Answers
Check the picture below.
there are a few angles shaded, I'll call that angle at O ∡O, and that angle at "x" ∡x and the green angle at A, ∡A, and the angle at B, ∡B, just so you know which angle we're referring to.
well, first off let's notice that B and C are points of tangency, meaning we get right-angles as you see in the picture, if we run an angle bisector from ∡x, towards point O, we get two congruent triangles, lemme shorten that up some, 90 + 90 + ∡O +∡x = 360, which means that ∡O + ∡x = 180, meaning that ∡O = 180 - ∡x, if that's so, the angle at point O across the shade, is 360 - ∡O or 360 - (180 - ∡x).
alrighty, by the inscribed angle theorem, ∡A is half of ∡O.
let's now focus on the triangle AOB, we'll be using half of ∡A and half of ∡O and ∡B on that triangle, let's proceed.
[tex]\measuredangle x + \measuredangle O=180\implies \measuredangle O=180-\measuredangle x \\\\\\ \measuredangle A = \cfrac{\measuredangle O}{2}\implies \measuredangle A = \cfrac{180-\measuredangle x}{2} \\\\\\ \stackrel{\textit{the angle across from }\measuredangle O~is}{360-\measuredangle O}\implies 360-(180 - \measuredangle x)\implies 180+\measuredangle x \\\\[-0.35em] ~\dotfill[/tex]
[tex]\stackrel{\textit{\large the sum of all three angles at }\triangle AOB}{\stackrel{\textit{half of }\measuredangle A}{\cfrac{1}{2}\cdot \cfrac{180-\measuredangle x}{2}}~~ + ~~\stackrel{\textit{half the angle across from }\measuredangle O}{\cfrac{180+\measuredangle x}{2}}~~ +~~\measuredangle B~~ =~~180} \\\\\\ \cfrac{180-\measuredangle x}{4}+\cfrac{180+\measuredangle x}{2}+\measuredangle B = 180[/tex]
now, let's multiply both sides by the LCD of all denominators, hmmmm in this case that'll be 4, so multiplying both sides by the LCD will do away with the denominators, so let's do so.
[tex]4\left( \cfrac{180-\measuredangle x}{4}+\cfrac{180+\measuredangle x}{2}+\measuredangle B \right) = 4(180) \\\\\\ (180-\measuredangle x)+2(180+\measuredangle x)+4\measuredangle B = 720 \\\\\\ (180-\measuredangle x)+(360+2\measuredangle x)+4\measuredangle B = 720\implies 540+\measuredangle x+4\measuredangle B = 720[/tex]
[tex]\measuredangle x+4\measuredangle B = 180\implies 4\measuredangle B = 180-\measuredangle x\implies \measuredangle B = \cfrac{180-\measuredangle x}{4} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \measuredangle B = 45 - \cfrac{\measuredangle x}{4}~\hfill[/tex]
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Answer:
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Step-by-step explanation:
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Step-by-step explanation:
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Filler and more filler
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Answers
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Answers
a.
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Answers
Answer:
y = 10; x = -2
Step-by-step explanation:
Because both are equal to y, you can set them equal to each other.
-9x - 8 = -6x - 2
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Answer:
4900
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Answer:
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Zayden has a total of 20 bills in his wallet. Also, his wallet only contains $50 and $100 bills. If the numbers of $50 and $100 bills are interchanged, the total amount of money in Zayden’s wallet would be $500 more than it originally was. Find the original amount of money in his wallet.
$
Answers
Step-by-step explanation:
x = number of $50 bills
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triangle total angle value = 180°
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Answer:
Step-by-step explanation:
This is an isosceles triangle. You can tell because 2 of the sides are equal and the third is not equal to either of the other two.
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Answers
Answer : 115,200
Step - by - step explanation :
sorry if this is wrong !
127,600 --> 128,000
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Answer:
50 miles
Step-by-step explanation:
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Answer:
50 miles
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See picture attached
Graph the line that has a slope of 4/3 and contains the point (0,-4)?
Please I need help fast
Answers
Answer:
It's attached
Step-by-step explanation:
y=4/3x-4
is the equation for the line
So you just plot the line.
The equation for the given slope and point is y = 4x/3 - 4
What is slope?The slope of a line is a number that describes both the direction and the steepness of the line.
Given that, a line that has a slope of 4/3 and contains the point (0,-4)
The slope intercept of a line is y = mx+c, where m is slope,
Here, m = 4/3, x = 0 and y = -4
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-4 = 4/3x0+c
c = -4
Establishing the equation,
y = 4x/3-4
Now plotting the graph,
(Attached)
Hence, the graph will pass through the points (3,0) and (0,-4)
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