If (x+2) is a Factor x^3 + 2x^2 + 2x + k then find the value of K.​

Answer:

1 task

Step-by-step explanation:

100%=20 tasks

5%=1 task

[tex]A \cap B=\{10,30\}[/tex]

Answer:

Option A is the correct option

Step-by-step explanation:

[tex] \mathrm{Given}[/tex]

A = { 10 , 30 }

B = { 10 , 20 , 30 , 40 , 50 , 60 , 70 , 80 , 90 }

Now, let's find A ∩ B

A ∩ B = { 10 , 30 } ∩ { 10 , 20 , 30 , 40 , 50 , 60 , 70 , 80 , 90 }

The intersection of sets A and B is the set of all elements which belong to both A and B

A ∩ B = { 10 , 30 }

The intersection of sets A and B is denoted by ( A ∩ B ) and read as A intersection B.

Hope I helped!

Best regards!

Answer:

7+sqrt(37)

Step-by-step explanation:

7+sqrt(6*(3+4)-2+9-3*2^2)=7+sqrt(6*7+7-3*4)=7+sqrt(42+7-12)=7+sqrt(37)

Hi

let's call X amount of second going and Y the height reach by the ballon.

so Y=8X+94

f(x) = 8X+94

If you want to know how high will the ballon be in 25 seconds, remplace X by 25 and do the math. Have fun .

You end up at the point (5, 5).

Answer:

The answer is 72.

I am right .

Answer:

  [tex]\dfrac{3}{(y+2)^3}[/tex]

Step-by-step explanation:

Maybe you want this written using math symbols. It will be ...

  [tex]\boxed{\dfrac{3}{(y+2)^3}}[/tex]

Answer:

[tex]\huge\boxed{f(n)=\left\{\begin{array}{ccc}f(1)=20\\f(n)=f(n-1)-4\end{array}\right}[/tex]

Step-by-step explanation:

[tex]f(n)=20-4(n-1)=20+(n-1)(-4)\\\\\text{It's an explicit formula of an arithmetic sequence:}\\\\f(n)=a_1+(n-1)(d)\\\\a_1-\text{first term}\\d-\text{common difference}\\\\\text{Conclusion:}\\\text{Next term}=\text{previous one}\ -4\\\\\text{The recursive formula:}\\\\\huge\boxed{f(n)=\left\{\begin{array}{ccc}f(1)=20\\f(n)=f(n-1)-4\end{array}\right}[/tex]

Answer:

Step-by-step explanation:

someone answered already

Answer:

66

Step-by-step explanation:

when you plug in 9 for k. you do 6(9) which is 54. then add 12 to 54 and thats ur answer, 66.

Answer:

-29

Step-by-step explanation:

[tex] {\sqrt{7 - y }}^{2} = {6}^{2} [/tex]

[tex]7 - y = {6}^{2} [/tex]

y = 7-36

y = -29

Answer:

Attachment 1 : Option A,

Attachment 2 : Option C

Step-by-step explanation:

( 1 ) Here we know that " n " is 6. Now remember if n is odd, the number of petals on the graph will be n. However if n is even, the number of petals on the graph will be 2n.

6 is even, and hence the number of petals will be 2(6) = 12 petals. Solution : 12 petals

( 2 ) To solve such problems we tend to use the equation [tex]z = x + y * i = r(cos\theta +isin\theta)[/tex] where [tex]r = \sqrt{x^2+y^2}[/tex] etc. Here I find it simpler to see each option, and convert each into it's standard complex form. It might seem hard, but it is easy if you know the value of (cos(5π / 3)) etc...

The answer here will be option c, but let's prove it,

cos(5π / 3) = 1 / 2,

sin(5π / 3) = [tex]-\frac{\sqrt{3}}{2}[/tex]

Plugging those values in for " [tex]8\left(\cos \left(\frac{5\pi }{3}\right)+i\sin \left(\frac{5\pi }{3}\right)\right)[/tex] "

[tex]8\left(-\frac{\sqrt{3}i}{2}+\frac{1}{2}\right)[/tex]

= [tex]8\cdot \frac{1}{2}-8\cdot \frac{\sqrt{3}i}{2}[/tex] = [tex]4-4\sqrt{3}i[/tex]

Hence proved that your solution is option c.

