identify the terms of each expression 7 + 5 p + 4r + 6 s ​

Answer:

Step-by-step explanation:

Multiplying y by a value greater than 1 results in a vertical stretch. When the sign of it is negative there is a reflection over the x-axis. The appropriate choice is shown below.

__

The second attachment shows how the graph is flipped and stretched.

Answer:

sin C= 5/13

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

sin theta = opp / hyp

sin C= 5/13

Answer:

g(x)=-3x^{3}+2

Step-by-step explanation:

g(x) has a range that of (-infinity, +infinity), whereas f(x) has a range of (-infinity, -2].

Answer:

Step-by-step explanation:

● f(x) = -x^4 -2

● g(x) = -3x^3 + 2

Derivate both functions:

● f'(x) = -4x^3

● g'(x) = -9x^2

Solve the equations f'(x) =0 and g'(x) =0

● f'(x) = 0

● -4x^3 = 0

● x^3 = 0

● x =0

● g'(x) = 0

● -9x^2 = 0

● x^2 =0

● x = 0

So both functions f and g reach their maximum at 0.

● f(0) = 0^4-2 = -2

● g(0) = -3×0^3 +2 = 2

So g(0)>f(0)

So g has the largest maximum value.

Answer:

I believe it's D. histogram ; continuous

Step-by-step explanation:

Answer:

Step-by-step explanation:

it shows the maximum rise in temperature.

Answer:

b answer, will show the rise in temperature

Answer: 8

Step-by-step explanation:

Answer:

32

Step-by-step explanation:

This is because you would want the feet and the radium kinda meeting up in a way and would need to make sure you can fill it in with th e drive way as it will be on a horizontal base so you would need X2 of the driveway to make it into a standing up horizontal base

Hope this helps

If this seems incorrect please comment with the answer that it should be and I shall change my answer thanks you :)

The base angles of an isosceles trapezoid are equal; For EFGI to be a parallelogram, the measure of [tex]\angle HGI[/tex] is: 108 degrees

Given that:

[tex]\angle IEF = 36^o[/tex]

IEF and GHI are the base angles of the trapezoid.

So:

[tex]\angle GHI = \angle IEF = 36^o[/tex]

Also:

[tex]\triangle GHI[/tex] is an isosceles triangle.

This means that:

[tex]\angle GHI = \angle HIG = 36^o[/tex] --- base angles of an isosceles triangle

So:

[tex]\angle GHI + \angle HIG + \angle HGI = 180[/tex] --- sum of angles in a triangle

Substitute known values

[tex]36 + 36+ \angle HGI = 180[/tex]

[tex]72 + \angle HGI = 180[/tex]

Collect like terms

[tex]\angle HGI = 180-72[/tex]

[tex]\angle HGI = 108[/tex]

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Answer:

→To combine the two functions, you have to multiply them together, like so:

h(x) · s(x)

→This can also be shown as:

[tex](103)(1.03)^x^-^1[/tex]

The reason as to why you would multiply the two functions together, and not add, is because of the words accrues. Based on the information given, the interest amount of money, which is $103, accrues, which basically means that the money will increase in a pattern, over time. In addition, when a world problem involves a bank and money, multiplication is usually occurring.

The total amount of money Christina will have in her bank account as interest accrues after she deposits her $103 is g(x) = (103)(1.03)^(x-1).

Simple interest is the amount charged on the principal amount with a fixed rate of interest for a time period. Simple interest calculated only on the principal amount.

Christina has $103 earned from babysitting saved at home, and the amount is modeled by the function,

[tex]h(x) = 103[/tex]

She reads about a bank that has savings accounts that accrue interest according to the function,

[tex]s(x) = (1.03)^{(x-1)}[/tex]

This function means that the interest amount is 3% in value per year in which x represent the number of years.

Now the total amount of money she will have in her bank account as interest accrues will be equal to the product principal and interest rate.

Let the amount of money she will have in her bank account as interest accrues is represented by function g(x). Thus,

[tex]g(x) = (103)(1.03)^{(x-1)}[/tex]

Thus, the total amount of money Christina will have in her bank account as interest accrues after she deposits her $103 is.

