Answer:
yes
Explanation:
The heater is placed near the floor because the air currents move upwards so the hot air fills up the whole room. Whereas, an air conditioner is placed near the ceiling because the cold breeze tends to settle down. If it is placed near the floor then it will fill just the bottom of the room with cool air.
A cylindrical region of radius R contains a uniform magnetic field, parallel to its axis, with magnitude that is changing linearly with time. If r is the radial distance from the cylinder axis, the magnitude of the induced electric field inside the cylindrical region is proportional to:
The induced electric field inside the cylindrical region is directly proportional to r
What is the electric field?
An electric field is the physical field that surrounds electrically charged particles and exerts a force on all other charged particles in the field.
When a loop of wire is placed in a time-varying magnetic field, an induced electric field arises. This induced electric field allows the flow of current in the loop. There is no potential associated with this induced electric field.Here. a magnetic field with magnitude linearly varies with time.
Radial distance = r
Area of this region, A = π*r^2
Let the induced electric field be E.
Magnetic flux:
∅(B) = B*A
Let the magnetic field be kt,
where k is some constant and t is time.
(B) = kt * (πr^2)
Using Maxwell's equation of electromagnetism,
[tex]\int\limits^a_b {E} \, dr = -\frac{d∅}{dt}[/tex]
[tex]E* 2\pi r = - \frac{d}{dr}(\pi k tr^{2} )[/tex]
[tex]E*2\pi r = -\pi kr^{2}[/tex]
[tex]E = - \frac{kr}{2}[/tex]
Hence
E ∝ r
The induced electric field is directly proportional to r
So, option 2 is correct.
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Two hockey pucks with mass 0.1 kg slide across the ice and collide. Before
the collision, puck 1 is going 15 m/s to the east and puck 2 is going 12 m/s to
the west. After the collision, puck 2 is going 15 m/s to the east. What is the
velocity of puck 1?
A. 12 m/s west
B. 15 m/s east
C. 15 m/s west
D. 12 m/s east
The velocity of pluck 1 is 12 m/s west.
What is the conservation of momentum?The principle of the conservation of the linear momentum states that momentum before collision is equal to momentum after collision.
Now given that;
m1u1 + m2u2 = m1v1 + m2v2
(0.1 * 15) - (0.1 * 12) = 0.1* v + (0.1 * 15)
1.5 - 1.2 = 0.1v + 1.5
0.3 - 1.5 = 0.1v
v = -1.2/0.1
v = - 12 m/s
Hence, the velocity of pluck 1 is 12 m/s west.
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How can you determine where the wavelength released from a transition will fall in the electromagnetic spectrum?
You can change the wavelength into scientific notation and the electromagnetic spectrum will then tell you where it falls.
In physics, the wavelength is the spatial period of a periodic wave—the space over which the wave's shape repeats. It's miles the distance among consecutive corresponding points of the same section on the wave, together with two adjacent crests, troughs, or zero crossings, and is a function of each traveling wave and status wave, in addition to other spatial wave styles.
The inverse of the wavelength is referred to as the spatial frequency. Wavelength is normally designated through the Greek letter lambda (λ). The time period wavelength is also every now and then implemented to modulated waves, and to the sinusoidal envelopes of modulated waves or waves formed via interference of numerous sinusoids.
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A generator coil is rotated one quarter of a full revolution, from θ = 0° to θ = 90°,
in 13.2 ms. The coil has 353 loops, and it is a square 4.62 cm on a side. If the coil
is in a uniform magnetic field of 0.991 T, what is the maximum electromotive force
induced in the coil by the generator?
The maximum electromotive force induced in the coil by the generator is 56.45 V.
Maximum electromotive force induced in the coil
emf(max) = NAB/t
where;
N is number of turnsA is areaB is magnetic fieldt is timeSubstitute the given parameter and solve for maximum electromotive force induced in the coil.
Area of the loop = 0.0462 m x 0.0462 m = 0.00213 m²
emf(max) = (353 x 0.00213 x 0.991) / (13.2 x 10⁻³)
emf(max) = 56.45 V
Thus, the maximum electromotive force induced in the coil by the generator is 56.45 V.
