Answer:
A
Step-by-step explanation:
In this question, we are concerned with selecting which of the options best represents the difference of two squares.
Let’s have an exposition below as follows;
Consider two numbers, which are perfect squares and can be expressed as a square of their square roots;
a^2 and b^2
where a and b represents the square roots of the numbers respectively.
Inserting a difference between the two, we have;
a^2 - b^2
Now by applying the difference of two squares, these numbers will become;
a^2 - b^2 = (a + b)(a-b)
So our answer out of the options will be that option that could be expressed as above.
The correct answer to this is option A
Kindly note that;
x^2 -9 can be expressed as x^2 - 3^2 and consequently, this can be written as;
(x-3)(x + 3)
a number y cubed plus x squared decreased by 7
Step-by-step explanation:
It is read thus Y^3+X^2-7
The equation form from the given statement would be Y^3 + X^2 - 7.
How to form mathematical expression from the given description?You can represent the unknown amounts by the use of variables. Follow whatever the description is and convert it one by one mathematically.
For example if it is asked to increase some item by 4 , then you can add 4 in that item to increase it by 4.
We have been given a statement as;
"A number y cubed plus x squared decreased by 7".
So, the equation form would be
Y^3 + X^2 - 7
Learn more about expression here;
https://brainly.com/question/14083225
#SPJ2
The complete question is
"A number y cubed plus x squared decreased by 7". write the expression.
Trigonometric ratios
class 9
please answer my questions
Step-by-step explanation:
Hi there!
Please see the answer in the picture.
Hope it helps!
1. Approach
One is given a trigonometric equation with and one is asked to prove that it is true. Using the attached image, combined with the knowledge of trigonometry, one can evaluate each trigonometric function. Then one can simplify each ratio to solve. To yield the most accurate result, one has to each of the ratios in a fractional form, rather than simplifying it into a decimal form. Remember the right angle trigonometric ratios, these ratios describe the relationship between the sides and angles in a right triangle. Such ratios are as follows,
[tex]sin(\theta)=\frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}\\\\tan(\theta)=\frac{opposite}{adjacent}\\\\csc(\theta)=\frac{hypotenuse}{opposite}\\\\sec(\theta)=\frac{hypotenuse}{adjacent}\\\\cot(\theta)=\frac{adjacent}{opposite}[/tex]
Please note that the terms (opposite) and (adjacent) are relative to the angle uses in the ratio, however the term (hypotenuse) refers to the side opposite the right angle, this side never changes its name. Use these ratios to evaluate the trigonometric functions. Then simplify to prove the identity.
2. Problem (9)
[tex]\frac{sin(60)+cos(30)}{1+sin(30)+cos(60)}=sin(60)[/tex]
As per the attached image, the following statements regarding the value of each ratio can be made:
[tex]sin(60)=\frac{\sqrt{3}}{2}\\\\cos(30)=\frac{\sqrt{3}}{2}\\\\sin(30)=\frac{1}{2}\\\\cos(60)=\frac{1}{2}[/tex]
Substitute,
[tex]\frac{sin(60)+cos(30)}{1+sin(30)+cos(60)}=sin(60)[/tex]
[tex]\frac{\frac{\sqrt{3}}{2}+\frac{\sqrt{3}}{2}}{1+\frac{1}{2}+\frac{1}{2}}=\frac{\sqrt{3}}{2}[/tex]
Simplify,
[tex]\frac{\frac{\sqrt{3}}{2}+\frac{\sqrt{3}}{2}}{1+\frac{1}{2}+\frac{1}{2}}=\frac{\sqrt{3}}{2}[/tex]
[tex]\frac{\frac{2\sqrt{3}}{2}}{1+\frac{1}{2}+\frac{1}{2}}=\frac{\sqrt{3}}{2}[/tex]
[tex]\frac{\frac{2\sqrt{3}}{2}}{1+1}=\frac{\sqrt{3}}{2}[/tex]
[tex]\frac{\sqrt{3}}{1+1}=\frac{\sqrt{3}}{2}[/tex]
[tex]\frac{\sqrt{3}}{2}=\frac{\sqrt{3}}{2}[/tex]
Thus, this equation is true.
2. Problem (10)
Use a similar strategy to evaluate this equation,
[tex]\frac{1-cos(30)}{sin(30)}=\frac{1-cot(60)}{1+cot(60)}[/tex]
Use the attached image to evaluate the ratios.
