Johnny lets a 0.5 kg ball roll on the floor of the classroom. The ball gradually slows down. Draw a free body diagram and calculate the acceleration of the ball

Answer:

which question

Explanation:

please explain better

According to the given statement The ball's velocity just before it stopped was  8.0 m/s.

The correct option is B.

The rate at which velocity and speed change over time is referred to as acceleration. When anything moves faster or slower, it is said to be accelerating or decelerating in a straight line. Even if the speed remains constant, moving in a circle quickens because the direction is always changing.

A increase in an object's orientation or speed is referred to as acceleration. Acceleration is the term for the pace at which speed changes. Don't forget that velocity is made up of two components: direction and speed.

The definition of acceleration comes first

a = v[tex]_f[/tex] - v[tex]_o[/tex] /t

2 = v[tex]_f[/tex]- 0/4

v[tex]_f[/tex]= 8 m/s

After 4 seconds, the ball will be moving at a speed of 8 m/s.

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Answer:

  379.12 km/h N 9.86° W

Explanation:

You want to know the resultant velocity when a plane's velocity of 373.52 km/h N is modified by a crosswind at 64.90 km/h W.

In (N, E) coordinates, the sum of the velocities is ...

  (373.52, 0) +(0, -64.90) = (373.52, -64.90)

The magnitude of this vector is ...

  |v| = √(373.52² +64.90²) ≈ 379.12 . . . . km/h

The direction will be west of north by the angle ...

  θ = arctan(-64.90/373.52) ≈ -9.86° . . . . . . N = 0°, + = clockwise

The resultant velocity is 379.12 km/h N 9.86° W.

Water spinning in a turbine has Kinetic energy.

We must exert force on an object to accelerate it. We have to put up the effort to use force. Energy is transmitted when work is done on an object, and the thing then moves at a new, constant speed. The energy that is transported is referred to as kinetic energy, and it is influenced by the mass and speed attained.

In physics, kinetic energy is described as follows:

The amount of labor an object can accomplish through motion is measured by its kinetic energy.

As a scalar quantity, kinetic energy can only be fully defined by its magnitude.

Water spinning in a turbine has kinetic energy which is used to produced electric energy.

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Answer:

See below

Explanation:

See diagram below

8 seconds to 60 m/s     then    60 m/s for 22 seconds then   to 0 m/s in 5 seconds

The wavelength of a wave with frequency of 100.2Khz is 2.99 × 10³m.

Wavelength is the length of a single cycle of a wave, as measured by the distance between one peak or trough of a wave and the next.

The wavelength is often designated in physics as λ, and corresponds to the velocity of the wave divided by its frequency as follows:

λ = v/f

Where;

According to this question, the frequency of a wave is 100.2KHz, which is equivalent to 1.002 × 10⁵Hz.

λ = 3 × 10⁸ ÷ 1.002 × 10⁵

λ = 2.99 × 10³m

Therefore, 2.99 × 10³m is the wavelength of the wave.

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Answer:

The other arrow/force should be in the same direction that Alex is pushing the heavy box.

Explanation:

If Alex is pushing the heavy box to the right, then another person helping him that is also pushing the heavy box to the right would lessen the amount that he has to push.

Answer:

Explanation:

Mass of disk = 0.14 kgSpring constant = 155 N/mLength = 4 cmWe need to calculate the speed Using energy conservationWhere, k = spring constantx = compressed lengthm = mass of the discPut the value into the formulaHence, The speed with which the disk slides across the surface is 1.33095 m/s.

A race car is traveling in a uniform circular motion around a race track, the radial acceleration of the car when the velocity is doubled and the radius of the circle is halved will increase by a factor of 8 (Option D)

To arrive at the above conclusion, we must recall that radial acceleration is defined by:

Ac = v²/r; where

Ac - is the magnitude of radial acceleration

v -  is the linear or tangential speed

r - is the radius of the circular path

A′c -  is the new magnitude of the radial acceleration.

Given that the linear velocity is duplicated and simultaneously the radius is split in two, then the new radial acceleration increases by a factor of 8, according to the following calculation:

A'c = (2v²)/(0.5r)

= 4v²/(0.5r)

= 8 · (v²/r)

= 8 · Ac

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Full Question:

A race car is traveling in a uniform circular motion around a race track what happens to the radial acceleration of the car if the velocity is doubled and the radius of the circle is halfed?

A. It remains the same.

B. It increases by a factor of 2.

C. It increases by a factor of 4.

D. It increases by a factor of 8.

E. It decreases by a factor of 2.

The best representation of the graph is an upward-sloping line drawn on a graph with acceleration shown on the y-axis and force shown on the x-axis​. Option D

We know that there is a direct relationship between the force and the acceleration of the object. According to the Newton second law, when force is applied to an object. The object would acquire an acceleration. In order words, the force that acts on the body is able to increase  the speed of the object.

