It takes 6 people pulling with a force of 500. N each to begin moving the opposing team which was pulling with a combined force of 2500. N during a match of tug-of -war. If the total mass of both teams was 2000. kg, what was the force due to static friction? HELP ME .

Leveling the amount of work done at each work station is an example of Value Stream Mapping.

Value stream mapping was developed out of lean manufacturing, which companies use to create a visual guide of all the components required to deliver a product or service for the purpose of analyzing and optimizing the entire process.

The process of creating a value stream map takes all the people, processes, information, and inventory you need and presents them in flowchart form.

Learning core Lean Six Sigma (LSS) tools can help you become more attractive to new employers or increase the value you offer in your current workplace in a number of ways, including:

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The angle of the rope makes with the vertical when the ball's kinetic energy is halved is 14.78°.

Parameter

When the ball is pushed horizontally and moves from point A to point B where the ball's kinetic energy halves, the law of conservation of energy applies.

Mechanical energy at A = Mechanical energy at B

Epa + Eka = Epb + EKb

Eka - Ekb = EPb - Epa

[tex]Ek_A -\frac{1}{2}Ek_A = mgh_B - mgh_A[/tex]

[tex]\frac{1}{2}Ek_A = mg \: (h_B - h_A)[/tex]

[tex]\frac{1}{2} \times \frac{1}{2} m v_A^2 = mgh[/tex]

[tex] \frac{1}{4} v_A^2 = gh[/tex]

[tex]gh = \frac{1}{4} \times 1.3^2[/tex]

gh = 0.4225

[tex]h = \frac{0.4225}{9.8}[/tex]

h = 0.043 m

Look at the picture

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The animal with the lowest bar on that bar graph would be the mountain lion.

A bar graph is a visual representation of data that uses rectangular bars having lengths according to the values they represent. A bar graph, which can be shown horizontally or vertically, compares sets of data.

According to the question, mountain lions had the lowest bar on a bar graph since they have the smallest population 150 of all the species.

Bar graphs are a way of representing the numerical data sets of different aspects on a graph paper that allows easy calculations and conclusions.

On the graph sheets, the quantitative method is shown as bars, which show their values.

The answer to the query indicated that Mountain Lions would have the graph's lowest bar.

The picture provided below shows the plotted and associated bar graph again for the aforementioned query.

The vertical or y-axis represents the animal population, while the horizontal or x-axis shows the various species of animals.

Mountain lions are the species with the least amount of residents in the area.

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The question is -

If the data below were put into a bar graph, which animal would have the lowest bar on the bar graph? Number of Individuals in a Rocky Mountain Forest Organism Population Mountain lions 150 Bobcats 300 Coyotes 10,000 Deer 25,000 mountain lions bobcats coyotes deer Mark this and return Save and Exit.

Answer: the answer is A

Explanation:i got it from a friend it was right

The load of 1.8 N will give it an extension of 12cm.

Amount of force required to increase unit length of a spring is known as spring constant. Si unit of spring constant is Newton/meter.

Given parameters:

Loads on the spring; F₁ = 7.5 N.

Increase in length of the spring; x₁ = 50 cm = 0.5 m.

So, spring constant of it; k = F₁/x₁ = 7.5/0.5 N/m = 15 N/m.

Hence, to extent it of 12 cm; required load

= spring constant × increase in length

= 15 N/m × 12 cm.

= 15 N/m × 0.12 m.

= 1.8 N.

So, the required load is 1.8 N.

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When rain is falling vertically at 8m/s then the speed of the car is calculated to be 4.618 m/s.

The velocity of the raindrops adds to the velocity of the car to produce a velocity of the rain relative to the car.

