I need help with this math problem

I Need Help With This Math Problem

Answers

Answer 1

Answer:

1). [tex]\frac{2}{x^{2}-x-12 }=\frac{2}{(x+3)(x-4)}[/tex]

2). [tex]\frac{1}{x^{2}-16 }=\frac{1}{(x-4)(x+4)}[/tex]

Step-by-step explanation:

In this question we have to write the fractions in the factored form.

Rational expressions are [tex]\frac{2}{x^{2}-x-12 }[/tex] and [tex]\frac{1}{x^{2}-16 }[/tex].

1). [tex]\frac{2}{x^{2}-x-12 }[/tex]

Factored form of the denominator (x² - x - 12) = x² - 4x + 3x - 12

                                                                           = x(x - 4) + 3(x - 4)

                                                                           = (x + 3)(x - 4)

Therefore. [tex]\frac{2}{x^{2}-x-12 }=\frac{2}{(x+3)(x-4)}[/tex]

2). [tex]\frac{1}{x^{2}-16 }[/tex]

Factored form of the denominator (x² - 16) = (x - 4)(x + 4)

[Since (a²- b²) = (a - b)(a + b)]

Therefore, [tex]\frac{1}{x^{2}-16 }=\frac{1}{(x-4)(x+4)}[/tex]


Related Questions

Find the area of the triangle with the following measurements: B = 67°, a = 13 cm, c = 21 cm

Answers

9514 1404 393

Answer:

  125.6 cm²

Step-by-step explanation:

The relevant area formula is ...

  Area = (1/2)ac·sin(B)

  Area = (1/2)(13 cm)(21 cm)·sin(67°) ≈ 125.6 cm²

A number to be multiplied is called a?

Answers

Answer:

The number to be multiplied is the "multiplicand"

Step-by-step explanation:

a base when it is written in exponential notation

Un taxímetro inicia con 50 unidades y el banderazo o arranque es de $4500, las unidades comienzan a cambiar p0r cada kilometros recorrido. La función lineal que representa esta situación es y = 50x +4500 donde y representa el precio que cuesta la carrera y x la distancia recorrida en kilómetros. a) ¿ Cuanto cuesta una carrera si la distancia recorrida fue de 23 kilómetros?

Answers

Answer: $5650

Step-by-step explanation:

El precio de la carrera es:

y = ($50/km)*x + $4500.

Donde x representa la cantidad recorrida en Km.

Ahora se nos pregunta:

¿ Cuanto cuesta una carrera si la distancia recorrida fue de 23 kilómetros?

Para esto, debemos reemplazar la variable en la equacion por 23km:

x = 23km

y = ($50/km)*23km + $4500 = $5650

Question
Consider this expression.
4/2² - 6²
Type the correct answer in the box. Use numerals instead of words. For help, see this worked example e.
When a =
-5 and b = 3, the value of the expression is
Submit

Answers

Answer:

16

Step-by-step explanation:

4 * sqrt( a^2 - b^2)

Let a = -5 and b =3

4 * sqrt( (-5)^2 - 3^2)

Do the squaring first

4 * sqrt( 25 - 9)

Subtract inside the square root

4 * sqrt( 16)

Take the square root

4 * 4

Multiply 16

Answer:

[tex]\Large \boxed{16}[/tex]

Step-by-step explanation:

[tex]4\sqrt{a^2-b^2 }[/tex]

[tex]\sf Plug \ in \ the \ values \ for \ a \ and \ b.[/tex]

[tex]4\sqrt{-5^2-3^2 }[/tex]

[tex]4\sqrt{25-9 }[/tex]

[tex]4\sqrt{16}[/tex]

[tex]4 \times 4=16[/tex]

What is the domain of f(x) = 5^x - 7?
O {x|x>-7)
O {XIX<-7}
O {x|x>0}
O {x | x is a real number}

Answers

Step-by-step explanation:

{ x| x all real numbers}

The domain of f(x) = 5x – 7 will be all real numbers, as the function is a straight line, with no discontinuities, thus undefined at no value of x.

The domain of the function f(x) = 5ˣ - 7 is {x | x is a real number}.

What is Function?

A function is a relation from a set A to a set B where the elements in set A only maps to one and only one image in set B. No elements in set A has more than one image in set B.

Given function is,

f(x) = 5ˣ - 7

The domain of the function is the set of all values of x such that the function is defined.

