If Thor throws his axe horizontally at a velocity of 50 m/s at and a height of 20 m, how long does it take before it hits the ground? (gravity is 9.8 m/s^2)

Answer: I’m sure theirs people out there that like you, and if there isn’t, you should just focus on yourself.

Explanation:

Answer:

Well, There are a couple reasons it could seem like nobody loves you...

Explanation:

One reason is that people really do love you, they just were never shown love and affection so they are unsure of how to show that to you. Another reason could be that it's god telling you that you are meant for much bigger and greater things. Maybe it's him reminding you that, yeah, people really suck, but that's life, and you're better than that. If you make the right decisions in life, you will be able to stand taller than they ever did. I hope this helps.. : )

Answer:

t = 3.25 seconds.

Explanation:

A person throws a baseball from a height of 7 feet with an initial vertical velocity of 50 feet per second is given by :

[tex]h=-16t^2+vt+h_0[/tex]

[tex]h=-16t^2+50t+7[/tex]

We need to find the amount of time the baseball is in the air before it hits the ground. ATQ,

h = 0

[tex]-16t^2+50t+7=0\\\\t=\dfrac{-50 \pm \sqrt{50^2-4\times (-16)(7)} }{2(-16)}\\\\t=\dfrac{-50 + \sqrt{50^2-4\times (-16)(7)} }{2(-16)}, \dfrac{-50- \sqrt{50^2-4\times (-16)(7)} }{2(-16)}\\\\t=-0.134\ s,3.25\ s[/tex]

Neglecting negative value, t = 3.25 s

So, the baseball will hit the ground at t = 3.25 seconds.

Explanation:

i think it will be on the ground

Answer:

No, they will not change.

Explanation:

Answer:

Initial velocity is independent of the slope of the graph; that is, the acceleration. An object thrown downward still accelerates after release at the same rate as an object that is dropped.

Answer:

The acceleration of the ball from 0.5 to 0.7 seconds is 10 m/s²

Explanation:

The data from the given velocity-time graph are as follows;

Velocity (meters per second)       [tex]{}[/tex]                       Time (seconds)

0                                                    [tex]{}[/tex]                          0.4

0.5                                                   [tex]{}[/tex]                        0.45

1.                                                 [tex]{}[/tex]                             0.5

1.5                                                   [tex]{}[/tex]                         0.55

2.2                                                   [tex]{}[/tex]                        0.6

2.5                                                   [tex]{}[/tex]                        0.65

3.0                                                   [tex]{}[/tex]                        0.7

3.5                                                   [tex]{}[/tex]                        0.75

4.0                                                   [tex]{}[/tex]                        0.8

4.5                                                   [tex]{}[/tex]                        0.85

Therefore, the average acceleration of the ball from 0.7 to 0.7 seconds is given as follows;

Acceleration = (Change in velocity)/(Related change in time)

Acceleration = (3.0 - 1)m/s/(0.7 - 0.5)s = 2/0.2 m/s²  = 10 m/s²

The acceleration of the ball from 0.5 to 0.7 seconds = 10 m/s².

Answer:

2

Explanation:

Answer:

False

Explanation:

Answer:

a. 42.92 m/s b 4.4 s c. 915.2 m

Explanation:

Here is the complete question

A volcano erupts, and a chunk of hot magma is launched horizontally with a speed of  ​ 208 m/s, from a height of 94 m. We can ignore air resistance.

What is the vertical velocity of the magma when it hits the ground?

Solution

a. Using v² = u² - 2gy since it is motion under gravity, where u = initial vertical velocity = 0 m/s, g = acceleration due to gravity = -9.8 m/s² and y =  height = 94 m.

Substituting these values into the equation, we have

v² = u² - 2gy

v² = 0² - 2 × (-9.8 m/s²) × 94 m

v² = 1842.4 m²/s²

v = √1842.4 m²/s²

v = 42.92 m/s

b. We also find the time it takes to drop from the height of 94 m from

y = ut - 1/2gt² , u = 0

So, t = √(2y/g)

= √(2 × 94 m ÷ 9.8 m/s²)

= √19.184 s²

= 4.4 s

c. The horizontal distance the chunk of hot magma covers is thus x = Vt where v = horizontal velocity = 208 m/s

x = 208 m/s × 4.4 s = 915.2 m

Answer:

that's wrong its 911

Explanation:

trust me

Answer:

The options are not shown, so let's derive the relationship.

For an object that is at a height H above the ground, and is not moving, the potential energy will be:

U = m*g*H

where m is the mass of the object, and g is the gravitational acceleration.

Now, the kinetic energy of an object can be written as:

K = (1/2)*m*v^2

where v is the velocity.

Now, when we drop the object, the potential energy begins to transform into kinetic energy, and by the conservation of the energy, by the moment that H is equal to zero (So the potential energy is zero) all the initial potential energy must now be converted into kinetic energy.

Uinitial = Kfinal.

m*g*H = (1/2)*m*v^2

v^2 = 2*g*H

v = √(2*g*H)

So we expressed the final velocity (the velocity at which the object impacts the ground) in terms of the height, H.

Answer:

False

Explanation:

:)

Answer:

The answer is false

Explanation:

The clouds have nothing to do with the changes in the phases of the moon but, rather the postioning of the sun and the moon regarding revolution and the spinning of the earth on it axis.

I hope this helps you good luck and have a good day.

Answer:

Most likely it will reach 29.4 up in the air before coming back down.

Explanation:

The force of the ball will be the same on how high it will go.

