If y = 3. what is 6y?​

Answers

Answer 1

Your question has been heard loud and clear.

If y = 3 , then 6y = 6(3) = 18

Thank you


Related Questions

If a wind turbine makes 64 full revolutions every 1 minute, what is its angular speed?

Answers

Answer:

this is wind turbine angular speed

Step-by-step explanation:

given data

angular speed ω = 64 rpm

time = 1 min = 60 seconds

                                                                           

solution

we know that angular speed ω is expess as

ω = [tex]\frac{2\pi }{T}[/tex]    .........................1

ω = 64 × [tex]\frac{2\pi }{T}[/tex]

ω  = 6.70 rad/s

so this is wind turbine angular speed

what is 67% of 89.5?

Answers

67% of 89.5 is 59.965.

Answer:

59.96

Step-by-step explanation:

when 67% if 89.5 is expressed in numbers,

[tex]\frac{67}{100}*89.5\\ \frac{5996.5}{100}\\ =59.96[/tex]

Ana must take 11.25 mL of Medicine A daily. She must take 5.5 mL of Medicine B daily. How many more ml of Medicine A than Medicine B must she take
daily?

Answers

Answer:

5.75

Step-by-step explanation:

11.25 - 5.5 = 5.75.

So, Ana must take 5.5 more mL of Medicine A than Medicine B.

Hope this helps!

3 πd=12 π
what does d equal?

Answers

__________

D = 4

__________

i blelieve this is it.

Answer:

d =4

Step-by-step explanation:

[tex]3\pi d = 12 \pi\\\\divide\:both\:sides\:of\:the\:equation\:by\: 3\:\pi\\\frac{3 \pi d}{3\pi} = \frac{12 \pi}{3\pi} \\\\d=4[/tex]

Explain How you got that answer

Answers

Answer:

[tex]\huge\boxed{Center= (-3,4) , Radius = 5\sqrt{2} }[/tex]

Step-by-step explanation:

Given equation is

[tex]x^2 + y^2 + 6x-8y - 25 = 0[/tex]

Adding 25 to both sides

[tex]x^2 + y^2 +6x-8y = 25[/tex]

Completing squares

[tex]x^2 +6x +y^2 - 8y = 25\\(x)^2-2(x)(-3) + (y)^2 - 2(x)(4) = 25[/tex]

Both of their "b" is -3 and 4 respectively

So, adding (-3)² => 9 and (4)² => 16 to both sides

[tex](x+3)^2 + (y-4)^2 = 25 + 9 + 16\\(x+3)^2 + (y-4)^2 = 50\\(x-(-3))^2 + (y-4)^2 = (5\sqrt{2)^2}[/tex]

Comparing it with [tex](x-h)^2+(y-k)^2 = r^2[/tex], where center = (h,k) and radius = r.

We get:

Center = (-3,4)

Radius = [tex]5\sqrt{2}[/tex]

16p - 32q + 5 when p= 2 and q = 1​

Answers

Answer:

0

Step-by-step explanation:

16x2= 32 and 32x1=32 so 32-32=0

How to solve

1) 16(2) - 32(1) + 5

2) 16 x 2 = 32

3) -32 x 1 = -32

4) 32 - 32 + 5 = 5

Answer is 5

Robert has available 400 yards of fencing and wishes to enclose a rectangular area. Express the areaAof the rectangle as a function of the widthwof the rectangle. For what value ofwis the arealargest? What is the maximum area?

Answers

Answer:

A) A = 200w - w²

B) w = 100 yards

C) Max Area = 10000 sq.yards

Step-by-step explanation:

We are told that Robert has available 400 yards of fencing.

A) we want to find the expression of the area in terms of the width "w".

Since width is "w", and perimeter is 400,if we assume that length is l, then we have;

2(l + w) = 400

Divide both sides by 2 gives;

l + w = 200

l = 200 - w

Thus, Area of rectangle can be written as;

A = w(200 - w)

A = 200w - w²

B) To find the value of w for which the area is largest, we will differentiate the expression for the area and equate to zero.

Thus;

dA/dw = 200 - 2w

Equating to zero;

200 - 2w = 0

2w = 200

w = 200/2

w = 100 yards

C) Maximum area will occur at w = 100.

