Each of the three choices is tasteless, exhibitionist, juvenile, and dangerous. John should do none of them.
Encountering a news crew, there's no reason for John to call attention to himself in a childish way, or interfere with their work in any way.
What he should do is:
==> Slow down
==> Pass the scene cautiously
==> Resume his normal, legal speed quietly, in case the crew happens to be recording audio at the moment.
Mysteriously, this course of action is nowhere to be found among the choices listed.
Answer:
all three options :)
Explanation:
cuz merica
If 5 complete oscillations of a sound wave pass through a point in 0.5 s and the speed of sound was recorded to be 10 m/s, then find the wavelength of the sound.
Answer:
λ = 2.5m
Explanation:
Given the following :
Speed of sound (v) = 10m/s
If 5 oscillations pass through a point in 0.5seconds;
Time taken (period) for 1 oscillation is :
Number of oscillations / total time taken
5 / 0.5 = 0.25 seconds
Wavelength, period and Velocity are related by the formula:
v = λ / T
λ = v * T
λ = 10 * 0.25
λ = 2.5 m
how to find the mechanical advantage
Answer:
[tex]{ \bf{mechanical \: adv = \frac{load}{effort} }}[/tex]
use the techniques to find the unit for speed
Answer:
The formula for speed is speed=distance
time
Explanation:
to work out what the units are for speed,you need to know the units for distance and time.In this example,distance is in metres(m) and time is in seconds (s) , so the units for speed is metre per second (m/s).
Answer answer answer it it it
Answer:
(B) Parachutes
Explanation:
Air resistance works to slow down trains and airplanes, so it isn't desirable. Air resistance also causes pendulums to slow and stop.
Parachutes need air resistance to slow a person's fall. So air resistance is desirable here.
Answer:
B i answered it it it
Explanation:
A baseball pitcher throws a 0.14 kg ball toward a batter who is 18 m away.
The ball is traveling at 40 m/s when it leaves the pitcher's hand. What is the
ball's kinetic energy at this point?
A. 112 J
OB. 224 J
C. 12J
D. 3 J
SUBMIT
Answer:
A. 112 J
Explanation:
KE = ½mv² = ½(0.14)40² = 112 J
Một xe chạy trong 2 giờ với tốc độ trung bình 45 km/h rồi chạy tiếp 4 giờ với tốc độ trung bình 40 km/h. Tốc độ trung bình của xe trong cả quá trình chuyển động đó gần giá trị nào nhất sau đây?
Answer:
hlo
Explanation:
plzz mark me as brainlest
i can do anything
observe the virual skateboarder coming down the hill and over the ramp describe how each of newton’s laws of motion can be observed in this action you can choose the dry wet or muddy conditions or some combination of these
Answer:
first part the skater goes down a constant slope ramp, initially he has Newton's second law
pply Newton's third law, the normal is the reaction to the support of the body on the surface
the ramp shoots off. axis becomes zero and therefore with Newton's first law its speed
Explanation:
It is the description of this movement let's write Newton's laws.
* The first law that a body goes at constant speed or zero if the sum of the external forces is zero
* the second law is F = m a
* The third law states that the forces act in pairs of equal magnitude and opposite direction, one applied to each body.
Let's apply these laws to our case
In the first part the skater goes down a constant slope ramp, initially he has Newton's second law when he accelerates from the initial velocity of zero to a terminal velocity.
The expression for this is
Wₓ - fr = ma
W sin θ - μ W cos θ = m a
W = mg
g (sin θ - μ cos) = a
the value of the coefficient of kinetic friction depends on the condition of the surface, dry, wet or muddy
This is Newton's second law
On the Y axis, which is perpendicular to the ramp we have
N- [tex]W_{y}[/tex] = 0
If we apply Newton's third law, the normal is the reaction to the support of the body on the surface, note that it can be different from the weight.
In the second part when he is on the ramp.
In the ramp the skater enters with a speed v, suppose that the ramp has an incline so that the skater can jump, in this case the angle is positive with respect to the axis x
In this case the analysis is similar to the previous one
Newton's second law gives the acceleration of the skater, who when he reaches the end of the ramp shoots off.
