If f(x) = x-2, what is f¹(x)?
f¹(x) = 9x + 18
ƒ²¹(x) = x + 2
f¹(x) = 9x+2
ƒ¹ (x) = -2x +

The value of [tex]f^{-1}(49)[/tex] is 4

The given function is:

[tex]f(x)=(x+3)^2[/tex]

Let f(x) be represented by y

[tex]y=(x+3)^2[/tex]

Make x the subject of the formula

[tex]\sqrt{y} =x+3[/tex]

Subtract 3 from both sides

[tex]x=\sqrt{y} -3[/tex]

Replace x by [tex]f^{-1}(x)[/tex] and let y be replaced by x

[tex]f^{-1}(x)=\sqrt{x} -3[/tex]

Substitute x = 49 into the inverse function

[tex]f^{-1}(x)=\sqrt{49} -3\\\\f^{-1}(x)=7-3\\\\f^{-1}(x)=4[/tex]

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The correct statement comparing the theoretical and experimental probabilities is given as follows:

[tex]\frac{1}{4} < \frac{7}{25}[/tex].

A probability is given by the number of desired outcomes divided by the number of total outcomes.

The theoretical probability is taken before any experiment. Since the four sections are equal, the theoretical probability is:

T(H) = 1/4.

The experimental probability is taken considering previous experiments. Out of 100 tosses, 28 landed on H, hence:

E(H) = 28/100 = 7/25.

Hence the correct statement is:

[tex]\frac{1}{4} < \frac{7}{25}[/tex].

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The missing digit for the American Express Traveler's Check identification number is option (C) 6 is the correct answer.

In this question,

A Check Digit is a decimal (or alphanumeric) digit added to a number for the purpose of detecting the sorts of errors humans typically make on data entry.

A check digit is a digit added to a string of numbers for error detection purposes. Normally, the check digit is computed from the other digits in the string. A check digit helps digital systems detect changes when data is transferred from transmitter to receiver.

The last digit of a bar code number is a calculated check digit. The check digit is calculated from all the other numbers in the bar code and helps to confirm the integrity of your bar code number.

The American Express Traveler's Check identification number is 783920*814.

In Airline tickets, there are several digits plus a check digit.

Divide the ID number by 7. The check digit is the remainder.

Sum of digits = 7+8+3+9+2+0+8+1+4

⇒ 42

Now divide the sum by 7, the remainder is

⇒ 42 mod 7 = 42 - (5×7)

⇒ 42 mod 7 = 6

Hence we can conclude that the missing digit for the American Express Traveler's Check identification number is option (C) 6 is the correct answer.

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Answer:

(x - 5)^2 + (y - 6)^2 = 64

Step-by-step explanation:

Every circumference is in the form:

(x - xc)^2 + (y - yc)^2 = r^2

Where xc is the x of the center. Yc is the y of the center. r is the radius. We just plug in the values and we're done.

Answer:

[tex](x-5)^2+(y-6)^2=64[/tex]

Step-by-step explanation:

Equation of a circle

[tex](x-a)^2+(y-b)^2=r^2[/tex]

where:

Given:

Substitute the given values into the formula:

[tex]\implies (x-5)^2+(y-6)^2=8^2[/tex]

[tex]\implies (x-5)^2+(y-6)^2=64[/tex]

Therefore, the equation of a circle with the given values is:

[tex](x-5)^2+(y-6)^2=64[/tex]

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The equation of the line is 3x + y = 1

The points are given as:

(5, −2) and (3, 4)

Start by calculating the slope (m)

m =(y2 - y1)/(x2 - x1)

This gives

m = (4 + 2)/(3 - 5)

Evaluate

m = -3

The equation is then calculated as:

y = m(x - x1) + y1

This gives

y = -3(x + 2) +5

So, we have:

y = -3x - 6 + 5

Evaluate the like terms

y = -3x - 1

Rewrite as:

3x + y = 1

Hence, the equation of the line is 3x + y = 1

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The total amount of money received from sales of shoes that month = $4968

Salary = $11000

Number of shoes sold = 360

Cost of 1 shoe = $460

Total cost of shoes sold = 360 x 460

Total cost of shoes sold = $165600

Since $165600 is greater than $100000, she will earn a commission of 3%

Commission = (3/100) x $165600

Commission = $4968

The commission is the amount of money received from sales of shoes. Other earnings are salary or increment

Therefore, the total amount of money received from sales of shoes that month = $4968

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The expression that is not a rational expression is:

[tex]\frac{(x + 3)(2x - 1)}{x + 3}[/tex]

A rational expression is an expression that has a variable in the denominator.

