If a girl is sitting on box and the girl weighs 10kg and the box weighs 50 kg, how much force will be
needed to accelerate the box 5 m/s2? If the same force is used, what will the acceleration be if the girl hops off the box?

4.80m is the far of the recipients must goods dropped.

The speed of an object is the rate at which it moves through space. A slow-moving object travels a relatively short distance in a given amount of time, whereas a fast-moving object travels a long distance in a short amount of time.

A)Since we are aware that the plane's vertical speed is zero

In this instance, the mass is dropped with no beginning speed.

thus, we will

y=1/2gt²

235=1/2(9.81)t²

t=6.92s

Consequently, it is given as the horizontal distance it moved.

d=vt

d=(69.4)(6.92)

d=480.4m

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The electric field should be applied is 3,694.5 .

As we know from electromagnetic theory we have a relation with electric field and magnetic field with force, which is

F = qE + qv x B

or we can write that

F = qE + qvBsinФ

To allow proton to move with the constant speed, we need to apply zero external force

It means F = 0

or we can write that

qE = -qvBsinФ

putting the appropriate values, we get

E = 4105 x 0.9

E = 3,694.5

Hence the magnitude of the electric field is 3,694.5 .

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Answer: D

Explanation:

If the net acceleration is downward but has a magnitude less than G, the force of F has a larger magnitude than the tension in the rope.

We do know thаt the net force equаls mаss times the аccelerаtion. Now if we tаke the block аs а system, meаning we mаke use of the equаtion, mаss times аccelerаtion equаls net force, on the block. Now the lаst element of the rope is pulling the block upwаrds. This is becаuse the block pulls the rope down, hence due to newton's third lаw the rope too should pull the block, but in opposite directions, thаt is upwаrds. Hence the tension аcts upwаrds on the block. Therefore the net force is weight downwаrds аnd tension upwаrds, this equаls mаss times аccelerаtion,

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In the period 6 inner transition element series, the 4f orbitals begin to be filled after the element Lanthanum(La) and Cerium(Ce).

The d and f Block elements in the groups of 3 to 11 are also called transition elements and inner transition elements respectively. 4f and 5f orbitals of f-block elements are steadily in the latter of two long periods.

Inner transition element:

Inner transition elements are those elements in which the last electron enters the f-orbital. The elements in which the 4f and the 5f orbitals are progressively filled are called f-block elements. These includes lanthanoids( Z = 58 - 71) and actinoids (Z = 90 - 103).

Therefore period 6 inner transition elements begin with Lanthanum and Cerium.

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The weight of the large block of stone is 300 Newton. The result is obtained by dividing the gravitational potential energy by the height.

Gravitational potential energy is the energy stored in an object due to its position in a gravitational field. GPE can be expressed as

PE = mgh

Where

Given

How much does it weight?

The weight of an object is the mass times the acceleration of gravity.

W = mg

So, with the GPE equation, the weight is

PE = mgh

PE = W × h

4500 = W × 15

W = 4500 ÷ 15

W = 300 Newton

Hence, the weight of the large block of stone is 300 Newton.

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Astronomers can study how clusters of stars and gas move around the galactic center in nearby galaxies and use those movements to calculate the mass of the central black hole.

By monitoring the star motions in the galaxy's center, Webb will calculate the black hole's mass. Astronomers will calculate the mass of that black hole using NASA's James Webb Space Telescope. The outcome may appear to be unimportant, but a black hole's mass controls how it feeds and interacts with its surroundings.

Black holes are discovered when nearby material, such as gas, is pulled by gravity into a disk around the black hole. The gas molecules in the disk of the black hole are spinning so quickly that they heat up and release X-rays. From Earth, one can observe these X-rays.

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The ratio of I sub A to I sub B is 4.

How can you calculate the ratio of A to B?

A/B would be your formula if you were comparing one data point (A) to another data point (B). This indicates that you are multiplying information A by information B. For instance, your ratio will be 5/10 if A is 5 and B is 10. How do we determine each wheel's moments of inertia (around the axis of symmetry) I is equal to 1 over 2 times m times R squared is used to compute the moments of inertia for both masses and radii. We simply use a common factor to cancel. So 4:2=2:1 . The simplest representation of the ratio 4 to 2 is the ratio 2 to 1. Additionally, since each pair of numbers has the same relationship, the ratios are equivalent.