If we use any number for x, the function will be defined.

So the domain is the set of all real numbers.

So the correct option is last one {x | x is a real number}.

Hence the domain of the given function is {x | x is a real number}.

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what song goes whoooooo Iiiiii smoooooooooke ​

Answers

Answer:

Lol yu lateee das "who i smoke by yung ace"

Step-by-step explanation:

Answer:

woogle said woo hoo  by rock a teens

Step-by-step explanation:

A lime passes through the point (5,7) has a slope of 3. Which of the following gives the equation of the line

Answers

Answer:

Hey There!! The answer to this is (6, 10) There are no answer choices, so I will just list a few. But first, we need to create the equation.

Plugging in (5,7) into the equation y=mx+b, we can solve for b since all of the other variables are known, with m=3 as the slope.

So, 7=3*5+b

7=15+b

b = -8

y=3x-8 is your equation.

So, you can plug in any value of x you get a certain value of y.

(1,-5), (2,-2), (3,1), (4,4), (5,7), (6,10), (7,13) Thus, for The correct option (6, 10). Hope It Helped!~ ♡

ItsNobody~ ☆

Answer:

y=3x-8

Step-by-step explanation:

We can start by writing the equation of the line in point-slope form.

Point-slope form is y-y1=m(x-x1)

This is where:

y1= y-coordinate of a given point on the line

m= slope of the line

x1= x-coordinate of a given point on the line

The given point in this example is (5,7)

A point is (x-coordinate, y-coordinate)

Therefore,

y1=7

m=3

x1=5

Plug that into the form.

y-7=3(x-5)

We can now simplify that to slope-intercept form,since that is most standard.

y-7=3(x-5)

Start by distributing the right side.

y-7=3x-15

Add 7 to both sides.

y=3x-8

Find
two consecutive numbers
odd numbers such that the
sum of the
greater number
and 5 times the smaller
number is 92. Please give detailed step by step answer​

Answers

Answer:

The two odd numbers are 15 and 17

Step-by-step explanation:

Given

Let the odd numbers be represented with x and y

Let x be the greater number

[tex]x + 5y = 92[/tex]

Required

Find x and y

Since x and y are consecutive odd numbers and x is greater, then

[tex]x = y + 2[/tex]

Substitute y + 2 for x in [tex]x + 5y = 92[/tex]

[tex]y + 2 + 5y = 92[/tex]

Collect Like Terms

[tex]y + 5y = 92 - 2[/tex]

[tex]6y = 90[/tex]

Divide both sides by 6

[tex]\frac{6y}{6} = \frac{90}{6}[/tex]

[tex]y = \frac{90}{6}[/tex]

[tex]y = 15[/tex]

Substitute 15 for y in [tex]x = y + 2[/tex]

[tex]x = 15 + 2[/tex]

[tex]x = 17[/tex]

Hence; the two odd numbers are 15 and 17

Answer:

Maths

Step-by-step explanation:

Answer:

The two odd numbers are 15 and 17

Step-by-step explanation:

Given

Let the odd numbers be represented with x and y

Let x be the greater number

Required

Find x and y

Since x and y are consecutive odd numbers and x is greater, then

Substitute y + 2 for x in  

Collect Like Terms

Divide both sides by 6

Substitute 15 for y in  

Hence; the two odd numbers are 15 and 17

PLEASE gelp me with this, gelp me please oh please gelp me!

Answers

Answer:

V = 2143.57 cm^3

Step-by-step explanation:

The volume of a sphere is

V = 4/3 pi r^3

The diameter is 16 so the radius is 1/2 of the diameter or 8

V = 4/3 ( 3.14) (8)^3

V =2143.57333

Rounding to the nearest hundredth

V = 2143.57 cm^3

Answer:

2143.57 cm^3

Step-by-step explanation:

V = 4/3 * 3.14 * r^3

r = 1/2 * 16 = 8

So V = 4/3 * 3.14 * 8^3

= 2143.57 cm^3.

In a class of 70 pupils, 36 like tasty time , 34 like ice-
cream, 6 like both tasty time }
draw a Venn diagram to show the data.
find how
many
like neither tasty time nor ice-cream

Answers

Step-by-step explanation:

I think this might be the correct answer

The number of pupils that like neither tasty-time nor ice cream is 6 if in a class of 70 pupils, 36 like tasty time, 34 like ice cream, 6 like both tasty times.

