Is the sinusoidal pattern on a string longer or shorter when there is a greater propagation velocity?

Your question has been heard loud and clear.

An alpha particle , can move in any direction randomly. But with a magnetic field , we can deflect the alpha particle in any direction we want.

So , the magnetic field must be placed to the west of the alpha particle , so that the particle gets deflected and moves towards the north direction.

Thank you.

Like AL2006 said reasons for what

Answer:

Question 1: D because the height the ball bounces depends on all the other factors in the experiment.

Question 2: B because the the temperature of the water is not affected by the other variables.

Question 3: A because the more that they can control in the experiment, the more accurate the results will be.

Hopefully this helps :)

1:D 2:B 3:A

just took the test

Answer:

Lamp 1:  4 Volts,  and 0.2 Amps

Lamp 2 : 4 Volts, and 0.2 Amps

Explanation:

Considering that the three lamps are equal (they have the same resistance R), we can find the actual resistance of the lamps with the information they provide that the potential difference measured across lamp 3 is 8 volts, using Ohm's Law:

[tex]V = I\,*\,R\\R = \frac{V}{I}\\R= \frac{8}{0.4} \\R = 20\,\,\Omega[/tex]

We can also estimate the potential difference across the lamps 1 and 2 (which are connected in parallel) using Kirchhoff's loop law, which tells us that the 12 volts provided by the battery should equal the addition of voltage drops in lamp 3 plus the drop in the parallel combination of lamps 1 and 2 (call that X):

12 V = 8 V + X

X = 12 - 8 = 4 V

Now, the current circulating through lamp 1 should be given by Ohm's Law:

[tex]V = I\,*\,R\\I = \frac{V}{R} \\I = \frac{4}{20}\\I = 0.2 \,\,Amps[/tex]

Notice that lamp 2 is equal to lamp 1 so the current value should be the same: 0.2 Amps

Answer:

a) [tex]\mathbf{|\Delta p^{\to}_{11}| = 0 \ kg.m/s}[/tex]

b) [tex]\mathbf{|\Delta p^{\to}_{12}| = 500 \ kg.m/s}[/tex]

Explanation:

From the image attached below.

Suppose the child goes all the way around, i.e., 360, the child will execute a movement of 1 complete revolution and be at his starting point. At that point, the velocity vector is towards the y-direction.

Thus, the velocity of the child is:

[tex]v_1^{\to} = v \hat _v_1} \\ \\ v_1^{\to} = (5)(0,1,0)\\ \\ v_1^{\to} = (0,5,0) \ m/s[/tex]

the momentum will be:

[tex]p_1^{\to} = m v_1^{\to} \\ \\ p_1^{\to} = (50)(0,5,0) \\ \\ p_1^{\to} = (0,250,0) \ kg.m/s[/tex]

the  change in momentum now is [tex]\Delta p = p_1^{\to} -p_1^{\to}[/tex] since that is the child's momentum initially.

∴ [tex]\Delta p =(0,250,0) - (0,250,0)[/tex]

[tex]\mathbf{\Delta p =(0,0,0) \ kg.m/s}[/tex]

By subtracting the two vector graphically as being asked in the question, we have :

[tex]|\Delta p^{\to}_{11}| = \sqrt{(0)^2+(0)^2 +(0)^2 }[/tex]

[tex]\mathbf{|\Delta p^{\to}_{11}| = 0 \ kg.m/s}[/tex]

b) In going halfway around (180°), the child will be opposite with respect to the starting point. Hence, the velocity vector will be in the negative y-direction.

Thus, the velocity of the child is:

[tex]v_2^{\to} = v \hat _v_2} \\ \\ v_2^{\to} = (5)(0,-1,0)\\ \\ v_2^{\to} = (0,-5,0) \ m/s[/tex]

the momentum will be:

[tex]p_2^{\to} = m v_2^{\to} \\ \\ p_2^{\to} = (50)(0,-5,0) \\ \\ p_2^{\to} = (0,-250,0) \ kg.m/s[/tex]

the  change in momentum now is [tex]\Delta p = p_2^{\to} -p_1^{\to}[/tex] since that is the child's momentum initially.

