If ABCD is dilated by a factor of 3 the coordinates of A would be

Answer:

This list of all the outcome of  [tex]E^c[/tex] is  [tex]E^c = \{ 1,2,9,10,11,12,\}[/tex]

 [tex]P(E^c ) = 0.5[/tex]

Step-by-step explanation:

From the question we are told that

      The sample sample space is  [tex]S = \{ 1,2,3,4,5,6,7,8,9,10,11,12 \}[/tex]

       The number of elements in the sample space is [tex]n = 12[/tex]

        The event is  [tex]E = \{ 3,4,5,6,7,8 \}[/tex]

        The  number of outcomes in the Event is  [tex]n_e = 6[/tex]

The objective in to obtain [tex]P(E^c)[/tex]

 Now  [tex]E^c[/tex]  is the compliment of  E  and number of elements in [tex]E^c[/tex] ican be mathematically evaluated as

            [tex]nE^c = n - n_e[/tex]

substituting values

            [tex]E^c = 12-6[/tex]

             [tex]E^c = 6[/tex]

This list of all the outcomes of [tex]E^c[/tex] is

        [tex]E^c = \{ 1,2,9,10,11,12,\}[/tex]

Generally  [tex]P(E^c )[/tex]  which is the probability of  [tex]E^c[/tex] is mathematically evaluated  as

      [tex]P(E^c ) = \frac{nE^c}{n}[/tex]

substituting values

         [tex]P(E^c ) = \frac{6}{12}[/tex]

         [tex]P(E^c ) = 0.5[/tex]

Answer:

The equation i.e. used to denote the population after x years is:

P(x) = 490(1 + 0.200 to the power of x

Step-by-step explanation:

This problem could be modeled with the help of a exponential function.

The exponential function is given by:

P(x) = ab to the power of x

where a is the initial value.

and b=1+r where r is the rate of increase or decrease.

Here the initial population of the animals are given by: 490

i.e. a=490

Also, the rate of increase is: 20%

i.e. r=20%

i.e. r=0.20

Hence, the population function i.e. the population of the animals after x years is:

P(x) = 490(1 + 0.200 to the power of x

So for this, we will be using exponential form, which is y = ab^x (a = initial value, b = growth/decay).

Since we start off with 210 animals, that is our a variable.

Next, since this is *decreasing* by 14%, you are to subtract 0.14 (14% in decimal form) from 1 to get 0.86. That will be your b variable.

Putting everything together, your equation is y = 210(0.86)^x

Answer:

bzbdvdbdyrhevgdhs sdd

Step-by-step explanation:

ushebdvrudvd very

zhrjdvfjvrhfbrjrbr

hhrbdbdbfbfhfhthr

rhdjdbbffbdbbdve

Answer:

300.05 miles

Step-by-step explanation:

initial fee= $39.99

final bill = $ 100

cost =$ 0.20 per mile

remaining amount = $ 60.01

solution,

she drive = remaining amount / cost

=60.01/0.20

=300.05 miles

Answer:

500 miles

Step-by-step explanation:

Let us use cross multiplication to find the unknown amount.

Given:

1) Cost for 1 mile=$0.20

2)Cost for x miles=$100

Solution:

No of miles                             Cost

1) 1                                             $0.20

2)x                                             $100

By cross multiplying,

100 x 1= 0.20x

x=100/0.20

x=500 miles

Thank you!

Answer:

0

Step-by-step explanation:

0 because there is a $100 duty free exemption.

answer:

For this problem, use the tables and charts shown in this section.  

A United States Citizen returning to the States declares the following items at the customs office:

3 shirts at $8.50 each

2 dresses at $27.50 each

1 pair of gold cuff links at $17.50 per pair

If he has not used his duty free exemption yet, how much duty should he pay?

$0.00 !

$5.00

$10.00

$300

Answer:

8)  1.962 miles

9)  (-2, -1.5)

10) 0.515 miles

Step-by-step explanation:

√(-9 - 5)² + (1 - -4)² = 14.866

14.866 x .132 = 1.962

(-9+5)/2, (1 + -4)/2

-4/2, -3/2

-2, -3/2

√(-2 - 1)² + (-3/2 - -4)² = 3.905

3.905 x .132 = 0.515 miles

Step-by-step explanation:

Consuelo Butler

08/07

Homework: Practice

Exam 3

Question 1, 12.1.13

HW Score: 10%, 3 of 30 points

Score: 1 of 1

A professor had students keep track of their social interactions for a week. The

number of social interactions over the week is shown in the following grouped

frequency distribution. How many students had at least 60 social interactions for

the week?

