Identify the segments that are parallel, if any, if ∠EDA≅∠HCB.

Answers

Answer 1

In the above question, (image attached) The option that shows the segments that are parallel, if any, if ∠EDA≅∠HCB is option A: None of these.

What is the line segment about?

Note that by examining the the image if ∠EDA≅∠HCB, the two lines can never intersect even if they go a longer distance.

The reason why is that there are no parallel lines on it and as such, they cannot intercept.

Hence, In the above question, (image attached) The option that shows the segments that are parallel, if any, if ∠EDA≅∠HCB is option A: None of these.

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Identify The Segments That Are Parallel, If Any, If EDAHCB.

Related Questions

the bus bound for northtown departs every 15 minutes and the bus for eastown departs every 18 minutes from the central station. Both buses start at 9:30 AM each morning. When is the next time both buses will depart from the central station at the same time?

Answers

Considering the least common factor of 15 and 18, it is found that they will depart from the central station at the same time at 11 AM.

How to find the time it takes for periodic events to repeat at the same time?

To find the time that passes between the events happening at the same time, we need to find the least common multiple of the periods.

In this problem, the periods are of 15 and 18, hence their lcm is found as follows:

15 - 18|2

15 - 9|3

5 - 3|3

5 - 1|5

1 - 1

Hence:

lcm(15,18) = 2 x 3 x 3 x 5 = 90 minutes.

They will depart from the central station at the same time in 90 minutes from 9:30 AM, hence at 11 AM.

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I can find the 3 third side of the triangle

Answers

Answer:

15

Step-by-step explanation:

First side is 20

Second side is 20 * (3/2), as it is 1 and 1 half times longer than the first

Second side is 30(as calculated above)

65-20-30 = 15


The formula for finding the kinetic energy, E, of an object is given below, where m represents the mass and v represents the speed of
the object.
Solve the formula for v

Answers

The formula for the velocity, v is √2E/m

What is kinetic energy?

Kinetic energy is half the mass multiplied by the square of the speed of the object

It is written thus;

Kinetic energy = 1/ 2 × m × v²

To solve for 'v' mean that we should make 'v' the subject of formula

E = 1/ 2 mv²

E = [tex]\frac{mv^2}{2}[/tex]

cross multiply

[tex]2E = mv^2[/tex]

To make 'v' the subject, we have

[tex]v = \sqrt{\frac{2E}{m} }[/tex]

Thus, the formula for the velocity, v is √2E/m

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A manufacturing firm has adopted a new layout for its production process, which is intended to increase worker productivity. With the old layout, mean daily output was 200 units. A manager wants to test the null hypothesis that with the new layout, mean daily output is no greater than 200, against the alternative hypothesis that it is greater than 200. Assume that daily output levels are approximately normally distributed, with standard deviation 18 units. Which sampling distribution is the basis for this hypothesis test? Letter (see multiple choices in the instructions)

Answers

Since the standard deviation for the population is known, the z-distribution is used as the sampling distribution basis for this hypothesis test.

When to use the t-distribution and the z-distribution?

If the population standard deviation is known, the z-distribution is used.If the population standard deviation is not known, only the sample standard deviation, the t-distribution is used.

In this problem, the standard deviation for the population is known, hence the z-distribution is used.

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Using algebra, prove that 0.136 (3,6 recurring) is equal in value to 1/33.

Answers

Answer:

0.1363636... = 3/22

Step-by-step explanation:

Let x = 0.1363636...

           100x = 13.6363636...

  (-)            x =   0.1363636...

------------------------------------------

              99x = 13.5

x = 13.5/99

x = 135/990

x = 27/198

x = 9/66

x = 3/22

0.1363636... = 3/22

0.1363636... is not equal to 1/33.

1/33 = 0.030303...

The students at a High School earned money for an international animal rescue foundation. 82 seniors earned an average $26.75 per student, 74 juniors earned an average $12.25 per student, 96 sophomores earned an average $15.50 per student, and 99 freshmen earned an average $10.85 per student. What was the average collection for a student in this school?

Answers

Using the mean concept, the average collection for a student in this school was of $16.13.

What is the mean?

The mean of a data-set is given by the sum of all observations in the data-set divided by the number of observations.

