Katelynn is excited about her trip to Chicago with her orchestra. She needs to raise $500 in order to go. She decides to make and sell scarves in order to fund her trip. In order to make each scarf, she will need $3 worth of yarn. If she plans on making 100 scarves, how much must she charge for each scarf in order to be able to pay for her trip?

Answers

Answer 1

Answer:

$8 each scarf

Explanation:

Let the selling price for each scarf be x,

Formula:

unit amount(selling price - cost price) = total profit

Stepwise:

100(x - 3) = 500

100(x) - 100(3) = 500

100x - 300 = 500

100x = 500 + 300

100x = 800

x = 8


Related Questions

What is 3x^3+5x^2-11x+3/x+3

Answers

The solution to the expression (3x³ + 5x² - 11x + 3)/(x + 3) is (x - 1/3)(x - 1)

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

Given the expression:

(3x³ + 5x² - 11x + 3)/(x + 3)

= (x + 3)(x - 1/3)(x - 1) / (x + 3)

= (x - 1/3)(x - 1)

The solution to the expression (3x³ + 5x² - 11x + 3)/(x + 3) is (x - 1/3)(x - 1)

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Find the value of x in 1:x=6 1/4

Answers

Answer:

x = [tex]\frac{4}{25}[/tex]

Step-by-step explanation:

1 : x = 6 [tex]\frac{1}{4}[/tex] ← change to improper fraction

1 : x = [tex]\frac{25}{4}[/tex] , then

[tex]\frac{1}{x}[/tex] = [tex]\frac{25}{4}[/tex] ( cross- multiply )

25x = 4 ( divide both sides by 25 )

x = [tex]\frac{4}{25}[/tex]

help
11-16

please i dont understand

Answers

Answer:

  see attached

Step-by-step explanation:

There are many vocabulary words and theorems associated with angles where a transversal crosses parallel lines. These are needed for the "explain your reasoning" part of the question.

Where 2 lines cross

Where one line crosses another, the angles formed are either "adjacent" (share a side and vertex), or "vertical" (share only a vertex, formed from opposite rays). In Figure 11, x° and 67° are "adjacent" angles. In Figure 12, y° and 109° are "vertical" angles.

The adjacent angles are also called a "linear pair", and their total is 180°. They are supplementary.

The vertical angles are congruent.

Where a transversal crosses parallel lines

Two sets of four angles are formed when a transversal crosses parallel lines. The relations between angles of one of those sets and angles of the other of those sets are described using several different terms:

"Alternate" angles are on opposite sides of the transversal. "Consecutive" or "same-side" angles are on the same side of the transversal. "Exterior" angles are outside the parallel lines. "Interior" angles are between the parallel lines. "Corresponding" angles are in the same relation to the point of intersection.

Alternate exterior angles (congruent): Fig. 11, x° and y°.

Alternate interior angles (congruent): Fig. 13, y° and the one marked with the right angle symbol.

Consecutive interior angles (supplementary): Fig. 12, x° and 109°; Fig. 14, x° and y°.

Consecutive exterior angles (supplementary): none shown in these figures.

Corresponding angles (congruent): Fig 14, x° and 65°; Fig. 16, x° and 130°.

The upshot of all of these relations is this:

all acute angles are congruentall obtuse angles are congruentobtuse angles are supplementary to acute anglesIf any angle is a right angle, all of them are.

Application

The attached table shows the values of x° and y° in the various figures. For the purpose here, we simply identified the angles as acute or obtuse, and matched values accordingly. The explanation can get as elaborate as you like. For example, ...

  11. x° and y° are alternate exterior angles, so congruent. x° and 67° are a linear pair, so x° = 180° -67° = 113°.

  12. x° and 109° are consecutive interior angles, so supplementary. x° = 180° -109° = 71°. y° and 109° are vertical angles, so congruent.

PLEASE HELP I HAVE AN HOUR LEFT!!
Which statement correctly identifies an asymptote of g (x) = StartFraction 42 x cubed minus 15 Over 7 x cubed minus 4 x squared minus 3 EndFraction using limits?

Limit of g (x) as x approaches plus-or-minus infinity= 5, so g(x) has an asymptote at x = 5.
Limit of g (x) as x approaches plus-or-minus infinity= 6, so g(x) has an asymptote at x = 6.
Limit of g (x) as x approaches plus-or-minus infinity= 5, so g(x) has an asymptote at y = 5.
Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.