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A 58.5 kg wood board is resting on very smooth ice in the middle of a frozen lake. A 41.7 kg boy stands at one end of the board. He walks from one end of the board to the other end with a velocity of 1.27 m/s relative to the ice in the positive direction. What is the velocity of the board relative to the ice?
The velocity of the wood board which is resting on very smooth ice in the middle of a frozen lake relative to this ice is 0.905 m/s
What is conservation of momentum:It states the amount of momentum remains constant
Momentum of a moving body is the product of mass times velocity.
Formula for momentum:
P = m* vWhen the two objects collides, then the initial collision of the two body is equal to the final collision of two bodies by the law of conservation of momentum.
here,
mass of wood, m=58.5 kg
mass of boy, M=41.7 kg
velocity of the boy V=1.27 m/s
Thus,
The conservation of momentum,
m*v = M*V
substituting the value,
(58.5*v) = 1.27* 41.7
v = 52.95 / 58.5
v = 0.905 m/s
Thus, the velocity of the wood board which is resting on very smooth ice in the middle of a frozen lake relative to this ice is 0.905 m/s.
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Which would require the greater energy; slowing down of the orbital speed of the Earth so it crashes into the sun, or speeding up the orbital speed of the Earth so it escapes the sun
Answer: Speeding up the orbital speed of earth so it escapes the sun require the greater energy.
Explanation: To find the answer, we need to know more about the Orbital and escape velocities.
What is Orbital and Escape velocity?Orbital velocity can be defined as the minimum velocity required to put the satellite in its orbit around the earth.The expression for orbital velocity near to the surface of earth will be,[tex]V_o=\sqrt{gR}[/tex]
Escape velocity can be defined as the minimum velocity with which a body must be projected from the surface of earth, so that it escapes from the gravitational field of earth.The expression for orbital velocity will be,[tex]V_e=\sqrt{2gR}[/tex]
If we want to get into the sun, we want to slow down almost completely, so that your speed relative to the sun became almost zero.We need about twice the raw speed to go to the sun than to leave the sun.Thus, we can conclude that, the speeding up the orbital speed of earth so it escapes the sun require the greater energy.
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Question :
Which of the following has more inertia(mass)
(a) a rubber ball and a stone of the same size?
(b) a bicycle and a train?
(c) a five-rupees coin and a one-rupee coin?
[tex] \\ \\ \\ \\ \\ \\ \\ \\ \\ [/tex]
Please let ZzTheAmrcnNgtMareZz answer
A rubber ball and a stone of the same size are examples which will have more inertia and is therefore denoted as option A.
What is Inertia?This is referred to as the property exhibited by a body in which it has the tendency to remain at rest or in uniform motion.This property is dependent on the mass of the substance as we can deduce that the greater the mass, the greater the inertia and vice versa.
The size of a rubber ball and stone will have different masses in which that of the stone will be greater. This is as a result of the difference in the nature of the substances which are used to make both items mentioned above.
This is therefore the reason why a rubber ball and a stone of the same size as having more inertia(mass) where chosen as the most appropriate choice in this scenario.
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A proud deep-sea fisherman hangs a 69.5-kg fish from an ideal spring having negligible mass. The fish stretches the spring 0.130 m. (a) Find the force constant of the spring.
Force constant = k = 6811 N/m
Given:
mass = m = 69.5 kg
L(initial) = ideal spring length = 12 cm= 0.120 m
L(final) = final spring length = 13 cm= 0.130 m
Two forces acting on the object is k*x and mg
so,
kx-mg=0
kx = mg
k = mg/x
We know that x= displacement = L(final)- L(initial)
0.130-0.120=0.10
k= 69.5×9.8/0.10
k =6811 N/m
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An 80-N crate is pushed a distance of 5.0 m upward along a smooth incline that makes an angle of 30o with the horizontal. The force pushing the crate is parallel to the slope. If the speed of the crate increases at a rate of 1.5 m/s2, find the work done by the force. Group of answer choices 260 J 200 J 1 J 200 kJ 140 J
The work done by the force is 140 J.
Calculation:
It is given that, an 80-N crate is pushed a distance of 5.0 m upward along a smooth incline that makes an angle of [tex]30^\circ[/tex] with the horizontal. The force pushing the crate is parallel to the slope and the acceleration is 1.5 [tex]\text{ m/s}^2[/tex].