The number of students is given as follows:

82 + 74 + 96 + 99 = 351.

The sum is:

82 x 26.75 + 74 x 12.25 + 96 x 15.50 + 99 x 10.85 = $5662.15

Hence the mean is:

M = $5662.15/351 = $16.13.

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Solve the equation. -9×+1==×+17 O x=-8 O x = -2 O x=2 © ) x=8

Answers

The answer of this is -9= c+ b

Rhombus LMNO is shown with its diagonals.

Rhombus L M N O is shown. Diagonals are drawn from point M to point O and from point L to point N and intersect at point P. All sides are congruent.

Angle MLO measures 112°. What is the measure of angle MLP?
45°
56°
68°
90°

Answers

The angle m∠MLP in the rhombus is 56 degrees.

How to find the angle of a rhombus?

A rhombus has all its sides equal to each other.  The diagonals of a rhombus are angle bisectors.

Therefore,

m∠MLP = m∠MLO / 2

m∠MLO = 112°

m∠MLP = 112 / 2

Therefore,

m∠MLP = 56 degrees.

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Answer:

B. 56

Step-by-step explanation:

trust

What is the standard equation for the circle with center (1,-3) that passes through the point (2,2)?

Answers

The standard equation for the circle is (x - 1 ) ^2 + (y + 3)^2 = 2 ^2

A circle is a closed curve that is drawn from a fixed point called the center in which all points on the curve are the same distance from the center of the center. The equation of a circle with center (h, k) and radius r is given by:

(x-h)^2 + (y-k)^2 = r^2

This is the standard form of the equation. So if we know the coordinates of the center of the circle and also its radius, we can easily find its equation.

Consider any point P(x, y) on the circle. Let "a" be the radius of the circle which is equal to OP.

We know that the distance between the point (x, y) and the origin (0,0) can be found using the distance formula which is equal to -

√[x^2+y^2]= a

Therefore the equation of a circle with center as origin is,

x^2+y^2= a^2

Where "a" is the radius of the circle.

An alternative method

Let's derive another way. Assume that (x,y) is a point on the circle and the center of the circle is at the origin (0,0). Now, if we draw a perpendicular from the point (x,y) to the x-axis, we get a right triangle, where the radius of the circle is the hypotenuse. The base of the triangle is the distance along the x-axis and the height is the distance along the y-axis. Applying the Pythagorean theorem here, we therefore obtain:

x^2+y^2 = radius^2

We need to find the standard equation for the circle with center (1,-3) that passes through the point (2,2)

Standard equation for circle is

(x-h)^2 + (y-k)^2 = r^2................(1)

Here h = 1 , k = -3 and r = 2

put this value of h, k and r in equation (1), we get

(x - 1 ) ^2 + (y + 3)^2 = 2^2

Hence the standard equation of the circle is

(x - 1 ) ^2 + (y + 3)^2 = 2 ^2

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Consider the given set of numbers 70, 81, 91, 83, 88, and 55. A new number equal to a 12% increase in the median of this set is added to the list. What percentage larger is the mean of the new list in comparison with the original

Answers

New mean is 2.53% larger than the original mean.

What is mean?

Mean is nothing but the average of the given set of values. It denotes the equal distribution of values for a given data set.

We can find the percentage larger is the mean of the new list in comparison with the original as shown below:

Given, set of number 55, 70, 81, 83, 88, 91

Median= (81+83)/2

= 164/2

= 82

Mean = (55+70+81+83+88+91)/6

= 468/6

= 78

New value which is added = 82*1.12

= 91.84

New Mean = (55+70+81+83+88+91+91.84)/7

= 559.84/7

= 79.97

Increase in mean = 79.97-78

=1.97

increase percentage (1.97/78) *100

= 2.53%

Hence, new mean is 2.53% larger than the original mean.

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A cup holds 2\9 litre of water. How many cups of water can be filled with 3litre bottle

Answers

Answer:

the answer might be 13.5

write 75 as a product of prime use index notation when giving your answer

Answers

The prime factorization of 75 is 3 × 5 × 5 or 3 x 52.

I'J'is a translation of IJ Write the translation rule.

