In the figure below, O is the center of the circle. Name a diameter of the circle.

[tex]\textbf{ Heya !}[/tex]

Your Answer Is:-

[tex]\sf{9x\div6}[/tex]

because,

               it has a coefficient of 9 (a number that comes before a variable)

`hope that was helpful to u ~

Applying the trigonometry ratios, the correct option is: B. none of these are correct.

The trigonometry ratios are SOH CAH TOA, which are used for solving a right triangle.

Use the trigonometry ratio to find out which option is correct.

Cos Z = adj/hyp = 61/CZ, so option A is incorrect.

Sin Z = opp/hyp = 73/CZ,  so option C is incorrect.

Tan Z = opp/adj = 73/61,  so option D is incorrect.

Thus, the answer is: B. none of these are correct.

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Hello,

[tex]34 = p + 19[/tex]

[tex]34 - 19 = p + 19 - 19[/tex]

[tex]15 = p[/tex]

[tex]p = 15[/tex]

Answer:

also known as the population parameter of interest the parameter of interest is a practical value that gives you more information about the research sample or population being studied in other words these parameter define the describe the search population

what is parameter answer is given above

Using it's concepts, the mean and the standard deviation of the data-set are given as follows:

B. mean: 17; standard deviation: 7.53.

The mean for this problem is:

M = (22 + 21 + 20 + 4 + 19 + 6 + 24 + 11 + 26)/9 = 17

The standard deviation is:

[tex]S = \sqrt{\frac{(22-17)^2+(21-17)^2+(20-17)^2+(4-17)^2+(19-17)^2+(6-17)^2+(24-17)^2+(11-17)^2+(26-17)^2}{9}} = 7.53[/tex]

Hence option B is correct.

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a) The variables are:

b)

x + y ≥ 12

x*$0.75 + y*$1.25 ≤ $15

a) First we need to define the variables, in this case we have:

b) Now we want to write the system, we know that he must buy at least 12 items, then:

x + y ≥ 12

And he can spend, at most, $15, then:

x*$0.75 + y*$1.25 ≤ $15

These two inequalities conform the system of inequalities:

x + y ≥ 12

x*$0.75 + y*$1.25 ≤ $15

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The results of dividing 1 into pieces that are each 1/9 of a whole is 9

1 ÷ 1/9

1 ÷ 1/9

= 1 × 9/1

= (1 × 9) / (1 × 1)

= 9/1

= 9

Complete question:

If 1 is divided into pieces that are each 1/9 of a whole, how many pieces are there

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The information to fill one the box regarding the proof include:

It should be noted that when two triangles of each corresponding sides are equal, then it's said that they are similar.

Here AB = CD, and AD = CB as they illustrate the fact that they are parallel.

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The area of the parallelogram is 135 square meters.

A quadrilateral with the opposing sides parallel is called a parallelogram (and therefore opposite angles equal).

Properties of parallelogram are-

The area of parallelogram = Base×Height

A = B×H

Calculation for the area of the given parallelogram.

The base is 15 meters.

The height is 9 meters

Area = 15×9

        = 135

Therefore, the area of the parallelogram is 135 square meter.

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Answer:

60:1

Step-by-step explanation:

60:1 = 366:x

60x = 366

x = 6.1

366 minutes is equivalent to 6.1 hours.

Convert 366 minutes to hours.

[tex]\boldsymbol{\sf{Therefore \ \to \ 366 \not{m}*\dfrac{1 \ hr}{60\not{m}}=6.1 \ hr }}[/tex]

We conclude that a time of 366 minutes is equal to 6.1 hours

There are 60 minutes in 1 hour. To convert from minutes to hours, divide the number of minutes by 60. For example, 120 minutes equals 2 hours because 120/60=2.

Probability of someone over age 30 winning the tickets is; 38.46%

We are given;

Number of People over 30 years of age = 15

Number of people between 20 and 30 years old = 14

Number of People under 20 years old = 10

Total number of people in the group = 15 + 14 + 10 = 39

Thus;

Probability of someone over age 30 winning the tickets = 15/39 = 38.46%

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Basado en la información, el valor de abc + bca + cab debe ser de 60.

