i need to know the measurements of this to the appropriate amount of significant figures

I Need To Know The Measurements Of This To The Appropriate Amount Of Significant Figures

Answers

Answer 1

Answer:

[See Below]

Explanation:

23 or 23.5 ml.


Related Questions

A 147-g piece of metal has a density of 7.00 g/ml. 50- ml graduated cylinder contains 20.0 ml of water what is the final volume after the metal is added to the graduated cylinder

Answers

Answer:

The final volume was 41

Explanation:

m = 147 grams

d = 7.00 g/mL

V = x - 20

=========

d = m/V

=========

7 = 147 / (x - 20)

Multiply both sides by x - 20

7*(x - 20) = 147

Divide both sides by 7

x - 20 = 147 / 7

x - 20 = 21  

Add 20 to both sides

x = 21 + 20

x = 41

The final volume was 41

Is radium fluoride soluble? (RaF2)

Answers

Answer:

No it is not soluble

Explanation:

if you were to look at the solubilibity table its not there

What is the first thing you need to do if someone is on fire?

Answers

Answer:

help them

Explanation:

Answer:

Roll over the ground as fast as possible and cover the person as soon as possible.

Explanation:

When you run, the body on fire catches oxygen which stimulates a combustion reaction hence causing the fire to grow bigger.

Hope this helps! :)

And if possible, please mark this answer brainliest so I can get to the next rank :)

Draw line structures for the cis and trans configurations of CH3CH2CH=CHCH3.

Answers

Answer:

See attached picture.

Explanation:

Hello,

In this case, on the attached picture you will find the required line structures for the cis and trans configurations of the given compound (2-pentene). Take into account for the cis that the adjacent carbons to those having the double bond remain in the same plane, whereas for the trans one, the adjacent carbons remain in a different plane.

Regards-

Atoms of elements at the top of a group on the periodic table are smaller than the atoms of elements at the bottom of the group. How does this help explain the difference in the reactivity of metals within a group?

Answers

Answer:

a

Explanation:

a

Which of the following questions could be answered by a scientific experiment?
a. Which type of flower is the prettiest?
b. Which type of music is the most relaxing?
c. Which type of thermos keeps ice water cold the longest?
d. What is the best color to paint your bedroom?

Answers

the answer to it is C...

Answer:

C.

Explanation:

All other questions are opinion-based and can't have a definite answer.

A mixture is made by adding 50.0 mL of 0.20 M NaOH(aq) to 50.0 mL of water. At 25.0 °C, what is its pH?

Answers

Answer:

13

Explanation:

From the dilution formula;

C1V1 = C2V2

C1= concentration of the stock solution = 0.2 M

V1 = volume of the stock solution = 50.0 ml

C2= concentration of the diluted solution= the unknown

V2= volume of diluted solution= 100 ml

C2= C1V1/V2

C2= 0.2 × 50/100

C2= 0.1 M

But

pOH= -log[OH^-]

But [OH^-] = 0.1 M

pOH= -log [0.1]

pOH= 1

Since;

pH +pOH = 14

pH= 14 - pOH

pH= 14- 1

pH= 13

why do canned baked beans last longer in a can than in air?

Answers

Because when anything is exposed to air, it come in contact with bacteria which begin to break down the proteins in the beans. But when it’s in a can, it can’t get exposed to bacteria which means it won’t break down.

Hope this sheds some light ♥︎

The branch of science which deals with chemical bonds is called chemistry.

The correct answer to the question is rancidity.

The process of decomposition of the edible items in presence of air which gives a bad odor is called rancidity.

The canned baked items are less prone to rancidity because they have preservation and nitrogen gas in them which prevent them from decomposition.

When the food reacts with the air it starts to decomposition due to oxidation.

Hence, canned baked last longer than the can in the air.

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which statment best describes the chamces that occured in the reactant in forming the alkene product

Answers

Hello. You did not enter answer options. The options are:

a. The OH group was removed from the reactante

b. The OH group was replaced by an H atom.

c. Two atoms were removed from the reactant.

d. An H atom abd a OH group have been removed drom the reactant.

