In humans, a type of blindness is due to a dominant allele (B). Normal vision is the result of a
recessive allele (b). Migraine headaches are due to a dominant allele (M), and normal (no migraines)
is recessive (m).
A male who is heterozygous for blindness and does not suffer from migraines marries a woman who
has normal vision and does not suffer from migraines.
Could they produce a child with normal vision who does not suffer from headaches? If yes, can the
probability of such a child be determined?
You must draw a Punnett square within the space provided to receive any credit for your answer!
Answers
Answer:
Yes, a child with normal vision who does not suffer from headaches can be produced.
The probability of producing such child from this cross is 1/2 or 50%
Explanation:
This question involves two distinct genes in humans. One coding for blindness and the other for Migraine headaches. The alleles for blindness (B) and Migraine (M) are dominant over the alleles for normal vision (b) and no Migraine (m).
According to the question, a male who is heterozygous for blindness and does not suffer from migraines will have the genotype; Bbmm while a female who
has normal vision and does not suffer from migraines will have genotype; bbmm. If these two parents are crossed, the following genotypes of gametes will be produced by each parent:
Bbmm- Bm, Bm, bm and bm
bbmm- bm, bm, bm, and bm
Using these gametes to construct a punnet square (see attached image), the following offsprings with genotypes; Bbmm and bbmm in the ratio 1:1 will be produced.
Bbmm (8/16) are offsprings with blindness and have no Migraine headache
bbmm (8/16) are offsprings with normal vision and have no migraine headache
Hence, this cross can produce a child with normal vision who does not suffer from headaches (bbmm). Also, the probability of producing such child is 8/16 or 1/2.
Related Questions
HELP PLEASE FAST ASAP PLEASE HELP
Answers
Answer:
D. Their ability to replicate very fast and natural mutations combine to allow them to evolve rapidly
Explanation:
They develop mutations in their DNA that can be resistant to the drugs given.
A decrease in muscular activity or damage to neurons that attach to skeletal muscle can lead to a reduction in the size of muscle called
Answers
Answer:
The correct answer is atrophy
Biochemical and genetic experiments have demonstrated that the _________ of tRNA are important for recognition by its cognate aminotransferase-tRNA synthetase.
Answers
Answer: Acceptor stem and anticodon loop.
Explanation:
Transfer RNA (tRNA) is a small RNA nucleic acid involved in protein synthesis (translation). Each tRNA molecule has two important areas:
A region of trinucleotides, called the anticodon A region where a specific amino acid binds.During translation, the ribosome reads the sequence of the mRNA in groups of three bases to assemble the protein. So, in the mRNA chain there are codons, set of three bases, which determine the amino acid to be added to the peptide chain. The tRNA transfers the amino acid to the ribosomes, and then arranges them along the messenger RNA (mRNA) molecule. Then, the tRNA must have an anticodon that is complementary to the codon. Each type of tRNA is specifically combined with 1 of the 20 amino acids to be incorporated into proteins.
This means, during translation, each time an amino acid is added to the growing chain, a tRNA molecule is formed whose base pairs have a complementary sequence with mRNA molecule, ensuring that the appropriate amino acid is inserted into the protein. So, tRNA is a key link between RNA transcription and the translation of that RNA into protein. On the other hand, aminotransferases are enzymes responsible for attaching amino acids to the 3ʹ‐end of cognate tRNAs.
The acceptor stem is the site of attachment of amino acids to tRNA, and anticodon loop is the site of tRNA that is complementary to the codons found in mRNA (that determine the amino acid that will be added) This means, both parts are important for recognition, because the acceptor stem is where the amino acid is, and the anticodon loop ensures that the appropriate amino acid is inserted into the protein.
I need help, please!!
Answers
Answer:
Aerobic respiration ; Respiration using oxygen
Mitochondria ; Where respiration takes place
Anaerobic respiration ; Respiration in the absence of oxygen
Lactic acid ; Substance that build up in the muscles during anaerobic respiration .
Fermentation ; Process that converts sugar into alcohol
Explanation:
I hope it helps :)
Answer:
aerobic respiration - resperation using oxygen
mitochondria - where resperation takes place
anaerobic respiration - resperation in the absence of oxygen
lactic acid - substance that builds up in muscles during anerobic resperation
fermentation - process that converts sugar into alcohol
as Ethanol fermentation is also known as alcoholic fermentation
( hope I helped you ) :)
Tissue found in leaf stalks below the epidermis is________.
Answers
Explaination
Collenchyma is the tissue found below the epidermis of a leaf stalk. These are simple permanent tissue, perform photosynthesis when chloroplast is present.
