In the drawing, what is the vector sum of forces A→+B→+C→ if each grid square is 7.00 N on a side? If the resultant is eastward, enter a positive value and if the resultant is westward, enter a negative value.

Answer:

35.11 m/s

Explanation:

While flying due east at 33 meters/second, an airplane is also being carried due north at 12 meters/second by the wind, then the plane’s resultant velocity would be 35.11 meters/second.

The total displacement covered by any object per unit of time is known as velocity.

the mathematical expression for velocity is given by

velocity = total displacement /total time

As given in the problem , while flying due east at 33 m/s, an airplane is also being carried due north at 12 m/s by the wind and we have to find the resultant velocity of the plane,

Resultant velocity = √( 33² + 12²)

                              = 35.11 meters/second

Thus, the plane’s resultant velocity would be 35.11 meters/second

Learn more about Velocity here, refer to the link;

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Answer:

The mmf required is [tex]1.125[/tex]×[tex]10^{-3}[/tex] A

Explanation:

The Magnetomotive force (mmf) is given by the formula below

[tex]F_{M} = Hl\\[/tex]

where [tex]F_{M}[/tex] is the Magnetomotive force (mmf)

[tex]H[/tex] is the Magnetic field strength

[tex]l[/tex] is the magnetic length

The magnetic permeability μ is given by

μ = [tex]B / H[/tex]

Where [tex]B[/tex] is the Magnetic flux density

and [tex]H[/tex] is the Magnetic field strength

From the question,

[tex]B[/tex] = 1.2Wb/m^2

μ = 1600m

From μ = [tex]B / H[/tex]

∴[tex]H = B/[/tex]μ

[tex]H = 1.2 / 1600\\[/tex]

[tex]H = 7.5[/tex] × [tex]10^{-4}[/tex]A/m

Now, for the Magnetomotive force (mmf)

[tex]F_{M} = Hl\\[/tex]

From the question

[tex]l[/tex] = 1.5 m

∴ [tex]F_{M} = 7.5[/tex]×[tex]10^{-4}[/tex] × [tex]1.5[/tex]

[tex]F_{M} = 1.125[/tex]×[tex]10^{-3} A[/tex]

Hence, The mmf required is [tex]1.125[/tex]×[tex]10^{-3}[/tex] A

Answer:

The constant of proportionality between charge and voltage is the capacitance.

Explanation:

The capacitance ([tex]C[/tex]), measured in farads, is the ratio of charge to voltage, that is:

[tex]C = \frac{Q}{V}[/tex]

Where:

[tex]Q[/tex] - Charge, measured in coulombs.

[tex]V[/tex] - Voltage, measured in volts.

If charge is clear, it is easy to concluded that capacitante is a constant of direct proportionality.

Hence, the correct answer is B.

Answer:

An example of operational definition of the term weight of an object, operationalized to a degree, would be the following: "weight is the numbers that appear when that object is placed on a weighing scale"

Answer:

A) J= 398 A/m²

B) E= 1.6×10⁶ N/C

C) P= ×10⁴ W

Explanation:

My work is in the attachment. Comment with questions or if something seems wrong with my work. (Honestly, they seem little high but it could just be the given numbers being unrealistic.) Below I have explanations of each part to match up with the image as well.

Part A:

Current density (J) is defined as the amount of current in a particular cross-sectional area. To get this, we simply need to divide the current (I) by the cross-sectional area of the electron beam tube (A).

Part B:

This one took the most work for me. I used a kinematic equation (yes they apply to electrons) to find the electric field (E). I used a modified form of the familiar: ∆d=V₀τ+aτ²/2

We can use the fact that τ= V/a, a=(qE/m), and V₀=0 here to rewrite the equation in terms of values we know and/or can look up. From there we solve for E and plug in the values.

Part C:

Power (P) is simply work (W) over time (τ). We know what τ is from before and can take W= mV²/2. Plugging these in and reducing some values gives us an equation for power as well.

Answer:

The distance of the cat will appear farther than it really is

Explanation:

The index of refraction of water is more than that of air. Light rays from the cat  are refracted towards the normal at the surface and diverge outwards. This extends the virtual position of the cat, putting in a place farther than it really is.

