If a planet was located approximately 24 thousand light-years from the center of a galaxy and orbits that center once every 194 million years, how fast is the planet traveling around the galaxy in km/hr? If needed, use 3.0 × 108 m/s for the speed of light.

Answer:

The distance of the cat will appear farther than it really is

Explanation:

The index of refraction of water is more than that of air. Light rays from the cat  are refracted towards the normal at the surface and diverge outwards. This extends the virtual position of the cat, putting in a place farther than it really is.

Answer:

This is due to variation bin air pressure at the two different altitudes, so air rushes out through the eustachian tube to hit the eardrum and back when u reach the ground

Explanation:

Heat is a form of energy that can transfer from hot body to cold body.Temperature is the degree of hotness and coldness of a body.

Heat is measured in joules, but temp. is measured in Kelvin

Answer:

temperature is the degree of hotness and coldness of the body or an object while heat is the energy transferred from hot to a cooler object as a result if differencein temperature ☺

Answer:

81,725 N/m^2

Explanation:

Given the following :

Height of water = 2m

Density of water = 1000kg/m^3

Atmospheric pressure (Pat) = 101325 N/m^2

Lowest pressure (Pl) can be obtained thus ;

Pat - Pl = density × height × acceleration due to gravity

101325 - Pl = 1000 × 2 × 9.8

101325 - Pl = 19600

101325 - 19600 = Pl

Lowest pressure (Pl) = 81,725 N/m^2

81,725 N/m^2 = (81,725/101325) atm

= 0.8065630 = 0.8065 atm

Answer:

b. 0.493

Explanation:

Answer

density of mercury is 13.6 g/ml and that 1 lb = 0.45 kg.

Answer:

v = rw

Explanation:

When an object is rolling continuously without slipping, then every angle it rotates through, is equal to a distance the perimeter has rotated.

If the object completes 10 revolutions and takes a particular time, let's say t to complete it. The angular distance would then be 20 π rad, while its angular velocity will be 20 π/t

The circumference will somehow translate to the distance it covers, which is 20πr, this means that the speed is 20πr/t

So, like the question asked, the linear speed compared to angular speed is

v : w

20πr/t : 20πt, which can be simplified to

r : 1

In essence, v = rw

Answer:

The mmf required is [tex]1.125[/tex]×[tex]10^{-3}[/tex] A

Explanation:

The Magnetomotive force (mmf) is given by the formula below

[tex]F_{M} = Hl\\[/tex]

where [tex]F_{M}[/tex] is the Magnetomotive force (mmf)

[tex]H[/tex] is the Magnetic field strength

[tex]l[/tex] is the magnetic length

The magnetic permeability μ is given by

μ = [tex]B / H[/tex]

Where [tex]B[/tex] is the Magnetic flux density

and [tex]H[/tex] is the Magnetic field strength

From the question,

[tex]B[/tex] = 1.2Wb/m^2

μ = 1600m

From μ = [tex]B / H[/tex]

∴[tex]H = B/[/tex]μ

[tex]H = 1.2 / 1600\\[/tex]

[tex]H = 7.5[/tex] × [tex]10^{-4}[/tex]A/m

Now, for the Magnetomotive force (mmf)

[tex]F_{M} = Hl\\[/tex]

From the question

[tex]l[/tex] = 1.5 m

∴ [tex]F_{M} = 7.5[/tex]×[tex]10^{-4}[/tex] × [tex]1.5[/tex]

[tex]F_{M} = 1.125[/tex]×[tex]10^{-3} A[/tex]

Hence, The mmf required is [tex]1.125[/tex]×[tex]10^{-3}[/tex] A

Answer:

The object will remain where it was placed on the fluid

Explanation:

If an object is immersed in a fluid, with both the object and the fluid having the same density, the force of buoyancy (the force acting upward) will be equal to the gravitational force (the weight pulling the object down) making the object remain in the position it was placed in the fluid. Meaning it will neither sink down or float through the surface.

For practical purpose, it should however be noted that the chances of this happening is very low.