Answer:

Each guest must bring 5 cans.

Step-by-step explanation:

1000-565=435

435/87=5

Answer:

Find answer below

Step-by-step explanation:

f(x)=2x-6

Domain of 2x-6: {solution:-∞<x<∞, interval notation: -∞, ∞}

Range of 2x-6: {solution:-∞<f(x)<∞, interval notation: -∞, ∞}

Parity of 2x-6: Neither even nor odd

Axis interception points of 2x-6: x intercepts : (3, 0) y intercepts (0, -6)

inverse of 2x-6: x/2+6/2

slope of 2x-6: m=2

Plotting : y=2x-6

Answer:

6.22 sec

Step-by-step explanation:

h(t) = 105t-16t^2

For values of t for which height will be 34 feet can be obtained by substituting 34 in place of h(t) and solving for t

34=105t-16t^2, using quadratic formula we have t=1/32*(105±sqrt(8849)) which translates to - 0.34sec and 6.22sec but as time can't be negative, time is 6.22sec

Answer:

Its commutative property..

Step-by-step explanation:

Commutative property says A×B=B×A

Explanation is attached below.

Answer:

160 miles

Step-by-step explanation:

We can use a ratio to solve

220 miles         x miles

--------------- = ----------------------

5.5 hours          4 hours

Using cross products

220 *4 = 5.5x

880 = 5.5x

Divide each side by 5.5

880/5.5 = x

160 miles

Answer:

[tex]\large \boxed{\mathrm{C. \ 160 \ miles}}[/tex]

Step-by-step explanation:

We can solve this problem by ratios.

Let x be the missing value.

[tex]\displaystyle \frac{220}{5.5} =\frac{x}{4}[/tex]

Cross multiply.

[tex]5.5 \times x = 220 \times 4[/tex]

[tex]5.5x=880[/tex]

Divide both sides by 5.5.

[tex]\displaystyle \frac{5.5x}{5.5} =\frac{880}{5.5}[/tex]

[tex]x=160[/tex]

Answer:

2·5·5·5·5

Step-by-step explanation:

2(5)^4 is equivalent to 2·5·5·5·5; 2 is used as a multiplicand just once, but 5 is used four times.

Answer:

AB or the distance across the river is about 171.36 meters.

Step-by-step explanation:

Please refer to the diagram below (not to scale). The area between the two blue lines is the river.

To find AB, we can use the Law of Sines. Recall that:

[tex]\displaystyle \frac{\sin A}{a} = \frac{\sin B}{b} = \frac{\sin C}{c}[/tex]

BC (or a) is opposite to ∠A and AB (or c) is opposite to ∠C. Thus, we will substitute in these values.

First, find ∠A. The interior angles of a triangle must total 180°. Thus:

[tex]m\angle A + m\angle B + m\angle C = 180^\circ[/tex]

Substitute:

[tex]\displaystyle m\angle A + (112.2^\circ) +(18.3^\circ) = 180^\circ[/tex]

Solve for ∠A:

[tex]m\angle A = 49.5^\circ[/tex]

Substitute BC for a, AB for c, 49.5° for A and 18.3° for C into the Law of Sines. Thus:

[tex]\displaystyle \frac{\sin 49.5^\circ}{BC} = \frac{\sin 18.3^\circ}{AB}[/tex]

Since BC = 415 m:

[tex]\displaystyle \frac{\sin 49.5^\circ}{415} = \frac{\sin 18.3^\circ}{AB}[/tex]

Solve for AB. Cross-multiply:

[tex]\displaystyle AB \sin 49.5^\circ = 415\sin 18.3^\circ[/tex]

And divide:

[tex]\displaystyle AB = \frac{415\sin 18.3^\circ}{\sin 49.5^\circ}[/tex]

Use a calculator. Hence:

[tex]AB = 171.3648...\approx 171.36\text{ m}[/tex]

AB or the distance across the river is about 171.36 meters.

Answer: approx 1196 students.

Step-by-step explanation:

As known for normal distribution 95.4% of all results are situating at +-2*s distance from the mean. (s is the standard deviation)

2s=16*2=32 . The mean +2s= 104+32=136 = approx 140.

95.4% from 52000 = 49608 students. The residual amont ( which is out of the border mean+-2s)= 52000-49608=2392

Because of the normal distribution simmetry the number of the students which has IQ 140 and more is twice less than 2392.