In addition, you forgot to add an image that complements the question. The image is attached below.

Answer:

d. An H atom abd a OH group have been removed drom the reactant

Explanation:

As you can see in the image, the reagent is an alcohol molecule. For the transformation of the alcohol molecule into an alkene molecule, it is necessary that an intramolecular dehydration occurs, that is, it is necessary that a water molecule (two H atoms and an O atom) go out from inside the alcohol and that is exactly what happened, that is, we can say that an H atom and an OH group were removed from the reagent to form the alkene.

Please helpppp
Answer separately
1) 2) 3) 4) 5)

Answers

1) 4.5 mL

2) 12 mL

3) 82 mL

4) 110 mL

5) 330 mL

1)4.5 ml
2) 12 ml
3)82 ml

Which of the following has the smallest radius?
A)S^-2,
B)Cl^-1
C) Ar
D) K^+1

Answers

Answer:

d

Explanation:

when an atom lose an electron its radius reduces

500.0 mL sample of a gas at 760.0 mm Hg were compressed to 200.0 mL. Find the new pressure if the temperature remains constant

Answers

Answer:

1900 mmHg.

Explanation:

The following data were obtained from the question:

Initial volume (V1) = 500 mL

Initial pressure (P1) = 760 mmHg

Final volume (V2) = 200 mL

Final pressure (P2) =?

Temperature = constant.

Since the temperature is constant, we shall use the Boyle's law equation to obtain the new pressure as illustrated below:

P1V1 = P2V2

760 × 500 = P2 × 200

Divide both side by 200

P2 = (760 × 500) / 200

P2 = 1900 mmHg

Therefore, the new pressure is 1900 mmHg.

A pipet is used to transfer 5.00 mL of a 1.25 M stock solution in flask "S" to a 25.00 mL volumetric flask "B," which is then diluted with DI H2O to the calibration mark. The solution is thoroughly mixed. Next, 2.00 mL of the solution in volumetric flask "A" is transferred by pipet to 50.00 mL volumetric flask "B" and then diluted with DI H2O to the calibration mark. Calculate the molarity of the solution in volumetric flask "B". How do I solve this?

Answers

Answer: the molarity of the solution in volumetric flask "B' is 0.0100 M

Explanation:

Given that;

the Molarity of stock solution M₁ = 1.25M

The molarity os solution in volumetric flask A (M₂) = M₂

Volume of stock solution pipet out (V₁) = 5.00mL

Volume of solution in volumetric flask A V₂ = 25.00mL

using the dilution formula

M₁V₁ = M₂V₂

M₂ = M₁V₁ / V₂

WE SUBSTITUTE

M₂ =  ( 1.25 × 5.00 ) / 25.00 mL

M₂ = 0.25 M

Now volume of solution pipet out from volumetric flask A V₂ = 2.00 mL

Molarity of solution in volumetric flask B (M₃) = M₃

Volume of solution in volumetric flask B V₃ = 50.00m L

Using dilution formula again

M₂V₂ = M₃V₃

M₃ = M₂V₂ / V₃

WE SUBSTITUTE

M₃ = ( 0.25 × 2.0) / 50.0

M₃ = 0.0100 M

Therefore the molarity of the solution in volumetric flask "B' is 0.0100 M

The concentration of the final solution is 0.01 M.

This is a problem of serial dilution. We have to first obtain the concentration of  the solution in the new flask.

C1V1 = C2 V2

C1 = concentration of stock solution = 1.25 M

V1 = volume of stock solution =  5.00 mL

C2 = concentration of solution in the new flask = ?

V2 = volume of solution in flask B in the new flask = 25.00 mL

C2 = C1V1 /V2

C2 = 1.25 M ×  5.00 mL/ 25.00 mL

C2 = 0.25 M

Again we need to find the concentration when this solution is further diluted;

C1 = 0.25 M

V1 = 2.00 mL

C2 = ?

V2 = 50.00 mL

C2 = C1V1/V2

C2 = 0.25 M ×  2.00 mL/50.00 mL

C2 = 0.01 M

The concentration of the final solution is 0.01 M.