Complete Question

Calculate the average volume per molecule for an ideal gas at room temperature and atmospheric pressure. Then take the cube root to get an estimate of the average distance between molecules. How does this distance compare to the size of a molecule like [tex]N_2[/tex]?

Answer:

The  average volume per molecule is  

   [tex]\frac{V}{N} = 4.09 *10^{-26} \ m^3/molecule[/tex]

 The average distance between molecules

  [tex]d = 3.45 *10^{-9} \ m[/tex]

The size of  [tex]N_2[/tex] is 100 times smaller than the obtained value  

Explanation:

From the question we can deduce that we are considering an ideal

Generally the ideal gas equation is mathematically represented as

       [tex]PV = NkT[/tex]

Here  T  is the room temperature with value  T  =  300  \ K  

     k is the Boltzmann constant with value  [tex]k = 1.38 *10^{-23} \ J/K[/tex]  

      P  is the atmospheric pressure with value  [tex]P = 1.0 *10^{5} \ N/m^2[/tex]

     N is the number of molecules

Now  the  volume per molecule is mathematically deduced from the above equation as

        [tex]\frac{V}{N} = \frac{kT}{P}[/tex]

=>      [tex]\frac{V}{N} = \frac{ 1.381 *10^{-23} * 300}{ 1.0*10^{5}}[/tex]

=>      [tex]\frac{V}{N} = 4.09 *10^{-26} \ m^3/molecule[/tex]

Now the distance is mathematically evaluated as

      [tex]d = \sqrt{\frac{V}{N} }[/tex]

=>    [tex]d = \sqrt[3]{4.09*10^{-26}}[/tex]

=>     [tex]d = 3.45 *10^{-9} \ m[/tex]

Generally the size of  [tex]N_2[/tex]  is  115 pm which is  100 times smaller  than the  obtained value  

  Generally the size of  [tex]H_2O[/tex] is  [tex]95.84 \ pm[/tex] which is  10 times smaller than the obtained value  

Based on the ideal gas equation, the calculated values are as follows:

The average volume per molecule is calculated using the given formula derived from the ideal gas equation:

where:

At room temperature and atmospheric pressure;

T = 300 k

P = 1.0 × 10^5 N/m^2

Substituting the values in the equation above to calculate the average volume per molecule, V/n:

V/n = 1.38 × 10^-23 × 300/1.0 × 10^5 N/m^2

V/n = 4.09 × 10^-23 m^3/molecule

Thus, the average volume per molecule is 4.09 × 10^-23 m^3/molecule

The average distance between molecules can be determined by using the formula:

[tex]d = \sqrt[3]{ \frac{v}{n} } [/tex]

Substituting the values for V/n

[tex]d = \sqrt[3]{4.09 \times {10}^{ - 23} } [/tex]

d = 3.45 × 10^-9 m or 3.45 nm

Therefore, the average distance between molecules is 3.45 nm

A molecule of N2 has an average size of 115 pm or 0.115 nm.

Comparing the two values:

3.45/0.115 = 30

Therefore, the N2 molecule is about 30 times smaller than the average distance between molecules.

Learn more about distance between molecules ans Ideal gas equation at: https://brainly.com/question/14375674

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Explanation:

Heat is a form of energy that can transfer from hot body to cold body.Temperature is the degree of hotness and coldness of a body.

Heat is measured in joules, but temp. is measured in Kelvin

Answer:

temperature is the degree of hotness and coldness of the body or an object while heat is the energy transferred from hot to a cooler object as a result if differencein temperature ☺

Answer:

B) less than 700 N

Explanation:

Given;

normal weight of the person, W = 700 N

An elevator moving upward but slowing down at a steady rate, shows that upward force is less than downward force, thus, the reading on the scale will be  less than 700 N.

Also, from Newton's second law

R - mg = ma

where;

R is the reading on the scale

mg is the weight of the person = W = 700 N

a is negative acceleration upward = -a

R - mg = -ma

R = mg - ma

Thus, If this person is standing on a bathroom scale inside the elevator, the scale will read less than 700 N.