Answers

Answer:

(x+6), (y+9)

Step-by-step explanation:

The x coordinate of J goes from -7 to -1, so it is translated x+6

The y coordinate of j goes from -8 to 1, which is a difference of 9, so it's translated y + 9

Find the area of each figure as described or shown. Write final answer on blank provided. Show work. Include units as part of your answer. If needed, round answer to 2 decimal places.

Answers

Answer:

482.84u², 42.5cm², 51.5ft²

Step-by-step explanation:

1) A = 2(1 + √2)a²

A = 2(1 + √2)(80 / 8)²

A = 482.84units²

2) Square = 5²

Square = 25

T1 = 3 x 5 / 2

T1 = 7.5

T2 = 4 x 5 / 2

T2 = 10

Total = 10 + 7.5 + 25

Total = 42.5cm²

3) Rect = 4(8 + 3)

Rect = 44

T1 = 2 x 3 / 2

T1 = 3

T2 = 3 x 3 / 2

T2 = 4.5

Total = 3 + 4.5 + 44

Total = 51.5ft²

A circular table has a radius of 5cm. decorative trim is placed along the outside edge. how long is the trim?single line text.

Answers

If the radius of the circular table is 5 cm then the length of the trim required is 31.4 cm.

Given that the radius of the circular table is 5 cm.

What is the length of trim needed to decorate along the outside trim?

Circumference is the length of arc of the circle.It is also known as the perimeter of the  circle.

Circumference of the circle=2πr in which r is the radius of the circle.

It is given that the trim is placed and decorated along the outside edge, so the perimeter of the circle must equal to the length of trim needed.

Length of trim needed to decorate the circular table=2πr

=2*π*5

=10π

=10*3.14

=31.4 cm.

Hence the length of the trim needed to decorate along the table is 31.4 cm.

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Evaluate the interval (Calculus 2)

Answers

Answer:

[tex]2 \tan (6x)+2 \sec (6x)+\text{C}[/tex]

Step-by-step explanation:

Fundamental Theorem of Calculus

[tex]\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))[/tex]

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.

Given indefinite integral:

[tex]\displaystyle \int \dfrac{12}{1-\sin (6x)}\:\:\text{d}x[/tex]

[tex]\boxed{\begin{minipage}{5 cm}\underline{Terms multiplied by constants}\\\\$\displaystyle \int a\:\text{f}(x)\:\text{d}x=a \int \text{f}(x) \:\text{d}x$\end{minipage}}[/tex]

If the terms are multiplied by constants, take them outside the integral:

[tex]\implies 12\displaystyle \int \dfrac{1}{1-\sin (6x)}\:\:\text{d}x[/tex]

Multiply by the conjugate of 1 - sin(6x) :

[tex]\implies 12\displaystyle \int \dfrac{1}{1-\sin (6x)} \cdot \dfrac{1+\sin(6x)}{1+\sin(6x)}\:\:\text{d}x[/tex]

[tex]\implies 12\displaystyle \int \dfrac{1+\sin(6x)}{1-\sin^2(6x)} \:\:\text{d}x[/tex]

[tex]\textsf{Use the identity} \quad \sin^2 x+ \cos^2 x=1:[/tex]

[tex]\implies \sin^2 (6x) + \cos^2 (6x)=1[/tex]

[tex]\implies \cos^2 (6x)=1- \sin^2 (6x)[/tex]

[tex]\implies 12\displaystyle \int \dfrac{1+\sin(6x)}{\cos^2(6x)} \:\:\text{d}x[/tex]

Expand:

[tex]\implies 12\displaystyle \int \dfrac{1}{\cos^2(6x)}+\dfrac{\sin(6x)}{\cos^2(6x)} \:\:\text{d}x[/tex]

[tex]\textsf{Use the identities }\:\: \sec \theta=\dfrac{1}{\cos \theta} \textsf{ and } \tan\theta=\dfrac{\sin \theta}{\cos \theta}:[/tex]

[tex]\implies 12\displaystyle \int \sec^2(6x)+\dfrac{\tan(6x)}{\cos(6x)} \:\:\text{d}x[/tex]

[tex]\implies 12\displaystyle \int \sec^2(6x)+\tan(6x)\sec(6x) \:\:\text{d}x[/tex]