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The bomb must be released 3375 m before the target when dropped from the height of 2500.0 m

An equation of motion is an equation that describes the behavior of a physical system in terms of motion as a function of time. More specifically, the equations of motion describe the behavior of a physical system as a set of mathematical functions related to dynamic variables.

Following are the equations of motion:

v = u + at

s = ut + 1/2 at²

v² = u² + 2as

Before calculating the horizontal distance let's calculate the time taken by the bomb to reach the ground by using following equation:

s = ut + 1/2 gt²

u = initial velocity in the vertical direction (0)

s = vertical displacement from the ground (−2500.0 m)

g =  acceleration due to gravity (-9.8 m/s²)

Now substitute the the value in the above reaction:

-2500 = 0 × t +  1/2 × -9.8 t²

-2500 = -4.9 t²

t = 22.5 s

Now the distance covered by the bomb in horizontal direction by the time it reaches the ground is:

D = v × t

Where, D = distance covered by bomb horizontally

v = velocity of bomber (150 m/s )

t = time taken to reach the ground (22.5 s)

D = 150 × 22.5

D = 3375 m

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When a car travels at 5m/s and brakes at the rate of 2 m/s², the length of time to travel 6 m is 2 or 3 seconds.

Use the equation of motion for deceleration:

s = u . t - 1/2. a t²

Where:

s = distance

u = initial velocity

t = travel time

a = acceleration (minus sign means deceleration)

Parameters given in the problem:

s = 6 m

u = 5 m/s

a = 2 m/s²

Plug these parameters into the formula:

6 = 5t - 1/2. 2 . t²

t² - 5t + 6 = 0

(t - 3) (t - 2) = 0

t = 3  or  t = 2

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The given images are labelled as either element, compound, mixture of elements or mixture of compounds accordingly.

The answers are marked according in order of the images as follows:

If there are only single type of atoms present without being in contact with another atom, it is called as elements. If one atom is in contact with another atoms it is a compound. If there are more than one type of element, it is a mixture of elements. If there are more than one type of compound, it is a mixture of compounds.

Therefore, the given images are labelled as either element, compound, mixture of elements or mixture of compounds accordingly.

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The phase angle between the voltages of the capacitor and inductor in rlc circuit is 180°.

The phase angle is the component of a periodic wave. It is the shift between the AC current and the voltage on the measured impedance. The two elements of phase angle are reactance(X) and resistance (R).

The phrase for phase angle is, Xₐ = sinωt

where Xₐ= phase angle

ω = wavelength of the wave in 1 revolution

t = time period of 1 revolution

The instantaneous voltage ΔvR is in phase with the current, ΔvL leads the current by 90°, while ΔvC lags behind the current by 90°. The instantaneous values of these three voltages do add algebraically to give the instantaneous voltages across the RLC combination.

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Light passes straight through two vertical polarizers. The axes of the filters are aligned parallel to each other. The way the light that passes through the second filter compared to the light that passed through the first filter is that all of the light will pass through both polarizers.

A polarizer, also known as a polariser, is an optical filter that allows light waves of one polarization to pass while blocking light waves of other polarizations. It may convert an undefined or mixed polarization light beam into a polarized light beam by filtering it.

Calcite, a naturally occurring mineral, is used to make the majority of birefringent polarizers. Calcite is common in polycrystalline form, but optical-grade calcite is scarce, making birefringent polarizers more expensive than most other varieties.

Remember that polarising filters can lower the amount of light reaching your camera's sensor by up to two or three f-stops, so avoid using them in low-light settings.  This includes photography during blue hour, at night, and when capturing the Aurora Borealis.

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The consumption to operate the heater for 15 days is $2.25

Electricity consumption refers to all of the electricity used to perform a movement, manufacture something, or definitely inhabit a construction. here are some examples: In a manufacturing unit, overall electricity consumption can be measured with aid of looking at how lots power a manufacturing technique consumes, for instance, via making car elements.

The full-strength intake consists of that of coal, crude oil and their products, natural gasoline, and electricity, but, it excludes the intake of gas of low calorific fee, bio-strength, and solar energy.