B)  less than 700 N.

Answer:

The smallest possibility is 0.01E-22kgm/s

Explanation:

Using

Momentum= h/4πx

= 6.6x 10^-34Js/ 4(3.142* 50*10-12m)

= 0.01*10^-22kgm/s

Answer:

we approach a maximum or minimum the values ​​of the ordinate are closer and closer and when passing this point the values ​​change their trend

Explanation:

The reason for this process occurs because as we approach a maximum or minimum the values ​​of the ordinate are closer and closer and when passing this point the values ​​change their trend if they were rising, they begin to fall and if they were falling they begin to rise. Therefore the maximum point is a point of inflection of the curve since its trend changes.

Another way of looking at this process is that mathematically the point where there is a maximum or a minimum corresponds to the point where the first derivative is equal to zero, this is the slope of the line is horizontal, so the points before after correspond to values ​​with slope of different sign.

Answer:

v = 6.20 10⁻¹² m / s,   v =  1.96 10⁻²  cm/year

Explanation:

This is a kinematics problem, specifically of uniform motion

        v = d / t

let's reduce the magnitudes to the SI system

      d = 8.8 km (1000 m / 1 km) = 8.8 10³ m

      t = 45 10⁶ years (365 day / 1 year) (24 h / 1 day) (3600 s / 1h)

       t = 1,419 10¹⁵ s

let's calculate the speed

        v = 8.8 10³ / 1.1419 10¹⁵

         v = 6.20 10⁻¹² m / s

This is the correct unit of the SI system, but it is more common to give the value in centimeters per year, so let's reduce the value

       v = 8.8 105 / 45 106

       v =  1.96 10⁻²  cm/year

Answer:

The object will remain where it was placed on the fluid

Explanation:

If an object is immersed in a fluid, with both the object and the fluid having the same density, the force of buoyancy (the force acting upward) will be equal to the gravitational force (the weight pulling the object down) making the object remain in the position it was placed in the fluid. Meaning it will neither sink down or float through the surface.

For practical purpose, it should however be noted that the chances of this happening is very low.

NOTE: When an object is less dense than the liquid/fluid, it will float and when it is more dense than the liquid, it will sink

Answer: 80

Explanation: 7.2 hours x 60mph = 432 m

7.2 hrs - 1.8 hrs= 5.4 hrs

432m/5.4hrs = 80

Answer: 80 mph

Explanation:

Just is

Answer:

Average speed is 5 m/s

Explanation:

The initial speed = 0 m/s (since the runner starts from rest)

Final speed = 10 m/s

time interval = 2 sec

average speed = ?

The speed is assumed to change at a constant rate

Average speed = (final speed + initial speed)/2

==> (10 + 0)/2 = 10/2 = 5 m/s

Answer: I believe farther. Correct me if I am wrong

Explanation:

Answer:

Closer.

Explanation:

Due to the refraction of light passing through water and air.

Answer:3) variable affinities (stickiness) for something it is running past. Physical ... -measurement number (significant digits) unit (such as inches) -Significant ... Mass 1 oz. 28.25 g. Relations Between English and Metric Units Mass 1 dram. 1.772 g ... -graduated cylinder has an error of about 1% (± 0.1 mL in 10 mL). -Volumetric

Explanation:

Answer:

1. 28.25 mL, three significant digits.

2. 54.074 mL, three significant digits

3. 600.006 km, four significant digits

4. 1356 kg + 4.2 kg + 19.891 kg

Explanation:

Complete Question

A circular area with a radius of 6.60 cm lies in the xy-plane. What is the magnitude of the magnetic flux through this circle due to a uniform magnetic field B = 0.250 T oriented in the following ways?