Thus;

A_max = 200(100) - 100(100)

A_max = 10000 sq.yards

Tony ran 1/2 of a mile for 1/4 of an hour. How many miles per hour did he run? A)1.0 B)2.0 C)3.0 D)4.0 E)5.0

Answers

Answer:

2.0

Step-by-step explanation:

Answer:

B. 2.0 miles

Step-by-step explanation:

Tony ran 1/2 of a mile for 1/4 of an hour.

First, to make it easier, change each fraction into decimals:

1/2 = 0.5

1/4 = 0.25

It takes Tony 0.25 hours to run 0.5 miles.

You are solving for 1 hours worth. Multiply 4 to both terms:

0.25 hr x 4 = 1 hr

0.5 miles x 4 = 2.0 miles

B. 2.0 miles is your answer.

~

Solve for w 98 = 7w Simplify your answer as much as possible.

Answers

Answer:

W = 14

Step-by-step explanation:

7w=98

Divide

w=98/7

Done

w=14

Hope this helps! :)

(pls mark brainliest)

Answer:

w = 14

Step-by-step explanation:

98 = 7w

98/7 = 7w/7

14 = w

Hope this helps.

the product of a number and 3 of that number and six is the same as the sum

Answers

The product of a number and 3:

Let's call this number x, so the product of this number and 3 would be 3x.

This product is equal to the sum of the number and six => x+6

Therefore:

3x = x+6
X=3

411,500 science notation

Answers

Answer:

the answer is 4.115 x 10^5

Step-by-step explanation:

hope that helps

algebra 2
50 POINTS
HELP

Answers

Answer:

{-3, 2}U{2, 5}

Step-by-step explanation:

For an equation to be negative, it would need to be in a negative range (below the x-axis or the coordinates are negative y-values). Therefore, we can examine this question and see that the graph is negative when the function crosses the x-axis at -3 and it remains negative until you reach 2 on the x-axis.

Therefore, the first set of negative values is (-3, 2).

Secondly, applying the same logic as before, the function decreases at 2 and then touches the x-axis again at 5. Therefore, the second negative value would be (2, 5).

The negative values are {-3, 2}U{2, 5}.

Answer:

{-3, 2}U{2, 5}

Step-by-step explanation:

Number of times the individual changed jobs in the last 5 years is what kind of variable? A. This variable is a continuous numerical variable that is interval-scaled. B. This variable is a discrete numerical variable that is interval-scaled. C. This variable is a categorical variable that is ordinal-scaled. D. This variable is a discrete numerical variable that is ratio-scaled. E. This variable is a continuous numerical variable that is ratio-scaled. F. This variable is a categorical variable that is nominal-scaled.

Answers

Answer: D. This variable is a discrete numerical variable that is ratio-scaled.

Step-by-step explanation:

A Discrete variables are variables which are countable in a finite amount of time. For example, you can count the amount of money in your bank wallet, but same can’t be said for the money you have deposited in eveyones bank account as this is infinite.

So the number of times an individual changes job in a five years period is a perfect example of  a discrete numerical variable that is ratio scaled because it can be counted.


Solve M= 2HA + 2HT for H.

Answers

Answer:

  H = M/(2A +2T)

Step-by-step explanation:

Factor out H and divide by its coefficient.

  M = 2HA +2HT

  M = H(2A +2T)

  M/(2A +2T) = H

  H = M/(2A +2T)

How do you write 1/46 in simplest form.

Answers

Answer:

1/46 is already in the simplest form.

Answer:

1/46 is already in its simplest form.

evaluate the following -3 - (-8)

Answers

Answer:

The answer to the problem is 5.

Answer:

5

Step-by-step explanation:

[tex]-3-\left(-8\right)\\\\\mathrm{Apply\:rule}\:-\left(-a\right)=a\\=-3+8\\\\\mathrm{Add/Subtract\:the\:numbers:}\:\\-3+8\\=5[/tex]

Simplify and Show all of your work please!

Answers

Answer:

[tex]\Huge \boxed{\mathrm{9}}[/tex]

Step-by-step explanation:

[tex]\Rightarrow \displaystyle \frac{18 \div 2 * 3}{5-2}[/tex]

Dividing first.

[tex]\Rightarrow \displaystyle \frac{9 * 3}{5-2}[/tex]

Multiplying and subtracting.