Answers

The statement that correctly describes the horizontal asymptote of g(x) is:

Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.

What are the asymptotes of a function f(x)?

The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.The horizontal asymptote is the limit of f(x) as x goes to infinity, as long as this value is different of infinity.

In this problem, the function is:

[tex]g(x) = \frac{42x^3 - 15}{7x^3 - 4x^2 - 3}[/tex]

The horizontal asymptote is given as follows:

[tex]y = \lim_{x \rightarrow \infty} g(x) = \lim_{x \rightarrow \infty} \frac{42x^3 - 15}{7x^3 - 4x^2 - 3} = \lim_{x \rightarrow \infty} \frac{42x^3}{7x^3} = \lim_{x \rightarrow \infty} 6 = 6[/tex]

Hence the correct statement is:

Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.

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please give the answer

Answers

The function can be solved as follows:

f(6 + 4) = 25f(6) - f(4) = 20f(6 - 4) = 1f(6) - f(4) = 6f(6) . f(4) = 91

How to solve function?

f(x) = 3x - 5

Therefore, the function can be solved as follows:

f(6 + 4) = f(10) = 3(10) - 5 = 25

f(6) + f(4) = 3(6) - 5 + (3(4) - 5)

f(6) - f(4) = 13 + 7

f(6) - f(4) = 20

f(6 - 4) = f(2) = 3(2) - 5 = 6 - 5 = 1

f(6) - f(4) = 3(6) - 5 - (3(4) - 5)

f(6) - f(4) = 18 - 5  - (12 - 5)

f(6) - f(4) = 13 - 7

f(6) - f(4) = 6

f(6.4) = f(24) = 3(24) - 5 = 72 - 5 = 67

f(6) . f(4) = (3(6) - 5 ) (3(4) - 5)

f(6) . f(4) = (18 - 5)(12 - 5)

f(6) . f(4) = (13)(7) = 91

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A pizza company is building a rectangular solid box to be able to deliver personal pan pizzas. The pizza company wants the volume of the delivery box to be 756 cubic inches. The length of the delivery box is 6 inches less than twice the width, and the height is 2 inches less than the width. Determine the width of the delivery box.

Answers

The width of the delivery box is 9 inches.

Given that  volume of delivery box is 756 cubic inches,length is 6 inches less than twice the width, height is 2 inches less than width.

let width be x

Length = 2x- 6

Height = x - 2

Width = x

We can find the value of x by putting values one by one and then we will be able to get the value of  x which is width.

Because the delivery box is cuboid in shape so the volume is equal to product of length,breadth and height.

When x=7: Volume=7 x (7 - 2) x (2x7 - 6) = 7 x 5 x 8 = 280

When x=9,Volume will be 9 x (9 - 2) x (2x9 - 6) = 9 x 7 x 12 = 756

Therefore, the width of the delivery box is 9 inches.

Hence the width of the delivery box is 9 inches.

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solve for the balloon volume using the equation below

Answers

The volume of the balloon is 1441.64cm³.

How to calculate the volume?

The radius of the balloon is given as 7cm. Also, the equation to calculate the volume is given as c³/6π²

The circumference c will be:

= 2πr = 2 × 22/7 × 7

= 44

The volume will be:

= c³/6π²

= 44³/(6 × 3.14²)

= 85284/(59.1576)

= 1441.64

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Find a linear inequality with the following solution set. Each grid line represents one unit.

Answers

The linear inequality that represents the solution set is (- 1 / 3) · x - y ≥ 8 / 3.

How to derive the inequality that represents the image

Herein we have an representation of a inequality of the form y ≤ f(x), where f(x) is a linear function, that is, a first grade polynomial. By geometry we know that a equation of the line can be known from two distinct points set on Cartesian plane:

Slope

m = [- 4 - (- 2)] / [4 - (- 2)]

m = (- 2) / 6

m = - 1 / 3

Intercept (m = - 1 / 3, (x, y) = (4, - 4)

b = y - m · x

b = - 4 - (- 1 / 3) · 4

b = - 4 + 4 / 3

b = - 8 / 3

Then, we find that the inequality is:

y ≤ (- 1 / 3) · x - 8 / 3

8 / 3 ≤ (- 1 / 3) · x - y

(- 1 / 3) · x - y ≥ 8 / 3

The linear inequality that represents the solution set is (- 1 / 3) · x - y ≥ 8 / 3.