(a) in the +z-direction

Wb

(b) at an angle of 54

Answer:

a

[tex]\phi = 0.00342 \ Wb[/tex]

b

[tex]\phi = 0.00201 \ Wb[/tex]

Explanation:

From the question we are told that

   The  radius is  [tex]r = 6.60 \ cm = 0.066 \ m[/tex]

    The magnitude of the magnetic field is [tex]B = 0.250 \ T[/tex]

Generally the cross -sectional area is mathematically represented as

     [tex]A = \pi r^2[/tex]

     [tex]A = 3.142 * (0.066)^2[/tex]

     [tex]A = 0.01369 \ m^2[/tex]

Generally  when the magnetic field is oriented in the +z-direction the magnetic flux is mathematically represented as

      [tex]\phi = B* A cos(0)[/tex]

=>    [tex]\phi = 0.01369 * 0.250 * cos (0)[/tex]

=>     [tex]\phi = 0.00342 \ Wb[/tex]

  Now when the magnetic field is oriented  at an angle of 54°  the magnetic flux is mathematically represented as

      [tex]\phi = B* A cos(54)[/tex]

      [tex]\phi = 0.01369 * 0.250 * cos (54)[/tex]

     [tex]\phi = 0.00201 \ Wb[/tex]

Answer:

v = 100 m/s

Explanation:

Given:

v₀ = 0 m/s

a = 10 m/s²

t = 10 s

Find: v

v = at + v₀

v = (10 m/s²) (10 s) + 0 m/s

v = 100 m/s

Answer:

Yes, lava is a liquid, that cools into rock, which is a solid.

Answer

density of mercury is 13.6 g/ml and that 1 lb = 0.45 kg.

Answer:

81,725 N/m^2

Explanation:

Given the following :

Height of water = 2m

Density of water = 1000kg/m^3

Atmospheric pressure (Pat) = 101325 N/m^2

Lowest pressure (Pl) can be obtained thus ;

Pat - Pl = density × height × acceleration due to gravity

101325 - Pl = 1000 × 2 × 9.8

101325 - Pl = 19600

101325 - 19600 = Pl

Lowest pressure (Pl) = 81,725 N/m^2

81,725 N/m^2 = (81,725/101325) atm

= 0.8065630 = 0.8065 atm

Explanation:

It is given that,

The object distance from the lens is 10 cm, u = -10 cm

Image is formed at a distance of 40 cm away from the lens, u = 40 cm

The lens formula is : [tex]\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}[/tex], v is image distance

[tex]\dfrac{1}{40}-\dfrac{1}{-10}=\dfrac{1}{f}\\\\f=8\ cm[/tex]

The focal length is 8 cm

Magnification,

[tex]m=\dfrac{v}{u}\\\\m=\dfrac{40}{-10}\\\\m=-4[/tex]

The magnification is negative, it means that the formed image is inverted.

Answer:

16∠45° Ω

Explanation:

Applying,

Z = V/I................... Equation 1

Where Z = Impedance, V = Voltage output, I = current input.

Given: V = 120cos(10t+75°), = 120∠75°,  I = 7.5cos(10t+30) = 7.5∠30°

Substitute these values into equation 1

Z = 120cos(10t+75°)/7.5cos(10t+30)

Z = 120∠75°/ 7.5∠30°

Z = 16∠(75°-30)

Z = 16∠45° Ω

Hence the impedance of the linear network is 16∠45° Ω

Answer:

This is due to variation bin air pressure at the two different altitudes, so air rushes out through the eustachian tube to hit the eardrum and back when u reach the ground

Answer:

The wavelength in nanometers is 849.81 nanometers (nm)

Explanation:

Here is the complete question:

A laser technician measures the wavelength of light from a new semiconductor laser. The wavelength is 8.4981 × 10⁻⁷m . What is the wavelength in nanometers. Write your answer as a decimal.

Explanation:

The given wavelength is 8.4981 × 10⁻⁷m.

To determine the wavelength in nanometers, we will convert the given wavelength from meters (m) to nanometers (nm).