What is the Venn diagram?

It is defined as the diagram that shows a logical relation between sets.

The Venn diagram consists of circles to show the logical relation.

We have:

In a class of 70 pupils, 36 like tasty time, 34 like ice cream, 6 like both tasty time.

Total = 70 pupils

Number of like tasty time = 36

Number of like ice cream = 34

Number of like both = 6

Let x be the total number of pupils that like neither tasty-time nor ice cream

The number of pupils that like ice cream only =  34 - 6 = 28

The number of pupils that like tasty-time only = 36 - 6 = 30

From the Venn diagram:

28 + 30 + 6 + x = 70

x = 70 - 64

x = 6

Thus, the number of pupils that like neither tasty-time nor ice cream is 6 if in a class of 70 pupils, 36 like tasty time, 34 like ice cream, 6 like both tasty times.

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Using Normal Distribution, what is the area to the right of 0.72 under the
standard normal curve?

Answers

Answer: 0.2358

Step-by-step explanation:

Using Normal Distribution, under the  standard normal curve

The area to the right of z is given by P(Z>z)=1-P(Z<z)

So, the area to the right of z= 0.72 under the  standard normal curve would be:

P(Z>0.72)=1-P(z<0.72)

=1-0.7642   [By using p-value table]

= 0.2358

Hence, the area to the right of z= 0.72 under the  standard normal curve is 0.2358 .

Nicole ordered a volleyball for $9.75

Answers

That’s Nice!!

I don’t think you copied the WHOLE ENTIRE question. I would suggest resubmitting the question so we can help you with it!!

Have a great day and stay safe and positive!!

Answer:

the other person is right

you should try putting the WHOLE question

Step-by-step explanation:

Please help with step by step.

Answers

Answer:

(-9x^5+x^4-12x^2+21x) / (-3x^2)

= -9x^5+x^4-12x^2+21x / -3x^2

= x(-9x^4+x^3-12x+21) / -3x^2

= -9x^4+x^3-12x+21 / -3x

= -9x^4+x^3-12x+21
- ——————————-
3x

A sequence of 1 million iid symbols(+1 and +2), Xi, are transmitted through a channel and summed to produce a new random variable W. Assume that the probability of transmitting a +1 is 0.4. Show your work
a) Determine the expected value for W
b) Determine the variance of W

Answers

Answer:

E(w) = 1600000

v(w) = 240000

Step-by-step explanation:

given data

sequence = 1 million iid  (+1 and +2)

probability of transmitting a +1 =  0.4

solution

sequence will be here as

P{Xi = k } = 0.4              for k = +1

                  0.6              for k = +2

and define is

x1  + x2 + ................ + X1000000

so for expected value for W

E(w) = E( x1  + x2 + ................ +  X1000000 )   ......................1

as per the linear probability of expectation

E(w) = 1000000 ( 0.4 × 1 + 0.6 × 2)

E(w) = 1600000

and

for variance of W

v(w) = V ( x1  + x2 + ................ + X1000000 )    ..........................2

v(w) = V x1  + V x2 + ................  + V  X1000000

here also same as that xi are i.e d so cov(xi, xj ) = 0 and i ≠ j

so

v(w) = 1000000 ( v(x) )

v(w) = 1000000 ( 0.24)

v(w) = 240000

Simplify your answer as much as possible.

Answers

Answer:

x = -4

Step-by-step explanation:

2 = 3x + 22/5

Numerator = denominator x quotient

Numerator = 5 x 2

Numerator = 10

3x + 22 = 10

Subtract 22 from both sides

3x = -12

x = -12/3

x = -4
•••••••••••••••••••••••••••
Hope this helps!

Bye love you.

- doomdabomb

A hunter shot 7 ducks. The hunter's dog recovered 5/7 of the ducks. How many ducks were recover

Answers

Answer:

5

Step-by-step explanation:

Just multiply 5/7 by 7 since his dog retrieved 5/7 out of the 7 ducks he shot.

Answer:

5

Step-by-step explanation:

7*5/7

7 represents the # of ducks

5/7 represents the # of ducks that were recovered

The question asks the number of ducks that were recovered so you should multiply the total # of ducks there are by the fraction that were recovered.

Which statements can be used to compare the characteristics of the functions? Select three options.

Answers

Answer:

Step-by-step explanation:

g(x) has the smallest minimum value. All three functions share the same domain and the y-intercept is also the same for all three thus options (C),(D), and (E) is correct.

