If UV = 4x, VW = 3x, and UW = 7, what is UV?

Answer:

(7÷g)[tex]^{4}[/tex]

Step-by-step explanation:

The quotient is the answer to a division problem.  So the quotient of 7 and g means to divide 7 and g.  Then raise that to the 4th power.

Answer:

umm, 3/4

like

bru

Step-by-step explanation:

Answer:

no solution

Step-by-step explanation:

Given

4 + 7x = 7(x + 1) ← distribute

4 + 7x = 7x + 7 ( subtract 4 from both sides )

7x = 7x + 3 ( subtract 7x from both sides )

0 = 3 ← not possible

This indicates the equation has no solution

Answer: $2800

Step-by-step explanation:

if the function is f(x) and shes already saved $1000 plug in the functions, or in other words plug in x for weeks.

1000 + 150 x

(plug in x)

1000 + 150 x 12

so now you do 150 x 12 which equels 1800

then add how muh shes saved and thats will be your total.

Answer: x= 2, -1

Step-by-step explanation:

Answer:

-3

Step-by-step explanation:

To find:

The value of '?' in the following expression:

[tex]x^2y^8.x^3y^? = x^5y^5[/tex]

Solution:

First of all, let us have a look at a few rules of the exponents:

[tex]1.\ a^b.a^c=a^{b+c}[/tex]

[tex]2.\ a^b.a^{-c}=a^{b-c}[/tex]

Let us apply these rules and try to find out the missing value ('?') in the given expression.

Left Hand Side (LHS):

[tex]x^2y^8.x^3y^?\\\Rightarrow x^2.x^3.y^8.y^?\\\Rightarrow x^{2+3}y^{8+?}\\\Rightarrow x^{5}y^{8+?}[/tex]

Now, let us compare the LHS with RHS, we get:

[tex]x^{5}y^{8+?} = x^{5}y^{5}[/tex]

Dividing with [tex]x^5[/tex] on both sides:

[tex]y^{8+?} = y^5\\\Rightarrow 8+? = 5\\\Rightarrow ? = 5-8 \\\Rightarrow ? =-3[/tex]

Therefore, the missing value in the expression is -3.

Answer:

-3

Rules of the exponents power:

1.  a^b * a^c = a^(b+c)

2. a^b * a^(-c) = a^(b-c)

Applying these rules on Left Hand Side of the expression given:

= x2y8 * x3y?

= x2x3 * y8y?

= x^(2 + 3) * y^(8 + ?)

Right hand side of the expression given:

= x5y5

Comparing the LHS and RHS, we get

x5y^(8 + ?) = x5y5

Dividing with x5 on both sides:

y^(8 + ?) = y5

8 + ? = 5

? = 5 - 8

? = -3

Therefore, the missing value in the expression is -3.

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Answer:

The denominator of [tex] \frac{g}{h} [/tex] is h and Numerator is g.

Answer:

9.77112

Step-by-step explanation:

Given

[tex](9.93).0.984[/tex]

Required

Evaluate

To get the value of the expression, we simply multiply both together as follows; 9.93 * 0.984

First, take note of the decimal places

9.93 = 2 decimal places

0.984 = 3 decimal places

Remove the decimals and multiply the numbers as follows

   9   9   3

   9    8   4

----------------------

       3    9   7     2

   7  9   4   4

8  9  3  7

-----------------------------------

9   7   7   1   1   2

Add the decimal places

2 decimal place + 3 decimal places = 5 decimal places

Hence, the result is 9.77112 (5 decimal places)

It is an equation, telling you that left side of = is same as right side and asking you to solve it (figure out the x).

[tex]x^2=\frac{9}{256}[/tex]

Apply square root on both sides of the equation to get rid of power on x.

[tex]x=\pm\sqrt{\frac{9}{256}}[/tex]

Now simplity the square root.

[tex]x=\pm\frac{\sqrt{9}}{\sqrt{256}}=\boxed{\pm\frac{9}{16}}[/tex]

Hope this helps.

Answer: letter B. -2,-1.5,0

Step-by-step explanation: hope it helps

The order from least to greatest are;

⇒ -2, -2, -2, -2, -1.5, -1.5, -1.5, 0, 0, 0, 0, |-1.5|

Here,

The list of ordered pair are;

−1.5, −2, 0, , −2, −1.5, 0, , |−1.5|, −2, 0, , −2, −1.5, 0, ,

We have to arrange it from least to greatest.