[tex]\Rightarrow \displaystyle \frac{27}{3}[/tex]

Division.

[tex]\Rightarrow 9[/tex]

To save for her newborn son's college education, Kelli Peterson will invest $1,500.00 at the end of each year for the next 18 years. The interest rate she expects to earn on her investment is 9%. How much money will she have saved by the time her son turns 18?

Answers

Answer:

9% of $1500 is $15 so she gains an extra $15 for each of the 18 years

$1500 in the bank each year for 18 years is $27000 after 18 years

$15 each year as well so that’s an extra $270 in the bank

The total in the bank is the sum of what she has invested and the interest so the total in the bank is $27270

Step-by-step explanation:

Find an equation of the line passing through the point (−3,−7) that is perpendicular to the line y= −5x+4

Answers

Answer:

y = 1/5x - 6.4

Step-by-step explanation:

Perpendicular lines have opposite reciprocal slopes, so the slope will be 1/5

Then, plug the slope and the point into the equation y = mx + b to find b

y = mx + b

-7 = 1/5(-3) + b

-7 = -0.6 + b

-6.4 = b

Then, plug this and the slope into the equation

y = 1/5x - 6.4 will be the equation

What will be the remainder when 6x ^5+ 4x^4 -27x^
3
- 7x² + 27x + 3/2 is divided by (2x^2 - 3)
^2

Answers

Answer:

Remainder = (3145/8)x - 408

Step-by-step explanation:

We want to find the remainder when 6x^(5) + 4x⁴ - 27x³ - 7x² + 27x + 3/2 is divided by (2x² - 3)²

Let's expand (2x² - 3)² to give ;

(2x - 3)(2x - 3) = 4x² - 6x - 6x + 9 = 4x² - 12x + 9

So,we can divide now;

______________________

4x²-12x+9 |6x^(5)+4x⁴-27x³-7x²+27x+3/2

First of all, we'll divide the term with the highest power inside the long division symbol by the term with the highest power outside the division symbol. This will give;

3/2x³

______________________

4x²-12x+9 |6x^(5)+4x⁴-27x³-7x²+27x+3/2

6x^(5)-18x⁴-(27/2)x³

We now subtract the new multiplied term beneath the original one from the original one to get;

3/2x³

______________________

4x²-12x+9 |6x^(5)+4x⁴-27x³-7x²+27x+3/2

6x^(5)-18x⁴-(27/2)x³

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

22x⁴+(27/2)x³+27x +3/2

We'll now divide the term in new polynomial gotten with the highest power by the term with the highest power outside the division symbol. This gives;

(3/2)x³ + (11/2)x²

______________________

4x²-12x+9 |6x^(5)+4x⁴-27x³-7x²+27x+3/2

6x^(5)-18x⁴-(27/2)x³

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

22x⁴+(27/2)x³+27x +3/2

22x⁴-66x³ + (99/2)x²

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

We now subtract the new multiplied term beneath the immediate one from the immediate one to get;

(3/2)x³ + (11/2)x²

______________________

4x²-12x+9 |6x^(5)+4x⁴-27x³-7x²+27x+3/2

6x^(5)-18x⁴-(27/2)x³

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

22x⁴+(27/2)x³-7x²+27x +3/2

22x⁴-66x³ + (99/2)x²

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

(159/2)x³-(113/2)x²+27x+(3/2)

We'll now divide the term in new polynomial gotten with the highest power by the term with the highest power outside the division symbol. This gives;

(3/2)x³ + (11/2)x² + (159/8)x

______________________

4x²-12x+9 |6x^(5)+4x⁴-27x³-7x²+27x+3/2

6x^(5)-18x⁴-(27/2)x³

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

22x⁴+(27/2)x³-7x²+27x +3/2

22x⁴-66x³ + (99/2)x²

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

(159/2)x³-(113/2)x²+27x+(3/2)

(159/2)x³-(477/2)x²+(1431/8)x

We now subtract the new multiplied term beneath the immediate one from the immediate one to get;

(3/2)x³ + (11/2)x² + (159/8)x

______________________

4x²-12x+9 |6x^(5)+4x⁴-27x³-7x²+27x+3/2

6x^(5)-18x⁴-(27/2)x³

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

22x⁴+(27/2)x³-7x²+27x +3/2

22x⁴-66x³ + (99/2)x²

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

(159/2)x³-(113/2)x²+27x+(3/2)