[tex]g(x) = (103)(1.03)^{(x-1)}.[/tex]

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Answer:

I am not good at word problems but I think I found some good examples

Step-by-step explanation:

Durain beans cost $9 per pound and they sold 11 pounds.

Multiply the cost by the amount sold: 9 x 11 = $99

Subtract that from the total sold:

196 - 99 = $97

Now divide the amount left by the cost per pound for Ice cream beans:

97 / 10 = 9.7 pounds.

Answer:

5040

Step-by-step explanation:

All the possible Numbers that can be placed in the last for places =0,1,2,3,4,5,6,7,8,9

If all the digits  have be different , then

= 10 x 9 x 8 x 7

= 90 x 56

=  5040   are total no. of 4-digit numbers can be made using those 4 digits.

Answer:

The correct option is;

b) 0 sq, units

Step-by-step explanation:

The vertices of the triangle are;

(4, 0), (2, 3), (8, -6)

The distance formula fr finding the length of a segment is given as follows;

[tex]l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}[/tex]

Where, (x₁, y₁) and (x₂, y₂) are the coordinates of the end points of the line

For the points (4, 0) and (2, 3) , we have;

√((3 - 0)² + (2 -4)²) = √13

Distance from (4, 0) to (2, 3) = √13

For the points (4, 0) and (8, -6) , we have;

√((-6 - 0)² + (8 -4)²) = √13 =

Distance from (4, 0) to (8, -6) = 2·√13

For the points (2, 3) and (8, -6) , we have;

√((-6 - 3)² + (8 -2)²) = 3·√13 =

Distance from (2, 3) to (8, -6) = 3·√13

Therefore, the perimeter of the triangle = 6·√13

The semi perimeter s = 3·√13

The area of the triangle,  [tex]A = \sqrt{s\cdot \left (s-a \right )\cdot \left (s-b \right ) \cdot \left ( s-c \right )}[/tex]

Where;

a, b, and c are the length of the sides of the triangle;

[tex]A = \sqrt{3\cdot \sqrt{3} \cdot \left (3\cdot \sqrt{3} -\sqrt{3} \right )\cdot \left (3\cdot \sqrt{3} -2 \cdot \sqrt{3} \right ) \cdot \left ( 3\cdot \sqrt{3} -3\cdot \sqrt{3} \right )} = 0[/tex]

Therefore, the area = 0 sq, units.

Answer:

(D) 6

Step-by-step explanation:

We can substitute the values of a (7) and b (-4) into the equation to find it's result.

[tex]\frac{|2a| -b}{3} \\\\\\\frac{|2\cdot7|-(-4)}{3}\\\\\frac{|14|+4}{3}\\\\\frac{14+4}{3}\\\\\frac{18}{3}\\\\ 6[/tex]

So 6 is the value of this expression when a is 7 and b is -4.

Hope this helped!

Answer:

1) one and two-thirds hour

2) 2.4 miles

verifying, by putting [tex] \theta=60^{\circ}[/tex]

LHS≠RHS

hence the question is FALSE

It depends on how b approaches 0

If b is positive and gets closer to zero, then we say b is approaching 0 from the right, or from the positive side. Let's say a = 1. The equation a/b turns into 1/b. Looking at a table of values, 1/b will steadily increase without bound as positive b values get closer to 0.

On the other side, if b is negative and gets closer to zero, then 1/b will be negative and those negative values will decrease without bound. So 1/b approaches negative infinity if we approach 0 on the left (or negative) side.

The graph of y = 1/x shows this. See the diagram below. Note the vertical asymptote at x = 0. The portion to the right of it has the curve go upward to positive infinity as x approaches 0. The curve to the left goes down to negative infinity as x approaches 0.

Answer:

The value of the 2 is two-thousand

Step-by-step explanation:

Answer:

thousands

Step-by-step explanation:

thousands, hundreds tens ones

2                    4              7      3

Answer:

Alice will have to pay $13.33

Ben will have to pay $23.33

Kelvin will have to pay $43.33

Step-by-step explanation:

Given that

Alice destination is 20 miles away

Ben destination is 30 miles away

Calvin destination is 40 miles away.

For a mile, taxi costs 2 dollars.

To find:

How much each person has to pay if they share the same taxi to their respective destinations?