[tex]cos(30)=\frac{\sqrt{3}}{2}\\\\sin(30)=\frac{1}{2}\\\\cot(60)=\frac{1}{\sqrt{3}}[/tex]
Substitute,
[tex]\frac{1-cos(30)}{sin(30)}=\frac{1-cot(60)}{1+cot(60)}[/tex]
[tex]\frac{1-\frac{\sqrt{3}}{2}}{\frac{1}{2}}=\frac{1-\frac{1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]
Simplify,
[tex]\frac{1-\frac{\sqrt{3}}{2}}{\frac{1}{2}}=\frac{1-\frac{1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]
[tex]\frac{\frac{2-\sqrt{3}}{2}}{\frac{1}{2}}=\frac{1-\frac{1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]
[tex]\frac{\frac{2-\sqrt{3}}{2}}{\frac{1}{2}}=\frac{\frac{\sqrt{3}-1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]
[tex]\frac{\frac{2-\sqrt{3}}{2}}{\frac{1}{2}}=\frac{\frac{\sqrt{3}-1}{\sqrt{3}}}{\frac{\sqrt{3}+1}{\sqrt{3}}}[/tex]
[tex]2-\sqrt{3}=\frac{\frac{\sqrt{3}-1}{\sqrt{3}}}{\frac{\sqrt{3}+1}{\sqrt{3}}}[/tex]
[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}}*\frac{\sqrt{3}}{\sqrt{3}+1}}[/tex]
[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}+1}[/tex]
Rationalize the denominator,
[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}+1}[/tex]
[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}+1}*\frac{\sqrt{3}-1}{\sqrt{3}-1}[/tex]
[tex]2-\sqrt{3}=\frac{(\sqrt{3}-1)^2}{3-1}[/tex]
[tex]2-\sqrt{3}=\frac{3-2\sqrt{3}+1}{2}[/tex]
[tex]2-\sqrt{3}=\frac{4-2\sqrt{3}}{2}[/tex]
[tex]2-\sqrt{3}=2-\sqrt{3}[/tex]
Therefore, this equation is also true.
find the value s of.. a and b if 0 and 2 are the zeros of the polynomial p(x) =2xcube minus 5xsquare plus ax plus b find the third zero of the polynomial
Answer:
a = 2, b = 0 , x = [tex]\frac{1}{2}[/tex]
Step-by-step explanation:
Given that x = 0 and x = 2 are zeros of p(x) , then
p(0) = 0 and p(2) = 0
p(0) = 2(0)³ - 5(0)² + a(0) + b = 0 , that is
0 - 0+ 0 + b = 0, then b = 0
p(2) = 2(2)³ - 5(2)² + 2a + b = 0 , that is
16 - 20 + 2a + 0 = 0
- 4 + 2a = 0 ( add 4 to both sides )
2a = 4 ( divide both sides by 2 )
a = 2
Then
p(x) = 2x³ - 5x² + 2x ← factor out x from each term
= x(2x² - 5x + 2)
= x(2x - 1)(x - 2)
To find zeros equate p(x) to zero
x(2x - 1)(x - 2) = 0
Equate each factor to zero and solve for x
x = 0
x - 2 = 0 ⇒ x = 2
These are the 2 zeros already known (given)
2x - 1 = 0 ⇒ 2x = 1 ⇒ x = [tex]\frac{1}{2}[/tex] ← third zero of p(x)
find the lower quartile for the data {47.2, 33.8, 43, 62, 5.8, 9, 61.4, 30.8, 68.2, 51.6, 13.2, 17.4, 64.2, 50.6, 29.4, 40.4}
Answer:
The lower quartile is 23.4
Step-by-step explanation:
The given data are;
47.2, 33.8, 43, 62, 5.8, 9, 61.4, 30.8, 68.2, 51.6, 13.2, 17.4, 64.2, 50.6, 29.4, 40.4
Rearranging the data, we have;
5.8, 9, 13.2, 17.4, 29.4, 30.8, 33.8, 40.4, 43, 47.2, 50.6, 51.6, 61.4, 62, 64.2, 68.2
The lower quartile, Q₁, is the (n + 1)/4 th term which is (16 +1)/4 = 4.25th term
However since we have an even set of numbers, we place a separator at the middle and we look for the median of the left half as follows
5.8, 9, 13.2, 17.4, 29.4, 30.8, 33.8, 40.4║ 43, 47.2, 50.6, 51.6, 61.4, 62, 64.2, 68.2
We have two numbers (17.4 + 29.4) at the median of the left set of numbers, we find the average of the two numbers to get the lower quartile
The lower quartile is therefore = (17.4 + 29.4)/2 = 23.4.