It is required to find the work done by the force.
The free-body diagram is shown below,
Here, W=80 N, a=-1.5 [tex]\text{ m/s}^2[/tex]
We can write the net force equation as,
[tex]\begin{gathered}F-W \sin 30^{\circ}=m a \\F-m g \sin 30^{\circ}=\left(\frac{W}{g}\right) a\end{gathered}[/tex]
Here W is the weight of the object, m is the mass of the body, and F is the applied force.
Thus,
[tex]\begin{aligned}F-(80 \mathrm{~N}) \sin 30^{\circ} &=\left(\frac{80 \mathrm{~N}}{9.8 \mathrm{~m} / \mathrm{s}^{2}}\right)\left(-1.5 \mathrm{~m} / \mathrm{s}^{2}\right) \\F &=27.755 \mathrm{~N}\end{aligned}[/tex]
It is known that the work done by the force is calculated as the multiplication of the applied force and the displacement.
Thus the work one is,
[tex]\begin{aligned}W &=(27.755 \mathrm{~N})(5 \mathrm{~m}) \\& \approx 140 \mathrm{~J}\end{aligned}[/tex]
Thus the last option is the correct one.
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Two men standing on the same side of wall and at the same distance from It, such that they are 4oom apart when one fires a gun the other hears the first report in 1.2s and the second in 0.5s after the first. calculate 1) Velocity of sound in air . 2)the perpendicular distance of the men from the wall.
Answer:
1. 571.43m/s
2. 142.9m and 342.9m
Explanation:
1.Take the difference in time.
1.2-0.7=0.7 seconds
Take the distance between them and divide with differnce in time.
400÷0.7=571.43 seconds.
2.Take the time of the two men and divide by two.
0.5÷2= 0.25 secs
1.2÷2= 0.6 secs
multiply each with the velocity.
0.25×571.43=142.9m
0.6×571.43=342.9m
An ideal ammeter would have zero resistance while an ideal voltmeter would have infinite resistance, why?.
Answer: An ideal ammeter would have zero resistance, because to ensure that, there is no voltage drop due to the internal resistance. Similarly, an ideal voltmeter would have infinite resistance, because to ensure that there is no current is drawn by the voltmeter.
Explanation: To find the answer, we need to know about the Ammeter and Voltmeter.
What is an ammeter?An ammeter is a device, that can be used to measure the electric current flows through a circuit in amperes.An ideal ammeter would have zero resistance, because to ensure that, there is no voltage drop due to the internal resistance when it is connected in series to measure the current.What is voltmeter?A voltmeter is a device, that can be used to measure the electric potential difference generated between the terminals of an electric circuit in volts.An ideal voltmeter would have infinite resistance, because to ensure that there is no current is drawn by the voltmeter, when it is connected in parallel to measure the voltage.Thus, we can conclude that, an ideal ammeter would have zero resistance, because to ensure that, there is no voltage drop due to the internal resistance. Similarly, an ideal voltmeter would have infinite resistance, because to ensure that there is no current is drawn by the voltmeter.
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A laser is shone through a double slit and a particular interference pattern is observed on a screen some distance away. If the separation between the openings is increased, the distance between the fringes will
The distance between the fringes (y) will decrease.
What is meant by double slit?
In the double-slit experiment, a beam of light is aimed at a barrier with two vertical slits. After the light passes through the slits, the resulting pattern is recorded on a photographic plate. When one slit is covered, a single line of light is displayed, aligned with whichever slit is open.To solve this problem it is necessary to apply the concepts related to double split conditions. The equation describing this effect is given by
dsinθ = mλ
λ = dsinθ /m
λ = wavelength
d= distance between slits
m = Any integer, representing the repetitions of the spectrum
If θ is small, then sinθ = y/L and the previous equation can be given as
λ = dy /mL
L = Length from screen with slits
y = distance between fringes
From this last equation we can realize that if the separation between the openings (d) is increased, the distance between the fringes (y) will decrease.
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When the absolute value of the price elasticity of demand falls in the range 0 to 1, demand is said to be _____.