Collenchyma tissue is composed by elongated living cells of uneven primary thick walls, which possess hemicellulose, cellulose, and pectic materials. It provides support, structure, mechanical strength, and flexibility to the petiole, leaf veins, and stem of young plants, allowing for easy bending without breakage.
What are the features of Nuclear Receptor Screening Services?
Nuclear receptors (NRs) are a class of proteins responsible for thyroid hormones and sensing steroid and certain other molecules. There are 48 genes in the human genome that code for the NRs. As the largest family of eukaryotic transcription factors, NRs control numerous processes involved in development, cell cycle, and important metabolic pathways.
https://dda.creative-bioarray.com/nuclear-receptor-screening.html
Answers
Answer:
The nuclear receptor superfamily comprises a large group of transcription factors that play a key regulatory role in development and homeostasis of multicellular organisms. A special feature of nuclear receptors is their ability to bind to condensed chromatin templates, which makes them important initiators of gene transcription. Moreover, the ability of nuclear receptors to sequentially recruit a variety of transcription factors and coregulators to target promoters and to orchestrate the whole process of gene transcription confirms their biological significance and stimulates intensive research and a high level of scientific interest in this field. In this review, we summarise current knowledge regarding the structure and function of nuclear receptors as principal regulators of gene expression. Emphasis is given to the molecular mechanisms of nuclear receptor-mediated transcriptional activation and repression including recent progress made in this area.
Which of the following describes the most likely impact that exposure to pollutants in the atmosphere would have on one’s personal health?
Answers
Answer:
It will lead to upper respiratory infections and pneumonia.
Explanation:
Which of the circumstances below most accurately describes conditions that are likely to permit a robust anti-tumor adaptive immune response?
a. A tumor with high expression of proteins that have mutations in sequences encoding HLA-binding peptides.
b. A robust acute inflammatory response to PAMPs expressed specifically by tumor cells.
c. Anti-tumor T lymphocytes that have high expression of CTLA-4.
d. A tumor with high expression of PD-L1.
Answers
Did you ever figure out the answer to this question?
The study of PAMP-DAMP complexes is vital to the advancement of knowledge regarding inflammatory disorders in general and cancer in particular. Therefore, option (B) is correct.
What is PAMP-DAMP complexes?Increasing evidence links inflammation to cancer, and at the root of inflammation are PAMPs and DAMPs (DAMPs). Microorganisms contain PAMPs, which are detected by pattern recognition receptors on monocytes and DCs (PRRs). PRR activation produces pro-inflammatory cytokines.
A robust immune response requires endogenous chemicals that pose 'risk' to self-tissues and are created by injured or stressed cells; these are DAMPs, which also trigger inflammation. PAMPs and DAMPs each have about 100 receptors. PAMPs and DAMPs interact; a PRR can bind to both. In this system, PAMPs and DAMPs affect each other's activation threshold. Thus, PAMP-DAMP relationships describe inflammation in a predictable 'inflammatory code'
PAMP-DAMP complexes are key to understanding inflammatory disorders and cancer.
Learn more about adaptive immune response, here:
https://brainly.com/question/28073370
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Nucleus is where dna is stored and where rna transcription occurs
Answers
Answer:
Yes that is correct
Explanation:
The best fossil evidence to suggest that Neandertals could produce a language like that of modern humans comes from which bone(s) collected at Kebara, Israel?
a. the hyoid
b. the mandible
c. the cervical(neck) vertebrae
d. the ribs
Answers
Answer:
The answer is A.
Explanation:
The best fossil evidence that suggests Neandertals' ability to produce a language like modern humans comes from the hyoid bone.
This bone is located in the neck between the chin and the thyroid, which is also named "tongue bone" or "language bone".
So the correct answer is A.
I hope this answer helps.
"Acidic" is an appropriate description for four of the following. Which one is the exception?
Answers
Answer:
magnesium hydroxide
Explanation:
is the inorganic compound with the chemical formulaMg( OH)2.it is a common component of antacid such as milk of magnesia
A 23 year old female presents with bilateral loss of central vision. You obtain a detailed family history and produced the associated pedigree. Which of the following transmission patterns is most consistent with this patient's family history?
a. Autosomal dominant
b. Autosomal recessive
c. X-linked dominant
d. X-linked recessive
e. Mitochondrial
Answers
Answer:
e. Mitochondrial
Explanation:
This is a case of mitochondrial heredity so correct answer is e. Mitochondrial In this case, the mother transfers her mitochondria to her children. So the child is affected. The male does not pass this trait on to his children. We can see from the lineage that the mother has defective mitochondria so all their children will have defective mitochondria. One of his sons has mitochondrial, but is unable to pass it on to the next generation.In this diagram of a long bone, which type of bone marking is circled? anatomical drawing of a long bone showing the internal structure, with the point where the blood vessels enter circled
Answers
Answer:
the answer is osteon
Explanation:
The diagram represents a food pyramid. The concentration of the pesticide DDT in individual
organisms at level D is higher than the concentration in individuals at level A because DDT is
A. produced by organisms at level C ingested by
those in level D
B. passed through levels A, B, and C to organisms
at level D.