Find the missing value can someone help me get this
Answer:
-3
Step-by-step explanation:
-5 = -8 - (- 3)
factorise the following 1. x²-2x+15.... 2. y²-19y+90
Answer:
1. x²-2x+15
This can't be factored, I've tried multiple ways now, but it just can't be factored.
2. y²-19y+90
Let's factor y^2−19y+90
y^2−19y+90
The middle number is -19 and the last number is 90.
Factoring means we want something like
(y+_)(y+_)
Which numbers go in the blanks?
We need two numbers that...
Add together to get -19
Multiply together to get 90
Can you think of the two numbers?
Try -9 and -10:
-9+-10 = -19
-9*-10 = 90
Fill in the blanks in
(y+_)(y+_)
with -9 and -10 to get...
(y-9)(y-10)
Answer:
(y−9) (y−10)
please answer if you can
Step-by-step explanation:
denominator
add numerator
Rick is driving to his uncle's house in Greensville, which is 120 miles from Rick's town. After covering x miles, Rick sees a sign stating that Greensville is 20 miles away. Which equation, when solved, will give the value of x?
Answer:
The equation which will give the value of x when solved is C. x + 20 = 120
x=100
Step-by-step explanation:
Total distance=120 miles
Distance covered=x miles
Distance remaining=20 miles
The equation is
Total distance=Distance covered + distance remaining
120 miles= x miles + 20 miles
120 miles - 20 miles = x miles
100 miles =x miles
Check:
Total distance=Distance covered + distance remaining
120 miles = 100 miles + 20 miles
120 miles =120 miles
The equation which will give the value of x when solved is C. x+20=120
the difference of two numbers is 24.if the smaller number is 38,find the greater one
Answer:
62
Step-by-step explanation:
add 24 to the smaller number to get the greater one
Answer:
62
Step-by-step explanation:
let, the greater number be 'x' and smaller number be 'y'
x-y=24 i.e. x-38=24
or, X=24+38
X= 62
what is the x intercept for y=(2x(x-3))/(x-1). ?
my answer sheet says it is supposed to be -0.5
Answer:
( 0,0) and (3,0)
Step-by-step explanation:
y=(2x(x-3))/(x-1)
Set y = 0
0 =(2x(x-3))/(x-1)
Multiply each side by x-1, which makes x not equal to 1
0 =(2x(x-3))
Using the zero product property
2x=0 x-3 =0
x=0 x= 3
The x intercepts are x=0 x= 3
( 0,0) and (3,0)
Sammy and Hannah are finalists in a cooking competition. For the final round, each of them will randomly select a card without replacement that will reveal what their star ingredient must be. Here are the available cards:
Cabbage
Spinach
Kale
Leeks
Carrots
Turnips
Cabbage
Leeks
Spinach
Carrots
Kale
Turnips
Sammy and Hannah both want to get leeks as their star ingredient. Sammy will draw first, followed by Hannah.
What is the probability that NEITHER contestant draws leeks?
Round your answer to two decimal places.
The probability that neither of them draws the Leeks card is P = 4/6 = 0.667
Here we can assume that all the cards have the same probability of being randomly drawn.
The cards are:
Cabbage Spinach Kale Leeks Carrots TurnipsSo we have 6 cards. We want to find the probability that neither contestant draws the "Leeks" card.
Sammy draws first, the probability of drawing the Leeks card will be equal to the quotient between the number of Leeks cards (one) and the total number of cards (6).
Then the probability of drawing the leeks card is p = 1/6
This means that the probability of NOT drawing the leeks card is:
q = 1 - 1/6 = 5/6.
Now draws Hanna, now there are 5 cards in the deck (because one was already drawn). With the same approach as before, the probability of drawing the Leeks card is p = 1/5, then the probability of NOT drawing the card is:
q = 1 - 1/5 = 4/5.
The joint probability (this is, the probability of both of these events to happen together) is just the product of the individual probabilities.
Then the probability that neither of them draws the Leeks card is:
P = (4/5)*(5/6) = 4/6 = 0.667
If you want to learn more about probability, you can read:
https://brainly.com/question/24349426
T. For a science experiment, Katie had
to cool one sample bacteria to -52°C.
She had to cool a second sample
bacterium to -79°C. What is the
difference in the two temperatures?
Please help me figure out the equation too.
Answer:
Step-by-step explanation:
A "difference" indicates subtraction is being used. The difference between these 2 numbers is found the same way we find the distance between 2 points on a number line. Since both the difference and the distance have to be positive numbers, the formula to find it is
|a - b| which is the absolute value of a - b.