Solution:

For the first 20 miles, the taxi will be shared by all 3 of them.

Charges for 20 miles = 20 [tex]\times[/tex] 2 = $40

This $40 will be shared among all 3.

Each will pay = [tex]\frac{40}{3} = \$13.33[/tex]

Charges for Alice = $13.33

Charges for Ben = $13.33

Charges for Calvin = $13.33

For the next 10 miles, the taxi will be shared by Ben and Calvin.

Charges for 10 miles = 10 [tex]\times[/tex] 2 = $20

This $20 will be shared between Ben and Calvin.

Each will pay = [tex]\frac{20}{2} = \$10[/tex]

Charges for Alice = $13.33

Charges for Ben = $13.33 + 10 = $23.33

Charges for Calvin = $13.33 + 10 = $23.33

For the next 10 miles, Calvin travels alone.

Charges for 10 miles = 10 [tex]\times[/tex] 2 = $20

This $20 will be paid by Calvin alone.

Charges for Alice = $13.33

Charges for Ben = $23.33

Charges for Calvin = $23.33 + 20 = $43.33

Answer:

7/40 is the fraction filled with water

Step-by-step explanation:

Here we start by calculating the volume of the cylindrical tank.

Mathematically, that would be;

V = π * r^2 * h

From the question

r = 80 cm = 80/100 = 0.8 meters

h = 1.4 meters

π = 22/7

Plugging these values into the volume equation, we have;

V = 22/7 * 0.8 * 0.8 * 1.4 = 2.816 m^3

But mathematically;

1 m^3 = 1000 liters

So 2.816 m^3 = 2.816 * 1000 = 2816 liters

So the fraction filled with water will be;

492.8/2816 = 0.175 = 175/1000 = 7/40

Answer:it’s the top right box

Step-by-step explanation: what I did was I added 24+24 and 19+19 which gives you 86ft

Answer:It is left side 21ft and top 22ft Step-by-step explanation:

Answer:

Below

Step-by-step explanation:

5)

The sequence includes the terms 3,6,9,12,15.. and so on

Notice that each time we add 3.

The first term is 3.

We can see it in a different way

● 3 = 3×1

● 6 = 3×2

● 9 = 3×3

● 12 = 3×4

Let 1 be n. Notice what happens

● 3 = 3n

● 6 = 3 × (n+1)

● 9 = 3 × (n+2)

● 12 = 3 × (n+3)

So we can express it as.

● a1 = 3 × 1 =3

● a2 = 3×2 =6

● a3 = 3×3 = 9

So the third term is a3 wich is 9

● a6 = 3×6 = 18

So the sixth term is 18 .

■■■■■■■■■■■■■■■■■■■■■■■■■■

6)

the sequence is defined by:

● f(n-1) = -0.5 f(n)

Repalce n-1 with n and n with n+1

● f(n) = -0.5 f(n+1)

So to get a term you must multiply the next one by -0.5

The first term in the sequence is 120.

● 120 = -0.5 f(n+1)

● f(n+1) = 120/-0.5

● f(n+1) = -60

So the second term is -60

Answer:

Below

Step-by-step explanation:

Part A: -1 and 2.5

Part B: The vertex is a minimum

Part C: tbh, I'm not quite sure about this part but just use parts A and B to answer :)

(you can also use the website desmos. com/calculator as a graphing calculator)

1. The first step here is to arrange the data set's form least to greatest,

Sherelle:  26, 39, 56, 58, 60, 62, 65, 66, 66, 68, 71, 72, 72, 73, 74, 75, 81, 83, 84, 85

Venita:  44, 45, 51, 51, 53, 53, 55, 57, 58, 62, 65, 66, 69, 69, 70, 73, 75, 77, 78, 79

Now we can determine our 5 - number summary based on the numbers respective positions.

First Data Set,

(Five - Number Summary) - Minimum : 26, Quartile 1 : 60, Median : 69.5, Quartile 3 : 75, Maximum : 85

Second Data Set,

(Five - Number Summary) - Minimum : 44, Quartile 1 : 53, Median : 63.5, Quartile 3 : 73, Maximum : 79

2. This part is based on your drawings of the box and whisker plots, so you would have to figure that part out by yourself.