NOTE: When an object is less dense than the liquid/fluid, it will float and when it is more dense than the liquid, it will sink

Answer:

The smallest possibility is 0.01E-22kgm/s

Explanation:

Using

Momentum= h/4πx

= 6.6x 10^-34Js/ 4(3.142* 50*10-12m)

= 0.01*10^-22kgm/s

Explanation:

It is given that,

The object distance from the lens is 10 cm, u = -10 cm

Image is formed at a distance of 40 cm away from the lens, u = 40 cm

The lens formula is : [tex]\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}[/tex], v is image distance

[tex]\dfrac{1}{40}-\dfrac{1}{-10}=\dfrac{1}{f}\\\\f=8\ cm[/tex]

The focal length is 8 cm

Magnification,

[tex]m=\dfrac{v}{u}\\\\m=\dfrac{40}{-10}\\\\m=-4[/tex]

The magnification is negative, it means that the formed image is inverted.

Answer:

The final velocity of the object after 2 seconds is 30 m/s

Explanation:

Given;

constant downward acceleration, a =  10 m/s²

initial velocity of the object falling down, v = 10 m/s

time of fall, t = 2 s

The final velocity of the object is given by;

v = u + at

where;

v is the final velocity

v = 10 + (10)(2)

v = 10 + 20

v = 30 m/s

Therefore, the final velocity of the object after 2 seconds is 30 m/s

Answer:

There are [tex]3.372 \times 10^{22}[/tex] molecules in a cubic centimeter of water at ordinary pressure and temperature.

Explanation:

Let suppose that liquid is water at a pressure of a atmosphere and a temperature of 25 ºC. Due to incompresibility of liquids, water density does not have any change of importance due to changes in pressure and temperature.

Density and molar mass of water are 1 gram per cubic centimeter and 18.015 grams per mole. The mass of water in a cubic centimeter ([tex]m[/tex]), measured in grams, is:

[tex]m = \rho\cdot V[/tex]

Where:

[tex]\rho[/tex] - Density, measured in grams per cubic meter.

[tex]V[/tex] - Volume of the sample, measured in cubic meters.

Given that [tex]\rho = 1\,\frac{g}{cm^{3}}[/tex] and [tex]V = 1\,cm^{3}[/tex], the mass of water is:

[tex]m = \left(1\,\frac{g}{cm^{3}} \right)\cdot (1\,cm^{2})[/tex]

[tex]m = 1\,g[/tex]

The amount of moles ([tex]n[/tex]) inside the sample is:

[tex]n = \frac{m}{M}[/tex]

Where:

[tex]m[/tex] - Mass of the sample, measured in grams.

[tex]M[/tex] - Molar mass, measured in grams per mole.

If [tex]m = 1\,g[/tex] and [tex]M = 18.015\,\frac{g}{mole}[/tex], then:

[tex]n = \frac{1\,g}{18.015\,\frac{g}{mole} }[/tex]

[tex]n = 0.056\,mole[/tex]

According to the Avogadro's Principle, there are [tex]6.022\times 10^{23}[/tex] molecules per mole. Hence, the number of molecules in a cubic centimeter of water at ordinary pressure and temperature is determined by simple rule of three:

[tex]x = (0.056\,mole)\times\left(6.022\times 10^{23}\,\frac{molecules}{mole} \right)[/tex]

[tex]x = 3.372\times 10^{22}\,molecules[/tex]

There are [tex]3.372 \times 10^{22}[/tex] molecules in a cubic centimeter of water at ordinary pressure and temperature.

Answer:

The slower runner is 1.71 km from the finish line when the fastest runner finishes the race.

Explanation:

Given;

the speed of the slower runner, u₁ = 11.8 km/hr

the speed of the fastest runner, u₂ = 15 km/hr

distance, d = 8 km

The time when the fastest runner finishes the race is given by;

[tex]Time = \frac{Distance }{speed}\\\\Time = \frac{8}{15} \\\\Time = 0.533 \ hr[/tex]

The distance covered by the slower runner at this time is given by;

d₁ = u₁ x 0.533 hr

d₁ = 11.8 km/hr x 0.533 hr

d₁ = 6.29 km

Additional distance (x) the slower runner need to finish is given by;

6.29 km + x = 8km

x = 8 k m - 6.29 km

x = 1.71 km

Therefore, the slower runner is 1.71 km from the finish line when the fastest runner finishes the race.

Answer:

1.8*10^8m/s

Explanation:

Using

L= lo√1-v²/c²

So making v subject we have

V= c√1-4.8²/6²

V= 0.6*c

V= 0.6*3E8m/s

V= 1.8*10^8m/s

Complete Question

Calculate the average volume per molecule for an ideal gas at room temperature and atmospheric pressure. Then take the cube root to get an estimate of the average distance between molecules. How does this distance compare to the size of a molecule like [tex]N_2[/tex]?