∴ [tex]\Delta p =(0,-250,0) - (0,250,0)[/tex]

[tex]{\Delta p =(0,-500,0) \ kg.m/s[/tex]

By subtracting the two vector graphically as being asked in the question, we have :

[tex]|\Delta p^{\to}_{12}| = \sqrt{(0)^2+(-500)^2 +(0)^2 }[/tex]

[tex]|\Delta p^{\to}_{12}| = \sqrt{250000}[/tex]

[tex]\mathbf{|\Delta p^{\to}_{12}| = 500 \ kg.m/s}[/tex]

Answer:

2

Explanation:

kilogram and megagram is the larger unit

Complete Question

Martin is conducting an experiment. His first test gives him a yield of 5.2 grams. His second test gives him a yield of 1.3 grams. His third test gives him a yield of 8.5 grams. On average, his yield is 5.0 grams, which is close to the known yield of 5.1 grams of substance. Which of the following are true?

A His results are accurate but not precise.

B His results are neither accurate nor precise.

C His results are both accurate and precise

D His results are precise but not accurate.

Answer:

Correct option is A

Explanation:

From the question we are told that  

   The  yield of the first test [tex]k  =  5.2 \  g[/tex]

   The  yield of the second  is  [tex]u =  1.3 \  g[/tex]

   The  third yield is  [tex]p =  8.5 \  g[/tex]

   The  average yield  [tex]A = 5.0 \ g[/tex]

    The  know yield is  [tex]A_S =  5.1 \  g[/tex]

From the data given we see that

        [tex]A_S \ne A[/tex]

Since his average yield is closer to the known yield then the answer is accurate

But since the yield for each test are not repeated the answer is not precise

So the answer is accurate but not precise  

His results are accurate but not precise.

Your question is not complete, it seems to be missing the following information;

"A His results are accurate but not precise.

B His results are neither accurate nor precise.

C His results are both accurate and precise.

D His results are precise but not accurate."

The given parameters;

Each of the measurement is far from each other. That is 5.2 grams, 1.3 grams and 8.5 grams are all far apart. So this measurement is not precise.

The known average (5.1 g) and the measured average (5.0 g) are close to each other, so the measurement is accurate.

Thus, we can conclude that his results are accurate but not precise.

Learn more here: https://brainly.com/question/13377944

Answer:

Density is the mass of an object divided by its volume. Density often has units of grams per cubic centimeter (g/cm3). Remember, grams is a mass and cubic centimeters is a volume (the same volume as 1 milliliter).

Explanation:

Hey, there!

Density is defined as mass per unit volume. so, when we keep is as a formula we get like,

[tex]density = \frac{mass}{volume} [/tex]

So, you can state that density is calculated by dividing mass by its unit volume.

Hope it helps...

Answer:

1.2J

26 N

(-28, 14) m/s

Explanation:

energy

U = kQq / d = 8.99*10^9 * (2.5*10^-6C)² / 0.047m

U = 0.0562/0.047

U = 1.20 J

to two significant figures

tension

T = kQq / d²

T = U / d

T = 1.2 / 0.047

T = 25.53 N = 26 N to 2 sf

Momentum is conserved, and the initial momentum is zero:

0 = 0.0020 * V2 + 0.0040 * V4

so

V2 = -2 * V4

Energy is also conserved:

½ * 0.0020 * (-2V4)² + ½ * 0.0040 * (V4)² = 1.2 J

-½ * 0.0080 * V4² + ½ * 0.0040 * V4² = 1.2 J

-0.0040V4² + 0.002V4² = 1.2 J

0.0060V4² = 1.2 J

V4² = 1.2/0.0060

V4² = 200

V4 = √200

V4 = 14 m/s

and since V2 = -2 * V4

V2 = -28 m/s

(V2, V4) = (-28, 14)