[tex]\boxed{\begin{minipage}{5 cm}\underline{Integrating $\sec^2 kx$}\\\\$\displaystyle \int \sec^2 kx\:\text{d}x=\dfrac{1}{k} \tan kx\:\:(+\text{C})$\end{minipage}}[/tex]

[tex]\boxed{\begin{minipage}{6 cm}\underline{Integrating $ \sec kx \tan kx$}\\\\$\displaystyle \int \sec kx \tan kx\:\text{d}x= \dfrac{1}{k}\sec kx\:\:(+\text{C})$\end{minipage}}[/tex]

[tex]\implies 12 \left[\dfrac{1}{6} \tan (6x)+\dfrac{1}{6} \sec (6x) \right]+\text{C}[/tex]

Simplify:

[tex]\implies \dfrac{12}{6} \tan (6x)+\dfrac{12}{6} \sec (6x)+\text{C}[/tex]

[tex]\implies 2 \tan (6x)+2 \sec (6x)+\text{C}[/tex]

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Substitute [tex]y=6x[/tex] and [tex]dy=6\,dx[/tex] to transform the integral to

[tex]\displaystyle \int \frac{12}{1-\sin(6x)} \, dx = 2 \int \frac{dy}{1 - \sin(y)}[/tex]

Now substitute [tex]t=\tan\left(\frac y2\right)[/tex] and [tex]dt=\frac12 \sec^2\left(\frac y2\right) \, dy[/tex] to transform this to

[tex]\displaystyle 2 \int \frac{dy}{1 - \sin(y)} = 2 \int \frac1{1-\frac{2t}{1+t^2}}\cdot\frac{2\,dt}{1+t^2} = 4 \int \frac{dt}{(t-1)^2}[/tex]

Finally, substitute [tex]s = t-1[/tex] and [tex]ds=dt[/tex] to get

[tex]\displaystyle 4 \int \frac{dt}{(t-1)^2} = 4 \int \frac{ds}{s^2} = -\dfrac4s + C[/tex]

Now recover the antiderivative in terms of [tex]x[/tex].

[tex]\displaystyle \int \frac{12}{1-\sin(6x)} \, dx = -\frac4s + C \\\\ ~~~~~~~~ = -\frac4{t-1} + C \\\\ ~~~~~~~~ = -\frac4{\tan\left(\frac y2\right) - 1} + C \\\\ ~~~~~~~~ = \boxed{-\frac4{\tan(3x) - 1} + C}[/tex]

In a survey of 300 college graduates, 46% reported that they entered a profession closely related to their college major. If 9 of those survey subjects are randomly selected without replacement for a follow-up survey, what is the probability that 3 of them entered a profession closely related to their college major

Answers

Probability is 17.5% that 3 of them entered a profession closely related to their college

According to the statement

we have given that survey of 300 college graduates, 46% reported that they entered a profession closely and

We know that  For each college graduate, there are only two possible outcomes. Either they have entered a profession closely related to their college major, or they have not. The probability of a college graduate having entered a profession closely related to their college major is independent of other college graduates, so we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

This is P(X = 3) when n = 8. and the value of p is 0.46 put the value in the binomial formula then the outcome of answer will 17.5%

So, Probability is 17.5% that 3 of them entered a profession closely related to their college

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Figure ABCD is transformed to figure A prime B prime C prime D prime, as shown: A coordinate grid is shown from negative 5 to 0 to 5 on both x -and y-axes. A polygon ABCD has A at ordered pair 1, 3, B at ordered pair 3, 4, C at ordered pair 2, 1, D at ordered pair 1, 1. A polygon A prime B prime C prime D prime has A prime at ordered pair negative 3, 3, B prime at ordered pair negative 5, 4, C prime at ordered pair negative 4, 1, D prime at ordered pair negative 3, 1. Which of the following sequences of transformations is used to obtain figure A prime B prime C prime D prime from figure ABCD?

Answers

Figure ABCD was translated 2 units to the right so as to obtain figure A'B'C'D'

What is transformation?

Transformation is the movement of a point from its initial location to a new location. Types of transformation are translation, reflection, rotation and dilation.