If we look at the table that was shown in the question that we have attached here, you would notice that as the force that acted on the object was increased, there was a commensurate increase in the acceleration of the object as seen.

This goes on to buttress that the relationship between the force and the accaleration is a direct relationship. This also tell us that we will have a graph that runs upwards and not downwards!

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The half life of the sample is 393.4 days while it would take 47.3 days for 100 mg sample to break down to 92 mg.

We know that the half life has to do with the time that it takes for only half of the number of the radioactive atoms in the sample to remain. We have in this case that;

N/No = (1/2)t/[tex]t_{\frac{1}{2} }[/tex]

No = Number of radioactive atoms originally present

N = Number of atoms at time t

t = time taken

[tex]t_{\frac{1}{2} }[/tex] = half life

Then we are told that the sample decreases by 60 percent thus 40 percent is left.

We have;

0.4No/No = (1/2)^520/[tex]t_{\frac{1}{2} }[/tex]

0.4 =  (1/2)^520/[tex]t_{\frac{1}{2} }[/tex]

ln0.4 = 520/[tex]t_{\frac{1}{2} }[/tex] ln 0.5

520/[tex]t_{\frac{1}{2} }[/tex] = ln0.4 /ln 0.5

[tex]t_{\frac{1}{2} }[/tex] =520/ ln0.4 /ln 0.5

= 393.4 days

Then

Using;

92/100 = (1/2)^t/ 393.4

0.92 = (1/2)^t/ 393.4

ln 0.92 = t/ 393.4 ln 0.5

t = ln 0.92/  ln 0.5 * 393.4

t = 47 days

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Answer:

The power for the LED stems from the movement of a magnet through a coil of wire on a tube. Each time the magnet moves through the coil of wires, the magnet generates a pulse of electricity. This is what happens when you shake the flashlight. A capacitor allows you to use the flashlight without continuously shaking it.

TRUE: The total change in momentum for this interaction is zero.

FALSE: The change in the space bug's momentum is greater than the change in the spaceship's momentum.

UNDETERMINED: If the space bug had stuck to the spaceship instead of bouncing off, momentum would not have been conserved for this interaction.

Answer:2,520

Explanation: The truck goes 14 meters per second

Since it is traveling for 3 minutes which is 180 seconds, all you need to do is times the 180 seconds with the 14 meters. :)

Option -a is correct. The two objects' respective masses and distances from one another.

In other words, a line connecting the two masses is where the force vectors we could depict on each mass lie. When two objects pull on one another due to gravity, this is always true. The lines of those attractional forces run between the centers of mass of the two objects.

Any particle of matter in the universe will gravitate toward any other with a force that varies directly as the product of the masses and inversely as the square of the distance between them, according to Newton's law of gravitation.

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A program that could do an instantaneous analysis of video motion will be useful it in a sportscast to analyze events as they occur.

A motion video is defined as the display of video images at a rate (such as thirty frames per second) that causes objects to appear to move smoothly and continuously.

Sports inherently involve fast and accurate motion, which can be difficult for competitors to master but also for coaches and trainers to analyze and audiences to follow. Because of the nature of most sports, monitoring with sensors or other devices attached to players or equipment is generally not possible. This opens up a plethora of opportunities for the use of computer vision techniques to assist competitors, coaches, and the audience

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Sound waves are mechanical waves. They need a medium for propagation. In air the sound waves will travel smoothly and we can get it. Whereas  in vacuum, no medium is there and the sound waves cannot propagate.No sound can be produced there.

Mechanical waves are waves propagating through a medium such as air, water etc. There are two types of mechanical waves namely transverse wave and longitudinal waves.

In transverse waves, the vibration of particles is in a direction perpendicular to the wave whereas, in longitudinal waves,  both are in one direction. Sound wave is a longitudinal wave.

Unlike electromagnetic waves mechanical waves cannot be travelled in vacuum. Hence if we try to produce sound in space or vacuum,no effect will be there but in air and water sound waves can be propagated.

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Answer:

its b and a

Explanation:

The approximate tangential speed of an object orbiting Earth with a radius of 1.8 × 108 m and a period of 2.2 × 104 s is  5.34 m/sec.

The speed of an object is the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.

Given in the question an object orbiting Earth with a radius of 1.8 × 108 m and a period of 2.2 × 104 s, tangential speed is ,

v = [tex]2\pi*r[/tex]/t

v = 2*3.14*1.8*108/2.2*104

v = 5.34 m/sec.

The approximate tangential speed of an object orbiting Earth with a radius of 1.8 × 108 m and a period of 2.2 × 104 s is  5.34 m/sec.

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Answer:

kinetic energy

Explanation:

It is kinetic energy because it is an energy in motion. In order words it is an energy which the body or object moves.

The displacement of the runner according to the graph is obtained as 250 m.