When the absolute value of the price elasticity of demand falls in the range 0 to 1, demand is said to be inelastic.
A good or service that has an income elasticity of demand between zero and 1 is considered a normal good and income inelastic. If a good or service has an income elasticity of demand below zero, it is considered an inferior good and has negative income elasticity.
Inelastic is an economic term referring to the static quantity of a good or service when its price changes. Inelastic means that when the price goes up, consumers' buying habits stay about the same, and when the price goes down, consumers' buying habits also remain unchanged.
Price elasticity of demand is a measurement of the change in consumption of a product in relation to a change in its price. A good is elastic if a price change causes a substantial change in demand or supply.
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An 80,000 kg plane is flying at 900 km/h at a height of 10 kilometers. What is its total mechanical energy? Group of answer choices 478 MJ 250 MJ 10,340 MJ 773 MJ
The mechanical energy of the given flying object is 10,340 MJ. So the correct choice is 10,340 MJ.
Mechanical energy: The mechanical energy of an object is the sum of its potential energy and kinetic energy.
The formula for the mechanical energy E is:
E=K+U
where K is the kinetic energy and U is the potential energy.
Kinetic energy: The energy possessed by an object due to the motion.
The kinetic energy is given by the formula,
K=(1/2)*(mv^2)
where m is the mass of the object and v is the velocity of the object.
Potential energy: The energy possessed by an object due to its relative position from a given point.
The potential energy is given by the formula,
U=m*g*h
where g is the acceleration due to gravity and h is the height of the object from the ground.
Substitute K=(1/2)*(mv^2) and U=m*g*h in the formula of the mechanical energy to get the following formula,
E=(1/2)*(mv^2)+m*g*h
Given that m=80000 kg, h=10 km, and v=900 km/h, and the value of g is 9.8 m/s^(-2), the value of the total mechanical energy is,
E=(1/2)*(80,000 kg)(900 km/h )^2+(80,000 kg)*(9.8 m/s^(-2))*(10 km)
Note: 1 km= 1000 m and 1 km/h = 5/18 m/s. 1 MJ = 10^(6) J
E=(1/2)*(80,000 kg)*(900*(5/18) m/s )^2+(80000 kg)*(9.8 m/s^(-2))*(10000 m)
E=(1/2)*(80,000 kg)*(250 m/s)^2+7840*10^(6) J
E=2500*10^(6) J+7840*10^(6) J
E=10340*10^(6) J
E=10340 MJ
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Pure (r)-mandelic acid has has [α]d = 150°. If a mixture of (r)-mandelic acid and (s)-mandelic acid has [α]d = 120°, what is the enantiomeric excess of (r)-mandelic acid in the mixture?
The enantiomeric excess of (r)-mandelic acid in the mixture IS 80%.
The optical rotation of the mandelic acid was measured on a Perkin rotation of the optically active mandelic acid. Ethanol isn't always a suitable solvent for resolution due to the fact the salts are very soluble in it.
Enantiomers excess = (mixture/pure) × 100
⇒ excess enantiomers = +120/+150 × 100
⇒ excess enantiomers = 80%
A Racemic aggregate Is An equal aggregate Of two Enantiomers And Has a specific Rotation of 0° (Optically Inactive) the 2 components of “racemic acid” are (2S,3S)-tartaric acid, that is levorotatory, or (–); and (2R, 3R) tartaric acid, that is dextrorotatory.
Mandelic acid loosens the bonds that adhere the dead or antique pores and skin cells to the pores and skin surface. This allows the shedding of antiques.
The angle of rotation in ranges of the plane of polarization of a ray of monochromatic light that passes via a tube lengthy containing the substance.
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When driving in fog, A. low beam headlights. B. Use high beam headlights for better visibility. C. Use your hour at 10 second intervals. D. Turn on the heat in your vehicle.(1 Point)
The correct alternative is (a) use low beam headlights when driving in fog.
Use of low beam headlights is better than high beam headlights when driving in fog because high beams are aimed higher to maximize the seeing distance and their bright light doesn't provide the clear visibility through the fog. The high beam light bounces back and just reflect back into the eyes of driver resulting in a sharp glare making it difficult for the driver to see through the fog. Low beams are only directed sideward or downward which ensure that the light doesn't reflect back into the eyes while driving through fog. The low beam lights doesn't obscure the vision and prevent collisions by providing clear visibility through the fog.