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A fertilizer is advertised as containing 17.3% sodium nitrate, NaNO3 (by mass). How much
NaNO3 molecules is there in 0.520 kg of fertilizer?​

Answers

Answer:

6.37 × 10²³ molecules

Explanation:

The molar mass of NaNO₃ = (23 × 1) + (14 ×1) + (16 × 3) = 23 + 14 + 48 = 85 g/mol

Since the fertilizer contains 17.3% sodium nitrate, The number of sodium nitrate in 0.520 kg of fertilizer = 17.3% × 0.520 kg = 0.173 × 520 g = 89.96 g

Number of moles of NaNO₃ in 0.520 kg of fertilizer =  89.96 g / 85 g/mol = 1.0584 moles

Number of molecules of NaNO₃ in 0.520 kg of fertilizer =  1.0584 moles × 6.02 × 10²³ = 6.37 × 10²³ molecules

The normal boiling point of acetic acid is 118.1°C. If a sample of the acetic acid is at 125.2°C, predict the signs of ΔH, ΔS, and ΔG for the boiling process at this temperature

Answers

The question is incomplete; the complete question is;

The normal boiling point of acetic acid is 118.1°C. If a sample of the acetic acid is at 125.2°C, predict the

signs of ∆H, ∆S, and ∆G for the boiling process at this temperature.

A. ∆H > 0, ∆S > 0, ∆G < 0

B. ∆H > 0, ∆S > 0, ∆G > 0

C. ∆H > 0, ∆S < 0, ∆G < 0

D. ∆H < 0, ∆S > 0, ∆G > 0

E. ∆H < 0, ∆S < 0, ∆G > 0

Answer:

∆H > 0, ∆S > 0, ∆G < 0

Explanation:

If we look at the question carefully, we will observe that it deals with a phase change from liquid to vapour phase.

Energy is required to break the intermolecular bonds in the liquid as it changes into vapour hence the process is endothermic, ∆H>0.

Also, the entropy of the vapour phase is greater than that of the liquid phase hence there is a positive change in entropy, ∆S>0.

Lastly, the process is spontaneous, hence the change in free energy ∆G is less than zero.

An experiment requires that enough SiCl2Br2 be used to yield of bromine . How much SiCl2Br2 must be weighed out?

Answers

Answer:

42.75 grams of SiCl2Br2 must be weighed out

Explanation:

Here is the complete question:

An experiment requires that enough SiCl2Br2 be used to yield 13.2g of bromine . How much SiCl2Br2 must be weighed out?

Explanation:

First, we will determine the Molar mass of SiCl2Br2,

Si = 28.08, Cl = 35.45, Br = 79.90

Molar mass of SiCl2Br2 = 28.08 + 35.45(2) + 79.90(2)

= 258.78

Hence, the molar mass of SiCl2Br2 is 258.78 g/mol

If 79.90 grams of bromine is present in 258.78 grams of SiCl2Br2

Then, 13.2 grams of bromine will be present in [tex]x[/tex] grams of SiCl2Br2

[tex]x[/tex] = (13.2× 258.78) / 79.90

[tex]x[/tex] = 42.75 grams

Hence, 42.75 grams of SiCl2Br2 must be weighed out.

There is 6.83L of water in a container. Calculate the volume of water in gallons.

Answers

Answer:

1.804295

Explanation:

Hope this helps <3

Show that the units of kinetic energy (from ½ mv2 ) and gravitational potential energy (from mgh) are the same.

Answers

Answer:

The units of both types of energy are Joule (kg × m² × s⁻²).