Calculation:-

Voltage (V) = 200 V

Current (I) = 25 A

Power (P) = VI = 200 * 25 = 5,000 W

Now, the calculation of the energy consumption for 15 days in KW/h

We will convert W to kW,

1000 W = 1kW

Therefore,

5,000 W = 5000 W × 1 KW / 1000 W = 5kW

The daily energy consumption will be calculated. This is attainable as follows,

P = 5kW

Time(t) = 10 h

Energy (E) = P/t = 5/10 = 0.5 kW/h per day.

Finally, we will calculate the energy usage for the next 30 days. This is attainable as follows:

1 day = 0.5 kW

Cost of one day = 0.5 * 0.30 = $ 0.15

Now, the cost to operate the heater for 15 days = $ 15 * 0.15 = $2.25

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The quarterback is located 0.3v above ground. The fundamental element of every projectile's body that is moving is its horizontal velocity (vx).

The fundamental element of every projectile's body that is moving is its horizontal velocity (vx). In any projectile motion, it is typically utilized to know the velocity value at which the particle travels along the horizontal direction. It's even thought of as the body's starting point for movement.

Let's say the projectile-moving particle reaches the highest point of its horizontal path. In that case, the horizontal velocity will typically be zero since the force of gravity will cause it to fall vertically downward as soon as it reaches the peak point. Vertical velocity has no impact on this horizontal velocity when it is at its highest point.

Let the horizontal velocity of the object = v

X = vt

X = 0.3v

Thus, The quarterback is located 0.3v above ground.

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Transverse waves  are waves that move the medium at right angles to the direction in which the waves travel.

Waves are defined to be oscillations or vibrations about a fixed point, accompanied by the transfer of energy travelling from one medium to another. There are mainly two types of mechanical waves, namely longitudinal waves and transverse waves.

Longitudinal waves are waves in which the movement of the particles in the medium is in the same dimension as the wave’s movement direction. Examples of longitudinal waves include compression wave and sound waves. Transverse waves are waves in which the medium moves at an angle to the wave’s direction. Examples include stringed instruments and light waves.

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The frictional force where k is the unitary force of kinetic friction acting on an object and k is the coefficient of kinetic friction. For the vast majority of surfaces, K is less than S.

The weight of the object and the roughness of the surface in contact determine how much frictional force is generated. The friction force will grow as the roughness increases.

The weight of the object bearing normal to the surface times the coefficient of friction for the contacting surfaces gives the amount of the friction force. The force's direction is perpendicular to the surface and is in opposition to any forces acting on the box.

The amount of kinetic friction is inversely proportional to the amount of normal force and the degree of roughness between the sliding surfaces. The amount of static friction is inversely proportional to the amount of normal force and the degree of roughness between the sliding surfaces.

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A stater glides off a frozen pond onto a patch of ground at a speed of 3.1 m/S. Here she is stowed at a constant rate of 3.00 m/s .  The skater will move at a speed of v = 1.01 m/s , when she has slid 0.42 m across the ground

The branch of physics that defines motion with respect to space and time, ignoring the cause of that motion, is known as kinematics. Kinematics equations are a set of equations that can derive an unknown aspect of a body’s motion if the other aspects are provided.

using kinematics equation

[tex]v^{2} - u^{2} = 2as[/tex]

[tex]v^{2} = u^{2}[/tex] + 2as

   = [tex](3.1)^{2}[/tex] - 2 * 3 * 0.42

v    = 1.01 m/s

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40.47 m/s is the speed of the arrow leaving the bow. When 0.0850 kg arrow fired horizontally, and If bowstring exerts average force of 89.0 N on the arrow over distance of 0. 782 m.

The primary indicator of object's position and speed is its velocity. It is distance that object travels in one unit of time. Displacement of item in one unit of time is definition of velocity.