12

Number of Social

Interactions

30-34

35-39

40-44

45-49

50-54

55-59

60-64

65-69

70-74

75-79

Frequency

9

14

11

15

16

8

7

By calculating the greater than cumulative frequency using the given frequency table, 12 students had at least 60 social interactions for the week.

The greater than cumulative frequency is also known as the more than type cumulative frequency. Here, the greater than cumulative frequency distribution is obtained by determining the cumulative total frequencies starting from the highest class to the lowest class.

Class interval     Frequency     Cumulative frequency

30-34                9                   85

35-39                14                   76

40-44                11                   62

45-49                15                   51

50-54                16                   36

55-59                 8                   20

60-64                 7                   12

65-69                 3                    5

70-74                  1                    2

75-79                  1                     1

[We read the cumulative frequencies with respect to the corresponding lower class limits. For example, 85 students had 'more than 30' social interactions, 76 students had 'more than 35 social interactions and so on.]

By reading the greater than cumulative frequency, we find that 12 students had at least 60 social interactions for the week.

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volume of a cone

.

.

.

volume of sphere

.

.

number of spheres that can be made......

.

.

hence a hemisphere can be formed

Answer:

Step-by-step explanation:

Total balls in bag = 4+2

= 6 balls

Total white balls = 4

Total black balls = 2

The possible outcomes are

Black and Black or White and White or White and Black or Black and White.

Probability of black and black = 2/6

= 1/3

Probability of white and white = 4/6

= 2/3

Probability of Black and white or White and black

= 1/3×2/3

= 2/9

please click thanks and mark brainliest if you like :)

possible outcomes will be white and black, white and white, black and white or black and black

Answer:

(i) 0.32          (ii) 0.85

(iii) 0.3412    (iv) 0.20

(v) 0.29         (vi) 0.12

Step-by-step explanation:

The data provided is as follows:

   Race                    Smoker (S)         Nonsmoker (N)             Row Total

 White(W)                    290                       560                           850

  Black(B)                     30                        120                           150

Column Total                320                       680                        1,000

(i)

Compute the value of P (S) as follows:

[tex]P(S)=\frac{n(S)}{N}=\frac{320}{1000}=0.32[/tex]

P (S) = 0.32.

(ii)

Compute the value of P (W) as follows:

[tex]P(W)=\frac{n(W)}{T}=\frac{850}{1000}=0.85[/tex]

P (W) = 0.85.

(iii)

Compute the value of P (S|W) as follows:

[tex]P(S|W)=\frac{n(S\cap W)}{n(W)}=\frac{290}{850}=0.3412[/tex]

P (S|W) = 0.3412.

(iv)

Compute the value of P (S|B) as follows:

[tex]P(S|B)=\frac{n(S\cap B)}{n(B)}=\frac{30}{150}=0.20[/tex]

P (S|W) = 0.20.

(v)

Compute the value of P (S∩W) as follows:

[tex]P(S\cap W)=\frac{n(S\cap W)}{T}=\frac{290}{1000}=0.29[/tex]

P (S∩W) = 0.29.

(vi)

Compute the value of P (N∩B) as follows:

[tex]P(N\cap B)=\frac{n(N\cap B)}{T}=\frac{120}{1000}=0.12[/tex]

P (S∩W) = 0.12.

Answer:

78 units2

Step-by-step explanation:

The Area of the triangle is 54 units2

The rectangle on the side has an area of 24 units2.

Add them together, and you get 78.

I hope this helps!

pls ❤ and give brainliest pls

The required coordinates of point B are (-3, 7) where point M is the midpoint of AB.

A midpoint is defined as in the middle of the line connecting two points a position known as a midpoint. A location in the middle of a line connecting the two points that are equally far from both points is the midpoint.

Point A is located at (1, 5), and point M is located at (-1, 6). If point M is the midpoint of AB

We can use these coordinates to find the coordinates of point B, which is the midpoint of line segment AB.

Let the coordinates of B would be (x, y)

Substituting the coordinates of points A into the midpoint formula gives us :

-1 = (x+1)/2 ; 6 = (y+5)/2

-2 = x +1 ; 12 = y + 5

x =  -3; y = 7

Therefore, the required coordinates of point B are (-3, 7).

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9514 1404 393

Answer:

  20,971,520

Step-by-step explanation:

The population is doubling every hour, so after 17 hours it will be the initial population (160) multiplied by 2^17 = 131,072.

After 17 hours, he can expect to find 160×131072 = 20,971,520 bacteria.