El valor de la combinación de estás tres letras es de 20.

Según la propiedad conmutativa el orden de los factores sumados no debe afectar su resultado, por lo que:

20+20+20 = 60

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Answer:

Step-by-step explanation:

$240 = 100

$48 = X

100 * 48 = 240X

4800 / 240 = 240X / 240

X = 20

She spent 20% on the dress

Step 1

Using the points (2,0) and (-2, -3), we get the slope is

[tex]\frac{-3-0}{-2-2}=\frac{3}{4}[/tex]

Step 2

Using the point (2,0), the equation is

[tex]y=\frac{3}{4}(x-2)[/tex]

Step 3

Using the distributive property, we get [tex]y=\frac{3}{4}x-\frac{3}{2}[/tex].

Answer:

c

Step-by-step explanation:

im smart like that

Tangent of a circle is a line which touches the circle at a point from outside the circle.

Given a tangent to a circle through a point outside the circle.

We have to draw a tangent to a circle from point outside the circle.

Tangent of a circle is a line which touches the circle at a point from outside the circle.. The point at which tangent touches the circle is known as point of contact.The radius of the circle and tangent are perprndicukar to each other at the point of contact. There cannot be any tangent  to the circle through a point inside the circle. There can be one tangent to a point on the circle. The steps of drawing a tangent to a circle are as under:

1) Draw a circle with the radius neede with center O.

2) Join center of the circle O and any point P on the circle OP is the radius of the circle.

3) Draw a line perpendicular to radius OP through point P which is the intersection point of tangent and circle.

This line is the tangent to the circle at P.

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Answer:

igu

you could crop out question n use pic :)

Answer:

1/xyz^3

Step-by-step explanation:

exponents are subtracted when divided

x^0 is 1

negative exponents are positive in the denominator

(4x^0y^-2z^-3) / (4xy-1)

(4xy^-2z^-3) / (4xy^-1)

x-1y^-1z^-3

1/xyz^3

An analyst obtains the salaries of all 200 federal appeals court judges in 2017 and computes the mean salary to be $215,000. the $215,000 is a parameter.

Therefore, an analyst obtains the salaries of all 200 federal appeals court judges in 2017 and computes the mean salary to be $215,000. the $215,000 is a parameter.

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Answer:

See below.

Step-by-step explanation:

Here is an example:-

Solve by elimination:

2x - 3y  =   0

3x + 2y =  13

To eliminate the y terms Multiply the first equation by 2 and the second by 3. This gives:

4x  - 6y = 0

9x + 6y = 39      Adding the 2 equations:

13x + 0 = 39

13x = 39

x = 39/13 = 3

Finally we find y by plugging x = 3 into the first equation:

2(3) - 3y = 0

3y = 2(3) = 6

y = 2.

Answer: 22.5

Step-by-step explanation:

[tex]\sin 64^{\circ}=\frac{x}{25}\\\\x=25 \sin 64^{\circ}\\\\x \approx 22.5[/tex]

The solution to the inequality 6x + 3y ≤ 84 is the dark region shown and the point (9, 10) satisfies this inequality.

An equation is an expression that shows the relationship between two or more variables and numbers.

Let x represent the number of rides Darren can ride and y represent the number of exhibits he can view. Hence:

6x + 3y ≤ 84

The solution to the inequality 6x + 3y ≤ 84 is the dark region shown and the point (9, 10) satisfies this inequality.

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It was A! I got it right on the Edmentum/Plato test!! YW!!!

Answer:

1. Multiply the slope by 2 and look at the numerator

2. 5/7

3. slide A

4. The run of slide a is shorter which means that its steeper because the rise is the same

5. 10

6. 5 units?