By Newton's second law of motion,

F = ma

m is the mass of the arrow (kg) = 0.0850 kg

a is the acceleration of the arrow (m/s²)

F is the force applied (N) = 89.0 N

F= ma

a = F/m

a = 89.0/ 0.0850

∴ a= 1,047.059 m/s²

Now, object have acceleration, and the object will move in non-uniform motion. so the formula applied is:

[tex]v_{t}[/tex] = [tex]v_{0}[/tex] + at

[tex]v_{t}^{2}[/tex] = [tex]v_{0}^{2}[/tex] + 2×a×d

∴ d = [tex]v_{0}[/tex]×t +1/2× a ×t²

here,

[tex]v_{0}[/tex] = initial speed (m/s) = 0 m/s (arrow stationary in bowstring)

[tex]v_{t}[/tex] = final speed (m/s)

a = acceleration (m/s²) = 1,047.059 m/s²

t = interval (s)

d = distance (m) = 0.782 m

[tex]v_{t}^{2}[/tex] = [tex]v_{0}^{2}[/tex] + 2×a×d

[tex]v_{t}^{2}[/tex] = 0² + 2 × 1,047.059 × 0.782

 [tex]v_{t}^{2}[/tex] = 1637.6

[tex]v_{t}[/tex] = [tex]\sqrt{1637.6}[/tex]

[tex]v_{t}[/tex] = 40.47 m/s

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3.74 m/s is  the speed of the cart of mass 2.0 kg and the string gives a centripetal force of 40. N.

The force that creates centripetal acceleration is known as centripetal force. All objects in uniform circular motion accelerate toward the center of the circle, and as a result, they must likewise experience a force from the center. The centripetal force is that force.

Briefing :

Given ,The mass of the cart, m = 2 kg,

The standard equation would be F = ma , where a is acceleration, f is force, and m is mass. However, the breaking strength of the string is 40 N.

a   =    [tex]\frac{v^{2} }{r}[/tex]

F   =   ma

F   =   [tex]\frac{mv^{2} }{r}[/tex]

40 =   [tex]\frac{2v^{2} }{0.70}[/tex]

[tex]v^{2}[/tex]  =   14

v   =  [tex]\sqrt{14}[/tex]

v  =  3.74 m/s

Therefore , the speed of the cart is 3.74 m/s .

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The acceleration is if the force is halved and the item's mass is doubled is 2.5 m/s².

Force is a push or pulls upon an item due to the item's interaction with a few different item. strain is a energy that could change the motion of an item. A force can purpose an object with mass to exchange its velocity, i.e., to boost up. stress also may be defined intuitively as a push or a pull. A force has each significance and route, making it a vector amount.

In the first case,

Let the mass of the object is = m

acceleration = 10 m/s²

The constant force F = ma

                             F = 10m   ---------(1)

New case 2,

force F' = F/2

mass M' = 2m

a = F'/M'

  = F/2 × 2m

a = F/4m

F = 4ma ----------(2)

dividing equations 1 and 2

   ⇒  [tex]\frac{F = 4ma}{F = 10m}[/tex]

a = 10/4

a = 2.5 m/s²

The phrase 'force' has a unique which means. At this degree, it's far truely appropriate to describe a pressure as a push or a pull. A force isn't always something that an item consists of or 'has in it. A pressure is exerted on one object thru another. The idea of a force is not confined to living matters or non-dwelling matters.

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The distance x must be 7.92 m for the crane to be balanced according to principle of conservation of energy.

The distance x can be determined by applying the principle of conservation of energy as shown below.

According to this principle of conservation of energy;

the input work (energy) = output work (energy)

F₁d₁ = F₀d₀

where;

(4400) x (9) = 5000x

39600 = 5000x

x = 39600/5000

x = 7.92 m

Thus, the crate a balanced condition, the output work must be equal to the input work.

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Roller balder will have 28,665 J gravitational potential energy at the top of a hill that is 45.0 meters high

gravitation potential energy = m*g*h

mass = 65 kg

g = 9.8 [tex]m/s^{2}[/tex]

h = 45 m

gravitation potential energy  = 65 * 9.8 * 45 = 28,665 J

Roller balder will have 28,665 J gravitational potential energy at the top of a hill that is 45.0 meters high

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If these resistors are connected in parallel across the terminals of the same battery, the power delivered by the battery is 80 W

Write the expression for the total power delivered by the battery in

parallel,Pp = 2P1

Here, Po is the total power delivered by the battery in parallel.