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What is the type? f(x)=-1/5x³-5+10x²​

Answers

This is a cubic function with the highest degree of 3, the correct order would be:
f(x) = -1.5x^3 + 10x^2 - 5

‼️‼️PLEASE HELP I WILL MARK BRAINLIEST ‼️‼️Dilate the figure by the scale factor. Then enter
the new coordinates.
C(-2,1)
A(1,4)
B(2,2)
K = 6
A' ([?], [])
B' ([ ], [ ])
C' ([ ], [ ])

Answers

Answer:After dialation

A'=6,24

B'=12,12

C'=-12,6

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x/2 + 11 = 19
solve this equation

Answers

Answer:

x/2 = 19-11

x/2 = 8

x = 8×2

x= 16

Answer:

x=16

Step-by-step explanation:

x/2 + 11 = 19

*2     *2    *2    Multiply 2 on both sides to make x stand by itself

x+22 = 38

  -22   -22

x=16

Check

Plug in 16 instead of x.

16/2 + 11 = 19

8+11=19

19=19

Hope it helps:)

Rearrange the equation so a is the independent variable.
−3a+6b=a+4b

Answers

Answer:

6b-4b=a+3a

2b=4a

4a=2b

a=2b/4

a=b/2

The name of this bronze-casting process relies on a modeled original form made from a pliable material. This method is known as ________.

Answers

The bronze-casting process that depends on a modelled original form is:  lost-wax casting.

What is Lost-wax Casting?

Lost-wax casting is a bronze-casting process which is also referred to as the cire-perdue. In this type of metal casting, a wax model is created when a molten metal is usually poured into a mold. The wax model is then melted and drained.

In summary, the name for this bronze-casting process that relies on this wax model is called: lost-wax casting.

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Find the surface area of the prism. Round to the nearest tenth if necessary. please help!!

Answers

Answer:

72

Step-by-step explanation:

This shape is a prism; it's a 3-D shape with 6 sides. Basically, it's a box.

All 6 sides are rectangles.

Surface area means that we'll find the area of all 6 rectangles and add them up.

There's a front and back, left and right, and a top and bottom.

The area of a rectangle is length×width or base×height.



The front and back are identical.

Area = length×width

Area = 6×3 = 18

Since the front and back are the same, two of the rectangles have area = 18.



The left and right are the same:

Area = 3 × 2

Area = 6

Two faces have area = 6.

The top and bottom are the same.

Area = 6 × 2

Area = 12

Again, two faces have area = 12.

To find the total surface area, add up all 6 areas.

A =18+18+6+6+12+12

A = 72

Can someone help me please with this having trouble doing it!!

Answers

Due to length restriction we kindly invite to check the explanation for further details about the analysis of three quadratic equations and inherent rigid transformations.

How to difference between parent quadratic equations and resulting quadratic equations

Herein we find the graph of the parent quadratic equation f(x) = x² and two proposed resulting functions, whose difference with the former one have to be explained in terms of the kind of rigid transformations they have.

By comparing them, we find that both functions g(x) and h(x) are the result of a rigid transformation of the form f'(x) = k · f(x), where the transformation is a simple vertical dilation for k > 1, simple vertical contraction for 0 < k < 1, vertical contraction and reflection around the x-axis for - 1 < k < 0 and vertical dilation and reflection around the x-axis for k < - 1.

Function g(x) is the result of dilating f(x) by a factor of 3 and function h(x) is the result of dilating and reflecting f(x) around the x-axis by a factor of - 3.

The tables for each quadratic function are summarized below:

g(x):

 x             - 2             - 1               0             1                2

g(x)            12               3              0             3               12

f(x):

 x             - 2             - 1               0             1                2

g(x)          - 12            - 3               0           - 3            - 12

Lastly, we prepare the graph with the three functions in the image attached below.

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Nora works at a retail store. She earns a commission of $5.50 on each item she sells. If she sells 17 items, how much does she earn from commissions?

Answers

The total earnings in commission is $93.50

How to determine the total commission?