As the surface becomes rougher, friction increases and on rainy days, we are more likely to slip because water acts as a lubricant between feet and the ground. Dry friction is converted to fluid friction by rainwater.  Rain drops have a uniform type of motion

Given rain is falling vertically with 8 m/s speed

and rain drop makes an angle of  30°

As we know that, tan∅ = V (horizontal) / V (vertical)

Hence,  V (horizontal)= tan ∅ *  V (vertical)

= tan (30° ) * 8

speed of the car​ = 4.618 m/s.

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We cannot. The precise location of the electron cannot be predicted. The likelihood of where an electron will land can be predicted.

Only the likelihood of an electron being present at different sites can be predicted. The probability distribution can even tell you the average location of several electrons, but quantum theory cannot tell you the precise location of the electron. It can only give you a rough sense of where the one electron will end up.

The wave effectively splits into two new waves as it travels through both holes, each of which spreads out from a different slit. Then, there is interference between these two waves. A peak and a trough may occasionally cross paths where they cancel one another out.

The double-slit experiment, which was conducted to study the characteristics of light in the eighteenth century, has subsequently been found to illustrate the duality of photons as well as the ideas of superposition and quantum interference.

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To determine the total number of microstates, we need to determine the density of states in one dimension. The density of states function (g(E)) is the number of microstates per unit length per unit energy range.

In one dimension for a particle of mass 'm' in a box of length 'L' we have the energy given
E: hk2 2

From the boundary conditions of the cuboid at x=0 and x=L, we deduce that 'k' can take on discrete values ​​in units of 2π/L. Consequently, the quantum states are in units of L/2π. The number of states 'N' for momentum 'k' will be equal to,

2KL N = TT

And the energy E at any momentum "k" is given by

E: hk2 2

The density of states in 1D is given by

9(E) 1 IN L DE = 1 DN dk L dk de

we know

NP 27 dk 1

AND,

hk DE Ε dk dk dЕ = m hk m

Notation in terms of energy E,

dk DE -m 1/2 E-1/2 -1/2

The density of states will be

9(E) 1 dN 1 dN dk IDE = I dk DE L L dE V2 m1/2E-12 πh

The total number of microstates at energy 'E' is,

2m Z(E) = [” 9(E)E = Z dE = E-1/2 DE 6.* -12dE = 22m VE ић пh

(i) A two-particle system will have the number of microstates will be,

Z(E) = 21(E1Z2E - E1)

where Z1 and Z2 are the microstates due to particle 1 and particle 2 calculated above. E1 is the energy of particle 1, so the energy of particle 2 is E-E1.

(ii) For indistinguishable particles, the number of microstates will be

Z(E) 21(E1)Z2(E – E1) 2!

​​​​where Z1 and Z2 are the microstates caused by particle 1 and particle 2, respectively, calculated as above. E1 is the energy of particle 1 and (E-E1) is the energy of particle 2. 2! it comes as a result of the fact that if we exchange two particles, due to their indistinguishability, the result will be the same.

E is the total energy of the system for both the above cases.

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Answer: As soon as it leaves the barrel.

Explanation:

A bullet fired from a rifle begins to fall immediately upon leaving the barrel. Despite its initial forward momentum, the bullet is subject to the force of gravity.

The gravitational force acts vertically downward and causes the bullet to accelerate downward due to its free fall. However, due to its initial high velocity, the bullet's downward acceleration is minimal compared to its forward motion. As a result, the bullet follows a curved trajectory known as a ballistic trajectory.

Over time, the effects of gravity become more significant, causing the bullet to gradually descend and eventually hit the ground, following a parabolic path.

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Amplitude does not affect wave speed because amplitude is a measure of the wave energy as it oscillates. This implies that movement of the wave is separate from the movement indicated by the sleep of the wave.

By increasing the tension, the wave speed increases and hence frequency increases. Greater tension implies greater acceleration of particles, which means greater speed of particles and hence greater speed of wave.

As we know, speed = frequency * wavelength. This clearly means that speed is directly proportional to the frequency such that when frequency increases, speed also increases and vice versa.