Pp = 2 [(ΔV)²/R]

= 4 [(ΔV)²/2R]

= 4Ps

Pp =4(20)

   P =80 W

Electrical resistance is implemented as a circuit element by resistors, which are passive two-terminal electrical components. Resistors are devices that are used in electronic circuits for a variety of purposes, including lowering current flow, adjusting signal levels, dividing voltages, biasing active components, and terminating transmission lines. Electrical resistance is provided by a resistor, a two-terminal electrical component. Resistors are mainly used to split voltages, block transmission signals, reduce current flow, and bias active components in electronic circuits.

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The net force on the car during its deceleration =  9139.2 N

Deceleration is actually inversely related to acceleration. We know that acceleration is the rate at which an object is speeding up, and deceleration is the rate at which an object is slowing down. For example, when you brake while driving, deceleration is used to slow the vehicle.

Given, m= 1020 kg

u= 0 m/s

V = 94 km/h or 26.1 m/s

t = 10 s

For deceleration

u = 26.1 m/s

v = 0

S = 38 m

by equation of motion ;

v² = u² + 2as

0 = 26.1² + 38a

a = - 8.96 m/s²

Net force during deceleration:

F= m*a

F= 1020 × 8.96

F = 9139.2 N

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The velocity of sound in helium gas is 968 m/s if the spacing between resonances is 110cm.

We have to go from antinode to antinode. In an air column, the spacing between resonance is wavelength /2 as we have to go from antinode to antinode.

wavelength = 220 cm = 2.2m

As we know the velocity formula

Then Velocity = f * λ

Where f is the frequency and λ is the wavelength.

So Velocity of wave = 440 * 2.2 = 968m/s

Hence, the velocity of sound in helium gas is 968 m/s if the spacing between resonances is 110cm.

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For a solar mass star, the red-giant phase normally lasts just around a billion years overall, with practically all of that time being spent on the red-giant branch.

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According to the first law of thermodynamics, work done by a system will cause decrease in the internal energy, assuming that no heat is transferred to or from the system.

First law of thermodynamics says that energy can neither be created nor it can be destroyed, it can only be transferred from one form to another form. This is also a law of conservation of energy.

It means if there is any work done by any system then that system has burned its energy to do the work. so when energy is used to do the work , there will be decrease in the internal energy of the system, and that will be equal to the workdone.

ΔU = ΔW

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The static friction force of the pavement on the wheels will not do any work on the skateboard.

Static friction is a variable resisting force that is equal and opposite to the external force until it exceeds the motion threshold when sliding begins.

If the skateboard is rolling at a constant speed without any other forces acting on it, then there is no tendency to slip between the wheel and the surface, so there is no frictional work. Friction will only try to prevent slipping between the 2 surfaces.

On an inclined plane, the wheels will tend to slide down, and if there were no friction, it would again slide between the wheels and the inclined surface. Perhaps friction will always try to counteract the slip, so here it acts upward on the slope to try to prevent the skateboard from sliding down the slope. This has the effect of applying a moment to the skateboard causing it to roll.

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Calculate the striking trampoline.

What is zero velocity?

The zero-velocity surface is a notion connected to the N-body gravity problem. It represents a surface that a body with the specified energy cannot traverse because it would have zero velocity there. George William Hill made the initial proclamation about it.

What is resistance?

A circuit's opposition to current flow is measured by its resistance. The Greek letter omega () stands for ohms, which are used to measure resistance. Georg Simon Ohm (1784–1854), a German physicist who examined the connection between voltage, current, and resistance, is the subject of the name "Ohm."

mass of each friends= 50kg

number of friends =10

total mass= 50×10=500kg

now initial velocity before, falling =0

let final velocity be V

v²-μ²= 2as

⇒v²+2as=2as(μ=0)

∴V=[tex]\sqrt{2as}[/tex]=[tex]\sqrt{2*9.8*2}[/tex]  ( acceleration due to gravity =9.8m/s²) ( s=2m given)

=6.26ms⁻¹

∴The velocity of the friends, just before striking the trampoline= 6.26ms⁻¹

Now after striking the trampoline, the velocity of the people decelerate to 0, in a time interval 0.5s.

∴deceleration= 6.26/ 0.5= 12.52ms⁻²

∴Force required to decelerate=mass× deacceleration

=500×12.52

=6260.99

=6261N

but that trampoline has a threshold of 500N, which is less than force required to stop, the people.

hence the friends succeed in striking the trampoline.

Therefore, the friends succeed in striking the trampoline.

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