C. excreted by organisms at level A as a toxic
waste.
D. synthesized by organisms at level D.
Answers
Answer:
The answer is "Choice b".
Explanation:
In the given question diagram is missing. so first, we define the diagram after that we explain why the above given choice is correct.
In the attached file the food pyramid can be a divide into the level, in which the D pesticides use the "dichloro-diphenyl-trichloroethane ", which concentration is higher than its entities from the level of A because DDT is transferred with species at level D by levels A, B, and C, that's why the choice "b" is correct.
Role of mitosis in plant growth and development
Answers
Answer:
The mitosis cell division helps in vegetative growth in plants. It also helps in healing of wounds
You continue this approach by designing two separate experiments. In the first experiment, you use glucose where "Coccupies position 1. In the second experiments, 14C occupies position 2 and 6 in the glucose molecules. For each experiment, you use 0.2 moles of radiolabeled glucose and you assume that all the pyruvate formed is converted to acetyl-CoA. What following statements are correct? (select 3)
a) When glucose is labeled on carbon #1, 0.2 mole of acetyl-CoA is radiolabeled
b) When glucose is labeled on carbon #1, 0.1 mole of acetyl-CoA is radiolabeled
c) When glucose is labeled on carbons #2 and #6, 0.2 mole of acetyl-CoA is radiolabeled
d) When glucose is labeled on carbons #2 and 6, 0.1 mole of acetyl-CoA is radiolabeled
e) When glucose is labeled on carbons #2 and 6, the carbonyl groups of half of the acetyl-CoA molecules are radiolabeled
f) When glucose is labeled on carbons #2 and 6, the methyl groups of half of the acetyl-CoA molecules are radiolabeled
Answers
Answer:
b) When glucose is labeled on carbon #1, 0.1 mole of acetyl-CoA is radiolabeled
c) When glucose is labeled on carbons #2 and #6, 0.2 mole of acetyl-CoA is radiolabeled
e) When glucose is labeled on carbons #2 and 6, the carbonyl groups of half of the acetyl-CoA molecules are radiolabeled
f) When glucose is labeled on carbons #2 and 6, the methyl groups of half of the acetyl-CoA molecules are radiolabeled
Explanation:
When glucose undergoes glycolysis, it is converted into two molecules of pyruvate with carbon 1 to 3 forming the first molecule of pyruvate and carbon 4 to 6 the second molecule of pyruvate. The C-1 and C-6 of the glucose molecule becomes the methyl groups of each of the two molecules of pyruvate. The C-2 and C-5 of the glucose molecule forms the carbonyl carbon of each of the two pyruvate molecules. Each of the two pyruvate molecules undergoes further oxidation to yield acetyl-CoA with the carbonyl and methyl groups of pyruvate retained in the acetyl-CoA molecules.
Thus when 0.2 moles of glucose are labelled at C-1 and then C-2 and C-6 in each of the two experiments the following results are obtained:
When glucose is labeled on carbon-1, 0.1 mole of acetyl-CoA is radiolabeled since half of the two pyruvate molecules are obtained from C-1
When glucose is labeled on carbon-2 and carbon-6, 0.2 mole of acetyl-CoA is radiolabeled since the C-2 and C-6 of the glucose molecules forms a part of one of each of the two pyruvate molecules.
When glucose is labeled on carbons #2 and 6, the carbonyl groups of half of the acetyl-CoA molecules are radiolabeled since one of the two carbonyl groups of the two pyruvate molecules is formed from C-2 of glucose.
When glucose is labeled on carbon-2 and carbon-6, the methyl groups of half of the acetyl-CoA molecules are radiolabeled since one of the two methyl groups of the two pyruvate molecules is formed from C-6 of glucose.
What are the four main components of soil?
A. Water
B. Sediment
C. Air
D. Humus
E. Bedrock
Answers
Answer:
The four (4) components of soil are;
WaterAirMineralsorganic(06.03 LC) Which of the following is an example of how HIV can be transmitted from one person to another? Contact between infected blood and a mucus membrane Contact between infected saliva and an open wound Contact between infected blood and skin Contact between infected saliva and lining of mouth
Answers
Answer:
i believe the answer is contact between a infected blood and a mucus membrane
Explanation:
explain the scientific theory of evolution and the evidence scientist found that proves it to be valid ?