Answer:

A. 340 grams

Step-by-step explanation:

My brain

Answer:

2/3

Step-by-step explanation:

24/36

Divide the top and the bottom by 12

24/12 =2

36/12 = 3

2/3

Answer:

The Perimeter is 24 inches

Step-by-step explanation:

Perimeter is all the sides of something added up. All sides on a square are equal so each side is 6 inches

6+6+6+6=24

Answer:

[tex]\boxed{\frac{984}{1000}}[/tex]

Step-by-step explanation:

Hey there!

Well .984 is 984 over 1000 so .984 as a fraction is 984/1000.

We can check this by doing 984 / 1000 which is .984.

Hope this helps :)

Answer:

Hello,

Answer 26.9

Step-by-step explanation:

[tex]z=\dfrac{x-m}{\sigma} \\m=20.8\\\sigma=5.2\\\\p(z>?)\geq 0.12\ \longrightarrow 1-p(z\leq ?)=(1-0.12))\\\\Using\ table\ of\ normal\ reduce\ with\ 4 \decimals : ?=1.175\\\\x=1.175*5.2+20.8=26.91\approx{26.9}[/tex]

Answer:

The answer is below

Step-by-step explanation:

The question is not complete, let me solve a question that is exactly like this one.

A certain car model has a mean gas mileage of 34 miles per gallon (mpg) with a standard deviation 5 mpg. A pizza delivery company buys 43 of these cars. What is the probability that the average mileage of the fleet is greater than 33.5 mpg?

Answer:

Given that the mean (μ) is 34 miles per gallon (mpg) with a standard deviation (σ) 5 mpg. The sample (n) is 43.

The z score is used in statistics to determine by how much the raw score is above or below the mean. It is given by:

[tex]z=\frac{x-\mu}{\sigma} \\for\ a \ sample\ size:\\z=\frac{x-\mu}{\sigma/\sqrt{n} }[/tex]

For the average mileage of the fleet is greater than 33.5 mpg (x > 33.5):

[tex]z=\frac{x-\mu}{\sigma/\sqrt{n} }\\z=\frac{33.5-34}{5/\sqrt{43} } =-0.66[/tex]

From the normal distribution table, The probability that the average mileage of the fleet is greater than 33.5 mpg = P(x > 33.5) = P(z > -0.66) = 1 - P(z < -0.66) = 1 - 0.2546 = 0.7454 = 74.54%

Answer:

4i.

Step-by-step explanation:

To find the flux through the square, we use the divergence theorem for the flux. So Flux of F(x,y) = ∫∫divF(x,y).dA

F(x,y) = hxy,x - yi

div(F(x,y)) = dF(x,y)/dx + dF(x,y)dy = dhxy/dx + d(x - yi)/dy = hy - i

So, ∫∫divF(x,y).dA = ∫∫(hy - i).dA

= ∫∫(hy - i).dxdy

= ∫∫hydxdy - ∫∫idxdy

Since we are integrating along the boundary of the square given by −1 ≤ x ≤ 1, −1 ≤ y ≤ 1, then

∫∫divF(x,y).dA = ∫₋₁¹∫₋₁¹hydxdy - ∫₋₁¹∫₋₁¹idxdy

= h∫₋₁¹{y²/2}¹₋₁dx - i∫₋₁¹[y]₋₁¹dx

= h∫₋₁¹{1²/2 - (-1)/2²}dx - i∫₋₁¹[1 - (-1)]dx

= h∫₋₁¹{1/2 - 1)/2}dx - i∫₋₁¹[1 + 1)]dx

= 0 - i∫₋₁¹2dx

= - 2i[x]₋₁¹

= 2i[1 - (-1)]

= 2i[1 + 1]

= 2i(2)

= 4i  

Answer:

32449.3

Step-by-step explanation:

use the formula A = P(1+r / 100)^t

20000 × (1+ (8.4 / 100))^6

=32449.3

Answer:

4.

Step-by-step explanation:

Change of base formula is

logb x = loga x / loga b

So logx 25 = log5 25 /log5 x

Now log5 25 = log5 5^2 = 2, so:

logx 25 = 2 / log5 x

So log5 x^2 * logx 25

= log5 x^2 * 2 /log5 x

= 2 log5 x * 2 / log5 x

= 4.