What is a graph?

A graph is a diametrical representation of any function between the dependent and independent variables.

For example y = x² form a parabola now by looking at only the graph we can predict that it has only a positive value irrespective of the interval of x.

As per the given table,

The minimum value among all functions is -204 which is for g(x).

The domain is the set of x since all function defines the same x thus they have the same domain.

At y-intercept x = 0

Since at x = 0 all function is 3 thus all three will have the same y-intercept.

Hence "The smallest minimal value is for g(x). The y-intercept for all three functions is the same, and all three functions have the same domain".

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Which option is correct and how would one solve for it?

Answers

Answer:

28

Step-by-step explanation:

We need to find the value of [tex]\Sigma_{x=0}^3\ 2x^2[/tex]

We know that,

[tex]\Sigma n^2=\dfrac{n(n+1)(2n+1)}{6}[/tex]

Here, n = 3

So,

[tex]\Sigma n^2=\dfrac{3(3+1)(2(3)+1)}{6}\\\\\Sigma n^2=14[/tex]

So,

[tex]\Sigma_{x=0}^3\ 2x^2=2\times 14\\\\=28[/tex]

So, the value of [tex]\Sigma_{x=0}^3\ 2x^2[/tex] is 28. Hence, the correct option is (d).

How many odd numbers with 4 different digits, can be formed using the digits 1, 2, 3, 4, 5, 6, 7, 8? (No repetition is allowed)
A. 71
B. 200
C. 210
D. 840
E.1680

Answers

Answer:

840 ( D )

Step-by-step explanation:

GIVEN DIGITS : 1,2,3,4,5,6,7,8  

Number of odd numbers = 4

Number of even numbers = 4

therefore the number of odd numbers with 4 different digits can be formed by the same way the number of even numbers ( without repetition )

Hence the number of ways odd numbers with 4 different digits = Total number of ways of forming 4 digit numbers / 2

8*7*6*5 = 1680 / 2 =  840 ways

find the length of the arc . round your answers to the nearest tenth PLEASE HURRY

Answers

Answer:

10.2

Step-by-step explanation:

Length of arc=(2*pi*r)*(theta/360)

Length of arc=(2*pi*3)*(195/360)=10.2

What is the volume of a pyramid below?



600 cm^3

750 cm^3

900 cm^3

1800 cm^3

Answers

Answer: 600 cm³

Step-by-step explanation:

Volume of square pyramid = (1/3) · b² · h

b = base edge length = 10 cmh = height = 18 cm

Therefore, the volume can be calculated as

[tex]\frac{1}{3} *10^{2}*18=\frac{1}{3}*100*18=\frac{1}{3}*1800=\frac{1800}{3}=600[/tex]

Answer

900

Step-by-step explanation:

it is pyramid and finding its volume we use the 3 components that is length, with and the height

1/2 base x width x height

5 x 18 x 10 = 900cm³

Find the first, second, third and fourth order Maclaurin polynomials of f(x) =

arctan(x). Draw the graph of f(x) and the four polynomials on the same

diagram. (Sketch by hand or use software.)

#urgent please give me this answer and help me#

Answers

The first, second, third and fourth order Maclaurin polynomials of f(x)=arctan(x) are:

The first order Maclaurin polynomial is f(x)=xThe second order Maclaurin polynomial is also f(x)=xThe third order Maclaurin polynomial is [tex]f(x)=x-\frac{1}{3}x^{3}[/tex]The fourth order Maclaurin polynomial is also [tex]f(x)=x-\frac{1}{3}x^{3}[/tex]You can see the graph on the attached picture.

So let's start by finding the first order maclaurin polynomial:

f(x)=f(0)+f'(0)x

so let's find each part of the function:

f(0)=arctan(0)

f(0)=0

now, let's find the first derivative of f(x)

f(x)=arctan(x)

This is a usual derivative so there is a rule we can use here:

[tex]f'(x)=\frac{1}{x^{2}+1}[/tex]

so now we can find f'(0)

[tex]f'(0)=\frac{1}{(0)^{2}+1}[/tex]

f'(0)=1

So we can now complete the first order Maclaurin Polynomial:

f(x)=0+1x

which simplifies to:

f(x)=x

Now let's find the second order polynomial, for which we will need to get the second derivative of the function:

[tex]f(x)=f(0)+f'(0)x+\frac{f''(0)}{2!}x^{2}[/tex]

so:

[tex]f'(x)=\frac{1}{x^{2}+1}[/tex]

we can rewrite this derivative as:

[tex]f'(x)=(x^{2}+1)^{-1}[/tex]

and use the chain rule to get:

[tex]f''(x)=-1(x^{2}+1)^{-2}(2x)[/tex]

which simplifies to:

[tex]f''(x)=-\frac{2x}{(x^{2}+1)^{2}}[/tex]

now, we can find f''(0):

[tex]f''(0)=-\frac{2(0)}{((0)^{2}+1)^{2}}[/tex]

which yields:

f''(0)=0

so now we can complete the second order Maclaurin polynomial:

[tex]f(x)=0+1x+\frac{0}{2!}x^{2}[/tex]

which simplifies to:

f(x)=x

Now let's find the third order polynomial, for which we will need to get the third derivative of the function:

[tex]f(x)=f(0)+f'(0)x+\frac{f''(0)}{2!}x^{2}+\frac{f'''(0)}{3!}x^{3}[/tex]

so:

[tex]f''(x)=-\frac{2x}{(x^{2}+1)^{2}}[/tex]

In this case we can use the quotient rule to solve this:

Quotient rule: Whenever you have a function in the form , then it's derivative is:

[tex]f'(x)=\frac{p'q-pq'}{q^{2}}[/tex]

in this case:

p=2x

p'=2

[tex]q=(x^{2}+1)^{2}[/tex]

[tex]q'=2(x^{2}+1)(2x)[/tex]

[tex]q'=4x(x^{2}+1)[/tex]

So when using the quotient rule we get:

[tex]f'(x)=\frac{p'q-pq'}{q^{2}}[/tex]

[tex]f'''(x)=\frac{(2)(x^{2}+1)^{2}-(2x)(4x)(x^{2}+1)}{((x^{2}+1)^{2})^{2}}[/tex]

which simplifies to:

[tex]f'''(x)=\frac{-2x^{2}-2+8x^{2}}{(x^{2}+1)^{3}}[/tex]

[tex]f'''(x)=\frac{6x^{2}-2}{(x^{2}+1)^{3}}[/tex]

now, we can find f'''(0):

[tex]f'''(0)=\frac{6(0)^{2}-2}{((0)^{2}+1)^{3}}[/tex]

which yields:

f'''(0)=-2

so now we can complete the third order Maclaurin polynomial:

[tex]f(x)=0+1x+\frac{0}{2!}x^{2}-\frac{2}{3!}x^{3}[/tex]

which simplifies to:

[tex]f(x)=x-\frac{1}{3}x^{3}[/tex]

Now let's find the fourth order polynomial, for which we will need to get the fourth derivative of the function:

[tex]f(x)=f(0)+f'(0)x+\frac{f''(0)}{2!}x^{2}+\frac{f'''(0)}{3!}x^{3}+\frac{f^{(4)}(0)}{4!}x^{4}[/tex]

so:

[tex]f'''(x)=\frac{6x^{2}-2}{(x^{2}+1)^{3}}[/tex]

In this case we can use the quotient rule to solve this:

[tex]f'(x)=\frac{p'q-pq'}{q^{2}}[/tex]

in this case:

[tex]p=6x^{2}-2[/tex]

p'=12x

[tex]q=(x^{2}+1)^{3}[/tex]

[tex]q'=3(x^{2}+1)^{2}(2x)[/tex]

[tex]q'=6x(x^{2}+1)^{2}[/tex]

So when using the quotient rule we get:

[tex]f'(x)=\frac{p'q-pq'}{q^{2}}[/tex]

[tex]f^{4}(x)=\frac{(12x)(x^{2}+1)^{3}-(6x^{2}-2)(6x)(x^{2}+1)^{2}}{((x^{2}+1)^{3})^{2}}[/tex]

which simplifies to:

[tex]f^{4}(x)=\frac{12x^{3}+12x-6x^{3}+12x}{(x^{2}+1)^{4}}[/tex]

[tex]f^{4}(x)=\frac{6x^{3}+24x}{(x^{2}+1)^{4}}[/tex]

now, we can find f^{4}(0):

[tex]f^{4}(x)=\frac{6(0)^{3}+24(0)}{((0)^{2}+1)^{4}}[/tex]

which yields:

[tex]f^{4}(0)=0[/tex]

so now we can complete the fourth order Maclaurin polynomial:

[tex]f(x)=0+1x+\frac{0}{2!}x^{2}-\frac{2}{3!}x^{3}+\frac{0}{4!}x^{4}[/tex]

which simplifies to:

[tex]f(x)=x-\frac{1}{3}x^{3}[/tex]

you can find the graph of the four polynomials in the attached picture.