If a = -52 and b = -79:
| -52 - (-79) | = | -52 + 79 | = 27 OR
If a = -79 and b = -52:
| -79 - (-52) | = | -79 + 52 | = | -27 | = 27
Donny has three times as many candy canes as Marc. Marc has thirty more candy canes than Bob. They have 500 candy canes altogether. How many candy canes does Donny have?
Answer:
318
Step-by-step explanation:
Bob=x
Marc=x+30
Donny=3(x+30)
x+x+30+3x+90=500
5x=500-120
5x=380
x=76
Bob has x = 76
Marc has x+30=106
Donny has 3*112=318
318+106+76=500
Which set of integers are in the right order from least to greatest?
1-10], -3, 2,7
7, 1-10], -3,2
2, -3, 7, 1-10
-3, 2, 7, 1-10
Answer:
1-10, -3, 2, 7
im sorry if i give a wrong answer
We can calculate EEE, the amount of euros that has the same value as DDD U.S. Dollars, using the equation E=\dfrac{17}{20}DE= 20 17 DE, equals, start fraction, 17, divided by, 20, end fraction, D. How many euros have the same value as 111 U.S. Dollar? euros How many U.S. Dollars have the same value as 111 euro? dollars
Answer: 1 U.S.dollar = 0.85 euro.
1 euro = 1.18 dollars.
Step-by-step explanation:
The given equation: [tex]E=\dfrac{17}{20}D[/tex]
, where 'E' is the amount of euros that has the same value as 'D' U.S. Dollars.
At D= 1,
[tex]E=\dfrac{17}{20}=0.85\text{ euro}[/tex]
i.e. 1 U.S.dollar = 0.85 euro.
At E= 1 , we have
[tex]1=\dfrac{17}{20}D\\\\\Rightarrow\ D= 20/17\approx1.18\text{ dollars}[/tex]
Hence, 1 euro = 1.18 dollars.
(SAT Prep) Find the value of x
Answer:
55°Step-by-step explanation:
It should be:
x - 25 = 45 - 15x = 30 + 25x = 55the king needs a 10th graders help DX
Answer:
12) 1/8 inch = 0.125 inch
= 0.003175 m
= 3.175 x 10-3 m
= 0.3175 cm
13) 2 is rational and π is irrattional. π is approximately 3.14 and is the bigger of two
14) C= 40,005,306.33 m
= 4.0005 x 107 m
15) 12,615,800,000
= 1.26158 x 1010
=126158 x 105
16) Let's take speed of ant as 1Km/h=1000m/h. Then time 1666.875 days
Step-by-step explanation:
The perimeter of a square is numerically equals to its area. Find its side and area.
Answer:
4 and 16 units²
Step-by-step explanation:
The perimeter of a square of side s = 4s and area = s² , equating gives
s² = 4s ( subtract 4s from both sides )
s² - 4s = 0 ( factor out s from each term on the left )
s(s - 4) = 0
Equate each factor to zero and solve for s
s = 0
s - 4 = 0 ⇒ s = 4
However, s > 0, thus s= 4
That is side = 4 units and area = 4² = 16 units²
For a ,a relationship to be a function, which values cannot repeat: the x-
values or the y-values? *
Answer:
The x - valuesThe y-values repeat in various functions (for example: quadratic function: y=x²; y=4 for x=2 and for x=-2)
What if the following choices will simplify 7-5(3)^2
answers:
1)18
2)12
3)-38
4)None of the choices are correct
Answer:
-38
Step-by-step explanation:
7-5(3)^2
PEMDAS
Since there are no parentheses to execute
Exponents next
7-5(3)^2
7-5*9
Multiply and divide next
7 - 45
-38
pls help with this question
Try this
(x^2 + x - 12) + (x^2 - 8x + 16)
2y - 1
√36
i wanted to help you! :)
Answer:
[tex]\frac{3}{3}[/tex] = 1 (everything basically cancels)
Step-by-step explanation:
Help me pls pls help me
Answer:
F. 1/2
Step-by-step explanation:
If the ratio of team assistants to players are 1/6 and there are 36 players that means that there are 6 team assistants. If we do the ratio of coaches to assistant that would be 3/6 or F. 1/2
Y=-5x+30 x=10 what is the solution to the system of equations 1)(-20,10) 2)(10,-20) 3)(10,4) 4)(4,10)
Answer:
2) (10, -20)Step-by-step explanation:
y = - 5x + 30 and x = 10 ⇒ y = -5•10 + 30 = -50 + 30 = -20
x = 10 and y = -20 ⇒ (10, -20)
Answer:
Its B. (10, –20)
Step-by-step explanation:
I just took the quiz on edge
The common difference of an ap is -2 find its sum of first term is hundred and last term is -10 with full solution
Answer:
2520
Step-by-step explanation:
The n th term of an AP is
[tex]a_{n}[/tex] = a₁ + (n - 1)d
where a₁ is the first term and d the common difference.