Hence, it is a good idea to use only low beam headlights while driving through the fog to ensure the correct visibility.
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A new CFD method for determination of translational added mass coefficients of an underwater vehicle
A new CFD method for determination of translational is RANS simulations
What is CFD?Using numerical analysis and data structures, the field of computational fluid dynamics (CFD) studies and resolves issues involving fluid flows. The computations necessary to model the fluid's free-stream flow and its interactions with surfaces constrained by boundary conditions (both liquids and gases) are done on computers. Better answers can be found using high-speed supercomputers, which are frequently needed to address the most challenging issues.
Five prominent CFD methods -
Finite Difference Method (FDM)Finite Volume Method (FVM)Finite Element Method (FEM)Lattice Boltzmann Method (LBM)Smoothed Particle Hydrodynamics (SPH)to learn more about Fluid dynamics go to - https://brainly.com/question/5144636
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According to present scientific understanding of the Milky Way's formation, which of the following statements are true
Halo stars formed before disk stars and the protogalatic cloud(s) contained essentially no elements besides hydrogen and helium.
Halo starsThe hierarchical growth of huge galaxies like the Milky Way results in the natural by-product of extended star haloes. Our galaxy's star halo should contain traces of past merger events if this process is a significant contributor to the galaxy's expansion. However, it is difficult to reliably identify real halo stars. Aims. We have entered a new phase of galactic astronomy with the launch of the Gaia space telescope. Over two million stars the majority of which are in the solar neighbourhood have their locations, parallaxes, and proper motions listed in the initial Gaia data release. This sample will be expanded to include more than 1.5 billion stars in the second Gaia data release, of which 5 million will be fully phase-space characterized stars.
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A relief plane flying horizontally at 65.0 m/s is delivering a
food package to people stranded on an island. If the
island is a horizontal distance of 789 m away,
how high is the plane?
(Unit = m)
22000
Ay (m)
mily
The height of the plane delivering a food package to people stranded on an island is 722.2 m.
Time of motion of the food package
The time taken for the food package to hit the ground level is calculated as follows;
X = vt
where;
X is horizontal distance traveled by the food packagev is horizontal distancet is time of motiont = X/v
t = 789/65
t = 12.14 seconds
Height of the planeh = ¹/₂gt²
where;
h is height of fall of the food package which is height of the planet is time of motion of food packageg is acceleration due to gravityh = (0.5)(9.8)(12.14²)
h = 722.2 m
Thus, the height of the plane delivering a food package to people stranded on an island is 722.2 m.
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Answer:
722.2
Explanation:
Monochromatic light with wavelength 590 nm passes through a single slit 2. 30 ?m wide and 1. 90 m from a screen. Find the distance between the first- and second-order dark fringes on the screen.
The distance between the first and second-order dark fringe is 0.441 m.
Diffraction of a single slit:
When the light wave passes through a single slit of width which is comparable to the wavelength of the light, then the light wave bends at the edges of the slit. This is called diffraction.
Note: It is assumed that the slit is 3*10^(-3) mm wide. 1 nm = 10^(-9) m and 1mm = 10^(-3) m.
The dark fringes are obtained at the position which satisfies the equation,
d*sinθ = mλ
where d is the slit width, λ is the wavelength of the wave, θ is the angle of diffraction and m denotes the order of the dark fringe.
For first order fringe (m=1), the angle of diffraction θ₁ is,
d*sinθ₁ = λ
sinθ₁ =λ/d
Substitute λ=590 nm, d=3*10^(-3) mm, and solve it.
sinθ₁ =(590 nm)/(3*10^(-3) mm)
sinθ₁ =(590*10^(-9))/ (3*10^(-3)*10^(-3) m)
sinθ₁ =0.196
θ₁ =11.03 degree
Similarly, for second-order fringe (m=2), the angle of diffraction θ₂ is,
d*sinθ₂= 2λ
sinθ₂ =2λ/d
Substitute λ=590 nm, d=3*10^(-3) mm, and solve it.