What is Modulus function?

The modulus function give the absolute value of a number irrespective of the number being positive or negative.

Now,

The list of ordered pair are;

−1.5, −2, 0, , −2, −1.5, 0, , |−1.5|, −2, 0, , −2, −1.5, 0.

Since, |-1.5| = 1.5

And, -2 < -1.5

So, The order from least to greatest are;

⇒ -2, -2, -2, -2, -1.5, -1.5, -1.5, 0, 0, 0, 0, |-1.5|

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Answer:

6

Step-by-step explanation:

75 divided by 12.5 equals 6 cups of salsa

Answer:

2, 15

Step-by-step explanation:

LCM= Lowest Common Denominator

4, 30 divided by 2 is the lowest because you cant do 3 because ti wouldn't work for (4) and it wouldn't be 4 because it would make 30 into 7.5 which is not right

so the answer is 2, 15

Answer:

a) 15.5 cm

b) 37.2 cm

Step-by-step explanation:

For part a you would write 4(x+1) because perimeter is adding the sides and all sides of a square are equal. then you would set that equal to 66 and get 4(x+1)=66 and then distribute the 4 and get 4x+4=66 and then subtract the 4 from 66 and get 4x=62. Then you divide 62 by 4 and get 15.5.

For part b you do essentially the same thing but set it equal to 152.8 and get 4(x+1)=152.8 and then distribute the 4 to get 4x+4=152.8 then subtract the 4 and get 148.8 and then divide that by 4 and get 37.2.

Answer:

Step-by-step explanation:

a) Length = (x +1)  cm

Perimeter of square = 66 cm

4 * length = 66

4* (x +1) = 66

Divide both sides by 4

[tex]\frac{4*(x +1)}{4}=\frac{66}{4}[/tex]

x + 1 = 16.5

Subtract 1 from both sides,

x = 16.5 -1

x = 15.5 cm

b) Length = (x +1)  cm

Perimeter of square = 152.8 cm

4 * length = 152.8

4* (x +1) = 152.8

Divide both sides by 4

[tex]\frac{4*(x +1)}{4}=\frac{152.8}{4}[/tex]

x + 1 = 38.2

Subtract 1 from both sides,

x = 38.2 -1

x = 37.2 cm

Answer:

The taller building is the second building which is the apartment building on the left with an height of 58.4m

Step-by-step explanation:

This is a Trigonometric question. We solve this using the Tangent formula

tan θ = Opposite side/Adjacent side

We are given 2 buildings

Building 1

tan θ = Opposite side/Adjacent side

θ = Angle of Elevation = 40°

Distance from the base of the building = Adjacent = 56m

Height of the building = Opposite side = unknown

tan 40 = 0pposite/56m

Opposite = tan 40 × 56m

Opposite = 46.989579346m

Approximately = 47m

Height of Building 1 = 47m

Building 2

tan θ = Opposite side/Adjacent side

θ = Angle of Elevation = 50°

Distance from the base of the building = Adjacent = 49m

Height of the building = Opposite side = unknown

tan 50 = 0pposite/49m

Opposite = tan 50 × 49m

Opposite = 58.395926037m

Approximately = 58.4m

Height of Building 2 = 58.4m

The taller building is the second building which is the apartment building on the left with an height of 58.4m

Answer:

2*2*5*5

Step-by-step explanation:

Answer:

Step-by-step explanation:

mean µ  =  500

standard deviation  σ  =   100

Required P ( X < µ + σ )

=  P ( X < 500 + 100  )

= P ( X < 600 )

= P [Z < (X - µ) / σ  ]

=  P [Z < (600 - 500) / 100  ]

= P [Z < + 1  ]

= .8413

In terms of percent the probability is 84.13 % .

Answer:

C

Step-by-step explanation:

I might be wrong but the best option I see would be C

Here, we are required to identify which part of the sentence is a clause .

The clause in the sentence is "Salim and Anna met when they were in first grade"

First, we must know that a clause is simply defined as a group of words containing a subject and predicate and functions as a part of a complex or compound sentence.

The sentence "Salim and Anna met when they were in first grade, and they have been best friends for 10 years." is a compound sentence.

And, the "Salim and Anna met when they were in first grade" part of the sentence is a clause as it has a subject which is "Salim and Anna" and a predicate which is the rest of the sentence i.e "met when they were in first grade"

The part of the sentence which is a clause is Salim and Anna met when they were in first grade

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Answer: A

Step-by-step explanation:

I got it correct..