The energy of this system is 1.2J

The  tension in the string is 26 N

The speed of each sphere when they are far apart is (-28, 14) m/s

The energy should be

U = kQq / d

= 8.99*10^9 * (2.5*10^-6C)² / 0.047m

U = 0.0562/0.047

U = 1.20 J

The tension should be

T = kQq / d²

T = U / d

T = 1.2 / 0.047

T = 25.53 N

= 26 N

The speed should be

Since Momentum should be conserved, and the initial momentum is zero:

So,

0 = 0.0020 * V2 + 0.0040 * V4

Now

V2 = -2 * V4

Due to this, Energy is also conserved:

½ * 0.0020 * (-2V4)² + ½ * 0.0040 * (V4)² = 1.2 J

-½ * 0.0080 * V4² + ½ * 0.0040 * V4² = 1.2 J

-0.0040V4² + 0.002V4² = 1.2 J

0.0060V4² = 1.2 J

V4² = 1.2/0.0060

V4² = 200

V4 = √200

V4 = 14 m/s

and now V2 = -2 * V4

V2 = -28 m/s

(V2, V4) = (-28, 14)

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Answer:

The presence of dwarf galaxies around the Milky Way supports what picture that our galaxy was formed by a coming together or combination of smaller systems

Answer:

7,790.38 m/s

Explanation:

Given the following :

What linear speed must an Earth satellite have to be in a circular orbit at an altitude of 203 km above Earth's surface

Altitude = 203 km

Using the formula :

V = √GM/r

Where G = gravitational constant =6.67×10^-11

Kindly check attached picture for detailed explanation.

Answer:

A)       ΔEm = 0.29,  B)   v₁ = 5.8 m/s, c)   v₂=  4.9 m / s    D) the correct answer from 4

Explanation:

For this exercise we will use conservation of energy, taking care of how to choose our system

A) For this case we take two instants

starting point. When the ball goes out

        Em₀ = U = m g y₁

Final point. When the ball reaches its maximum height

         [tex]Em_{f}[/tex] = U = m g y₂

In this case we see that there is a loss of mechanical energy at the moment of rebound, therefore the fraction of energy lost is

          ΔEm = Em_{f} / Em₀

          ΔEm = mg y₂ / mg y₁

          ΔEm = y₂ / y₁

          ΔEm = 1.2 / 1.7

the lost part of energy  

          ΔEm = 1 -0.706

          ΔEm = 0.29

B) the velocity just before the bounce

starting point. When the ball is released

          Em₀ = U = m g y₁

final punot. Just wide of the bounce

           Em_{f} = K = ½ m v₁²

As it has not yet rebounded, it has no energy loss, therefore the mechanical energy is conserved

            Em₀ = Em_{f}

            m g y₁ = ½ m v₁²

             v₁ = √ 2 g y₁

let's calculate

            v₁ =√ (2 9.8 1.7)

             v₁ = 5.77 m / s

            v₁ = 5.8 m/s

C) the velocity just after the bounce

   starting point, after bounce

               Em₀ = K = ½ m v₂²

   final point. Maximum height after bounce

               Em_{f} = U = m g y₂

as it already bounced, the energy is conserved in this interval

               Em₀ = Em_{f}

               ½ m v₂² = m g y₂

               v₂ = √ (2 g y₂)

               v₂ = √ (2 9.8 1.2)

               v₂ = 4.85 m / s

               v₂=  4.9 m / s

D) during the time that the bounce lasts, there is a strong change in energy, part of it is transformed into thermal energy, due to several processes: friction, change in the potential energy of the molecules of the ball, change in the internal energy of the balls. molecules.

Therefore we cannot specify a single process, consequently the correct answer from 4

Answer:

b

Explanation:

a looks so silly

Answer:

Explanation:

We shall apply law of conservation of momentum to solve the problem .