For expression [tex]\frac{(x + 3)(2x - 1)}{x + 3}[/tex], x + 3 is a common term to the numerator and denominator, hence it is simplified to 2x - 1 and is not a rational expression.

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The option that is not a rational expression is [tex]\frac{3x + 4\sqrt{x} -7}{2x+2}[/tex]

Rational expression are fraction whose numerator and denominator are polynomials.

In other words, rational expression is the ratio of two polynomials.

Therefore, an example of a ration expression is as follows:

[tex]\frac{x^{2}+9 }{x + 1}[/tex]

Therefore, the option that is not a rational expression is as follows;

[tex]\frac{3x + 4\sqrt{x} -7}{2x+2}[/tex]

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Probability that Margie's first serve will be good at least four of the next six times she serves is 0.68

What is Binomial Distribution in Probability?

Assume that n independent replications of a random experiment with exactly two outcomes are performed. Success has a probability of [tex]p[/tex], while failure has a probability of [tex]q[/tex]. Assume that out of these n times, we will experience success [tex]x[/tex] times and failure [tex]n-x[/tex] times. There are [tex]^nC_x[/tex] different ways in which we can succeed. If, [tex]X[/tex] has a binomial distribution, then,

[tex]P(X=x)=p(x)[/tex]

                  [tex]=[/tex] [tex]^nC_xp^xq^{n-x}[/tex]

for [tex]x[/tex] = 0, 1,..., n. Here,  [tex]q=1-p[/tex]. A binomial variate is any such random variable [tex]X[/tex]. A group of n separate Bernoullian trials is known as a binomial trial. Binomial distribution requirements:

For each trial, the odds of success [tex]p[/tex], or failure [tex]q[/tex], remain constant.

Given,

Probability of good serves = Success

⇒ [tex]p=\frac{20}{30}[/tex]

⇒[tex]p=\frac{2}{3}[/tex]

Failure = [tex]q[/tex]

⇒ [tex]q=1-p[/tex]

⇒ [tex]q=1-\frac{2}{3}[/tex]

⇒ [tex]q=\frac{1}{3}[/tex]

Number of trials [tex]= n[/tex]

[tex]n=6[/tex]

Probability of at least four good serve = [tex]P(4 < X < 6)[/tex]

According to the binomial distribution,

Therefore,

[tex]P(4 \leq X \leq 6)=P(X=4)+P(X=5)+P(X=6)[/tex]

                      [tex]=[/tex] [tex]^6C_4(\frac{2}{3}) ^4(\frac{1}{3})^2+ ^6C_5(\frac{2}{3}) ^5(\frac{1}{3})^1+^6C_6(\frac{2}{3}) ^6(\frac{1}{3})^0[/tex]

                      [tex]=[/tex] [tex]15\times\frac{16}{729} +6\times\frac{32}{729} +1\times\frac{64}{729}[/tex]

                      [tex]=[/tex] [tex]\frac{496}{729}[/tex]

                      [tex]= 0.68[/tex]

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[tex]\textbf{Heya !}[/tex]

the mode is the number that occurs the most

All numbers here occur once, except [tex]\sf{100}[/tex].

so 100 is the mode.

`hope it was helpful to u ~

Using the monthly payment formula, it is found that her down payment should be of $1,419.

It is given by:

[tex]A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}[/tex]

In which:

For this problem, the parameters are:

A = 250, r = 0.072, n = 72.

Hence:

r/12 = 0.072/12 = 0.006.

We solve for P to find the total amount of the monthly payments, hence:

[tex]A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}[/tex]

[tex]P\frac{0.006(1.006)^{72}}{(1.006)^{72}-1} = 250[/tex]

0.0171452057P = 250

P = 250/0.0171452057

P = $14,581.

The total payment is of $16,000, hence her down payment should be of:

16000 - 14581 = $1,419.

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The equation of the perpendicular bisector of BC with B(-2, 1), and C(4, 2) is y = 7.6 - 6•x

The slope, m, of the line BC is calculated as follows;

The slope of the perpendicular line to BC is -1/(1/6) = -6

The midpoint of the line BC is found as follows;

[tex] \left( - 2 + \frac{4 - ( - 2)}{2}, \: 1 + \frac{2 - 1}{2} \right) = (1,\: 1.5)[/tex]

The perpendicular bisector is the perpendicular line constructed from the midpoint of BC.

The equation of the perpendicular bisector in point and slope form is therefore;

(y - 1.5) = -6•(x - 1)

y - 1.6 = -6•x + 6

y = -6•x + 6 + 1.6 = 7.6 - 6•x

Which gives;

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The length of ED is half the length of AB.