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Answer:

Work = 196 Joules (1 kg*m^2/sec^2 is 1 Joule)

Explanation:

Work, W, is defined as force. F, times displacement, d.  

  W = Force*displacement

In the worker's case, the force he/she is struggling against is Earth's gravity's acceleration, g, (9.8 m/sec^2) times the mass, m.

Force = mg

Force = (10kg)*(9.8 m/sec^2) = 98 kg*m/sec^2

Use this force in the work calculation.

W = Force*displacement

The displacement is 2 meters.

Work = (98 kg*m/sec^2)*(2 meters) = 196 kg*m^2/sec^2

1 kg*m^2/sec^2 is 1 Joule

Work = 196 Joules

Answer: B. Energy

Explanation:

The Energy is the quantity that only depicts the magnitude and not the direction, hence it is a scalar quantity, so option B is correct.

In physics, energy is the capacity to do work. It might be potential, kinetic, thermal, electrical, chemical, radioactive, etc. Heat and work are further examples of energy being transferred from one body to another. Once it has been transmitted, energy is always allotted based on its nature. Thus, heat transmission could result in thermal energy while effort could produce mechanical energy.

The scalar quantity means they have only the magnitude and no direction. The velocity of any object tells the speed at which it is moving and its direction also, and the force applied to an object also tells the magnitude with direction, the momentum of an object is dependent on the force, so it is also a vector quantity

Therefore, Energy is the quantity that only depicts the magnitude and not the direction, hence it is a scalar quantity.

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Answer:

2. The object must have zero average acceleration over the interval.

Explanation:

Notes:

-Velocity can have zero change if it is either at rest or moving at a constant velocity. This also means there is zero acceleration (acceleration is any change in velocity).

-Velocity is also speed and direction, so if it changes direction (for example: moving backward or in a circle) it is not constant even if it has a constant speed. It also means the object is accelerating.

1: Nothing can be determined without additional information.

Incorrect, because it is solvable by the process of elimination.

2: The object must have zero average acceleration over the interval.

Correct, because zero acceleration equals zero change in velocity.

3: The object must be changing position.

Incorrect, because you don't know whether or not the object is accelerating.

4:  The object must have zero average velocity over the interval.

Incorrect, because this implies it is at rest. To have zero change, it can be at rest OR moving at a constant velocity.

5:  The object must have constant velocity over the interval.

Incorrect, because zero change in velocity can mean either be at rest OR moving at a constant velocity.

6: The object must begin and end at the same position.

Incorrect, because to begin and end at the same position implies that it was at rest or it changed direction while moving to end at the same position. (see Notes above for explanation)

7: The object must have constant acceleration over the interval.

Incorrect, because you can't have zero change in velocity if there is acceleration (Acceleration is any change in velocity).

8: The object must be at rest.

Incorrect, because to have zero change, it can be at rest OR moving at a constant velocity.

Answer:

Light can travel through a glass or through a vacuum

The moment of inertia of the boxer's forearm will be 0.525kg.[tex]m^{2}[/tex]

In physics, it means quantitative measure of the rotational inertia of the body. As an example, the opposition that the body exhibits to having its speed of rotation about an axis altered by the application of a torque (turning force). The axis may be internal or external and may or may not be fixed.

From the question given, the triceps muscle in the back of the upper arm extends the forearm of a professional boxer when he extends his arm,
Torque generated due to this force is,

τ = F * r
τ = torque is generated

F = force exerted = 2903n
r = the radius of the lever arm = 2.35cm = 0.0235m

Now let's use the torque formula
τ = 2903N * 0.0235m
τ = 68.2205 N.m

Next, we want to find the moment of inertia of the boxer's forearm by calculating the relation between torque and moment of inertia and angular acceleration,

τ = torque = 68.2205Nm
I = moment of inertia
α = angular acceleration = 130 rad / s²

τ = Iα
68.2205 = I*130rad/s²
I = 0.525 kg.m² (rounded)

Therefore, the value of moment of inertia is 0.525kg.m²

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The force needed to bring a car to rest from a speed is 2,541 Newton.