The given parameters are:

Commission = $5.50

Items = 17

The total commission is:

Total = $5.5 0 * 17

Evaluate

Total = $93.50

Hence, the total earnings in commission is $93.50

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what is the solution to the equation 35-2x=23

Answers

Answer:

x = 6

Step-by-step explanation:

35 - 2x = 23

35 - 23 - 2x = 0

35 - 23 = 2x

12 = 2x

x = 6

35- 2x = 23

Subtract 35 from both sides.

-2x = 23 - 35

Subtract 35 from 23 to get −12.

-2x = -12

Divide both sides by −2.

x = -12 / - 2

Divide −12 by −2 to get 6.

x = 6 ===> Answer

100 POINTS PLEASE HELP!!!
The coordinate plane below represents a community. Points A through F are houses in the community.

graph of coordinate plane. Point A is at negative 5, 5. Point B is at negative 4, negative 2. Point C is at 2, 1. Point D is at negative 2, 4. Point E is at 2, 4. Point F is at 3, negative 4.

Part A: Using the graph above, create a system of inequalities that only contains points C and F in the overlapping shaded regions. Explain how the lines will be graphed and shaded on the coordinate grid above. (7 points)

Part B: Explain how to verify that the points C and F are solutions to the system of inequalities created in Part A. (5 points)

Part C: Erica wants to live in the area defined by y < 7x − 4. Explain how you can identify the houses in which Erica is interested in living. (2 points)

Answers

Answer:

[tex]\sf A) \quad \begin{cases}\sf y > -5x+5\\\sf y < -5x+12\end{cases}[/tex]

B)  see below

C)  points C, E and F

Step-by-step explanation:

Given points:

A = (-5, 5)B = (-4, -2)C = (2, 1)D = (-2, 4)E = (2, 4)F = (3, -4)

Part A

A system of inequalities is a set of two or more inequalities in one or more variables.

To create a system of inequalities that only contains C and F in the overlapping shaded region, create a linear equation where points C, F and E are to the right of the line and a linear equation where points C, F, A, B and D are to the left of the line.

The easiest way to do this is to find the slope of the line that passes through points C and F, then add values to move the lines either side of the points.

[tex]\sf slope\:(m)=\dfrac{change\:in\:y}{change\:in\:x}=\dfrac{y_F-y_C}{x_F-x_C}=\dfrac{-4-1}{3-2}=-5[/tex]

Therefore:

[tex]\sf y = -5x + 5[/tex]  →  points C, F and E are to the right of the line.

[tex]\sf y=-5x+12[/tex]  →  points C, F, A, B and D are the left of the line.

Therefore, the system of inequalities that only contains points C and F in the overlapping shaded regions is:

[tex]\begin{cases}\sf y > -5x+5\\\sf y < -5x+12\end{cases}[/tex]

To graph the system of inequalities:

Plot 2 points on each of the lines.Draw a dashed line through each pairs of points.Shade the intersected region that is above the line y > -5x + 5 and below the line y < -5x + 12.

Part B

To verify that the points C and F are solutions to the system of inequalities created in Part A, substitute the x-values of both points into the system of inequalities.  If the y-values satisfy both inequalities, then the points are solutions to the system.

Point C (2, 1)

[tex]\implies \sf x=2 \implies 1 > -5(2)+5 \implies 1 > -5\quad verified[/tex]

[tex]\implies \sf x=2 \implies 1 < -5(2)+12\implies 1 < 2 \quad verified[/tex]

Point F (3, -4)

[tex]\implies \sf x=3 \implies -4 > -5(3)+5 \implies -4 > -10\quad verified[/tex]

[tex]\implies \sf x=3 \implies -4 < -5(3)+12\implies -4 < -3 \quad verified[/tex]

Part C

Method 1

Graph the line y = 7x - 4 (making the line dashed since it is y < 7x - 4).

Shade below the dashed line.

Points that are contained in the shaded region are the houses in which Erica is interested in living:  points C, E and F.

Method 2

Substitute the x-value of each point into the given inequality y < 7x - 4.

Any point where the y-value satisfies the inequality is a house that Erica is interested in living.