Helium-3 collides with nitrogen-14 at rest . After the collision the newly formed deuterium atom and oxygen-15  atom moves .

momentum before the collision

= 3.016 x 6.346 x 10⁶ + 14.003 x 0 = 19.14 x 10⁶ unit

momentum after collision

2.014 x 1.531 x 10⁷ + 15.003 V

3.083 x 10⁷ +  15.003 V units

Applying the law of conservation of momentum ,

19.14 x 10⁶ = 3.083 x 10⁷ +  15.003 V

1.914 x 10⁷ = 3.083 x 10⁷ +  15.003 V

15.003 V = - 1.169 x 10⁷

V = .077917 x 10⁷

= 7.79 x 10⁵  m /s

= .0779 x 10⁷ m /s

mass of helium atom = 3.016 u = 3.016 x 1.67 x 10⁻²⁷ kg

velocity = 6.346 x 10⁶ m /s

kinetic energy = 1 /2 x  3.016 x 1.67 x 10⁻²⁷ x (6.346 x 10⁶ )²

= 101.42 x 10⁻¹⁵ J  

kinetic energy of nitrogen atoms = 0

Total energy before collision =  101.42 x 10⁻¹⁵ J  

Similarly kinetic energy after collision

= 1 /2 x [ 2.014 x 1.531² + 15.003 x .0779² ] x 1.67 x 10⁻²⁷ x 10¹⁴

= .835 x [ 4.72  + .09 ] x 10⁻¹³ J

=  4.016 x 10⁻¹³ J

= 401.6 x 10⁻¹⁵  J  

value of kinetic energy is increased .

Answer:

A. Using

Fl= ( v+vl/v+vz)fz

= (340+19/340+31) x 2020

= 1954.7Hz

Then to find the frequency of sound when reflected from the truck such that the driver becomes the listener

we use

F"= ( v+vz/v+vl) fz

= 340+31/340+19 x 2020

2087.5Hz

B to find the wavelength of sound we use

Wavelength= V+vl/ F"

= 340+31/2087.5= 0.18m

Answer:

The distance moved is 44 metres.

The magnitude of displacement is 20 metres with northward direction.

Answer:

44 m.

North 20 m.

Explanation:

Distance moved = 26 + 12 + 6

=  44 m.

Magnitude of the displacement = 26 - 12 + 6

= 20m

Direction is Northward.

the quest for civic virtue

Explanation:

improving schools, the society....to help educators like yourself, the bill of rights institute has written a New classroom-friendly curriculum called Heroes and Villains....

Answer:

When inertia increases, it's because the mass increased, which increases the normal force, which ultimately increases friction.

Answer:

Acceleration, a = -3 m/s²

Explanation:

Given that,

Initial speed, u = 15 m/s

Final speed, v = 0

Time, t = 5 s

We need to find the acceleration of the train. It is equal to the change in velocity divided by time taken. So,

[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{0-15\ m/s}{5\ s}\\\\a=-3\ m/s^2[/tex]

So, the acceleration of the train is 3 m/s² and it is deaccelerating.

Answer:

Given x = bt-c²

We know that t= time (s)

x= distance (m)

So

bxt= meters

m/s x s= m

And then c= m/s²

And b= m/s

Answer:

The  power is   [tex]P  =  41429 \  W[/tex]

Explanation:

From the question we are told that

   The  energy is  [tex]E =  435  \  J[/tex]

    The time taken is  [tex]t =  10.5 \  ms  =  10.5 *10^{-3} \  s[/tex]

Generally the the average power is  mathematically represented as

       [tex]P  =  \frac{E}{t}[/tex]

=>    [tex]P  =  \frac{ 435}{ 10.5*10^{-3}}[/tex]

=>     [tex]P  =  41429 \  W[/tex]

Answer:

False

Explanation:

Faraday's law gives the relationship between the induced emf and the rate of change of magnetic flux i.e.