The formula in non-uniform motion

v = u + at

v² = u² + 2ad

[tex]d = u \times t + \frac{1}{2} \times a \times t^2[/tex]

Because the final speed is km/h, we must convert it into m/s

v = 85.0 km/h

v = [tex]85.0 \times \frac{1 \: km}{1 \: hour}[/tex]

v = [tex]85.0 \times \frac{1,000 \: m}{3,600 \: s}[/tex]

v = [tex]\frac{850}{36}[/tex]

v = 23.6 m/s

Calculate the acceleration

v² = u² + 2ad

23.6² = 0² + (2×a×15)

556.96 = 230a

[tex]a = \frac{556.96}{230}[/tex]

a = 2.42 m/s

Formula to find the force F=ma

F = ma

F = 1,050×2.42

F = 2541 Newton

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A cylindrical resistor of radius 4.5 mm and length 2.0 cm is made of material that has a resistivity then current density J is  1.12 × [tex]10^{5}[/tex]

Since P = i^2 r = (J^2) (A^2) R

J = 1/A [tex]\sqrt{P/R}[/tex]

Current density (J)  = 1.12 × [tex]10^{5}[/tex]

A material's electrical resistivity, also known as specific electrical resistance or volume resistivity, is a key characteristic that quantifies how effectively it resists electric current. A substance that permits electric current to flow easily has a low resistance. The Greek letter is often used to signify resistivity (rho). Ohm-meters (m) are the metric unit for electrical resistivity.  For instance, the resistivity of a material is 1 m if it has sheet contacts on two of its opposing faces and has a 1 resistance between them.

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Using the concepts of gravitation, we find that it is true that tides are the periodic short term change in the height of the ocean surface at a particular place, generated by the long wavelength progressive waves that are caused by  interaction of gravitational force of the moon and sun.

Gravitational force is one of  basic forces of nature. It is a force that acts between two bodies and it is always attractive in the nature. Gravitational force is the force with which the objects are attracted to the centre of  earth. The motion of the planets and the moon are  governed by this force

Kepler’s first law All the planets will revolve around the sun in an elliptical orbit with the sun at one of the focus.

Hence, tides are the periodic short term change in the height of  the ocean surface at a particular place, generated by the long wavelength progressive waves that are caused by  interaction of gravitational force of the moon and sun is true.

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The ball's initial velocity  is  14 m/s

Since the equation of motion we referring to for  calculating  the initial velocity are :

s=ut+1/2at²  ....1

v²= u²+2as .... 2

where u and v are initial and final velocity, t is the time taken, a is the acceleration due to gravity and s is the distance or we can also  say the height .As we are given h₁ and  h₂ which are 2.45 m and  7.45 m and the time is taken, t which is  1.45 s, and at last we are having a = -9.8ms^-2

using the 2 equations, we get  

v₁= √(u²−2gh₁),

from equation 1, we get

h₂ =√(u₂−2gh₁t)−1/2gt₂

there the initial velocity will be:

u= √(((h₂+1/2gt²)/t)²+2gh1

 =√(((7.35+1/2*9.80*(1.45)^2)/1.45)^2+2×9.80×2.45)

 = 14

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The third snowman will be placed at a distance of 2.1m from the 15.0 kg mass such that the net gravitational force on it by the other two is zero .

Mass of the snowman 1 = M1 = 15 kg

Mass of the snowman 2 = M2 = 20 kg

Distance between both the masses = r = 4 m

Gravitational force is the force that attracts any two objects of mass.

where G is the gravitational force constant,

M1 and M2 are the masses of the two different bodies respectively,

r is the distance between the masses.

F = [tex]\frac{GM1M2}{r^{2} }[/tex]

Let the mass M3 be the mass which lies between the masses such that the net gravitational force on it by the other two is zero.