Answer:

AE = 7.5

Step-by-step explanation:

Since <BAC = [tex]90^{0}[/tex], then;

<BAD = <DAE = <CAE = [tex]30^{0}[/tex] (complementary angles)

From ΔABC, applying the Pythagoras theorem to determine the length of side AC;

[tex]/BC/^{2}[/tex] = [tex]/AC/^{2}[/tex] + [tex]/AB/^{2}[/tex]

[tex]/10/^{2}[/tex] = [tex]/AC/^{2}[/tex] + [tex]/5/^{2}[/tex]

100 = [tex]/AC/^{2}[/tex] + 25

[tex]/AC/^{2}[/tex] = 100 - 25

[tex]/AC/^{2}[/tex] = 75

AC = [tex]\sqrt{75}[/tex]

Applying trigonometric function to ΔCAE,

Cos [tex]30^{0}[/tex] = [tex]\frac{AE}{\sqrt{75} }[/tex]

AE = [tex]\sqrt{75}[/tex] × Cos [tex]30^{0}[/tex]

    = 7.5

Therefore, AE = 7.5

Answer:

8

Step-by-step explanation:

The given is a special right triangle with angle measures

90-60-30 and side lengths represented by

2a-a[tex]\sqrt{3}[/tex]-a

x is the side length that sees angle measure 90 degrees so it's represented by 2a

and 4[tex]\sqrt{3}[/tex] is the side length that sees angle measure that sees 60 degrees so the value of a is 4

therefore x = 2*4 = 8

Answer:

a) -3/13

b) -1/8

Step-by-step explanation:

a)  - (21 / 7) / (91 / 7) = 3/13

b) (32 / 32 ) / - (256 / 32) = -1/8​

Answer:

3 weeks

Step-by-step explanation:

6 quarts = 12 pints

12 divided by 3 = 4

Step-by-step explanation:

1 quart = 2 pints

6 quarts = 2 x 6 = 12 pints

12 ÷ 4 = 3

He can have 3 weeks

Answer:

see explanation

Step-by-step explanation:

(43)

3[tex]x^{5}[/tex] - 75x³ ← factor out 3x³ from each term

= 3x³(x² - 25) ← this is a difference of squares and factors in general as

a² - b² = (a - b)(a + b) , thus

x² - 25 = x² - 5² = (x - 5)(x + 5)

Thus

3[tex]x^{5}[/tex] - 75x³ = 3x³(x - 5)(x + 5)

(44)

81c² + 72c + 16 ← is a perfect square of the form

(ac + b)² = a²c² + 2abc + b²

Compare coefficients of like terms

a² = 81 ⇒ a = [tex]\sqrt{81}[/tex] = 9

b² = 16 ⇒ b = [tex]\sqrt{16}[/tex] = 4

and 2ab = 2 × 9 × 4 = 72

Thus

81c² + 72c + 16 = (9c + 4)²

1. 3x^5 -75x³

=3x³(x²-25)

=3x³(x²-5²)

=3x³(x-5)(x+5)

2. 81c²+72c+16

=81c²+36c+36c+16

=9c(9c+4)+4(9c+4)

=(9c+4)(9c+4)

=(9c+4)²

Complete Question

Find the​ mean, variance, and standard deviation of the binomial distribution with the given values of n and p. ​, The​ mean, ​, is nothing. ​(Round to the nearest tenth as​ needed.)

    p =  0.6   n =  18

Answer:

The mean   [tex]\mu = 10.5[/tex]

The standard deviation [tex]\sigma = 2.08[/tex]

The  variance   [tex]var = 4.32[/tex]

Step-by-step explanation:

From the question we are told that

      The probability of success   is  [tex]p = 0.6[/tex]

      The  sample size is [tex]n = 18[/tex]

  Generally given that the distribution is binomial, then the probability of failure is mathematically represented as

              [tex]q = 1- p[/tex]

substituting values

              [tex]q = 1- 0.6[/tex]

              [tex]q =0.4[/tex]

Generally the mean is mathematically evaluated as

             [tex]\mu = np[/tex]

substituting values

             [tex]\mu = 18 * 0.6[/tex]    

             [tex]\mu = 10.5[/tex]

The  standard deviation is evaluated as

              [tex]\sigma = \sqrt{npq}[/tex]

substituting values

               [tex]\sigma = \sqrt{18 * 0.6 * 0.4}[/tex]

              [tex]\sigma = 2.08[/tex]

The variance is evaluated as

               [tex]var = \sigma^2[/tex]

substituting value

              [tex]var = 2.08^2[/tex]

              [tex]var = 4.32[/tex]

Answer:

Step-by-step explanation:

[tex](1+6i)-(7+3i) ?\\Group\:the\:real\:part\:and\:the\:imaginary\\\:part\:of\:the\:complex\:number\\\left(a+bi\right)\pm \left(c+di\right)=\left(a\:\pm \:c\right)+\left(b\:\pm \:d\right)i\\=\left(1-7\right)+\left(6-3\right)i\\1-7=-6\\6-3=3\\=-6+3i[/tex]