Answer:

The  average volume per molecule is  

   [tex]\frac{V}{N} = 4.09 *10^{-26} \ m^3/molecule[/tex]

 The average distance between molecules

  [tex]d = 3.45 *10^{-9} \ m[/tex]

The size of  [tex]N_2[/tex] is 100 times smaller than the obtained value  

Explanation:

From the question we can deduce that we are considering an ideal

Generally the ideal gas equation is mathematically represented as

       [tex]PV = NkT[/tex]

Here  T  is the room temperature with value  T  =  300  \ K  

     k is the Boltzmann constant with value  [tex]k = 1.38 *10^{-23} \ J/K[/tex]  

      P  is the atmospheric pressure with value  [tex]P = 1.0 *10^{5} \ N/m^2[/tex]

     N is the number of molecules

Now  the  volume per molecule is mathematically deduced from the above equation as

        [tex]\frac{V}{N} = \frac{kT}{P}[/tex]

=>      [tex]\frac{V}{N} = \frac{ 1.381 *10^{-23} * 300}{ 1.0*10^{5}}[/tex]

=>      [tex]\frac{V}{N} = 4.09 *10^{-26} \ m^3/molecule[/tex]

Now the distance is mathematically evaluated as

      [tex]d = \sqrt{\frac{V}{N} }[/tex]

=>    [tex]d = \sqrt[3]{4.09*10^{-26}}[/tex]

=>     [tex]d = 3.45 *10^{-9} \ m[/tex]

Generally the size of  [tex]N_2[/tex]  is  115 pm which is  100 times smaller  than the  obtained value  

  Generally the size of  [tex]H_2O[/tex] is  [tex]95.84 \ pm[/tex] which is  10 times smaller than the obtained value  

Based on the ideal gas equation, the calculated values are as follows:

The average volume per molecule is calculated using the given formula derived from the ideal gas equation:

where:

At room temperature and atmospheric pressure;

T = 300 k

P = 1.0 × 10^5 N/m^2

Substituting the values in the equation above to calculate the average volume per molecule, V/n:

V/n = 1.38 × 10^-23 × 300/1.0 × 10^5 N/m^2

V/n = 4.09 × 10^-23 m^3/molecule

Thus, the average volume per molecule is 4.09 × 10^-23 m^3/molecule

The average distance between molecules can be determined by using the formula:

[tex]d = \sqrt[3]{ \frac{v}{n} } [/tex]

Substituting the values for V/n

[tex]d = \sqrt[3]{4.09 \times {10}^{ - 23} } [/tex]

d = 3.45 × 10^-9 m or 3.45 nm

Therefore, the average distance between molecules is 3.45 nm

A molecule of N2 has an average size of 115 pm or 0.115 nm.

Comparing the two values:

3.45/0.115 = 30

Therefore, the N2 molecule is about 30 times smaller than the average distance between molecules.

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Answer:

A) J= 398 A/m²

B) E= 1.6×10⁶ N/C

C) P= ×10⁴ W

Explanation:

My work is in the attachment. Comment with questions or if something seems wrong with my work. (Honestly, they seem little high but it could just be the given numbers being unrealistic.) Below I have explanations of each part to match up with the image as well.

Part A:

Current density (J) is defined as the amount of current in a particular cross-sectional area. To get this, we simply need to divide the current (I) by the cross-sectional area of the electron beam tube (A).

Part B:

This one took the most work for me. I used a kinematic equation (yes they apply to electrons) to find the electric field (E). I used a modified form of the familiar: ∆d=V₀τ+aτ²/2

We can use the fact that τ= V/a, a=(qE/m), and V₀=0 here to rewrite the equation in terms of values we know and/or can look up. From there we solve for E and plug in the values.

Part C:

Power (P) is simply work (W) over time (τ). We know what τ is from before and can take W= mV²/2. Plugging these in and reducing some values gives us an equation for power as well.