F = [tex]\frac{GM1M3}{(r-d)^{2} }[/tex]  = [tex]\frac{GM2M3}{(d)^{2} }[/tex]

here 'd' is the distance at which the mass M3 will be placed such that the net gravitational force on it by the other two is zero.

[tex]\frac{GM1M3}{(r-d)^{2} }[/tex]  = [tex]\frac{GM2M3}{(d)^{2} }[/tex]

[tex]\frac{M1}{(r-d)^{2} }[/tex]  = [tex]\frac{M2}{(d)^{2} }[/tex]

[tex]\frac{15}{(4-d)^{2} }[/tex]  = [tex]\frac{20}{(d)^{2} }[/tex]

3[tex]d^{2}[/tex] = 4[tex](4-d)^{2}[/tex]

3[tex]d^{2}[/tex] = 4 (16 + [tex]d^{2}[/tex] - 2*4*d)

3[tex]d^{2}[/tex] = 64 + 4[tex]d^{2}[/tex] - 32d

[tex]d^{2}[/tex] - 32d + 64 = 0

On solving the above quadratic equation we get the values of d as;

d1 = 29.

d2 = 2.1

Since the d is the distance between the two masses therefore it must be less than 4 m, therefore d2 will be considered as the value of d.

Hence the mass M3 should be placed at a distance of 2.1 m away from the mass M1 to get zero as the net gravitational force

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Formula of Coefficient of friction= F/N

Force applied on the block =47N (Provided in the question)

Mass of the body=15kg (Provided in the question)

Normal force applicable on the body(N)=m x g

N= m x g

Where N represents the Normal Force, m the mass of the body and g represents the gravitational force.

N= 15 x 9.8

N=147N

When a force is applied on a body that is less than that of the Limiting force ( the maximum static friction that can be there) then the friction force produced as a reaction to that force is equal and opposite in nature, acting on the same body.

Since a 47N force is applied on the block a static friction force of the same value will pull the body in the opposite direction.

Thus force due to Friction=47 N

Coefficient of Friction= Friction/ Normal Force

Coefficient of friction =47/147

coefficient of friction=0.319

coefficient of friction≈0.32

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Answer:Use Bungee Cord Power. Use the tension of bungee cords as opposed to springs to power your catapult.

Shoot From the Best Angle. Create an arm break that stops the arm at a 45-degree angle from the floor.

Explanation:

Answer:

10 m/s

Explanation:

Kinetic energy= [tex]\frac{1}{2}[/tex]mv² where m is mass and v is velocity.

We have to make v the subject so we should rearrange the equation

K=[tex]\frac{1}{2}[/tex]mv²

v²= [tex]\frac{K}{0.5*m}[/tex] (use algebra)

v²= 7/0.5×0.140

v²=100

v=√100

v=10 m/s

We can confirm this by using the kinetic energy formula.

K=[tex]\frac{1}{2}[/tex]×0.140×10²

K= 7 J

Hence it is proved that velocity is 10 m/s

With wavelengths of around 10-1000 m, radio waves used by cell phones to communicate with cell towers are far too big to be ionizing. In reality, WiFi runs at very specific frequencies, 2.4 GHz or 5 GHz, which correspond to wavelengths of 12 cm or 6 cm, respectively.

Since radiofrequency waves are electromagnetic fields rather than ionizing radiation like X-rays or gamma rays, they cannot ionize or destroy chemical bonds in living organisms.

The signal is transformed back into the data that was first sent by the transmitter when the radio waves reach a receiver. Your voice is sent through radio waves to the person you are contacting when you use a cell phone as a transmitter.

The primary means of communication between mobile phones and neighboring cell towers is through RF waves, an electromagnetic spectrum energy type.

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☆ Hello ☆

We first apply the data to the problem.

Data:

Then, we apply the formula that is.