So the first, second, third and fourth order Maclaurin polynomials of f(x)=arctan(x) are:

The first order Maclaurin polynomial is f(x)=xThe second order Maclaurin polynomial is also f(x)=xThe third order Maclaurin polynomial is [tex]f(x)=x-\frac{1}{3}x^{3}[/tex]The fourth order Maclaurin polynomial is also [tex]f(x)=x-\frac{1}{3}x^{3}[/tex]

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If a system of linear equations has no solution, what does this mean about the two lines?

Answers

Answer:

The two lines do not intersect, and are parallel to one another on a graph.

Step-by-step explanation:

A system of equations consists of two or more equations with two or more variables. The solution to these variables must satisfy all of the variables in the equations in the system at the same time. Usually, all the equations in the system are considered and solved simultaneously. A linear equation might have a unique solution, an infinite solution, or no solution at all.

A system with exactly one solution is called a consistent system, and it is said to be independent, and the graph of its lines intersects at the point that is the solution to the equations. A system with an infinite number of solution is said to be dependent and the lines are coincident on a graph.

If a system has no solution, it is said to be inconsistent . The graphs of the lines do not intersect, and the lines are parallel to one another on the graph.

For two lines of linear equations to have no solution, they must be parallel to each other i.e they must have the same slope.

The standard form of writing linear equation is expressed as y = mx + b

m is the slope of the line

b is the y-intercept

For two lines of linear equations to have no solution, they must be parallel to each other i.e they must have the same slope.

For instance, the system of equations y = 2x + 7 and y = 2x - 3 have no solutions because they have the same slope.

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[tex]log(x) * log(2)[/tex]

Why can't this problem be solved?

Answers

Answer:

Because it is not an equation.

Step-by-step explanation:

[tex] log(x) \times log(2) \\ = log(x + 2) [/tex]

The line perpendicular to y=3/4x+7 containing (3,-4)

Answers

Answer:

y = - [tex]\frac{4}{3}[/tex] x

Step-by-step explanation:

1). [tex]y_{1}[/tex] = [tex]m_{1}[/tex] [tex]x_{1}[/tex] + [tex]b_{1}[/tex]  

[tex]y_{2}[/tex] = [tex]m_{2}[/tex] [tex]x_{2}[/tex] + [tex]b_{2}[/tex]

[tex]y_{1}[/tex] ⊥ [tex]y_{2}[/tex]  if  [tex]m_{2}[/tex] = - [tex]\frac{1}{m_{1} }[/tex]

2). ( [tex]x_{3}[/tex] , [tex]y_{3}[/tex] )