Figure ABCD was translated 2 units to the right so as to obtain figure A'B'C'D'

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Describe how the graph of the function g(x) = -5x²-2 is related to the graph of
the function f(x) = 5x².

(A) reflection of f(x) = 5x² across the x-axis and translated left 2 units

(B) translation of f(x) = 5x² down 2 units

(C) reflection of f(x) = 5x² across the x-axis and translated down 2 units

(D) reflection of f(x) = 5x² right 2 units

Answers

Answer:

(C) reflection of f(x) = 5x² across the x-axis and translated down 2 units

Solve the equation algebraically. Calculus section 1.5 of textbook
2^x + 2^-x = 5

Answers

The value of x from the given expression is [tex]\frac{5+\sqrt{29}}{2log2} \\[/tex]

Solving quadratic expression

Given the algebraic expression below;

2^x + 2^-x = 5

This can also be expressed as:

1/2^x+ 1/2^x = 5

Let P = 2^x, such that;

P + 1/P = 5

P²-1/P = 5

P²-1 = 5P

P²-5P-1=0

On factrorizing, then;

P = [tex]\frac{5+\sqrt{29}}{2} \\[/tex]

Since 2^x = P, then;

[tex]2^x=\frac{5+\sqrt{29}}{2} \\\\xlog2=\frac{5+\sqrt{29}}{2} \\\\x=\frac{5+\sqrt{29}}{2log2} \\[/tex]

Hence the value of x from the given expression is [tex]\frac{5+\sqrt{29}}{2log2} \\[/tex]

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fit the model, part a, to the data using simple linear regression. give the least squares prediction equation

Answers

Answer:

fitting a simple linear regression first select the cell in data set second on the analyse it ribbon tap in statistical analysis group click fit model and then click the simple degradation model 3rd the wild drop down list select the response variable 4th in the X drop down let's select the predicated

How did the temperature change if :
At first, it increased by 5% and then increased by 20%

So my question is,
What would the process be for solving this (Please answer it in a way a middle schooler can understand!)

Answers

Answer: Net Increase of 26%

===================================================

Explanation:

If it increases by 5%, then we use the multiplier 1.05

Think of it like saying 100% + 5% = 1 + 0.05 = 1.05

Similarly, an increase of 20% means we involve 1.20

Combine those multipliers to get: 1.05*1.20 = 1.26

This is a net increase of 26%

Interestingly, we get fairly close to 25% which is what many students might go for (since 5 + 20 = 25). This is a beginner's trap.

----------------

An example:

Let's say the temperature is 20 degrees Celsius (68 degrees Fahrenheit)

An increase of 5% means it moves to 1.05*20 = 21 degrees C

A 20% increase means we go to 1.20*21 = 25.2 degrees C

The shortcut would be to do a 26% increase to get 1.26*20 = 25.2 to help confirm we have the correct combined increase.

A car dealership needs a program to store information about the cars for sale. For each car, they want to keep track of the following information: number of doors (2 or 4), whether the car has air conditioning, and its average number of miles per gallon. Which of the following is the best design

Answers

The best object-oriented program design for this car dealership's software program is to use a single class Car, with three instance variables (fields):

numDoorshasAirmilesPerGallon.

What is a class?

A class can be defined as a user-defined blueprint (prototype) or template that is typically used by software programmers to create objects and define the data types, categories, and methods that should be associated with these objects.

In object-oriented programming (OOP) language, a class that is written or created to implement an interface in a software would most likely implement all of that interface's method declarations without any coding error.

In this scenario, the best object-oriented program design for this car dealership's software program is to use a single class Car, with three instance variables (fields):

int numDoorsboolean hasAirdouble milesPerGallon.

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Complete Question:

A car dealership needs a program to store information about the cars for sale. For each car, they want to keep track of the following information: number of doors (2 or 4), whether the car has air conditioning, and its average number of miles per gallon. Which of the following is the best design?

(A) Use four unrelated classes: Car, Doors, AirConditioning, and MilesPerGallon.

(B) Use a class Car with three subclasses: Doors, AirConditioning, and MilesPerGallon.

(C) Use a class Car, with fields: numDoors, hasAir, and milesPerGallon.

(D) Use a class Car, with subclasses of Doors, AirConditioning, and MilesPerGallon.