Answer:

The least is 9950 and the largest is 10049 people

Step-by-step explanation:

If the number is rounded to the nearest hundred, the smallest number of people that could have attended the parade is 9950 because, rounding up the number 9950 to the nearest hundred would give 10000. If the number 9950 is decreased by 1 (9949), and rounded up to nearest hundred you won't get 10000. Hence the smallest number of people is 9950

While the largest number of people is 10049. 10049 to the nearest hundred  is 10000. A further increase to the number 10049 would give a number greater than 10000 when rounded to nearest hundred.

Answer:

[tex]\Huge \boxed{\mathrm{B.} \ 1+h(x)}[/tex]

[tex]\rule[225]{225}{2}[/tex]

Step-by-step explanation:

The function is odd when f(-x) = -f(x).

1 + h(-x) = 1 + -h(x)

[tex]1 + -(-x)^5 + 12(-x) = 1 + -(-x^5 + 12x)[/tex]

Solving:

[tex]1 + x^5 -12x= 1 + x^5 - 12x[/tex]

[tex]x=x[/tex]

The equation is true.

[tex]\rule[225]{225}{2}[/tex]

Answer:

12* ( 4+5)

Step-by-step explanation:

48 = 12 * 4

60 = 12 * 5

48 + 60 = 12*4 + 12*5

             = 12*( 4 + 5)

            = 12* 9

            = 108

Answer:

The area of the new triangle is 180 m²

Step-by-step explanation:

let the height of the triangle = h

let the base of the triangle = b

The area of right triangle is given by;

A =  ¹/₂bh

20 = ¹/₂bh

If we multiple each side of the triangle by 3, the new area of the triangle will be as follows;

A= ¹/₂(3b)(3h)

A = ¹/₂(9) (bh)

A = 9(¹/₂bh)

A = 9(20)

A = 180 m²

Therefore, the area of the new triangle is 180 m²

Answer: D

Step-by-step explanation:

Answer:

I) how many student are offering both subject , if only 70 students are offering neither biology nor chemistry?

= 160 students

II) how many students are offering at least one biology and chemistry?

= 330 students

Step-by-step explanation:

I) how many student are offering both subject , if only 70 students are offering neither biology nor chemistry?

Total number of student n ( B ∪ C) = 400

Students offering biology n(B) = 300

Students offering chemistry n(C) = 190

Students not offering biology nor chemistry = 70

Students offering both biology and chemistry n ( B ∩ C) = ??

n ( B ∪ C) - Students neither offering biology nor chemistry = n(B ) + n ( C ) - n ( B ∩ C)

400 - 70 = 300 + 190 - n ( B ∩ C)

330 = 490 - n ( B ∩ C)

n ( B ∩ C) = 490 - 330

n ( B ∩ C) = 160

Therefore, students offering both Biology and Chemistry are 160 students.

II) how many students are offering at least one biology and chemistry?

n(B' ) + n ( C') + n ( B ∩ C)

n(B') = Students offering biology only

= n(B) - n ( B ∩ C)

= 300 - 160 = 140

n(C') = Students offering chemistry only

n(C) - n ( B ∩ C)

= 190 - 160

= 30

(300 - 160) + (190 - 160) + 160

140 + 30 + 160

= 330 students

u hav egiven someone discount o f5% total is 580. 580×5÷100=29

580-29=551

Answer:

-4,-1

i have to put 20 character so here is 20 characters

Answer:

( -4, 1 )

Step-by-step explanation:

( 4, 1 ) starts in quadrant 1. ( +, + )

When reflected over the y-axis it moves to quadrant 2. ( -, + )

Answer:

22

Step-by-step explanation:

Given that T is the midpoint of line PQ, PT and TQ are both equal segments of line PQ.

PT is given as 5x + 2,

TQ = 7x - 6

Therefore:

[tex] 5x + 2 = 7x - 6 [/tex]

Solve for x

[tex] 5x + 2 - 7x = 7x - 6 - 7x [/tex]

[tex] -2x + 2 = -6 [/tex]

[tex] -2x + 2 - 2 = -6 - 2 [/tex]

[tex] -2x = -8 [/tex]

[tex] \frac{-2x}{-2} = \frac{-8}{-2} [/tex]

[tex] x = 4 [/tex]

PT = [tex] 5x + 2 [/tex]

Input the value of x

[tex] PT = 5(4) + 2 = 20 + 2 = 22 [/tex]