[tex]\epsilon=\dfrac{-d\phi}{dt}[/tex]

The given statement "A large magnetic flux change through a coil must induce a greater emf in the coil than a small flux change" is false. The reason is that if the rate of change of magnetic flux is greater, then its will induce more emf. It would mean it does not say about emf.

Hence, it is false.

Answer:

Here are some examples of orderliness In nature​

1. The proposal that the order of nature showed evidence of having its own human-like "intelligence" goes back to the origins of Greek natural philosophy and science, and its attention to the orderliness of nature, often with special reference to the revolving of the heavens.

2. For Stillman, the orderliness of Astaire-like dance is an actual cure for destructive emotions.

3. Tells about the orderliness of the crowds, and of the dispatch with which the trains were being filled and emptied.

Answer:

0.043°

Explanation:

Snell's law States that the ratio of the angle of incidence to angle of refraction is a constant for a given pair of media.

n = sin(i)/sin(r)

n1/n2 = sin(i)/sin(r)

For the green polystyrene

n2 = refractive index of green polystyrene = 1.493

n1 = refractive index of air = 1

1/1.493= sin30°/sin(r1)

sin(r1) = sin30°×1.493

sin(r1) = 0.5×1.493

sin(r1) = 0.7465

r1 = sin^-1(0.7465)

r1 = 48.288°

For the yellow polystyrene

n2 = refractive index of yellow polystyrene = 1.492

n1 = refractive index of air = 1

1.492/1= sin30°/sin(r2)

sin(r2) = sin30°×1.492

sin(r2) = 0.5×1.492

sin(r2) = 0.746

r2 = sin^-1(0.746)

r2 = 48.245°

The angle between the colors when they emerge = r1-r2

angle between the colors when they emerge = 48.288°-48.245°

angle between the colors when they emerge = 0.043°

Answer:

B. Repel each other

Explanation:

Two like charges have the same sign. Example an electron with a negative charge (-e) and another electron with same charge(-e). Or a proton with a positive charge (+e) and another proton with same charge (+e). Since each of  these pair charges have the same sign, they will repel each other.

On the other hand, if the charges are opposite, ie  negative charge and positive charge, they will attract each other.

B. Repel each other

Answer:

Velocity = 8 ft/s

Acceleration = 0 m/s²

Explanation:

Since, the horse is moving with a constant velocity, whose magnitude is given as equal to 8 ft/s. Therefore, it will have the same velocity when it is 10 ft away from the barn. And the velocity of hay bale will be same as the velocity of horse, as the horse is carrying the bales. Therefore:

Velocity = 8 ft/s

Coming to the second part of the question, which relates to the acceleration of the hay bale, when horse is 10 ft away from the barn. The formula for acceleration is given as:

Acceleration = Change in Velocity/ Time

But, the velocity of the horse in constant, which means there is no change in velocity. Hence,

Change in Velocity = 0

Therefore,

Acceleration = 0/Time

Acceleration 0 m/s²

Answer:

A) Average speed = 18.75 m/s

B) More time is spent at 15 m/s than at 25 m/s.

Explanation:

Let the first distance be d1 and the second distance be d2.

We are given;

d1 = 10 km = 10000 m

d2 = 10 km = 10000 m

Speed; v1 = 15 m/s

Speed; v2 = 25 m/s

Now, the formula for distance is; Distance = speed x time

Thus:

d1 = v1 x t1

t1 = d1/v1 = 10000/15 = 666.67 seconds

Also,

d2 = v2 x t2

t2 = d2/v2 = 10000/25 = 400 seconds

Average speed = total distance/total time = (10000 + 10000)/(666.67 + 400) = 18.75 m/s

From earlier, since t1 = 666.67 seconds and t2 = 400 seconds, then;

More time at 15 m/s than at 25 m/s.

Answer:

that's too much to read

Answer:

power=work done /time taken

therefore..375/11

=34.09

there he used 34.1

Vector  explanation is apex and I got 100 on the test and it’s the definition