John 450 words in half an hour. How many words would he type in 7 minutes?

That's possible when function tends to zero

[tex]\\ \rm\hookrightarrow 0.25x^2-x+9.5=0[/tex]

[tex]\\ \rm\hookrightarrow 1/4x^2-x+19/2=0[/tex]

[tex]\\ \rm\hookrightarrow x^2-x+38=0[/tex]

[tex]\\ \rm\hookrightarrow x=\dfrac{1\pm\sqrt{1-152}}{2}[/tex]

[tex]\\ \rm\hookrightarrow x=\dfrac{1\pm\sqrt{151}i}{2}[/tex]

Answer:

8.5 ft

Step-by-step explanation:

[tex]f(x) = 0.25x^2 - x + 9.5[/tex]

To find the minimum point of the function, differentiate:

[tex]f'(x) = 0.5x - 1[/tex]

set to zero and solve for x:

[tex]f'(x) =0\\ \implies0.5x - 1=0\\\implies x=2[/tex]

Substitute found value of x into function to find y (height):

[tex]f(2) = 0.25(2)^2 - 2 + 9.5=8.5[/tex]

Therefore, the lowest point on the bottom edge of the banner is 8.5 ft above the floor.

Answer:

square root graph

Step-by-step explanation:

this is the graph given by a square root function

Answer: 52 degrees

Step-by-step explanation:

Answer:

1m=100cm

Step-by-step explanation:

do it correctly, sooo ya

Answer:

B

Step-by-step explanation:

among the following below which of these represents a plane screen of a cellphone .

Answer:

Step-by-step explanation:

Givens

Greeting Card = 3.79

Total Cost = 5.11

Post cards = x

Equation

Total Cost = Greeting Card + 4x

Solution

Substitute the gives into the equation

5.11 = 3.79 + 4x                       Subtract 3.79 from both sides

5.11 - 3.79 = 3.79 - 3.79 + 4x  Combine

1.32 = 4x                                  Divide by 4

1.32/4 = 4x/4

x = 33

Each post card costs 0.33 dollars

Answer:

The answer is B- 10h( h+3+5j) AND C- 2(5h+15+25j)

Answer:

The maximum height (vertex) is at (0,256), which is also when it began (Y-Intercept). It will take 4 units for it to hit the ground.

Let us know how you do on the test.

Answer:

The value of x round to the nearest tenth is 12.04

Step-by-step explanation:

We have used trigonometric ratios to calculate the required value.

Answer:

  14

Step-by-step explanation:

The triangle inequality is usually expressed as ...

  a +b > c

for any permutation of a, b, c.

Here, that would mean ...

  1 + 14 > c

  c < 15

The largest whole-number value that the third side (c) can have is 14.

_____

Additional comments

Some authors write the triangle inequality as ...

  a +b ≥ c

If you use that version, the longest side could be 15. Such a "triangle" would look like a line segment, and have zero area.

__

We can also check the shortest length:

  c +1 > 14

  c > 13

The smallest whole-number value for the shortest side is also 14. That is, the only triangle with whole-number side lengths of 1 and 14 will be an isosceles triangle with two sides of length 14.

Answer:

0.0073

Step-by-step explanation:

<3

Answer:

0.0025

Step-by-step explanation:

This is because , you have the number 75, and dividing that by 3 is 25, but since our number is 0.75, that means we are adding the 2 zeros from our 300 and add it on to be to 0.0025, this won’t work in some situations.

Hope that helps!

The mistake that Anja made during the simplification of the considered expression is given by: Option C:  She subtracted the coefficients instead of dividing them

Constants who are in multiplication with variables are called coefficients of those variables.

For example, in [tex]10x^2[/tex] we have 10 as coefficient of [tex]x^2[/tex]

Those variables who have got no visible coefficient has 1 as their coefficient. Thus, [tex]x^2[/tex] has got its coefficient as 1. It is true since 1 multiplied with any number is that number itself.( [tex]x^2 = 1 \times x^2[/tex] )

If we have [tex]a^b[/tex] then 'a' is called base and 'b' is called power or exponent and we call it "a is raised to the power b" (this statement might change from text to text slightly).

Exponentiation(the process of raising some number to some power) have some basic rules as:

[tex]a^{-b} = \dfrac{1}{a^b}\\\\a^0 = 1 (a \neq 0)\\\\a^1 = a\\\\(a^b)^c = a^{b \times c}\\\\ a^b \times a^c = a^{b+c} \\\\^n\sqrt{a} = a^{1/n} \\\\(ab)^c = a^c \times b^c[/tex]

For the considered situation, the expression that Anja is simplifying is:
[tex]\dfrac{10x^{-5}}{-5x^{10}}[/tex]

Anja simplified it to [tex]\dfrac{15}{x^{15}}[/tex]

She performed operations with variable 'x' correctly since

[tex]\dfrac{x^{-5}}{x^{10}} = \dfrac{1}{x^5} \times \dfrac{1}{x^{10}} = \dfrac{1}{x^{15}}[/tex]

But coefficients will also get divided. Instead of dividing 10 by -5, she subtracted them (as 10 - (-5) = 10 + 5 = 15)

This was her mistake.

