Is the star moving toward earth, away from earth, or is there not enough information provided to determine its motion?

Answers

Answer 1

If a star is moving towards Earth, shift towards the blue end of the spectrum, this is called blue shift. If the star is moving away from Earth the light from that star will be red and is called red shift .

The faster a star moves towards the earth, the more its light is shifted to higher frequencies. In contrast, if a star is moving away from the earth, its light is shifted to lower frequencies on the color spectrum

if a star is moving towards Earth, it appears to emit light that is shorter in wavelength compared to a source of light that isn't moving. Because shorter wavelengths correspond to a shift towards the blue end of the spectrum, this is called blue shift.

If the star is moving away from Earth, its light will lose energy to reach Earth, therefore the light from that star will be red and is called red shift

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Related Questions

The only source of light in a room is the lightbulb shown. An opaque disk is placed in front of the bulb. A screen is then placed successively at positions A, B, and C. At which screen position(s) does the disk cast a shadow that is completely dark at the center

Answers

On screen A the opaque disk cast a shadow that is completely dark at the center

opaque is defined as difficult to understand or not allowing light to pass through. The appearance of a black sheet of paper is an illustration of opaqueness. The study of astrophysics is an illustration of opaque.

An opaque object illuminated by a point source of light is said to produce a crisp shadow whose dimensions may be determined using geometry. This is according to geometric optics. The computation process is quite simple. Light beams are uniformly emitted from the source in all directions. These rays can be visualized as lines radiating straight out from the source. When a light source encounters an opaque object, the light rays cease moving away from the source.

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Color is a result of the absorption and reflection of light. A shirt appears a color because it reflects that color of light. A shirt appears black when it absorbs all wavelengths of light. Why does a shirt appear white outside on a sunny day

Answers

The clothing seems white because the entire light is reflected.

what is absorption and reflection?

Absorption:

This occurs when light is transformed into another type of energy. This happens when light vanishes while travelling through another medium.

reflection:

It is referred to as light reflection when a light ray hits a polished, smooth surface and bounces back. The incident light rays hit the surface and are reflected off of it. The beam that returns is referred to as the reflected ray.

according to the question we know that a shirt appears a color because it reflects that color of light. A shirt appears black when it absorbs all wavelengths of light. In case  of white shirt no wavelength is absorbed by the shirt due to which the shirt appears white and in simple words the entire light is reflected back.

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If you want the ball to land in your hand when it comes back down, should you toss the ball straight upward, in a forward direction, or in a backward direction, relative to your body

Answers

Straight upward

the ball moves in the forward direction with your walking speed at all times. If you want the ball to land in your hand when it comes back down, you should toss the ball straight upward.

What is Projectile motion ?

Projectile motion is the motion of an object thrown (projected) into the air.

After the initial force that launches the object, it only experiences the force of gravity. The object is called a projectile, and its path is called its trajectory

A projectile can be a thrown ball, a bullet or a springboard diver ... Except for air resistance, the forward velocity of any projectile is constant and is equal to the initial velocity when it was released.

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Supposing the half-life of element x to be 1 year, if you have a 100 gram sample of x, how much of element x would be left after 4 years? (do not use significant digits in answering this question.)
75 g
50 g
25 g
6.25 g

Answers

6.25 gram of element x would be left after 4 years.

What's half life of an element?Half - life is the time period of decay of an element to half of its initial number of nuclei.After n no. of half lives, no. of nuclei left in the sample is initial number of nuclei / 2^n

What's the amount of 100 gm of element x left after 4 half lives ?

Leftover amount of the element x = 100/2^4

= 100/16 = 6.25 gram

Thus, we can conclude that 6.25 gram of element x would be left after 4 years.

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Water flows through a pipe with a cross-sectional area of 0.002 m^2 at a mass flow rate of 4 kg/s. the density of water is 1 000 kg/m^3. Determine its average velocity

Answers

Water flows through a pipe with a cross-sectional area of 0.002 m^2 at a mass flow rate of 4 kg/s. The density of water is 1 000 kg/m^3 . The average velocity will be 2m/s

The flow rate of a liquid is how much fluid passes through an area in a particular time. Flow rate can be articulated in either in terms of velocity and cross-sectional area, or time and volume.

Flow rate = Volume of fluid / time

               = (Area * distance) / time

               =  Area * average velocity      (distance / time = average velocity)

Given

Cross-sectional area  = 0.002 [tex]m^{2}[/tex]

Flow rate =  4 kg/s

Average velocity = Flow rate / (Area * density)

                            = 4 / (0.002 * 1000)

                           = 2m/s

hence , the  average velocity will be 2 m/s

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According to hubble's law, with = 70 km/s , how far away is a galaxy whose recessional velocity is 6000 km/s ?

Answers

The galaxy will be D = 84.96 km far away

Hubble's law, which says simply that a galaxy's velocity (or as is sometimes plotted, its redshift) is directly proportional to its distance, also tells us something important about the state of the universe. If the universe is static and unchanging, there should be no correlation between distance and velocity.

Recessional velocity is the rate at which an extragalactic astronomical object recedes (becomes more distant) from an observer as a result of the expansion of the universe. It can be measured by observing the wavelength shifts of spectral lines emitted by the object, known as the object's cosmological redshift.

V (r) = H * D + V pec

6000 = 69.8 * D + 70

5930 / 69.8 = D

D = 84.96 km

The galaxy will be D = 84.96 km far away

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PLEASE HELP QUICK! Why does thermal energy increase on a roller coaster? Especially when it goes up the second hill?