Explanation:

Step 1: Show the units of kinetic energy

The equation for kinetic energy is:

K = 1/2 × m × v²

where,

m: mass

v: speed

The units are:

K = 1/2 × m × v²

[K] = kg × (m/s)²

[K] = kg × m² × s⁻² = J

Step 2: Show the units of gravitational potential energy

The equation for gravitational potential energy is:

G = m × g × h

where,

m: mass

g: gravity

h: height

The units are:

G = m × g × h

[G] = kg × m/s² × m

[G] = kg × m² × s⁻² = J

A piece of metal with a mass of 150 g is placed in a 50 mL graduated cylinder. The water level rises from 20 mL to 45mL. What is the volume of the metal

Answers

Answer:

25 mL

Explanation:

The water level increased from 20mL to 45mL

That is the volume of the metal

45 - 20 = 25

The volume of the metal was 25 mL

Density = mass / volume

Density = 150 / 25

Density = 6 grams / mL

Choose the best answer below. Which of the following reactions will have the largest equilibrium constant at 298 K?
a) 302(g) → 203(9) AGOrxn = +326 kJ
b) Mg(s) + N20(g) → Mgo(s) + N2(g) AG9rxn = -673.0 kJ
c) 2Hg(g) + O2(g) → 2HgO(s) AGºrx = -180.8 kJ
d) CaCO3(s) » Cao(s) + CO2(g) AG = +131.1 kJ
It is not possible to determine the reaction with the largest equilibrium constant using the given information.

Answers

Answer:

Explanation:

Relation between ΔG₀ and K ( equilibrium constant ) is as follows .

lnK =  -  ΔG₀ / RT

[tex]K = e^{-\frac{\triangle G_0}{RT}[/tex]

The value of R and T are same for all reactions .

So higher the value of negative ΔG₀ , higher will be the value of K  .

Mg(s) + N₂0(g) → MgO(s) + N₂(g)

has the ΔG₀ value of -673 kJ which is highest negative value . So this reaction will have highest value of equilibrium constant K .

The reaction N O space plus thin space O subscript 3 space rightwards arrow space N O subscript 2 space plus thin space O subscript 2 is first order with respect to both NO and O3. The rate constatnt is 2.20 x 107 M-1s-1. If at a given moment, the concentration of NO is 3.3 x 10-6 M and the concentration of O3 is 5.9 x 10-7 M, what is the rate of reaction at that moment

Answers

Answer:

4.3 × 10⁻⁵ M s⁻¹

Explanation:

Step 1: Given data

Rate constant (k):  2.20 × 10⁷ M⁻¹s⁻¹Concentration of NO ([NO]): 3.3 × 10⁻⁶ MConcentration of O₃ ([O₃]): 5.9 × 10⁻⁷ MFirst order with respect to both NO and O₃

Step 2: Write the balanced reaction

NO + O₃ ⇒ NO₂ + O₂

Step 3: Calculate the reaction rate

The rate law is:

rate = k × [NO] × [O₃]

rate = 2.20 × 10⁷ M⁻¹s⁻¹ × 3.3 × 10⁻⁶ M × 5.9 × 10⁻⁷ M

rate = 4.3 × 10⁻⁵ M s⁻¹

Which family contains elements with a full octet of valence electrons?
A. The actinides
B. The halogens
C. The alkali metals
D. The noble gases

Answers

D. the noble gasses !!!!

The family of elements that contains elements with a full octet of valence electrons is D. The noble gases. These elements have achieved stability by completely filling their outer electron shells with 8 electrons (except for helium, which has 2).


Noble gases are located in Group 18 of the periodic table and include elements such as helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and radon (Rn). These elements have a completely filled outer electron shell, also known as a full octet. A full octet means that the outermost energy level of the atom contains 8 electrons, except for helium which has only 2 electrons.

Having a full octet of valence electrons makes noble gases highly stable and unreactive. This stability is due to the fact that the atoms of noble gases have achieved the same electron configuration as the nearest noble gas element.

For example, helium has a full outer shell with 2 electrons, which is the same electron configuration as the nearest noble gas, neon. Neon and the other noble gases have 8 electrons in their outermost shell, fulfilling the octet rule.

In contrast, the other options mentioned:

A. The actinides: The actinides are a series of elements in the periodic table that have their valence electrons in the 5f orbital. They do not have a full octet of valence electrons.

B. The halogens: The halogens are located in Group 17 of the periodic table and include elements such as fluorine (F), chlorine (Cl), bromine (Br), iodine (I), and astatine (At). These elements have 7 valence electrons and are highly reactive, seeking to gain one electron to achieve a full octet.