[tex]\sf Point\: A: \quad x=-5 \implies 5 < 7(-5)-4 \implies -5 < -39 \implies no[/tex]

[tex]\sf Point\: B: \quad x=-4 \implies -2 < 7(-4)-4 \implies -2 < -32 \implies no[/tex]

[tex]\sf Point\: C: \quad x=2 \implies 1 < 7(2)-4 \implies 1 < 10 \implies yes[/tex]

[tex]\sf Point\: D: \quad x=-2 \implies 4 < 7(-2)-4 \implies 4 < -18 \implies no[/tex]

[tex]\sf Point\: E: \quad x=2 \implies 4 < 7(2)-4 \implies 4 < 10 \implies yes[/tex]

[tex]\sf Point\: F: \quad x=3 \implies -4 < 7(3)-4 \implies -4 < 17 \implies yes[/tex]

Use substitution to find the integral. (Remember to use absolute values where appropriate.) square root x / x-4

Answers

Answer:

Step-by-step explanation:

here is a solution and verify

I NEED HELP NOW PLSSS!!! Daredevil Robbie Knievel is building a ramp to attempt to jump his motorcycle over 35 school buses. The surface of the ramp will be 40 feet long and the ramp must stand 11 feet tall in order to clear the buses. What angle will the ramp form with the ground?


A. 7°

B. 15°

C. 16°

D. 74°

Answers

The angle that the ramp makes with the ground is 16 degrees.

What angle does the ramp make with ground?

We can see that the ramp is and its support now constitutes a right angled triangle.

Thus, the hypotenuse of the triangle is 40feet while the opposite of the angle is 11 feet.

The angle made with the ground is;

sin x = 11/40

x = sin-1(11/40)

x = 16 degrees

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Which function could be a stretch of the exponential decay function shown on the graph?

f(x) = 2(6)x
f(x) = One-half(6)x
f(x) = 2(one-sixth) Superscript x
f(x) = One-half (one-sixth) Superscript x

Answers

We find that the function that could be a stretch of the exponential decay is [tex]f(x) = 2\cdot \left(\frac{1}{6} \right)^{x}[/tex]. (Correct choice: C)

What function represents a stretch of a exponential decay function?

Exponential functions are trascedent functions whose form is described below:

[tex]y = a\cdot r^{x}[/tex]     (1)

Where:

a - Stretch factorr - Growth rate

There are two conditions for a stretch factor and exponential decay: (i) a > 1, (ii) 0 < r < 1. Thus, we find that the function that could be a stretch of the exponential decay is [tex]f(x) = 2\cdot \left(\frac{1}{6} \right)^{x}[/tex]. (Correct choice: C)

Remark

The picture is missing and it cannot be found, but statement is still solvable as there is only one choice that responds the question.

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2. complete the table to summarize each student's conjecture: (2 points: 1 point for each row)
student
conjecture
trey
serena

Answers

The statements which summarize each student's conjecture are:

Trey thinks building 4 arch will be a reflection and then a double translation.Serena thinks building 4 arch will be a double reflection.  

What are the students trying to find out?

Trey and Serena are both trying to find the number of stones that were in the original arch or vault. Thus, when they identify the number of stones and its main features, they would be able to determine the type of arch or vault that was built there.

The statements which summarize each student's conjecture are:

Trey thinks building 4 arch will be a reflection and then a double translation.Serena thinks building 4 arch will be a double reflection.  

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Complete Question:

The Students' Conjectures: During an archeological dig, the students found a voussoir from a semicircular stone arch. A voussoir is a trapezoidal (wedge-shaped) stone used to build an arch or vault.

1. What are the students trying to find out? (1 point)

2. Complete the table to summarize each student's conjecture: (2 points: 1 point for each row)

Answer:

Step-by-step explanation:

Can someone please help???

Answers

Answer:

A 0.08

Step-by-step explanation:

30) A student has not been to class and must pass a 20 question true/false exam to continue in the course. The student will guess on every question and must get at least 14 correct to pass the test. What is the probability that the student will pass the test

Answers

The probability that the student will pass the test is 0.057

In probability theory and statistics, the Bernoulli distribution, named after Swiss mathematician Jacob Bernoulli,[1] is the discrete probability distribution of a random variable which takes the value 1 with probability [tex]p[/tex] and the value 0 with probability [tex]{\displaystyle q=1-p}[/tex]. Less formally, it can be thought of as a model for the set of possible outcomes of any single experiment that asks a yes–no question. Such questions lead to outcomes that are boolean-valued: a single bit whose value is success/yes/true/one with probability p and failure/no/false/zero with probability q.