Reasons:

The given parameters are;

In ΔABC, point E is the midpoint of AC

The midpoint of BC is the point D

Segment ED = s

Segment CE = p

Segment EA = r

Segment CD = q

Segment DB = t

Segment ED = s

Segment AB = u

Required:

The expression that represents the value of [tex]s[/tex].

Solution:

CE = 0.5 × AC Definition of midpoint

CD = 0.5 × CB Definition of midpoint

Therefore, we have;

[tex]\frac{CE}{AC} =\frac{CD}{CB} =0.5[/tex]

Therefore, given that ∠C ≅ ∠C, by the reflexive property, we have;

ΔABC is similar to ΔCDE by Side-Angle-Side similarity

Which gives;

[tex]\frac{CE}{AC} = \frac{CD}{CB} = \frac{ED}{AB} =0.5=\frac{1}{2}[/tex]

ED = s and AB = u which gives;

[tex]\frac{ED}{AB}=\frac{s}{u} =0.5=\frac{1}{2}[/tex]

[tex]\frac{s}{u} =\frac{1}{2}[/tex]

Which gives:

[tex]s=\frac{1}{2} *u[/tex]

The expression that represents the value of s is; s = one-half u

Therefore, the length of ED is half the length of AB.

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The question you are looking for is here:

If point E is the midpoint of segment AC and point D is the midpoint of segment BC, which expression represents the value of s? triangle CAB, point E is on segment AC between points A and C and point D is on segment BC between points B and C, creating segment ED, CE equals p, EA equals r, CD equals q, DB equals t, ED equals s, and AB equals u s equals p over q s = one half s equals q over p s = 2u

The height of the cylinder is 4 x units.

The area of the cylinder’s base is One-fourthπx2 square units .

What is the volume of cylinder?

We know the volume of a cylinder is given by the formula  π r2 h, where r is the radius of the cylinder and h is the height.

Formula for volume of the cylinder

V = r² π h

Volume of the cylinder= πx³

Diameter=x

Radius (r)=diameter/2

       r  =  x/2

     V = r² π h

   πx³=(x/2)² πh

πx³= (x²/4)πh

Divide both sides by π

x³ =(x²/4)h

Make h the subject of the formula

  h = x³ ÷ x²/4

     =x³ ×4 / x²

     =4x³ / x²

     =4 * x * x * x / x * x

  h=4x

Area of the base:

B = r² π

r=x/2

B=(x/2)² * π

 =(x²/4)π

=πx²/4

=1/4(πx²)

Therefore, The area of the cylinder’s base is One-fourthπx2 square units.

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The complete question is -

A cylinder with a base diameter of x units has a volume of πx3 cubic units. A cylinder with a base diameter of x units has a volume of pi x cubed cubic units. Which statements about the cylinder are true? Select two options. The radius of the cylinder is 2x units. The area of the cylinder’s base is One-fourthπx2 square units. The area of the cylinder’s base is One-halfπx2 square units. The height of the cylinder is 2x units. The height of the cylinder is 4x units.

Answer:

C. B=38.8, C=95.2, c=42.9

Step-by-step explanation:

Find B by using sine rule

sin 46/31=sin B/27

sin B= 27 sin 46/31

B=sin‐¹(0.627)

B=38.8

Find C

C= 180-(A+B)

C=180-(38.8+46)

C=95.2

Using sine rule, Find c

31/sin 46=c/sin 95.2

c=31 sin 95.2/sin 46

c=42.9

The point F as described in the task content is at point; 0.6 on the number line.

Since it follows from.tge task content that; point D is at -3, and point E Is at 6, it follows that the length of segment, DE is; |-3-6| = 9.

Consequently, since the ratio of Df to FE ls 2:3

It follows that point F is at -3 + (2/5) × 9.

Point F is therefore at 0.6 on the number line.

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Answer:

it depends.

Step-by-step explanation:

A perfect square is a number that can be expressed as the product of an interger by itself or as the second exponent of an interger. For example, 25 is a perfect square because it is the product of interger 5 by itself, 5 × 5 =25.

[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]

[tex]\textsf{ \underline{\underline{Steps to solve the problem} }:}[/tex]

[tex]\qquad❖ \: \sf \: \angle1 \cong \angle2[/tex]

( by corresponding angle pair )

[tex]\qquad❖ \: \sf \: \angle2 \cong \angle3[/tex]

( given in the question )

[tex] \qquad \large \sf {Conclusion} : [/tex]

[tex]\qquad❖ \: \sf \: \angle1 \cong \angle3[/tex]

Applying the distance formula, to calculate the coordinates of B, use: 3 =√[(x-4)² + (y-2)²]  

The distance formula, [tex]d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex], is used to find the distance between two points on a coordinate plane.