C. The alkali metals: The alkali metals are located in Group 1 of the periodic table and include elements such as lithium (Li), sodium (Na), potassium (K), rubidium (Rb), cesium (Cs), and francium (Fr). These elements have 1 valence electron and are highly reactive, seeking to lose this electron to achieve a full octet.

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Which of these names can be used to describe
this substance?
propylbutane
propane
dimethylmethane

Answers

Answer:

Dimethylmethane and propane

Explanation:

electrons are blank in an ionic bond, whereas they are blank in a polar covalent bond, and blank in a nonpolar covalent bond

Answers

Answer:

Electrons are transferred in an ionic bond, whereas they are unequally shared in a polar covalent bond, are equally blank in a nonpolar covalent bond.

Explanation:

An ionic bond involved the transfer of electron(s) from one atom to another. For instance, NaCl is formed by a transfer of one electron from sodium to chlorine.

A polar covalent bond is formed by an unequal sharing of electrons between atoms of different electro negativities. This is the case in polar HCl.

Non polar covalent bonds are formed when electrons are equally shared between two or more atoms such as in CH4.

Why is the oxygen end of the water molecule attracted to the sodium ion

Answers

Explanation:

oxygen has a negative charge

sodium has a positive charge

opposites attract

HBr can be added to an alkene in the presence of peroxides, R-O-O-R. What role do peroxides play in this reaction

Answers

Answer:

The peroxide initiates the free radical reaction

Explanation:

The addition of HBr to alkene in the presence of peroxides occurs via a free radical mechanism.

The organic peroxide acts as the initiator of the free radical reaction. The organic free radical interacts with HBr to produce a bromine free radical which now interacts with the alkene and the propagation steps continue until it is terminated by the coupling of two free radicals.

The peroxide effect leads to anti-Markovnikov addition.

digesting a candy bar is a physical change or chemical change? why?​

Answers

Answer:

Chemical Change

Explanation:

Because it dissolves with the help of saliva , then into stomach and excreted in a different form

Answer:

Yess its a chemical change

:*

Explanation:

If two separate containers A and B have the same volume and temperature, but container A has more gaseous molecules than B, then container A will have:

Answers

Answer:

Higher pressure, is the right answer.

Explanation:

The A will have a higher pressure. Since we have given the volume and temperature is same in both containers A and B. Below is the calculation for proof that shows which container has the higher pressure while keeping the volume and temperature the same.  

[tex]So, \ V_A = V_B \\\frac{n_A T_A}{P_A} = \frac{n_B T_B}{P_B} \\Here, \ T_A = T_B \\P_A = \frac{n_A}{n_B} \times P_B \\\frac{n_A}{n_B} > 1 \\\frac{P_A}{P_B} > 1 \\P_A > P_B \\[/tex]

Therefore, the container “A” will have higher pressure.

Container A will have a higher pressure than container B.

According to the approximations of ideal gas conditions, the pressure of a gas is directly proportional to the number of molecules of a gas at constant temperature and volume.

Having this in mind, at constant temperature and volume, container A has more gaseous molecules than B, then container A will have a higher pressure than container B.

Missing parts;

If two separate containers A and B have the same volume and temperature, but container A has more gaseous molecules than B, then container A will have: A) Higher pressure B) Lower pressure C) A greater universal gas constant D) A smaller universal gas constant

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What happens to the molecules of a liquid when it cools

Answers

Answer:

As the molecules of a liquid are cooled they slow down. As the molecules slow down they take up less volume. Taking up less room because of the molecules lower energy causes the liquid to contract.

Explanation:

PLZ HELP ASAP FOR 20 POINT FOR BOTH!

Answers

1.08 g/cm^3
(when multiplying or dividing you use the least amount of significant figures to answer your question by which is the 19.5. That gives you 3 significant figures.)

4.83 km
(when adding or subtracting however you use the least precise the 4.810 goes into the thousandths place which is more precise then the 0.08 which only goes to the hundredths place.)
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