To find the number of terms given [tex]a_{n}[/tex] = - 10 , d = - 2 and a₁ = 100, then
100 - 2(n - 1) = - 10 ( subtract 100 from both sides )
- 2(n - 1) = - 110 ( divide both sides by - 2 )
n - 1 = 55 ( add 1 to both sides )
n = 56 ← number of terms
Given n, a₁ and a₅₆ , then the sun of the terms is
[tex]S_{56}[/tex] = [tex]\frac{n}{2}[/tex] (a₁ + a₅₆ )
= [tex]\frac{56}{2}[/tex] (100 - 10) = 28 × 90 = 2520
Please answer this question now
Answer:
AB = 72°
Step-by-step explanation:
The inscribed angle ADC is half the measure of its intercepted arc, thus
56° = [tex]\frac{1}{2}[/tex] ( m ABC ) ← multiply both sides by 2
112° = ABC
ABC = AB + BC = AB + 40, so
AB + 40 = 112 ( subtract 40 from both sides )
AB = 72°
The area of a square field is 60025 square metre. Find the perimeter of the field. With explanation .
Answer: P≈2.4×10 power5
Step-by-step Explanation: P=4a=4·60025=2.401×10 power5
Answer:
[tex]\huge \boxed{\mathrm{980 \ m}}[/tex]
Step-by-step explanation:
The formula for the area of a square is:
[tex]A=s^2[/tex]
The area is given as 60025 m².
We need to find the length of each side.
[tex]60025=s^2[/tex]
Take the square root of both sides.
[tex]s=245[/tex]
The side length is 245 m.
The formula for the perimeter of a square is:
[tex]P=4s[/tex]
Plug in the value for the side length.
[tex]P=4(245)[/tex]
[tex]P=980[/tex]
The perimeter of the field is 980 m.
Complete the sequence
8,27,64,125,.........
Just next letter
Answer:
216.
Step-by-step explanation:
These numbers are perfect cubes starting with 2^3.
2^3, 3^3, 4^3, 5^3 so the next one is 6^3, which is 216.
Can someone please do this for me please
Answer:
r=-11
Step-by-step explanation:
7r+2=5(r-4)
7r+2=5r-20
2r=-22
r=-11
Simply. If the solution is not a real number enter not a real number rotate picture answer all 3 please
Answer:
13. [tex]\frac{\sqrt[5]{x^4} }{x}[/tex].
14. [tex]v = \pm3\sqrt{5}[/tex]
15. 2.
Step-by-step explanation:
13. [tex]x^{1/5} * x^{-2/5}[/tex]
= [tex]x^{1/5 + (-2/5)}[/tex]
= [tex]x^{1/5 - 2/5}[/tex]
= [tex]x^{-1/5}[/tex]
= [tex]\frac{1}{x^{1/5}}[/tex]
= [tex]\frac{x^{4/5}}{x^{1/5 + 4/5}}[/tex]
= [tex]\frac{x^{4/5}}{x}[/tex]
= [tex]\frac{\sqrt[5]{x^4} }{x}[/tex].
14. [tex]v^2 - 45 = 0[/tex]
[tex]v^2 = 45[/tex]
[tex]\sqrt{v^2} = \pm\sqrt{45}[/tex]
[tex]\sqrt{v^2} = \pm\sqrt{3^2 * 5}[/tex]
[tex]v = \pm3\sqrt{5}[/tex].
15. [tex]\sqrt[3]{2} * \sqrt[3]{4}[/tex]
= [tex]\sqrt[3]{2 * 4}[/tex]
= [tex]\sqrt[3]{2 * 2 * 2}[/tex]
= [tex]\sqrt[3]{2 ^3}[/tex]
= 2.
Hope this helps!
PLEASE HELP ME FAST...
I will mark you a BRAINLEST
Answer: Hi!
Row A: 7, 11, 15, 19, 23
Row B: 51, 42, 33, 24, 15
Row C: 4, 8, 16, 32, 64
Row D: 64, 32, 16, 8, 4
(If you notice, Row C and Row D are just swapped in order!)
Hope this helps!
Hi there! Hopefully this helps!
--------------------------------------------------------------------------------------------------------------
A's rule, add 4: 7, 11, 15, 19, 23
B's rule, Subtract 9: 51, 42, 33, 24, 15
C's rule, Multiply by 2: 4, 8, 16, 32, 64
D's rule, Divide by 2: 64, 32, 16, 8, 4