Answer:
b) in atmostphere
Explanation:
I made lots of research and it should be b.
a. On a particular day, atmospheric pressure is 730 mm of mercury In pascals 97392.2896252, b. On a particular day, atmospheric pressure is 730 mm of mercury in atmospheres 0.960526316 atm, c. on a particular day, atmospheric pressure is 730 mm of mercury in millibars 973.70355547 mb.
a) To convert atmospheric pressure from mm of mercury to pascals, we can use the conversion factor: 1 mm Hg = 133.322387415 pascals.
Pressure in pascals = 730 mm Hg * 133.322387415 = 97392.2896252 pascals.
b) To convert atmospheric pressure from mm of mercury to atmospheres, we can use the conversion factor: 1 atm = 760 mm Hg.
Pressure in atmospheres = 730 mm Hg / 760 = 0.960526316 atm.
c) Atmospheric pressure is often expressed in millibars (mb), where 1 atmosphere is approximately equal to 1013.25 millibars.
Pressure in millibars = 0.960526316 atm * 1013.25 mb/atm = 973.70355547 mb.
Atmospheric pressure is the force exerted by the weight of air molecules in the Earth's atmosphere. It can be measured in various units, including millimeters of mercury, pascals, atmospheres, and millibars.
Converting between these units involves using conversion factors based on established relationships between them.
In this case, the provided pressure of 730 mm Hg was converted to pascals, atmospheres, and millibars using the appropriate conversion factors.
Conversions help express pressure measurements in units that are more suitable for different contexts or calculations.
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A train travels southwest from point A to point B through the Arizona desert at 55 mi/h. How far will the train travel six-and-a-half hours?
Explanation:
Distance = speed × time
d = (55 mi/hr) (6.5 hr)
d = 357.5 mi
A spring of initial length 35 cm acquires a length of 55 cm when we hang from it a mass of 3.5 kg. Calculate:
a) The elastic constant of the spring.
b) The length of the spring when we hang a mass of 5 Kg.
Answer:
the elastic constant of the spring=1.715
the length of the spring=0.28
Explanation:
we know that according to hooks law
F=-k x
F= force
k= elastic constant
x= extension or compression
given
length change from 35cm to 55 cm so delta x = L2-L1= 55-35=20 cm
now to find k we need F and F =ma
M for part a is 3.5 kg
so F=3.5 kg *9.8=34.3
now k=F/x
k=34.3/20=1.715 N/cm=171.5 N/m
now to find length given mass is 5 kg so
F= ma
F=5*9.8=49 N
so x =F/k
x=49/171.5
x=0.28
please help urgent have you ever seen the old “Pull the tablecloth out from under the dishes” trick? Use Newton’s 1st Law to explain the following:
a. In this trick, are the dishes “objects in motion,” or “objects at rest?”
b. If the dishes end up staying on the table, was an UNBALANCED FORCE applied to them? How do you know?
Answer:
I kinda dont remember the 1st law so search it up on
and it should tell u , but if u need any help from the
You put a piece of ice into a glass of lemonade at room temperature. Which statements explains the heat flow in this scenario? A. Heat flows in both directions. B. Heat flows from the ice to the lemonade. C. Heat flows from the lemonade to the ice. D. Heat flows from the ice to the lemonade to the glass.
Answer:
C. Heat flows from lemonade to the ice
Explanation:
Transfer of heat from the drink to the ice is what melts the ice and cools the drink.
i)Distinguish between different methods of charging. ii) You are provided with a positively charged gold leaf electroscope. State and explain what happens when a. a glass rod rubbed with silk is brought near the disc of electroscope. b. an ebonite rod rubbed with fur is brought near the disc of electroscope. c. an uncharged metal rod is brought near the disc of electroscope d. a glass rod rubbed with silk is rolled on the disc of electroscope.
Answer:
Explanation:
On rubbing a glass rod with silk, the electrons from the glass rod get transferred to the silk. The silk now has an excess of electrons and so is negatively-charged. On the other hand, the glass rod is deficient in electrons and hence is positively-charged.
In the above case, the silk undergoes negative electrification.
Now, when the positively charged glass rod is touched on the disc of a negatively charged gold leaf electroscope, the electrons shifts towards rod, hence amount of charge on gold leaves decreases and the divergence between the gold leaves decreases as unlike charges attract each other.
Hence, the divergence decreases when a glass rod rubbed with silk is brought near the disc of negatively charged electroscope.
hope it helps pls mark me as brainliest
Which is an example of current electricity?
Answer:
D
Explanation:
i just did it trust me
show how three identical 6 resistors must be connected tho have the following effective resistance values 9 and 4 ohms
Answer:
connect two 9 ohms resistance in series now it becomes 18 ohm
Brainstorm and write at least 3 potential challenges or important points to consider when conducting the described
data collection.