Answers

as friction does negative work, the mechanical energy decreases. The work done by friction transforms mechanical energy into heat, a non-mechanical form of energy. As a result, the temperature of the track and the wheels increase.

he most accurate place to conduct a weight check is: Select one: At the surface, at the beginning of the dive. At the deepest point reached during the dive. At safety-stop depth, at the end of the dive. None of the above.

Answers

The most accurate place to conduct a weight check is at safety-stop death, at the end of the dive.

Why is a weight check important in diving?

A weight check before diving helps an individual decide on the right amount of weight needed for each scuba dive.

To do a weight check one must float upright on the surface, head placed above water. The individual then needs to ­release some air from their Buoyancy compensator as they take a deep breath from their regulator.

Now if the individual sinks rapidly below the ­surface, they are overweight and if their head stays above the water surface, then they are underweight. Thus, when an individual sinks up to the mask ­level, then the weight is just right.

Therefore, the most accurate place to conduct a weight check is at safety-stop depth, at the end of the dive.

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What happens if :
. The test charge is not tiny.

Answers

The magnitude of the test charge must be small enough so that it does not disturb the issuance of the charges whose electric field we wish to measure otherwise the metric field will be different from the actual field.

How does test charge affect electric field?

As the quantity of authority on the test charge (q) is increased, the force exerted on it is improved by the same factor. Thus, the ratio of force per charge (F / q) stays the same.

Adjusting the amount of charge on the test charge will not change the electric field force.

What is a test charge used for?

The charge that is used to measure the electric field strength is directed to as a test charge since it is used to test the field strength. The test charge has a portion of charge denoted by the symbol q.

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Three charges, qA is +6.0 μC, qB is –5.0 μC, and qc is +6.0 μC, are located at the corners of a square with each
side length at 5.0 cm as shown in the diagram. Calculate the electric field at point D.

Answers

The net electric field at point D is determined as 3.95 x 10⁷ N/C.

Electric field at D due to charge A

E = kq/r²

where;

r is the distance between A and Dq is charge A

E(AD) = (9 x 10⁹ x 6 x 10⁻⁶)/(0.05²)

E(AD) = 2.16 x 10⁷ i N/C

Electric field at D due to charge B

E = kq/r²

where;

r is the distance between A and Bq is charge B

r² = 5²  + 5²

r² = 50

r = √50

r = 7.07 cm

E(BD) = (9 x 10⁹ x 5 x 10⁻⁶)/(0.0707²)

E(BD) = 9 x 10⁶ N/C

in x - direction = 9 x 10⁶ N/C x cos(45) = 6.36 x 10⁶ i  N/C

in y - direction = 9 x 10⁶ N/C x sin(45) = 6.36 x 10⁶j  N/C

Electric field at D due to charge C

E = kq/r²

where;

r is the distance between C and Dq is charge C

E(CD) = (9 x 10⁹ x 6 x 10⁻⁶)/(0.05²)

E(CD) = 2.16 x 10⁷ j N/C

sum of electric field in x direction

Ei = 2.16 x 10⁷ i N/C  + 6.36 x 10⁶ i  N/C

Ei = 2.796 x 10⁷ i N/C

sum of  electric field in y direction

Ej = 2.16 x 10⁷ j N/C  + 6.36 x 10⁶j  N/C

Ej = 2.796 x 10⁷ j N/C

Resultant electric field at D

E = √Ei² + Ej²

E = √[(2.796 x 10⁷)² + (2.796 x 10⁷)²]

E = 3.95 x 10⁷ N/C

Thus, the net electric field at point D is determined as 3.95 x 10⁷ N/C.

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A 67 V power supply is connected to three identical resistors in series. If the current through the resistors is measured at 0.95 A, what is the value of each resistor? Round your answer to 2 decimal places.

Answers

The value of the identical resistors would be 70. 53 Ohms

How to determine the values

We have the formula for resistance to be;

Resistance = Voltage/ current

Voltage = 67 V

Current = 0. 95A

Substitute the values

Resistance =

[tex] \frac{67}{0.95} [/tex]

Resistance = 70.53 Ohms

Thus, the value of the identical resistors would be 70. 53 Ohms

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The north-pole end of a bar magnet is held near a stationary positively charged piece of plastic. How is the plastic affected?.

Answers

When the north-pole end of a bar magnet is held near a stationary positively charged piece of plastic, it remains unaffected.

What is a bar magnet?

A bar magnet is made of ferromagnetic substance that produces

magnetic field.

What are the properties of a bar magnet?

Magnets attract ferromagnetic materials like iron, cobalt and nickel.Like poles repel each other and unlike poles attract each other.The strength of both poles is always the same.When a magnetic material is kept in contact with a bar magnet it acquires the magnetic property.Some materials like gold, silver and water get repelled by magnets.

Since plastic is not a ferromagnetic material or any other material like gold and silver ,they remain unaffected in the presence of magnetic field.

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A vector is 14.4 m long and
points in a 133 degree
direction.
Find the x-component of the
vector.

Answers

The x-component of the given vector is determined as 10.53 m.

X component of the vector

The x-component of a vector is defined as the value of the vector or component of the vector in the x direction.

For a vector of 14.4 m long and pointing in a 133 degree direction.

The x-component of the vector is calculated as follows;

Vx = V cosθ

where;

θ is the angle of inclination measured from positive x axis

θ = 133⁰ - 90⁰ = 43⁰

Vx = 14.4 x cos(43)

Vx = 10.53 m

Thus, the x-component of the given vector is determined as 10.53 m.

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