Step-by-step explanation:

#1

We know

slope=tanØ

Here in slide B

But

Then

#2

The slope of slide A

#3 and 4

Compare tangents

Slide A is steeper

#5

Found in #1

#6

Slide A is higher as 15>10

It looks like the boundaries of [tex]R[/tex] are the lines [tex]y=\dfrac23x [/tex] and [tex]y=3x[/tex], as well as the hyperbolas [tex]xy=\frac23[/tex] and [tex]xy=3[/tex]. Naturally, the domain of integration is the set

[tex]R = \left\{(x,y) ~:~ \dfrac{2x}3 \le y \le 3x \text{ and } \dfrac23 \le xy \le 3 \right\}[/tex]

By substituting [tex]x=\frac uv[/tex] and [tex]y=v[/tex], so [tex]xy=u[/tex], we have

[tex]\dfrac23 \le xy \le 3 \implies \dfrac23 \le u \le 3[/tex]

and

[tex]\dfrac{2x}3 \le y \le 3x \implies \dfrac{2u}{3v} \le v \le \dfrac{3u}v \implies \dfrac{2u}3 \le v^2 \le 3u \implies \sqrt{\dfrac{2u}3} \le v \le \sqrt{3u}[/tex]

so that

[tex]R = \left\{(u,v) ~:~ \dfrac23 \le u \le 3 \text{ and } \sqrt{\dfrac{2u}3 \le v \le \sqrt{3u}\right\}[/tex]

Compute the Jacobian for this transformation and its determinant.

[tex]J = \begin{bmatrix}x_u & x_v \\ y_u & y_v\end{bmatrix} = \begin{bmatrix}\dfrac1v & -\dfrac u{v^2} \\\\ 0 & 1 \end{bmatrix} \implies \det(J) = \dfrac1v[/tex]

Then the area element under this change of variables is

[tex]dA = dx\,dy = \dfrac{du\,dv}v[/tex]

and the integral transforms to

[tex]\displaystyle \iint_R 9xy \, dA = \int_{2/3}^3 \int_{\sqrt{2u/3}}^{\sqrt{3u}} \frac{dv\,du}v[/tex]

Now compute it.

[tex]\displaystyle \iint_R 9xy \, dA = \int_{2/3}^3 \ln|v|\bigg|_{v=\sqrt{2u/3}}^{v=\sqrt{3u}} \,du \\\\ ~~~~~~~~ = \int_{2/3}^3 \ln\left(\sqrt{3u}\right) - \ln\left(\sqrt{\frac{2u}3}\right) \, du \\\\ ~~~~~~~~ = \frac12 \int_{2/3}^3 \ln(3u) - \ln\left(\frac{2u}3\right) \, du \\\\ ~~~~~~~~ = \frac12 \int_{2/3}^3 \ln\left(\frac{3u}{\frac{2u}3}\right) \, du \\\\ ~~~~~~~~ = \frac12 \ln\left(\frac92\right) \int_{2/3}^3 du \\\\ ~~~~~~~~ = \frac12 \ln\left(\frac92\right) \left(3-\frac23\right) = \boxed{\frac76 \ln\left(\frac92\right)}[/tex]

The price that must be charged for a 1-hour tutoring session to produce this amount of revenue is 24.5 dollars

The first thing to do with word problem is to understand the question. After that, make analysis of the question.

It is given that a A private tutoring company charges $20 for a 1-hour session. Currently, 300 students are each tutored for an hour each week. Since the company is losing money, the owner has decided to increase the price. For each 50¢ increase, That is $20.5 for each students.

If she estimates that 5 fewer students will participate, that is, 295 students, and the company needs to bring in $6,210 per week to stay in business.

Let us assume that 1 hour per day. And there are 7 days in a week.

Divide the money by 7 to know the value per day

6210/7 = 887.14

Now, divide the amount per day by 250 students to know the amount per student per hour

887.14/295 = 3.007

The price that must be charged for a 1-hour tutoring session to produce this amount of revenue should be 20.5 + 4 = 24.5 dollars

Therefore, each student will pay $24.5 per hour

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The correct option is (c) h = 10sin(π15t)+35.

The equations can be used to model h, the height in feet of the end of one blade, as a function of time, t, in seconds is  h = 10sin(π15t)+35.