(159/2)x³-(477/2)x²+(1431/8)x

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

182x²-(1215/8)x + (3/2)

We'll now divide the term in new polynomial gotten with the highest power by the term with the highest power outside the division symbol. This gives;

(3/2)x³+(11/2)x²+(159/8)x+(91/2)

______________________

4x²-12x+9 |6x^(5)+4x⁴-27x³-7x²+27x+3/2

6x^(5)-18x⁴-(27/2)x³

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

22x⁴+(27/2)x³-7x²+27x +3/2

22x⁴-66x³ + (99/2)x²

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

(159/2)x³-(113/2)x²+27x+(3/2)

(159/2)x³-(477/2)x²+(1431/8)x

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

182x²-(1215/8)x + (3/2)

182x²-545x + 819/2

We now subtract the new multiplied term beneath the immediate one from the immediate one to get;

182x² - (1215/8)x + (3/2) - 182x² + 545x - 819/2 = (3145/8)x - 408

Remainder = (3145/8)x - 408

Use the Trapezoidal Rule and Simpson's Rule to approximate the value of the definite integral for the value of n. Round the answers to four decimal places and compare the results with the exact value definite integral.
∫9 4 √xdx,n=8.

Answers

Answer and Step-by-step explanation: The Trapezoidal and Simpson's Rules are method to approximate a definite integral.

Trapezoidal Rule evaluates the area under the curve (definition of integral) by dividing the total area into trapezoids.

The formula to calculate is given by:

[tex]\int\limits^a_b {f(x)} \, dx = \frac{b-a}{2n}[f(x_{0})+2f(x_{1})+2f(x_{2})+...+2f(x_{n-1})+f(x_{n})][/tex]

The definite integral will be:

[tex]\int\limits^9_4 {\sqrt{x} } \, dx = \frac{9-4}{2.8}[2+2.\sqrt{5} +2.\sqrt{6} +2.\sqrt{7}+2.\sqrt{8}+3][/tex]

[tex]\int\limits^9_4 {\sqrt{x} } \, dx = \frac{5}{16}[25.3193][/tex]

[tex]\int\limits^9_4 {\sqrt{x} } \, dx = 7.9122[/tex]

Simpson's Rule divides the area under the curve into an even interval number of subintervals, each with equal width.

The formula to calculate is:

[tex]\int\limits^a_b {f(x)} \, dx = \frac{b-a}{3n}[f(x_{0})+4f(x_{1})+2f(x_{2})+...+2f(x_{n-2})+4f(x_{n-1})+f(x_{n})][/tex]

The definite integral will be:

[tex]\int\limits^9_4 {\sqrt{x} } \, dx = \frac{9-4}{3.8}[2+4.\sqrt{5} +2.\sqrt{6} +4.\sqrt{7} +4\sqrt{8} +3][/tex]

[tex]\int\limits^9_4 {\sqrt{x} } \, dx = \frac{5}{24}[40.7398][/tex]

[tex]\int\limits^9_4 {\sqrt{x} } \, dx = 8.4875[/tex]

Calculating the definite integral by using the Fundamental Theorem of Calculus:

[tex]\int\limits^9_4 {\sqrt{x} } \, dx = \int\limits^9_4 {x^{\frac{1}{2} }} \, dx[/tex]

[tex]\int\limits^9_4 {\sqrt{x} } \, dx = \frac{2.\sqrt[]{x^{3}} }{3}[/tex]

[tex]\int\limits^9_4 {\sqrt{x} } \, dx = \frac{2.\sqrt[]{9^{3}} }{3}-\frac{2.\sqrt[]{4^{3}} }{3}[/tex]

[tex]\int\limits^9_4 {\sqrt{x} } \, dx = 12.6667[/tex]

Comparing results, note that Simpson's Rule is closer to the exact value, i.e., gives better approximation to the exactly value calculated by the fundamental theorem.

Round to the nearest cent.
6. $10.407

Answers

Answer:

the answer is 10.41. If you have a number 5 or more you round the nearest number on the left up 1 if it's 4 or less it stays the same it doesn't go up or down.