The correct simplification would be: [tex]\dfrac{10x^{-5}}{-5x^{10}} = \dfrac{10}{-5} \times \dfrac{x^{-5}}{x^{10}} = -2 \times \dfrac{1}{x^{15}} = \dfrac{-2}{x^{15}} = -2x^{-15}[/tex]

Thus, the mistake that Anja made during the simplification of the considered expression is given by: Option C:  She subtracted the coefficients instead of dividing them

Learn more about exponent and bases here:

https://brainly.com/question/847241

Answer: c

Step-by-step explanation:

The point that approximates the solution for Tenisha's system of equations is (1, 1.4).

given functions are:

[tex]f(x) =log_{3} 5x\\\\f(x) = log_{5} (2x+8)[/tex]

One needs to plot the graphs and can get the intersection points of these two functions on coordinate axes and intersection points will be the required solution.

Find the attached graph

In the attached graph, we can see that the intersection point of given functions is approximately (1, 1.4)

Therefore, the point that approximates the solution for Tenisha's system of equations is (1, 1.4).

To get more about the graphs visit:

https://brainly.com/question/14323743

Answer:

the correct answer is : b

Solution :

Let,

We know that,

[tex]{ \longrightarrow \bf \qquad \: (AB) {}^{2} +( BC) {}^{2} = (AC) {}^{2} }[/tex]

[tex]{ \longrightarrow \sf \qquad \: (AB) {}^{2} +( 4) {}^{2} = (5) {}^{2} }[/tex]

[tex]{ \longrightarrow \sf \qquad \: (AB) {}^{2} = (5) {}^{2} - ( 4) {}^{2} }[/tex]

[tex]{ \longrightarrow \sf \qquad \: AB = \sqrt{(5) {}^{2} - ( 4) {}^{2}} }[/tex]

[tex]{ \longrightarrow \sf \qquad \: AB = \sqrt{25 - 16 }}[/tex]

[tex]{ \longrightarrow \sf \qquad \: AB = \sqrt{9 }}[/tex]

[tex]{ \longrightarrow {\pmb {\bf\qquad \: AB = 3}}}[/tex]

Therefore,

Answer: A, C

Step-by-step explanation:

a) True since this is when the graph intersects the x axis.

b) False, this is a minimum, not a maximum.

c) True, this is tue turning point.

d) False, the axis of symmetry is x=-3, not y=-4.

Answer:

see explanation

Step-by-step explanation:

8(16) + 8(6) ← factor out 8 from each term

= 8(16 + 6)

= 8(22)

= 8 × 22

= 176

Answer:

A: -6 + 2

Step-by-step explanation:

remember two negative signs makes a positive sign

The inequality that can be used to determine whether the bag can be sold is; x + 7 >= 60

According to the question;

It then follows that since, the expected mass should be 60 grams.

The required inequality is; x + 7 >= 60

Read more on inequalities;

https://brainly.com/question/24372553

The equation of the sum of any two squares x and y is x^2 + y^2 = (x + y)^2 - 2xy

The question is incomplete, as there are no parameters to determine the last digit of the first number.

So, I will give a general explanation

The sum of squares of two numbers x and y is:

[tex]x^2 + y^2 = (x + y)^2 - 2xy[/tex]

Assume the numbers are 5 and 6, then the equation becomes

[tex]5^2 + 6^2 = (5 + 6)^2 - 2*5*6[/tex]

Evaluate

[tex]5^2 + 6^2 = 61[/tex]

Read more about sum of squares at:

https://brainly.com/question/52031

Answer:

The answer is 13.25 I'm so sorry if its incorrect please let me know so I can fix it

Answer:

half

Step-by-step explanation:

Answer:

1/2 of the mango or half

Step-by-step explanation:

Subtract the difference:

2690 - 284 = 2406

Divide by 2:

2406 / 2 = 1203

Ricky Had 1,203

Pedro had 1203 + 284 = 1,487

(-2,-4) , (-2, -3) , (-4, -3)

when you rotate 180° then the x and y of each point will become the opposite

Answer:

(x-2,y-4), (x-2,y-3) and (x-4,-y3)

Step-by-step explanation:

The rule is (x,y)-->(-x,-y) so

(x2,y4)=(x-2,y-4)

(x2,y3)=(x-2,y-3)

(x4,y3)=(x-4,-y3)

never mined rong center point It would not let me change any thange