The blades of a turbine, which resemble propellers and function much like an airplane wing, capture the wind's energy.

A pocket of low-pressure air develops on one side of the blade when the wind blows. The blade is subsequently drawn toward the low-pressure air pocket, which turns the rotor.

Calculation for the equation of the model height-

Let's now review each choice individually and select the best one.

The blade is horizontal at time t = 0. As a result, h = 35 at t = 0 is valid for all of the possibilities in this situation.

They accomplish two spins in a minute. The blades will so complete one rotation in 30 seconds. and they will complete a quarter rotation in 15/2 seconds. Because of this, the blade will be vertically up from time t = 0 to t = 15/2. Its height in this instance should be 35 + 10 = 45 ft. Let's now examine the available possibilities.

If we put t=15/2 in the options

Option (a) gives h = 25

Option (b) gives h = -10sin(15/2) + 35

Option (c) gives h = 45

Option (d) gives h = 10sin(15/2) + 35

Therefore, the correct equation is given in option c.

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The complete question is -

The blades of a windmill turn on an axis that is 35 feet above the ground. The blades are 10 feet long and complete two rotations every minute. Which of the following equations can be used to model h, the height in feet of the end of one blade, as a function of time, t, in seconds? Assume that the blade is pointing to the right, parallel to the ground at t = 0 seconds, and that the windmill turns counterclockwise at a constant rate.

a) h = −10sin(π15t)+35  

b) h = −10sin(πt)+35

c) h = 10sin(π15t)+35

d) h = 10sin(πt)+35

Based on the calculations, the correct value of the test statistic is equal to 3.2.

For samples A and B, the hypothesis is given by:

H₀: μ₁ ≤ μ₂

H₁: μ₁ > μ₂

Since both samples have a normal distribution, we would use a pooled z-test to determine the value of the test statistic:

[tex]z = \frac{\bar{x_1} - \bar{x_2} -(\mu_1 - \mu_2) }{\sqrt{\frac{\sigma_1^2}{n_1} + \frac{\sigma_1^2}{n_1}} }[/tex]

Substituting the given parameters into the formula, we have;

[tex]z = \frac{33 - 25 -(0) }{\sqrt{\frac{3^2}{4} + \frac{4^2}{4}} }\\\\z = \frac{8 }{\sqrt{\frac{9}{4} + \frac{16}{4}} }\\\\z = \frac{8 }{\sqrt{\frac{25}{4} } }\\\\z = \frac{8 }{\frac{5}{2} }}\\\\z = 8 \times \frac{2}{5}[/tex]

z = 3.2.

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We can to convert the expression  [tex](3^{\frac{1}{5} } )^{2}[/tex] to the radical expression   [tex]\sqrt[5]{9}[/tex].  by using the laws of indices.

A radical expression is an expression of the form ⁿ√x where it is called the nth root of x.

Now, to write [tex](3^{\frac{1}{5} } )^{2}[/tex] as  the radical expression [tex]\sqrt[5]{9}[/tex], we use following laws of indices

So,  [tex](3^{\frac{1}{5} } )^{2} = (3^{2} )^{\frac{1}{5} }[/tex]

  [tex](3^{2} )^{\frac{1}{5} } = 9^{\frac{1}{5} } = \sqrt[5]{9}[/tex]

Thus, we can to convert the expression  [tex](3^{\frac{1}{5} } )^{2}[/tex] to the radical expression   [tex]\sqrt[5]{9}[/tex].  by using the laws of indices.

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Answer:

3x²y (2x²-3y²+ 4y)

Step-by-step explanation:

Factor the expression 6x^4y-9x²y³+12x²y².

First, check if there is a GCF. The GCF is 3x²y.

3x²y (2x²-3y²+ 4y).

This equation cannot be factored further. Therefore, the answer is
3x²y (2x²-3y²+ 4y).

Hope this helps!

Answer:

3x²y(-3y²+4y+2)

Step-by-step explanation:

6x⁴y-9x²y³+12x²y²

solution:

first common

3x²y(2x²-3y²+4y)

3x²y(-3y²+4y+2)