At this point the force in the x (horizontal) axis becomes zero and therefore with Newton's first law its speed this axis remains constant and the force in the y axis is the force of gravity and has an acceleration that changes if velocity according to Newton's second law
Answer:look at explanations
Explanation:
Two friends are carrying a 200-kg crate up a flight of stairs. The crate is 1.25 m long and 0.500 m high, and its center of gravity is at its center. The stairs make a 45.0° angle with respect to the floor. The crate also is carried at a 45.0° angle, so that its bottom side is parallel to the slope of the stairs (Fig. 2). If the force each person applies is vertical, what is the magnitude of each of these forces?
Let consider the whole system to be at equilibrium where the net force is zero. The forces [tex]F_A[/tex] and [tex]F_B[/tex] are acting in the upward direction while the weight (w) of the crate is acting in the downward direction.
The force at equilibrium in the y-direction is computed as:
[tex]\sum F_y = ma_y[/tex]
[tex]F_A +F_B= mg[/tex]
[tex]\mathbf{F_A = mg -F_B}[/tex] ---- (1)
Recall that the weight w = mg
where;
mass (m) = 200 g g(constant gravity) = 9.8 m/s²w = 200 × 9.8
w = 1960 N
The torque about the bottom end is also zero. i.e.
[tex]\sum \tau=0[/tex]
∴
[tex]F_B L_Z - wL_w = 0[/tex] --- (2)
[tex]F_B L_Z= wL_w[/tex]
[tex]F_B = \omega (\dfrac{L_w}{L_z})[/tex]
[tex]F_B =1960\times (\dfrac{0.375\times cos 45^0}{1.25\times cos 45^0})[/tex]
[tex]F_B =1960\times (0.3)[/tex]
[tex]\mathsf{F_B = 588 \ N}[/tex]
Replacing the value for the force of B into equation (1); we have:
[tex]F_A = mg - F_B[/tex]
[tex]F_A = 1960 - 588[/tex]
[tex]\mathsf{F_A = 1372 N}[/tex]
Thus, we can conclude that the magnitude of these forces i.e force B and force A are 588 N and 1372 N respectively.
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-
Speed is a scalar, a quantity that is
described by
alone.
Answer:
True
Explanation:
Thats is true since it cannot be a vector because speed only gives a magnitude, not a direction as well.
whats the beginning of life called
Answer:
Abiogenesis in evolutionary science, not sure about creation science
Explanation:
A 5kg block is pushed 3m at a constant velocity up a vertical wall by a constant force applied at an angle of 37 degree with the horizontal, if the coefficient of kinetic friction between the block and the wall is 0.3. what is the work done by the force on the block?
The work done by the force on the block is:
[tex]W=135.41*3=406.23 \: J[/tex]
The direction of motion here is in the y-direction, so we need to find the component of the force in this direction.
Using trigonometric functions:
[tex]F_{y}=Fsin(37)[/tex]
This component is in the positive y-direction.
Now, there is a friction force between the block and the wall, so we need to find the friction force.
[tex]F_{f}=\mu N[/tex]
Where:
μ is the coefficient of kinetic frictionN is the normal force (Here N = Fcos(37))Let's use the first Newton's Law to get F.
F(y) is upward (+) and F(f) and the weight is downward (-).
[tex]F_{y}-F_{f}-W=0[/tex]
[tex]F_{y}-F_{f}=mg[/tex]
Factoring F in the left side:
[tex]F(sin(37)-\mu cos(37))=mg[/tex]
[tex]F=\frac{mg}{sin(37)-\mu cos(37)}[/tex]
[tex]F=\frac{5*9.81g}{sin(37)-(0.3*cos(37))}[/tex]
[tex]F=135.41\: N[/tex]
Therefore, the work done will be:
[tex]W=Fd[/tex]
[tex]W=135.41*3=406.23 \: J[/tex]
You can learn more about work definition here:
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What is principle of liver??
Answer:
lever: Principle of the Lever
lever: Principle of the LeverIt has been found by experiment that two equal forces acting in opposite directions, i.e., clockwise and counterclockwise, and applied to a uniform lever at equal distances from the fulcrum counteract each other and establish a state of equilibrium, or balance, in the lever.
Which type of energy is produced
by vibrations traveling in waves?
A. chemical energy
B. nuclear energy
C. sound energy
Answer:
C. sound energy
Explanation:
hope this helps
Express the time spent to daily life activities during holidays as a fraction of whole day 1. Represent the fractions in pictorial form. 2. Write the fractions in simplest form. 3. Arrange them in ascending order.