The student will pass if he at least answers 14 questions correctly .

This can be written as a Bernoulli distribution function [tex]P(Q=i)= 20C_{i} (\frac{1}{2} )^i(1-\frac{1}{2} )^(20-i)[/tex]

P(Q≥ 14) = P(Q=14) + P(Q=15) + P(Q=16) +P(Q=17) + P(Q=18)+ P(Q=19) +   P(Q=20)

 P(Q=14) = 20[tex]C_{14}[/tex][tex](1/2)^{20}[/tex]

 P(Q=15) = 20[tex]C_{15}[/tex][tex](1/2)^{20}[/tex]

 P(Q=16) = 20[tex]C_{16}[/tex][tex](1/2)^{20}[/tex]

 P(Q=17) = 20[tex]C_{17}[/tex][tex](1/2)^{20}[/tex]

 P(Q=18) = 20[tex]C_{18}[/tex][tex](1/2)^{20}[/tex]

 P(Q=19) = 20[tex]C_{19}[/tex][tex](1/2)^{20}[/tex]

 P(Q=20) = [tex]20C_{20}(1/2)^{20}[/tex]

On summing up all we get,

P(Q≥ 14) = (38760 + 15504 + 4845+ 1140 + 190 + 20 + 1)/2^(20)

= 15115/262144=0.057

Thus the probability that the student will pass the test is 0.057

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Find all solutions to 2w^4 - 5w^2 + 2 = 0
asap please

Answers

Answer:

w = ±[tex]\sqrt{1/2}[/tex] or w= ±[tex]\sqrt{2}[/tex]

Step-by-step explanation:

if we say some variable y = w^2, we can rewrite the equation to:

2y^2 - 5y + 2 = 0

this can be factored into (2y-1)(y-2) = 0

putting w^2 back in the place of y, that's (2w^2 - 1)(w^2 - 2) = 0

The equation is a fourth degree polynomial, so there are four roots, or four values of w that will cause the equation to equal 0.

If 0 is multiplied by anything, the result is 0, so we set 2w^2 - 1 = 0 and solve for w, which is ±√1/2, then set w^2 - 2 = 0 to get w = ±√2 as our roots

the four solutions are ±√1/2 and ±√2

(because the positive counts as one solution and the negative another solution)

in quadrilateral ABCD, AB || CD. which additional piece of information is needed to determine the ABCD is a parallelogram?

Answers

The additional information needed to determine that ABCD is a parallelogram is: A. AB ≅ CD.

How to Identify a Parallelogram?

One of the criteria for proving that a quadrilateral is a parallelogram is that one of the pairs of opposite sides are congruent and also parallel to each.

We are already given that side AB is parallel to side CD, therefore, the additional information we would need to prove that quadrilateral ABCD is a parallelogram is: A. AB ≅ CD.

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A public health organization reports that 40%of baby boys 6-8 months old in the United
States weigh more than 20 pounds. A sample of 10 babies is studied. Round the answers to three decimal places.
what is the probability that more than 4 weigh more than 20 pounds
What is the probability that fewer than 3 weigh more than 20 pounds?
Would it be unusual if more than 7 of them weigh more than 20 pounds?

Answers

Using the binomial distribution, the probabilities are given as follows:

0.3675 = 36.75% probability that more than 4 weigh more than 20 pounds.0.1673 = 16.73% probability that fewer than 3 weigh more than 20 pounds.Since P(X > 7) < 0.05, it would be unusual if more than 7 of them weigh more than 20 pounds.

What is the binomial distribution formula?

The formula is:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters are:

x is the number of successes.n is the number of trials.p is the probability of a success on a single trial.

The values of the parameters for this problem are:

n = 10, p = 0.4.