N=2392:2=1196

Answer:

Answer:

  18√91 +54√3

Step-by-step explanation:

Name the point at the top of the pyramid "A", the point at the left front corner "B", and the one in the center of the hexagonal base "C". Then right triangle ABC is shown. The "base" BC of that triangle is the same measure as the front edge (6), because the diameter of a regular hexagon is equal to twice the side length.

Using the Pythagorean theorem, we can find the face edge length to be ...

  AB^2 = BC^2 +AC^2

  AB^2 = 6^2 +8^2 = 100

  AB = √100 = 10

If we call the midpoint of the front edge "D", then we need to find the length of AD in order to determine the face area. Again, we can use the Pythagorean theorem.

  AB^2 = BD^2 +AD^2

  AD^2 = AB^2 -BD^2 = 10^2 -3^2 = 91

  AD = √91

The area of one of the 6 lateral faces is ...

  A = (1/2)bh = (1/2)(6)√91 = 3√91

The area of one of the 6 equilateral triangles that make up the base is ...

  A = (√3)/4·s^2 = (√3)/4(6^2) = 9√3

Then the total area of the pyramid is ...

  total area = 6 × (face area + partial base area)

  = 6(3√91 +9√3)

  total area =  18√91 +54√3

Assuming the cube is closed, you can use the divergence theorem:

[tex]\displaystyle\iint_S\vec F\cdot\mathrm dS=\iiint_T\mathrm{div}\vec F\,\mathrm dV[/tex]

where [tex]S[/tex] is the surface of the cube and [tex]T[/tex] is the region bounded by [tex]S[/tex].

We have

[tex]\mathrm{div}\vec F=\dfrac{\partial(y+z)}{\partial x}+\dfrac{\partial(x+z)}{\partial y}+\dfrac{\partial(x+y)}{\partial z}=0[/tex]

so the flux is 0.

Answer:

Question in English please I don't understand your language.

Answer:

85

Step-by-step explanation:

Add  to get total. divide by 4.

Answer:

B. 85

Step-by-step explanation:

Sorry for this very late response. But if anyone wasn't sure if 85 is the correct answer, it is. I can confirm this because I just took the test. I hope I could help! (:

Answer:draw a triangle

Step-by-step explanation:

Answer:

?

Step-by-step explanation

my 4th person to ask a question

Answer:

answer is

In empty set, n(A) = { }.

Using the fundamental counting principle, it is found that: 50 2-scoop combinations are possible.

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The flavors and the toppings are independent, which means that the fundamental counting principle is used to solve this question, which states that if there are p ways to do a thing, and q ways to do another thing, and these two things are independent, there are p*q ways to do both things.

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In this question:

So,

[tex]10 \times 5 = 50[/tex]

50 2-scoop combinations are possible.

A similar question is found at https://brainly.com/question/24067651

Answer:

Step-by-step explanation:

Given the limit of the function [tex]\lim_{(x,y) \to (0,0)} \frac{x^4-34y^2}{x^2+17y^2}[/tex], to find the limit, the following steps must be taken.

Step 1: Substitute the limit at x = 0 and y = 0 into the function

[tex]= \lim_{(x,y) \to (0,0)} \frac{x^4-34y^2}{x^2+17y^2}\\= \frac{0^4-34(0)^2}{0^2+17(0)^2}\\= \frac{0}{0} (indeterminate)[/tex]

Step 2: Substitute y = mx int o the function and simplify

[tex]= \lim_{(x,mx) \to (0,0)} \frac{x^4-34(mx)^2}{x^2+17(mx)^2}\\\\= \lim_{(x,mx) \to (0,0)} \frac{x^4-34m^2x^2}{x^2+17m^2x^2}\\\\\\= \lim_{(x,mx) \to (0,0)} \frac{x^2(x^2-34m^2)}{x^2(1+17m^2)}\\\\\\= \lim_{(x,mx) \to (0,0)} \frac{x^2-34m^2}{1+17m^2}\\[/tex]

[tex]= \frac{0^2-34m^2}{1+17m^2}\\\\= \frac{34m^2}{1+17m^2}\\\\[/tex]

Since there are still variable 'm' in the resulting function, this shows that the limit of the function does not exist, Hence, the function DNE