sinθ₂ =(2*590 nm)/(3*10^(-3) mm)
sinθ₂ =(2*590*10^(-9))/ (3*10^(-3)*10^(-3) m)
sinθ₂ =0.393
θ₂ =23.14 degree
From geometry, the positions x₁ and x₂ of the first and second-order dark fringe from the center of the screen are x₁=Dtanθ₁ and x₂= Dtanθ₂ where D is the distance of the screen from the slit. The distance s between the first-order and second-order dark fringe is then given by,
s=D(tanθ₂-tanθ₁)
Substitute D=1.90 m, θ₁=11.03 degree, and θ₂=23.14 degree in this equation and solve it.
s=1.90*(tan(23.14)-tan(11.03))
s=1.90*(0.427-0.195)
s=0.441 m
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A drop of oil is floating between two parallel plates with a separation of 8.3 mm. If the mass of the oil drop is 2.7 x 10-15 kg, and its charge is -9.612 x 10-19 C, determine the voltage across the charged plates and determine which plate is positive.
The voltage across the charged plates is 228.5 V.
Voltage across the platesV = Fd/q
V = (mgd)/q
where;
m is mass of the oilg is acceleration due to gravityd is the distance of separationq is chargeV = (2.7 x 10⁻¹⁵ x 9.8 x 8.3 x 10⁻³) / (9.612 x 10⁻¹⁹)
V = 228.5 V
Thus, the voltage across the charged plates is 228.5 V.
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The path of a charged particle moving parallel to a uniform magnetic field will be a:______.
The path of a charged particle moving parallel to a uniform magnetic field will be straight line
Force on a charged particle moving in a magnetic field can be calculated by = q.(v*B )
q = charge of the particle
v = velocity of the particle
B = magnetic field
theta = angle between v and B
q . (v B sin (theta) )
Since, particle is parallel to the magnetic field
hence , theta = 0°
so sin(theta) = sin 0° = 0
hence , force = 0
since , there is no force acting on the particle it will remain in that motion in hat it was when it initially came in the magnetic field . Hence It will be moving along a straight line path because the magnetic force on the charged particle is zero.
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The kinetic friction force that a horizontal surface exerts on a 60.0-kg object is 50.0 n. if the initial speed of the object is 25.0 m/s, what distance will it slide before coming to a stop?
Answer:
KE = 1/2 M v^2
KE = 60/2 * 25^2 = 18750 Joules initial Kinetic Energy
W = Fs * d distance thru which friction acts
d = W / Fs = 18750 J / 50 N = 375 m
Jim climbs up a rope from an initial height of 1.30 m to a final height of 3.20 m. If Jim's mass is 45 kg, what is the change in his gravitational potential energy? Group of answer choices 1980 J 187 J 85.5 J 838 J
The change in the gravitational potential energy of the boy is 838 J.
So the correct choice is 838 J.
What is gravitational potential energy?
The energy possessed by an object due to its position from the chosen reference point when gravity is acting on that object is called gravitational potential energy.
The formula to calculate the difference in the potential energy is given by the formula,
U=m*g*h
where U is the difference in the potential energy, m is the mass, g is the acceleration due to gravity, and h is the height difference between the initial height and the final height.
The height difference is given by the formula,
h=h2-h1
where h2 is the final height and h1 is the initial height.
Given that the initial height is 1.30 m and the final height is 3.20 m, substitute h1=1.30 m and h2=3.20 m in the formula of height to calculate the height difference.
h=3.20-1.30
h=1.90 m
The mass of the boy is 45 kg and the value of g is 9.8 m/s^2. Substitute m=45 kg, g=9.8 m/s^2, and h=1.90 m in the formula of the gravitational potential energy to calculate the difference in the gravitational potential energy.
U=45*9.8*1.90
U=837.9 J
U≈838
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A ray of light strikes a boundary between two transparent materials, and there is no transmitted ray, as shown in the figure. What can you conclude about the indices of refraction of these two materials
Answer:q
Explanation:
A 150 g piece of metal has a specific heat capacity of 0.845 J/g°C. If it takes 3.30x 103 J to heat the metal to 120°C, the initial temperature of the metal was
The initial temperature of the metal was 94.24⁰C.