(E) Use classes: Doors, AirConditioning, and MilesPerGallon, each with a subclass Car.

Which graph represents the circle given by the equation x + y - 4x + 9y -7 = 0?

Answers

The graph of the circle equation is graph (d)

How to determine the circle?

The equation is given as:

x^2 + y^2 - 4x + 9y -7 = 0

Rewrite as:

x^2 - 4x + y^2 + 9y = 7

Express (x^2 - 4x) and (y^2 + 9y) as perfect squares.

So, we have:

(x - 2)^2 + (y + 3)^2 = 7 + 4 +  20.25

Evaluate the sum

(x - 2)^2 + (y + 3)^2 = 31.25

A circle equation is represented as:

(x - h)^2 + (y - k)^2 = r^2

Where

Center = (h, k)

Radius = r

So, we have:

(h, k) = (2, -3)

r^2 = 31.25

r = 5.5

The circle that has a center of (2, -3) and a radius of 5.5 is graph d

Hence, the graph of the circle equation is graph (d)

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A car can travel 161 miles on 7 gallons of gas. how much gas will it need to go 368 miles?

Answers

Answer:

16 gallons of gas

Step-by-step explanation:

Two ways to answer this

1:

Find how many miles per gallon the car can go. Then, divide the amount the car needs to go with the miles per gallon. This gets you the gallons of gas needed to go the amount. In this case, 161 ÷ 7 = 23. 368 ÷ 23 = 16.

2:

Make a proportion. [tex]\frac{161}{7} = \frac{368}{x}[/tex]. Solve for x. 161 and 7 cancel out to get 23. [tex]\frac{23}{1} = \frac{368}{x}[/tex]. Now you can either divide 368 and 23 and multiply the quotient by 1 to get x, or you can cross multiply to get an equation you can solve. In the first case, 368 ÷ 23=16. 1*16=16. x=16. In the second case, 23x=368. Divide both sides by 23 and you get x = 16.

The sum of 3 consecutive integers is 2190. what is the value of the smallest integer?

Answers

Answer:

3x+2=2190

3x=2190-2

3x=2188

x=2188÷3

x=729

An elf, a dwarf, a hobbit, a wizard, and a man are sitting in a line.How many different ways can they sit if the elf and the dwarf insist on sitting next to each other

Answers

Answer: 24

Step-by-step explanation:

1. Number Them

Elf and Dwarf = 1

Hobbit = 2

Wizard = 3

Man = 4

* Elf and Dwarf are put together so that they are always sitting together

2. Multiply

1 x 2 x 3 x 4 = 24

Write an expression that can be used to produce vector b from vector a, and explain how you determined that expression.

Answers

The explanation regarding the vector is illustrated below.

How to illustrate the information?

It should be noted that vector A with components a, b, c, can be written as (a, b, c) or in terms of unit vectors as ai + bj + ck.

In this case, the letters I, j, and k are the standard symbols for the unit vectors in the x, y, and z directions.

Therefore, if A = (3,4,5( you can write A = 3i + 4j + 5k.

If B = (1, 1, 1), you can write B = I + j + k.

Then A - B is the vector whose component are the difference in each components.

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20 PIONTSSS TO WHOEVER ANDWER THIS QUESTION !!!

Answers

Answer:

The answer would be 36cm².

Step-by-step explanation:

⇒ Two prisms are similar.

⇒ Scale factor = 3:8

⇒ The ratio of the surface area is 9:64.

⇒ So S₁ : S₂ = 9:64

⇒ S₁ : 256 = 9:64

⇒ S₁ = 36cm²

This would mean that the answer is 36 centimeters ² (squared).

The answer is 36cm2.

Emily convinced her mom to buy a giant box of her favorite cereal. Her mom doesn't think the box will fit on their shelf. The volume of the box is 10{,}00010,00010, comma, 000 cm^3
3
cubed. The base of the box is 252525 cm by 101010 cm.

Answers

The height of the rectangular cereal box is 40 cm.

How to find height of a rectangular prism?

Volume of a rectangular prism = lwh

where

l = lengthw = widthh = height

Therefore,

10000 = 25 × 10 × h

10000 = 250h

h = 10000 / 250

h = 40 cm

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