Answer:
(II). The fractions in simplest form
[tex]\dfrac{31}{35}[/tex], [tex]\dfrac{91}{165}[/tex] and [tex]\dfrac{13}{5}[/tex]
(III). The fractions in ascending order
[tex]\dfrac{91}{165}<\dfrac{31}{35}<\dfrac{13}{5}[/tex]
Explanation:
Given that,
(I). Represent the fractions in pictorial form
(II). Write the fractions in simplest form.
(III). Arrange them in ascending order.
Suppose, The fractions in pictorial form
(a). [tex]\dfrac{3}{5}+\dfrac{2}{7}[/tex]
(b). [tex]\dfrac{9}{11}-\dfrac{4}{15}[/tex]
(c). [tex]\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}[/tex]
We need to write in simplest form
Using given fraction
(a). [tex]\dfrac{3}{5}+\dfrac{2}{7}=\dfrac{3\times7}{5\times7}+\dfrac{2\times5}{7\times5}[/tex]
[tex]\dfrac{3}{5}+\dfrac{2}{7}=\dfrac{21}{35}+\dfrac{10}{35}[/tex]
[tex]\dfrac{3}{5}+\dfrac{2}{7}=\dfrac{21+10}{35}[/tex]
[tex]\dfrac{3}{5}+\dfrac{2}{7}=\dfrac{31}{35}[/tex]
(b). [tex]\dfrac{9}{11}-\dfrac{4}{15}=\dfrac{9\times15}{11\times15}-\dfrac{4\times11}{15\times11}[/tex]
[tex]\dfrac{9}{11}-\dfrac{4}{15}=\dfrac{135-44}{165}[/tex]
[tex]\dfrac{9}{11}-\dfrac{4}{15}=\dfrac{91}{165}[/tex]
(c). [tex]\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}=\dfrac{7}{10}+\dfrac{2\times2}{5\times2}+\dfrac{3\times5}{5\times2}[/tex]
[tex]\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}=\dfrac{7}{10}+\dfrac{4+15}{10}[/tex]
[tex]\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}=\dfrac{7+4+15}{10}[/tex]
[tex]\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}=\dfrac{26}{10}[/tex]
[tex]\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}=\dfrac{13}{5}[/tex]
We need to arrange them in ascending order
Using simplest form
The simplest fraction in ascending order
[tex]\dfrac{91}{165}<\dfrac{31}{35}<\dfrac{13}{5}[/tex]
Hence, This is required solution.
"For a first order instrument with a sensitivity of .4 mV/K and a time" constant of 25 ms, find the instrument’s response as a function of time for a sudden temperature increase from 273 K to 473 K. Before the temperature increase, the instrument output was a steady 109.2 mV. Plot the response y(t) as a function of time. What are the units for y(t)? Find the 90% rise time for y(t90) and the error fraction, Γ(t90).
Answer:
Explanation:
Given that:
For a first order instrument with a sensitivity of .4 mV/K
constant c = 25 ms = 25 × 10⁻³ s
The initial temperature [tex]T_1[/tex] = 273 K
The final temperature [tex]T_2[/tex] = 473 K
The initial volume = 0.4 mV/K × 273 K = 109.2 V
The final volume = 0.4 mV/K × 473 K = 189.2 V
the instrument’s response as a function of time for a sudden temperature increase can be computed as follows:
Let consider y to be the function of time i.e y(t).
So;
y(t) = 109.2 + (189.2 - 109.2)( 1 - [tex]\mathbf{e^{-t/c}}[/tex])mV
y(t) = (109.2 + 80 ( 1 - [tex]\mathbf{e^{t/25\times 10^{-3}}}[/tex])) mV
Plot the response y(t) as a function of time.
The plot of y(t) as a function of time can be seen in the diagram attached below.
What are the units for y(t)?
The unit for y(t) is mV.
Find the 90% rise time for y(t90) and the error fraction,
The 90% rise time for y(t90) is as follows:
Initially 90% of 189.2 mV = 0.9 × 189.2 mV
= 170.28 mV
170.28 mV = (109.2 + 80 ( 1 - [tex]\mathbf{e^{t/25\times 10^{-3}}}[/tex])) mV
170.28 mV - 109.2 mV = 80 ( 1 - [tex]\mathbf{e^{t/25\times 10^{-3}}}[/tex])) mV
61.08 mV = 80 ( 1 - [tex]\mathbf{e^{t/25\times 10^{-3}}}[/tex])) mV
0.7635 mV = ( 1 - [tex]\mathbf{e^{t/25\times 10^{-3}}}[/tex])) mV
t = 1.44 × 25 × 10⁻³ s
t = 0.036 s
t = 36 ms
The error fraction = [tex]\dfrac{189.2-170.28 }{189.2}[/tex]
The error fraction = 0.1
The error fraction = 10%
How do we find the weight of a beam
Answer:
Standard weight: We calculate the standard weight as follows: G = L * mweight, where L is the length of the beam calculated as the difference between the extreme points of the beam body along the direction of the beam axis, taking into account all features except holes.