Answers
Answer:
There are many theories
But main evidences are
Fossils of Plants animals and other organisms who lived on this planet at sometime. Oprain And Halden theory which suggests the chemical and biological evolution.In which of the following ways is DNA replication different from DNA transcription?
Answers
Answer:
Thymine is used in replication while uracil is used in transcription.
Explanation:
New cells can only be created after transcription has taken place. Replication results in mRNA strands while transcription creates new DNA. Transcription happens outside the nucleus and replication happens inside the nucleus. Thymine is used in replication while uracil is used in transcription.
DNA replication is a process whereby DNA makes a copy of itself while DNA transcription is a process whereby a messenger RNA is synthesized from a DNA strand.
Both processes involve the building-up of nucleotides or purine.pyrimidine bases. Replication involves building up of cytosine, guanines, adenine, and thymine bases while in transcription, the thymine base is replaced by uracil base.
Hence, the correct answer is that Thymine is used in replication while uracil is used in transcription.
Fermentation converts organic material into a fuel whose primary component is
A. methane
B. sugar
C. yeast
D. alcohol
Answers
Answer:
D. alcohol
Explanation:
Fermentation by microorganisms converts organic materials into alcohol
Note the mechanism of absorption (passive or active transport) of the following food breakdown products, and indicate by a check mark whether the absorption would result in their movement into the blood capillaries of the lymphatic capillaries (lacteals).
Substance Mechanism of absorption Blood Lymph
Monosaccharides
Fatty acids and glycerol
Amino acids
Water
Ca2+ , Na+ , Ca2+
Answers
Answer:
The absorption of monosaccharides takes place via facilitated and cotransport mechanism and is transported through blood capillaries present in the villi.
The absorption of glycerol and fatty acids takes place through diffusion and the majority of them are transported via lymph capillaries, while some are transported through blood capillaries.
The absorption of amino acids takes place via a cotransport mechanism with sodium ions and is transported through blood capillaries.
The absorption of water takes place by the process of osmosis via diffusion and is transported with the help of blood capillaries.
The absorption of calcium and sodium ions takes place via an active transport mechanism, while the absorption of chlorine takes place via the process of diffusion. The transportation of all these ions takes place with the help of blood capillaries.
While not an official step in the process, Acetyl CoA formation is a transition between glycolysis and krebs, and occurs only in the presence of oxygen.
A. True
B. False
Answers
Answer:
A. True
Explanation:
Acetyl coA is a compound which helps in the transport and availability of the acetyl group to the citric acid cycle (Krebs cycle).
Though it is not an official step in the process, Acetyl CoA formation is a transition between glycolysis and krebs, and occurs only in the presence of oxygen.
The Acetyl group helps in the oxidation for energy production.
Can somebody help me
Answers
Answer:
No they should not, heres why:
Explanation:
It has been proven on countless occasions that people forget details within minutes of an event. When you forget things, and you try to remeber, your brain will fill in the blanks with what it wants to see. In every case, if possible try to use hard evidence, ie: Videos, recordings, fingerprints, blood, and other stuff. If not that try to use multiple witness accounts and compare them.
The valve present between right atrium and ventricle is
Answers
Circle
1
2
Circle the most reactive metal in each set.
1) Magnesium / Potassium
2) Aluminum / Gold
3) Cobalt / Cesium / Calcium
4) Iron / Titanium / Potassium
5) Francium / Lithium / Beryllium
لی
Answers
Answer:
Explanation:
1) potassium
2)Aluminium
3) Cesium
4) potassium
5) Beryllium
what is haemopoiesis??
Answers
Haemopoiesis is from greek meaning “ to make. new blood” •
Explanation:
It refers to the formation of blood cellular. components.
Which statement best describes a hypothesis?
Answers
Answer:
A hypothesis is an idea or explanation you can test through study and experimentation.
Explanation:
Identify the organelle where photosynthesis takes place.
B
C
D
E
Answers
Answer:
E
Explanation:
If E is the Chloroplasts, where photosynthesis takes place, then the answer is E.
Answer:
E
Explanation:
g why did you digest the plasmid with XhoI? What is your expectation if the plasmid is a closed vector without an insert? What is your expectation if your plasmid has an insert (how many bands, what are their sizes)?
Answers
Answer:
I digest the plasmid with Xholin so as to find out the total size of the plasmid after insertion of the gene of interest and whether or not the insert went into the vector. Ao the plasmid is a reclosed vector without an put we expect to see one band. However, if the plasmid has an insert, we expect to see two bands on the gel