The probability that more than 4 weigh more than 20 pounds is:

[tex]P(X > 4) = 1 - P(X \leq 4)[/tex]

In which:

[tex]P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)[/tex]

Then:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{10,0}.(0.4)^{0}.(0.6)^{10} = 0.0061[/tex]

[tex]P(X = 1) = C_{10,1}.(0.4)^{1}.(0.6)^{9} = 0.0403[/tex]

[tex]P(X = 2) = C_{10,2}.(0.4)^{2}.(0.6)^{8} = 0.1209[/tex]

[tex]P(X = 3) = C_{10,3}.(0.4)^{3}.(0.6)^{7} = 0.2150[/tex]

[tex]P(X = 4) = C_{10,4}.(0.4)^{4}.(0.6)^{6} = 0.2502[/tex]

Hence:

[tex]P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0061 + 0.0403 + 0.1209 + 0.2150 + 0.2502 = 0.6325[/tex]

[tex]P(X > 4) = 1 - P(X \leq 4) = 1 - 0.6325 = 0.3675[/tex]

0.3675 = 36.75% probability that more than 4 weigh more than 20 pounds.

The probability that fewer than 3 weigh more than 20 pounds is:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0061 + 0.0403 + 0.1209 = 0.1673

0.1673 = 16.73% probability that fewer than 3 weigh more than 20 pounds.

For more than 7, the probability is:

[tex]P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10)[/tex]

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 8) = C_{10,8}.(0.4)^{8}.(0.6)^{2} = 0.0106[/tex]

[tex]P(X = 9) = C_{10,9}.(0.4)^{9}.(0.6)^{1} = 0.0016[/tex]

[tex]P(X = 10) = C_{10,10}.(0.4)^{10}.(0.6)^{0} = 0.0001[/tex]

Since P(X > 7) < 0.05, it would be unusual if more than 7 of them weigh more than 20 pounds.

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Consider an unstructured overlay network in which each node randomly chooses c neighbors. If P and Q are both neighbors of R, what is the probability that they are also neighbors of each other

Answers

The probability value become is 2c/(N-1).

According to the statement

we have given that If P and Q are both neighbors of R, and by considering unstructured network in which each node randomly chooses c neighbors.

we have to find that the probability of neighbors that they are also neighbors of each other.

So, For this purpose to find the probability is

Consider a network of N nodes unstructured and let

If each node chooses c neighbors at random,

then the probability that P will become by choose Q, or Q chooses P is roughly 2c/(N-1).

And the probability outcomes value become is 2c/(N-1).

So, The probability value become is 2c/(N-1).

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Which equation is equivalent to
f(x) = 16x4 -81 = 0?
✓(4x² +9)(4x² - 9) = 0 ✓
COMPLETE
Select all of the zeroes of the function.
O
2/3
DONE

Answers

The given equation is equivalent to (4x²+9)*(4x²-9) or (4x²+9)*(2x-3)*(2x+3). And the zero of the function are: [tex]\pm \frac{3}{2}[/tex] and [tex]\pm \frac{3}{2}i[/tex].

What is a Quadratic Function?

The quadratic function can represent a quadratic equation in the Standard form: ax²+bx+c=0 where: a, b and c are your respective coefficients. In the quadratic function the coefficient "a" must be different than zero (a≠0) and the degree of the function must be equal to 2.

For solving a quadratic function you should find the discriminant: D=b²-4ac and after that use this variable in the formula: [tex]x=\frac{-b\pm\sqrt{D} }{2a}[/tex].

Factoring

In math, factoring or factorization is used to write an algebraic expression in factors. There are some rules for factorization.  One of them is a factor out a common term for example: x²-x= x(x-1), where x is a common term.

The question gives: [tex]16x^4-81=0[/tex], you can factor this equation. See below.

(4x²+9)*(4x²-9)

(4x²+9)*(2x-3)*(2x+3)

Therefore, you should choose one of options: (4x²+9)*(4x²-9) or (4x²+9)*(2x-3)*(2x+3).

Next step is to solve the given equation. Solving for  (4x²+9)*(2x-3)*(2x+3)=0, then:

For 2x-3=0

      x=3/2

For 2x+3=0

      x= -3/2

For 4x²+9=0

      4x²=-9

       x²= -9/4

      x = [tex]\pm \sqrt{\frac{-9}{4} }[/tex]

      x   =[tex]\pm \frac{3}{2}*\sqrt{-1 }\\ \\ \pm \frac{3}{2}*i[/tex]

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Help me with this question please

Answers

the answer is 991^2/80
The answer is 991^2/80
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