3. First off we know that our data set is composed of the years from 1900, so let's rewrite the set based off of the actual year -

Sherelle:  1926, 1939, 1956, 1958, 1960, 1962, 1965, 1966, 1966, 1968, 1971, 1972, 1972, 1973, 1974, 1975, 1981, 1983, 1984, 1985

Venita:  1944, 1945, 1951, 1951, 1953, 1953, 1955, 1957, 1958, 1962, 1965, 1966, 1969, 1969, 1970, 1973, 1975, 1977, 1978, 1979

( a ) Now in Sherelle's defence, she can say that the lowest coin date in her group is 1926, comparative to Venita's group - the lowest coin date in hers being 1944. Therefore, she is more likely to have the 1916 coin, after all that date is the lowest overall in both their data set.

( b ) In Venita defence, she can say that the mean of her data set is lower than the mean of Sherelle's data set. Take a look at the calculations below,

Sherella's Mean : [tex]\frac{39336}{20}[/tex] = [tex]\frac{9834}{5}[/tex] = 1966.8,

Venita's Mean : [tex]\frac{39250}{20}[/tex] = [tex]\frac{3925}{2}[/tex] = 1962.5

( c ) I would say Sherella's bag would most likely contain the 1916 coin. The mean is a prominent factor, but their mean(s) only differ by a very small quantity. That too, Sherella's bag contains the lowest coin in both their groups, and though that is not a prominent factor, it could be that she does have the 1916 coin.

Answer:

x=2

y=-3

Step-by-step explanation:

2x+y = 1

3x+2y = 0

Multiply the first equation by -2

-4x-2y = -2

Add this to the second equation

-4x-2y = -2

3x+2y = 0

-------------------

-x = -2

Multiply by -1

x = 2

Now find y

2x+y = 1

2(2) +y = 1

4 +y = 1

Subtract 4 from each side

y = 1-4

y = -3

Answer: y = -2x + 1

Solution to the system: (2,-3)

Step-by-step explanation:

2x + y = 1

3x + 2y = 0

We can solve this using substitution

The first thing that we're going to want to do is solve for y in the first equation

Solve for y

2x + y = 1

Subtract 2x from both sides

y = 1 - 2x

We now have the two equations

y = -2x + 1 and 3x + 2y = 0

The next step in solving the system is to plug in the expression of y ( -2x + 1) into the second equation

3x + 2y = 0

Substitute -2x + 1 for y

3x + 2(-2x + 1) = 0

Now solve for x

Distribute the 2 to the -2x and 1

2 * -2x = -4x

2 * 1 = 2

We now have 3x - 4x + 2 = 0

Combine like terms

-x + 2 = 0

Add x to both sides

2 = x

Now to find the value of y we substitute the value of x into one of the equations and solve for y

2x + y = 1

x = 2

2(2) + y = 1

Multiply

4 + y = 1

Subtract 4 from both sides

y = -3

The solution to the system is (2,-3)

And we are done!

Answer:

area ≈ 12.505

perimeter ≈  16.1684

Step-by-step explanation:

We are given

- the radius of the circle (and therefore area of the circle)

- the area of the triangle

We want to find

- angle AOB/AOT. We want to find this because 360/the angle gives us how many OABs fit into the circle. For example, if AOT was 30 degrees, 360/30 = 12 (there are 360 degrees in a circle, so that's where 360 comes from). The area of the circle is equal to πr² = π6² = 36π, and because AOT is 30 degrees, there are 12 equal parts of sector OAB in the circle, so 36π/12=3π would be the area of the sector. A similar conclusion can be reached from the circumference instead of the area to find the distance between A and B along the circle, and OA + AB + BO = the perimeter of the minor sector.