Explanation:
I want Brainliest plz!!
: Lili
Thiết bị nào sau đây không phải là nguồn điện
A. Ắc quy
B. Pin
C. Máy phát điện
D. Bóng đèn điện
Thiết bị không phải nguồn điện:
Đáp án D
A ball is dropped from a height of 180m- Calculate the velocity of the ball when it strikes the ground
Answer:
6s , 60mls
Explanation:
hope this helps love
Answer:
0m/s
Explanation:
When the object strikes the ground, it then becomes in uniform motion and when an object is in uniform motion, the velocity is 0
If an object has a mass of 200kg but its Ke is 40J, what is its speed?
Answer:
0.632456 m/s
Explanation:
Define potentiol energy , kenetic energy.
Potential energy is stored energy. For example, if a bowling ball is on top of a giant hill, we say it has potential energy because it has the potential to do work which is to roll down the hill.
Kinetic energy is the energy of movement so once that ball rolls down that hill, that potential energy is converted to kinetic energy.
Hey there!
Potential energy and kinetic energy are the two main groups of energy when it comes to all of that. Potential energy is stored energy. Kinetic energy is the energy that is released.
For example, potential energy is when you hold a ball higher than the ground, and kinetic energy is when you release the ball.
Hope this helps! Have a great day! :)
A 20 kg truck drives in a circle of radius 4 m at 10m/s. What is the
centripetal force on the truck?
A. 500 N
B. 650 N
C. 350 N
D. 800 N
We know
[tex]\boxed{\sf F_c=\dfrac{mv^2}{r}}[/tex]
[tex]\\ \sf\longmapsto F_c=\dfrac{20(10)^2}{4}[/tex]
[tex]\\ \sf\longmapsto F_c=\dfrac{20(100)}{4}[/tex]
[tex]\\ \sf\longmapsto F_c=\dfrac{2000}{4}[/tex]
[tex]\\ \sf\longmapsto F_c=500N[/tex]
The centripetal force on the truck can be determined from the mass, velocity and the radius of the circular path. The centripetal force acting on the truck is 500 N. Hence, option A is correct.
What is centripetal force?Centripetal force is a type force acting on an object traveling through a circular path. The centripetal force is the rotational analogue of the linear force.
The centripetal force acting on an object is related to the mass, velocity and radius of the circular path is given by:
Fc = mv ²/r
Given that, mass of truck = 20 Kg
radius of circle = 4 m
velocity = 10 m/s
Then, centripetal force Fc = 20 kg × 10² m/s / 4 m = 500 N
Therefore, the centripetal force on the truck is 500 N.
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Can ya pls answer dis rq!
Answer:
For vegetarians beans
Explanation:
Because it's plant protein and very proteinious
A concave mirror has a radius of curvature of 80cm. If the real image of an object is formed at 1m, how far from the mirror is the object?
Answer:
66.7 cm
Explanation:
The focal length is half the radius of curvature, or f = 40 cm.
The image is real, so i = +100 cm.
The distance to the object is therefore:
1/o + 1/f = 1/i
1/o + 1/40 = 1/100
o = -66.7 cm
The object is 66.7 cm left of the mirror.
what does grit mean in psychology
Answer:
The meaning of grit in psychology is a positive, non-cognitive trait based on an individual's perseverance of effort combined with the passion for a particular long-term goal or end state.
The distance covered by a body along the x axis is given by x=2t^3+5t^2+t where t is measured in seconds and x is in meter. Find average speed in a time interval from t= 0s and t=2s
Explanation:
It is given that,
The distance covered by a body along the x-axis is given by :
[tex]x=2t^3+5t^2+t[/tex]
t is in seconds and x is meters
Speed of the body is given by :
[tex]v=\dfrac{dx}{dt}\\\\v=\dfrac{d(2t^3+5t^2+t)}{dt}\\\\v=6t^2+10t+1[/tex]
At t = 0,
[tex]v=6(0)^2+10(0)+1=1\ m/s[/tex]
At t = 2 s,
[tex]v=6(2)^2+10(2)+1=45\ m/s[/tex]
So, the average speed in a time interval from t= 0s and t=2s is 45 m/s.