1 nanometer = 1 × 10⁻⁹ meters

∴ 10⁻⁹ meters = 1 nanometer

To convert 8.4981 × 10⁻⁷m to nanometer (nm):

If 10⁻⁹ meters (m) = 1 nanometer (nm)

Then,  8.4981 × 10⁻⁷m = (8.4981 × 10⁻⁷m × 1 nm) / 10⁻⁹ m

8.4981 × 10⁻⁷m = 8.4981 × 10⁻⁷ × 10⁹ nm

= 8.4981 × 10² nm

= 849.81 nm

Hence, the wavelength in nanometers is 849.81 nm

Answer:

b. 0.493

Explanation:

Answer:

The  value is  [tex]\theta_2 = 20.322^o[/tex]

Explanation:

From the question we are told that

  The angle of the first order maximum is  [tex]\theta _1 = 10.0^o[/tex]

Generally the condition for constructive interference is  

     [tex]dsin\theta = n \lambda[/tex]

Here  d is the separation between the slit ,

n  is the order of maxima  with values n  =  1, 2 , 3 ... for first , second , third ... order of maxima

    Now for first order of maximum

        [tex]dsin\theta_1 = \lambda \ \ ... \ \ ( 1)[/tex]

=>      [tex]dsin(10) = \lambda \ \ ... \ \ ( 1)[/tex]

    Now for second order of maximum

       [tex]dsin\theta = 2\lambda \ \ ... \ \ ( 2)[/tex]

dividing equation 1  by 2

      [tex]\frac{d sin (10)}{d sin (\theta_2 )} = \frac{\lambda}{2\lambda}[/tex]

     [tex]\frac{ sin (10)}{ sin (\theta_2 )} = \frac{1}{2}[/tex]

=>   [tex]2sin(10) = sin (\theta_2 )[/tex]

=>    [tex]0.3473 = sin(\theta_2)[/tex]

=>   [tex]\theta_2 = sin^{-1} [0.3473][/tex]

=>   [tex]\theta_2 = 20.322^o[/tex]

Answer:

There are [tex]3.372 \times 10^{22}[/tex] molecules in a cubic centimeter of water at ordinary pressure and temperature.

Explanation:

Let suppose that liquid is water at a pressure of a atmosphere and a temperature of 25 ºC. Due to incompresibility of liquids, water density does not have any change of importance due to changes in pressure and temperature.

Density and molar mass of water are 1 gram per cubic centimeter and 18.015 grams per mole. The mass of water in a cubic centimeter ([tex]m[/tex]), measured in grams, is:

[tex]m = \rho\cdot V[/tex]

Where:

[tex]\rho[/tex] - Density, measured in grams per cubic meter.

[tex]V[/tex] - Volume of the sample, measured in cubic meters.

Given that [tex]\rho = 1\,\frac{g}{cm^{3}}[/tex] and [tex]V = 1\,cm^{3}[/tex], the mass of water is:

[tex]m = \left(1\,\frac{g}{cm^{3}} \right)\cdot (1\,cm^{2})[/tex]

[tex]m = 1\,g[/tex]

The amount of moles ([tex]n[/tex]) inside the sample is:

[tex]n = \frac{m}{M}[/tex]

Where:

[tex]m[/tex] - Mass of the sample, measured in grams.

[tex]M[/tex] - Molar mass, measured in grams per mole.

If [tex]m = 1\,g[/tex] and [tex]M = 18.015\,\frac{g}{mole}[/tex], then:

[tex]n = \frac{1\,g}{18.015\,\frac{g}{mole} }[/tex]

[tex]n = 0.056\,mole[/tex]

According to the Avogadro's Principle, there are [tex]6.022\times 10^{23}[/tex] molecules per mole. Hence, the number of molecules in a cubic centimeter of water at ordinary pressure and temperature is determined by simple rule of three:

[tex]x = (0.056\,mole)\times\left(6.022\times 10^{23}\,\frac{molecules}{mole} \right)[/tex]

[tex]x = 3.372\times 10^{22}\,molecules[/tex]

There are [tex]3.372 \times 10^{22}[/tex] molecules in a cubic centimeter of water at ordinary pressure and temperature.

Answer:

D. The person's force on the box is as strong as the force of the box on the person, but the frictional force on the person is forward and large while the backward frictional force on the box is small.

Explanation:

When a bag is pulled, then it involves a person’s force on the box meaning there is an opposite force which is equal to the force of the box on the person.

When the box is pulled, there is a forward frictional force on the person which is big when compared to the backward frictional force which is small. This positive difference is responsible for the movement of the box.