y - [tex]y_{3}[/tex] = m( x - [tex]x_{3}[/tex] )

~~~~~~~~~~~~~~~~~~

y = [tex]\frac{3}{4}[/tex] x + 7

[tex]m_{1}[/tex] = [tex]\frac{3}{4}[/tex]

[tex]m_{2}[/tex] = - [tex]\frac{4}{3}[/tex]

( 3, - 4 )

y - ( - 4) = - [tex]\frac{4}{3}[/tex] ( x - 3 )

y + 4 = - [tex]\frac{4}{3}[/tex] x + 4

y = - [tex]\frac{4}{3}[/tex] x

Give the domain and range.
x –2 0 2 y –1 0 1
a. domain: {2, 0, 2}, range: {1, 0, 1} b. domain: {–2, 0, 2}, range: {–1, 0, 1} c. domain: {–1, 0, 1}, range: {–2, 0, 2} d. domain: {1, 0, 1}, range: {2, 0, 2}

Answers

Answer:

B. domain {-2, 0, 2}, range {-1, 0, 1}

Step-by-step explanation:

The x values and y values as ordered pairs would be: (-2,-1), (0,0), (2,1)

The domain is the all of the values of x and the range is all the values of y.

find the n^th root of z = -2i, n = 6​

Answers

Answer:

2^(1/6) (cos(-pi/12)+i sin(-pi/12))

2^(1/6) (cos(3pi/12)+i sin(3pi/12))

2^(1/6) (cos(7pi/12)+i sin(7pi/12))

2^(1/6) (cos(11pi/12)+i sin(11pi/12))

2^(1/6) (cos(5pi/4)+i sin(5pi/4))

2^(1/6) (cos(19pi/12)+i sin(19pi/12))

Step-by-step explanation:

Let's convert to polar form.

-2i=2(cos(A)+i sin(A) )

There is no real part so cos(A) has to be zero and since we want -2 and we already have 2 then we need sin(A)=-1 so let's choose A=-pi/2.

So z=2(cos(-pi/2)+i sin(-pi/2)).

There are actually infinitely many ways we can write this polar form which we will need.

z=2(cos(-pi/2+2pi k)+i sin(-pi/2+2pi k))

where k is an integer

Now let's find the 6 6th roots or z.

2^(1/6) (cos(-pi/12+2pi k/6)+i sin(-pi/12+2pi k/6))

Reducing

2^(1/6) (cos(-pi/12+pi k/3)+i sin(-pi/12+pi k/3))

Plug in k=0,1,2,3,4,5 to find the 6 6th roots.

k=0:

2^(1/6) (cos(-pi/12+pi (0)/3)+i sin(-pi/12+pi (0)/3))

=2^(1/6) (cos(-pi/12)+i sin(-pi/12))

k=1:

2^(1/6) (cos(-pi/12+pi/3)+i sin(-pi/12+pi/3))

2^(1/6) (cos(3pi/12)+i sin(3pi/12))

k=2:

2^(1/6) (cos(-pi/12+2pi/3)+i sin(-pi/12+2pi/3))

2^(1/6) (cos(7pi/12)+i sin(7pi/12))

k=3:

2^(1/6) (cos(-pi/12+3pi/3)+i sin(-pi/12+3pi/3))

2^(1/6) (cos(11pi/12)+i sin(11pi/12))

k=4:

2^(1/6) (cos(-pi/12+4pi/3)+i sin(-pi/12+4pi/3))

2^(1/6) (cos(15pi/12)+i sin(15pi/12))

2^(1/6) (cos(5pi/4)+i sin(5pi/4))

k=5:

2^(1/6) (cos(-pi/12+5pi/3)+i sin(-pi/12+5pi/3))

2^(1/6) (cos(19pi/12)+i sin(19pi/12))

. A swimming pool was filling with water at a constant rate of 200 gallons per hour. The pool had
50 gallons before the timer started. Write an equation in standard form to model the situation, then
find the amount of water in the pool after 2 hours and 15 minutes.

Answers

300 amount of the water in the pool after 2 hours and 15 minutes

GIVING OUT BRAINLIEST TO THE FIRST PERSON WHO ANSWERS!! I would appreciate if if you do answer though! <3

Also, include ALL work!

Answers

Answer:

The answer is option B

Step-by-step explanation:

Total number of people = 800

To find the number of unemployed people we must first find the total percentage of the pie chart

That's

25 + 10 + 5 + 60 = 100%

5 % out of the 100% are unemployed

To find the number of unemployed people divide 5 % by the total percentage that's 100% and multiply them by the total number of people

That's

[tex] \frac{5}{100} \times 800[/tex]

5 × 8

We have the final answer as

40 people

Hope this helps you

Find the largest integer which belongs to the following interval: (−∞, 8)

Answers

Answer:

7

Step-by-step explanation:

The following range includes numbers from negative infinity to 8. But, 8 isn't included, because there is a parentheses not a bracket. So, basically you can have 7.9999999. But, it asks for an integer, so it is 7.

The largest integer which belongs to the interval: (−∞, 8) is 7

To determine the largest integer, we will first ascertain what the use of parentheses and brackets denote.

The use of parentheses ( ) stands for open interval, that is, the extreme numbers of the set are not included.

If the brackets [ ] were used instead, that will be closed interval, that is, the extreme numbers of the set are included.

Since ( ) were used in the question, that means the extreme numbers −∞ and 8 are NOT included in the set.

Now, let us define an integer.

An integer is a positive or negative whole number or zero.

Hence, the integers in the set will include: −∞+1, −∞ + 2, ... 5, 6, and 7.

The largest integer here is 7

Hence, the largest integer which belongs to the interval: (−∞, 8) is 7

Learn more in the link below:

https://brainly.com/question/13324131

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