Plz help me I need to turn this in tomorrow and I’m working on on it at 10:35 pm
Although you did not mention the "described data collection," we can help you answer in the following terms.
The three potential challenges or important points to consider when conducting data collection are:
1.- To correctly establish the specific information needed to get as a result of the research.
2.- The kind of methodology appropriate to get that expected data.
3.- The process needed to analyze and interpret that data.
- As well, it is of the utmost importance that the researcher considers the type of data compared to the budget needed to get it. Here, the budget should consider the cost of the collection process.
- Of course, the result of the process has to result in data that is valid and accurate, because that is the nature of a good research project.
Here we have to stress the relevance of the establishment of a good hypothesis to start the collection process, no matter the data collection methods used to get the data such as interviews, focus groups, observations, and so on.
We can conclude that collection data is a rigorous process that should be strictly followed to really obtain the kind of data needed to support the foundation of any research.
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An electron and a proton are 6.5x10 ^ -11 m apart, find the magnitude of the electric and gravitational force between the two particles
Explanation:
The electric force is:
F = k q₁ q₂ / r²
F = (9×10⁹ Nm²/C²) (-1.6×10⁻¹⁹ C) (+1.6×10⁻¹⁹ C) / (6.5×10⁻¹¹ m)²
F = 5.4×10⁻⁸ N
The gravitational force is:
F = G m₁ m₂ / r²
F = (6.67×10⁻¹¹ Nm²/kg²) (9.11×10⁻³¹ kg) (1.67×10⁻²⁷ kg) / (6.5×10⁻¹¹ m)²
F = 2.40×10⁻⁴⁷ N
How long will it take a 6000W motor to lift a 5000kg load through a height of 2.5m?
Answer:
20.4375 seconds.
Explanation:
Wattage = Work / time
Work = f * d
F = mass * acceleration
mass = 5000 kg
acceleration = force of gravity
acceleration = 9.81
Force = 5000 * 9.81
Force = 49050 N
Work = F * d
d = 2.5
Work = 49050 * 2.5
Work = 122625 Joules
Wattage = Work / time
time = work / wattage
wattage = 6000 watts
time = 122625 / 6000
time = 20.4375 seconds.
What is The distance traveled by a vehicle in 12 minutes,if it’s speed is 35km/h
Answer: 7 km
Explanation: 12 minutes is 1/5 of an hour. 35/5=7
How to find average acceleration only using displacement and time?
Answer:
Average acceleration = Displacement / (time)^2
Explanation:
The unit for acceleration is
[tex]m {s}^{ - 2} [/tex]
Displacement = m
Time = s
Hence the units of displacement and time should be manipulated to get the unit of acceleration.
You can't. You can only find average velocity.
But if you also know that initial velocity is zero ... the object started from rest ... then
Avg acceleration =
2 x displacement / time-squared
........................
Answer:
14°F = 263.15 K
31°F = 272.594 K
71°F = 294.817 K
35°F = 274.817 K
Explanation:
Use the formula 273.15 + ((°F–32)•5)/9
3) An earth moving machine uses diesel oil, which when burnt will produce 3.0x10 9 J of energy. The work performed by the machine is 2.7x 10 8 J. What is the efficiency of the machine?
Answer:
The answer is below
Explanation:
The efficiency of a machine is the ratio of its output to its input. The efficiency shows how effective the machine by the way it converts the input energy into work. The higher the efficiency of the machine the more effective it is. The efficiency is usually less than 1.
Given that the machine uses diesel oil (input) that can produce 3.0 x 10⁹ J of energy while the work performed by the machine (output) is 2.7 x 10⁸ J. The efficiency is given as:
Efficiency = output / input = 2.7 x 10⁸ J / 3.0 x 10⁹ J = 0.09 = 9%
This means that the machine is not effective because of its low efficiency
an object weights 0.250 kgf in air 0.150 in water and 0.125 in an oil.find out the density of the object and the oil
Answer:
1) The density of the object = 2500 kg/m³
2) The density of the oil = 1250 kg/m³
Explanation:
1) The information relating to the question are;
The mass of the object in air = 0.250 kgf
The mass of the object in water = 0.150 kgf
The mass of the object in the oil = 0.125 kgf
By Archimedes's principle, we have;
The upthrust on the object in water = Mass in air - mass in water = The weight of the water displaced
The upthrust on the object in water = 0.250 - 0.150 = 0.1 kgf
∴ The weight of the water displaced = 0.1 kgf
Given that the object is completely immersed in the water, we have;
The volume of the water displaced = The volume of the object
The volume of 0.1 kg of water water displaced = Mass of the water/(Density of water)
The volume of 0.1 kg of water = 0.1/1000 = 0.0001 m³
The density of the object = (Mass in air)/ volume = 0.250/0.0001 = 2500 kg/m³
The density of the object = 2500 kg/m³
2) Whereby the mass of the object in the oil = 0.125 kgf
The upthrust of the oil = The weight of the oil displaced
The upthrust of the oil on the object = Mass of the object in air - mass of the object in the oil
The upthrust of the oil on the object = 0.250 - 0.125 = 0.125 kgf
The weight of the oil displaced = The upthrust of the oil
Given that the volume of the oil displaced = The volume of the oil, we have;
The volume of the oil displaced = 0.0001 m³
The mass of the 0.0001 m³ = 0.125 kg
Therefore the density of the oil = 0.125/0.0001 = 1250 kg/m³.