The term displacement has to do with the distance that is covered in a specified direction. The difference between distance and displacement is that displacement is a vector while distance is a scalar quantity.

Thus we bring the direction into play when we are talking about the displacement of the object. Now we have a graph that shows the displacement of the runner in the vertical axis and then shows the time that is taken in the horizontal axis.

Given the graph as we have it, we can be bale to pick out the following from the graph;

1) Displacement of the runner at 100 s = 500 m

2) Displacement of the runner at 300 s = 750 m

Therefore;

Displacement of the runner between 100 and 300 seconds;

750 m - 500 m = 250 m

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The ball is 25 times more energetic when it is thrown by the professional then when it is thrown by the child.

Basically we ought to be reminded that the kinetic energy of the object is the energy that is possessed by the object by virtue of the fact that the object is in motion.

We have to recall that the kinetic energy is given by;

KE = 1/2 mv^2

m = mass of the object

v = velocity of the object

Since the mass of the object is held the same let us take note of the speed with which the ball is thrown by the student and the professional respectively

Speed of the student =  20 mph or 8.9 m/s

Speed of the professional = 100 mph or 44.7 m/s

Energy of the ball by the student = 0.5 * m * (8.9)^2

Energy of the ball by the professional = 0.5 * m * (44.7)^2

We now have;

0.5 * m * (44.7)^2/0.5 * m * (8.9)^2

25 times

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The expected profit is positive for the customers 1, 2, 3, 4, 5.

This is the term that is used to refer to the gain that would be expected to be gotten based on the fact that a person has engaged in a business.

We have 1 - 0.05 = 0.95 profit if the coupon is used

-0.05 is the profit if the coupon is not used

for consumer 1

the probability = 0.44

expected profit = 0.44 x 0.95 - 0.05 x 0.56

= 0.418 - 0.028

= 0.39

for consumer 2

the probability = 0.34

expected profit = 0.34 x 0.95 - 0.05 x 0.66

= 0.323 - 0.033

= 0.29

For consumer 3

the probability = 0.24

expected profit = 0.24 x 0.95 - 0.05 x 0.76

= 0.228 - 0.038

= 0.19

For consumer 4

the probability = 0.11

expected profit = 0.11 x 0.95 - 0.05 x 0.89

= 0.1045 - 0.0445

= 0.06

For consumer 5

the probability = 0.06

expected profit = 0.06 x 0.95 - 0.05 x 0.94

= 0.057 - 0.047

= 0.01

The expected profits can be listed as:

The expected profits are positive for all of 1, 2, 3, 4, and 5, hence these customers can purchase the coupon.

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Answer:

  74.7 m

Explanation:

You want the minimum radius of curvature of a vertical circular arc so that vehicles traveling 95 km/h making the transition from horizontal to an 18° down grade will not leave the road.

The acceleration due to gravity on the vehicle at the point it is traveling 18° down is ...

  g·cos(18°) ≈ (9.8 m/s²)·0.95106 ≈ 9.32 m/s²

The radius of an arc and the speed of travel are related to the normal acceleration by ...

  r = v²/a

where v is the speed along the arc, and 'a' is the normal acceleration required to make an object follow the circular curve.

The speed of 95 km/h can be translated to m/s by ...

  (95 km/h) · (1000 m/(1 km)) · (1 h)/(3600 s) = 95/3.6 m/s ≈ 26.389 m/s

Using the above relation to find the radius, we get ...

  r = (26.389 m/s)²/(9.32 m/s²) ≈ 74.72 m

The minimum radius of the vertical circular arc should be 74.7 meters to prevent vehicles from becoming airborne.

__

Additional comment

In actual roadway design, factors of sight distance and stopping distance come into play. Sight distance over this crest would be about 25 m. It would need to be more than 6 times that distance for the roadway to be safe at 95 km/h.

An 18° down grade is about 3 times the usual maximum for roadway design, which will severely increase stopping distance. The vertical arc described here would leave the car with no normal force on the roadway at the end of the arc, so braking would be impossible. Passengers would be feeling weightless, too.

Roadway curves are generally parabolic (not circular), so they have a constant rate of change of slope with horizontal distance.

0.116 rad/s is the angular speed in radians, during the time interval from 0.75 s to 14.2 s

ω=Δθ/Δt

Δθ= 90° = 1.571rad

Δt=13.45

ω=1.571/13.45

ω=0.116 rad/s

The rate of change of angular displacement, or the angle a body travels along a circular path, is the definition of angular speed. Calculating angular speed involves dividing the quantity of rotations or revolutions made by a body by the amount of time required. Omega is a Greek letter that represents angular speed. The SI's angular speed unit is rad/s.

As is well known, angular speed is determined by dividing the rate of displacement change by the time. As a result, the angular speed equation is = /t. Despite the procedure stated above, a different and more well-liked formula is used to determine angular speed in competitive testing. As ω = θ/t

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Answer:

I don't Know espero que le entiendas