Wagonium-292 has a half-life of 1 hour. If you started with an 80 gram sample, how much Wagonium-292 will remain after 4 hours? A.) 10g B.) 40g C.) 160g D.) 5G
After 1 hour, 80 g decays to 40 g.
After another hour (total 2 hours), 40 g decays to 20 g.
After another hour (total 3), 20 g decays to 10 g.
After one more hour (total 4), 10 g decays to (D) 5 g.
A skydiver falls toward the ground at a constant velocity. Which statement best applies Newton’s laws of motion to explain the skydiver’s motion? An upward force balances the downward force of gravity on the skydiver. The skydiver’s inertia is zero, which no longer allows for acceleration. An unbalanced force pulls the skydiver toward the ground. The mass of the skydiver is so great that there is no acceleration
Answer: A) an upward force balances the downward force of gravity on the skydiver
Explanation: I got it correct on my test on edge
The statement best applies Newton’s laws of motion to explain the skydiver’s motion an upward force balances the downward force of gravity on the skydiver. Thus, option A is correct.
Which statement best applies Newton’s laws of motion?
The statement that best applies Newton’s laws of motion to explain the skydiver’s motion is that an upward force balances the downward force of gravity on the skydiver. Newton's 3rd law often applies to skydiving.
When gravity is not acting upon the skydivers they would continue moving in the direction the vehicle they jumped from was moving. If no air resistance takes place, then the skydivers would still accelerating at 9.8 m/s until they hit the ground.
The skydiver after leaving the aircraft will accelerates downwards due to the force of gravity usually as there is no air resistance acting in the upwards direction, and there is a resultant force acting downwards, the skydiver will accelerates towards the ground.
Therefore, The statement best applies Newton’s laws of motion to explain the skydiver’s motion an upward force balances the downward force of gravity on the skydiver. Thus, option A is correct.
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What is the voltage of the power source if a motor with a resistance of 20 2 draws a
current of 1.5 A?
Answer:
190v I believe
hope this helped a little and if it did pls mark brainiest :)
High voltage power is often carried in wire bundles made up of individual strands. In your initial post to the discussion, discuss the forces on the strands of wire due to the current flowing through them. What would happen if the force acted opposite of the known behavior? Provide a detailed description.
Answer:
There will be a huge problem of holding the wire strands together, and the power losses will also be amplified.
Explanation:
The force per unit length on two current carrying conductors, lying parallel to each other is proportional to the product of the current through the conductors, and inversely proportional to their distance apart. This force is attractive if the current flows through these conductors in the same direction, and is repulsive if it flows in the opposite direction.
For the strand of wire that make up a high voltage wire bundle, there will be a force of attraction pulling the wires closer to each other, and they will experience the maximum pulling force possible, since they lie next to each other. This force helps to hold these wires in a high tension wire strand together, limiting the area, and reducing "skin effect."
In the case that this wires in the wire strand acts in opposite of the known behavior, the wires will repel and push each other apart. This pushing apart will increase power loss due "skin effect" which is increased by an increase in exposed surface area of the wire strands. This will pose a big problem for high tension transmission.
A magnet pulls a piece of iron with a force of 1 N. What is the force that the iron piece exerts on the magnet?
The iron piece exerts a force of 1 N divided by the ratio of the weight of the iron piece to the weight of the magnet in the same direction.
The iron piece exerts a force of 1 N on the magnet in the opposite direction.
The iron piece exerts a force of 1 N divided by the ratio of the weight of the iron piece to the weight of the magnet in the opposite direction.
The iron piece exerts a force of 1 N on the magnet in the same direction.
Answer:
the final statements the correct one is. The second
The iron piece exerts a force of 1 N on the magnet in the opposite direction
Explanation:
In this exercise they give us the force exerted by a magnet on an iron bar and ask us the force that the iron bar exerts on the magnet. We can see that these are action and reaction forces, which by Newton's third law must be of equal magnitude and opposite direction, each applied to one of the bodies.
the final statements the correct one is. The second
The iron piece exerts a force of 1 N on the magnet in the opposite direction