$10.41 is the correct answer

Find the area of the region that lies inside the first curve and outside the second curve.
r= 10cos( θ)
r= 5

Answers

Answer:

Step-by-step explanation:

From the given information:

r = 10 cos( θ)

r = 5

We are to find the  the area of the region that lies inside the first curve and outside the second curve.

The first thing we need to do is to determine the intersection of the points in these two curves.

To do that :

let equate the two parameters together

So;

10 cos( θ) = 5

cos( θ) = [tex]\dfrac{1}{2}[/tex]

[tex]\theta = -\dfrac{\pi}{3}, \ \ \dfrac{\pi}{3}[/tex]

Now, the area of the  region that lies inside the first curve and outside the second curve can be determined by finding the integral . i.e

[tex]A = \dfrac{1}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} (10 \ cos \ \theta)^2 d \theta - \dfrac{1}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \ \ 5^2 d \theta[/tex]

[tex]A = \dfrac{1}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} 100 \ cos^2 \ \theta d \theta - \dfrac{25}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \ \ d \theta[/tex]

[tex]A = 50 \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \begin {pmatrix} \dfrac{cos \ 2 \theta +1}{2} \end {pmatrix} \ \ d \theta - \dfrac{25}{2} \begin {bmatrix} \theta \end {bmatrix}^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}}[/tex]

[tex]A =\dfrac{ 50}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \begin {pmatrix} {cos \ 2 \theta +1} \end {pmatrix} \ \ d \theta - \dfrac{25}{2} \begin {bmatrix} \dfrac{\pi}{3} - (- \dfrac{\pi}{3} )\end {bmatrix}[/tex]

[tex]A =25 \begin {bmatrix} \dfrac{sin2 \theta }{2} + \theta \end {bmatrix}^{\dfrac{\pi}{3}}_{\dfrac{\pi}{3}} \ \ - \dfrac{25}{2} \begin {bmatrix} \dfrac{2 \pi}{3} \end {bmatrix}[/tex]

[tex]A =25 \begin {bmatrix} \dfrac{sin (\dfrac{2 \pi}{3} )}{2}+\dfrac{\pi}{3} - \dfrac{ sin (\dfrac{-2\pi}{3}) }{2}-(-\dfrac{\pi}{3}) \end {bmatrix} - \dfrac{25 \pi}{3}[/tex]

[tex]A = 25 \begin{bmatrix} \dfrac{\dfrac{\sqrt{3}}{2} }{2} +\dfrac{\pi}{3} + \dfrac{\dfrac{\sqrt{3}}{2} }{2} + \dfrac{\pi}{3} \end {bmatrix}- \dfrac{ 25 \pi}{3}[/tex]

[tex]A = 25 \begin{bmatrix} \dfrac{\sqrt{3}}{2 } +\dfrac{2 \pi}{3} \end {bmatrix}- \dfrac{ 25 \pi}{3}[/tex]

[tex]A = \dfrac{25 \sqrt{3}}{2 } +\dfrac{25 \pi}{3}[/tex]

The diagrammatic expression showing the area of the region that lies inside the first curve and outside the second curve can be seen in the attached file below.

Solve the problem. A variable x has the possible observations shown below. Possible observations of x: -3 -1 0 1 1 2 4 4 5 Find the z-score corresponding to an observed value of x of 2.

Answers

Answer:

The z-score corresponding to an observed value of x of 2 is 0.215.

Step-by-step explanation:

We are given that a variable x has the possible observations shown below;

Possible observations of X: -3, -1, 0, 1, 1, 2, 4, 4, 5.

Firstly, we will find the mean and the standard deviation of X, i.e;

Mean of X, ([tex]\mu[/tex]) = [tex]\frac{\sum X}{n}[/tex]

                       =  [tex]\frac{(-3)+ (-1)+ 0+ 1+ 1+ 2+ 4+ 4+ 5}{9}[/tex]  

                       =  [tex]\frac{13}{9}[/tex]  = 1.44

Standard deviation of X, ([tex]\sigma[/tex]) =  [tex]\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }[/tex]

                            =  [tex]\sqrt{\frac{(-3-1.44)^{2}+(-1-1.44)^{2}+......+(4-1.44)^{2}+(5-1.44)^{2} }{9-1} }[/tex]

                            =  2.603

Now, the z-score corresponding to an observed value of x of 2 is given by;

                  z-score =  [tex]\frac{X-\mu}{\sigma}[/tex]

                               =  [tex]\frac{2-1.44}{2.603}[/tex]  = 0.215.        

the perimeter of a rectangle is 12cm. If the length is 2 less than 3 times the width, find the length

Answers

Answer:

The length of the rectangle would be 4.