Answer:

v = 100 m/s

Explanation:

Given:

v₀ = 0 m/s

a = 10 m/s²

t = 10 s

Find: v

v = at + v₀

v = (10 m/s²) (10 s) + 0 m/s

v = 100 m/s

Answer:

The  value is  [tex]\theta_2 = 20.322^o[/tex]

Explanation:

From the question we are told that

  The angle of the first order maximum is  [tex]\theta _1 = 10.0^o[/tex]

Generally the condition for constructive interference is  

     [tex]dsin\theta = n \lambda[/tex]

Here  d is the separation between the slit ,

n  is the order of maxima  with values n  =  1, 2 , 3 ... for first , second , third ... order of maxima

    Now for first order of maximum

        [tex]dsin\theta_1 = \lambda \ \ ... \ \ ( 1)[/tex]

=>      [tex]dsin(10) = \lambda \ \ ... \ \ ( 1)[/tex]

    Now for second order of maximum

       [tex]dsin\theta = 2\lambda \ \ ... \ \ ( 2)[/tex]

dividing equation 1  by 2

      [tex]\frac{d sin (10)}{d sin (\theta_2 )} = \frac{\lambda}{2\lambda}[/tex]

     [tex]\frac{ sin (10)}{ sin (\theta_2 )} = \frac{1}{2}[/tex]

=>   [tex]2sin(10) = sin (\theta_2 )[/tex]

=>    [tex]0.3473 = sin(\theta_2)[/tex]

=>   [tex]\theta_2 = sin^{-1} [0.3473][/tex]

=>   [tex]\theta_2 = 20.322^o[/tex]

Answer:

"the magnitude of the magnetic field at a point of distance a around a wire, carrying a constant current I, is inversely proportional to the distance a of the wire from that point"

Explanation:

The magnitude of the magnetic field from a long straight wire (A approximately a finite length of wire at least for close points around the wire.) decreases with distance from the wire. It does not follow the inverse square rule as is the electric field from a point charge. We can then say that "the magnitude of the magnetic field at a point of distance a around a wire, carrying a constant current I, is inversely proportional to the distance a of the wire from that point"

From the Biot-Savart rule,

B = μI/2πR

where B is the magnitude of the magnetic field

I is the current through the wire

μ is the permeability of free space or vacuum

R is the distance between the point and the wire, in this case is = a

Complete question:

a farmer wants to use a wireless camera he has installed in his barn which is about 100 yards from his house. what kind of antenna should he use on the house and barn to get the best signal.

Answer: Unidirectional antenna

Explanation: Based on the description given in the scenario above, the farmer should use a unidirectional antenna in other to get the best signal taking advantage of the fact that he knows where he wants the Transmission to come from. The good transmission signal attributed to unidirectional antennas stems from the fact that, the area covered is relatively small as signal transmission and radiofrequecy energy is focused in a particular direction, meaning that less area is covered using a unidirectional antenna,hiwevwr, it leverages this limitation to provide very good signal within the limited area covered.

Answer: I believe farther. Correct me if I am wrong

Explanation:

Answer:

Closer.

Explanation:

Due to the refraction of light passing through water and air.

Complete Question

A circular area with a radius of 6.60 cm lies in the xy-plane. What is the magnitude of the magnetic flux through this circle due to a uniform magnetic field B = 0.250 T oriented in the following ways?

(a) in the +z-direction

Wb

(b) at an angle of 54

Answer:

a

[tex]\phi = 0.00342 \ Wb[/tex]

b

[tex]\phi = 0.00201 \ Wb[/tex]

Explanation:

From the question we are told that

   The  radius is  [tex]r = 6.60 \ cm = 0.066 \ m[/tex]

    The magnitude of the magnetic field is [tex]B = 0.250 \ T[/tex]

Generally the cross -sectional area is mathematically represented as

     [tex]A = \pi r^2[/tex]

     [tex]A = 3.142 * (0.066)^2[/tex]

     [tex]A = 0.01369 \ m^2[/tex]

Generally  when the magnetic field is oriented in the +z-direction the magnetic flux is mathematically represented as

      [tex]\phi = B* A cos(0)[/tex]

=>    [tex]\phi = 0.01369 * 0.250 * cos (0)[/tex]

=>     [tex]\phi = 0.00342 \ Wb[/tex]

  Now when the magnetic field is oriented  at an angle of 54°  the magnetic flux is mathematically represented as

      [tex]\phi = B* A cos(54)[/tex]

      [tex]\phi = 0.01369 * 0.250 * cos (54)[/tex]

     [tex]\phi = 0.00201 \ Wb[/tex]

Answer:

35.11 m/s

Explanation:

While flying due east at 33 meters/second, an airplane is also being carried due north at 12 meters/second by the wind, then the plane’s resultant velocity would be 35.11 meters/second.