Initial temperature of the metal
The initial temperature of the metal is calculated as follows;
Q = mcΔθ
where;
Δθ is change in temperatureΔθ = Q/mc
Δθ = (3,300) / (0.854 x 150)
Δθ = 25.76⁰C
Δθ = T₂ - T₁
T₁ = T₂ - Δθ
T₁ = 120 - 25.76
T₁ = 94.24⁰C
Thus, the initial temperature of the metal was 94.24⁰C.
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Does your experimental density of the unknown liquid agree with the true value? if no, give reasons for the discrepancy. Do not include operator errors
The reasons for the discrepancy in the experimental density of the unknown liquid agree with the true value can be instrument not having same levels , Temperature Effects , Kind of scales used and Shape of objects used for measure .
According to the question
Discrepancy:
The state or quality of being discrepant or in disagreement, as by displaying an unexpected or unacceptable difference; inconsistency.
Density:
Density is mass per unit volume, so when measuring density, you find the mass of the object and divide it by its measured volume.
All measurements include some uncertainty, however, and certain kinds of errors can increase the uncertainty in your calculation.
The reason of discrepancy in the experimental density of the unknown liquid agree with the true value can be:
1. Use of instrument not having same levels
2. Temperature Effects as Density varies with temperature .
3. Kind of scales used for measures
4. Shape of objects used for measure .
Hence, the reasons for the discrepancy is instrument not having same levels , Temperature Effects , Kind of scales used and Shape of objects used for measure .
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When a voltage of 12 V is applied to a resistor, a current of 2.5 A passes through it. What is the resistance of the resistor
Answer:
4.8 Ω
Explanation:
Ohm's law
V = IR
or V/I = R
12/2.5 = R = 4.8 Ω
A 2.50 × 105 w motor is used for 26.4 s to pull a boat straight toward shore. how far does the boat move toward shore if a force of 4.20 × 104 n is applied by the motor? 157 m 1,590 m 1.11 × 106 m 6.60 × 106 m
The distance travelled by the boat towards shore if a force of 4.20x10⁴N is applied is 157.14 m.
Power is a unit of measurement for the amount of work completed in a particular period of time; it may be computed using both work and time. Divide the amount of work by the length of time it takes to do the work to find power. The unit of work is the joule. The unit of power measurement is known as joules of work per second.
The power of the motor = 2.50x10⁵ W
= 2.50x10⁵ N m/s
The time it takes to pull the boat = 26.4 s
The force applied = 4.20x10⁴ N
Using the formula;
[tex]d = \frac{Pt}{F}[/tex]
where,
P = Power
t = Time taken
F = Force applied
d = Distance travelled
The distance traveled by the boat = 2.50x10⁵ N m /s (26.4 s) /(4.20x10⁴ N)
=157.14 m
Therefore, the distance travelled by the boat if a force of 4.20x10⁴N is applied is 157.14 m.
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A conducting loop in the form of a circle is placed perpendicular to a magnetic field of 0. 50 t. If the area of the loop decreases at a rate of 3. 0 × 10-3 m2/s, what is the induced emf in the loop?
The induced emf in the loop is -1500 μ V or - 0.0015 V .
According to the question
A conducting loop in the form of a circle is placed perpendicular to a magnetic field of 0. 50 t.
i.e
Magnetic field (B) = 0. 50 T
Area of circle or loop = [tex]\pi r^{2}[/tex]
Now,
The area of the loop decreases at a rate of 3. 0 × 10⁻³ m/s
i.e
dA = 3. 0 × 10⁻³ meter²
dt = 1 sec
As per the formula of Induced e.m.f in the loop
emf is dependent on number of turns of coil, shape of the coil, strength of magnet and speed with which magnet is moved. Emf is independent of resistivity of wire of the coil.
[tex]e=-B*\frac{dA}{dt}[/tex]
where A is the area of the loop.
Now ,
Substituting the values in the formula
[tex]e=-B*\frac{dA}{dt}[/tex]
[tex]e= - 0.50 *\frac{ 3 * 10^{-3}}{1}[/tex]
e = - 0.0015 V
OR
e = -1500 * 10⁻⁶ V
e = -1500 μ V
Negative just signifies emf will such be induced that current induced will oppose change in magnetic field though it
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