First, we can say that OAT is a right triangle because a tangent line is perpendicular to the line from the center to the point on the circle, so AT is perpendicular to OA. This forms two right angles, one of which is OAT

One thing that we can start to solve is AT. We know that the area of a triangle is equal to base * height /2, and the height of this triangle is AO, with the base being AT. Therefore, we can say

15 = AO * AT / 2

15 = 6 * AT / 2

15 = 3 * AT

divide both sides by 3 to isolate AT

AT = 5

Because OAT is a right triangle, we can say that the hypotenuse ² =  the sum of the squares of the two other lengths. The hypotenuse is opposite of the largest angle (in this case, the right angle, as in a right triangle, the right angle is always the largest), so it is OT in this case. The other two sides are OA and AT, so we can say that

OA² + AT² = OT²

5²+6² = OT²

25+36=61=OT²

square root both sides

OT = √61

Next, the Law of Sines states that

sinA/a = sinB/b = sinC/c with angles A, B, and C with sides a, b, and c. Corresponding sides are opposite their corresponding angles, so in this case, AT corresponds to angle AOT, OT corresponds to angle OAT, and AO corresponds to angle ATO.

We want to find angle AOT, as stated earlier, so we have

sin(OAT)/OT = sin(ATO)/OA = sin(AOT)/AT

We know the side lengths as well as OAT/sin(OAT) and want to figure out AOT/sin(AOT), so one equation that helps us get there is

sin(OAT)/OT = sin(AOT)/AT, encompassing our 3 known values and isolating the one unknown. We thus have

sin(90)/√61 = sin(AOT) /5

plug in sin(90) = 1

1/√61 = sin(AOT)/5

multiply both sides by 5 to isolate sin(AOT)

5/√61 = sin(AOT)

we can thus say that

arcsin(5/√61) = AOT ≈39.80557

As stated previously, given ∠AOT, we can find the area and perimeter of the sector. There are 360/39.80557 ≈ 9.04396 equal parts of sector OAB in the circle. The area of the circle is πr² = 36π, so 36π / 9.04396 ≈ 12.505 as the area. The circumference is equal to π * diameter = π * 2 * radius = 12 * π, and there are 9.04396 equal parts of arc AB in the circumference, so the length of arc is 12π / 9.04396 ≈ 4.1684. Add that to OA and OB (both are equal to the radius of 6, as any point from the center to a point on the circle is equal to the radius) to get 6+6 + 4.1684 = 16.1684 as the perimeter of the sector

Answer:

4 and 5

Step-by-step explanation:

cube root of 66 is 4.041240021

Each edge of the cube is 20cm. If it stayed on the edges it would need to walk on 3 edges for a total distance of 3 x 20 = 60 cm.

If it walked diagonally across the front face and then one edge it would travel:

Diagonal = sqrt(20^2 + 20^2) = 28.28

Total distance waling a diagonal and then an edge = 28.28 + 20 = 48.28 cm

The shortest distance would be diagonally across the front face then the edge to point B and the distance would be 48.28 cm.

(u × v) • w makes sense, since u × v is another vector, and so (u × v) • w is a scalar.

u × (v • w) does not make sense, since v • w is a scalar, and the cross product is not defined between a vector and a scalar.

(u × v) × w makes sense, since u × v is a vector and so is w.

u • (v • w) does not make sense, since v • w is scalar, and the dot product is not defined between a vector and a scalar.

Answer:

The points for this will be:

A: (1, -4)

B: (-4, -2)

C: (-5, 4)

D: (-2, 1)

Step-by-step explanation:

If we reflect a shape over the x-axis, all of it’s points y values will be negated.

So, (1, 4) becomes (1, -4)

(-4, 2) becomes (-4, -2)

(-5, -4) becomes (-5, 4)

and (-2, -1) becomes (-2, 1)

Hope this helped!

New coordinates of the quadrilateral are A' is (1, -4), B' is (-4, -2), C' is (-5, 4) and D' is (-2, 1)

Graph is a mathematical representation of a network and it describes the relationship between lines and points.

The coordinates of quadrilateral ABCD are A is (1, 4), B is (-4, 2), C is (-5, -4) and D is (-2, -1)

After reflecting across the x-axis , the x-coordinates of the vertices will remain the same, but the signs of their y-coordinates will change.

Therefore, the new coordinates of the vertices will be:

A' is (1, -4)

B' is (-4, -2)

C' is (-5, 4)

D' is (-2, 1)

Hence,  new coordinates of the quadrilateral are A' is (1, -4), B' is (-4, -2), C' is (-5, 4) and D' is (-2, 1)

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