The total displacement covered by any object per unit of time is known as velocity.

the mathematical expression for velocity is given by

velocity = total displacement /total time

As given in the problem , while flying due east at 33 m/s, an airplane is also being carried due north at 12 m/s by the wind and we have to find the resultant velocity of the plane,

Resultant velocity = √( 33² + 12²)

                              = 35.11 meters/second

Thus, the plane’s resultant velocity would be 35.11 meters/second

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Answer:

D. 10 seconds

Explanation:

All Houston Methodist Hospital buildings employs the use of EPSS(Emergency Power Supply System). This system employs the use of an emergency power generator that turns on to supply emergency power after normal power shuts down within 10 seconds during power outage.

Due to it being used in a hospital the importance of this emergency power system cannot be overemphasized as it is used to provide power supply to hospital equipment such as life support machines etc.

Answer:

52°

Explanation:

The initial intensity [tex]I_{0}[/tex] = [tex]I[/tex]

The final intensity [tex]I_{f}[/tex] = 38% of [tex]I[/tex] = 0.38

From the polarizing equation

[tex]I_{f} = I_{0} cos^{2}[/tex]θ

substituting values, we have

[tex]0.38I = I cos^{2}[/tex]θ

0.38 = [tex]cos^2[/tex]θ

cosθ = [tex]\sqrt{0.38}[/tex]

cosθ = 0.6164

θ = [tex]cos^{-1}[/tex] 0.6164

θ = 51.9 ≅ 52°

Answer:

The time taken in years is   [tex]x = 125 \  years[/tex]

Explanation:

From the question we are told that

   The  speed is  [tex]v  = 540.00 \ km /hr  =  \frac{540 *1000}{3600} =  150\  m/s[/tex]

    The distance from the sun to Pluto is  [tex]d =  5.9*10^{9} \  k m =  5.9*10^9 * 1000 =  5.9*10^{12} \  m[/tex]

Generally the time  taken is mathematically represented as

     [tex]t =  \frac{d}{v}[/tex]

=>   [tex]t = \frac{5.9*10^{11}}{150}[/tex]

=>   [tex]t =  3.933*10^{9}[/tex]

Converting to years

   [tex]1 year  \to  3.154*10^7 \  s[/tex]

    [tex]x \  years  \to 3.933*10^{9}[/tex]

=>  [tex]x = \frac{ 3.933*10^{9} * 1 }{ 3.154 *10^7}[/tex]

=>    [tex]x = 125 \  years[/tex]

Answer: 80

Explanation: 7.2 hours x 60mph = 432 m

7.2 hrs - 1.8 hrs= 5.4 hrs

432m/5.4hrs = 80

Answer: 80 mph

Explanation:

Just is

Answer:

v = 6.20 10⁻¹² m / s,   v =  1.96 10⁻²  cm/year

Explanation:

This is a kinematics problem, specifically of uniform motion

        v = d / t

let's reduce the magnitudes to the SI system

      d = 8.8 km (1000 m / 1 km) = 8.8 10³ m

      t = 45 10⁶ years (365 day / 1 year) (24 h / 1 day) (3600 s / 1h)

       t = 1,419 10¹⁵ s

let's calculate the speed

        v = 8.8 10³ / 1.1419 10¹⁵

         v = 6.20 10⁻¹² m / s

This is the correct unit of the SI system, but it is more common to give the value in centimeters per year, so let's reduce the value

       v = 8.8 105 / 45 106

       v =  1.96 10⁻²  cm/year

Answer:

The wavelength in nanometers is 849.81 nanometers (nm)

Explanation:

Here is the complete question:

A laser technician measures the wavelength of light from a new semiconductor laser. The wavelength is 8.4981 × 10⁻⁷m . What is the wavelength in nanometers. Write your answer as a decimal.

Explanation:

The given wavelength is 8.4981 × 10⁻⁷m.

To determine the wavelength in nanometers, we will convert the given wavelength from meters (m) to nanometers (nm).

1 nanometer = 1 × 10⁻⁹ meters

∴ 10⁻⁹ meters = 1 nanometer

To convert 8.4981 × 10⁻⁷m to nanometer (nm):

If 10⁻⁹ meters (m) = 1 nanometer (nm)

Then,  8.4981 × 10⁻⁷m = (8.4981 × 10⁻⁷m × 1 nm) / 10⁻⁹ m

8.4981 × 10⁻⁷m = 8.4981 × 10⁻⁷ × 10⁹ nm

= 8.4981 × 10² nm

= 849.81 nm

Hence, the wavelength in nanometers is 849.81 nm