The density of the oil = 1250 kg/m³.
The motion of a particle along a straight line is described by the equation x=6+4t2 -t 4 , where x is in meter and t is in seconds. Find position, velocity, and acceleration of the object when t=2s.
Answer:
The position of the particle is 6m
The velocity of the particle is 16 m/s in negative direction
The acceleration of the object is -40 m/s²
Explanation:
Given;
motion of the particle along a straight line as x = 6 + 4t² - t⁴
The position of the object when t = 2s
x = 6 + 4(2)² - (2)⁴
x = 6 + 16 - 16
x = 6m
The velocity of the object when t = 2s
Velocity = dx/dt
dx/dt = 8t - 4t³
when t = 2s
Velocity = 8(2) - 4(2)³
Velocity = 16 - 32
Velocity = -16m/s
Velocity = 16 m/s (in negative direction)
The acceleration of the object when t = 2s
Acceleration = d²x/dt² = 8 - 12t²
Acceleration = 8 - 12 (2)²
Acceleration = -40 m/s²
1. Car A is heading East at 25 m/s and car B is also heading East at 25 m/s. What is the relative velocity between car A
and car B? How would the passenger in Car A describe Car B's motion
The relative velocity between Car A and Car B is 0 m/s
Since Car A is heading East at 25 m/s, its velocity is u = + 25 m/s. (since it is moving in the positive x- direction)
Also, car B is also heading East at 25 m/s, its velocity is v = + 25 m/s. (since it is moving in the positive x- direction)
So, the relative velocity between car A and Car B is V = velocity of car A - velocity of car B.
So, V = u - v
V = + 25 m/s - (+ 25 m/s)
V = + 25 m/s - 25 m/s
V = 0 m/s
So, the relative velocity between Car A and Car B is 0 m/s
The passenger in Car A would describe Car B's motion as stationary.
Since Car A is heading East at 25 m/s and car B is also heading East at 25 m/s, both cars are moving at a velocity of + 25 m/s.
Since their relative velocity is 0 m/s, it would appear to a passenger in Car A that car B is stationary according to motion from car A's reference frame.
So, the passenger in Car A would describe Car B's motion as stationary.
Exercise combined with a _____________________________________can help control weight.
Answer:
healthy diet
Explanation:
Exercise and a healthy diet are the two things people do to stay healthy
a ferris wheel has a centripetal acceleration equal to 2m/s squared. what is the centripetal force acting on a 45 kg boy riding in one of the cars when the car is on the top of the ferris wheel? what is the force exerted by the seat on the boy when the car is at the top of the ferris wheel
Explanation:
[tex]centripetal \: force = \frac{m {v}^{2} }{r} [/tex]
Centripetal force = 45 * 2 = 90 N
Therefore, centripetal force acting on a 45 kg boy riding in one of the cars when the car is on the top of the ferris wheel is 90 N.
The force exerted by the seat on the boy when the car is at the top of the ferris wheel is a centrifugal (pseudo force) acting (since the since the seat is in non- inertial frame) in exact opposite direction (Outwards) as the centripetal force and is equal in magnitude.
At the end of an investigation, you must__________ ____________. Your results may or may not support your hypothesis.
Answer:
could and largejsjisj and we look like they can get to
3. Assume that the elastic bands on a slingshot work like a spring with a
spring constant of 250 N/m. If you have to pull back with 100 N of stretch
(spring) force to fully stretch the bands, how far will the elastic bands stretch?
Please help me
As you stretch the band a distance x, the force you need to exert has a magnitude of (250 N/m) x.
