} {b}^{2} )} }{24} [/tex]

[tex]x = 6( {a}^{2} + {b}^{2} )± \frac{ \sqrt{36( {a}^{2} + {b}^{2} ) {}^{2} - 144 {a}^{2} {b}^{2} } }{24} [/tex]

[tex]x = 6( {a}^{2} + {b}^{2} )± \frac{ \sqrt{36( ({a}^{2} + {b}^{2}) {}^{2} - 4 {a}^{2} {b}^{2} }) }{24} [/tex]

[tex]x = 6( {a}^{2} + {b}^{2} )± \frac{6 \sqrt{ ({a}^{2} + {b}^{2} ) {}^{2} - 4 {a}^{2} {b}^{2} } }{24} [/tex]

[tex]x = 6( {a}^{2} + {b}^{2} )± \frac{ \sqrt{( {a}^{2} + {b}^{2} ) {}^{2} - 4 {a}^{2} {b}^{2} } }{4} [/tex]

Answer: x₁=6b²,  x₂=6a².

Step-by-step explanation:

[tex]12x^2-6*(a^2+b^2)+3a^2b^2=0\\D=(6*(a^2+b^2))^2-4*12*3a^2b^2\\D=6^2*(a^2+b^2)^2-144a^2b^2\\D=36*(a^4+2a^2b^2+b^4)-144a^2b^2\\D=36a^4+72a^2b^2+b^4-144a^2b^2\\D=36a^4-72a^2b^2+36b^4\\D=(6a^2)^2-2*6a^2*6b^2+(6b^2)^2\\D=(6a^2-6b^2)^2\\\sqrt{D}=\sqrt{(6a^2-6b^2)^2}=|6a^2-6b^2|=б(6a^2-6b^2).\\\displaystyle x_{1,2}=\frac{-(-6*(a^2+b^2))б(6a^2-6b^2)}{2} .\\x_1=\frac{6a^2+6b^2-6a^2+6b^2}{2} \\x_1=\frac{12b^2}{2} \\x_1=6b^2.\\x_2=\frac{6a^2+6b^2+6a^2-6b^2}{2} \\x_2=\frac{12a^2}{2} \\x_2=6a^2.[/tex]

HELP, WILL GIVE BRAINLEST..
Factor the GCF: -6x³y + 9x²y2 - 12xy³ (5 points)
O 3xy(-2x² + 3xy - 4y²)
O-3xy(2x² + 3xy - 4y²)
O-3xy(2x2-3xy + 4y²)
O-3(2x³y - 3x²y² + 4xy³)

Answers

Answer:

[tex]\sf -3xy\left(2x^2-3xy+4y^2\right)[/tex]

Step-by-step explanation:

[tex]\sf -6x^3y+9x^2y^2-12xy^3[/tex]

To factor the GCF of 6x³y + 9x²y2 - 12xy³ let's apply the exponent rule:-

[tex]\boxed{\sf a^{b+c}=a^ba^c}[/tex]

[tex]\boxed{\sf x^3y=xx^2y,\:x^2y^2=xxyy,\:xy^3=xyy^2}[/tex]

[tex]\sf -6xx^2y+9xxyy-12xyy^2[/tex]

Rewrite,

-6 as 2 * 39 as 3 * 3-12 as 4 * 3

[tex]\sf 2\cdot \:3xx^2y+3\cdot \:3xxyy+4\cdot \:3xyy^2[/tex]

Now, factor out the common term [tex]\sf -3xy[/tex]:-

[tex]\sf -3xy\left(2x^2-3xy+4y^2\right)[/tex]

__________________________

What is 8 11/12 + 9 5/18

Answers

Step-by-step explanation:

The picture is the full explanation for this question answer.

18.19 is the solution for the given improper function.

What are mathematical operations?

The term "operation" in mathematics refers to the process of computing a value utilizing operands and a math operator. For the specified operands or integers, the math operator's symbol has predetermined rules that must be followed. In mathematics, there are five basic operations: addition, subtraction, multiplication, division, and modular forms.

To add 8 11/12 and 9 5/18, we need to first find a common denominator. The smallest number that both 12 and 18 divide evenly is 36.

Converting 8 11/12 to an improper fraction:

8 11/12 = (8 × 12 + 11) / 12 = 107/12

Converting 9 5/18 to an improper fraction:

9 5/18 = (9 × 18 + 5) / 18 = 167/18

Now that we have a common denominator of 36, we can add the two fractions:

107/12 + 167/18 = (107 × 3) / (12 × 3) + (167 × 2) / (18 × 2)

= 321/36 + 334/36 = 655/36

So 8 11/12 + 9 5/18 = 655/36 or approximately 18.19.

Learn more about Mathematical operations here:

https://brainly.com/question/20628271

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graph the following system of inequalities. y ≤ 1 3 ⁢ x − 2 x < 4

Answers

By using an online graphing calculator, the solution to this system of inequalities are plotted in the image attached below.

How to graph a system of inequalities?

An inequality is a mathematical relation that compares two (2) or more integers and variables in an equation based on any of the following:

Less than (<).Greater than (>).Less than or equal to (≤).Greater than or equal to (≥).

Given the following system of inequalities:

y ≤ 1/3x  ⇒ y - 1/3x ≤ 0

y - 2x < 4

By using an online graphing calculator, the solution to this system of inequalities are plotted in the image attached below.

Read more on inequalities here: brainly.com/question/24372553

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Complete Question:

Graph the following system of inequalities.

y ≤ 1/3x and y - 2x < 4

area of the ceiling of a room 4 metre high is 48 metre square if the area of four walls of the room is 112 m square calculate the length and breadth of a room.​

Answers

Answer:

Breadth=8

Length=6

OR

breadth = 6

length=8

Step-by-step explanation:

Area of 4 walls = 2(l+b)h

112=2.4(l+b)

112/8=l+b

14=l+b

l=14-b

Area of base or ceiling=l x b

48=(14-b).b

48=14b-b²

b²-14b+48=0

factorize it and we get

(b-6)(b-8)=0

taking b-6=0

b=6

l=14-6

l=8

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