Answer:

Intrusive igneous rocks cool from magma slowly because they are buried beneath the surface, so they have large crystals. Extrusive igneous rocks cool from lava rapidly because they form at the surface, so they have small crystals. Texture reflects how an igneous rock formed

Explanation:

Answer:

2,500 watts

Explanation:

I got this answer right on a test. I hope it works for you to.

Answer:

2500 wats

Explanation:

Surface waves are winds blowing through the  surface of ocean water. Therefore, option B is correct. All other options are just examples of waves and not wind.

Ocean water flows in currents, much like air does in the atmosphere. A current is an oceanic current, or stream, of flowing water. The primary cause of surface currents is wind, although not daily winds.

The main wind belts are what produce surface currents. These winds always blow in the same direction. so that they can maintain the direction of the water's flow.

Three factors influence surface currents: global wind patterns, Earth's rotation, and the configuration of ocean basins. Because they disperse heat over the earth, surface currents are crucial. Global climate is significantly influenced by surface currents as well.

Find more on surface waves:

https://brainly.com/question/13779567

#SPJ5

Answer:

option C

since F=ma

the acceleration of an object depends on the object's mass and the net applied force

Answer:

-100N

Explanation:

Newton's third law of motion states that to every force exerted on one body, there is an equal and opposite force. This means that if object A exerts an ACTION force on B, there is a force called REACTION FORCE, which is equal and opposite, exerted on A by B.

The action and reaction forces are equal in size/magnitude but opposite in direction. In this case where a tennis racket strikes a tennis ball with a force (action force) of 100N, the ball will strike the racket with a reaction force of -100N.

F(RB) = -F(BR)

Answer:

there was 9 but pluto got kicked out of the solar System so 8

Answer:

See the answer below

Explanation:

This is because, at 20 °C, the solution has become saturated with the baking soda.

The solubility of a substance is the maximum amount of that substance that will dissolve in a particular solvent at a given temperature. The solubility of a substance generally increases with an increase in temperature.

At 20 °C temperature, the maximum amount of baking soda that can dissolve in a liter of water has been exceeded by Miguel. Hence, no matter how hard he tries to stir the solution, the excess baking soda will not dissolve.

The reason he can’t get all of the baking soda to dissolve is; because at 20 °C, the solution has become saturated with the baking soda.

For us to say a substance is soluble, it means that the maximum amount of that substance will dissolve in a particular solvent at a given temperature. Thus, the solubility of a substance is said increase with a corresponding increase in temperature.

From the question, at 20 °C temperature, miguel has exceeded the maximum amount of baking soda that can dissolve in a liter of water. Therefore, no matter how hard he tries to stir the solution, it will not dissolve due to the excess soda.

Read more about saturated solution at; https://brainly.com/question/4529762

Answer:

Explanation:

The x component of electric field Ex = k Q / R²

= 9 x 10⁹ x 5 x 10⁻⁹ / .5²

= 180 N .

The y component of electric field Ey = k Q / R²

The y component of electric field Ey

= 9 x 10⁹ x 5 x 10⁻⁹ / 1.5²

= 20 N

Total field = [tex]\sqrt{180^2+20^2}[/tex]

= 181.1 N .

Angle with x axis = Tanθ = Ey / Ex = 20 / 180 = .111

= 6.33⁰

Answer:

a vacuum formed above the column of mercury in a mercury barometer.

Answer:

An air-free space above the free surface of a liquid in a vessel that is closed above the liquid

Answer:

Time in air t = 1.38 second (Approx)

Explanation:

Given:

Initial speed u = 0 m/s

Final speed v = 13.5 m/s

Find:

Time in air t

Computation:

v = u + gt

g = 9.8 m/s²

13.5 = 0 + (9.8)(t)

13.5 = 9.8 t

t = 13.5 / 9.8

t = 1.3777 second

Time in air t = 1.38 second (Approx)

Answer:

it is the same substance because it didn't change the process of that it was it just changed its state for would to liquid

Answer:

one truck load is 2.5*1.5*1 = 3.75m^3

7/3.75 = 1.86 loads,

so 2 trips must be made.

Explanation:

Answer:

The y-component of the ball's velocity is 10 m/s

The second choice 10.0 m/s is correct

Explanation:

Projectile Motion

It's the type of motion that experiences an object that is projected near the Earth's surface and moves along a curved path exclusively under the action of gravity.

Being vo the magnitude of the initial velocity and θ the angle it makes with the horizontal, the components of the initial velocity are calculated as follows:

[tex]v_{ox}=v_o.\cos\theta[/tex]

[tex]v_{oy}=v_o.\sin\theta[/tex]

Since the football is kicked at vo=20 m/s and an angle of θ=30°:

[tex]v_{oy}=20.\sin 30^\circ[/tex]

[tex]v_{oy}=20*0.5=10[/tex]

The y-component of the ball's velocity is 10 m/s

The second choice 10.0 m/s is correct

Answer:

I think balanced

Explanation:

because there is a 2 on each arrow

Answer I'm thinking balanced as well

Explanation:

Answer:

x = 121.86 m

Explanation:

It is given that,

The vertical velocity of a plane, [tex]v_x=18\ m/s[/tex]

It is flying above the target, h = 225 m

First we will find the time taken by the plane to reach the ground. It can be calculated using the second equation of motion as follow :

[tex]h=ut+\dfrac{1}{2}at^2[/tex]

Here, u = 0 and a = g

[tex]h=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2h}{g}} \\\\t=\sqrt{\dfrac{2\times 225}{9.81}} \\\\t=6.77\ s[/tex]

Let x is the horizontal distance from the target. It can be calculated as follows :

[tex]x=v_xt\\\\x=18\times 6.77\\\\x=121.86\ m[/tex]

So, the rescue pilot drop the package at a distance of 121.86 m from the target.