Formula:

Finally we develop the problem.

Developing:

The distance traveled is 400 kilometers.

Uniform line movement

Rectilinear uniform motion is one in which an object moves in a straight line, it is a single direction, with a constant speed. When we speak of constant speed we mean that the movement maintains the same speed; that is, the object does not move faster or slower, always at the same speed.

We have that the data is:

Speed (V) = 80 km/h

Distance (d) = ?

Time (t) = 5 h

The formula for uniform motion is:

[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{V=\frac{d}{t} } \end{gathered}$} }[/tex]

We clear for the distance

[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{d=v*t} \end{gathered}$} }[/tex]

[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{d=80\ \frac{km}{\not{h}}*5\not{h} } \end{gathered}$}}[/tex]

[tex]\boxed{\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{d=400 \ km} \end{gathered}$}}}[/tex]

Answer:

1875 J

Explanation:

kinetic energy= [tex]\frac{1}{2}[/tex]×mass×velocity²

K.E=[tex]\frac{1}{2}[/tex]mv²

K.E=[tex]\frac{1}{2}[/tex]×150×5.0²

K.E= 1875 J

Acceleration: the rate at which the speed and direction of a moving object vary over time.A point or object going straight ahead is accelerated when it accelerates or decelerates.

Three different accelerated motion types exist: average acceleration, non-uniform acceleration, and uniform acceleration.

a = F / m

1 N = 1 kg•m/s²

F = ma; where F = force in newtons (N), m = mass in kg, and a = acceleration in m/s².

Known and Unknown

F = 3000 N = 3000kg•m/s²

m = 1200 kg

a = F/m

a = (3000 kg•m/s²)/(1200 kg)

Kilograms cancel.a =  2.5m/s²

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Answer:

A quality of matter that is unrelated to a change in its chemical makeup is called a physical property.

Examples of physical properties of matter:

Physical properties are any qualities of matter that may be felt or seen without changing the sample's chemical composition.

Due to the wide range of features that make up physical attributes, they are further separated into intensive and extensive as well as isotropic and anisotropic categories.

Any characteristic that can be recognized and measured by sight, hearing, touch, smell, or other senses without evoking a chemical reaction is referred to as a physical property. Examples of physical traits are:

Color, Shape, Volume, Density, Calorific value, Boiling point, Viscosity, Pressure, Solubility, electrical current

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The wise and economic use of energy sources is the best way of conserving existing energy sources because it ensures that energy sources that are not renewable such as petroleum are effectively managed so that they last for a longer time.

The conservation of resources refers to the various steps ad method employed to ensure that the existing resources are available for a long time and for future generations.

Conservation of energy sources involves effective and efficient use and management of energy sources so that they last longer. One way is the use of renewable energy.

One of the most important ways of the conservation of resources is the process of recycling to ensure that resources are reused.

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The number of elements pictured in the above image is 3 (option C).

Element are any one of the simplest chemical substances that cannot be decomposed in a chemical reaction or by any chemical means and made up of atoms all having the same number of protons.

There are about 118 chemical elements, each with its own type of atom. Everything in the universe contains the atoms of at least one or more elements. The periodic table lists all the known elements, grouping together those with similar properties.

According to this question, elements are represented by different colours. Each colour represents each element.

The three colours are as follows:

This means that there are three elements in the above image.

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The best model according to vespr  model has the best arrangement of a given number of electron domains and is the one with less repulsion among the  electrons

The VESPR model is also known as VSEPR theory or valence shell electron pair repulsion theory. This model provides a three-dimensional structure for the arrangement of electrons within an atom. According to this model, valence shell electrons participate in chemical bonding processes. Molecular geometry shows that only valence shell electrons participate in ionic or molecular bonding.

The theory is based on the premise that repulsion between the pairs of valence electrons in all atoms and the atoms will always tend to arrange  themselves in a manner in which this electron pair repulsion is minimized

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