We are given one point A(4, 2), let:

B (x, y) = (x2, y2)

A(4, 2) = (x1, y1)

d = 3 units

Plug in the values into the distance formula to find how to calculate the coordinates of B:

3 =√[(x-4)² + (y-2)²]  

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Answer: the answer is 661.55

Step-by-step explanation:

interest formula: F = Pe^(rt)

Answer:

∠ABE = 33°

Step-by-step explanation:

        Angle bisector is a straight line that divides the angle into two congruent (equal) angles.

So, BE bisects the ∠ABD into two equal angles.

⇒∠ABE will be half of ∠ABD

∠ABD = ∠ABE + ∠BED

66°     = ∠ABE + ∠ABE

66      = 2∠ABE

∠ABE = 66/2

∠ABE = 33°

52.94% of the viewers prefer videos on a mobile or laptop device

The given parameters are

Viewers that prefer videos on a mobile or laptop device = 18

Total number of viewers = 34

The percentage of voters in this category is then calculated as

Percentage = 18/34 * 100%

Evaluate the expression

Percentage = 52.94%

Hence, 52.94% of the viewers prefer videos on a mobile or laptop device

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Answer:

( x-3) ^2 + ( y-1) ^2 = 4

Step-by-step explanation:

The equation for a circle is given by

( x-h)^2 + ( y-k) ^2 = r^2  where (h,k) is the center and r is the radius

( x-3) ^2 + ( y-1) ^2 = 2^2

( x-3) ^2 + ( y-1) ^2 = 4

Answer:

b. x^2+4x

Step-by-step explanation:

So since you don't know the width, you can just represent it as a variable, and in this case that variable will be "x". Now using this variable we can use it to represent the length since there is a relationship between the width and length which is given. Since the length is 4 feet greater than the width, we can represent the length as (x+4). Now to find the area, we simply multiply the length * width, which is x * (x+4) = x^2 + 4x

Using the z-distribution, it is found that the 95% confidence interval for the proportion of college students who work to pay for tuition and living expenses is: (0.4239, 0.5161).

If we had increased the confidence level, the margin of error also would have increased.

A confidence interval of proportions is given by:

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which:

In this problem, we have a 95% confidence level, hence[tex]\alpha = 0.95[/tex], z is the value of Z that has a p-value of [tex]\frac{1+0.95}{2} = 0.975[/tex], so the critical value is z = 1.96. Increasing the confidence level, z also increases, hence the margin of error also would have increased.

The sample size and the estimate are given as follows:

[tex]n = 450, \pi = 0.47[/tex].

The lower and the upper bound of the interval are given, respectively, by:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.47 - 1.96\sqrt{\frac{0.47(0.53)}{450}} = 0.4239[/tex]

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.47 + 1.96\sqrt{\frac{0.47(0.53)}{450}} = 0.5161[/tex]

The 95% confidence interval for the proportion of college students who work to pay for tuition and living expenses is: (0.4239, 0.5161).

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Answer:

2

Step-by-step explanation:

(-1,-4) (2,2)

To find the slope, use the equation y2-y1/x2-x1

2-(-4)/2-(-1) = 6/3

6/3=2

2 is the slope.

Answer:

-1,-3,-4 it is just subtracting the same amount.

Step-by-step explanation:

Answer:

[tex]\huge\boxed{\sf DE = 9}[/tex]

Step-by-step explanation:

From the figure,

AB = 2

BC = 3

AD = 6

Substitute in the given formula

[tex]\displaystyle \frac{AB}{BC} =\frac{AD}{DE} \\\\\frac{2}{3} = \frac{6}{DE} \\\\Cross \ Multiply \\\\2 \times DE = 6 \times 3\\\\2DE = 18\\\\Divide \ 2 \ to \ both \ sides\\\\DE = 18/2\\\\DE = 9\\\\\rule[225]{225}{2}[/tex]

Option (d) is correct. Convenience sampling collects sample information from easy-to-collect groups.

Given convenient sampling.

Convenience sampling is defined as a method adopted by researchers in which they collect market research data from a pre-existing group of respondents. This is the most commonly used sampling technique because it is extremely fast, simple and economical. In many cases, members are easily accessible to be part of the template. It is non-probability sampling and therefore different from random sampling. Since the samples are taken for convenience, the samples are not always representative of the population and therefore have bias. In this case, people were sampled simply because they were convenient.

Thus, convenience sampling collects sample information from easy-to-collect groups.

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