Step-by-step explanation:

We can start by naming the width x.

Therefore, the length would 3x-2.

The perimeter of the rectangle would then be:

2(3x-2+x)

We can set up the given equation

2(3x-2+x)=12

Solve for x.

Divide both sides by 2.

3x-2+x=6

Combine like terms.

4x-2=6

Add 2 to both sides.

4x=8

Divide both sides by 4.

x=2

The width would then be 2.

We can plug that into the expression for length.

3x-2

3(2)-2

6-2

4

The length of the rectangle would be 4.

What is mAngleRST in degrees?

Answers

Answer:

The measure of angle RST = 120°

Step-by-step explanation:

Answer:

The measure of angle RST = 120°

hope this helps

Which x values is the graph below discontinuous

Answers

For any value of X where there’s a jumb is discontinues. -3,-1,1,3

Answer:

-3,-1,1,3,5

Step-by-step explanation:

Now change matrix B to a 3 x 3 matrix and enter
these values for B:
B=
1.2 1.4 3.1
2.2 1.1 5.6
3.7 4.2 6.7

Answers

The 3×3 Matrix is  [tex]B=\left[\begin{array}{ccc}1.2&1.4&3.1\\2.2&1.1&5.6\\3.7&4.2&6.7\end{array}\right][/tex]

What is Matrix?

In mathematics, a matrix is a rectangular array or table of numbers, symbols, or expressions, arranged in rows and columns, which is used to represent a mathematical object or a property of such an object

What is 3×3 Matrix?

A 3 x 3 matrix is calculated for a matrix having 3 rows and 3 columns

Given,

B=

1.2 1.4 3.1

2.2 1.1 5.6

3.7 4.2 6.7

Then the 3×3 matrix is

[tex]B=\left[\begin{array}{ccc}1.2&1.4&3.1\\2.2&1.1&5.6\\3.7&4.2&6.7\end{array}\right][/tex]

Hence, The 3×3 Matrix is [tex]B=\left[\begin{array}{ccc}1.2&1.4&3.1\\2.2&1.1&5.6\\3.7&4.2&6.7\end{array}\right][/tex]

Learn more about Matrix and 3×3 Matrix here

https://brainly.com/question/12759849

#SPJ2

Answer:

Step-by-step explanation:

c11 =

⇒ 56.1  

c12 =

⇒ 12.1

c13 =

⇒ 236

Find the equation of the line perpendicular to y=2x-6 that passes through the point (1,5). If possible, write the equation in slope-intercept form.

Answers

Answer:

[tex]y=-0.5x+4.5[/tex]

Step-by-step explanation:

The slope of [tex]y=2x-6[/tex] is:

[tex]2[/tex]

The negative reciprocal of that slope is:

[tex]m=-\frac{1}{2}[/tex]

So the perpendicular line will have a slope of [tex]-1/2[/tex]:

[tex]y - y_1 = (-\frac{1}{2} )(x - x_1)[/tex]

And now put in the point [tex](1,5)[/tex]:

[tex]y-5=(-\frac{1}{2})(x-1)[/tex]

And that answer is OK, but let's also put it in [tex]y=mx+b[/tex] form:

[tex]y-5=-\frac{x}{2}+\frac{1}{2}[/tex][tex]y=-\frac{x}{2}+\frac{11}{2}[/tex][tex]y=-0.5x+4.5[/tex]

please help ive been stuck on this for a very long time

Answers

It’s A because 3x+1 is = 3 x 2 = 5

By Thales' theorem:

[tex]\[\begin{array}{l}\frac{{18}}{{2x + 2}} = \frac{{24}}{{3x + 1}}\\18(3x + 1) = 24(2x + 2)\\54x + 18 = 48x + 48\\6x = 30\\x = 5\\A.\end{array}\][/tex]

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