So if 100 N is required to stretch it to maximum length, then this length is x such that
100 N = (250 N/m) x ==> x = (100 N)/(250 N/m) = 0.4 m
Answer:
0.6
Explanation:
I got it right
1. Determina el momento que produce una fuerza de 7 N tangente a una rueda de un metro de diámetro, sabiendo que el punto de aplicación es el mismo borde de dicha rueda provocando un impulso en el sentido de las agujas del reloj. Solución:
Answer:
τ= F r into the blade
Explanation:
The moment of a force is defined by
τ = F x r
where the bold indicates vectors
Let us write in the expression in magnitude
τ = F r sin θ
in our case the force is tangent to the wheel therefore the angle between F and the radius is 90º, and the sin 90 = 1
τ= F r
The direction of τ can be used by the rule of the right hand, the fingers curve in the direction of the torque when advancing from the force to the radius and the thumb points in the direction of the torque.
In this case, for a clockwise rotation, the fingers are curved in the direction and the thumb points into the blade, this is the direction of the τ.
TRASLATE
El momento de una fura es definido por
τ = F x r
donde la negrillas indican vectores
Escribamos en ta expresión en magnitud
τ = F r sin θ
en nuestro caso la fuerza es tangente a la rueda por lo tanto el angulo entre F y el radios es 90º, y el sin 90=1
τ = F r
la dirección de tau la podemos usar la regla de la mano derecha, los dedos curva en la dirección del torque al avanzar dese la fuerza al radio y el pulgar apunta en la dirección del torque.
En este caso para un giro en sentido horario los dedos se curvan ente sentido y el pulgar apunta hacia dentro de lla hoja, esta es la dirección del troque
when we jump off a boat towards the shore the boat moves back why
its not in nurtal or park
what is the distance fallen for a freely falling ojvect 1 s after being dropped from a rest position
Answer:
111op
Explanation:
Answer:
11op
Explanation:good job and work hard
what is Newton's first law of motion?
EXPLAIN WITH SOME EXAMPLES
Answer:
The tendency of undisturbed objects to stay at rest or to keep moving with the same velocity is called inertia. This is why, the first law of motion is also known as the law of inertia.
Example.: A ball at rest on the ground continues to be at rest unless someone kicks it or any external force acts on it.
Explanation:
I hope this will help you buddy
3. Calculate the wavelength of wave that has a frequency of 4.75 x 1012Hz.
a. 1.43 x 1021 m
b. 6.31 x 105 m
1.58 x 104 m
d. 6.31 x 105 m
please help
C.
We know
[tex]\boxed{\sf \lambda=\dfrac{C}{V}}[/tex]
[tex]\\ \sf\longmapsto \lambda=\dfrac{3\times 10^8ms^{-1}}{4.75\times 10^{12}s^{-1}}[/tex]
[tex]\\ \sf\longmapsto \lambda=0.631\times 10^{-4}m[/tex]
[tex]\\ \sf\longmapsto \lambda=6.31\times 10^{-5}m[/tex]
In nonequilibrium, total counterclockwise moments = total clockwise moments. *True False
Answer:
[tex]{ \bf{false}}[/tex]
Explanation:
Because it breaks the law of moments.
A storm is moving east towards your house at an average speed of 35 km / hr. If the storm is currently 80 km from your house, how much time do you expect it to arrive
Answer:
The expected time is 2.28 hours.
Explanation:
The speed of storm = 35 km/hr
The distance between the house and the storm = 80 km.
Now, we have to find the time taken by storm to arrive at the house. Here, we can determine the time by dividing the distance with speed.
The time, taken by storm = Distance/speed
The time, taken by storm = 80 / 35
The time, taken by storm = 2.28 hours.
Mr. Franklin uses a machine that has an efficiency of 80%. The machine applies a force of 800 N through a distance of 20 m. Mr. Franklin applies a force of 50 N on the machine. Through what distance does Mr. Franklin apply the force? 4 m 16 m 260 m 400 m
Answer:
The distance Mr Franklin applied the force is 400 m
Explanation:
The efficiency of the machine = 80%
The force applied by the machine = 800 N
The distance over which the force is applied by the machine = 20 m
The force applied by Mr. Franklin = 50 N
The work done by the machine = 800 × 20 = 16000 J
The ideal work at 100% efficiency = X
80% of X = 16000 J
X = 16000 N/0.8 = 20,000 J
Therefore, we have have;
Work = Force × Distance;
20,000 J = 50 N × Distance Mr Franklin applied the force
Distance Mr Franklin applied the force = 20,000 J/(50 N) = 400 m
The distance Mr Franklin applied the force = 400 m.
Answer:
the awnser in 400m
Explanation:
did the test on edge 2020 and got it right
The force exerted by the earth on a body is called ______of a body.
Answer:
The force exerted by the earth on a body is called gravitational of a body.
i think this is the answer
Answer:weight
Explanation: